Answer:
1.25cm
Explanation:
Using
Minimum, as dsinစ = (m+1/2) lambda
Third dark fringe m= 2
dsinစ = (2+1/2)lambda
d(y/L)= (5/2) lambda
Y= 5/2* lambda *L/d
So substituting
=[ (500E-9m)(5m)/0.5E-3] 5/2
=0.0125m
= 1.25cm
Explanation:
A particle has velocity v⃗1 v → 1 as it accelerates from 1 to 2. What is its velocity vector v⃗2 v → 2 as it moves away from point 2 on its way to point 3?
Answer:
The velocity of the particle will be downward.
Explanation:
Given that,
The velocity of a particle is v₁. It is accelerated from 1 to 2.
If it moves away from point 2 on its way then
We need to find the velocity of particle
According to figure,
A particle moves downward from 1 to 2 with the velocity v₁ and after that the particle moves downward from 2 to 3 with the velocity v₂.
Hence, The velocity of the particle will be downward.
A 22-g bullet traveling 240 m/s penetrates a 2.0-kg block of wood and emerges going 150 m/s. If the block is stationary on a frictionless surface when hit, how fast does it move after the bullet emerges?
Answer:
After the bullet emerges the block moves at 0.99 m/s
Explanation:
Given;
mass of bullet, m₁ = 22 g = 0.022 kg
initial speed of the bullet, u₁ = 240 m/s
final speed of the bullet, v₁ = 150 m/s
mass of block, m₂ = 2.0 kg
initial speed of the block, u₂ = 0
Let the final speed of the block = v₂
Apply principles of conservation of linear momentum;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
0.022 x 240 + 2 x 0 = 0.022 x 150 + 2v₂
5.28 = 3.3 + 2v₂
5.28 - 3.3 = 2v₂
1.98 = 2v₂
v₂ = 1.98 / 2
v₂ = 0.99 m/s
Therefore, after the bullet emerges the block moves at 0.99 m/s
The body moves at a speed of 2.61m/s after the bullet emerges.
According to the law of collision which states that the momentum of the body before the collision is equal to the momentum of the body after the collision.
The formula for calculating the collision of a body is expressed as:
p = mv
m is the mass of the body
v is the velocity of the body
Based on the law above;
[tex]m_1u_1+m_2u_2=(m_1+m_2)v[/tex]
v is the final velocity of the body after the collision
Substitute the given parameters into the formula as shown:
[tex]0.022(240) + 2(0) = (0.022+2)v\\ 5.28 = 2.022v\\v=\frac{5.28}{2.022}\\v= 2.611m/s[/tex]
This shows that the body moves at a speed of 2.61m/s after the bullet emerges.
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If Matthew was traveling into space from Earth, which of these would he be able to reach first? A) Sun B) Venus C) Alpha centauri D) not enough information given
C.) Alpha Centauri
Explanation:
Due to it being the closest planetary system to earth.
About 4.367 light years away.
Answer: not enough information given
Explanation:
Replacing an object attached to a spring with an object having 14 the original mass will change the frequency of oscillation of the system by a factor of
Answer:
The frequency changes by a factor of 0.27.
Explanation:
The frequency of an object with mass m attached to a spring is given as
[tex]f[/tex] = [tex]\frac{1}{2\pi } \sqrt{\frac{k}{m} }[/tex]
where [tex]f[/tex] is the frequency
k is the spring constant of the spring
m is the mass of the substance on the spring.
If the mass of the system is increased by 14 means the new frequency becomes
[tex]f_{n}[/tex] = [tex]\frac{1}{2\pi } \sqrt{\frac{k}{14m} }[/tex]
simplifying, we have
[tex]f_{n}[/tex] = [tex]\frac{1}{2\pi \sqrt{14} } \sqrt{\frac{k}{m} }[/tex]
[tex]f_{n}[/tex] = [tex]\frac{1}{3.742*2\pi } \sqrt{\frac{k}{m} }[/tex]
if we divide this final frequency by the original frequency, we'll have
==> [tex]\frac{1}{3.742*2\pi } \sqrt{\frac{k}{m} }[/tex] ÷ [tex]\frac{1}{2\pi } \sqrt{\frac{k}{m} }[/tex]
==> [tex]\frac{1}{3.742*2\pi } \sqrt{\frac{k}{m} }[/tex] x [tex]2\pi \sqrt{\frac{m}{k} }[/tex]
==> 1/3.742 = 0.27
1. The most likely injuries in an Anatomy class are (circle all that apply)
a. chemical spill
b. cut from scalpel
c, burn from
open
flame
d. foreign object or splash in eye
e, animal bite
A sealed tank containing seawater to a height of 10.5 mm also contains air above the water at a gauge pressure of 2.95 atmatm. Water flows out from the bottom through a small hole. How fast is this water moving?
Answer:
The water is flowing at the rate of 28.04 m/s.
Explanation:
Given;
Height of sea water, z₁ = 10.5 m
gauge pressure, [tex]P_{gauge \ pressure}[/tex] = 2.95 atm
Atmospheric pressure, [tex]P_{atm}[/tex] = 101325 Pa
To determine the speed of the water, apply Bernoulli's equation;
[tex]P_1 + \rho gz_1 + \frac{1}{2}\rho v_1^2 = P_2 + \rho gz_2 + \frac{1}{2}\rho v_2^2[/tex]
where;
P₁ = [tex]P_{gauge \ pressure} + P_{atm \ pressure}[/tex]
P₂ = [tex]P_{atm}[/tex]
v₁ = 0
z₂ = 0
Substitute in these values and the Bernoulli's equation will reduce to;
[tex]P_1 + \rho gz_1 + \frac{1}{2}\rho v_1^2 = P_2 + \rho gz_2 + \frac{1}{2}\rho v_2^2\\\\P_1 + \rho gz_1 + \frac{1}{2}\rho (0)^2 = P_2 + \rho g(0) + \frac{1}{2}\rho v_2^2\\\\P_1 + \rho gz_1 = P_2 + \frac{1}{2}\rho v_2^2\\\\P_{gauge} + P_{atm} + \rho gz_1 = P_{atm} + \frac{1}{2}\rho v_2^2\\\\P_{gauge} + \rho gz_1 = \frac{1}{2}\rho v_2^2\\\\v_2^2 = \frac{2(P_{gauge} + \rho gz_1)}{\rho} \\\\v_2 = \sqrt{ \frac{2(P_{gauge} + \rho gz_1)}{\rho} }[/tex]
where;
[tex]\rho[/tex] is the density of seawater = 1030 kg/m³
[tex]v_2 = \sqrt{ \frac{2(2.95*101325 \ + \ 1030*9.8*10.5 )}{1030} }\\\\v_2 = 28.04 \ m/s[/tex]
Therefore, the water is flowing at the rate of 28.04 m/s.
Answer:
C. effusion because there is a movement of a gas through a small opening into a larger volume
Explanation:
Edge2020
Have a great day y'all :)
Find the sum of 46 and -46
Answer:
0
Explanation:
Explain Cheetah how force, velocity, and acceleration are related.
Explanation:
A cheetahs force, velocity, and acceleration are related because velocity goes by seconds/mile per hour, force goes by strength and energy, and acceleration goes by how the velocity changes the speed.
The greatest speed recorded by a baseball thrown by a pitcher was 162.3 km / h, obtained by Nolan Ryan in 1974. If the ball leaves the pitcher's hand with a horizontal speed of this magnitude, how much will the ball have fallen? by the time you have traveled 20 m horizontally?
Answer:
0.96 m
Explanation:
First, convert km/h to m/s.
162.3 km/h × (1000 m/km) × (1 hr / 3600 s) = 45.08 m/s
Now find the time it takes to move 20 m horizontally.
Δx = v₀ t + ½ at²
20 m = (45.08 m/s) t + ½ (0 m/s²) t²
t = 0.4436 s
Finally, find how far the ball falls in that time.
Δy = v₀ t + ½ at²
Δy = (0 m/s) (0.4436 s) + ½ (-9.8 m/s²) (0.4436 s)²
Δy = -0.96 m
The ball will have fallen 0.96 meters.
A hydraulic press has one piston of diameter 4.0 cm and the other piston of diameter 8.0 cm. What force must be applied to the smaller piston to obtain a force of 1600 N at the larger piston
Answer:
400 N
Explanation:
Pressure is equal on both pistons.
P = P
F / A = F / A
F / (πd²/4) = F / (πd²/4)
F / d² = F / d²
1600 N / (8.0 cm)² = F / (4.0 cm)²
F = 400 N
The force that should be applied to the smaller piston is 400 N.
Given that,
A hydraulic press has one piston of diameter 4.0 cm and the other piston of diameter 8.0 cm. Pressure is equal on both pistons.Based on the above information, the calculation is as follows:
[tex]1600 N \div (8.0 cm)^2 = F \div (4.0 cm)^2[/tex]
F = 400 N
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J. Henry Alston was the first African American to publish his research findings on the perception of heat and cold in a major US psychology journal. Please select the best answer from the choices provided T F
Answer:
True
Explanation:
J. Henry Alston was known as a famous African American psychologist. He was known through his thorough study of the sensations of heat and cold.
He thereby became the first African American to publish his research findings on the perception of heat and cold in a major US psychology journal and was an important figure in the field.
Narrow, bright fringes are observed on a screen behind a diffraction grating. The entire experiment is then immersed in water. Do the fringes on the screen get closer together, get farther apart, remain the same, or disappear? Explain.
Answer:
n (a sin θ) = m λ₀
n> 1, therefore the fringes move away from each other
Explanation:
The diffraction experiment the constructive interference fringes is described by
a sin θ = m λ₀
in this equation it is assumed that the experiment emptied the air n = 1
When the same experiment is performed in water, the wavelength changes
λₙ = λ₀ / n
execution for constructive interference
a sin θ = m λₙ
we substitute
a sin θ = m λ / n
n (a sin θ) = m λ₀
the refractive index of water is n = 1.33, so for the same wavelength the separation of the spectrum is multiplied by n> 1, therefore the fringes move away from each other
When an external magnetic field is applied, what happens to the protons in a sample?
A) All protons align with the field.
B) All protons align opposite to the field.
C) Some protons align with the field and some align opposite to it.
D) All protons assume a random orientation.
Answer:
Some protons align with the field and some align opposite to it.
Explanation:
Majority align to the field because these protons tend to act like small magnets under the effect of this external field
On account of external magnetic field, the protons will align with the magnetic field. Hence, option (a) is correct.
The given problem is based on the concept of magnetic field. The region where the magnetic force is experienced is known as magnetic field. Generally, the protons are the charged entities carrying the positive polarity and are one of the major constituents of modern atomic structure.
The origin of magnetic field occurs due to charged particles present in a specific space. And the magnetic field is due to the flowing of liquid metal in the outer core of the planet generates electric currents.In the condition when an external field is applied, the majority of protons align to the field because these protons tend to act like small magnets under the effect of this external field.Thus, we can conclude that on account of external magnetic field, the protons will align with the field.
Learn more about the magnetic field here:
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Water enters a student's house 10.0 m above the ground through a pipe with a cross section area of 1.00 x 10-4m2 at ground. Inside the house the pipe's cross section area is 0.50 x 10-4m2. The student in the house want to know the water pressure inside the pipe at the ground level. He first measured the volume of the bath tank that equals to 45.0 L. Then he fill the tank (the tank is 10 meters above the ground) inside the house with 90.0 seconds. The pipe inside the house is open with the sea level pressure The density of water is 1000 kgm3.
(a) Calculate the water speed at the ground pipe with larger cross section area and the water speed inside the house with smaller cross section area.
(b) Calculate the water pressure in the pipeline at the ground level.
Answer:
(a). V₁ = 10m/s (velocity inside the house), V₂ = 5m/s (velocity at ground level)
(b). P₂ = 236500 Pa
Explanation:
This is quite straight-forward so let us begin by defining the terms given.
Given that;
The cross-section area inside the student's house A₁ = 0.50 0.50 x 10-4m2.
Let us make the velocity of water inside the house be V₁
such that the Volume of water entering the per second is = A₁V₁
Therefore, in 90sec:
45 L = 90 A₁V₁
V₁ = 45 * 10⁻³m³ / 90*0.5*10⁻⁴
V₁ = 10m/s (velocity of water inside the house)
From the continuity equation we have that;
A₁V₁ = A₂V₂
0.5*10⁻⁴ * 10 = 1*10⁻⁴ V₂
V₂ = 5m/s (velocity at ground level)
(b). We are told to calculate the water pressure in the pipeline at the ground level.
Using Bernoulli's equation;
P₁ + pgh₁ + 1/2PV₁² (inside) = P₂ + pgh₂ + 1/2PV₂² (ground level)
1.01*10⁵ + 1000*9.8*10 + 1/2*1000*(10)² = P₂ + 0 + 1/2*1000*(5)²
P₂ (pressure) = 1.01*10⁵Pa
Therefore we have;
101000 + 98000 + 50000 = P₂ + 12500
P₂ = 236500 Pa
cheers I hope this helped !!
A race car is on a track has a velocity of 200 m/s. 15 seconds later the driver notices that he is going 350 m/s. What is his acceleration?
Answer:
initial velocity (u) = 200m/s
final velocity (v) = 350 m/s
time (t) = 15s
acceleration (a) = ?
NOW,
a=v-u/t
a= 350-200/15
a= 50/15
a= 3.3333
Explanation:
it's too easy just u need to understand the question . and go according to it's content .
main thing to memorize is it's simple formula.
I HAVE SOLVE THIS QNA. IN VERY
SIMPLE AND UNDERSTANDABLE FORM.
I høpë u hađ uņdērstøöď ťhìs şølutîóñ
:verý ×wəłł.
What properties do you think a spoon must have for it to be
useful as an eating tool? What additional properties must an edible spoon
have?
Answer:
eating instrument must be: HARDNESS, INERT, NOT TOXIC
eating tools: digested by the body
Explanation:
An eating instrument must be able to contain food, so it must have a good HARDNESS, besides it must be poorly absorbent of heat and the most important must be INERT, not react with food or be NOT TOXIC to humans.
Additionally, for a spoon to be edible, it must be able to be digested by the body, in general they are made with a starch base, so that the non-digestible parts of it have not been toxic to the body and can be eliminated from it.
There are numerous features of a spoon but these properties must an edible spoon
have
A spoon must be Sizable in nature to be use on the mouthA spoon must not contain an fatal substance as it will be used for eating A spoon Strong and not weather under pressure of heat A spoon should be Durable to stand the test of timeFor more information on this visit
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Statement I: At the same temperature lighter gas molecules have a higher average velocity than heavier gas molecules.
Statement II: At the same temperature lighter gas molecules have a higher average kinetic energy than heavier gas molecules.
a) Statement 1 and statement 2 are correct and statement 2 is the correct explanation of statement 1
b) Both the statement 1 and statement 2 are correct and statement 2 is not the correct explanation of statement 1
c) Statement 1 is correct but statement 2 is not correct
d) Statement 1 is not correct but statement 2 is correct
e) Both the statement 1 and statement 2 is not correct
Answer:
Statement 1 and statement 2 are correct and statement 2 is the correct explanation of statement 1
Explanation:
Both the velocity and kinetic energy of a gas molecule depends on its relative molecular mass according to Graham's law of diffusion in gases. Hence, the greater the relative molecular mass of the gas, the lesser its average velocity and kinetic energy.
Hence we can see that statement 2 vividly explains the postulation of statement 1 and makes the points more easily comprehensible.
An oil layer that is 5.0 cm thick is spread smoothly and evenly over the surface of water on a windless day. What is the angle of refraction in the wa
Answer:
32.1
Explanation:
NOTE: You did not state the angle of incidence, and thus, I will be using 45° as my angle of incidence, all you need to do is replace it with your own value if it's different.
To solve this question, we are going to be using Snell's Law.
Snell's law describes the relationship between the angles of incidence and refraction, when referring to light or other waves passing through a boundary between two different isotropic media, such as water, glass, or air.
Snell's law is mathematically given as
sin(A1)/sin(A2) = n2/n1, where
n1 = incidence index
n2 = refracted index
A1 = incidence angle
A2 = refracted angle
The refraction index of oil is 1.15, and that of water is 1.33, so
if we take oil first,
sin A2 = (n1.sinA1)/n2
sin A2 = (1 * sin 45)/1.15
sin A2 = 0.7071/1.15
sin A2 = 0.6149
A2 = sin^-1 0.6149
A2 = 37.9°
Then
sin A3 = (1.15 * sin 37.9) / 1.33
sin A3 = (0.6149 * 1.15) / 1.33
sin A3 = 0.7071 / 1.33
sin A3 = 0.5317
A3 = sin^-1 0.5317
A3 = 32.1
What type of information is available to scientists through a Global Positioning System (GPS) device?
Answer:
GPS receivers provide location in latitude, longitude, and altitude. They also provide the accurate time. GPS includes 24 satellites that circle Earth in precise orbits.
A 68.5 kg astronaut is doing a repair in space on the orbiting space station. He throws a 2.25 kg tool with a speed of 3.20 m / s relative to the space station. With what speed and direction will the astronaut begin to move?
Explanation:
Momentum is conserved.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Initially, both the astronaut and the tool are at rest, so u₁ = u₂ = 0 m/s.
After throwing the tool, the tool has a velocity of v₂ = 3.20 m/s.
(68.5 kg) (0 m/s) + (2.25 kg) (0 m/s) = (68.5 kg) v + (2.25 kg) (3.20 m/s)
0 = (68.5 kg) v + 7.2 kg m/s
v = -0.105 m/s
The astronaut moves at a speed of 0.105 m/s in the opposite direction.
The speed and the direction of the astronaut is 0.105 m/s in opposite direction to the motion of the tool.
Note: The momentum of the astronaut is equal and opposite to the momentum of the tool
To calculate the speed and the direction of the astronaut, we use the formula below.
Formula:
MV = -mv.............. Equation 1Where:
M = mass of the astronautV = speed of the astronautm = mass of the toolv = speed of the tool.make V the subject of the equation
V = mv/M................. Equation 2From the question,
Given:
m = 2.25 kgM = 68.5 kgv = 3.2 m/sSubstitute these values into equation 2
V = (2.25×3.2)/68.5V = 0.105 m/s in opposite direction to the speed of the tool.Hence, The speed and the direction of the astronaut is 0.105 m/s in opposite direction to the motion of the tool.
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What are the density, specific gravity and mass of the air in a room whose dimensions are 4 m * 6 m * 8 m at 100 kPa and 25 C.
Answer:
Density = 1.1839 kg/m³
Mass = 227.3088 kg
Specific Gravity = 0.00118746 kg/m³
Explanation:
Room dimensions are 4 m, 6 m & 8 m. Thus, volume = 4 × 6 × 8 = 192 m³
Now, from tables, density of air at 25°C is 1.1839 kg/m³
Now formula for density is;
ρ = mass(m)/volume(v)
Plugging in the relevant values to give;
1.1839 = m/192
m = 227.3088 kg
Formula for specific gravity of air is;
S.G_air = density of air/density of water
From tables, density of water at 25°C is 997 kg/m³
S.G_air = 1.1839/997 = 0.00118746 kg/m³
Zoning laws establish _______. a. what types of buildings can be built in an area b. the uses an area of land can be put to c. who can live in an area d. the types of business that can occupy a building Please select the best answer from the choices provided A B C D
Answer:
its B
Explanation:
Answer:
It's B
Explanation: hope it helps ^w^
What is the mass of a rock lifted 2 meters off the ground that has 196 J of potential energy?
Answer:
10kg
Explanation:
Let PE=potential energy
PE=196J
g(gravitational force)=9.8m/s^2
h(change in height)=2m
m=?
PE=m*g*(change in h)
196=m*9.8*2
m=10kg
Trial 1: Get a textbook and put a sheet of paper on top of it. Fold the paper as needed to keep the paper from sticking over the edge of the book.Hold the textbook with the paper on top, horizontally about waist high.Drop the book and paper so that they hit the floor flat. Record your observations.Trial 2: With the book in one hand and the paper in the other, drop the book and paper simultaneously from the same height. Record your observations.
Answer:
1) the two objects reach the floor at the same time.
2)the book reaches the floor much earlier than the foil
In conclusion, the difference in motion between the two systems subjected to the same acceleration depends on the weight of the body and friction force, when the body has less weight, the friction of the air affects it more
Explanation:
This interesting experiment has the following results
1) first case. Sheet on top of book
In this case the two objects reach the floor at the same time.
This shows that the acceleration in the two objects is the same and we call it the acceleration of gravity.
The speed of the body increases as it goes down linearly.
This occurs because the book that receives air resistance is much heavier, so the resistance has almost no effect on its movement, the sheet does not have the air resistance because it goes down next to the book.
2) second case. Book and sheet next to each other.
In this case the book reaches the floor much earlier than the foil.
This is because the resisting force of the air has almost no effect on the book and its movement is little affected by this force.
In the case of the blade, it has very little weight, therefore as its speed increases, the resistance force of the air rapidly equals the weight of the blade.
W_sheet - fr = 0
so after this, since the acceleration is zero, it goes down at constant speed, this speed is called the terminal velocity.
In conclusion, the difference in motion between the two systems subjected to the same acceleration depends on the weight of the body and friction force, when the body has less weight, the friction of the air affects it more.
Select the correct answer from each drop-down menu.
What forms of energy are involved when snow on a mountain breaks loose, resulting in an avalanche?
During an avalanche, the
energy of the snow on the mountain is converted into
energy as the snow cascades down.
Answer:
Gravitational potential energy is converted into kinetic energy
Explanation:
During an avalanche, the gravitational potential
energy of the snow on the mountain is converted into
kinetic energy as the snow cascades down.
The potential energy stored by the snow collected high in the mountain under the gravitational field created by our Earth, breaks loose and as it comes down acquiring velocity, it is converted into kinetic energy due to its accelerated motion
Light from a helium-neon laser (λ = 633 nm) is used to illuminate two narrow slits. The interference pattern is observed on a screen 2.5 m behind the slits. Eleven bright fringes are seen, spanning a distance of 54 mm. What is the spacing (in mm) between the slits?
Answer:
The value is [tex]d = 0.000293 \ m[/tex]
Explanation:
From the question we are told that
The wavelength is [tex]\lambda = 633 \ nm = 633 *10^{-9} \ m[/tex]
The distance of the screen is [tex]D = 2.5 \ m[/tex]
The order of the bright fringes is [tex]n = 10[/tex] (10 fringe + central maximum = eleven bright fringes )
The distance between the fringe is [tex]y = 54 \ mm = 0.054 \ m[/tex]
Generally the condition for constructive interference is
[tex]d sin \theta = n * \lambda[/tex]
=> [tex]d = \frac{n * \lambda}{sin \theta}[/tex]
Now from the SOHCAHTOA rule the angle [tex]sin \theta[/tex] is mathematically represented as
[tex]sin (\theta) = \frac{y}{D}[/tex]
So
[tex]d = \frac{n * \lambda}{\frac{y}{D} }[/tex]
=> [tex]d = \frac{10 * 633 *10^{-9}}{\frac{0.054}{ 2.5} }[/tex]
=> [tex]d = 0.000293 \ m[/tex]
In the previous part, you determined the maximum angle that still allows the crate to remain at rest. If the coefficient of friction is less than 0.7, what happens to this angle? A. The maximum angle increases.B. The maximum angle decreases.C. The maximum angle remains the same.D. Simulation q not sure if needed.
Answer:
B. The maximum angle decreases
Explanation:
If θ be the maximum angle of a slope that allows a crate placed on it to remain at rest , following condition exists .
tanθ = μ , θ is called angle of repose . μ is coefficient of static friction .
So the tan of angle of repose θ is proportional to coefficient of static friction.
If coefficient of static friction is less than .7 , naturally angle of repose will also become less ,ie, it at lower angle of inclination , the object will start slipping .
What is the direction of the magnetic force on the current in each of the six cases?
Answer:
is the equation for magnetic force on a length l of wire carrying a current I in a uniform magnetic field B, as shown in Figure 2. If we divide both sides of this expression by l, we find that the magnetic force per unit length of wire in a uniform field is F l=IBsinθ.
Explanation:
Consider the following:
a) radio waves emitted by a weather radar system to detect raindrops and ice crystals in the atmosphere to study weather patterns;
b) microwaves used in communication satellite transmissions;
c) infrared waves that are perceived as heat when you turn on a burner on an electric stove;
d) the multicolor light in a rainbow;
e) the ultraviolet solar radiation that reaches the surface of the earth and causes unprotected skin to burn; and
f) X rays used in medicine for diagnostic imaging.
Answer:
They have different wavelengths.
They have different frequencies.
They propagate at different speeds through non-vacuum media depending on both their frequency and the material in which they travel.
Explanation:
The complete question is
Consider the following:
a) radio waves emitted by a weather radar system to detect raindrops and ice crystals in the atmosphere to study weather patterns;
b) microwaves used in communication satellite transmissions;
c) infrared waves that are perceived as heat when you turn on a burner on an electric stove;
d) the multicolor light in a rainbow;
e) the ultraviolet solar radiation that reaches the surface of the earth and causes unprotected skin to burn; and
f) X rays used in medicine for diagnostic imaging.
Which of the following statements correctly describe the various forms of EM radiation listed above?
check all that apply to the above
They have different wavelengths.
They have different frequencies.
They propagate at different speeds through a vacuum depending on their frequency.
They propagate at different speeds through non-vacuum media depending on both their frequency and the material in which they travel.
They require different media to propagate.
All the above phenomena are due the electromagnetic wave spectrum. Electromagnetic waves travel at a constant speed of 3 x 10^8 m/s in a vacuum. Within the spectrum, the different types of electromagnetic waves exists in different band range of frequencies and wavelengths unique to each of the waves, and the energy they carry. When these waves enter a non-vacuum medium, their speed change, depending on the nature of the material of the medium, and the frequency or the wavelength of the incoming wave.
Light with an intensity of 1 kW/m2 falls normally on a surface with an area of 1 cm2 and is completely absorbed. The force of the radiation on the surface is
Answer:
The force of the radiation on the surface is 3.33 X 10⁻¹⁰ N
Explanation:
Given;
intensity of light, I = 1 kw/m²
area of the surface, A = 1 cm² = 1 x 10⁻⁴ m²
Power of the incident light, P = I x A
Power of the incident light, P = (1 kw/m²) x (1 x 10⁻⁴ m²)
Power of the incident light, P = 1 x 10⁻⁴ kW = 0.1 W
Power of the incident light is given by;
P = Fv
where;
F is the force of the radiation on the surface
v is the speed of light = 3 x 10⁸ m/s
F = P/ v
F = (0.1) / (3 x 10⁸)
F = 3.33 X 10⁻¹⁰ N
Therefore, the force of the radiation on the surface is 3.33 X 10⁻¹⁰ N