A 4.0-kg block extends a spring 16 cm from its unstretched position. The block is removed and a 0.50-kg body is hung from the same spring. If the spring is then stretched and released, what is its period of motion

Answers

Answer 1

The period of motion for the 0.50-kg body is 0.32 seconds.

T = 2π√(m/k)

U = 1/2 kx²

where U is the potential energy, x is the displacement of the spring from its equilibrium position, and k is the spring constant.

For the 4.0-kg block, we have:

U = mgh = (4.0 kg)(9.8 m/s²)(0.16 m) = 6.272 J

The potential energy is equal to the energy stored in the spring, so we can set U = 1/2 kx² and solve for k:

k = 2U/x² = 2(6.272 J)/(0.16 m)² = 980 N/m

Now, we can calculate the period for the 0.50-kg body:

T = 2π√(m/k) = 2π√(0.50 kg/980 N/m) = 0.32 s (rounded to two significant figures)

The motion refers to the act of moving or changing position. It is a fundamental concept in physics that describes the movement of objects in space over time. Motion can be described using various parameters such as distance, speed, acceleration, and direction.

There are three types of motion: translational, rotational, and vibrational. The translational motion refers to the movement of an object from one place to another, while rotational motion refers to the movement of an object around its axis. Vibrational motion refers to the back-and-forth movement of an object around a fixed point.

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Related Questions

Electrons Group of answer choices have no magnetic properties. have the same magnetic behavior as particles of iron. behave like tiny bar magnets of different strengths. behave like tiny bar magnets of the same strength.

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Electrons behave like tiny bar magnets of the same strength.

In an atom, electrons exhibit magnetic properties due to their intrinsic properties: spin and orbital motion. The magnetic moment of an electron is primarily determined by its spin, which gives it a magnetic dipole moment, similar to a tiny bar magnet. All electrons have the same spin, and hence, their magnetic strength is also the same.

The magnetic behavior of electrons plays a vital role in various physical phenomena, such as magnetism in materials and magnetic resonance imaging (MRI) in medical diagnostics. The collective behavior of electrons in a material determines whether it will be ferromagnetic, paramagnetic, or diamagnetic. Ferromagnetic materials, like iron, have domains where the magnetic moments of electrons align, creating a strong magnetic field. In paramagnetic and diamagnetic materials, the alignment of electron magnetic moments is weaker or opposes an applied magnetic field, respectively.

In summary, electrons behave like tiny bar magnets with the same strength due to their inherent spin and orbital motion, contributing to the magnetic properties observed in different materials.

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A roller-coaster car has a potential energy of 250 000 J and a kinetic energy of 65 000 J at point A in its travel. At the low point of the ride, the potential energy is zero, and 35 000 J of work have been done against friction since it left point A. What is the kinetic energy of the roller coaster at this low point

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The kinetic energy of the roller coaster at the low point of the ride is 280 000 J.

To find the kinetic energy of the roller coaster at the low point, we need to consider the conservation of mechanical energy, which states that the total mechanical energy remains constant if only conservative forces act on the object. The total mechanical energy is the sum of the potential energy and the kinetic energy.

At point A, the total mechanical energy is:
Total Energy = Potential Energy + Kinetic Energy
Total Energy = 250,000 J + 65,000 J = 315,000 J

Since 35,000 J of work have been done against friction, we need to subtract this value from the total mechanical energy:
Total Energy - Work Done = 315,000 J - 35,000 J = 280,000 J

At the low point, the potential energy is zero, so the remaining energy is kinetic energy:
Kinetic Energy = Total Energy - Potential Energy
Kinetic Energy = 280,000 J - 0 J = 280,000 J

So, the kinetic energy is 280,000 J.

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If the amplitude of an Eu field in a linearly polarized wave doubles, what will happen to the energy density of the wave

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the energy density of the wave will increase by a factor of 4 if the amplitude of the electric field doubles in a linearly polarized wave. This means that there will be more energy per unit volume in the wave.

The energy density of an electromagnetic wave is given by the formula:

u = (1/2) * ε * [tex]E^2[/tex]

Where u is the energy density, ε is the permittivity of the medium, and E is the amplitude of the electric field.

If the amplitude of the electric field E doubles, then the energy density u will increase by a factor of 4, because:

u' = (1/2) * ε *[tex](2E)^2[/tex] = 2 * (1/2) * ε *[tex]E^2[/tex] = 2u

What is amplitude?

Amplitude refers to the maximum displacement or distance that a particle in a medium moves from its rest position when a wave passes through that medium.

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When a riffle fires a bullet, the riffle will recoil. This is an illustration of the _______________.

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According to the given information this is an illustration of Newton's third law of motion, which states that for every action, there is an equal and opposite reaction.

In this case, the action is the firing of the bullet and the reaction is the recoil of the rifle.When a rifle fires a bullet, the rifle will recoil. This is an illustration of the conservation of momentum, specifically Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction.The law applies to all objects, regardless of their size, shape, or motion. For example, when a person jumps off a diving board, they exert a force on the board, which in turn exerts an equal and opposite force back on the person, propelling them into the air.The third law is based on the principle of conservation of momentum. The momentum of an object is equal to its mass multiplied by its velocity. When two objects interact, their momentum changes, but the total momentum of the system remains constant. This is because the forces they exert on each other are equal and opposite, canceling each other out.

The third law has many practical applications, such as in the design of rockets and other propulsion systems. It also helps explain the behavior of objects in collisions and the motion of fluids. Understanding Newton's third law is essential for understanding the principles of mechanics and motion.

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If 1/10 kg mass is attached on the end/bottom of a vertically hanging spring, and the spring stretches down 10 cm, what is the spring constant

Answers

The spring constant is -9.81 N/m

We can use Hooke's law to find the spring constant of the spring.

Hooke's law states that the force exerted by a spring is proportional to the amount of stretch or compression of the spring, as long as the limit of proportionality is not exceeded.

The formula for Hooke's law is:

F = -kx

where F is the force exerted by the spring, x is the amount of stretch or compression of the spring, and k is the spring constant.

In this case, the mass of the object attached to the spring is 1/10 kg, and the spring stretches down 10 cm or 0.1 meters.

We can assume that the gravitational force acting on the mass is negligible compared to the force exerted by the spring.

Therefore, the force exerted by the spring is equal to the weight of the mass:

F = mg = (1/10 kg) * 9.81 m/s^2 = 0.981 N

Substituting the values into Hooke's law, we get:

0.981 N = -k * 0.1 m

Solving for k, we get:

k = -0.981 N / 0.1 m

k = -9.81 N/m

Note that the negative sign indicates that the force exerted by the spring is in the opposite direction of the displacement of the spring.

In other words, the spring is being stretched, so the force exerted by the spring is upwards, while the weight of the mass is downwards.

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