evaluate ∫413x 5x√ dx. enter your answer as an exact fraction if necessary.
∫^16_9 (-x^1/2-5)dx
provide your answer below:

Answers

Answer 1

The value of the second integral is -109/3.

For the first integral, we can use the power rule and the constant multiple rule of integration:

∫413x 5x√ dx = [tex]4/3 \times 13x^{3/2 }\times 2/3 \times 5x3/2+1/2 + C[/tex]

= 40[tex]x^{5/2[/tex] / 15 + C

= 8[tex]x^{5/2[/tex] / 3 + C

where C is the constant of integration.

For the second integral, we can use the power rule and the constant multiple rule of integration:

∫[tex]^{16}_9 (-x^1/2-5)dx = (-2/3 \times x^(3/2) - 5x)^{16_9}[/tex]

= [tex](-2/3 \times 16^{(3/2)} - 5 \times 16) - (-2/3 \times 9^{(3/2)} - 5 \times 9)[/tex]

= (-2/3 × 64 - 80) - (-2/3 × 27 - 45)

= (-128/3 - 80) - (-54/3 - 45)

= -208/3 + 99/3

= -109/3

Therefore, the value of the second integral is -109/3.

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Answer 2

To evaluate ∫413x 5x√ dx, we can use integration by substitution. Let u = 5x√, then du/dx = 5/2x^1/2 and dx = 2/5u^2/5 du.

Substituting these into the integral, we get:

∫413x 5x√ dx = ∫4u u(2/5u^2/5) du

Simplifying:

∫413x 5x√ dx = 8/5 ∫u^7/5 du

Integrating:

∫413x 5x√ dx = 8/5 * (5/12)u^(12/5) + C

Substituting back in for u:

∫413x 5x√ dx = 2/3 x^(3/2) * (5x√)^(2/5) + C

Simplifying:

∫413x 5x√ dx = 2/3 x^(3/2) * (5x)^(2/5) + C

Now, to evaluate ∫^16_9 (-x^1/2-5)dx, we can use the power rule of integration:

∫^16_9 (-x^1/2-5)dx = [-2/3x^(3/2) - 5x] from 9 to 16

Substituting in the limits:

∫^16_9 (-x^1/2-5)dx = [-2/3(16)^(3/2) - 5(16)] - [-2/3(9)^(3/2) - 5(9)]

Simplifying:

∫^16_9 (-x^1/2-5)dx = [(-32/3) - 80] - [(-18/3) - 45]

∫^16_9 (-x^1/2-5)dx = -112/3

Therefore, the answer to the second integral is -112/3.
To evaluate the given integral ∫^16_9 (-x^(1/2) - 5) dx, we'll find the antiderivative of the function and then apply the Fundamental Theorem of Calculus.

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

Answer:

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