Find the following vector. The vector in the direction of (10,- 24) with length 2 The vector in the direction of (10, – 24) with length 2 is? Complete parts (a) through (c) below. 4i + 3j. + a. Find two unit vectors parallel to v= - b. Find b if y= (5.0 ) ,b) is a unit vector. c. Find all values of a such that w=ai - Žj is a unit vector.

The direction that the genes are transcribed is shown by the arrows. The arrow directs attention to the 3' end. When creating DNA strands, arrows are crucial.

Using only the nucleotides A, T, G, and C, construct a compact DNA molecule. Because of their antiparallel structure, the two strands of the double helix that make up DNA molecules move in the opposite directions from one another. Humans and unicellular protists are two eukaryotic species that have telomeres, which are repeating regions at the very ends of chromosomes. The telomeres, which function as caps to protect the internal chromosomal regions, lose a small amount of their length with each cycle of DNA replication.

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For each Part, the x- and y-components of the vectors are mathematically stated as follows.x=-1.939 km and y=3.498 km,x= -2 cm/s,0, y=, x= -7.6412m/s^2, -10.517m/s^2

What are the vectors' x- and y-components?

Measures for the question

We typically adhere to a fundamental premise where

component=Fsintheta for x

Fcostheta as the y component

Therefore

For A

the x component

x= -4 x sin (29°)

x= -1.939 km

Is y component

y= 4 x cos (29°)

y= 3.498 km

For B

the x component

x= -2 cm/s

Is y component

y= 0

For C

the x component

x= -13 x sin (36°)

x= -7.6412m/s^2

Is y component

y= -13 x cos (36°)

y= -10.517m/s^2

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The full question:

Part AFind the x- and y-components of the vector d⃗ = (4.0 km, 29 ∘ left of +y-axis). Express your answer using two significant figures. Enter the x and y components of the vector separated by a comma.d⃗ = km Part BFind the x- and y-components of the vector v⃗ = (2.0 cm/s , −x-direction).Express your answer using two significant figures. Enter the x and y components of the vector separated by a comma.v⃗ = cm/s Part CFind the x- and y-components of the vector a⃗ = (13 m/s2 , 36 ∘ left of −y-axis).Express your answer using two significant figures. Enter the x and y components of the vector separated by a comma.a⃗ x = m/s2

Part A.

It is impossible to determine the speed of the test charge at point y based solely on the information provided. The speed of the charge at point y could be greater than, less than, or equal to v0 depending on various factors such as the presence of electric flux or magnetic fields, resistance, or other forces that may have acted on the charge between points x and y. A detailed analysis of the situation taking into account all relevant factors would be required to determine the speed of the charge at point y.

Part B.

The electric flux through a face of a cube can be calculated using the following formula:

where Φ is the electric flux, ε0 is the permittivity of free space (8.854 x 10^-12 C^2/Nm^2), E is the electric field through the face, and A is the area of the face.

Given that the sides of the cube have length L1, the area of one face can be calculated as A = L1^2. Substituting this value into the formula for Φ, we get:

So, the electric flux through one face of the cube can be calculated by multiplying the permittivity of free space, the electric field through the face, and the square of the side length.

Electric Flux is the number of lines of force from the electric field that penetrates a surface, even though the electric field in a conductor is not moving. Electric flux is used to describe and measure the magnitude of the electric field at a certain distance from the test charge.

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Stairways must be installed at least 30 degrees, but no more than 50 degrees from the horizontal.

Stairways and stepping stools are a significant wellspring of wounds and fatalities among development laborers.OSHA gauges that there are 24,882 wounds furthermore, upwards of 36 fatalities each year because of falls from flights of stairs and stepping stools utilized in development. Almost 50% of these wounds are adequately serious to demand investment off the gig - 11,570 lost working day wounds and 13,312 non-lost business day wounds happen yearly because of tumbles from flights of stairs and stepping stools utilized in development.

These information show that work nearby stepping stools and flights of stairs is dangerous. All the more significantly,they show that consistence with OSHA's necessities for the protected utilization of stepping stools and flights of stairs might have forestalled large numbers of these wounds.

This conversation fills in as a speedy and simple reference for use on places of work. The prerequisites of OSHA security guidelines for the protected utilization of stepping stools and steps (Subpart X, Title 29 Code of Government Guidelines, Part 1926.1050 through 1926.1060) are made sense of conversation.

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The spring constant k can be determined using the equation:

Therefore, k = (30 × 9.81 + 20) × 0.3/(0.3^2 - 0.1^2) = 301.53 N/m .

The equation is a mathematical expression that states the equality of two expressions. It is typically written using symbols and numbers and is used to find the solution to a problem. Equations are used in all fields of mathematics, from basic algebra to calculus and beyond. They can also be used to find the relationships between variables, explore trends, and make predictions. Equations are a powerful tool for understanding and manipulating the world around us.

k = (mg + mA)h/(h2 - h1)

where m is the total mass of the system (m = mA + mB), g is the acceleration due to gravity, h is the height of the system in equilibrium, and h1 and h2 are the heights at which the spring is unstretched and stretched, respectively.

In this case, m = 30 kg, g = 9.81 m/s2, h = 0.3 m, h1 = 0.1 m, and h2 = 0.3 m.

Therefore, k = (30 × 9.81 + 20) × 0.3/(0.3^2 - 0.1^2) = 301.53 N/m .

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The eccentricity of the red planet is 1.3175 x 10¹² m².

The eccentricity of the red planet is the product of the Semi-Major axis (a) and the linear eccentricity (c).

The Semi-Major axis (a)  is given as 1,550,000 m and the linear eccentricity (c) is given as 850,000 m.

The eccentricity of the red planet is calculated as follows;

e = ca

e = 850,000 m x 1,550,000 m

e = 1.3175 x 10¹² m²

Thus, the eccentricity of red planet is a function of the Semi-Major axis (a)  and the linear eccentricity (c) .

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Astronauts and their spacecraft still have mass and are subject to the effects of Earth's gravity while they are in space. In this way, even though the gravitational pull of the Earth is weaker in space than it is on Earth's surface, objects still have weight.

All objects fall at the same pace due to gravity in a vacuum. It is irrelevant how much mass the thing has.

"The force that gravity exerts on the item," according to our textbook, is how weight is defined. The astronauts are weightless since space has zero gravity. But since mass is a measure of how much matter is there, they are not massless. Independent of gravity, mass may be measured.

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lan can decrease the magnetic force on the washers by increasing the distance between the magnet and the pile of metal washers.

A material or object that creates a magnetic field is called a magnet.

The most noteworthy characteristic of a magnet, a force that pulls on other ferromagnetic elements like iron, steel, nickel, cobalt, etc., as well as the ability to attract or repel other magnets, is caused by this invisible magnetic field.

The strength of the magnetic force produced by a magnet increases when the distance between the magnet and an object experiencing the magnetic force is reduced.

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The time it will take for the car moving at an acceleration of 5.00m/s² is 2.45s.

Acceleration refers to the change of velocity with respect to time (can include deceleration or changing direction).

The acceleration can be calculated using one of the equation of motions as follows:

s = ut + ½at²

Where;

15 = (0 × t) + ½ × -5 × t²

15 = 0 + -2.5t²

15 = -2.5t²

t² = 6

t = √6

t = 2.45s

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The density of an object can be calculated using the equation density = mass / volume.

Density is a measurement of the mass per unit volume of an object. Or it could also be interpreted as a comparison between the mass and volume of an object, as reported by the Ministry of Education and Culture's Learning Resources website.

The higher the density of an object, the greater the mass of each volume. The average density of each object is the total mass divided by the total volume.

An example of an object that has a higher density is iron, while an example of an object that has a lower density is water.

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Answer:it would be zero since its constant velocity and there is no acceleration

Explanation:

The total translational kinetic energy of the molecules in an E. coli bacterium at 37°C can be made.

To calculate the total translational kinetic energy of all the molecules in an E. coli bacterium, we need to know its temperature and the molecular masses of the constituent molecules.

At 37°C, the temperature of the bacterium can be converted to kelvins: 37°C + 273.15 = 310 K

We can then use the equation for the average kinetic energy of an ideal gas to find the translational kinetic energy per molecule:

[tex]E_k = \frac{3}{2} kT[/tex], where k is the Boltzmann constant ( [tex]1.38 x 10^{-23} J/K[/tex]) , T is the temperature in kelvins, and [tex]E_k[/tex] is the average kinetic energy per molecule.

For the water molecules, which make up 70% of the bacterium by weight, their average molecular mass is approximately 18 u, and for the other molecules, the average molecular mass is on the order of 10' u.

By assuming the bacterium has N molecules, we can find its total translational kinetic energy:

[tex]E_t = N \cdot E_k = N \cdot \frac{3}{2} \cdot k \cdot T = \frac{3}{2} \cdot k \cdot T \cdot N[/tex]

(mass of bacterium / average molecular mass)

Therefore, the total translational kinetic energy of all the molecules in an E. coli bacterium of mass [tex]2.0 * 10^{-15} kg[/tex]   at 37°C can be calculated as:

[tex]E_t = \frac{3}{2} * (1.38 x 10^{-23} J/K) * 310 K * (2.0 * 10^{-15} kg / (18 u * (10^{-3} kg/u) * 0.7 + (10^5 u * (10^{-3} kg/u) * 0.3))[/tex]

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The 4 V, 5 V, and 6 V equipotential lines between two parallel plates are evenly spaced.

Equipotential lines represent points in space that are at the same potential or voltage. In the context of two parallel plates, these lines would be perpendicular to the plates and would indicate the potential at different points between them.

If the 4 V, 5 V, and 6 V equipotential lines are evenly spaced, this means that the potential difference between the plates is uniform and the same at each of these points. This would occur if the electric field between the plates was uniform and the same in strength everywhere.

The uniformity of the electric field is due to the plates being parallel and of equal size, as well as the presence of a uniform electric charge on each plate. These conditions would lead to a uniform distribution of the electric field and the equipotential lines being evenly spaced.

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Kepler's second law states that a planet moves most quickly during perihelion and most slowly at aphelion. The orbit's total period (T) is related to the cube of the planet's average distance from the Sun (R).

According to Kepler's Second Law, as a planet rounds the Sun, an arbitrary vertical connecting them sweeps across the same amount of space at the same rate. In essence, this means that asteroids do not travel throughout their revolutions at a constant speed.

The speed of the planet as it travels through its elliptical orbit is governed by Kepler's second law. Kepler demonstrated that no matter where in the orbit the planet is, the region that it "sweeps out" over a period of time is the same.

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The electric field is directed away from the positive charge, so its direction is radially outward from the charge. The magnitude of the electric field is 9.29 x 10^5 N/C.

An electric field is a field that surrounds a charged particle or a collection of charged particles and can affect other charged particles in the vicinity. It is a vector field that represents the force that would be exerted on a test charge placed in that field. The strength of the electric field at a particular point is defined as the force per unit charge at that point.

The electric field (E) generated by a point charge (Q) at a distance (r) from the charge is given by Coulomb's law: E = k * Q / r^2, where k is Coulomb's constant (approximately equal to 8.99 x 10^9 N m^2/C^2). To find the magnitude and direction of the electric field 0.45 m from a +7.85 x 10^-9 C point charge, we can use the formula:

E = k * Q / r^2 = 8.99 x 10^9 N m^2/C^2 * 7.85 x 10^-9 C / (0.45 m)^2 = 9.29 x 10^5 N/C

Therefore, The electric field is directed away from the positive charge, so its direction is radially outward from the charge. The magnitude of the electric field is 9.29 x 10^5 N/C.

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The density of cube is 300000 kg/m^3.

We know that density of a substance is : Mass/volume

Given,

Mass = 51.84g = 51.84 / 1000 kg

Volume = 0.012* 0.012* 0.012 m^3

Putting these values in above equation we get;

Density =  300000 kg/m^3.

So the density of cube is  300000 kg/m^3.

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For the transistor model in the following figure, obtain the Thevenin equivalent is [tex]V_{th}[/tex]=-700V and [tex]R_{th}=5[/tex]kohm.

To find the Thevenin equivalent ,

By temporarily removing the load resistance from the original circuit and reducing what is left to an analogous circuit made up of a single voltage source and series resistance, Thevenin's theorem can simplify this analysis.

After reconnecting the load resistance to the Thevenin equivalent circuit, calculations can be performed as if the entire network were just a straightforward series circuit.

Now, the voltage given is 21V

[tex]R_{1}=3[/tex] kohm

[tex]R_{2}=5[/tex] kohm

as, V=ir

So, I=[tex]\frac{21}{R_{1} }[/tex]

I=[tex]\frac{21}{3}[/tex]

I=7mA

[tex]V_{th}[/tex]=-20I×[tex]R_{2}[/tex]

[tex]V_{th}[/tex]=-20×7×5

[tex]V_{th}[/tex]=-700V

and to find the value of [tex]R_{th}[/tex]

i=0A

20i=0 means it is short circuit.

[tex]R_{th}=R_{2}=5[/tex] kohm

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Earth's mass is approximately 81 times greater than the Moon's mass. Earth has a mass of approximately 5.97 x 10^24 kilograms, while the Moon has a mass of approximately 7.34 x 10^22 kilograms.

Why Earth's mass is more than Moon's mass?

Earth's mass is much greater than the Moon's due to its larger size and composition. Earth is a terrestrial planet with a dense iron-nickel core, while the Moon is a smaller, rocky satellite.

Earth's greater size allowed it to retain more heat and develop a stronger gravitational field, which in turn allowed it to retain more volatile elements and heavier elements that would have otherwise been lost to space. This led to a more massive planet with a much stronger gravitational pull, which makes it about 81 times more massive than the Moon.

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The acceleration of the elevator is 1.1 m/s^2.

We have given that when the elevator is at rest the scales reads 834 N.

So W = 834 N

Acceleration due to gravity , g = 9.8 m/s^2

We know that W = mg

So, m = 834/9.8 = 85.1 kg

Now as the elevator moves upward so effective acceleration = g+a

Scale reading W = 928 N and mass m = 85.1 kg.

So,

ma + mg = W

⇒ a + g = W/m

⇒ a + g = 928/ 85.1

⇒ a + g = 10.90

⇒ a = 10.90 - g

⇒ a = 10.90 - 9.80

⇒ a = 1.10 m/s^2

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The location of the CM of a system ( 0.5l , 0.25l )

x = (m1.x1 +m2.x2 +m3.x3) / ( m1 + m2 +m3)

x = ( m x 0 + m x 0 + 2m x l ) / ( m+m+2m)

x = 2m x l / 4m

x = 0.5 l

y = (m1 x y1 +m2 x y2 +m3 x y3) / ( m1 + m2 +m3)

y = (m x 0) + m x l + 2m x 0 ) / ( m + m + 2m )

y = m x l / 4m

y = 0.25 l

A position established in relation to an object or set of objects is the center of mass.

It represents the system's average location as weighted by each component's mass.

The center of mass for straightforward stiff objects with homogeneous density is found at the centroid.

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a) To construct an Energy-Interaction diagram, we first need to identify the energy sources and interactions involved in the scenario. The energy sources in this case are gravitational potential energy and kinetic energy. At the top of the hill, the skier has potential energy due to her height above the ground and kinetic energy due to her initial velocity of 10 m/s. As she skis down the slope, she loses potential energy and gains kinetic energy. At the middle flat part (10 m), the skier's velocity can be calculated using the conservation of energy principle. The change in potential energy is equal to the change in kinetic energy.

PEinitial = mgh = 55 x 9.8 x 10 = 5390 J

KEinitial = 0.5mv^2 = 0.5 x 55 x 10^2 = 275 J

PEfinal = mgh = 55 x 9.8 x 10 = 5390 J

KEfinal = 0.5mv^2

5390 - 275 = 5390 - 0.5mv^2

v^2 = 10780/55 = 196

v = sqrt(196) = 14 m/s

So the skier's velocity at the middle flat part (10 m) is 14 m/s.

b) To find the speed of the skier at the bottom of the hill (before she starts stopping), we need to again use the conservation of energy principle. The potential energy at the bottom of the hill is zero, and all of the skier's energy is in the form of kinetic energy.

PEinitial = mgh = 55 x 9.8 x 10 = 5390 J

KEinitial = 0.5mv^2 = 0.5 x 55 x 10^2 = 275 J

PEfinal = 0

KEfinal = 0.5mv^2

5390 - 275 = 0.5mv^2

v^2 = 5115/55 = 93

v = sqrt(93) = 9.64 m/s

So the skier's velocity at the bottom of the hill (before she starts stopping) is 9.64 m/s.

c) To predict the amount of snow melted by the skier while stopping, we need to calculate the amount of energy required to melt the snow. The energy required to melt the snow is given by the heat of fusion, which is the amount of energy required to change a substance from a solid to a liquid at its melting point. For water, the heat of fusion is 333.55 J/g. We also need to know the mass of snow melted, which can be calculated using the velocity of the skier just before she comes to a stop (9.64 m/s) and the conservation of energy principle.

PEinitial = 0

KEinitial = 0.5mv^2 = 0.5 x 55 x 9.64^2 = 257 J

PEfinal = 0

Q = KEinitial

Q = 257 J

m = Q/Lf = 257/333.55 = 0.766 g

So the skier melted 0.766 g of snow while stopping.

d) To solve for the amount of snow melted using a different interval, we could use the velocity of the skier at the middle flat part (10 m) instead of the velocity just before she comes to a stop. The calculation would be the same as in c), but with the velocity being 14 m/s instead of 9.64 m/s. This

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The direction of the net force on the charge at the top is downwards.

This is because the electric field created by the charge at the bottom exerts an electric force on the charge at the top, which is directed downwards. This electric force is greater than the force of gravity, which acts upwards, resulting in a net force directed downwards. This is a result of the inverse square law of electrostatics, which states that the force between two point charges is proportional to the inverse of their distance squared. Thus, the force between the charges is stronger when they are closer together, resulting in a net force directed downwards.

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The following are true:

The net electric field at any location inside a block of copper is zero if the copper block is in equilibrium.

The net electric field inside a block of metal is zero under all circumstances.

The electric field from an external charge cannot penetrate to the center of a block of iron.

Equilibrium in a conductor refers to a state where the electric field is zero inside the conductor and there is no net flow of mobile charged particles. The electric field from an external charge cannot penetrate to the center of a block of iron, meaning that the electric field is confined to the surface of the metal. The net electric field at any location inside a block of copper is zero if the copper block is in equilibrium, meaning that the electric field is uniform and balanced throughout the conductor. The net electric field inside a block of metal is zero under all circumstances, regardless of the presence of an external electric field. This is because the electric field inside a metal is always balanced and uniform, due to the movement of mobile charged particles within the conductor.

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The top speed of a cheetah is generally approximately 120 km/h (75 mph). However, this speed is only possible over short distances, usually around 460 meters (500 yards), and the cheetah may attain it in a matter of seconds. Its speed decreases after that distance as it becomes fatigued.

Speed is the pace at which an item moves along a route in time, whereas velocity is the rate and direction of movement. In other words, velocity is a vector, whereas speed is a scalar number. The pace at which an object's location changes in any direction. Speed is defined as the ratio of distance traveled to time spent traveling. The direction of movement of the body or item is defined by velocity. Speed is fundamentally a scalar number. Velocity is, in essence, a vector quantity. It is the pace at which distance changes. It is the displacement rate of change.

Here,

A cheetah's peak speed is usually around 120 km/h (75 mph). However, this speed is only achievable over short distances, often approximately 460 meters (500 yards), and the cheetah may reach this speed in a couple of seconds. Its speed slows after that distance as it tired.

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The coefficient of friction between a sandal and wood would be 0.5

In physics, what is a friction?

The force that prevents motion when the surfaces of two objects come into contact is known as friction. Friction lessens a machine's mechanical advantage, or, to put it another way, friction decreases the output to input ratio.

A coefficient of friction is a number that depicts the interaction between two objects and their typical response to one another. The resistive force of friction divided by the normal or perpendicular force pushing the objects together yields the coefficient of friction, which is a numerical value. Equation represents it as follows:

Coefficient of friction, μ = Ff /FN

                                      μ = 7/14

                                      μ = 0.5

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A student could find the total mass of copper produced by using production data, use density and volume, use chemical analysis, or consult an expert.

We can use several methods to find total mass of copper produced:

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The force exerted by b on a is given by 1.90N along the left.

Let the charge of the particle 'a' and 'b' be q and Q respectively.

Given,

The force exerted ([tex]F_{ab}[/tex]) when the two particles are at distance (d = 12.9 mm) is 2.66 N from a to b.

So, [tex]F_{ab} = \frac{kqQ}{d^2} \hat{x}[/tex] (along the right)

[tex]\implies F_{ab} \times d^2 = kqQ\\\implies kqQ = 2.66 N \times 12.9 mm\\\implies kqQ = 34.314 Nmm[/tex]

Now after the separation between them is 18 mm

The force on a due to b when the distance between them is (D = 18mm) is ([tex]F_{ba}[/tex])

i.e. [tex]F_{ba} = \frac{kqQ}{D^2}(-\hat{x})[/tex] (along the left)

[tex]\implies kqQ = -F_{ba}\times D^2 \\\implies 34.314 Nmm = -F_{ba} \times 18mm\\\implies F_{ba} = -1.90 N[/tex]

Hence the force exerted by b on a is given by 1.90N along the left.

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The acceleration due to gravity near the surface of the hypothetical planet is 9.79 m/s^2, which is the same as the acceleration due to gravity near the surface of the Earth.

The acceleration due to gravity near the surface of a planet is given by the formula:

g = G * M / R^2

where G is the gravitational constant (6.67 x 10^-11 Nm^2/kg^2), M is the mass of the planet, and R is the radius of the planet.

Since the mass of the hypothetical planet is the same as the Earth, we can use the mass of the Earth for M. The radius of the hypothetical planet is 1.98 times the radius of the Earth, so we can use the following for R:

R = 1.98 * 6380 km = 12618.4 km

We can now substitute these values into the formula for g:

g = 6.67 x 10^-11 Nm^2/kg^2 * 5.98 x 10^24 kg / (12618.4 x 10^3 m)^2

Simplifying this expression gives us:

g = 9.79 m/s^2

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The energy per degree of freedom of a gas particle at temperature 376K is 3/2 kT, where k is the Boltzmann constant and T is the temperature in Kelvin.

Hence, the energy per degree of freedom at 376K is 3/2 x 8.6173 x 10-5 x 376 = 0.007845 ev.

What is temperature?

Temperature is a physical quantity which measures the degree of hotness or coldness of an object. It is measured on the Celsius (°C), Fahrenheit (°F) or Kelvin (K) scales. Temperature is related to the amount of thermal energy in a system, and is an important factor in many fields of science, such as physics, chemistry, meteorology, and engineering. Temperature affects the rate of many chemical reactions, and is a key factor in the functioning of living organisms. It also plays an important role in the Earth's climate and weather pattern.

Therefore, energy per degree of freedom at 376K is 3/2 x 8.6173 x 10-5 x 376 = 0.007845 ev.

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A) the height the object reaches is 0.148 m.

B) the velocity of the object 0.380 seconds after release is 10.79 m/s.

a) To find the height the object reaches, we need to find the vertical component of velocity. We can use the following equation:

Vy = V0y + ayt

Where V0y is the initial vertical velocity (0 m/s, since the object was thrown from rest), a is acceleration due to gravity (-9.8 m/s^2), t is time (0.430 s), and Vy is the final vertical velocity.

Plugging in the values, we get:

Vy = 0 + (-9.8)(0.430) = -4.266 m/s

Next, we can find the height using the following equation:

y = V0yt + (1/2)at^2

Plugging in the values, we get:

y = (0)(0.430) + (1/2)(-9.8)(0.430)^2 = -0.148 m

So, the height the object reaches is 0.148 m.

b) To find the velocity of the object 0.380 seconds after release, we need to use the following equation:

V = V0 + at

Where V0 is the initial velocity (25.2 km/h converted to m/s), a is acceleration due to gravity (-9.8 m/s^2), and t is time (0.380 s).

Plugging in the values, we get:

V = 25.2 * 1000/3600 + (-9.8)(0.380) = 10.79 m/s

So, the velocity of the object 0.380 seconds after release is 10.79 m/s.

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