We consume a variety of goods and services, including groceries, toothpaste, internet access, cars and gas, fruits, and many more. They are likely to purchase an item if the price is low and it appears to be what they need or want.
Describe the relationship between a consumer and a producer.
People are producers when they create products and services—goods and services, goods and services, goods and services. They are consumers when they use the products that have been produced, the products that have been produced, the products that have been produced.
We pay costs for these products since we use them constantly and we need them in our daily life. We purchase groceries and fruits because we must eat food. Usually, the price of a thing is determined by the demand for it. Then, you can consider market competition, inflation rates, the standard of the goods, where they are available, how much it costs to produce them, as well as numerous government regulations and taxes.
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calculate the de Broglie wavelength associated with an electron accelerated through a potential difference of 1 kV.
1.2 x 10⁻¹¹ m is the de Broglie wavelength associated with an electron accelerated through a potential difference of 1 kV.
Define De Broglie wavelength .
De Broglie wavelength is the wavelength that is connected to an item in relation to its momentum and mass. Typically, a particle's force is inversely proportional to its de Broglie wavelength.
The relationship between the momentum of a moving particle and its wavelength is given by the de Broglie equation, h=mv. The likelihood of locating an object at a specific location in the configuration space is calculated using de Broglie waves. Making use of the de Broglie waves in the creation of electron microscopes is another significant use.
E = qV
q is 1.6 x 10⁻¹⁹ C
V is the potential difference.
v² = 2eV/m
v is 5.9 × 10⁹ m/s
λ = h/mv
h is the Planck Constant which is equal to 6.63x 10⁻³⁴ Js
Substituting values above we get λ = 1.2 x 10⁻¹¹ m.
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a mass attached to the end of a spring is set in motion. the mass is observed to oscillate up and down, completing 12 complete cycles every 3.00 s.
The frequency of such mass oscillation approximately 4 Hz, and its period is 0.5 seconds.
A frequency is defined.The quantity of pulses that pass a set location in a predetermined period of time is known as frequency. Therefore, if a wave passes through in less than a second, the frequencies is 2 per second. The periodicity is 100 times per hour if it consumes 1/100 of an hour.
Describe the frequency formula.The frequency equation is written as f = /, where is the waveform speed and is the wavelengths of the wave. f = /2, where is the resonant velocity, is the frequency formula described in terms of angular velocity.
12 complete cycle = 3 sec.
1 complete cycle = 3/12
= 1/4 sec.
mass oscillation, T = 1/2 sec.
= 0.5 sec.
f = 12/3
= 4 Hz
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Rocket observations show that dust particles in Earth's upper atmosphere are often electrically charged.a) Find the distance separating two dust particles if each has a charge of +e and the Coulomb force between them has magnitude 1.00x10−14−14N.b) Calculate the mass of one of the dust particles if this Coulomb force would accelerate it at 4.50x1088m/s22. (In the upper atmosphere, effects from other nearby charges typically result in a small net force and acceleration.)
a. The distance separating two dust particles if each has a charge of +e and the Coulomb force is 2.5 × 10⁻³ m
b. The mass of one of the dust particles if this Coulomb force would accelerate it is 2.22 x 10⁻²³ kg.
What is force?
Force is a physical quantity that represents the interaction between two objects that cause changes in motion of the objects. Force can be defined as the push or pull effect on an object. It is a vector quantity, which means it has both magnitude and direction. The unit of force in the International System of Units (SI) is the Newton (N), which is defined as the force required to accelerate a mass of one kilogram at a rate of one meter per second squared.
a) The force between two charged particles can be calculated using Coulomb's law, which states that the force between two point charges is proportional to the product of the charges and inversely proportional to the square of the distance between them:
F = k × q1 × q2 / r²
where k is the Coulomb constant (8.99 x 10⁹ N m²/C²), q1 and q2 are the charges of the two particles, and r is the distance between them.
Given that the force between the two particles is 1.00 x 10⁻¹⁴ N and each particle has a charge of +e, we can rearrange the equation to solve for r:
r = [tex]$ \sqrt{\frac{k \times q_1 \times q_2 }{ F} }[/tex]
= [tex]$ \mathrm{ \sqrt{\frac{8.99 \times 10^2 N m^2/C^2 \times 2e^2 }{ 1.00 \times 10^{-14} N} } }[/tex]
= 2.5 × 10⁻³ m
b) To calculate the mass of one of the dust particles, we can use Newton's second law, which states that the net force acting on an object is equal to its mass times its acceleration:
F = m × a
where F is the force, m is the mass, and a is the acceleration. Given that the acceleration of the particle is 4.50 x 10⁸ m/s², we can rearrange the equation to solve for m:
m = F / a
[tex]$ \mathrm{= \frac{1.00 \times 10^{-14} N}{ 4.50 \times 10^8 m/s^2} }[/tex]
= 2.22 x 10⁻²³ kg
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Let H(z) be the transfer function of a linear-phase FIR filter with real coefficients. The filter is known to have zeros in the following locations: Z1 = 1, Z2 = 2e^(-j0.41), Z3 = -j
(1) What is the smallest possible length (M) of this FIR filter? What are all possible zeros corresponding to your length-M FIR filter? (2) Which FIR filter type (I, II, III, IV) is your filter? ? (3) Please show the magnitude plot of frequency response of this FIR filter.
1) The smallest possible length (M) of the FIR filter is 4. The zeros for this length-4 FIR filter are: Z1 = 1, Z2 = 2e^(-j0.41), Z3 = -j, Z4 = -1.
What is FIR filter?A FIR filter (finite impulse response filter) is a type of filter used in signal processing. It is a linear, time-invariant, discrete-time filter whose impulse response (output in response to an impulse input) is of finite duration. This means that the output of the filter is only dependent on the current and previous inputs. FIR filters are used in many applications such as audio processing, telecommunications, and control systems.
2) The type of this FIR filter is Type III since its zeros are located on the unit circle.
3) The magnitude plot of the frequency response of this FIR filter is shown below. It is a linear-phase filter with real coefficients, so the frequency response should be symmetric around the Nyquist frequency.
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: The following five diagrams show pairs of astronomical objects that are all separated by the same distance d. Assume the asteroids are all identical and relatively small, just a few kilometers across. Considering only the two objects shown in each pair, rank the strength, from strongest to weakest, of the gravitational force acting on the asteroid on the left. Reset Help d d asteroid asteroid asteroid hydrogen atom asteroid Moon asteroid Sun d asteroid Earth
The ranking of the gravitational force acting on the asteroid are asteroid: sun, asteroid: earth, asteroid: moon, asteroid: asteroid, asteroid: hydrogen atom
What is an asteroid explain?
An asteroid is a small, rocky object that orbits the Sun. Asteroids are much smaller than planets, and are composed mostly of rock and minerals. They range in size from less than 1 meter to hundreds of kilometers across. Most asteroids are found in a region of space between the orbits of Mars and Jupiter known as the asteroid belt. On average, about 100 tons of material from asteroids and comets hits Earth's atmosphere each day. Most of this material is small dust-sized particles that burn up in the atmosphere before they reach the ground.
The gravitational force solely depends on the product of the masses because the distance is the same in each of the five scenarios. The mass of the object on the right determines the relative strength of gravitational force because the same asteroid is in each of the five scenarios on the left. Explore what transpires if we inquire about the gravitational force operating on the object on the right in Part B.
Therefore, asteroid: sun, asteroid: earth, asteroid: moon, asteroid: asteroid, asteroid: hydrogen atom are the answers.
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rectangular plate is supported by three cables as shown. knowing that the tension in cable ac is 60 n, determine the weight of the plate.
The weight of the plate is equal to -(60 × LAC)/LAB - 60.
What is plate?Plate is a flat dish used for serving food. It is usually made of ceramic, glass, metal, or plastic, and is sometimes decorated with patterns or designs. Plates are usually round, but can also be rectangular, square, or oval. They are used for a variety of meals, from casual to formal.
Using the principle of static equilibrium, we can set up a system of equations to solve for the weight of the plate.
Equilibrium in the vertical direction:
Weight of the plate + Tension in cable AB + Tension in cable AC = 0
W + TAB + TAC = 0
Equilibrium in the horizontal direction:
Moment created by the tension in cable AB + Moment created by the tension in cable AC = 0
TAB × LAB + TAC × LAC = 0
Where W is the weight of the plate, TAB is the tension in cable AB, TAC is the tension in cable AC, LAB is the length of cable AB, and LAC is the length of cable AC.
We know that the tension in cable AC is 60 N, so we can substitute that into the equations above:
W + TAB + 60 = 0
TAB × LAB + 60 × LAC = 0
We can now solve for the weight of the plate by solving the system of equations.
Substituting the second equation into the first equation:
W + TAB + 60 = 0
W + (60 × LAC)/LAB + 60 = 0
W = -(60 × LAC)/LAB - 60
Therefore, the weight of the plate is equal to -(60 × LAC)/LAB - 60.
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You encounter a moving walkway taht is 85m long and has a speed of 1.9m/s relatice to the ground. How long will it take you to cover the 85m length of the walkway if, once you get on the walkway, you immediately turn around and start walking in the opposite direction with a speed of 1.4 m/s relative to the walkway
It will take you 24.6 sec to cover the 85m length of the walkway.
What does the word "speed" mean?
Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. The distance traveled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity.
The term "displacement" refers to a shift in an object's position. It is a vector quantity with a magnitude and direction. The symbol for it is an arrow pointing from the initial location to the ending place. For instance, if an object shifts from location A to position B, its position changes.
V = 85m / 68s. = 1.25m/s Walking on ground.
t = d / V = 85m / (2.2+1.25)m/s = 24.6s.
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A volume of gas starts at a pressure of 10 atmospheres (atm) and a temperature of 27°C. If the temperature is increased by 75°C and the volume of the gas remains constant, what is the new pressure?
Answer:
the new pressure is 11.64 atmospheres.
Explanation:
Assuming that the gas follows the ideal gas law, which states that PV = nRT (where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in kelvin), we can use the formula P1/T1 = P2/T2 to solve for the new pressure P2.
Converting the initial temperature of 27°C to kelvin, we get T1 = 27°C + 273.15 = 300.15 K. Increasing the temperature by 75°C gives us the new temperature T2 = 300.15 K + 75°C = 348.15 K.
Using the formula, we can solve for P2:
P1/T1 = P2/T2
10 atm/300.15 K = P2/348.15 K
Simplifying the equation, we get:
P2 = (10 atm * 348.15 K) / 300.15 K
P2 = 11.64 atm (rounded to two decimal places)
Therefore, the new pressure is 11.64 atmospheres.
particle a of charge 3.24 x 10-4 c is at the origin, particle b of charge -5.64 x 10-4 c is at (4.00 m, 0), and particle c of charge 1.01 x 10-4 c is at (0, 3.00 m). we wish to find the net electric force on c.(a) What is the x component of the electric force exerted by A on C?(b) What is the y component of the force exerted by A on C?(c) Find the magnitude of the force exerted by B on C.(d) Calculate the x component of the force exerted by B on C.(e) Calculate the y component of the force exerted by B on C.(f) Sum the two x components from parts (a) and (d) to obtain the resultant x component of the electric force acting on C.(g) Similarly, find the y component of the resultant force vector acting on C.(h) Find the magnitu
(a) The x component of the electric force exerted by A on C is 2.29 x 10⁻⁷ N.
(b) The y component of the force exerted by A on C is 1.72 x 10⁻⁷ N.
(c) The magnitude of the force exerted by B on C is -3.96 x 10⁻⁷ N.
(d) The x component of the force exerted by B on C is -3.17 x 10⁻⁷ N.
(e) The y component of the force exerted by B on C is -2.38 x 10⁻⁷ N.
(f) The sum of two x components from parts (a) and (d) to obtain the resultant x component of the electric force acting on C is -0.88 x 10⁻⁷ N.
(g) The y component of the resultant force vector acting on C is -0.66 x 10⁻⁷ N.
(h) The magnitude of the net electric force on particle C is 1.01 x 10⁻⁷ N.
Net Electric ForceThe electric force exerted by a particle on another particle can be calculated using Coulomb's Law, which states that the force between two point charges is given by:
F = k * q1 * q2 / r²
where k is the Coulomb constant (8.99 x 10⁹ Nm²/C²), q1 and q2 are the magnitudes of the charges, and r is the distance between the two particles.
(a) The x component of the electric force exerted by particle A on C can be found by considering the x direction only. The distance between A and C can be found using the Pythagorean theorem:
r = sqrt((4.00 m)² + (3.00 m)²) = 5.00 m
The electric force in the x direction can then be found as follows:
F_x = k * q1 * q3 / r² * cos(θ)
where q1 is the charge of particle A (3.24 x 10⁻⁴ C), q3 is the charge of particle C (1.01 x 10⁻⁴ C), and θ is the angle between the line connecting the two particles and the x-axis. Since the line is in the first quadrant, cos(θ) is positive:
θ = arctan(3.00 m / 4.00 m) = 0.93 radians
cos(θ) = cos(0.93) = 0.80
F_x = k * q1 * q3 / r² * cos(θ) = (8.99 x 10⁹ Nm²/C²) * (3.24 x 10⁻⁴ C) * (1.01 x 10⁻⁴ C) / (5.00 m)² * 0.80 = 2.29 x 10⁻⁷ N
(b) The y component of the force exerted by A on C can be found in a similar manner:
F_y = k * q1 * q3 / r² * sin(θ)
sin(θ) = sin(0.93) = 0.60
F_y = k * q1 * q3 / r² * sin(θ) = (8.99 x 10⁹ Nm²/C²) * (3.24 x 10⁻⁴ C) * (1.01 x 10⁻⁴ C) / (5.00 m)² * 0.60 = 1.72 x 10⁻⁷ N
(c) The magnitude of the force exerted by B on C can be found using Coulomb's Law:
F = k * q2 * q3 / r²
where q2 is the charge of particle B (-5.64 x 10⁻⁴ C) and r is the distance between the two particles:
r = sqrt((4.00 m)² + (3.00 m)²) = 5.00 m
F = k * q2 * q3 / r² = (8.99 x 10⁹ Nm²/C²) * (-5.64 x 10⁻⁴ C) * (1.01 x 10⁻⁴ C) / (5.00 m)²= -3.96 x 10⁻⁷ N
(d) The x component of the force exerted by B on C can be found by considering the x direction only:
F_x = k * q2 * q3 / r² * cos(θ)
where q2 is the charge of particle B (-5.64 x 10⁻⁴ C), q3 is the charge of particle C (1.01 x 10⁻⁴ C), and θ is the angle between the line connecting the two particles and the x-axis. Since the line is in the first quadrant, cos(θ) is positive:
θ = arctan(3.00 m / 4.00 m) = 0.93 radians
cos(θ) = cos(0.93) = 0.80
F_x = k * q2 * q3 / r² * cos(θ) = (8.99 x 10⁹ Nm²/C²) * (-5.64 x 10⁻⁴ C) * (1.01 x 10⁻⁴C) / (5.00 m)² * 0.80 = -3.17 x 10⁻⁷ N
(e) The y component of the force exerted by B on C can be found in a similar manner:
F_y = k * q2 * q3 / r² * sin(θ)
sin(θ) = sin(0.93) = 0.60
F_y = k * q2 * q3 / r² * sin(θ) = (8.99 x 10⁹ Nm²/C²) * (-5.64 x 10⁻⁴ C) * (1.01 x 10⁻⁴ C) / (5.00 m)² * 0.60 = -2.38 x 10⁻⁷ N
(f) The x component of the resultant force can be found by summing the x components from parts (a) and (d):
F_x_resultant = F_x(A on C) + F_x(B on C) = 2.29 x 10⁻⁷ N + (-3.17 x 10⁻⁷ N) = -0.88 x 10⁻⁷ N
(g) The y component of the resultant force can be found by summing the y components from parts (b) and (e):
F_y_resultant = F_y(A on C) + F_y(B on C) = 1.72 x 10⁻⁷ N + (-2.38 x 10⁻⁷ N) = -0.66 x 10⁻⁷ N
(h) The magnitude of the resultant force can be found using the Pythagorean theorem:
F_resultant = sqrt(F_x_resultant² + F_y_resultant²) = sqrt((-0.88 x 10⁻⁷ N)² + (-0.66 x 10⁻⁷ N)²) = 1.01 x 10⁻⁷ N
So the magnitude of the net electric force on particle C is 1.01 x 10⁻⁷ N.
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Open the phase diagram for CO2 given in the introduction again. Use the phase diagram for CO2 in the interactive activity and determine which of the following statements are correct. CO2 is a gas under normal conditions of temperature and pressure.
All three phases of CO2 exist simultaneously at the triple point. When the pressure is 4 atm and the temperature is more than −56.7∘C, CO2 exists as a solid. When the pressure is 1 atm, there is no temperature at which the liquid phase of CO2 exists.
Movement across boundary line BO corresponds to a phase change.
CO2 forms a supercritical fluid at temperatures less than 31∘C.
The correct statements about the phase diagram for CO₂ from the given options are as follows:
All three phases of CO₂ exist simultaneously at the triple point.When the pressure is 1 atm, there is no temperature at which the liquid phase of CO₂ exists.CO₂ is a gas under normal conditions of temperature and pressure.Movement across boundary line BO corresponds to a phase change.The correct options are A, B, C, and D.
What is CO2's triple point?The parameters of temperature and pressure at which CO₂ is simultaneously present in all three physical states of matter are referred to as the triple point of CO₂.
At 5.2 atm, the triple point of CO₂ is -57 °C.At normal room temperature and atmospheric pressure, CO₂ is a gas.It is a significant greenhouse gas that is denser than air.Learn more about the triple point at: brainly.com/question/16945664
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A sinusoidal wave of frequency 710 Hz has a speed of 360 m/s. (a) How far apart are two points that differ in phase by π/2 rad? (b) What is the phase difference between two displacements at a certain point at times 4.00 ms apart?
the answer is (a) The corresponding length is 127 mm and (b) the phase difference is 4[tex]\pi[/tex] rad.
Using v = fλ,
we find the length of one cycle of the wave is
λ = 360 / 710
= 0.508 m
λ = 508 mm.
From f = 1 / T,
we find the time for one cycle of oscillation is
T = 1 / 710 = 0.002 × [tex]10^{-3}[/tex] s
T = 2.00 ms.
(a) A cycle is equivalent to 2[tex]\pi[/tex] radians, so that [tex]\pi[/tex]/2 rad corresponds to one-fourth of a cycle.
The corresponding length, therefore, is [tex]\pi[/tex]/4 = 508 / 4 = 127 mm.
(b) The interval 4.00 ms is double of T and thus corresponds to double of one cycle, or double of 2[tex]\pi[/tex] rad.
Thus, the phase difference is 2 × 2[tex]\pi[/tex]= 4[tex]\pi[/tex] rad.
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A photoelectric experiment indicates that violet light of wavelength 420 nm is the longest wavelength radiation that can cause photoemission of electrons from a particular multialkali photocathode surface.c. Given that the UV light of wavelength 300 nm has an intensity of 20 mW/cm2, if the emitted electrons are collected by applying a positive bias to the opposite electrode, what will be the photoelectric current density in mA cm-2 ?
The given information are not enough to determine the photoelectric current density
How to determine the photoelectric current densityFrom the question, we have the following parameters that can be used in our computation:
UV light of wavelength = 300 nmIntensity = 20 mW/cm²Violet light of wavelength = 420 nm (the longest)The photoelectric current density can be calculated using:
J = n * e / t
Where
n is proportional to the intensity of the light (I) and the quantum efficiency (η) of the photocathode (η)From the question, we do not have value for (η)
Hence, the photoelectric current density cannot be calculated
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The velocity of a particle moving along the x-axis is given for
t > 0 by vx = (32.0t - 2.00t3) m/s,
where t is in s. What is the acceleration of the particle when (after
t = 0)
it achieves its maximum displacement in the positive x-direction?
The acceleration of the particle when it achieves its maximum displacement in the positive x-direction is -6.00[tex]m/s^2[/tex].
The acceleration of a particle is defined as the rate of change of its velocity with respect to time. In this case, the velocity of the particle is given by vx = 32.0t - 2.00t^3 m/s. To find the acceleration, we can differentiate this expression with respect to time:
ax = dvx/dt = 32.0 - 6.00[tex]t^2 m/s^2[/tex].
The particle achieves its maximum displacement in the positive x-direction when its velocity is zero, which occurs when vx = 0. Solving for t in the equation vx = 32.0t - 2.00[tex]t^3[/tex] = 0, we find that t = ±√(16/3) s. The particle achieves its maximum displacement in the positive x-direction, so we want the positive value of t, which is t = √(16/3) s. Plugging this value of t into the expression for ax, we find that the acceleration of the particle is ax = 32.0 - 6.00(16/3) = -6.00 [tex]m/s^2[/tex].
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determine the direction of the resultant force, measured counterclockwise from the positive x axis. express your answer using three significant figures.
Resultant force direction = 11.08 degrees counter-clockwise from the positive x-axis.
In order to address this issue, we must first divide these forces into their corresponding x and y components, which we must then combine to determine the final force.
Given the magnitude of force (F1) = 32kN
The angle of direction (θ1) = 30°
F1x = -32k x cos(30°) = -27.7kN
F1y = -32 x sin(30°) = -16kN
Given a triangle, let cos(θ) = 5/13 = 0.99 then θ = 67.3°
The magnitude of force F2 = 26kN
The angle of direction (θ2) = 0.99°
F2x = -26 x cos(67.3°) = 10.03kN
F2y = 26 x sin(67.3°) = 23.9kN
Frx = F1x + F2x = -37.73kN
Fry = F1y + F2y = 7.9kN
Let the resultant force = Fr then,
Fr^2 = Frx^2 + Fry^2
Fr^2 = (-37.73)^2 + (7.9)^2
Fr = √1423.55+62.41 = √1485.96 = 38.5kN
Hence the resultant force = 38.5kN
θ = tan^-1(Fry/Frx) = tan^-1(7.9/-37.73) = -11.08°
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A cart loaded with bricks has a total mass of 9.4 kg and is pulled at constant speed by
a rope. The rope is inclined at 23.8 degrees above the horizontal and the cart moves 16.3 m on a horizontal floor. The coefficient of kinetic friction between ground and cart is 0.7 . The acceleration of gravity is 9.8 m/s^2. How much work is done on the cart by the rope? Answer in units of kJ.
explain the similarities and differences between the observations that supported the geocentric models of the solar system and the phenomena described in the table.
Answer:
The geocentric model says that the earth is at the center of the cosmos or universe, and the planets, the sun and the moon, and the stars circles around it. The early heliocentric models consider the sun as the center, and the planets revolve around the sun.
while standing at the edge of a building's roof, chad throws an egg upward with an initial speed of 8.00 m/s. the egg subsequently smashes on the ground, 12.0 m beneath the height from which chad threw it. ignore the effects of air resistance.At what speed does the egg pass the point from which it was thrown?v= _____m/sHow much time t does the egg spend in the air? t=___sWhat total distance d does the egg travel? d=___m
The result is obtained by using the equations in uniformly accelerated straight motion.
Uniformly Accelerated Straight MotionA uniformly accelerated straight motion is a motion with acceleration or deceleration in a straight line. The equations apply in vertical dimension are
v₁ = v₀ + gt
v₁² = v₀² + 2gh
h = v₀t + ½ gt²
Where
v₀ = initial velocityv₁ = final velocityg = acceleration due to gravityt = timeh = heightWhile standing at the edge of a building's roof, Chad throws an egg upward.
Initial speed, v₀ = 8.00 m/sIt finally falls 12.0 beneath the height at which Chad threw it. No air resistance.Find
The speed of the egg when passes the point which it was thrown!The time spent by the egg in the air!The total distance the egg travels!See the illustration picture in the attachment!
The distance between the egg when it was thrown and the highest point it could reach is
v₁² = v₀² - 2gh₁
0 = 8² - 2(10)h₁
64 = 20h₁
h₁ = 3.2 m
The egg then moves downward. The speed when it passes the initial point is
v₂² = v₁² + 2gh₁
v₂² = 0 + 2(10)(3.2)
v₂² = 64
v₂ = 8 m/s
The speed is the same with the initial speed.
The time spent by the egg from initial point to the highest point is
v₁ = v₀ - gt₁
0 = 8 - 10t₁
8 = 10t₁
t₁ = 0.8 s
The time spent from the highest point to the ground is
h = v₀t + ½ gt²
(3.2 + 12) = 0 + ½ (10)t₂²
15.2 = 5t₂²
t₂² = 3.04
t₂ = 1.74 s
The total time spent in the air will be
t = t₁ + t₂
t = 0.8 + 1.74
t = 2.54 s
The total distance traveled by the egg is
= 2(3.2) + 12
= 6.4 + 12
= 18.4 m
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what is a dielectric constant
Answer: The dielectric constant is the ratio of the capacitance formed by two plates with material between them to the capacitance of the same plates with air as the dielectric. For low megahertz, frequencies are less than are equal to 1,000 MHz.
Explanation:
An object is placed 7.0 cm away from a converging lens with a focal length of 7.0cm
you will use the lens equation to solve the problem
Your roommate is working on his bicycle and has the bike upside down. He spins the 70.0 cm -diameter wheel, and you notice that a pebble stuck in the tread goes by three times every second. Express your answer with the appropriate units.
Part A: What is the pebble's speed?
Part B: What is the pebble's acceleration?
The wheel's circumference is C = d = (0.7 m) = 2.2 m. The pebble travels 3C = 6.6 m in one second since it passes by three times every second. Hence, the stone moves at 6.6 m/s when v = d/t. Part B: The formula = /t, where is the change in angular speed and t is the time it takes for the change to occur, can be used to calculate the angular acceleration of the wheel.
What is an example of inertia?
Upon being battered, the mat releases dust. falling forward when abrupt breaks are applied in transit. When the tree is shaken violently, the leaves fall off. Artificial satellites continue to orbit in a circular motion due to inertia.
What is a SI unit of inertia?
An object's inability to change its position or the configuration of a particular body is known as inertia. Kilo Gram is the SI unit of inertia since mass is a measure of inertia. If you require a unit of inertial moment, it is Kg m2.
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a body of mass 10kg on a smooth inclined plane is connected over a smooth pulley to a mass of 15kg . the acceleration of the system is? please help ASAP will give branliest
The acceleration of the system is (m₁g sinθ + m₂g) / (m₁ + m₂) / (m₁ + m₂)
What is the acceleration of the system?
The acceleration of the system can be calculated using the equation of motion and considering the forces acting on each mass.
The equation of motion for the 10 kg mass is:
W₁ - T = m₁a
The equation of motion for the 15 kg mass is:
W₂ + T = m₂ a
Where;
m₁ and m₂ are the masses of the 10 kg and 15 kg masses respectivelya is the acceleration of the system.Solving for the tension T and substituting the values for W₁ and W₂, we get:
T = (m₁g sinθ + m₂g) / (m₁ + m₂)
And substituting T back into either equation, we get:
a = (m₁g sinθ + m₂g) / (m₁ + m₂) / (m₁ + m₂)
where;
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Joshua is attracted toward Earth by a 500-N gravitational force. The Earth is attracted toward Joshua with a force of1. 250 N.
2. 500 N.
3. 1000 N.
4. 0 N.
Joshua is attracted toward Earth by a 500-N gravitational force. The Earth is attracted toward Joshua with a force of 500 N (2)
The gravitational attraction that exists between an individual and the earth is directly proportional to the mass of the individual and inversely proportional to the square of the radius of the planet (distance from the person to the center of earth). Your weight is the number that represents the gravitational attraction between you and the Earth.
When you contact with the Earth, however, the momentum you gain is equivalent to the momentum the Earth obtains. Additionally, according to the traditional point of view, the force with which you are attracted to the Earth is equivalent to the force with which the Earth is attracted to you. Even if your gravity isn't particularly strong, it nonetheless manages to pull a vast amount of mass from the Earth.
Therefore, the Earth is attracted toward Joshua is equal to Joshua attracted towards Earth = 500 N
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Four lightweight balls A, B, C, and D are suspended by threads. Ball A has been touched by a plastic rod that was rubbed with wool. When the balls are brought close together, without touching, the following observations are made: Balls B, C, and D are attracted to ball A. Balls B and D have no effect on each other. Ball B is attracted to ball C.
The observations in this scenario can be explained in terms of electrostatic principles and charge behavior in the presence of an external electric field.
How do calculate the balls are brought close together, without touching?This is an example of an electrostatic interaction involving charge. Rubbing a plastic rod with wool electrified it and acquired an excess negative charge. This left an excess positive charge on the wool.
When the negatively charged sphere A approaches another sphere, it repels the electrons in the sphere, leaving an overall positive charge. Therefore, balls B, C, and D are attracted to ball A. Sphere B and sphere D are both positively charged, so they repel each other and do not affect each other.
Ball B is attracted to ball C because it has the opposite charge. Ball C is attracted to ball A, but ball B is not attracted to ball A. This is because both are negatively charged and therefore repel each other.
Therefore, the observations in this scenario can be explained by the electrostatic principle and the behavior of charges in the presence of an external electric field.
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a ball thrown upward reaches its maximum height and then falls back. if air resistance is negligible, its acceleration is
A ball sent upward reaches its highest point before falling backward. If aerodynamics is minimal, the motion's acceleration is constant throughout.
Describe acceleration.In physics, acceleration is the rate at which the movement of an object changes in relation to time. According to Newton's Second Law, the sum of all force applied on an item results in its acceleration. The axis of motion is altering, therefore an object moving at a steady speed on a circular path is still moving forward.
What are the three types of acceleration?The three forms of increasing motions are often classified as uniform acceleration, non-uniform acceleration, and average acceleration. Uniform acceleration describes a motion that occurs when a object follows an uniform path while accelerating gradually over time.
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What is the total displacement of person if he starts at home drives 2 kilometers due east and then turns around and drives 5 kilometers due west?
Include both magnitude and direction.
Answer:
3 West
Explanation:
Let east be the + direction.
2 - 5 = -3
Displacement = 3 West
A rider is training a horse. Horse moves 60 metres towards right in 3 seconds. Then it turns back and travels 30 metres in 2 seconds. Find its average velocity?
The average velocity of the horse, given that moves 60 m to the right and 30 m backward is 18 m/s
How do I determin the average velocity?Average velocity is defined as:
Average velocity = Total displacement / total time
With the above formula, we can obtain the average velocity. Details below:
Displacement to the right = 60 metersDisplacement to the left = 30 metersTotal displacement = 60 + 30 = 90 metersTime to the right = 3 secondsTime to the left = 2 secondsTotal time = 3 + 2 = 5 secondsAverage velocity =?Average velocity = Total displacement / total time
Average velocity = 90 / 5
Average velocity = 18 m/s
Thus, we can conclude that the average velocity is 18 m/s
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A 1105 kg automobile is pulied by a horizontal towline with a net force of 818 N. What is the acceleration of the auto? (Neglect friction, Enter your answen
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The acceleration of the auto is 0.74 m/s².
What is the acceleration of the automobile?
The acceleration of the automobile is calculated by applying Newton's second law of motion as shown below;
F = ma
where;
m is the mass of the automobilea is the acceleration of the automobileThe applied force of the automobile is given as 818 N and the mass of the automobile is given as 1105 kg.
a = F / m
a = ( 818 N ) / ( 1105 kg )
a = 0.74 m/s²
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Answer the following questions using the Velocity vs Time graph.
1. What is the car doing a position
2. What is the car doing a position
3. What is the car doing a position
According to the Velocity vs Time graph:
at A: car is moving with increased velocity with time
at B: the car is stationary or at uniform velocity
at E: the car is slowing down or its velocity decreases with time.
What is velocity, exactly?
The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate.
When an item is moving, its velocity is the rate at which it is changing position as seen from a certain point of view and as measured by a specific unit of time.
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The nucleus was discovered by Rutherford when this occurred to the alpha particles shot at gold foil in his laboratory. T/F?
The given statement about “The nucleus was discovered by Rutherford when this occurred to the alpha particles shot at gold foil in his laboratory.” is true, because in his famous experiment, alpha particles were seen to scatter away from a gold foil in the reverse direction.
In the Rutherford model, the atom is described as having a small, dense, positively charged core known as a nucleus, in which nearly all of the mass is concentrated, and around which the light, negative constituents known as electrons circulate at some distance, similar to how planets revolve around the sun at a certain distance. Under the guidance of Rutherford and German physicist Hans Geiger in 1909, Ernest Marsden, conducted a series of experiments that revealed the scattering of alpha particles from thin gold foil. This resulted in the hypothesis that the nucleus was small and dense.
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A person stands on a scale in an elevator. The maximum and minimum scale readings are 908.9 N and 494.7 N, respectively. The acceleration of gravity is 9.8 m/s 2 . Assume the magnitude of the acceleration is the same during starting and stopping, and determine the acceleration of the elevator. Answer in units of m/s 2 .
The acceleration of the elevator is 9.8 m/s^2, which is equal to the acceleration due to gravity.
The change in the person's weight can be used to calculate the elevator's acceleration.
The change in weight is: 908.9 N - 494.7 N = 414.2 N
Since weight is equal to mass times acceleration (W = m * a), we can rearrange the equation to solve for acceleration:
a = W / m
Where m is the mass of the person, which can be calculated using the acceleration due to gravity:
m = W / g = 414.2 N / 9.8 m/s^2 = 42.3 kg
Substituting the mass into the equation for acceleration:
a = 414.2 N / 42.3 kg = 9.8 m/s^2
So the acceleration of the elevator is 9.8 m/s^2, which is equal to the acceleration due to gravity.
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