Answer: I hope this helped!
Step-by-step explanation:
.
the tree nearest the house is our starting point. our point person is taking the clinometer reading 15.24 meters from the tree's base and they get a reading of 237`. our point person is 1.83 meters in height. how tall is the tree, rounded to the nearest meter?
he tree nearest the house is our starting point. Our point person is taking the clinometer reading 15.24 meters from the tree's base and they get a reading of 237`. Our point person is 1.83 meters in height.
How tall is the tree, rounded to the nearest meter?The height of the tree can be determined by using the tangent formula. The tangent formula is tan θ = h/d where θ = angle of elevation, h = height of the object, and d = horizontal distance.
The clinometer reading is the angle of elevation. Hence, we can use the given data to determine the height of the tree.The point person is standing at 15.24 m from the base of the tree. Therefore, the horizontal distance (d) is 15.24 m. The angle of elevation (θ) is 237 degrees (given in the question).
Convert the degrees to radians as tan function uses radians. Convert degrees to radians:[tex]237 × (π/180) = 4.135[/tex]radians.Now we can use the tangent formula to determine the height of the tree:tan θ = h/dtan 4.135 = [tex]h/15.24h = 15.24 × tan 4.135h = 15.24 × 0.07311h ≈ 1.1132[/tex] metersThe height of the tree is 1.1132 meters. But, we have to round the answer to the nearest meter. Therefore, the height of the tree, rounded to the nearest meter, is 1 meter.
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Calculator may be used to determine the final numeric value, but show all steps in solving without a calculator up to the final calculation. The surface area A and volume V of a spherical balloon are related by the equation A’ = 364V? where A is in square inches and Vis in cubic inches. If a balloon is being inflated with gas at the rate of 18 cubic inches per second, find the rate at which the surface area of the balloon is increasing at the instant the area is 153.24 square inches and the volume is 178.37 cubic inches
In the equation A’ = 364V relating the surface area A and the volume V of a spherical balloon. We are also given that the volume is increasing at a rate of 18 cubic inches per second.so the rate at which the surface area of the balloon is increasing is 6552 square inches per second
We want to find the rate at which the surface area is increasing when A = 153.24 square inches and V = 178.37 cubic inches.
To find the rate of change of A with respect to time, we can use the chain rule of differentiation:
dA/dt = dA/dV × dV/dt
We know that dV/dt = 18 cubic inches per second, so we just need to find dA/dV and then we can find dA/dt.
To find dA/dV, we differentiate the equation A’ = 364V with respect to volume V:
dA/dV = 364
Now we can find dA/dt:
dA/dt = dA/dV × dV/dt ⇒ 364 × 18 ⇒ 6552 square inches per second
So the rate at which the surface area of the balloon is increasing is 6552 square inches per second when A = 153.24 square inches and V = 178.37 cubic inches.
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Use the equation, 8^2x = 32^x+3, to complete the following problems.
(a) Rewrite the equation using the same base.
(b) Solve for x. Write your answer in simplest form.
Given: ,8^2x= 32^x+3
a: (2³)^2x = (2⁵)^x+3
b: Solving, we get
2^6x = 2^5x+15
Since bases are same, we have
=>6x=5x+15
=> x = 15
Determine whether the statement is true or false. If it is false, rewrite it as a true statement. A sampling distribution is normal only if the population is normal. Choose the correct answer below. A. The statement is true. B. The statement is false. A sampling distribution is normal only if n≥30. C. The statement is false. A sampling distribution is normal if either n≥30 or the population. D. The statement is false. A sampling distribution is never normal.
A sampling distribution is normal only if the population is normal. This statement is false because A sampling distribution is normal only if n≥30.
If the underlying population is normally distributed, the sampling distribution (such as the sample mean distribution, also known as the xbar distribution) is also normally distributed. Even though the population is not normally distributed, the x(bar) distribution is approximately normal if n > 30, due to the central limit theorem. Some textbooks may use values above 30, but after a certain threshold the x(bar) distribution is effectively "normal".
Option B is close, but misses the normal population part. n > 30 is not necessary if we know the population is normal.
A sampling distribution is the probability distribution of a statistic obtained from a large number of samples drawn from a particular population. The sampling distribution for a given population is the frequency distribution of a range of different outcomes that can occur in the population.
In statistics, a population is the entire basin from which a statistical sample is drawn. A population can refer to an entire population of people, objects, events, hospital visits, or measurements. Thus, a population can be said to be a global observation of subjects grouped by common characteristics.
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You are dealt five cards from a standard deck of 52 playing cards (A full house consists of three of one kind and two of another. For example, A A A 5-5 and K-K-K 10-10 are full houses) (a) in how many ways can you get a full house? ______ Ways (b) in how many ways can you get a five card combination containing two jacks and three aces ___ ways
The 32 ways to get a five-card combination containing two jacks and three aces.
(a) A full house consists of three of one kind and two of another kind. Therefore, there are 13 different choices for the rank of the triplet and 4 cards of the same rank. Once the triplet has been chosen, there are 12 choices for the rank of the pair and 4 cards of the same rank. Therefore, the number of ways to get a full house is as follows:$${13}{\times}{4}{\times}{12}{\times}{4}={7488}$$Therefore, there are 7488 ways to get a full house.(b) In this case, the two jacks and three aces must be chosen out of the 4 jacks and 4 aces in the deck. Therefore, the number of ways to get a five-card combination with two jacks and three aces is as follows:$$\frac{{4\choose2}{4\choose3}{44\choose0}}{5!}={32}$$Therefore, there are 32 ways to get a five-card combination containing two jacks and three aces.
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a farmer has 600 yards of fencing to enclose a rectangular garden. express the area a of the rectangle as a function of the width x of the rectangle. what is the domain of a?
a. a(x) = -x^2 + 6000x, Domain = {x|0 < x < 6000 }
b. a(x) = -x^2 + 300x, Domain = {x|0 < x < 300 }
c. a(x) = x^2 + 300x, Domain = {x|0 < x < 300 }
d. a(x) = -x^2 + 300x, Domain = {x|0 < x < 6000 }
The domain ofA is Answer: "d. [tex]a(x) = -x^2 + 300x[/tex], Domain = {x|0 < x < 6000 "}
A farmer has 600 yards of fencing to enclose a rectangular garden. The area A of the rectangle as a function of the width x of the rectangle can be expressed as follows:
[tex]A = x(300 - x) = 300x - x^{2}[/tex]
The domain of A is given by the interval of values of x that can be chosen for the width of the rectangle. The width of a rectangle must be positive, so we have 0 < x. If the farmer has 600 yards of fencing, we can get the maximum value of x as follows:
600 = 2x + 300x = 600/3 = 200
So we have x < 200.
Therefore, the domain of A is {x | 0 < x < 200}.
Rewriting the equation of A, we get:
A(x) = -x² + 300x, Domain = {x | 0 < x < 200}.
In yards, the answer would be {x | 0 < x < 6000}.
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A production facility contains two machines that are used to rework items that are initially defective. Let X be the number of hours that the first machine is in use, and let Ybe the number of hours that the second machine is in use, on a randomly chosen day. Assume that X and Y have joint probability density function given by 3. f(x) = { 3/2(x^2 +y^2) 0
Answer:
Step-by-step explanation:
Function P represents the perimeter, in inches, of a square with the side length x inches.P = x + x + x + x ... but it would be more efficient to write it this way: P =4xComplete the table.x 0 1 2 3 4 5 6P(x) 0
Function P represents the perimeter, in inches, of a square with the side length x inches. So, the perimeter of a square can be represented as P = x + x + x + x, which simplifies to P = 4x. This way is more efficient to write than the former.
Complete the table provided: x 0 1 2 3 4 5 6 P(x) 0 4 8 12 16 20 24. When x = 0, the perimeter of the square is 0.When x = 1, the perimeter of the square is P = 4(1) = 4. When x = 2, the perimeter of the square is P = 4(2) = 8. When x = 3, the perimeter of the square is P = 4(3) = 12. When x = 4, the perimeter of the square is P = 4(4) = 16. When x = 5, the perimeter of the square is P = 4(5) = 20. When x = 6, the perimeter of the square is P = 4(6) = 24.
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Find the greatest common factor and the least common multiple of the following terms. Submit all
solution steps and your final answers to earn full credit.
8a³b5
16a²b7
Answer:
To find the greatest common factor, we need to find the largest factor that divides both terms evenly. We can factor each term as follows:
8a³b5 = 2³ * a³ * b5
16a²b7 = 2⁴ * a² * b7
The greatest common factor is the product of the lowest exponent of each prime factor that appears in both terms. Therefore, the greatest common factor is:
GCF = 2³ * a² * b5 = 8a²b5
To find the least common multiple, we need to find the smallest multiple that both terms share. We can start by writing out the prime factorization of each term:
8a³b5 = 2³ * a³ * b5
16a²b7 = 2⁴ * a² * b7
The least common multiple is the product of the highest exponent of each prime factor that appears in either term. Therefore, the least common multiple is:
LCM = 2⁴ * a³ * b7 = 16a³b7
So, the greatest common factor is 8a²b5 and the least common multiple is 16a³b7.
Find the area of the shaded region.
80°
5 cm
A=[?] cm2
Enter a decimal rounded to the nearest tenth.
From the given information provided, the area of the shaded region inside the circle is 22.58
The area of a triangle is defined as the total space occupied by the three sides of a triangle in a 2-dimensional plane.
The space enclosed by the sector of a circle is called the area of the sector.
the radius of the circle is 5cm.
area of arc = radius² × θ/2
area of the arc is = 5² × 4π/9 = 25 × 4/9 = 34.88
area of the triangle inside circle = a×b × sin(y)/2
area of triangle = 5×5 × sin(80°)/2 = 25 × 0.492
area = 12.3
area of the shaded region is = 34.88 - 12.3 = 22.58
Hence, the area of the shaded region is 22.58
Question - Find the area of the shaded region in the circle if the angle of the arc is 80 degree radius is 5cm.
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I NEED HELP PLEASE !!
can i also get an easy explanation so i can know how to do the other problems pls
Answer:
Proofs attached to answer
Step-by-step explanation:
Proofs attached to answer
4.1.60-(15)+(-13 4.2.-2(3)+27 ÷(-3)
Answer:
-15
Step-by-step explanation:
4.1.60 - (15) + (-13) = 32
4.2. -2(3) + 27 ÷ (-3) = -2(3) - 9 = -15
Which of these planes is NOT in the {100} family for a tetragonal crystal? (A tetragonal unit cell drawn to proportion is included below for reference.)(A) (010)(B) (001)(C) (110)(D) Both B & C(E) All of these planes are in the {100} family.
The answer is (001). This is because B (001) has h and k as non-zero integers, which does not match the criteria for the {100} family.
The question is asking which of the planes (A), (B), (C), and (D) is not part of the {100} family for a tetragonal crystal.A tetragonal crystal is a three-dimensional structure made up of four faces that intersect at right angles, forming a unit cell. Each face of the unit cell is defined by a Miller index. A Miller index is a set of three integers written in the form {hkl}, which describes the orientation of the face relative to the crystal lattice. In a tetragonal crystal, the {100} family is the set of faces described by {hkl} such that h = k = 0 and l ≠ 0.
Therefore, A (010), C (110), and E (all of these planes are in the {100} family) are all part of the {100} family for a tetragonal crystal, while B (001) is not. because B (001) has h and k as non-zero integers, which does not match the criteria for the {100} family. In conclusion, the correct answer to the question is B (001).
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A fast food restaurant estimate that 45% of their customers buy drinks with their purchases. Last week, 6200 customers did not buy soft drinks. How may customers do they have?
A fast food restaurant estimate that 45% of their customers buy drinks with their purchases. Last week, 6200 customers did not buy soft drinks. They have a total of 11272 customers.
when in a percentage we take 100%
if 45% take soft drinks with their purchases
then the other 55% did not take soft drinks with their purchases
therefore, we have 6200 customers who did not buy soft drinks with their purchases.
now we know that 11272 are there total customers
therefore, now we have to subtract 6200 from 11272
we get 5072.
therefore 5072 customers who buy soft drinks with their purchases.
A fast food restaurant estimate that 45% of their customers buy drinks with their purchases. Last week, 6200 customers did not buy soft drinks. They have a total of 11272 customers
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Please help. Need answer ASAP!
Answer: 11
Step-by-step explanation:
Turn it into an improper fraction so 8 from 8 1/4 to 33/4
Then just divide by 3/4
This will give you 11
uessing on an exam: in a multiple choice exam, there are 5 questions and 4 choices for each question (a, b, c, d). nancy has not studied for the exam at all and decides to randomly guess the answers. what is the probability that: (please round all answers to four decimal places)
In a multiple choice exam, there are 5 questions and 4 choices for each question (a, b, c, d). nancy has not studied for the exam at all and decides to randomly guess the answers, the probability that Nancy will correctly answer all 5 questions by guessing is 0.000977
How to calculate the probability?In a multiple choice exam, there are 5 questions and 4 choices for each question (a, b, c, d). Nancy has not studied for the exam at all and decides to randomly guess the answers.
The probability of guessing on an exam can be calculated by using the formula:n(C)/(n(T))where n(C) is the number of favorable events and n(T) is the total number of events. Let's solve the given problem:
Probability of getting the first question correct: P (1st) = 1/4 Probability of getting the second question correct: P (2nd) = 1/4Probability of getting the third question correct: P (3rd) = 1/4 Probability of getting the fourth question correct: P (4th) = 1/4Probability of getting the fifth question correct: P (5th) = 1/4 The probability of guessing all questions correctly can be calculated by multiplying the probability of each question together. P (all) = P (1st) * P (2nd) * P (3rd) * P (4th) * P (5th)= 1/4 * 1/4 * 1/4 * 1/4 * 1/4= 1/1024Therefore, the probability that Nancy will correctly answer all 5 questions by guessing is 0.000977. (rounded to four decimal places)Answer: 0.000977
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PLEASE !! HELP i’ve been on this question for a while
Answer:
y = - [x - 1] + 2
Step-by-step explanation:
I think this is right
Im sorry if not :)
If the radius of the circle is 8 cm, what would the area of the square that is around it be? Use 3.14 as π.
Answer: 201.06
Step-by-step explanation:
A=πr2=π·8^2≈201.06193
Lara opened a savings account 1 year ago. The account earns 11% interest, compounded
continuously. If the current balance is $7,000.00, how much did she deposit initially?
Round your answer to the nearest cent.
As a result, Lara made a $6,262.71 initial deposit into her savings account.
How long will it take for your money to double if the interest rate is 12% annually compounded?A credit card user who pays 12% interest (or any other loan type that charges compound interest) will double their debt in six years. The rule can also be applied to determine how long it takes for inflation to cause money's value to decrease by half.
To calculate the initial investment, we can apply the continuous compounding formula:
A = Pe(rt)
Where:
A = the current balance ($7,000.00)
P = the initial deposit (unknown)
r = the annual interest rate (11% or 0.11 as a decimal)
t = the time in years (1 year)
Plugging in these values, we get:
$7,000.00 = Pe(0.11 * 1)
A shorter version of the exponential expression:
$7,000.00 = Pe0.11
$7,000.00 = P * 1.1166 (rounded to 4 decimal places)
Dividing both sides by 1.1166:
P = $6,262.71 (rounded to the nearest cent)
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Solve each equation for the other variable. (Hint: This will involve rewriting each equation in exponential form at some step in the process.)
a. y = log6(X)
b. X = log2(y/21)
The solution for the other variable, according to the stated statement, is[tex]X = 6^y[/tex] and [tex]y = 21 * 2^X[/tex]
What is an exponential number?Exponential numbers are represented by an, where an is multiplied by itself n times. An easy example is 8=2³=222. In exponential notation, an is known as the base, whereas n is known as the power, exponent, or index. Scientific notation is an example of an exponential number, with 10 usually typically serving as the base number.
Why is the term exponential used?Exponential functions are often employed in the biological sciences to describe the amount of a certain quantity over time, such as population size. Experiment data graphs are often created with time on the x-axis and amount on the y-axis.
a. y = log6(X)
[tex]6^y = X[/tex]
[tex]X = 6^y[/tex]
b. [tex]X = log2(y/21)[/tex]
[tex]2^X = y/21[/tex]
[tex]21 * 2^X = y[/tex]
[tex]y = 21 * 2^X[/tex]
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The neck of a gifaffe is 4 1/2 feet in length. Its neck is 30 perocent of it height whats the higet of the giffae
The giraffe is 15 feet tall based on the relation between the length of neck of giraffe and it's height.
Firstly convert the mixed fraction to fraction.
Length of neck of giraffe = (4×2)+1/2
Length of neck = 9/2 feet
Now, let us assume the height of giraffe be x. So, equation will be -
30% × x = 9/2
Rewriting the equation
30/100 × x = 9/2
Cancelling zero
3x/10 = 9/2
Again rewriting the equation
x = 90/6
Performing division on Right Hand Side of the equation
x = 15 feet
Thus, height of giraffe is 15 feet.
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leila is on her way home in her car. She has driven 30 miles so far, which is one-third of the way home. what is the total length of her drive.
Answer:
90 miles
Step-by-step explanation:
We know
She has driven 30 miles so far, which is one-third of the way home.
What is the total length of her drive?
We Take
30 x 3 = 90 miles
So, the total length of her drive is 90 miles.
Thirty-six percent of adult Internet users have purchased products or services online. For a random sample of 200 adult Internet users, find the mean, variance, and standard deviation for the number who have purchased goods or services online. Round your answer to one decimal place.
The mean, variance, and standard deviation for those who have purchased online goods or services are 72, 46.08, and 6.8, respectively.
That 36% of adult internet users have purchased products or services online and for a random sample of 200 adult internet users, we need to find the mean, variance, and standard deviation for the number who have purchased goods or services online.
Mean: Mean, μ = n * p = 200 * 0.36= 72Variance: Variance, σ² = n * p * q = 200 * 0.36 * 0.64= 46.08Standard Deviation: Standard Deviation, σ = √n * p * q= √(200 * 0.36 * 0.64)= 6.8Therefore, the mean, variance, and standard deviation for the number who have purchased goods or services online are 72, 46.08, and 6.8, respectively.
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Solve the following proportion for y. 13 11 8 y Round your answer to the nearest tenth. 1 X Ú
Answer:
Were sorry! Answer is not available right now check in later.
Step-by-step explanation:
12x²+11x-56 box method
The product of (4x + 7) and (3x - 8) is 12x² + 7x - 56.
WHAT IS BOX METHOD ?
The box method, also known as the grid method, is a visual method used to multiply two numbers or two binomials. It involves creating a grid or box and filling it in with the products of the digits in each row and column. The method works for both single-digit and multi-digit numbers.
To use the box method for multiplying two numbers, we draw a box with two rows and two columns. We write one number along the top row and the other number along the left column. Then, we multiply the digits in each row and column and write the products in the corresponding cell of the box. Finally, we add the numbers in each cell of the box to get the product of the two numbers.
The box method can be used to multiply two binomials, such as (4x + 7) and (3x - 8). To use the box method, we draw a box with four cells, and we write the two binomials along the top and left sides of the box, like this:
| 4x | 7
-------------------
3x | |
-------------------
| |
Then, we fill in the four cells of the box by multiplying the corresponding terms. For example, the top-left cell is filled by multiplying 4x and 3x, which gives 12x². The other cells are filled in a similar way:
| 4x | 7
-------------------
3x | 12x² | 28x
-------------------
| -21x | -56
Next, we combine the terms in each row and column of the box, and write the final answer as the sum of these terms:
12x² + 28x - 21x - 56
Simplifying this expression gives:
12x² + 7x - 56
Therefore, the product of (4x + 7) and (3x - 8) is 12x² + 7x - 56.
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The obtuse angle between the hands of a clock at 2.30 a.m. is
Answer: 105
Step-by-step explanation:
OBTUSE ANGLE (105°) IS FORMED AT 2:30 IN THE CLØCK.
As we know 12 division OF 360° CIRCLE GIVES 30°
AT TWO PM THE ANGLE BETWEEN HOUR AND MINUTE HAND IS 60° AFTER 30 MIN ARM ROTATES 180° AND HOUR ARM 30°/2 = 15°
SO THE ANGLE BETWEEN TWO ARMS IS (180-(60-15)
105
During one season of racing at the Talladega Superspeedway, the mean speed of the cars racing there was found to be 158.9 mph with a standard deviation of 6.7 mph. What speed represents the 30th percentile for speeds of race cars at Talladega? Assume that the racing speeds are normally distributed.
Solution:Given, the mean speed of the cars racing = 158.9 mph standard deviation = 6.7 mph
To find:What speed represents the 30th percentile for speeds of race cars at Talladega?
We need to find the z-score for the 30th percentile.From the standard normal distribution table, the z-score for the 30th percentile is -0.52.Using the formula for z-score we havez=(x-μ)/σwhere x is the speed of the carsμ is the mean speed = 158.9σ is the standard deviation = 6.7Substituting these values in the above equation we have-0.52=(x-158.9)/6.7Rearranging we get,x - 158.9 =[tex]-0.52 × 6.7x - 158.9 = -3.524x = 158.9 - 3.524x = 155.376[/tex]The speed that represents the 30th percentile for speeds of race cars at Talladega is approximately 155.38 mph.
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20+11 how much pizza have
Answer: 31 pizzas
Step-by-step explanation:
add them together
Jim orders prints from a website. The site charges him $6. 95 a month and $0. 04 for each print he orders.
Enter an equation that can be used to find the number of prints, P, Jim ordered last month if the website charged
him $17. 79. Enter your response in the first response box
Enter the number of prints Jim ordered last month. Enter your response in the second response box,
Number of prints Jim ordered last month is 271
Let's assume Jim ordered "P" prints last month. The cost of ordering "P" prints would be the sum of the monthly charge and the cost of each print, which is given by the equation:
Cost = Monthly Charge + (Cost per Print x Number of Prints)
Substitute the values in the equation
$17.79 = $6.95 + ($0.04 x P)
Simplifying the equation, we get:
$10.84 = $0.04 x P
Dividing both sides by $0.04, we get:
P = $10.84 / $0.04
Divide the numbers
P = 271
Therefore, Jim ordered 271 prints last month.
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Which of the following subsets of P2(R) are subspaces of P2(R)? Note: P2(R) is the vector space of all real polynomials of degree at most 2.A. {p(t) | p?(t)+1p(t)+6=0}B. {p(t) | p(?t)=?p(t) for all t}C. {p(t) | p(4)=7}D. {p(t) | \int_{-1}^{7}p(t)dt=0E. {p(t) | p?(8)=p(0)}F. {p(t) | p(3)=0}
The followings A, C, D, and F subsets of P₂ are subspace of P₂.
The subsets of P₂ that are subspace of P₂ are A, C, D, and F.
A.{p(t) | p'(t)+1p(t)+6=0} is a subspace of P₂ because it satisfies the criteria of being closed under addition and scalar multiplication.
B.{p(t) | p('t)='p(t) for all t} is not a subspace of P₂ because the derivative of p(0) does not equal p(4).
C. {p(t) | p(4)=7} is a subspace of P₂ because it satisfies the criteria of being closed under addition and scalar multiplication.
[tex]{p(t) | \int_{-1}^{7}p(t)dt=0[/tex] is constant } is a subspace of P₂ because it satisfies the criteria of being closed under addition and scalar multiplication.
E. {p(t) | '(8) = p(0)} is not a subspace of P₂ because the derivative of p(8) does not equal 0.
F. {p(t) | p(3)=0} for all t} is a subspace of P₂ because it satisfies the criteria of being closed under addition and scalar multiplication.
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