Figure ABCD has vertices A(1, 1), B(1, 4), C(4, 4), and D(4, 1). What are the coordinates of the vertices of Figure
A’B’C’D’ after a reflection across the line x = –2 and a translation 3 units up? Drag numbers to complete the coordinates.
Numbers may be used once, more than once, or not at all.

Answer: 7, 7, 19, and 19

Recall that a rectangle has congruent parallel sides, meaning the sides opposite are equivalent in length. Therefore, 2 sides are both 12 cm longer than the other two sides. Let's write an equation:

Let x be the shorter side, and x + 12 be the longer side.

x + x + (x + 12) + (x + 12) = 52

Combine like terms.

4x + 24 = 52

4x = 28

x = 7

Therefore, the shorter sides are 7, and the longer sides are 19

The average velocity of the function y = x² + 8x over the interval [5, 8] is 21.

Average velocity is a measure of the rate of change of an object's position over time. It is calculated by dividing the total change in position (displacement) of an object by the time interval over which the change occurred.

In mathematical terms, average velocity is given by the formula: v_avg = Δx / Δt, where Δx is the change in position (displacement) of the object and Δt is the time interval over which the change occurred. The average velocity is a vector quantity, meaning that it has both magnitude and direction.

The average velocity of an object gives a measure of its average speed and direction over a certain time interval. It is a useful concept in physics, especially in the study of mechanics and kinematics, where it is used to describe the motion of objects under different conditions and to calculate the velocity of objects at a specific instant in time.

The average velocity over an interval [a, b] is defined as the total change in position (y) divided by the total change in time (x), i.e., (y(b) - y(a)) / (b - a).

Given the function y = x² + 8x, we have:

y(5) = 5² + 8 × 5 = 25 + 40 = 65

y(8) = 8² + 8 × 8 = 64 + 64 = 128

So, the average velocity over the interval [5, 8] is:

(y(8) - y(5)) / (8 - 5) = (128 - 65) / (8 - 5) = 63 / 3 = 21.

Therefore, the average velocity of the function y = x² + 8x over the interval [5, 8] is 21.

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The only value of c that satisfies the initial condition g(2) = 5 is c = -3.

The graph of a function f consists of three line segments, with points (1,2), (2,3), and (3,4).

An antiderivative of f is a function g such that g'(x) = f(x). That is, g is the "opposite" of the derivative of f. The values of c in an antiderivative g(x) = f(x) + c are determined by the initial condition g(2) = 5, since g'(2) = f(2) = 3.

So, in order to determine the value of c, we need to integrate f(x) and find the value of g(2). The integral of f(x) is

g(x) = x² + 2x + c

Substituting x = 2 into this equation, we get

g(2) = 4 + 4 + c = 8 + c

Now, since g(2) = 5, we can solve for c:

5 = 8 + c

c = -3

Therefore, the only value of c that satisfies the initial condition g(2) = 5 is c = -3.

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Answer:

[tex]\boxed{\mbox \large a = \dfrac{9}{10} = 0.9}[/tex]

Step-by-step explanation:

Equation to be solved is
[tex]\dfrac{5}{3}a + \dfrac{4}{5} = a + \dfrac{7}{5}[/tex]

Step 1

Get rid of those annoying denominators by multiplying throughout 15. We choose 15 because it is the lowest common multiple of 3 and 5. Since 3 and  are prime numbers the LCM is 3 x 5 = 15

[tex]15 \cdot \dfrac{5}{3}a +15 \cdot \dfrac{4}{5} = 15\cdot a + 15\cdot \dfrac{7}{5}}[/tex]
==> [tex]25a + 12 = 15a + 21}\\[/tex]

Step 2

Subtract 15 from both sides:

==> [tex]25a -15a + 12 = 15a -15a + 21}\\\\\\ 10a + 12 = 21}\\[/tex]

Step 3

Subtract 21 from both sides
[tex]10a + 12 -12 = 21 - 12\\\\[/tex]

[tex]10a = 9[/tex]

Step 4

Divide by 10 both sides

[tex]\dfrac{10a}{10} = \dfrac{9}{10}\\\\\implies a = \dfrac{9}{10} = 0.9[/tex]

Two non-functions could be (a,a) -> a and (a,b) -> a and (a,a) -> b and (a,b) -> b, meaning that both inputs can result in either a or b.

A set is a collection of distinct objects, which can be anything, such as numbers, letters, or even other sets.

The set-roster notation is a way to write a set by listing its elements inside curly brackets {}.

(a) To write the set (XXX) XY, we need to repeat the set X three times, which would be X = {a,a,a}.

Then we can join it with the set Y to form (XXX) XY = {a,a,a,a,b}.

(b) To find two functions and two non-function relations from X x Y to Y, we need to understand what a function and a relation are. A function is for every element in the domain (X x Y), there is exactly one corresponding element in the codomain (Y) where as a non-function, or a relation, is a set of ordered pairs where the same input can have different outputs.

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The equation Ax = b has a solution for each b in R4 if and only if the columns of A span R4.

The equation Ax = b is a linear equation that is commonly used in linear algebra. This equation is used to find the solution of a system of linear equations. The equation consists of a matrix A and a vector b.

Spanning refers to the ability of a set of vectors to generate all other vectors in a given space. If the columns of A span R4, then for each vector b in R4, there exists a unique solution x in R4 such that Ax = b.

On the other hand, if the columns of A do not span R4, then there are some vectors in R4 that cannot be generated by the columns of A and thus the equation Ax = b will not have a solution for each b in R4.

In conclusion, the set of vectors in the matrix A must be able to generate all other vectors in R4 for the equation to have a solution for each b in R4.

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Chloe is 31 years old while Tino is 17 years old.

An equation is an expression that uses mathematical operations to show the relationship between numbers and variables. Types of equations are linear, quadratic, cubic and so on.

Let x represent Chloe present age and y represent Tino present age. Chloe and Tino have a combined age of 48. Hence:

x + y = 48     (1)

Also, Three years ago Chloe was double the age Tino, hence:

x - 3 = 2(y - 3)

x - 2y = -3    (2)

From both equations:

x = 31, y = 17

Chloe is 31 years old.

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s = {(-5, 7)} cannot be a basis for R^2 because it does not satisfy the three requirements of a basis: having at least two linearly independent vectors, containing only linearly independent vectors, and spanning the entire vector space.

The set s = {(-5, 7)} is not a basis for R^2 (the two-dimensional real vector space) for several reasons:

Cardinality: A basis for a vector space must contain at least two linearly independent vectors. Since s contains only one vector, it cannot be a basis for R^2, which has dimension 2.

Linear independence: A basis must contain linearly independent vectors. If a vector in the basis can be written as a linear combination of the other basis vectors, it is not linearly independent, and the set cannot be a basis.

Spanning: A basis must span the entire vector space, meaning that every vector in the vector space can be written as a linear combination of the basis vectors. The set s = {(-5, 7)} does not span R^2 because it contains only one vector, and not every vector in R^2 can be written as a scalar multiple of this vector.

Therefore, s = {(-5, 7)} cannot be a basis for R^2 because it does not satisfy the three requirements of a basis: having at least two linearly independent vectors, containing only linearly independent vectors, and spanning the entire vector space.

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Answer:

Below

Step-by-step explanation:

( 2/15 is incorrect)

1/12 is the same as   1 ÷ 12    use a calculator to see = .8333........

 do the same with the others and you will se that 7/8 = .875  and is the only one that terminates

The fraction 7/8 is the one that results in a terminating decimal.

A decimal representation of a fraction results in a terminating decimal if and only if all the prime factors of the denominator are 2 and/or 5, since 2 and 5 are the prime factors of 10, the base of our number system.

Let's analyze each fraction's denominator:

- For the fraction 1/12, the denominator is 12. The prime factors of 12 are 2 and 3. So, this fraction does not result in a terminating decimal.

- For the fraction 4/9, the denominator is 9. The prime factor of 9 is 3. Hence, this fraction doesn't result in a terminating decimal.

- For the fraction 2/15, the denominator is 15. The prime factors of 15 are 3 and 5. As the denominator contains the prime number 3, it doesn't result in a terminating decimal.

- For the fraction 7/8, the denominator is 8. The only prime factor of 8 is 2, which is one of the prime factors of 10. This means that the decimal representation of this fraction will be a terminating decimal.

Therefore, the fraction 7/8 is the one that results in a terminating decimal.

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Based on the graph, in year 4 there were 1.16 times more burglaries if compared to year 1.

Based on the graph, the number of burglaries these years was:

This shows a growing trend in the number of burglaries over the years.

number in year 4/ 1

255/220 = 1.159 which can be rounded to 1.16

Based on this, year 4 had 1.16 times more burglaries than year 1.

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The total meter reading of Dan electricity usage from July to October including the meter reading as at July is 33,289 units

Quantity of electricity Dan used from July to October = 942 units

Meter reading in July= 32, 347 units

The total meter reading = Quantity of electricity Dan used from July to October + Meter reading in July

= 942 units + 32, 347 units

= 33,289 units

Therefore, Dan used a total of 33,289 units of electricity from July to October including the previous reading.

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(a) The future value is $18,971.06, which is closest to option D) $64,521.06

(b) So the present value of the estimated payments is $317,375, which is closest to option A) $350,623.10

(c) The present value of the savings is $25,620.51, which is closest to option C) $73,734.84

A) The future value of the deposits can be calculated using the formula for compound interest:

FV = PV * (1 + r/n)^(nt)

where

PV = $7,000

r = 12% = 0.12

n = 2 (compounded semiannually)

t = 5 years = 10 semiannual periods

Plugging in these values, we get:

FV = $7,000 * (1 + 0.12/2)^(2 * 10)

FV = $7,000 * (1.06)^20

FV = $7,000 * 2.667532622

FV = $18,971.06

B) The present value of the estimated payments can be calculated using the formula for the present value of an annuity:

PV = PMT * (1 - (1 + r)^(-n)) / r

where

PMT = $31,000

r = 8% = 0.08

n = 20 payments (from age 70 to 90)

Plugging in these values, we get:

PV = $31,000 * (1 - (1 + 0.08)^(-20)) / 0.08

PV = $31,000 * (1 - 0.170811153) / 0.08

PV = $31,000 * 0.83 / 0.08

PV = $31,000 * 10.375

PV = $317,375

C) The present value of the savings can be calculated using the formula for present value of a lump sum:

PV = FV / (1 + r/n)^(nt)

where

FV = $12,000 * 10 (total savings)

r = 10% = 0.1

n = 2 (compounded semiannually)

t = 10 years = 20 semiannual periods

Plugging in these values, we get:

PV = ($12,000 * 10) / (1 + 0.1/2)^(2 * 20)

PV = ($120,000) / (1.05)^40

PV = $120,000 / 4.68

PV = $25,620.51

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This is a second order linear ordinary differential equation (ODE) of the form Xy″ (3x – 1)y′ – (4x 9)y is 0.

To solve this equation, we can use the method of integrating factors. The goal is to convert the given equation into a first-order linear ODE which can be easily solved using the technique of separation of variables.

The first step is to find the integrating factor, which is a function that when multiplied with the given equation, makes it a first-order linear ODE. In this case, the integrating factor is given by

[tex]= > e^{\int(3x-1) dx} = e^{(3x^2/2 - x)}[/tex]

Next, we multiply both sides of the given equation with the integrating factor to get

[tex]= > e^{(3x^2/2 - x)} = xy" (3x - 1)y' - (4x - 9)y = 0.[/tex]

After integrating both sides with respect to x, we get an equation in the form of a first-order linear ODE.

Finally, we solve the first-order linear ODE to obtain the general solution for y, which can then be solved using the initial condition y(0) = 0 to get the particular solution for y.

The method of integrating factors is a useful technique for solving second-order linear ODEs.

Complete Question:

Solve the differential equation xy"+(3x−1)y′−(4x+9)y=0 by using Laplace Transform.

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The geometric form known as a pentagon has five sides and five angles.

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The body will reach maximum height of 20 meter.

Law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time.

K + U = K' + U'

K = initial kinetic energy

U = initial potential energy

K' = final kinetic energy

U' = final potential energy

Given,

Mass of body m = 500g = 0.5 kg

Velocity v = 72km/h = 72000/3600 = 20 m/s

At initial point

Height h = 0

So, Potential energy U = mgh = mg(0) = 0

Kinetic energy K = (1/2)mv²

At highest point velocity u = 0

So, Kinetic energy K' = (1/2)u² = (1/2)×0 = 0

Potential energy U' = mgH

Now,

By law of conservation of energy

K + U = K' + U'

0 + (1/2)mv² = mgH + 0

(1/2)mv² = mgH

v² = 2gh

H = v²/2g

g is acceleration due to gravity, g = 10 m/s²

h = 20²/2×10

h = 20 meter

Hence, 20 meter is the maximum height to which the body will reach.

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a) Using the linear equation 68000 + 2000t, Alyssa would make a salary of $86,000 after 9 years of working for the company.

b) Based on the same linear equation, Alyssa's salary after t years would be 68000 + 2000t.

A linear equation is a mathematical equation written in the form of y=mx+b.

Linear equations involve a constant and a first-order (linear) term, where m is the slope and b is the y-intercept.

The offered annual salary of Alyssa = $68,000

Annual salary raise = $2,000

The number of years Alyssa would work for the company = t years

The number of years Alyssa worked in the company = 9 years

68000 + 2000t

68000 + 2000(9)

68000 + 18000

= 86,000

= $86,000

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The given coordinates make a right angled triangle.

Scaling is defined as the process of changing the dimensions of the original figure as per some specific proportional rule.

If the initial length is equivalent to {a}. Then, after the scaling by the scale factor of {K}, the length becomes {Ka}. Similarly, if the initial coordinates are (x, y) then after scaling the coordinates would be {Kx, Ky}.

Scale factor is a dimensionless quantity that tells by how much time a specific dimension of a figure is enlarged or reduced. Mathematically, it is the ratio of two similar quantities. In case of length scaling, we can write -

{K} = L{final}/L{initial}

Given are the coordinates of the triangle as -

P(-1, 3)

Q(9, - 1)

R(-3, - 2)

The distance formula is given as -

d² = (x₂ - x₁)² + (y₂ - y₁)²

PQ = 2√29

QR = √145

RP = √29

QR² = RP² + PQ²

145 = 29 x 4 + 29

145 = 145

Therefore, the given coordinates make a right angled triangle.

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let f be a differentiable function such that f(1)=2 and f′(x)=x2 2cosx 3 then f(4)= 4.1414

if a function is differential at x if the limit of a function exists at a pint x and the function is continuous at x point also then the function is differentiable at the point x

since sin and cos function are differentiable and their limit exists

Given that f is  a function given by

f(x) =2cosx +1

Here x is taken in radians.

Hence when x =1.5

we have cos 1.5 = 0.0707

2cosx = 0.1414

And hence

2cosx+1=1+0.1414

=1.1414

Thus we get

f(1.5) = 1.1414 apprxy

f( 4) = 0.1414 +4

      = 4.1414

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Answer:

C) 10.790

Step-by-step explanation:

we are given:

[tex]f(1)=2\\[/tex]

[tex]\frac{dy}{dx} =\sqrt{x^2+2cos(x)+3}[/tex]

we need to find:

[tex]f(4)=?[/tex]

integrate the function by using a TI-84 calculator (math > 9:fnInt( > input)

[tex]\\\int\limits^4_1 {\sqrt{x^2+2cos(x)+3} } \, dx \\\\\\=8.789[/tex]

since we are looking on the interval [1, 4] we need to add our two limiting values together:

[tex]F(4)+F(1)=2+8.789\\\\=10.790[/tex]

The ratio is 1:16 or (30 minutes:480 minutes).

What is the ratio of lunch interval to the total period in office?

The theory used in this question is the ratio of two numbers.

A ratio is a comparison of two numbers, usually expressed as a fraction or as a decimal. Ratios can be used to compare two numbers and identify relationships between them.

In this case, the ratio is being used to compare the lunch interval (30 minutes) to the total time the office is open (450 minutes).

Given:

The total time the office is open in minutes: 9 am - 5 pm = 8 hours = 8 x 60 minutes = 480 minutes.

Divide the lunch interval (30 minutes) by the total time the office is open (450 minutes): 30 minutes / 480 minutes.

= 1: 16

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The total amount of energy released or absorbed by the reaction, which is the change in free energy.

ΔG = ΔH - TΔS

This equation, also known as the Gibbs Free Energy equation, is used to calculate the change in free energy (ΔG) resulting from a chemical reaction. The equation states that the change in free energy is equal to the change in enthalpy (ΔH) minus the product of the absolute temperature (T) and the change in entropy (ΔS).

The enthalpy change (ΔH) is the change in the amount of energy released or absorbed during a reaction at constant pressure. It is a measure of the amount of energy stored in the bonds of the reactants and products. The entropy change (ΔS) is the measure of the randomness or disorder of a system. It is a measure of how much energy is dispersed or spread out from the reaction.

By combining the enthalpy and entropy changes of a reaction, the Gibbs Free Energy equation can be used to calculate the total amount of energy released or absorbed by the reaction, which is the change in free energy. For example, if ΔH is -50 kJ and ΔS is +40J/K, then the change in free energy is -10 kJ.

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The vector v with a magnitude of 9 and in the same direction as u = <18 / √29, 45 / √29>.

What is the vector?

A vector quantity has both a magnitude and a direction. Speed only has a magnitude, but no direction. Velocity has both.

Given a vector u = <2, 5>, the magnitude of the vector v that is in the same direction as u and has a magnitude of 9 can be found as follows:

Step 1: Find the unit vector in the direction of u

A unit vector in the direction of u can be found by dividing each component of u by its magnitude:

magnitude of u = √(2^2 + 5^2) = √(4 + 25) = √29

unit vector in the direction of u = u / magnitude of u = <2 / √29, 5 / √29> = <2 / √29, 5 / √29>

Step 2: Multiply the unit vector by the desired magnitude

To find the vector v with a magnitude of 9 and in the same direction as u, we can multiply the unit vector by 9:

v = magnitude * unit vector in the direction of u = 9 * <2 / √29, 5 / √29> = <18 / √29, 45 / √29>

Therefore, the vector v with a magnitude of 9 and in the same direction as u = <18 / √29, 45 / √29>.

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The total number of student that plotted the number of book they read is 18.

A dot blot the caption Book Read Over the Summer goes from 0 to 7. 0 ha 1 dot, 1 ha 3 dot, 2 ha 6, 3 ha 2, 4 ha 3, 5 ha 1 dot, 6 ha 2, and 7 ha 0 dot are the numbers. Using a dot plot

the total number of students who tracked how many books they read

add total dots  

1 dot + 3 dot +  6 dot +  2 dot + 3 dot +1 dot + 2 dot + 0 dot = 18.

The total number of student that plotted the number of book they read is 18.

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The population of a city can be modeled by a radical function, P(x) = 55,000 √x - 1945, where x represents the year and P(x) represents the population in that year.

The year 1945 has been subtracted from x in order to simplify the equation and make it easier to interpret.

In this particular problem, we are asked to find the year in which the population of the city was 275,000. To do this, we need to solve for x in the equation:

55,000 √x - 1945 = 275,000

The first step is to isolate x on one side of the equation. We can do this by adding 1945 to both sides:

55,000 √x = 275,000 + 1945

Next, we need to get rid of the square root symbol. One way to do this is to square both sides of the equation:

x = (275,000 + 1945) / 55,000^2

The square root has been eliminated, but the equation still doesn't give us x in a form that is easy to interpret. To get x in a more useful form, we can take the square root of both sides:

√x = √((275,000 + 1945) / 55,000^2)

So, the year in which the population of the city was 275,000 is approximately x + 1945 = 1976.

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Positive rational numbers cannot be added together.

If real numbers are multiplied, they are closed.

Irrational numbers cannot be divided in any way.

Subtraction causes closed integers.

Positive rational numbers cannot be added together.

a) The set is closed since the product of any two real numbers is a real number.

b) The quotient could occasionally be logical. (18/2) Equals 3, for instance. The set is thus not closed.

c) The set is closed since the difference between any two numbers is also an integer.

d) The set is closed since the product of any two positive rational numbers is a positive rational number.

The complete question is

Select from the drop-down menus to correctly identify whether the given operation is closed or not closed with respect to each set of numbers.

Real numbers are Closed/Not Closed under multiplication.

Irrational numbers are Closed/Not Closed under division.

Integers are Closed/Not Closed under subtraction.

Positive rational numbers are Closed/Not Closed under addition.

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The probability of choosing 2 students who both play soccer from a class of 10 students, where 5 students play soccer, is 5/6 or 0.83.

The probability of choosing 2 students who both play soccer from a class of 10 students, where 5 students play soccer, can be calculated using the formula for combinations:

[tex]C(5,2) =\frac{5!}{(2! * (5-2)!)}[/tex]

           [tex]= \frac{10}{(2 * 3!)} \\ \\=\frac{10}{(2 * 6) } \\\\= \frac{5}{6}[/tex]

So, the probability of choosing 2 students who both play soccer is 5/6 or 0.83.

This means that if the teacher randomly selects 2 students from the class, there is an 83% chance that both of them play soccer.

In conclusion, the probability of choosing 2 students who both play soccer from a class of 10 students, where 5 students play soccer, is 5/6 or 0.83.

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30 degrees Celsius in Fahrenheit is 86

What is 30 degrees Celsius in Fahrenheit?

      30ºC = 86ºF

calulation:

           T(ºF) = 30ºC × 9/5 + 32 = 86ºF

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Answer:

9

Step-by-step explanation:

7 x (9 x 2) = (7 x 9) x 2  This is the associative property.

7 x ( 18) = (63) x 2

126 = 126