find the mass of an object with a density of 1.5 g/cm^3 and had a volume of 8cm^3

Answer:

This question is incomplete

Explanation:

This question is incomplete, however, the relationship to between the angle of incidence and angle of refraction is best explained by snell's law with the equation below

ni sinθi = nr sinθr

where ni is the refractive index of the incident medium (assuming it's plate glass then 1.52)

nr is the refractive index of the refractive medium (1.33)

θi is the angle of incidence (30°)

θr is the angle of refraction (X)

If we substitute the values, we have

1.52 × sin 30 = 1.33 × sin X

1.52 × 0.5 = 1.33 × sin X

0.75 = 1.33 × sin X

sin X = 0.75/1.33

sin X = 0.571

X = sin⁻¹ 0.571

X = 34.82°

Thus, the angle of refraction will be 34.82°

Answer:

The hotter object radiate more power than the cooler object 15 times i.e 15σeA[tex]T^{4}[/tex]

Explanation:

From Stefan's law, an object would radiate power with respect to its temperature.

i.e Radiative power, Q = σeA[tex]T^{4}[/tex]

where Q is the radiative power, σ is the constant, e is the emissivity of the object, A is the area of the object and T is the temperature.

Let the temperature of the cooler object be represented by T.

So that its radiative power = σeA[tex]T^{4}[/tex]

Given that the temperature of the hotter object is twice as large as that of the cooler object.

Temperature of hotter object = 2T

So that its radiative power = σeA[tex](2T)^{4}[/tex]

                                         = 16σeA[tex]T^{4}[/tex]

Radiative power difference between the two objects = 16σeA[tex]T^{4}[/tex] - σeA[tex]T^{4}[/tex]

                                                                                        = 15σeA[tex]T^{4}[/tex]

The hotter object radiate more power than the cooler object 15 times.

The hotter object radiates 15 times more power  than the power of cooler object.

Absolute Temperature of one object = [tex]T_1[/tex]

Absolute Temperature of second object =[tex]T_2[/tex] = [tex]2T_1[/tex]

The Power emitted by the an object is given by the equation (1)

[tex]P= A\epsilon \sigma\;T^4[/tex].......(1)

Equation (1) is called as Stephan Boltzmann Law  

Where

P = Power emitted by the object in Joule

A = Surface area of the object

[tex]\epsilon[/tex] =  Emissivity of the object

T =  Absolute Temperature

Let us consider emissivities are equal

[tex]So \; P_1/P_2 = T_1^4/T_2^4\\[/tex]  ( Areas of both objects are equal)

[tex]P_1/P_2= T_1^4/16T1^4= 1/16[/tex]

[tex]P_2= 16 P_1[/tex]

Difference in Power = [tex]16P_1- P_1[/tex] = [tex]15P_1[/tex]

So the hotter object radiate 15 times more power  than the power of cooler object.

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Answer:

B. 0.51 ohms

Explanation:

Our data is as follows:

Resistor R = 20.0ohms

V1 = 12 volts

V2 = 0.300 V

We are to get the internal resistance of this battery

Now,

I = change in voltage/R

Change in voltage = v1-v2

= 12-0.300

= 11.7

Then,

I = 11.7/20

= 0.585Ri

Now

O.300 = 0.585Ri

Ri = 0.300/0.585

= 0.51 ohms

This is therefore the internal resistance of the battery.

Thank you!

Answer:

Gravity, or gravitation, is a natural phenomenon by which all things with mass or energy—including planets, stars, galaxies, and even light—are brought toward one another. On Earth, gravity gives weight to physical objects, and the Moon's gravity causes the ocean tides. 

Answer:

The answer is "[tex](1.265 \pm 0.010) \ s \ and \ 0.709 \%[/tex]"

Explanation:

In point i:

[tex]T_{theo}= 2\pi \sqrt{\frac{l}{g}}[/tex]

        [tex]=2\pi\sqrt{\frac{0.397}{9.8}}\\\\= 1.265 \ s[/tex]

If  error in the theoretical time period :

[tex]\frac{\Delta T_{theo}}{T_theo} = \frac{1}{2} \frac{\Delta l }{l}\\\\\Delta T_{theo} = 1.265 \times \frac{1}{2} \times \frac{0.006}{0.397}[/tex]

           [tex]= 0.010 \ s[/tex]

 [tex]T_{theo} = (1.265 \pm 0.010) \ s[/tex]

In point ii:

[tex]\% \ difference = \frac{|T_{exp} -T_{theo}|}{\frac{T_{exp}+T_{theo}}{2}} \times 100[/tex]

60 m

Concept Used:

We know that the area under a velocity-time graph represents the Displacement of the body

Displacement in the Last 6 seconds:

To find the Displacement in the last 6 seconds, we will find the area under the graph between x = 4 and x = 10

We can see that the shape formed is a rectangle also shown in the given graph. So, the area of the rectangle is the Displacement of the car in the last 6 seconds

Area of the Rectangle:

From the graph, we know that the rectangle is 10 (m/s) tall and 6 (s) wide

Area of Rectangle=  length*Breadth        

replacing the values

Area = 10 (m/s) * 6 (s)

Area = 60 m

Hence, the car travelled 60 m in the last 6 seconds of the graph

Answer:

L = 4.58 x 10⁴ kg.m²/s

Explanation:

The angular momentum is given by the formula:

L = mvr

but, v = rω

Therefore,

L = mr²ω

where,

L = Angular Momentum of the person = ?

m = mass of person = 99 kg

r = radius of earth = 6.37 x 10⁶ m

ω = Angular Speed of Earth's Rotation = θ/t

Since, earth completes 1 rotation in 1 day. Hence,

ω = (2π rad/1 day)(1 day/24 h)(1 h/3600 s)

ω =  7.27 x 10⁻⁵ rad/s

Therefore,

L = (99 kg)(6.37 x 10⁶ m)²(7.27 x 10⁻⁵ rad/s)

L = 4.58 x 10⁴ kg.m²/s

Answer:

Thermal Energy (Heat)

Answer:

Heat

Explanation:

the form that is raised from the atmosphere from earths surface is heat

Answer:

P = 350 [Pa]

Explanation:

The pressure is calculated by knowing the force and area. By means of the following formula can be calculated by means of the following equation.

Units of 1 [Pa] = 1 [N/m²]

P = F/A

where:

P = pressure [Pa]

F = force = 560 [N]

A = area = 1.6 [m²]

P = 560/1.6

P = 350 [Pa]

Answer:

Patellar region

Plantar region

Crural region

Answer:

B, C, D

Patellar, Plantar, Crural regions

Explanation:

Legs are the lower limbs of the body, consisting of all these parts. Just did assignment too.

Answer:

CaO, CaMg, or CaF2

Ca2Cl, CaNa, or CaP

CaF, CaMg, or CaNa

CaO, CaF2, or CaCl2

Explanation: i think

Answer:

(a). forms.

Explanation:

Bro even i ain't sure.

Answer:

I think its A? Because in the water cycle it goes from a liquid to a gas?

Explanation:

Answer:

My worldview is that the world is a beautiful place. IT has many wonders, and many kind people. There are also very nice places, governments, tech and more.

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 2 × 5

We have the final answer as

Hope this helps you

Answer:

352,088.37888Joules

Explanation:

Complete question;

A hiker of mass 53 kg is going to climb a mountain with elevation 2,574 ft.

A) If the hiker starts climbing at an elevation of 350 ft., what will their change in gravitational potential energy be, in joules, once they reach the top? (Assume the zero of gravitational potential is at sea level)

Chane in potential energy is expressed as;

ΔGPH = mgΔH

m is the mass of the hiker

g is the acceleration due to gravity;

ΔH is the change in height

Given

m = 53kg

g = 9.8m/s²

ΔH = 2574-350 = 2224ft

since 1ft = 0.3048m

2224ft = (2224*0.3048)m = 677.8752m

Required

Gravitational potential energy

Substitute the values into the formula;

ΔGPH = mgΔH

ΔGPH = 53(9.8)(677.8752)

ΔGPH = 352,088.37888Joules

Hence the gravitational potential energy is 352,088.37888Joules

The change in gravitational potential energy be, once the hiker reach the top of the mountain is 352088 joules or 352.1 kJ.

Gravitational potential energy is the energy which a body posses because of its position.

The gravitational potential energy of a body is given as,

[tex]U=mgh[/tex]

Here, (m) is the mass of the body, (g) is the gravitational force and (h) is the height of the body.

The mass of the hiker is 53 kg and the height of the climb is 2574 ft.

Now, the hiker starts climbing at an elevation of 350 ft. Thus, the net height of the hiker has to climb is,

[tex]h=2574-350\\h=2224\rm\; ft[/tex]

Convert this into the meter by multiplying 03048 as,

[tex]h=2224\times0.3048\\h=677.8752\rm\; m[/tex]

It is known that the value of g is 9.8 m/s². Plug in all the values as,

[tex]U=53\times9.8\times677.8752\\U=352088J\\U=352.1 \;\rm kJ[/tex]

Thus, the change in gravitational potential energy be, once the hiker reach the top of the mountain is 352088 joules or 352.1 kJ.

Learn more about the gravitational potential energy here;

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Answer:

m = 1

Explanation:

K.E = 8J

v = 4m/s

m = ?

Now,

K.E = 1÷2mv^2

8 = 1÷2 × m × (4)^2

8 = 1÷2 × m × 16

8 = m × 8

m × 8 = 8

m = 8 ÷ 8 = 1

m = 1

K.E. = 1÷2mv^2

K.E = 1÷2 × 1 × 4^2

K.E. = 8J

-TheUnknownScientist

Answer: 12cm.

Explanation:

First we need to calculate the focal length which will be:

= 100 / 4.25

= 23.529

The near point of the machinist will be solved using the equation:

1/u + 1/v = 1/f

where,

v = -25

f = 23.529

1/u + 1/v = 1/f

1/u - 1/25 = 1/23.529

1/u = 1/23.529 + 1/25

u = 12.12cm

u = 12cm approximately

Therefore, the near point of the machinist is 12cm

Answer:

flexible covering

Explanation:

The period of the enclosed cylinder is approximately 115.866 seconds.

The rotating enclosed cylinder is rotating at constant angular speed ([tex]\omega[/tex]), in radians per second, which means that experiments a constant radial angular acceleration ([tex]\alpha[/tex]), in radians per square second. Then, we derive an expression for the period of the cylinder, this is, the time needed by the cylinder to make one revolution:

[tex]g = \omega^{2}\cdot R[/tex] (1)

Where:

[tex]g = \frac{4\pi^{2}\cdot R}{T^{2}}[/tex]

[tex]T = 2\pi\cdot \sqrt{\frac{R}{g} }[/tex] (2)

Where [tex]T[/tex] is the period, in seconds.

If we know that [tex]R = 3335\,m[/tex] and [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], then the period of the enclosed cylinder is:

[tex]T = 2\pi\cdot \sqrt{\frac{3335\,m}{9.807\,\frac{m}{s^{2}} } }[/tex]

[tex]T \approx 115.866\,s\,(1.931\,min)[/tex]

The period of the enclosed cylinder is approximately 115.866 seconds.

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Answer:

Answer:

(1) 0.04 ohms (2) 55 ohms (3) 13 volt

Explanation:

(1) The resistance of an electric device is 40,000 microhms.

We need to convert it into ohms.

[tex]1\ \mu \Omega =10^{-6}\ \Omega[/tex]

To covert 40,000 microhms to ohms, multiply 40,000 and 10⁻⁶ as follows :

[tex]40000 \ \mu \Omega =40000 \times 10^{-6}\ \Omega\\\\=0.04\ \Omega[/tex]

(2) Voltage used, V = 110 V

Current, I = 2 A

We need to find the resistance of the iron. Using Ohms law to find it as follows :

V = IR, where R is resistance

[tex]R=\dfrac{V}{I}\\\\R=\dfrac{110}{2}\\\\R=55\ \Omega[/tex]

(3) Current, I = 0.2 A

Resistance, R = 65 ohms

We need to find the applied voltage in the circuit. Using Ohms law to find it as follows :

V=IR

V = 0.2 × 65

V = 13 volt

Answer:

1. 0.04 Ohms

2. 55 Ohms

3. 13 Volts

Explanation:

Penn Foster

Answer: 2 Hz (8 cycles/4 s = 2 cycles/s).

Explanation:

If a coil of slinky makes 3 vibrational cycles in one second, then the frequency is 3 Hz. And if a coil makes 8 vibrational cycles in 4 seconds, then the frequency is 2 Hz (8 cycles/4 s = 2 cycles/s).

Answer:

The largest possible range of the projectile is 163.27 m.

Explanation:

Given;

launch speed, u = 40 m/s

angle of projection, θ; between 0⁰ and 90⁰

The range of a projection is given as;

[tex]R = \frac{u^2sin(2\theta )}{g}[/tex]

The largest possible range will occur at 45 degrees angle of projection;

[tex]R = \frac{u^2sin(2\theta )}{g} \\\\R = \frac{(40)^2sin(2\ \times \ 45^0 )}{9.8}\\\\R = \frac{(40)^2sin( 90^0 )}{9.8}\\\\R = \frac{(40)^2( 1 )}{9.8} \\\\R = 163.27 \ m\\\\[/tex]

Therefore, the largest possible range of the projectile is 163.27 m.

Answer:

Explanation:

charge on the shell = 4πR²  x charge density

= 4 x 3.14 x 7.5² x 10⁻⁴ x 10⁻³ C

= 706.5 x 10⁻⁷ C  

electric field = k Q / d² , d is distance of point from centre

= 9 x 10⁹ x 706.5 x 10⁻⁷ / 10²

= 6358.5 N /C

= 6.358 kV / m

Answer:

S.H.M:- If the acceleration of the vibrating body directly varies with the displacement of the body from the mean position and always directed to the mean position, the motion of that body is called simple harmonic motion.

Ex:- (i) The motion of a pendulum is an S.H.M.

(ii) The motion of vibrating mass attached to a spring is an S.H.M.

Answer:

a)   y_total = 19.916 10⁻⁵ m ,   b)    Δθ = 1.91 10-⁻³ rad

Explanation

This is a diffraction exercise that is described by the expression

          a sin θ = m λ

the first minimum occurs for m = 1

         a sin θ = λ

        sin θ = λ / a

        θ = sin⁻¹ (633 10⁻⁹ / 0.330 10⁻³)

        θ = 1.918 10⁻³ rad

let's use trigonometry

        tan θ = y / x

        y = x tan θ

        y = 2.55 tan (3.936 10-3)

        y = 5.75 10⁻- m

this value is from the central maximum to one extreme of the value,

        y_ total = 2 y

        y_total = 2 (5.75e1)

        y_total = 19.916 10⁻⁵ m

b) For the second point and constructive inference we have m = 2

         sin θl = m λ

         θ = sin⁻¹ (lat / a)

         θ = sin⁻¹ (2 633 10-9 / 0.33010-3) = son-1 (3.836 10-3)

         θ = 3.84 10-3 give

The width of this maximum is

          Δθ = 1.3 10-3

          Δθ = 3.84 10⁻³- 1.918 10⁻³

          Δθ = 1.91 10-⁻³ rad

Answer:

The rotational inertia of the meter stick is 0.0618 kgm².

Explanation:

Given;

mass of the meter stick, m = 0.499 kg

perpendicular distance to the rotational axis, r = 35.2 cm = 0.352 m

The rotational inertia or moment of inertia for a point mass is given by;

I = mr²

where;

m is the point mass

r is the perpendicular distance

Substitute the givens and solve for moment of inertia.

I = (0.499)(0.352)²

I = 0.0618 kgm²

Therefore, the rotational inertia of the meter stick is 0.0618 kgm².

Answer:C,(Calcium,an alkaline earth metal with an oxidation number of +2 will form an ionic bond with chlorine,a halogen in group VllA with an oxidation number of -1 called calcium chloride (CaCl2)

Explanation:

on USAtestprep !!

Calcium, an alkaline earth metal with an oxidation number of +2 will form

an ionic bond with chlorine, a halogen in group VIIA with an oxidation

number of -1 called calcium chloride (CaCl₂). This is correct statement.

Simply said, the number assigned to each element in a chemical combination is the definition of an oxidation number. The total number of electrons that an atom in a molecule can share, lose, or gain while forming a chemical bond with an atom of a different element is known as the oxidation number.

Also known as oxidation state, oxidation number is a numerical value. But depending on whether we take into account the atoms' electronegativity or not, these phrases might occasionally have a different meaning. In coordination chemistry, the term "oxidation number" is often used.

According to Periodic table:  calcium is a alkaline earth metal with an oxidation number of +2 whereas chlorine is a halogen in group VIIA with an oxidation number of -1. When they reacts chemically, they form an ionic compound named calcium chloride having chemical formula CaCl₂.

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