Evaluate z- (y-z) if z= 4 and y =6

The solution is, their ages are 13 & 39 yrs., when the sum of the ages of a man and his son is equal to twice the difference of that ages, the product of their ages is 507.

An equation is a  mathematical statement that is made up of two expressions connected by an equal sign.  In its simplest form in algebra, the definition of an equation is a mathematical statement that shows that two mathematical expressions are equal. For instance, 3x + 5 = 14 is an equation, in which 3x + 5 and 14 are two expressions separated by an 'equal' sign.

here, we have,

The sum of the ages of a man and his son is equal to twice the difference of that ages,

the product of their ages is 507.

let, their ages are, a &b

now, The sum of the ages of a man and his son is equal to twice the difference of that ages,

so, we get,

a+b = 2(a-b)...(1)

and, ab = 507....(2)

we get,

from (1) we get,

solving both side,

2a - a = b + 2b

or, a = 3b

now, putting the value of a in (2),

from (2) we get,

so, 3b^2 = 507

solving we get,

b = 13

a= 39

Hence, The solution is, their ages are 13 & 39 yrs.

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The function T(t) has a vertical asymptote at t = 0, since the denominator T² approaches zero as t approaches 0.

A differential equation is an equation that contains one or more functions with its derivatives.

The given function is T(t)=1-5/t²

We need to find the vertical asymptote of the given function.

To find the vertical asymptotes, set the denominator equal to zero and solve for t.

The function T(t) has a vertical asymptote at t = 0, since the denominator T² approaches zero as t approaches 0 from either side.

There are no other vertical asymptotes for T(t).

Hence, the function T(t) has a vertical asymptote at t = 0, since the denominator T² approaches zero as t approaches 0.

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Answer:

the answer to your question is x=3.

Step-by-step explanation:

hope this helps.

Since x is less than -6, we use the first equation to calculate h(-6):

h(-6) = 4(-6) - 20 = -24

A function is a mathematical concept that assigns to each input value (or "argument") exactly one output value (or "image"). In other words, a function is a rule that assigns a unique output for each input value. The set of input values is called the domain of the function, and the set of output values is called the range. A function can be represented graphically as a curve, or analytically as a formula. Functions play a central role in many areas of mathematics, science, and engineering.

For x < -6, h(x) = -4x - 20. So, h(-6) = -4(-6) - 20 = 24 - 20 = 4.

For -6 ≤ x < 1, h(x) = x + 5. So, h(0) = 0 + 5 = 5.

For x ≥ 1, h(x) = 1. So, h(1) = h(7) = 1.

So, the values are:

h(-6) = 4, h(0) = 5, h(1) = h(7) = 1.

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The percentage discount is 95 percent

A percentage discount is a reduction in price that is expressed as a percentage of the original price.  Percentage discounts are commonly used in retail sales and promotions to incentivize customers to make purchases.

To determine the percentage discount of the orange, we can find the original price.

0.75 * 7 = 5.25

This is the cost of orange

The total amount charged = 4.30

The discount = 5.25 - 4.30 = 0.95

The percentage discount will be;

percentage discount = 0.95 * 100 = 95%

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The statement as an algebrai equation is x + 1/3 = 3/4

From the question, we have the following parameters that can be used in our computation:

The sum of X and one third is three fourths

In mathematics and algebra, we have

One third = 1/3

Three fourths = 3/4

So, the statement becomes

The sum of X and 1/3 is 3/4

Express as a summation equation

This gives

x + 1/3 = 3/4

Hence, the equation is x + 1/3 = 3/4

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The distance between the rests in the new map is 0.825 inches.

We know that the original scale is:

2 in = 33mi

or:

1 in = (33mi)/2

1in = 16.5 mi

And on a highway, there are 7 rests in 9 inches.

First, we transform these 9 inches to miles

9 in = 9*(16.5 mi) = 148.5 mi

If the 7 rests are evenly divided in that distance, the distance between each rest is:

148.5mi/6 = 24.75mi

(we divide by 6 because one rest is at each end, so there are 6 even spaces between the two ends)

Now, in the new map the scale is:

1 inch = 30mi

Then the distance between the rests in the new map is:

d = 24.75/30 inches

d = 0.825 inches.

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Answer:

1 cup: 80 cups

Step-by-step explanation:

A unit can be used for measurement and is commonly found in mathematics to describe length, size, etc.

To solve for the number of cups in 5 gallons, we can use this equation:

So, for every 5 gallons there are 80 cups.

The ratio now looks like this:

Therefore, the ratio of bleach to water in the wash is 1: 80

Step-by-step explanation:

arrange ff fraction 5/6,8/9,23

The volume of the solid generated by revolving the region about the y-axis is approximately 0.200 cubic units.  

To use the shell method to find the volume of the solid generated by revolving the region bounded by the curves [tex]$y=1$[/tex], [tex]$y=\frac{1}{2\pi e^{x^2/7}}$[/tex], [tex]$x=0$[/tex], and [tex]$x=1$[/tex] about the y-axis, we need to integrate along the x-axis.

The basic idea of the shell method is to take a vertical strip of width [tex]$dx$[/tex]and height [tex]$f(x)$[/tex] and revolve it about the y-axis to generate a thin shell of thickness [tex]$dx$[/tex] and radius x.

The volume of the solid is then given by the integral:

[tex]$$V = \int_{x=0}^{x=1} 2\pi x f(x) dx $$[/tex]

where [tex]$f(x)$[/tex] is the height of the shell at the position [tex]$x$[/tex]. In this case,

[tex]$f(x) =[/tex] [tex]1 - \frac{1}{2\pi e^{x^2/7}}$.[/tex]

So, we have:

[tex]$$V = \int_{x=0}^{x=1} 2\pi x \left(1 - \frac{1}{2\pi e^{x^2/7}}\right) dx $$[/tex]

Now, we can evaluate this integral using integration by substitution.

Let [tex]$u=x^2/7$[/tex], so [tex]$du/dx = 2x/7$[/tex] and [tex]$x,dx = 7/2,du$[/tex]. The integral becomes:

[tex]$$V = \int_{u=0}^{u=1/7} \frac{2\pi}{7} e^{-u} (7/2) du = \pi\int_{0}^{1/7} e^{-u} du$$[/tex]

Evaluating this integral gives:

[tex]$$V = \pi\left[-e^{-u}\right]_{0}^{1/7} = \pi\left(1 - e^{-1/7}\right) \approx \boxed{0.200}$$[/tex]

Therefore, the volume of the solid generated by revolving the region about the y-axis is approximately 0.200 cubic units.

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Using the triangular inequality we will get that:

A) 2 < x < 34.

B) 0 < x < 130

For a triangle with sides A, B, and C, the triangular inequality says that:

A + B > C

A + C > B

B + C > A

A) two lengths are 18 yards and 16 yards, and the missing length is x, so we can write:

18 + x > 16    →   x > 16 - 18 = -2

16 + x  > 18   →   x > 18 - 16 = 2

16 + 18 > x     →  34 > x

Taking the two more restrictive ones, we can see that 2 < x < 34.

B) Same thing:

x + 65 > 65

x + 65 > 65

65 + 65 >  x

If we simplify that, we will get:

0 < x < 130

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The given list of functions can be arranged in ascending order of growth rate as follows: g1(n), g5(n), g3(n), g4(n), g2(n), g6(n), and g7(n).

The Big O notation describes the upper bound of a function's growth rate. In other words, it represents the maximum amount of time or space that a function requires to complete its operations.

Using this concept, we can arrange the given list of functions in ascending order of growth rate as follows:

g1(n) = √2 log n: This function has a growth rate of O(log n), which is less than the growth rates of all other functions in the list.

g5(n) = n log n: This function has a growth rate of O(n log n), which is greater than the growth rate of g1(n), but less than the growth rates of all other functions in the list.

g3(n) = n 4/3: This function has a growth rate of O(n 4/3), which is greater than the growth rates of g1(n) and g5(n), but less than the growth rates of all other functions in the list.

g4(n) = n(log n)3: This function has a growth rate of O(n(log n)3), which is greater than the growth rates of g1(n), g5(n), and g3(n), but less than the growth rates of all other functions in the list.

g2(n) = 2n: This function has a growth rate of O(2n), which is greater than the growth rates of g1(n), g5(n), g3(n), and g4(n), but less than the growth rates of g6(n) and g7(n).

g6(n) = 22 n: This function has a growth rate of O(2n), which is greater than the growth rates of g1(n), g5(n), g3(n), g4(n), and g2(n), but less than the growth rate of g7(n).

g7(n) = 2n2: This function has a growth rate of O(2n2), which is greater than the growth rates of all other functions in the list.

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Complete Question:

Arrange the following list of functions in ascending order of growth rate, i.e. if the function g(n) immediately follows f(n) in your list then, it should be the case that f(n) = O(g(n)).

g1(n) = √2 log n

g2(n) = 2n

g3(n) = n 4/3

g4(n) = n(log n)3

g5(n) = n log n

g6(n) = 22 n

g7(n) = 2n2

Using Pythagorean theorem, the distance from the top of the hill to the bottom is 404.5 feet

The Pythagorean Theorem is a mathematical concept that states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. In mathematical terms, the theorem can be expressed as:

x^2 = y^2 + z^2,

where x is the length of the hypotenuse, and y and z are the lengths of the other two sides.

From the diagram given, we can find the hypothenuse by;

x² = 60² + 400²

x² = 163600

x = √163600

x = 404.5ft

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The probability of flipping a heads or tails is the same, which is P(H or T) = 1.0.

The experiment of flipping a coin is an example of a binomial experiment as it has two possible outcomes, heads (H) or tails (T). The trial is the act of flipping the coin, and the outcome is the result of the flip, either heads or tails. The probability of flipping a heads is 50%, which can be expressed as a fraction: P(H) = 1/2, or a decimal: P(H) = 0.5. The probability of flipping a tails is also 50%, which can be expressed as P(T) = 1/2, or P(T) = 0.5. Therefore, the probability of flipping a heads or tails is the same, and this probability can be calculated as follows: P(H or T) = P(H) + P(T) = 0.5 + 0.5 = 1.0.

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The Least Common Multiple ( LCM ) of 20 and 48 is 240

The Greatest Common Divisor GCF or the Highest Common Factor HCF is the highest number that divides exactly into two or more numbers. It is also expressed as GCF or HCF

Least Common Multiple (LCM) is a method to find the smallest common multiple between any two or more numbers. A common multiple is a number which is a multiple of two or more numbers

Product of HCF x LCM = product of two numbers

Given data ,

Let the first number be A

Now , the value of A = 20

Let the second number be B

Now , the value of B = 48

The least common multiple LCM of A and B is calculated by

Prime factorization of 20 = 2 x 2 x 5

Prime factorization of 48 = 2 x 2 x 2 x 2 x 3

Now , LCM = 2 × 2 × 2 × 2 × 3 × 5

The LCM of 20 and 48 = 240

Hence , the LCM is 240

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Answer:

djsushf sjsushsjd sjdusbs

Step-by-step explanation:

iahsjsidjdjdudjdbdjdid

a) The distribution of Z is given by: P(Z = 1) = 1 - F(2T, T), P(Z = 0) = F(2T, T)

b) X and Z are not independent,  Y and Z are not independent, and pair (X, Y) and Z are also not independent.

c) )X and Y are not independently existent.

a) The distribution of Z can be determined by finding the probability that S > 2T. Let F(s,t) be the joint cumulative distribution function of S and T. The probability that S > 2T is given by:

P(Z = 1) = P(S > 2T) = ∫∫_{2t < s} f(s,t) ds dt = 1 - F(2T, T)

Since T is nonnegative and has a continuous distribution, the cumulative distribution function F(2T, T) is also continuous and ranges from 0 to 1. Therefore, the distribution of Z is given by:

P(Z = 1) = 1 - F(2T, T), P(Z = 0) = F(2T, T)

b) X and Z are not independent, since the value of X affects the probability that S > 2T. For example, if X = x, then T >= x/2, so the value of Z depends on the value of X. Similarly, Y and Z are not independent, since the value of Y affects the probability that S > 2T. For example, if Y = y, then T <= y/2, so the value of Z depends on the value of Y.

The pair (X, Y) and Z are also not independent since the joint distribution of (X, Y) affects the probability that S > 2T. For example, if (X, Y) = (x, y), then T >= x/2 and T <= y/2, so the value of Z depends on the values of X and Y.

c) X and Y are not independent, since the value of X affects the value of Y. For example, if X = x, then Y >= x, so the value of Y depends on the value of X.

The complete question is:-

(Order statistics and independence) Let X be the minimum and Y the maximum of two independent, nonnegative random variables S and T with common continuous density f. Let Z denote the indicator function of the event (S > 2T). a) What is the distribution of Z? b) Are X and Z independent? Are Y and Z independent? Are (X, Y) and Z independent? c) Is X independent of Y?

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The composite function of f(x) and g(x) is given as follows:

f(g(x)) = 6x² - 10x - 21.

The composite function of f(x) and g(x) is given by the following rule:

(f ∘ g)(x) = f(g(x)).

It means that the output of the inside function serves as the input for the outside function.

The function g(x) in this problem is given as follows:

g(x) = 3x² - 5x - 7.

Hence, for the composite function in this problem, the lone instance of x in f(x) is replaced by 3x² - 5x - 7, as follows:

f(g(x)) = f(3x² - 5x - 7) = 2(3x² - 5x - 7) - 7 = 6x² - 10x - 21.

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the volume of the solid is x²/2R.

Let x be the length of the base of the rectangle.

The volume of the solid is given by:

V = ∫R 2x dx

= 2∫R x dx

= 2[x²/2]∫R dx

= x²/2 ∫R dx

= x²/2 (R - 0)

= x²/2 R

The volume of the solid is given by the integral of the cross sectional area of the solid. The cross sectional area is a rectangle whose base is x and the height is twice the length of the base. Therefore, the area of the cross section is 2x. The volume of the solid is calculated by integrating the area over the range of the variable, which in this case is R. The integral of 2x over the range R is 2x times R (2x*R). This can be simplified to x squared over two times R (x^2/2*R). Therefore, the volume of the solid is x squared over two times R.

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Step-by-step explanation:

from red to green the scale factor was 2 (or rather 1/2).

so, it is not clear if a scale factor of 3 means now enlargement or again reduction ?

if it means reduction then

A'' = A'/3 = (-4, -2)/3 = (-4/3, -2/3)

if it is enlargement then

A'' = A'×3 = (-4, -2)×3 = (-12, -6)

The  answer of this queation :∫ (4 + √x + x/x) dx = 4x + 2/3 x^(3/2) + x + C

where C = C1 + C2 + C3 is the constant of integration for the entire expression.

eparate integrals:

∫ 4 dx + ∫√x dx + ∫ x/x dx

The first two integrals can be easily integrated as follows:

∫ 4 dx = 4x + C1, where C1 is a constant of integration.

∫√x dx = 2/3 x^(3/2) + C2, where C2 is a constant of integration.

For the third integral, note that x/x simplifies to 1 for all nonzero x.

∫ x/x dx = ∫ 1 dx = x + C3, where C3 is a constant of integration.

Putting it all together, we have:

∫ (4 + √x + x/x) dx = 4x + 2/3 x^(3/2) + x + C

where the integration constant for the entire statement is C = C1 + C2 + C3.

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The integral Z sec3 x dx can be solved using substitution in two ways: either with u = tan x, or with u = sec x. The solutions are x + 1/4 (tan x)4 + C and 1/3 (sec x)3 + C, respectively.

a) Let u = tan x. Then du = sec2 x dx and dx = du/sec2 x, so

Z sec3 x dx = Z sec3 (tan x) (du/sec2 x)

                = Z sec2 (tan x) du

                = Z u sec2 u du

                = Z u (1 + u2) du

                = Z du + Z u3 du

                = x + 1/4 u4 + C

                = x + 1/4 (tan x)4 + C

b) Let u = sec x. Then du = sec x tan x dx = sec2 x dx and dx = du/sec2 x, so

Z sec3 x dx = Z sec3 (sec x) (du/sec2 x)

                = Z sec2 (sec x) du

                = Z u2 du

                = 1/3 u3 + C

                = 1/3 (sec x)3 + C

The integral Z sec3 x dx can be solved using substitution in two ways: either with u = tan x, or with u = sec x. The solutions are x + 1/4 (tan x)4 + C and 1/3 (sec x)3 + C, respectively.

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The solution to the parts of the question with regards to the quadratic equation are;

A quadratic equation is an equation of the form f(x) = a·x² + b·x + c

The discriminant, D, of a quadratic equation, f(x) = a·x² + b·x + c, can be obtained using the expression;

D = b² - 4 × a × c

The specified quadratic function is; -4·z² - 3·z + 5 = 0

The discriminant, D of the above quadratic expression is therefore;

D = (-3)² - 4 × (-4) × 5 = 89

The discriminant is larger than zero, therefore, the quadratic expression has two solutions.

The two method to be used to find the specific solution are;

Quadratic Formula;

The solutions of the quadratic equation based on the quadratic formula are;

z = (-(-3) ± √((-4)² - 4 × (-4) × 5))/(2 × (-4))

z = (3 ± √(89))/(-8)

Completing the Square

The completing the square method can be used as follows;

-4·z² - 3·z + 5 = 0

z² + (3/4)·z - 5/4 = 0

z² + (3/4)·z  = 5/4

z² + (3/4)·z + ((3/4)/2)² = 5/4 + ((3/4)/2)²

z² + (3/4)·z + (3/8)² = 5/4 + (3/8)²

(z + (3/8))² = 5/4 + (3/8)²

z + (3/8) = ±√((5/4) + (3/8)²)

z = ±√(5/4 + (3/8)²) - (3/8)

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Morse's monthly budget has a surplus of $3,860 (rounded to the nearest whole number).

From the we are to calculate Morse's monthly budget.

To determine Morse's monthly budget, we need to first calculate his total annual expenses:

Total Annual Expenses = Fixed Expenses + Living Expenses + Annual Expenses

= $2,117 + $489 + $475

= $3,081

Then, we can calculate his monthly budget by dividing his annual net income by 12:

Monthly Budget = Annual Net Income / 12

= $49,397 / 12

= $4,116.42

Now, we can determine Morse's monthly budget by subtracting his total monthly expenses from his monthly net income:

Monthly Budget = Monthly Net Income - Monthly Expenses

Monthly Net Income = Annual Net Income / 12 = $49,397 / 12 = $4,116.42 (rounded to the nearest cent)

Monthly Expenses = Total Annual Expenses / 12 = $3,081 / 12 = $256.75 (rounded to the nearest cent)

Monthly Budget = $4,116.42 - $256.75 = $3,859.67

Hence, Morse's monthly budget has a surplus of $3,860

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The missing sides of the triangles are given below.

Length is defined as the measurement of distance of an object from one end to the other.

To find the missing sides of the given triangles.

Question 1 :

In the triangle, consider sin 90° = [tex]\frac{opposite side}{hypotenuse side}[/tex]

                                               1 = [tex]\frac{13}{x}[/tex]

                                              ⇒ x = 13

Which is the length of the missing side of the triangle.

Question 2:

In this triangle, consider degree 63° we have to find the  length of hypotenuse side, then,

sin 63° =[tex]\frac{opposite side }{hypotenuse side}[/tex] = [tex]\frac{18}{x}[/tex]

0.89 x = 18

⇒ x = 18/0.22 = 20.22.

Length of the hypotenuse side is 20.22 cm.

Question 4:

In this triangle, consider cos function.

sin 18°= [tex]\frac{opposite side}{hypotenuse}[/tex] = x/11

0.3090*11 = x

x = 3.399 = 3.4 inches.

Question 5:

consider sin angle.

sin 90° = [tex]\frac{opposite side}{hypotenuse}[/tex] = x/21

⇒x = 21 yard.

Question: 6

For this triangle we consider, tan functions.

tan 43° = [tex]\frac{opposite side}{adjacent side}[/tex] = x/23

⇒ x =21.4 mm.

Question 7:

For this triangle , we consider sin function.

sin 33° = 9/x

⇒0.5446 *x=9/0.5446

⇒x = 16.5km

Question 8:

For this triangle we have to choose tan function,

tan67 ° = opposite side/ adjacent side

            = 17/x

⇒x = 7m

Question 9:

For this triangle, we take sin function.

sin 90°= opposite side/hypotenuse

        1   = x/19

⇒x = 19m

Question 10:

For this triangle we consider sin function,

sin 90°= 26/x

⇒x = 26 feet.

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The volume of material in a cylindrical shell is 180π.

Cylindrical shell with height 30 in & radius 6 in & and shell thickness 0.5 in.

We estimate the volume of material by using differentials dV with r=6 and d r=0.5.

One way to think of a cylinder is as a grouping of numerous congruent discs piled one on top of the other. We determine the area occupied by each disc separately, add them together, and then determine the area filled by a cylinder. As a result, the product of the base area and height can be used to determine the cylinder's volume.

The volume of a cylindrical shell is

Where, base radius ‘r’, and height ‘h’, the volume will be base times the height.

So,  [tex]$\frac{d V}{d r}=2 \pi r h$[/tex].

[tex]dV & =2 \pi r h d r \\[/tex]

[tex]& =2 \pi \cdot 6 \cdot 30 \cdot 0.5 \\& =180 \pi .[/tex]

Therefore, the volume is 180π.

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Answer: draw a number line and plot the 0, 1 , and 2

Explanation:

The set of all numbers x that are at a distance of 3 from the number 11 is {8, 14} or can be expressed using absolute value notation: |x - 11| = 3

The set of all numbers x that are at a distance of 3 from the number 11 can be described using absolute value notation as:

|x - 11| = 3

The absolute value of x minus 11 must be equal to 3. This can be interpreted geometrically as the set of all points on the number line that are 3 units away from the point 11. These points can be found by adding and subtracting 3 from 11, giving us the two solutions:

x = 11 + 3 = 14

x = 11 - 3 = 8

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