Find the angle measurements of the intersections for the two equations f(x) = 4x - 5 and g(x) = 2x^2 - 5.

Multiple answers

63
7 (This is one of the answers already)
20
76
90

Answer:

15

Step-by-step explanation:

3/5*25

Answer:

15 girls

Step-by-step explanation:

(3/5) x 25 = 15

Answer: The answer is A

Step-by-step explanation:

In the picture, model A shows 3 groups and in the 3 groups are 4 lines !

I'm bad explaining but I hope this helps .

Answer:

D 4x-y=1

Step-by-step explanation:

4x-y=1. (x=0 ,y= -1)

4(0)-(-1)= 1

0+1= 1

4x-y=1 (x=1 y=3)

4(1)-3=1

4-3=1

Answer:

A

Step-by-step explanation:

Step 1, setting variables:

We already know the exact height of the prism: 6 feet. We can set the unknown width as variable x, and length as x+2 (length is two feet more than width).

Step 2, writing equations:

Great! We have everything now. Let us write the equation by substituting our variables in:

[tex]V=l*w*h\\V=6w(w+2)\\[/tex]

Ok! Let us expand the equation:

[tex]V=6w^2+12w[/tex]

[tex]\fbox{A}[/tex]

I hope this helps! Let me know if you have any questions :)

Given:

In a right angle triangle ABC, [tex]m\angle C=90^\circ , a=4[/tex] and [tex]\sin A=\dfrac{1}{2}[/tex].

To find:

The length of the hypotenuse.

Solution:

It is given that [tex]m\angle C[/tex], so opposite side of this angle is the hypotenuse, i.e., c.

In a right angle triangle,

[tex]\sin \theta=\dfrac{Perpendicular}{Hypotenuse}[/tex]

In the given triangle,

[tex]\sin A=\dfrac{a}{c}[/tex]

Substituting the given values, we get

[tex]\dfrac{1}{2}=\dfrac{4}{c}[/tex]

By cross multiplication, we get

[tex]1\times c=4\times 2[/tex]

[tex]c=8[/tex]

Therefore, the length of the hypotenuse is 8 units.

Answer:

[tex]Range = 11[/tex]

[tex]\sigma^2 = 12.1[/tex]

[tex]\sigma = 3.5[/tex]

Step-by-step explanation:

Given

[tex]Data: 16,12,17,8,15,15,10,11,19,18[/tex]

Solving (a): Range

This is calculated as:

[tex]Range = Highest - Least[/tex]

Where:

[tex]Highest = 19[/tex]

[tex]Least = 8[/tex]

So:

[tex]Range = 19 - 8[/tex]

[tex]Range = 11[/tex]

Solving (b): The population variance

First, calculate the population mean using:

[tex]\mu = \frac{\sum x}{n}[/tex]

So:

[tex]\mu = \frac{16+12+17+8+15+15+10+11+19+18}{10}[/tex]

[tex]\mu = \frac{141}{10}[/tex]

[tex]\mu = 14.1[/tex]

So, the population variance is:

[tex]\sigma^2 = \frac{\sum(x - \mu)^2}{n}[/tex]

[tex]\sigma^2 = \frac{(16 - 14.1)^2 + (12 - 14.1)^2 +............... + (19- 14.1)^2 + (18- 14.1)^2}{10}[/tex]

[tex]\sigma^2 = \frac{120.9}{10}[/tex]

[tex]\sigma^2 = 12.09[/tex]

[tex]\sigma^2 = 12.1[/tex] --- approximated

Solving (c): The population standard deviation.

This is calculated as:

[tex]\sigma = \sqrt{\sigma^2[/tex]

[tex]\sigma = \sqrt{12.09[/tex]

[tex]\sigma = 3.5[/tex]

Answer:

C=$25+$15m

Step-by-step explanation:

C is Cost

m is 15 minutes

The price for a visit would be $25 + $15 times the amount of time they work on repairs.

The equation you could use to find the total cost of a repair visit is C=$25+$15m.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

It is given that:

The telephone company charges $25 for a service call, and $15 for every 15 minutes the service representative works on repairs.

Let C is Cost and m be 15 minutes

From the data given in the question:

C = 25 + 15m

Thus, the equation you could use to find the total cost of a repair visit is C=$25+$15m.

Learn more about the linear equation here:

brainly.com/question/11897796

#SPJ2

Step-by-step explanation:

answer in the image above

Answer: 17 and a half

Step-by-step explanation:

M    D    W

20  24  480

20   21  420

24   17 and a half  420

= 17 and a half

Answer:

t=3

Step-by-step explanation:

sorry if its incorrect i got it right on edgy.

Answer:

1) P = 282m, A = 141m^2

2) P = 82.4in, A = 40in^2

3) P = 62.7m, A = 73.1m^2

Step-by-step explanation:

1) top:L=12m, W=3m, mid: l= 12m, w= 12-7 = 5m, bot: l=15m, w=3m

Perimeter= 2(lw)

P = 2(12x3) + 2(12x5) + 2(15x3)

P = 2(36) + 2(60) + 2(45)

P = 72 + 120 + 90

P = 282m  

Area= lw

A = (12x3) + (12x5) + (15x3)

A = 36 + 60 + 45

A = 141m^2

2) Rectangle:l=7in, w=5in, Right Triangle:a=5-3=2in, b=12-7=5in

Perimeter= 2(lw) + (a+b+sqrt(a^2+b^2))

P = 2(7x5) + (2+5+sqrt(2^2+5^2))

P = 70 + 12.39

P = 82.4in

Area= lw + ((ab)/2)

A = (7x5) + ((2x5)/2)

A = 35 + 5

A = 40in^2

3) Semi-Circle: d=8m, r=8/2=4m, Right Triangle: a=8m, b=12m

Perimeter= pid + (a+b+sqrt(a^2+b^2))

P = 9pi + (8+12+sqrt(8^2+12^2))

P = 28.27 + 34.42

P = 62.7m

Area= (1/2)pir^2 + ((ab)/2)

A = (1/2)pir^2 + ((ab)/2)

A = (1/2)pi(4)^2 + ((8x12)/2)

A = 25.13 + 48

A = 73.1m^2

Answer:

,

Step-by-step explanation:

hear is your answer please give me Some thanks

9514 1404 393

Answer:

Step-by-step explanation:

The secondary voltage is proportional to the primary voltage. The constant of proportionality is the ratio of secondary turns to primary turns.

The secondary voltage is ...

  (200/500)(220 V) = 88 V

__

A transformer does not change the frequency.* The voltage in the secondary coil is still 50 Hz.

_____

* Most transformers are designed to operate as linear devices. It is possible to design a transformer (with special core material) that operates non-linearly, and/or that is "tuned" to a frequency other than the one exciting the primary. That is, the secondary voltage may be some harmonic of the primary voltage. This would be a relatively unusual application of a transformer, beyond the apparent scope of the question here.

a)rational number :

1)(3+4 )/2

=7/2 =3.5

2)(3.5+4)/2

=7.5/2 =3.25

b)irrational number :

1)10/3=3.33....

2)11/3=3.66....

......I hope it will help you. ..

Answer:

The real numbers, which can be represented by the ratio of two integer numbers, are called rational numbers, say P/Q where Q is not equal to zero.

The actual numbers that cannot be expressed as the two integer ratio are called irrational numbers.

Step-by-step explanation:

a)rational number :

1)

(3+4 )/2

=7/2 =3.5

2)

(3.5+4)/2

=7.5/2 =3.25

b)irrational number :

1)

10/3=3.33....

2)

11/3=3.66....

3)

√13

Answer:

P(66.4 < X < 241.6) = 0.5039 = 50.39%.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

A distribution of values is normal with a mean of 232.4 and a standard deviation of 92.2.

This means that [tex]\mu = 232.4, \sigma = 92.2[/tex]

Find the probability that a randomly selected value is between 66.4 and 241.6.

This is the p-value of Z when X = 241.6 subtracted by the p-value of Z when X = 66.4.

X = 241.6

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{241.6 - 232.4}{92.2}[/tex]

[tex]Z = 0.1[/tex]

[tex]Z = 0.1[/tex] has a p-value of 0.5398

X = 66.4

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{66.4 - 232.4}{92.2}[/tex]

[tex]Z = -1.8[/tex]

[tex]Z = -1.8[/tex] has a p-value of 0.0359

0.5398 - 0.0359 = 0.5039

P(66.4 < X < 241.6) = 0.5039 = 50.39%.

Answer:

Base=2 cm

Height=35 cm

or

Base=5 cm

Height=14 cm

Or

Base=7 cm

Height=10 cm

Or

Base=10 cm

Height=7 cm

Or

Base=14 cm

Height=5 cm

Or

Base=70 cm

Height=1 cm

Or

Base=35 cm

Height=2 cm

Or

Base=1 cm

Height=70 cm

Step-by-step explanation:

We are given that

Area of triangle=[tex]35cm^2[/tex]

We have to find the dimension of triangle.

We know that

Area of triangle=[tex]\frac{1}{2}\times base\times height[/tex]

Using the formula

[tex]35=\frac{1}{2}\times base\times height[/tex]

[tex]base\times height=35\times 2=70[/tex]

Factor of 70 :2,5,7,10,14,35,70

Therefore, the dimension could be

Base=2 cm

Height=35 cm

or

Base=5 cm

Height=14 cm

Or

Base=7 cm

Height=10 cm

Or

Base=10 cm

Height=7 cm

Or

Base=14 cm

Height=5 cm

Or

Base=70 cm

Height=1 cm

Or

Base=35 cm

Height=2 cm

Or

Base=1 cm

Height=70 cm

Answer:

8%

Step-by-step explanation:

Rate = 100×Interest ÷ Principal× Time

100× 2500/ 2500 × 8 = 800

800/100 = 8%

I hope this helps

9514 1404 393

Answer:

  14.4

Step-by-step explanation:

The Pythagorean theorem tells you ...

  7² +a² = 16²

  a² = 256 -49

  a = √207

  a ≈ 14.4

Answer:

StartFraction 25 divided by 1 Over 20 divided by 1 EndFraction = StartFraction 25 Over 20 EndFraction

Step-by-step explanation:

Number of trees = 25

Percentage of aok trees = 20%

To obtain the Number of oak trees :

(Number of trees ÷ 1) ÷ (percentage ÷1)

(25 / 1) ÷ (20 / 1) = (25 /1) * (20 / 1) = 25 / 20

StartFraction 25 divided by 1 Over 20 divided by 1 EndFraction = StartFraction 25 Over 20 EndFraction

Answer:

-80

Step-by-step explanation:

2x^2 + 3xy - 4y^2  

x = 2 | y = - 4

2(2)^2 + 3(2)(-4) - 4(-4)^2

2 * 4 + 3(2)(-4) - 4 * 16

8 - 24 - 64

-80

Answer:

The appropriate answer is "$12".

Step-by-step explanation:

As per the question,

Price per ticket,

= [tex]4+k[/tex]

Number of people,

= [tex]1800-90k[/tex]

Now,

The revenue (R) will be:

= [tex]Price \ per \ ticket\times Number \ of \ people[/tex]

By putting the values, we get

= [tex](4+k) (1800-9k)[/tex]

= [tex]-90k^2+1440k+7200[/tex]

or,

⇒ [tex]R'=1440-180k=0[/tex]

⇒                     [tex]180k=1440[/tex]

⇒                          [tex]k=\frac{1440}{180}[/tex]

                               [tex]=8[/tex]

hence,

The ticket price will be:

= [tex]4+k[/tex]

= [tex]4+8[/tex]

= [tex]12[/tex] ($)

Answer:

46

ayo how r u doin siahsvsgshsgsgsgsg

Answer:

80x⁴

Step-by-step explanation:

[tex](\frac{1}{ax} + 2ax^2)^5 = 5C_0(\frac{1}{ax})^5(2ax^2)^0 + 5C_1(\frac{1}{ax})^4(2ax^2)^1 + 5C_2(\frac{1}{ax})^3 (2ax^2)^2[/tex]

                           [tex]+ 5C_3 (\frac{1}{ax})^2(2ax^2)^3 + 5C_4(\frac{1}{ax})^1(2ax^2)^4 + 5C_5(\frac{1}{ax})^0(2ax^2)^5[/tex]

[tex]5C_0(\frac{1}{ax})^5(2ax^2)^0 =1 \times (\frac{1}{ax})^5 \times 1 = \frac{1}{a^5x^5}\\\\5C_1(\frac{1}{ax})^4(2ax^2)^1 = 5 \times (\frac{1}{ax})^4 \times (2ax^2)^1 = 10 ax^2 \times \frac{1}{a^4x^4} = \frac{10}{a^3x^2}\\\\5C_2 (\frac{1}{ax})^3 (2ax^2)^2= 10 \times (\frac{1}{ax})^3 \times (2ax^2)^2 = 10 \times \frac{1}{a^3x^3} \times 4a^2x^4 = \frac{40x}{a}\\\\5C_3 (\frac{1}{ax})^2 (2ax^2)^3 = 10 \times (\frac{1}{ax})^2 \times (2ax^2)^3 = 10 \times \frac{1}{a^2x^2} \times 8a^3 x^6 = 80ax^4\\\\[/tex]

[tex]5C_4(\frac{1}{ax})^1(2ax^2)^4 = 5 \times \frac{1}{ax} \times 16a^4x^8 = 80a^3x^7\\\\5C_5(\frac{1}{ax})^0(2ax^2)^5 = 1 \times 1 \times 32a^5x^{10}[/tex]

The fourth term of the expansion has the constant a,

the coefficient of a is 80x⁴

Answer:

Triangle has 180 degrees

Squares have 360 degrees

Step-by-step explanation:

4(-3)-5y=12

-12-5y=12

-5y=12+12

-y= 24/5

y= -24/5

y= -4⅕

hope it helps

Answer:

b = 7 inches and l = 12 inches

Step-by-step explanation:

Given that,

The area of a rectangle, A = 84 sq inches

Let the width is b.

Length = (5+b)

The area of a rectangle is given by :

A = lb

So,

[tex]84=b\times (5+b)\\\\b^2+5b-84=0\\\\(b-7)(b+12)=0\\\\b=7\ in, b =-12\ in[/tex]

Neglecting negative value,

b = 7 inches

Length, l = 5+b = 5+7

l = 12 inches

Answer:

A.

D needs to be equal or more to 260

Answer:

The correct option is A

Step-by-step explanation: