Find ∠MPN

Help me please

Answer:

try 4

Step-by-step explanation:

basically need to find number that when multiplied 3 times equals 64 so 4*4*4=64

Answer:

255 is the answer

Step-by-step explanation:

Divide 765 by 3 and the answer will come .

Hope it will help u

Answer:

From what I learn it is 360 degrees

Answer:

sorry i cannot help you

Step-by-step explanation:

simply take the average of the x and y coordinates

Answer:

Same side interior angles

Step-by-step explanation:

Same side interior angles are interior angles and on the same side. Sorry don't know how to better explain.

Answer:

first step - make x² the subject of the formula

x² = 25

second step :

find the square root of both sides

√x² = √25

x = 5

Step-by-step explanation:

Answer:

13.86

Step-by-step explanation:

In ∆ ABC ,

Answer:

y = -7x - 11

Step-by-step explanation:

Answer:

In order:

Distributive Property

Subtraction Property of Equality

Division Property of Equality or Reciprocal Property

Step-by-step explanation:

Answer:

I believe the answer should be 0 to -1

Step-by-step explanation:

the range of a function is the lowest y value to the highest y value of that function. so in that example, the lowest y value you have on that curved line is at 0, and the highest y value you have on that curved line is 1, so the range should be from 0 to 1, or {0, 1}.

Answer:

58

Step-by-step explanation:

Answer:

11. B.

12. C.

13. A.

14. D.

Step-by-step explanation:

for 11: we know that angles D and J are congruent from the tick marks, we also know that ∠FKD and ∠LKJ are congruent (vertical angles are congruent) therefore we need the sides between them

for 12: we know that ∠STU and ∠TUG are congruent, we also know that line TU is congruent to TU (reflexive property), therefore we need the angles adjacent to the first angles listed.

for 13: we know that ∠PQR and ∠CQR are congruent, we also know that lines RQ and RQ are congruent (reflexive property), therefore we need the other angles to which line RQ is between.

for 14: we know ∠B is congruent to ∠T and line AB is congruent to line ZY. therefore the angle cannot be connected to lines AB and ZY.

Step-by-step explanation:

hope it is helpful to you ☺️

Answer:

74.8% approximately

Step-by-step explanation:

Area of circle is pi×r^2=pi×4^2=16pi=50.27 approximately

Area of pentagon (assumption regular pentagon)=5/2×apothem×side length=5/2(3.2)(4.7)=37.6

So the probability that it lands in the red is 37.6/50.27 approximately =74.8% approximately

Answer:

Option C.

Step-by-step explanation:

For a given set of N elements:

{x₁, x₂, ..., xₙ}

The mean is given by:

[tex]M = \frac{x_1 + x_2 + ... + x_n}{N}[/tex]

And the variance is given by:

[tex]v = \frac{(x_1 - M)^2 + (x_2 - M)^2 + ... + (x_n - M)^2}{N}[/tex]

Then for our set:

{70, 80 ,75, 75, 80}

We have 5 elements, then N = 5

The first thing we need to find is the mean.

[tex]M = \frac{70 + 80 + 75 + 75 + 80}{5} = 76[/tex]

Then the variance will be:

[tex]v = \frac{(70 - 76)^2 + (80 - 76)^2 + (75 - 76)^2 + (75 - 76)^2 + (80 - 76)^2}{5} = 14[/tex]

The correct option is C, 14.

Answer:

D

Step-by-step explanation:

let y = f(x) and rearrange making x the subject

y = 2x - 10 ( add 10 to both sides )

y + 10 = 2x ( divide both sides by 2 )

[tex]\frac{y+10}{2}[/tex] = x

Change y back into terms of x with x = [tex]f^{-1}[/tex] (x) , then

[tex]f^{-1}[/tex] (x) = [tex]\frac{x+10}{2}[/tex] = [tex]\frac{1}{2}[/tex] x + 5 → D

Answer:

0.64 feet or 7.68 inches of snow on average over the 5 days.

Step-by-step explanation:

3.2/5

0.64ft

7.68in.

Answer:

Step-by-step explanation:

The youth shirt is 12 dollars

The adult shirt is 15 dollars

So the number of adult shirts is x

The number of youth shirts   is y

15 x + 12y = 489

You are not asked to solve this. You are just asked to find it.

Answer:

Procedure:

1) Form a system of 3 linear equations based on the two zeroes and a point.

2) Solve the resulting system by analytical methods.

3) Substitute all coefficients.

Step-by-step explanation:

A quadratic function is a polynomial of the form:

[tex]y = a\cdot x^{2}+b\cdot x + c[/tex] (1)

Where:

[tex]x[/tex] - Independent variable.

[tex]y[/tex] - Dependent variable.

[tex]a[/tex], [tex]b[/tex], [tex]c[/tex] - Coefficients.

A value of [tex]x[/tex] is a zero of the quadratic function if and only if [tex]y = 0[/tex]. By Fundamental Theorem of Algebra, quadratic functions with real coefficients may have two real solutions. We know the following three points: [tex]A(x,y) = (r_{1}, 0)[/tex], [tex]B(x,y) = (r_{2},0)[/tex] and [tex]C(x,y) = (x,y)[/tex]

Based on such information, we form the following system of linear equations:

[tex]a\cdot r_{1}^{2}+b\cdot r_{1} + c = 0[/tex] (2)

[tex]a\cdot r_{2}^{2}+b\cdot r_{2} + c = 0[/tex] (3)

[tex]a\cdot x^{2} + b\cdot x + c = y[/tex] (4)

There are several forms of solving the system of equations. We decide to solve for all coefficients by determinants:

[tex]a = \frac{\left|\begin{array}{ccc}0&r_{1}&1\\0&r_{2}&1\\y&x&1\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }[/tex]

[tex]a = \frac{y\cdot r_{1}-y\cdot r_{2}}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x+x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}[/tex]

[tex]a = \frac{y\cdot (r_{1}-r_{2})}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x +x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}[/tex]

[tex]b = \frac{\left|\begin{array}{ccc}r_{1}^{2}&0&1\\r_{2}^{2}&0&1\\x^{2}&y&1\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }[/tex]

[tex]b = \frac{(r_{2}^{2}-r_{1}^{2})\cdot y}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x +x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}[/tex]

[tex]c = \frac{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&0\\r_{2}^{2}&r_{2}&0\\x^{2}&x&y\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }[/tex]

[tex]c = \frac{(r_{1}^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1})\cdot y}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x + x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}[/tex]

And finally we obtain the equation of the quadratic function given two zeroes and a point.

Answer:

42

Step-by-step explanation:

Perimeter is [tex]2l+2w[/tex]

Answer: 42

Hope this helped! Please mark brainliest :)

Answer:

[tex]m \angle A = m \angle C[/tex] by reason [tex]\overline{AB} \cong \overline{BC}[/tex] and [tex]m \angle B = m \angle M = m \angle P[/tex].

[tex]\triangle AMO \cong \triangle CPO[/tex] SAS Theorem

Step-by-step explanation:

We proceed to demonstrate the statement by Geometric means:

1) [tex]\overline{AB} \cong \overline{BC}[/tex], [tex]\overline {AM} \cong \overline {PC}[/tex], [tex]m\angle AMO = m\angle CPO[/tex] Given.

2) [tex]\frac{AM}{AB} = \frac{PC}{BC}[/tex] Proportionality.

3) [tex]\frac{AM}{AM + MB} = \frac{PC}{BP + PC}[/tex] Definition of line segments.

4) [tex]\frac{1}{1+\frac{MB}{AM} } = \frac{1}{\frac{BP}{PC}+1}[/tex] Algebra.

5) [tex]\frac{BP}{PC} + 1 = 1 +\frac{MB}{AM}[/tex] Algebra.

6) [tex]\frac{BP}{PC} = \frac{MB}{AM}[/tex] Algebra.

7) [tex]BP = BM[/tex] By 1)

8) [tex]m \angle B = m \angle M = m \angle P[/tex] By 1), 7)

9) [tex]\triangle AMO \sim \triangle ABC[/tex], [tex]\triangle CPO \sim \triangle ABC[/tex] By 1), 7), 8). Defintion of simmilarity.

10) [tex]\frac{AM}{MO} = \frac{AB}{BC}[/tex], [tex]\frac{PO}{PC} = \frac{AB}{BC}[/tex] Definition of proportionality.

11) [tex]\frac{AM}{MO} = \frac{PO}{PC}[/tex] Algebra.

12) [tex]AM^{2} = PO\cdot MO[/tex] Algebra.

13) [tex]PO = MO[/tex] By 12) and Algebra.

14) [tex]\overline{PO} \cong \overline{MO}[/tex] By 13).

15) [tex]\triangle AMO \cong \triangle CPO[/tex] SAS Theorem/Result.

Answer:

y= (3/2)x-3

Step-by-step explanation:

We need two points to find the equation of a line. Let's take (2,0) and (4, 3).

In the equation y=mx+b, m represents the slope. To find the slope, we can calculate the change in y/change in x. For (2,0) and (4,3), the change in y is 3-0=3 and the change in x is 4-2=2. Therefore, our slope is 3/2.

Then, in the equation y=mx+b, we can plug 3/2 in for m to get y = (3/2)x+b. To find b, we can plug one point in, such as (2.0), to get 0=(3/2)(2) + b, 0=3+b, and b=-3, making our equation

y= (3/2)x-3

Answer:

the answer is C

Step-by-step explanation:

Answer:

3,082,000

Step-by-step explanation:

THE ANSWER IS 3,082,000 HOPE IT HELPS

Answer:

It should be B,  180 cm

Step-by-step explanation:

x = circumference of  circle D

18/360 = 9/x

9*360 = 18x

9*360/18 = x

x = 180

Answer:

Yes

Step-by-step explanation:

The question states that...

[tex]x=2\\y=2[/tex]

[tex]2\leq 4(2)-6\\2\leq 8-6\\2\leq 2[/tex]

Yes

Hope this helped! Please mark brianliest :)

Answer:yes

Step-by-step explanation:

Y<_4x-6

2<_4(2)-6

2<_8-6

2<_2

Answer:

31.80°

Step-by-step explanation:

In ∆ ABC :-