Answer:
Amino acids, along with glucose, are reabsorbed in the glomerular system with a passive or active mechanism as the fluid travels through the entire renal tubular system and enters the circulation again.
Active mechanisms are those that require expenditure of energy, that is, expenditure of the energy currency, while the passive ones do not, they occur through spontaneous non-energy processes such as osmosis, the osmotic gradient and the difference in concentrations in different compartments.
Explanation:
Glomerular filtration is the regulator of the excretion of metabolites and toxic molecules or not necessary for our body. That is why if the amino acid values are high as well as those of glucose in urine, we will be facing a pathology.
If glucose is increased, it is because there is a glycemic peak in blood volume, hence possible diabetes.
And if the amino acids are increased, we could be facing an autoimmune or proteolytic pathology where a large amount of body proteins such as muscle proteins would be breaking down and releasing the amino acids that make it up, this phenomenon usually appears in those people who suffer from rhabdomyolysis in expenses very intense energy sources not appropriate.
On the other hand, glomerular filtration occurs in the kidney and is carried out by the nephron, which is the functional unit of the kidney, within it there is a specific tubular system in collection, absorption and reabsorption, added to the presence of Bowman's capsule.
What evidence of climate change
Which image displays a chemical property about a substance? Choose all that apply
Answer:
Answer: II and IV
Explanation: Flammability and the ability to rust are chemical properties because they change an object. I, III, and V are physical properties because it doesn't change the object's composition. This includes weight, the change in matter (solid to liquid), or change in volume.
Hope this helps!!!
Explanation:
Answer:
Answer: II and IV
Explanation:
Explanation: Flammability and the ability to rust are chemical properties because they change an object. I, III, and V are physical properties because it doesn't change the object's composition. This includes weight, the change in matter (solid to liquid), or change in volume.
5. When ortho-bromonitrobenzene is treated with NaOH at elevated temperature, only one product is formed. (a) Draw the product. (b) Identify the intermediate formed en route to the product. (c) Would the reaction occur if the starting compound were meta-bromonitrobenzene
Answer:
The product formed is orthonitrophenol
Explanation:
The compound orthonitrophenol is formed when ortho-bromonitrobenzene is treated with NaOH at elevated temperature.
The reaction leads to the formation of an intermediate stabilized by resonance. This intermediate can not be formed by the meta isomer because a resonance stabilized intermediate can not be formed and the product is not stabilized by intramolecular hydrogen bonding hence this reaction will not occur.
Compare and contrast the characteristics of metals and nonmetals.
Let's find the temperature when the pressure is equal to zero. There are two ways of doing this, what are they? What is the temperature when the pressure equals zero? What is the significance of that number?
Answer:
The lower the temperature, the lower the pressure inside of the sphere. If the exact values were plotted out, a linear relationship would be apparent. Extrapolating this line to the point where there would be no pressure yields absolute zero, which is about -273.15 degrees Celsius.
What is the periodic table?
A. An arrangement of the known elements
B. A table of when elements were discovered
C. A list of major accomplishments in science
D. A timetable of advancements in chemistry
At 570. mmHg and 25 °C, a gas sample has a volume of 2270 mL. What is the final pressure (in mmHg) at a volume of 1250 mL and a temperature of 175 °C?
Answer:
The final pressure is 1556 mmHg
Explanation:
The gas laws are a set of chemical and physical laws that allow determining the behavior of gases in a closed system.
Boyle's law says that "The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure" and is expressed mathematically as: P * V = k
Charles's law states that the volume of gas at constant pressure is directly proportional to its temperature and is expressed mathematically as the quotient that exists between the volume and the temperature equal to a constant value:
[tex]\frac{V}{T}=k[/tex]
Gay - Lussac's law states that the pressure of gas at constant volume is directly proportional to its temperature and is expressed mathematically as the quotient between pressure and temperature equal to a constant:
[tex]\frac{P}{T}=k[/tex]
Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:
[tex]\frac{P*V}{T}=k[/tex]
When you want to study two different states, an initial one and a final one of a gas, it is possible to apply:
[tex]\frac{P1*V1}{T1}=\frac{P2*V2}{T2}[/tex]
In this case:
P1= 570 mmHgV1= 2270 mLT1= 25 C= 298 K (being 0 C= 273 K)P2= ?V2= 1250 mLT2= 175 C=448 KReplacing:
[tex]\frac{570 mmHg*2270 mL}{298 K}=\frac{P2*1250 mL}{448 K}[/tex]
Solving:
[tex]P2=\frac{448K}{1250 mL} *\frac{570 mmHg*2270 mL}{298 K}[/tex]
P2= 1556 mmHg
The final pressure is 1556 mmHg
Which of the following equations best represents methanol being dissolved in water
A. CH3OH(I) —> CH3+(aq) + OH-(aq)
B. CH3OH(I) —> CH3O-(aq) + H+(aq)
C. CH3OH(I) —> CH3OH(aq)
Answer: [tex]CH_3OH(l)\rightarrow CH_3OH(aq)[/tex]
Explanation:
According to the concept of “Like dissolves like”, the polar solutes dissolve in polar solvents, and non-polar solutes dissolve in non-polar solvents.
Covalent compounds which are formed by sharing of electrons between non metals, when dissolved in water, forms hydrogen bonding with water if they contain a electronegative atom along with hydrogen. Example: methanol [tex](CH_3OH)[/tex]
Ionic compounds which are made up of cations and anions, when dissolved in water, dissociate into ions. Example: [tex]NaCl[/tex]
Thus equation which best represents methanol being dissolved in water is:
[tex]CH_3OH(l)\rightarrow CH_3OH(aq)[/tex]
A nurse is preparing to administer 4300 units of Heparin which available in 2000 units/mL. How many mL should the nurse administer?
a. 12.9 mL
B. 1.29 mL
C. 2.15 mL
D. 16.0 mL
E. 3.00 mL
HELP ASAP
THANKS!
Taking into account the definition of units/mL, the correct option is option C. The nurse should administer 2.15 mL.
Heparin is an anticoagulant drug used in the treatment and prevention of blood clots caused by certain medical conditions or medical procedures. Heparin is also used before surgery to reduce the risk of blood clots. That is, this drug works by decreasing the blood's ability to clot.
The results of some medical tests are reported in units per milliliter (u/mL). This unit of concentration expresses unit of activity per unit of volume.
In this case, Heparin is available in 2,000 units/mL ands this means that for every 1 mL, there are Heparin 2,000 units.
Then you can apply the following rule of three: if 2,000 units are present for every 1 mL, 4,300 units are present in how many mL?
volume= (4,300 units× 1 mL) ÷ 2,000 unita
Solving:
volume= 2.15 mL
In summary, the correct option is option C. The nurse should administer 2.15 mL.
Learn more with this examples:
https://brainly.com/question/20366928?referrer=searchResultshttps://brainly.com/question/18030745?referrer=searchResultshttps://brainly.com/question/13956508?referrer=searchResultsDuring complete oxidation of the fatty acid CH3(CH2)14COOH, ________ molecules of acetyl-CoA are produced, and the fatty acid goes through the β-oxidation cycle ________ times
Answer:
During complete oxidation of the fatty acid CH3(CH2)14COOH, eight molecules of acetyl-CoA are produced, and the fatty acid goes through the β-oxidation cycle seven times.
Explanation:
In the β-oxidation of fatty acids, an acetyl-CoA molecule is removed from the fatty acid chain after every β-oxidation cycle that the fatty acid undergo, leaving behind a fatty acyl-CoA molecule shortened by two cabon atoms..
The removal of the acetyl-CoA molecule starts from the carboxyl end and shortens the fatty acid molecule by two carbon units. Successive β-oxidation cycles results in the complete oxidaton of the fatty acid molecle to acetyl -CoA molecules.
The compound CH3(CH2)14COOH, is a 16-carbon saturated fatty acid molecule known as palmitic acid.. It undergoes seven passes through the β-oxidation cycle to yield eight molecules of acetyl-CoA with each cycle yielding an acetyl-CoA molecule and a fatty acyl-CoA shortened by two carbon atoms. Finally, the seventh step yields two acetyl-CoA molecules.
During complete oxidation of CH3(CH2)14COOH, eight (8) molecules of acetyl-CoA are produced, and the fatty acid goes through the β-oxidation cycle seven (7) times.
Cellular respiration refers to a series of metabolic reactions by which aerobic cells use the energy stored in the chemical bonds of foods and oxygen to produce ATP and carbon dioxide.Cellular respiration has three stages: glycolysis, the Krebs cycle (also called TCA or tricarboxylic acid cycle) and oxidative phosphorylation.During the TCA cycle, a fatty acid containing a hydrocarbon tail of N atoms of carbons undergoes an amount of (N/2)−1 rounds of β-oxidation to be oxidized.Palmitic acid [chemical formula: CH3(CH2)14COOH] is a fatty acid with 16 carbon atoms in which 7 successive rounds of oxidation must take place to produce 8 acetyl-CoA molecules.In conclusion, during complete oxidation of CH3(CH2)14COOH, eight (8) molecules of acetyl-CoA are produced, and the fatty acid goes through the β-oxidation cycle seven (7) times.
Learn more in:
https://brainly.com/question/13254687
Diethyl malonate (the starting material for the malonic ester synthesis) reacts with bromine in acid-catalyzed conditions to form a product with molecular formula C7H11BrO4. Would you expect this product to be more or less acidic than diethyl malonate?
Answer:
The product would have more acidity than Diethyl malonate
Explanation:
For this question, first, we have to start with the structure of the bromination reaction. The bromination would add a "Br" atom in the middle carbon between the ester groups. Therefore, the molecule produced would be diethyl 2-bromomalonate and the formula of this compound fits with the reported by the question: [tex]C_7H_1_1BrO_4[/tex]
Now, if we have to analyze the acidity we have to check the most acidic hydrogen. In this case, is the "H" in the middle carbon (red hydrogen). In the Diethyl malonate, we have an inductive effect caused by the carbonyl groups on each side of the middle carbon. In the diethyl 2-bromomalonate, we have this same inductive effect plus the Br atom bonded to the same carbon. Therefore, would be easier to remove the hydrogen. So, diethyl 2-bromomalonate would ba more acidity than Diethyl malonate.
See figure 1
I hope it helps!
A chemist must prepare of aqueous copper(II) fluoride working solution. He'll do this by pouring out some aqueous copper(II) fluoride stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the copper(II) fluoride stock solution that the chemist should pour out.
Answer:
See answer below
Explanation:
First, you are not putting the whole data, however, I found an exercise very similar to this, so I'm gonna use this data, as an example, and you can use it as guide to solve yours. The exercise is the following:
A chemist must prepare 275. mL of 1967 uM aqueous copper(II) fluoride (Cur) working solution. He'll do this by pouring out some 2.63 mmol/L aqueous copper(II) fluoride stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the copper(II) fluoride stock solution that the chemist should pour out.
According to this, we want a more dilluted solution fo copper Fluoride solution. To do this, we need to know the moles that are required in the desired solution.
1967 uM in just mol/L is:
1967 uM * 1 M / 1x10⁶ uM = 1.967x10⁻³ M
Now that we have the concentration, we can calculate the moles required to prepare this solution:
moles = 1.967x10⁻³ mol/L * 0.275 L = 5.41x10⁻⁴ moles
These are the moles that we need to have to prepare this solution. Now, with the concentration of the stock solution, we just solve for the volume required:
V = moles / M
V = 5.41x10⁻⁴ / 2.63x10⁻³
V = 0.2057 L ----> 205.7 mL or 206 mL
To determine the concentration of SO4 2– ion in a sample of groundwater, 100.0 mL of the sample is titrated with 0.0250 M Ba(NO3)2, forming insoluble BaSO4. If 7.48 mL of the Ba(NO3)2 solution is required to reach the end point of the titration, what is the molarity of the SO4 2–?
Answer:
1.87x10⁻³ M SO₄²⁻
Explanation:
The reaction of SO₄²⁻ with Ba²⁺ (From Ba(NO₃)₂) is:
SO₄²⁻(aq) + Ba²⁺(aq) → BaSO₄(s)
Where 1 mole of SO₄²⁻ reacts per mole of Ba²⁺
To reach the end point in this titration, we need to add the same moles of Ba²⁺ that the moles that are of SO₄²⁻.
Thus, to find molarity of SO₄²⁻ we need to find first the moles of Ba²⁺ added (That will be the same of SO₄²⁻). And as the volume of the initial sample was 100mL we can find molarity (As ratio of moles of SO₄²⁻ per liter of solution).
Moles Ba²⁺:
7.48mL = 7.48x10⁻³L ₓ (0.0250moles / L) = 1.87x10⁻⁴ moles of Ba²⁺ = Moles of SO₄²⁻
Molarity SO₄²⁻:
As there are 1.87x10⁻⁴ moles of SO₄²⁻ in 100mL = 0.1L, molarity is:
1.87x10⁻⁴ moles of SO₄²⁻ / 0.1L =
1.87x10⁻³ M SO₄²⁻A conversion factor set up correctly to convert 15 inches to cm is _______.
A) 100 cm/1 m.
B) 1 inch/2.54 cm.
C) 1 cm/10 mm.
D) 2.54 cm/1 inch.
E) 10 cm/1 inch.
Answer:
e is the correct one , hope I helped u
which of the following best describes precision
Answer:
Good precision because he is hitting the same spot 3 times but we don't know if he is accurate. SO the answer is 2
What is an evaluation of work by qualified
people in a field before the work is published.
Answer:
Peer review is the evaluation of work by one or more people with similar competencies as the producers of the work (peers). It functions as a form of self-regulation by qualified members of a profession within the relevant field.
Hope it helped u if yes mark me BRAINLIEST pzllzllzl
Tysm
Determine which molecules are weak acids and weak bases, and place them in the appropriate category.
Answer:
[tex]CH_{3} COOH[/tex] is a weak acid with a strong conjugate base [tex](CH_{3} CO_{2} ^{-} )[/tex][tex]CH_{3} NH_{2}[/tex] is a weak base with a strong conjugate acid [tex](CHx_{3} NH_{2} ^{-} )[/tex]Explanation:
Weak acids do not completely dissociate in water to its distinctive ions, but instead forms conjugate bases; and ice versa with weak bases. The conjugate base has strong affinity for protons and vice versa.
I hope you found this explanation clear and easy to follow.
The SI unit of length equal to the distance light travels in a vacuum in 1/299 792 458 of a second is the ___.
Answer:
Meter.
Explanation:
Hello,
In this case, The SI unit of length equal to the distance light travels in a vacuum in 1/299 792 458 of a second is the meter as the physical standard used to establish such length.
Regards.
What a good example of hypothesis
Answer:
If you turn the lights on and off rapidly, then the bulb will burn out faster. It's some sort of prediction
Answer:
1. If I replace the battery in my car, then my car will get better gas mileage.
2. If I eat more vegetables, then I will lose weight faster.
3. If I add fertilizer to my garden, then my plants will grow faster.
4. If I brush my teeth every day, then I will not develop cavities.
5. If I take my vitamins every day, then I will not feel tired.
6. If 50 mL of water are added to my plants each day and they grow, then adding 100 mL of water each day will make them grow even more.
Explanation:
Place the following elements in order of increasing electronegativity.K Cs PA. K < P < CsB. P < Cs < KC. Cs < K < PD. P < K < CsE. Cs < P < K
Answer:
C. Cs < K < P
Explanation:
Electronegativity is the basically the tendency of an atom to attract electrons. The pauling scale is used to quantify electronegativity, the most electronegative element; fluorine has a value of 4.0 and francium, the least electronegative element has a value of 0.7
The electronegative values of the following elements are given as;
K = 0.82
Cs =0.79
P = 2.19
Arranging in order of increasing electronegativity, we have;
Cs < K < P. The correct option is;
C. Cs < K < P
3) Report how many significant figures each of the following numbers has and then write the number in
standard scientific notation.
Number
Number of Significant Figures
Standard Scientific Notation
0.0000620
0.05600
70820.0
309100
Answer:
Number of Significant Figures
0.0000620 = 6
0.05600 = 3
70820.0 = 5
309100 = 6
Standard Scientific Notation
0.0000620 = 6.2 * [tex]10^{-5}[/tex]
0.05600 = 5.6 * [tex]10^{-2}[/tex]
70820.0 = 7.082 * [tex]10^{4}[/tex]
309100 = 3.091 * [tex]10^{5}[/tex]
any help is appreciated
Answer:
1.63×10¹⁰ L.
Explanation:
We'll begin by calculating the number of mole in 125 g of silver (ii) oxide, AgO. This can be obtained as follow:
Mass of AgO = 125 g
Molar mass of AgO = 108 + 16 = 124 g/mol.
Mole of AgO =?
Mole = mass /Molar mass
Mole of AgO = 125 /124
Mole of AgO = 1.01 moles.
Next, we shall convert 6.19×10¯⁵ μmol/L to mol/L. This can be obtained as follow:
1 μmol/L = 1×10¯⁶ mol/L
Therefore,
6.19×10¯⁵ μmol/L = 6.19×10¯⁵ × 1×10¯⁶ = 6.19×10¯¹¹ mol/L
Finally, we shall determine the volume as follow:
Molarity = 6.19×10¯¹¹ mol/L
Mole of AgO = 1.01 moles
Volume =?
Molarity = mole /Volume
6.19×10¯¹¹ = 1.01/Volume
Cross multiply
6.19×10¯¹¹ × volume = 1.01
Divide both side by 6.19×10¯¹¹
Volume = 1.01/6.19×10¯¹¹
Volume = 1.63×10¹⁰ L
Therefore, the volume of the solution is 1.63×10¹⁰ L
Add coefficients to the reaction summary to show the net results of glycolysis. glucose+a ADP+b Pi+c NAD+⟶x pyruvate+y ATP+z NADH You do not need to add the water and hydrogen ions necessary to balance the overall reaction.
Then, Draw the structure of pyruvate at pH 7.4.
Answer:
See figure 1
Explanation:
For this question, we can start with the structure of pyruvic acid. In this molecule, we have two functional groups, the ketone group, and a carboxylic acid group.
In the acid group, we have an acidic hydrogen. That is, this hydrogen can leave the molecule to produce a hydronium ion ([tex]H^+[/tex]).
Now, to know what is the pH at which this hydrogen leaves the molecule we must look for the pKa value. Which for the case of this molecule is 2.45
If there is a pH value greater than 2.45, the molecule will lose hydrogen. In this case, we will have a value above 2.45 (7.4), which is why the conjugated acid of pyruvic acid will be produced, which is pyruvate.
Therefore, in the structure, we will have a negative charge on the acid group.
See figure 1
I hope it helps!
Which state in each of the following pairs has the higher entropy per mole of substance?
1. Ice at - 40 degrees C or ice at 0 degrees C.
2. N2 at STP or N2 at 0 degrees C and 10 atm.
3. N2 at STP or N2 at 0 degrees C in a volume of 50 L.
4. Water vapor at 150 degrees C and 1 atm or water vapor at 100 degrees C and 2 atm.
Answer:
1. Ice at 0 degrees C.
2. N₂ at STP.
3. N₂ at STP.
4. Water vapor at 150 degrees C and 1 atm.
Explanation:
First, we need to remember that entropy (S) is a measure of how spread out or dispersed the energy of a system is among the different possible ways that system can contain energy. The greater the dispersal, the greater is the entropy.
When the temperature is increased, the energies associated with all types of molecular motion increase. Consequently, the entropy of a system always increases with increasing temperature.
With this in mind, we consider the pairs:
1. Since the ice at 0ºC has a greater temperature than the ice at -40 ºC, the first has the higher entropy.
2. The N₂ at STP (that is, 1 atm and 25 ºC) has higher entropy than N₂ at 0ºC and 10 atm because it has a higher temperature and less pressure, which allows a greater dispersal of energy by the molecules of the gas.
3. The N₂ at STP has a higher entropy since it has a higher temperature than N₂ at 0ºC, even though it the first has a lower volume (24,4 L vs. 50 L).
4. The water vapor at 150 ºC and 1 atm have a higher temperature and a lower pressure. This means that its molecules will have an increased molecular motion than the molecules of water vapor at a lower temperature and higher pressure. Therefore, the first has the highest entropy.
Imagine that you are in the laboratory and your classmate gets a chemical
in their eyes. What would you do?
A ballon at 2.7atm has a volume of 1.6L.What will be the volume if the pressure is reduced to 1,3atm?
Answer:
3.3 L
Explanation:
Step 1: Given data
Initial pressure (P₁): 2.7 atmInitial volume (V₁): 1.6 LFinal pressure (P₂): 1.3 atmFinal volume (V₂): ?Step 2: Calculate the final volume of the balloon
Inside the balloon we have gas. If we consider it behaves as an ideal gas, we can calculate the final volume using Boyle's law.
P₁ × V₁ = P₂ × V₂
V₂ = P₁ × V₁ / P₂
V₂ = 2.7 atm × 1.6 L / 1.3 atm
V₂ = 3.3 L
Carboxypeptidases can be used to determine the entire sequence of short peptides (<50 amino acid residues) and it starts by reacting with the C-terminal amino acid.
a. True
b. False
Answer:
A. True
Explanation:
Carboxypeptidases are enzymes which function in the digestion of short peptides known as oligopeptides in the small intestine. Oligopeptides contain between 10 to 50 amino acid residues.
The two carboxypeptidases A and B involved in the digestion of proteins in the small intestine are secreted by the exocrine glands of the pancreas.They are both zinc-containing enzymes which remove successive carboxyl-terminal (C-terminal) residues from oligopeptides until free amino acids are obtained.
Since they function in this way, they can be used to determine the entire sequence of short peptides or oligopeptides.
what's the amount of solute in 1.75 L of 0.25 M HCl?
Answer: 0.4375 mols of solute
Explanation:
The problem is asking for the amount of solute. We are given the value of molarity. The molarity is 0.25M. We know that molarity is [tex]M=\frac{mols of solute}{liters of solution}[/tex]. Since we are given the liters of solution is 1.75, we can use those values to solve for mols of solute.
[tex]0.25M=\frac{x}{1.75L}[/tex] [multiply both sides by 1.75 L]
[tex]x=0.4375 mols[/tex]
There are 0.4375 mols of solute.
A sample of ozone gas occupies 225 mL at 1.00 atm and 0 °C. If the volume of the gas is 625 mL at 25 °C, what is the pressure?
Answer:
[tex]P_2=0.393atm[/tex]
Explanation:
Hello,
In this case, we can use the combined ideal gas law in order to analyze its behavior as a function of changing temperature, volume and pressure:
[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]
Thus, since we know the volume, temperature and pressure at the initial condition, we can compute the final pressure as shown below:
[tex]P_2=\frac{P_1V_1T_2}{T_1V_2} =\frac{1.00atm*225mL*(25+273)K}{(0+273)K*625mL}\\ \\P_2=0.393atm[/tex]
Regards.
how many mole of iron will be produced from 6.20 mole of carbon monboxide reacting with excess iron oxide
Answer:
6.20 mol
Explanation:
Step 1: Write the balanced reaction
FeO + CO → Fe + CO₂
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of carbon monoxide (CO) to iron (Fe) is 1:1.
Step 3: Calculate the moles of Fe produced from 6.20 moles of CO
6.20 mol CO × (1 mol Fe/1 mol CO) = 6.20 mol Fe