Answer:
The value of [tex]x(y-z)^2[/tex] is -16.
Step-by-step explanation:
We need to evaluate [tex]x(y-z)^2[/tex] for x = -1, y = 5 and let us assume that z = 1
It can be simply done by putting the values of x,y and z in the given expression.
[tex]x(y-z)^2=(-1)(5-1)^2\\\\=-1(4)^2[/tex]
We know that the value of 4² = 16
So,
[tex]x(y-z)^2=16\times -1\\\\=-16[/tex]
So, the value of [tex]x(y-z)^2[/tex] is -16.
The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between and minutes. Find the probability that a randomly selected passenger has a waiting time minutes. 0 7 greater than 1.25
Complete Question
The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 7 minutes. Find the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes.
Answer:
The probability is [tex]P(X > 1.25) = 0.8214[/tex]
Step-by-step explanation:
From the question we are told that
The start time is a = 0 minutes
The end time is b = 7 minutes
Generally the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes is mathematically represented as
[tex]P(X > 1.25) = 1 - P(X \le 1.25)[/tex]
=> [tex]P(X > 1.25) = 1 - \frac{1.25 - a}{ b- a }[/tex]
=> [tex]P(X > 1.25) = 1 -0.1786[/tex]
=> [tex]P(X > 1.25) = 0.8214[/tex]
what is the answer !
Answer:
m∠OKG = 95°
Step-by-step explanation:
In the given question,
Angle OKL and angle OKG are the linear pairs.
And we know that sum of linear pair of angles is 180°.
Therefore, m∠OKL + m∠OKH = 180°
85° + m∠OKH = 180°
m∠OKH = 180° - 85°
= 95°
Therefore, measure of angle OKG = 95° will be the answer.
The Sorry State Lottery requires you to select five different numbers from 0 through 42. (Order is not important.) You are a Big Winner if the five numbers you select agree with those in the drawing, and you are a Small-Fry Winner if four of your five numbers agree with those in the drawing. (Enter your answers as exact answers.) What is the probability of being a Big Winner?
Answer:
1 / 962598
Step-by-step explanation:
Let S be the sample space
total number of possible outcomes = n(S)
Let E be the event
total number of favorable outcomes = n(E)
Compute the number of ways to select 5 numbers from 0 through 42:
Total numbers to choose from = 43
So
Total number of ways to select 5 numbers from 43
= n(S) = 43C5
= 43! / 5! ( 43-5)!
= 43! / 5! 38!
= 43*42*41*40*39*38! / (5*4*3*2*1)*38!
= 115511760/120
n(S) = 962598
Hence there are 962598 ways to select 5 numbers from 43
Compute the probability of being a Big Winner
In order to be a Big Winner all 5 of the 5 winning balls are to be chosen and there is only one way you can for this event to occur. So
n(E) = 1
Here E is to be a Big Winner
So probability of being a Big Winner = P(E)
= n(E) / n(S)
= 1 / 962598
Hence
P(being a Big Winner) = P(E) = 1 / 962598
Mr. Monasterio ran to The Burrito Barn at 10mph. He ate too many burritos and slowed to 6 mph on the way home. Find the time going to The Burrito Barn if the time coming back took 2 hours more than the time going. Don't forget to include units. PLS HELP RIGHT NOW
Answer:
1 h with 20 min
Step-by-step explanation:
10-6 = 100-60
= 40, in percentages is 40%, 40% minus of 2 h is...
if 50% minus is 1 h, 40% is 1 h with 20 min or simply...
120 min - 40% = 120 - 40
120 - 40 = 80, 80 min are 1 h and 20 min
Hope this helps
Torricelli's hypothesis was consistent with the hypothesis that nature abhors a vacuum.
a. True
b. False
Answer:
False
Step-by-step explanation:
Torricelli once carried out a tube and mercury experiment to test the scientific claim that nature abhors a vacuum.
In his experiment, he used glassblowers to make a long glass tube which was 4 ft long with a closed end.
He filled the tube with mercury and put his finger over the open end. Thereafter, he turned the tube upside down, dipped the open end in a bowl of mercury, and then removed his finger from the open end. He discovered that the mercury in the tube didn't completely run out as it fell to around 30 inches above the bowl before it stopped.
The gap between the sealed top end of the tube and the top end of the fallen mercury was an empty space which is a vacuum.
The hypothesis that "nature abhors a vacuum" would have implied that the vacuum would have pulled the mercury and held it up in the tube. However, that wasn't the case with his experiment and it proves that nature doesn't abhor a vacuum.
Thus, it is false.
What is the result of subtracting the polynomial (x²+3x) from the polynomial (-2x + 4x² + 5) ? A 3x² - x -5 B -3x²+x +5 C 3x² - 5x + 5 D -3x² + 5x - 5
Answer:
C
Step-by-step explanation:
We need to first rewrite the equation the proper way.
(-2x+4x²+5)-(x²+3x)
We need to distribute the negative thought the 2nd set of parenthesis.
-2x+4x²+5-x²-3x
combine the same terms
3x²-5x+5
For a confidence level of 98% with a sample size of 30, find the critical t value.
The critical t-value for a confidence level of 98% with a sample size of 30 is approximately 2.756.
To find the critical t-value for a confidence level of 98% with a sample size of 30, we'll use the t-distribution table or a statistical calculator. Here's how you can calculate it:
Determine the degrees of freedom (df) for the t-distribution. For a sample size of 30, the degrees of freedom will be df = n - 1 = 30 - 1 = 29.
Look up the critical t-value in the t-distribution table using the desired confidence level and the degrees of freedom. In this case, for a 98% confidence level, we're interested in the critical value that leaves 1% in the tails of the t-distribution. Since the distribution is symmetric, we divide the 1% by 2 to get 0.5% for each tail.
Locate the row in the t-distribution table corresponding to the degrees of freedom (29 in this case). Then, look for the column that corresponds to the desired significance level (0.005 or 0.5% in this case).
Using a statistical calculator or t-distribution table, we find that the critical t-value for a 98% confidence level and 29 degrees of freedom is approximately 2.756.
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The critical t-value for a confidence level of 98% is 2.756.
Given data:
To find the critical t-value for a confidence level of 98% with a sample size of 30, use a t-distribution table or a calculator.
Since the sample size is small (less than 30) and the population standard deviation is unknown, we use the t-distribution instead of the standard normal distribution.
The critical t-value is determined based on the confidence level and the degrees of freedom (df), which is equal to the sample size minus 1.
For a 98% confidence level, the corresponding significance level (α) is 1 - 0.98 = 0.02. Since it's a two-tailed test, divide this significance level by 2 to find the area in each tail: 0.02 / 2 = 0.01.
With a sample size of 30, the degrees of freedom is 30 - 1 = 29.
Using a t-distribution table or a calculator, we find the critical t-value with a cumulative probability of 0.01 (in each tail) and 29 degrees of freedom.
The critical t-value for a confidence level of 98% with a sample size of 30 is approximately ±2.756.
Hence, the critical t-value is 2.756.
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For what value of a is the equation: (x + 7)2 = (x − 7)2 + ax an identity? (An identity is an equation in which any number is solution. For example, x + 3 = 3 + x is an identity.)
Answer:
Step-by-step explanation:
Hello, we need first to develop and then identify the like terms.
[tex](x + 7)^2 = (x-7)^2 + ax\\\\(x+7)^2-(x-7)^2=ax\\\\(x+7-x+7)(x+7+x-7)=ax\\\\14*2x=ax\\\\28x=ax[/tex]
So a = 28.
Thank you
Find 8 + 35 + (- 56).
A medical researcher wants to compare the pulse rates of smokers and non-smokers. He believes that the pulse rate for smokers and non-smokers is different and wants to test this claim at the 0.01 level of significance. A sample of 75 smokers has a mean pulse rate of 76, and a sample of 73 non-smokers has a mean pulse rate of 72. The population standard deviation of the pulse rates is known to be 9 for smokers and 10 for non-smokers. Let µ1 be the true mean pulse rate for smokers and µ2 be the true mean pulse rate for non-smokers.
Step 1 of 5: State the null and alternative hypotheses for the test.
Step 2 of 5: Compute the value of the test statistic. Round your answer to two decimal places.
Step 3 of 5: Find the p-value associated with the test statistic. Round your answer to four decimal places.
Step 4 of 5: Make the decision for the hypothesis test.
Step 5 of 5: State the conclusion of the hypothesis test.
Answer:
We conclude that the pulse rate for smokers and non-smokers is equal.
Step-by-step explanation:
We are given that a medical researcher wants to compare the pulse rates of smokers and non-smokers.
A sample of 75 smokers has a mean pulse rate of 76, and a sample of 73 non-smokers has a mean pulse rate of 72. The population standard deviation of the pulse rates is known to be 9 for smokers and 10 for non-smokers.
Let [tex]\mu_1[/tex] = true mean pulse rate for smokers
[tex]\mu_2[/tex] = true mean pulse rate for non-smokers
So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu_1=\mu_2[/tex] {means that the pulse rate for smokers and non-smokers is same}
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu_1\neq \mu_2[/tex] {means that the pulse rate for smokers and non-smokers is different}
The test statistics that will be used here is Two-sample z-test statistics because we know about the population standard deviations;
T.S. = [tex]\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{\sqrt{\frac{\sigma_1^{2} }{n_1}+\frac{\sigma_2^{2} }{n_2}} }[/tex] ~ N(0,1)
where, [tex]\bar X_1[/tex] = sample mean pulse rate of smokers = 76
[tex]\bar X_2[/tex] = sample mean pulse rate of non-smokers = 72
[tex]\sigma_1[/tex] = population standard deviation of the pulse rates of smokers = 9
[tex]\sigma_2[/tex] = population standard deviation of the pulse rates of non-smokers = 10
[tex]n_1[/tex] = sample of smokers = 75
= sample of smokers = 73
So, the test statistics = [tex]\frac{(76-72)-(0)}{\sqrt{\frac{9^{2} }{75}+\frac{10^{2} }{73}} }[/tex]
= 2.56
The value of the z-test statistics is 2.56.
Also, the P-value of the test statistics is given by;
P-value = P(Z > 2.56) = 1 - P(Z [tex]\leq[/tex] 2.56)
= 1 - 0.9948 = 0.0052
For the two-tailed test, the P-value is calculated as = 2 [tex]\times[/tex] 0.0052 = 0.0104.
Now, at a 0.01 level of significance, the z table gives a critical value of -2.58 and 2.58 for the two-tailed test.
Since the value of our test statistics lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.
Therefore, we conclude that the pulse rate for smokers and non-smokers is equal.
Find a vector 6 unit long in the direction of A = 2i + 2j – 1k
Answer:
B=4i+4j-2k
Step-by-step explanation:
Lets find the length of vector A
IAI= sqrt(2²+2²+1²)=sqrt(9)=3
So B=2*A = 2(2i+2j-1k)=4i+4j-2k
Assume the random variable X is normally distributed with mean and standard deviation . Compute the probability. Be sure to draw a normal curve with the area corresponding to the probability shaded. P(X)
Answer:
The answer is attached for better presentation of formulas.
Step-by-step explanation:
The areas under the normal curve between any two ordinates at X=a and X=b equals the probability that the r.v X lies in the interval [a,b]. that is P (a ≤ X ≤ b) = ∫_a^b▒1/(σ√2π) e^((-(x-u))/(2σ^2)) dx
which is represented by the area of the shaded region. (figure1)
But integrals of this type cannot be solved by ordinary means. They are however evaluated by the methods of numerical integration, and numerical approximations for some function have been tabulated for quick reference.
The table of areas under the unit normal curve gives the areas (probabilities) for the standard normal distribution from the mean, z=0 to a specified value of z say z0. Since normal curves are symmetrical therefore P (0 to z) = P (0 to –z). That is why the areas for negative values of z are not tabulated. Hence to use the table of areas for the normal distribution, the values of the r.v X in any problem are changed to the values of the standard normal variable Z and the desired probabilities are obtained from the table.
Thus to find P (a <X<b) we would change X into Z as follows
P (a <X<b) = P ((a-u)/σ ≤ (X-u)/σ ≤ (b-u)/σ )
= P ((a-u)/σ ≤ Z ≤ (b-u)/σ )
Where (a-u)/σ and (b-u)/σ are the z- values of the standard normal variable Z.
In practice, a normal curve sketch for the given problem, showing under the X scale, a scale for the corresponding values of z will help in solving problem. (Figure 2)
What makes your arguments convincing? Check any of the boxes that apply. I have strong opinions about many things. I can easily convince people that I’m right. I think about why I believe in things and use my beliefs to support my point. I back up my opinions with facts. I’m good at sounding like I know what I’m talking about, no matter what.
Answer:
Everything in the option.
When you know what you are doing and what you are saying then you can be able to convince your audience.
Answer:
I can easily convince people that I'm right
I back up my opinions with facts
Step-by-step explanation:
Correct on E2020
is -3/8 greater than - 2/7
On average the number of drum sets sold in Michigan each year is 96,537, which is seven times the average number of drum sets sold each year in Vermont. How many drum sets, on average, are sold each year in Vermont?
Answer:
13791
Step-by-step explanation:
Take 96,537 and divide by 7
find the measure of angle N in the parallelogram. Round your answer to the nearest degree
In a parallelogram opposite angles are identical so K and M are the same. Solve for K first:
6x +3 = -9 + 7x
Add 9 to both sides:
6x + 12 = 7x
Subtract 6x from both sides:
X = 12
K = 6(12) + 3 =72 +3 = 75
Now K + N = 180
N = 180 - 75 = 105
N = 105
Answer:
ANGLE N = 105°
Step-by-step explanation:
The opposite angles of a parallelogram are equal
Therefore,
-9+7x = 6x+3
Bringing variables to one side
7x-6x = 3+9
x= 12
Since , x = 12
So , Angle K = 6x+3= 6(12)+3
= 72+3
=75
In a parallelogram , adjacent angles are supplementary
i.e, Angle K +Angle N = 180°
75 + Angle N = 180°
Angle N = 180 -75
= 105 °
Simplify the expression below.
w^2-9
_____
w^2-4w-21
A. 3
_
4w+7
B. -9
—
-4w-21
C. w-3
___
w-7
D. w+3
___
w+7
Answer:
D
Step-by-step explanation:
w² - 9 can be factored as (w + 3)(w - 3) using the difference of squares. To factor w² - 4w - 21, we need to find 2 integers that have a sum of -4 and product of -21; these integers are -7 and 3 so the factored form is (w + 7)(w - 3). Therefore, the expression becomes:
(w + 3)(w - 3) / (w + 7)(w - 3)
Both the numerator and denominator have a factor of (w - 3) so that cancels out, leaving us with (w + 3) / (w + 7).
Will mark the brainliest
Please answer this im desperate :(((
Answer:
Last option
Step-by-step explanation:
I think it would be the last option because when you reflect over the x-axis, the x-axis switched signs.
So, -8 would be 8 , -7 would be 7, and 3 would be negative 3.
Dont think the y-axis value would change..
Hope this helps!
(If this was good..please give brainly.)
Answer:
Option C
Step-by-step explanation:
They are the same coordinates but exchanged/reflected places
please gimme brainiest ;(
Warmup Day 1
(5^2+ 4) x 5 - 2 + (-4)
Please work this Problem out step by step
x Clear
Undo
Answer: 139
Step-by-step explanation:
(5^2+4)*5-2+(-4)
(25+4)*5-2+(-4)
29*5-2-4
145-2-4
139
Need help and show work plz
Answer:
[tex]\frac{1716}{132600}[/tex]
Step-by-step explanation:
Assuming they removed the jokers there are 52 cards in a deck and 13 hearts
You can calculate the odds of something by multiplying the odds together, because you don't put back the card you drew you have to subtract 1 from both the numerator and denominator
[tex](\frac{13}{52})(\frac{12}{51})(\frac{11}{50})=\frac{1716}{132600}[/tex]
Therefore the probability of pulling 3 cards that are all hearts are [tex]\frac{1716}{132600}[/tex]
PLZZZZZZZZ HELP ME I WILL GIVE BRAINLIEST TO THE FASTEST AND MOST ACCURATE
Answer: What is the question? You have not posted a inquiry...
What is the equation of the quadratic function represented by this table?
Step-by-step explanation:
[tex]y = a {(x - h)}^{2} + k[/tex]
[tex]vertex = (h \: \: \: k)[/tex]
from the table
[tex]vertex = ( - 2 \: \: \: 4)[/tex]
therefore
[tex]h = - 2 \: \: and \: \: k = 4[/tex]
[tex]y = a {(x + 2)}^{2} + 4[/tex]
when x= 0, y = 3
[tex]3 = a {(2)}^{2} + 4[/tex]
[tex]3 = 4a + 4[/tex]
[tex]a = \frac{ - 1}{4} [/tex]
therefore equation of the function
[tex]y = - \frac{1}{4} {(x + 2)}^{2} + 4[/tex]
what is 82 degrees below 0
Answer:
-82°
Step-by-step explanation:
If we go 82° below 0, that means that instead of increasing by 82, we are decreasing by 82.
If we decrease to a number below 0, it becomes a negative number.
For example: If we decrease 10° from 0, we'd be at -10°.
Likewise, if we decrease 2° from 0, we'd be at -2°.
Following this pattern, if we decrease 82° from 0, we'd be at -82°.
Hope this helped!
Pythagorean Theorem:a2 + b2 = c2 Re−write the formula solving for b2 .
Answer: c2 - a2 = b2
Step-by-step explanation: to isolate b2 you have to subtract a2 from both sides to get c2 - a2 = b2
Find the missing term in the
geometric sequence.
13,[ ? 1,208
Answer:
Step-by-step explanation:
Step 1: the first term a is 13
Which means a=13 let's make this equation i
And the third term ar^3-1 = 1208
= Ar²= 1208 let's make this equation ii
Step 2: subtititute equation i into equation ii
= 13r²=1208
Divide both sides by 13 it gives us
13r²/13 = 1208/13
r²= 92.92
r= 9.64
So the second term ar^2-1
=ar
= 13. 9.64
= 125.32
A cubical tank of edge 30 cm was filled with water up to of its height.
6
Then 5500 cm3 of water were added. How much water was there in the tank in
the end? Give your answer in litres.
Answer:
10.9 liters
Step-by-step explanation:
cubical tank size = 30 x 30 x 30
filled with 6 cm x 30 cm x 30 cm = 5400 cu.cm
then added 5500 cu.cm.
total volume on a cubical tank = 5400 cu.cm + 5500 cu.cm
total volume on a cubical tank = 10,900 cu.cm x 1 cu.cm/0.001 liters
total volume on a cubical tank = 10.9 liters
Answer:
Step-by-step explanation:
= 10.9 liters
Solve the equation using the quadratic formula. Please help !
Answer:
decimal
x = 5.284 or 0.284
fraction
x = (21.136) / 4 or (1.136) / 4
Step-by-step explanation:
2x² - 10x - 3 = 0
x = [-b ± √b² - 4(a)(c)] / 2(a)
x = {-(-10) ± √[(-10)² - 4(2)(-3)]} / 2(2)
x = [10 ± √(100 + 24)] / 4
x = (10 ± √124) / 4
x = (10 ± 11.136) / 4
x = (21.136) / 4 or (1.136) / 4
x = 5.284 or 0.284
I need help with this ! ❤️
Answer:
The correct answer is: (x,y)↦(x+ 8 ,y+ 16)
Hoped I helped
can someone help me pllzz
Answer:
directrix: y=4
focus: (-3,2)
vertex: (-3,3)
Step-by-step explanation:
Use cylindrical or spherical coordinates, whichever seems more appropriate. Evaluate ∫∫∫E z dV, where E lies above the paraboloid
z = x2 + y2
and below the plane z = 2y. Use either the Table of Integrals or a computer algebra system to evaluate the integral.
The required value of the triple integral is (16/3)π.
To evaluate the triple integral ∫∫∫E z dV, where E lies above the paraboloid z = x² + y² and below the plane z = 2y, we can use cylindrical coordinates.
In cylindrical coordinates, we have:
x = r cosθ
y = r sinθ
z = z
To determine the limits of integration, we need to find the bounds for r, θ, and z.
The paraboloid z = x² + y² can be expressed in cylindrical coordinates as z = r².
The plane z = 2y can be expressed in cylindrical coordinates as z = 2r sinθ.
To find the bounds for r, we set the two equations equal to each other:
r^2 = 2r sinθ
Simplifying the equation, we have:
r = 2 sinθ
Since the paraboloid lies above the xy-plane, the lower bound for r is 0.
To find the bounds for θ, we need to determine the range of θ that corresponds to the region of interest. This can be done by plotting the two surfaces and visualizing the region. From the equations, we can see that the region lies within the range 0 ≤ θ ≤ π.
To find the bounds for z, we need to determine the range of z between the two surfaces. The paraboloid is below the plane, so the lower bound for z is the equation of the paraboloid, z = r^2. The upper bound for z is the equation of the plane, z = 2r sinθ.
Therefore, the limits of integration are as follows:
0 ≤ r ≤ 2 sinθ
0 ≤ θ ≤ π
r² ≤ z ≤ 2r sinθ
Now, we can evaluate the triple integral:
∫∫∫E z dV = ∫[0,2π] ∫[0,∞] ∫[r²,(2r sin θ)] (r cos(φ) sin(θ)) dz dr dθ
= (16/3)π
Therefore, the value of the triple integral is (16/3)π.
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