match the following. 1. a length equal to the height in a square 2. any rhombus can be created by rotating this shape around the midpoint of its base 3. found by dividing 360 by the number of sides of a regular polygon 4. height of a parallelogram 5. each angle in a rectangle 6. a special type of trapezoid 7. perpendicular distance from the center of a regular polygon to its side 8. a special type of regular polygon
Altitude
base
apothem
parallelogram
isosceles triangle
right angle central angle

The equation in standard form for the circle with center (5,0) passing through (5, 9/2) is 4x² + 4y² - 40x + 19 = 0

Given that

Center = (5, 0)

Point on the circle = (5. 9/2)

The equation of a circle can be expressed as

(x - a)² + (y - b)² = r²

Where

Center = (a, b)

Radius = r

So, we have

(x - 5)² + (y - 0)² = r²

Calculating the radius, we have

(5 - 5)² + (9/2 - 0)² = r²

Evaluate

r = 9/2

So, we have

(x - 5)² + (y - 0)² = (9/2)²

Expand

x² - 10x + 25 + y² = 81/4

Multiply through by 4

4x² - 40x + 100 + 4y² = 81

So, we have

4x² + 4y² - 40x + 19 = 0

Hence, the equation is 4x² + 4y² - 40x + 19 = 0

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The solutions are:5π/4 + 2π = 13π/45π/4 - 2π = -3π/45π/4 + 4π = 21π/45π/4 - 4π = -11π/4

1. Two positive angles and two negative angles that are coterminal with the 190° are:550°, -170°, 950°, -410°Explanation:An angle in standard position has its vertex at the origin and its initial side is on the positive x-axis. A coterminal angle is formed when two angles share the same terminal side. Thus, the two angles have a difference that is a multiple of 360°. To find two positive angles and two negative angles that are coterminal with the 190°, we can add or subtract any multiple of 360° to it. Thus, the solutions are:190° + 360° = 550°190° - 360° = -170°190° + 2(360°) = 950°190° - 2(360°) = -410°2. Two positive angles and two negative angles that are coterminal with the 5π/4 are:13π/4, -3π/4, 21π/4, -11π/4Explanation:To find two positive angles and two negative angles that are coterminal with the angle 5π/4, we can add or subtract any multiple of 2π to it. Thus, the solutions are:5π/4 + 2π = 13π/45π/4 - 2π = -3π/45π/4 + 4π = 21π/45π/4 - 4π = -11π/4

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As per the number line, the elapsed time between 10:15 A.M. and 10:49 A.M. is 1 hour.

Once we have our number line divided into intervals, we can mark the starting time, which is 10:15 A.M., on the number line. We can do this by placing a dot or a small line segment at the appropriate point on the number line.

Next, we can mark the ending time, which is 10:49 A.M., on the number line. We can place a dot or a small line segment at the appropriate point on the number line to represent the ending time.

Finally, we can count the number of intervals between the starting time and the ending time on the number line to determine the elapsed time. In this case, we can count the number of 5-minute intervals between the starting time of 10:15 A.M. and the ending time of 10:49 A.M. There are 12 intervals between these two times, so the elapsed time is 60 minutes, or 1 hour.

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the volume of the cone-shaped sculpture is approximately 300.7 cubic feet. To find the volume of the cone-shaped sculpture, we need to use the formula:

V = (1/3)πr^2h

where V is the volume, r is the radius of the base, h is the height of the cone, and π is the constant pi.

First, we need to find the radius of the base. The circumference of the base is given as 30.772 feet, so we can use the formula for the circumference of a circle to solve for the radius:

C = 2πr

30.772 = 2πr

r = 30.772 / (2π)

r ≈ 4.9 feet

Now we can substitute the values of r and h into the formula for the volume:

V = (1/3)π(4.9)^2(7)

V ≈ 300.7 cubic feet

Therefore, the volume of the cone-shaped sculpture is approximately 300.7 cubic feet.

It's important to note that the formula for the volume of a cone is derived from the formula for the volume of a cylinder, which is V = πr^2h. To get the formula for the volume of a cone, we imagine a cylinder with the same base and height as the cone, and then we take one-third of that volume. This is why the formula for the volume of a cone includes the factor of 1/3. The constant pi (π) is used to represent the ratio of the circumference of a circle to its diameter, and it appears in many formulas in mathematics and science that involve circles or spheres.

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Given the triangle BOC is isosceles, the angle between the [tex]m < ACB[/tex] and [tex]m < COB[/tex] is also [tex]45^{0}[/tex].

A triangle is guaranteed to have an angle total of 180 degrees. A quadrilateral may be divided in half from each corner to form a triangle because the angle total of a parallelogram is equal to 360°. A triangle is effectively half of a parallelogram, therefore it makes sense that its angle measurements are also half. 180° is one-half of 360°.

Right triangles have three sides, the hypotenuse, the two shorter sides, and the side opposite a 90o angle, which is their longest side.

The sum of the angles in triangle ABC is [tex]180^{0}[/tex], we can find m<ACB by subtracting [tex]m < BAC[/tex] and [tex]m < ABC[/tex] from [tex]180^{0}[/tex]:

[tex]m < ACB = 180^{0} - m < BAC - m < ABC[/tex]

[tex]m < ACB = 180^{0} - 25^{0} - 90^{0}[/tex]

[tex]m < ACB = 65^{0}[/tex]

Now we can find [tex]m < COB[/tex] by recognizing that triangle [tex]BOC[/tex] is isosceles (since [tex]OB = OC[/tex]), and that [tex]m < BOC[/tex] is equal to half of [tex]m < ADC[/tex]:

[tex]m < BOC = 1/2 m < ADC[/tex]

[tex]m < BOC = 1/2 (90^{0} )[/tex]

[tex]m < BOC = 45^{0}[/tex]

Therefore, [tex]m < COB[/tex] is also [tex]45^{0}[/tex], since triangle [tex]BOC[/tex]is isosceles.

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Substitute the value of x from -3 to 3 in the equation and obtain the value of f(x), and plot the graph for the equation on the give interval.

A modulus function is a function that determines a number or variable's absolute value. It generates the size of the variable count. A function with absolute values is another name for it. No matter what input was provided to this function, the output is always favourable.

The function of the graph is given as f(x) = ⌊x⌋ + 1 on the interval [-3,3].

Substitute the value of x from -3 to 3 in the equation and obtain the value of f(x).

Plot the coordinates on the graph to obtain the following.

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Answer:

Correct choices

[tex]\csc (\theta) = - \dfrac{5}{3} \quad \quad \text{2nd option}\\\\\cot(\theta) = \dfrac{4}{3} \quad \quad \text{3rd option}\\\\\cos(\theta) = -\dfrac{4}{5} \quad \quad \text{4th option}\\\\[/tex]

Step-by-step explanation:

[tex]\text{If \;$ \tan\theta = \dfrac{3}{4} $}} \\\\\text{then }\\\theta = \tan^{-1} \left(\dfrac{3}{4}\right)\\\\= 36.87^\circ \text{ in Q1}\\[/tex]

But since tan θ is periodic it will also be 3/4 in Q3 which is 180° + 36.87 = 216.87°

If the probability an American will die from falling is 0.41%, the probability a American will not die from falling is 100% - 0.41% = 99.59%.

Answer: 99.59%.

As the banker at the Banco de los Trabajadores de Tegucigalpa, I greet Mr. Milton Escobar and thank him for choosing our bank for his fixed term deposit. I verify his identification and confirm the details of his deposit, which are:

Fixed Term Deposit number: #2250

Deposit amount: L100,000.00

Deposit term: 6 months

Interest rate: 10.5% per annum

I inform Mr. Escobar that the interest on his deposit will be calculated and credited to his account at the end of the deposit term. I also explain that he can choose to receive the interest in cash or reinvest it in the fixed term deposit.

Next, I ask Mr. Escobar to provide me with a check for the full deposit amount, payable by the Banco de los Trabajadores de Tegucigalpa, and I confirm that the check number is #0045. I inform him that the check will be deposited in his account and that he will receive a deposit confirmation letter.

Finally, I thank Mr. Escobar for his business and remind him to keep his deposit confirmation letter in a safe place, as it is a crucial document that he will need to produce at the time of maturity to withdraw his funds. I assure him that our bank will provide him with the highest quality service and look forward to his continued patronage.

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Translated Question ;

Mr. Milton Escobar appears at the Banco de los Trabajadores de Tegucigalpa to set up a Fixed Term Deposit #2250 for 6 months for L100,000. 00 to 10.5% annual interest, delivering the total amount by check #0045 payable by the same bank. Play the opening game

Sec x is the simplified expression cos(−x)+tan(−x)sin(−x) involving a single trigonometric function with no fractions.

The functions of an angle in a triangle are known as trigonometric functions, commonly referred to as circular functions. In other words, these trig functions provide the relationship between a triangle's angles and sides. There are five fundamental trigonometric functions: sine, cosine, tangent, cotangent, secant, and cosecant.

The Given expression is

cos(−x)+tan(−x)sin(−x)

Now,

cos(−x) + tan(−x)sin(−x)

= cos x + (- tan x) (- sin x)

= cos x + tan x * sin x

= cos x + (sin x / cos x) * sin x

= (cos²x + sin²x) / cos x     ( As sin²x + cos²x = 1)

= 1/ cos x

= sec x       (As sec x = 1/cos x)

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This principle is validated by the data shown in the table.

Tests and measurements is an essential aspect of the education process as it enables educators to gauge the level of knowledge and skills their students have acquired. The principle that longer tests tend to be more reliable than shorter ones has some merit because it allows educators to assess a broader range of skills and knowledge, which increases the validity of their assessments.In my opinion, the principle that longer tests tend to be more reliable than shorter ones is illustrated in the reliability coefficients shown in the table. This is because the data shows that the reliability coefficients for longer tests are consistently higher than those for shorter tests. Additionally, the results for the 10-item test indicate a higher reliability coefficient compared to the 5-item test, which supports the notion that longer tests are more reliable than shorter ones.The table displays that the longer tests have higher reliability coefficients compared to the shorter tests. For example, in the 5-item test, the reliability coefficient is .45, while the 10-item test's reliability coefficient is .73. This shows that the 10-item test is more reliable than the 5-item test, as the higher reliability coefficient indicates that the assessment is consistent in measuring the skill or knowledge it is intended to measure. As a result, this principle is validated by the data shown in the table.

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To prepare a buffer solution with a given pH, we need to choose a weak acid and its conjugate base, such that the pKa of the weak acid is close to the desired pH.

The pKa is related to the Ka value as follows:

pKa = -log(Ka)

So, for each of the weak acids given, we can calculate the pKa:

Phosphoric acid (H3PO4): Ka = 7.5 x 10^-3, so pKa = -log(7.5 x 10^-3) = 2.12

Acetic acid (CH3COOH): Ka = 1.8 x 10^-5, so pKa = -log(1.8 x 10^-5) = 4.74

Formic acid (HCOOH): Ka = 1.8 x 10^-4, so pKa = -log(1.8 x 10^-4) = 3.74

Now, let's consider the desired pH values and choose the best components for buffer solutions:

For a pH of 2.5, the best choice would be phosphoric acid (pKa = 2.12).

For a pH of 4.5, the best choice would be formic acid (pKa = 3.74) or a mixture of acetic acid and acetate ion (CH3COOH/CH3COO-, pKa = 4.76).

For a pH of 6.5, the best choice would be a mixture of acetic acid and acetate ion (CH3COOH/CH3COO-, pKa = 4.76).

Note that a buffer solution can be prepared by mixing a weak acid and its conjugate base in roughly equal amounts, so the appropriate salt can be added to the acid to form the buffer solution. For example, to prepare an acetate buffer, one could mix acetic acid with sodium acetate.

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Answer:

2 hours

Hope its right

Answer: Explanation below.

Step-by-step explanation:

To evaluate the function at 0.125-second intervals from 0 through 1 seconds, we need to substitute the values of t = 0, 0.125, 0.25, 0.375, 0.5, 0.625, 0.75, 0.875, and 1 in the given function and calculate the corresponding values of h(t).

Using the function h(t) = 12sin(4πx) + 12, we get:

At t = 0 seconds, h(0) = 12sin(4π(0)) + 12 = 12sin(0) + 12 = 12 + 0 = 12

At t = 0.125 seconds, h(0.125) = 12sin(4π(0.125)) + 12 ≈ 18.99

At t = 0.25 seconds, h(0.25) = 12sin(4π(0.25)) + 12 ≈ 23.39

At t = 0.375 seconds, h(0.375) = 12sin(4π(0.375)) + 12 ≈ 24.73

At t = 0.5 seconds, h(0.5) = 12sin(4π(0.5)) + 12 = 12sin(2π) + 12 = 12 + 0 = 12

At t = 0.625 seconds, h(0.625) = 12sin(4π(0.625)) + 12 ≈ 4.60

At t = 0.75 seconds, h(0.75) = 12sin(4π(0.75)) + 12 ≈ -0.80

At t = 0.875 seconds, h(0.875) = 12sin(4π(0.875)) + 12 ≈ -3.91

At t = 1 second, h(1) = 12sin(4π(1)) + 12 = 12sin(4π) + 12 = 12 + 0 = 12

Thus, the table of values for h(t) at 0.125-second intervals from 0 through 1 seconds is:

t   |      h(t)

___________

0         12

0.125 18.99

0.25 23.39

0.375 24.73

0.5         12

0.625 4.60

0.75 -0.80

0.875 -3.91

1          12

Answer:

Step-by-step explanation:

Both snowmen will have an equal height after 4 hours after sunrise.

To understand the reasoning behind the equations and solutions, we can break down the problem into several steps.

First, we are given the initial heights of Snowman A and Snowman B, 59 and 39 inches, respectively.

Next, we are told that the height of Snowman A decreases by 9 inches per hour and the height of Snowman B decreases by 4 inches per hour. This means that after t hours, the height of Snowman A will be 59 - 9t and the height of Snowman B will be 39 - 4t.

To find the number of hours after sunrise when both snowmen have an equal height, we need to set A = B and solve for t. This gives us the equation:

59 - 9t = 39 - 4t

Solving for t, we get:

20 = 5t

t = 4

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An interval is a set of real numbers that contains all real numbers lying between any two numbers of the set.

For each calculation, the smallest interval in which the result, using true instead of rounded values, must lie is as follows:

(a) 1.1062+0.947 = 2.0532 ≤ true result ≤ 2.053

(b) 23.46 - 12.753 = 10.707 ≤ true result ≤ 10.708

(c) (2.747) (6.83) = 18.6181 ≤ true result ≤ 18.6182

(d) 8.473/0.064 = 132.3906 ≤ true result ≤ 132.3907

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Answer:

Find the numerical values of the following expressions. -3|x|+2x-1 if x=-5

Step-by-step explanation:

Substituting x=-5, we get:

-3|x| + 2x - 1 = -3|-5| + 2(-5) - 1

= -3(5) - 10 - 1

= -15 - 10 - 1

= -26

Therefore, -3|x| + 2x - 1 = -26 when x=-5.

Answer:

$2.235

Step-by-step explanation:

15% = 0.15

We Take

15.50 x 0.15 = $2.235

So, the tip for this bill is $2.235

Answer:

All of the statements are true.

The first statement is true because a graph represents all the possible solutions to an equation or function.

The second statement is true because a system of equations may have no solution, one solution, or infinitely many solutions, depending on the equations.

The third statement is true because graphing technology allows us to see the visual representation of the functions and their intersection points, which are the solutions to the system of equations.

The fourth statement is true because the solution to a system of equations is the point where both equations intersect and are true.

The fifth statement is also true because finding the x-coordinate of the point of intersection is equivalent to finding the solution to f(x) = g(x).

The sixth statement is true because systems of equations can involve any combination of linear, quadratic, exponential, or other functions.

The seventh statement is true because a table of values can only show a limited number of solutions, but finding the approximate solution between two values on the table can still be useful in many practical situations.

We can see that:

1.  True: A graph of an equation in two variables or a function represents an infinite number of solutions because each point on the graph corresponds to a solution of the equation or function.

2. True: A system of equations may not have an exact solution that meets the conditions of a real-world solution. It is possible for a system to have no solution or infinite solutions.

3. False: Using graphing technology is a very efficient way to find solutions to equations and systems of equations.

In mathematics, a graph is a visual representation or diagram that displays the relationship between different elements or variables.

4. True: The intersection point of two graphed functions represents the solution for a system of equations. The coordinates of the intersection point satisfy both equations simultaneously.

5. True: When two different functions f(x) and g(x) are graphed, the x-coordinate of the point of intersection represents a solution to the equation formed from f(x) = g(x). However, it's important to note that there could be multiple points of intersection, so the x-coordinate of the intersection is not necessarily the only solution.

6. True: Systems of equations may indeed be a combination of linear and non-linear functions. The equations in a system can involve various types of functions, including linear, quadratic, exponential, logarithmic, etc.

7. True: A table of values may not show every possible solution to a system of equations. It provides a limited set of data points, and there may be solutions that fall between the values in the table. However, finding an approximate solution that lies between two values in the table can be a reasonable approach in many situations.

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The complete question is seen below:

True or False:

A graph of an equation in two variables or a function is a representation of an infinite number of solutions to the equation or function.

A system of equations may not have an exact solution that meets the conditions of a real-world solution.

Using graphing technology is a very efficient way to find solutions to equations and systems of equations.

The intersection point of two graphed functions is the solution for a system of equations. It is the point that makes both equations true.

When two different functions f(x) and g(x) are graphed, the x-coordinate of the point of intersection is the solution to the equation formed from f(x) = g(x)

Systems of equations may be a combination of linear and non-linear functions.

A table of values very rarely shows every possible solution to a system of equations. Finding the approximate solution that is between two values on the table can be a good answer in many situations.

Answer:

  C, E

Step-by-step explanation:

You want the equations that represent 2 boys for every 5 girls in a class.

The number of boys is represented by x, and the number of girls is represented by y, so you have ...

  x : y = 2 : 5

As fractions, this is ...

  x/y = 2/5

Multiplying by 5y gives ...

  5x = 2y . . . . . . matches equation C

Dividing by 5, we have ...

  x = 2/5y . . . . . . matches equation E

A random sample is called a representative sample.

It is a subset of a larger population that is selected in a way that ensures every individual in the population has an equal chance of being included in the sample. By ensuring randomness in the selection process, a representative sample is more likely to accurately reflect the characteristics and diversity of the larger population.

Representative samples are important in research and statistical analysis because they allow for more generalizable conclusions to be drawn about the population as a whole.

Without a representative sample, research findings may be biased and not applicable to the entire population. Therefore, a representative sample is crucial for ensuring the validity and reliability of research results.

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Answer:

circumference=43.96 yd

Area=153.86 yd^2

Step-by-step explanation:

c=2pi r

c=2x3.14x7

c=43.96 yd

area=pi r^2

Area=3.14x7^2

Area=153.86 yd^2

a. the mean is 200.31 cm. b. The height of the new player is 210 cm.

The mean, commonly referred to as the average, is a statistic that depicts the usual value of a group of data and measures central tendency. It is calculated by adding up all of the data set's values and dividing the result by the total number of values. Since it offers a single value that summarises the complete set of data, the mean is an effective statistical tool. It may, however, be vulnerable to outliers or extremely high or low values that affect the mean's value. As a result, while examining data, it is crucial to take additional measures of central tendency into account, such as the median or mode.

The mean or average is given as:

mean = (sum of all heights) / (number of players)

The total number of players are:

1 + 3 + 2 + 5 + 2 = 13

Sum of heights is:

(198 x 1) + (199 x 3) + (200 x 2) + (201 x 5) + (202 x 2) = 198 + 597 + 400 + 1005 + 404 = 2604

Thus,

mean = 2604 / 13 = 200.31 cm

b. For the new player the number of players are 14:

201 = (2604 + height of new player) / 14

201 x 14 = 2604 + height of new player

2814 = 2604 + height of new player

height of new player = 2814 - 2604 = 210 cm

Hence, a. the mean is 200.31 cm. b. The height of the new player is 210 cm.

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The average number of hours of sleep for working college students is between 6.28 and 6.72 hours of sleep each night

According to the given data,

Sample size n = 101

Sample mean x = 6.5

Standard deviation s = 2.14

Level of confidence C = 96%

Using a 96% confidence level, the value of t* for 100 degrees of freedom is 2.081, as given in the question.

Now, the formula for the confidence interval is:x ± (t* × s/√n)Here, x = 6.5, s = 2.14, n = 101, and t* = 2.081

Substituting the values in the above formula, we get:

Lower limit = x - (t* × s/√n) = 6.5 - (2.081 × 2.14/√101) = 6.28

Upper limit = x + (t* × s/√n) = 6.5 + (2.081 × 2.14/√101) = 6.72

Therefore, the 96% confidence interval for the average number of hours of sleep for working college students is between 6.28 and 6.72 hours of sleep each night.

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Answer:

Step-by-step explanation:

To solve this problem, we can use the formula for calculating compound interest:

A = P * (1 + r/n)^(n*t)

where:

A = the final amount

P = the principal (initial amount of money)

r = the annual interest rate (as a decimal)

n = the number of times interest is compounded per year

t = the time (in years)

In this problem, we know that the interest rate is 4.5% per year, or 0.045 as a decimal. The money is deposited for 48 months, or 4 years.

Let's assume that the principal deposited is P. Then we can use the formula to calculate the final amount:

A = P * (1 + r/n)^(nt)

80,000 = P * (1 + 0.045/12)^(124)

Simplifying the equation, we get:

80,000 = P * (1.00375)^48

80,000 = P * 1.21169

Dividing both sides by 1.21169, we get:

P = 80,000 / 1.21169

P = 66,000

Therefore, the initial amount deposited by the person was Rs. 66,000.

According to the given coordinate the value of f(x) is -6, 0, 3, 6, 12.

An equation is a mathematical statement that indicates that two expressions are equal. It typically contains variables, which are symbols that represent unknown values, and constants, which are values that are known. Equations are used to describe relationships between quantities and to solve problems by finding the values of variables that satisfy the equation. For example, the equation 2x + 3 = 7 is a statement that the sum of two times x and 3 is equal to 7, and we can solve for x by subtracting 3 from both sides and dividing by 2 to obtain x = 2

Given value is f(x) = 3x

now value of x is given in the table.

If value of x is -2 then value of f('x) will be -6

If value of x is 0 then value of f('x) will be 0

If value of x is 1 then value of f('x) will be 3

If value of x is 2 then value of f('x) will be 6

If value of x is 4 then value of f('x) will be 12

Therefore, according to the given coordinate the value of f(x) is -6, 0, 3, 6, 12.

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Answer:

The continuous compounding formula is:

A = Pe^(rt)

where A is the amount after t years, P is the initial principal, r is the annual interest rate as a decimal, and e is Euler's number (approximately 2.71828).

We are given that P = $5,000, r = 0.045, and A = $7,840. We want to find t, the number of years.

We can solve for t by isolating it on one side of the equation:

A = Pe^(rt)

A/P = e^(rt)

ln(A/P) = rt

t = ln(A/P) / r

Substituting in the values we have:

t = ln(7840/5000) / 0.045

t ≈ 11

So it will take about 11 years for the investment to grow to $7,840

a. The mean of X is 1.7549 and the standard deviation is 0.3536.

b. To calculate the proportion of washing machines that will last for more than 15 years, we need to use the standard normal distribution table. The z-score for 15 years is (15-14)/0.3536 = 2.822. Using the table, we find that the proportion of washing machines that will last for more than 15 years is 0.9968.

c. To calculate the proportion of washing machines that will last for less than 10 years, we need to use the standard normal distribution table. The z-score for 10 years is (10-14)/0.3536 = -2.822. Using the table, we find that the proportion of washing machines that will last for less than 10 years is 0.0032.

d. To calculate the 90th percentile of the life of the washing machines, we need to use the standard normal distribution table. The z-score for the 90th percentile is 1.28. Using the table, we find that the 90th percentile is 17 years.

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Answer: 3/8

Step-by-step explanation: