Find the measure of CD.
Round to the nearest tenth.
mCD=[?]degrees

Find The Measure Of CD.Round To The Nearest Tenth.mCD=[?]degrees

Answers

Answer 1

Answer:

m(arc CD) = 14.1 cm

Step-by-step explanation:

Measure of an arc of the circle = [tex]\frac{\theta}{360}(2\pi r)[/tex]

Here 'r' = radius of the circle

θ = Angle subtended by the arc at the center of the circle

From triangle OED,

sin(∠EOD) = [tex]\frac{ED}{OD}[/tex]

sin(∠EOD) = [tex]\frac{\frac{12.7}{2}}{9.06}[/tex]

                 = [tex]\frac{6.35}{9.06}[/tex]

                 = 0.7

m∠EOD = 44.498

              ≈ 44.5°

Angle subtended by the arc CD at the center = m∠COD

                                                                            = 2(44.5)

                                                                            = 89°

m(arc CD) = [tex]\frac{89}{360}(2\pi)(9.06)[/tex]

                 = 14.07

                 ≈ 14.1 cm

Find The Measure Of CD.Round To The Nearest Tenth.mCD=[?]degrees

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Step-by-step explanation:

Given

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Required

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_____

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Answers

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Answer:

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Step-by-step explanation:

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Answers

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Answers

Answer:

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Step-by-step explanation:

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Answer:

Beck caught 45 fish

Step-by-step explanation:

a = number of fish Ally caught

b = number of fish Beck caught

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Answers

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Answers

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Answers

Answer:

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hi find the distance in the coordanite plane between the two points and show ur work


1 (5, -8) and (5,2)


2 (-8, -2) and (7, -2)


3 (9, 10) and (9, -2)


4 (11 , 6) and (-7, 6)

Answers

Answer:

The distance between (5, -8) and (5,2) is: d = 10 units

Step-by-step explanation:

Note: I will solve the first question as the procedure solution for the remaining questions is exactly the same.

Given the points

(5, -8)(5,2)

Determining the distance between (5, -8) and (5,2)

[tex]d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}[/tex]

substitute (x₁, y₁) = (2, 3) and (x₂, y₂) = (2, -5)

   [tex]=\sqrt{\left(5-5\right)^2+\left(2-\left(-8\right)\right)^2}[/tex]

   [tex]=\sqrt{\left(5-5\right)^2+\left(2+8\right)^2}[/tex]

   [tex]=\sqrt{0+10^2}[/tex]

   [tex]=\sqrt{10^2}[/tex]

   [tex]=10[/tex]  units

Therefore, the distance between (5, -8) and (5,2) is: d = 10 units

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Answers

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Answer:

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Answers

Answer:

4x² + 16x + 15 = 0

Step-by-step explanation:

We'll begin by determining the solutions to the graph.

The solutions to the graph is obtained by taking the values where the graph cut through the x–axis. This is illustrated below:

The solutions to the graph are:

x = –1.5 or –2.5

Finally, we shall determine the equation for the graph as follow:

x = –1.5 or x = –2.5

x = –3/2 or x = –5/2

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2x = –3 or 2x = –5

Rearrange

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Combine

(2x + 3)(2x + 5) = 0

Expand

2x(2x + 5) + 3(2x + 5) = 0

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4x² + 16x + 15 = 0

Thus, the equation for the graph is:

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