do forces that act a distance come in pairs?

Answers

Answer 1

Answer:

Forces come in pairs.

Explanation:

Distances are between two points. The distance from A to B is equal but opposite the distance from B to A.


Related Questions

Which are examples of perfectly inelastic collisions? Check all that apply.

a baseball bouncing off a bat
bumper cars bumping off of each other
a cue ball hitting an eight ball and stopping
a plane landing on an aircraft carrier
rain sticking to a window
two train cars coupling together

Answers

A plane landing on an aircraft carrier
Rain sticking to a window
Two train cars coupling together

Answer:

D. a plane landing on an aircraft carrier

E. rain sticking to a window

F. two train cars coupling together

Explanation:

the impulse-momentum relationship is a direct result of

Answers

Newton's second law.

__________________

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The impulse-momentum relationship is a direct result of Newton's second law of motion.

What is the impulse-momentum?

The impulse-momentum theorem states that the impulse applied to an object is equal to the change in its momentum. It proves that the change in momentum of an object depends not only on the amount of force applied but also on the duration of force applied.

Newton's second law states that the force acting on an object is equal to the rate of change of its momentum.

This means that a force applied to an object will cause a change in its momentum. The impulse-momentum relationship describes the relationship between the force applied to an object and the resulting change in its momentum.

The impulse-momentum relationship states that the impulse acting on an object is equal to the change in its momentum.

Impulse is defined as the force applied to an object over a period of time, while momentum is the product of an object's mass and velocity. Therefore, the impulse-momentum relationship can be expressed as:

Impulse = Change in momentum

This relationship is important in understanding the behavior of objects in motion, particularly in collisions or other situations where forces act over a period of time.

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a body of mass 10 kg is moving with velocity of 10ms-1.a force acts for 5 seconds to reduce its velocity to 2ms-1.find the momentum of the body before and after application of the force on it

Answers

Answer:

momentum before: 100kgm/s

momentum after: 20kgm/s

Explanation:

initial velocity: 10

final velocity: 2

p=mv

before: 10kg×10m/s

after:10kg×2m/s

I'm not 100% sure btw

A 4000kg truck has a head-on inelastic collision with a 2500kg truck.

A. calculate the total momentum of the trucks before they collide.


B. Calculate their speed just after they collide.

Answers

Answer:it could be B

Explanation:

im not sure

. a. Calculate the work done while lifting 300 kg of wate through a vertical height of 6 m. (Assume g = 10 m a =​

Answers

Answer:

potential energy = mgh = 300 × 10 × 6m = 18000 joule or 18 kilo joule.

Explanation:

what is value of 2.37 in sl units

Answers

The question is not clear

Question:
The US Navy is developing a railgun that uses magnetic field repulsion. The railgun can propel a 981 N projectile at seven times the speed of sound. How much energy is stored in this magnetic field? Assume a complete conversion of energy and a speed of sound of 340 m/s.

Answer choices:
A. 119 MJ
B. 283 MJ
C. 578 MJ
D. 2780 MJ

Answers

The relation of the kinetic energy allows to find the correct result for the energy stored in the electromagnet is:

B) 283 MJ

Kinetic energy is the energy due to the movement of bodies.

          K = ½ m v²

     

Where K is the kinetic energy, m is  the mass and v the spped.

They indicate that the weight of the bodye is W = 981 N and its final velocity is v = 7 [tex]v_s[/tex].

          W = m g

           

Since the projectile starts from rest, its initial velocity is zero, therefore the change in energy is

        ΔK = [tex]K_f - K_o = K_f[/tex]  

we substitute

        ΔK = ½ 981 / 9.8 (7 340) ²

         ΔK = 2.835 10⁸ J

They indicate that all the energy of the electromagnet is transformed into the energy of the projectile,

          Em = K

When reviewing the results, the correct one is:

       B) 283 MJ

In conclusion, using the relationship of kinetic energy we can find the correct result for the energy stored in the electromagnet is:

   B)  283 MJ

learn more about kinetic energy here: brainly.com/question/8101588

if vector b is added to vector a under what conditions does the resultant vector has magnitude a+b?​

Answers

Explanation:

hope it's useful for you knows

Tim is pushing a heavy box across the floor. He is using 300N of force and can accelerate at 2m/s/s. What is the mass of the box?

-298 kg
-600 kg
-0.006 kg
-150 kg

Answers

F=300Na=2m/s^2

Using Newton's second law

[tex]\\ \sf\Rrightarrow F=ma[/tex]

[tex]\\ \sf\Rrightarrow 300=2m[/tex]

[tex]\\ \sf\Rrightarrow m=150kg[/tex]

Hey there!

The formula of “mass” in physics is:

m = F/a

Whereas “f” is ‘force’, “a” is ‘acceleration’, & “m” is your ‘mass’ of course.

mass = 300 Net force/2 acceleration

300 Net force/2 acceleration = m

mass = 150

Therefore, your answer is: 150 kg

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)


It takes a car 4 seconds to slow down from 22 m/s to 6 m/s , what was its acceleration?

Answers

To Find The Acceleration of  A Car Slowing Down:

The change in speed is the final speed minus the initial speed. To find acceleration, divide the change in velocity by the length of time during which the velocity changed.

what is the energy equivalent of an object with a mass of 2.5 kg?

Answers

Answer:

2,500g is the answer yes

which is the hottest and coldest planet in solar system ?​

Answers

Answer:

hottest plant: vensus, close to the sun

coldest plant: Neptune, farthest from the sun

Explanation:

Under the Big Top elephant. Ella [2500 kg]. is attracted to Phant, the 3,000 kg elephant. They are separated by 8 m. What is the gravitational attraction between them? G=6.67×10^-11 (-11 is an exponent)​​

Answers

Hi there!

We can use the same equation for Gravitational Force:

[tex]\large\boxed{F_g = G\frac{m_1m_2}{r^2}}[/tex]

Fg = force due to gravity (N)

G = gravitational constant

m1,m2 = masses of objects (kg)

r = distance between objects (m)

Plug in the values provided:

[tex]F_g = (6.67*10^{-11})\frac{(2500)(3000)}{8^2} = \large\boxed{7.814 * 10^{-6}N }[/tex]

[tex]\huge\bf\underline{\underline{\pink{A}\orange{N}\blue{S}\green{W}\red{E}\purple{R:-}}}[/tex]

Here we've been given,

Universal gravitational constant (G) = [tex] \sf{6.67 \times {10}^{ - 11} }[/tex]

Mass of object 1 (m1) = 2500 kg

Mass of object 2 (m2) = 3000 kg

Distance between two objects (r) = 8 m

We have to find the gravitational attraction force (Fg) = ?

The standard formula to solve is given by,

[tex]:\implies\tt{F_g = g \frac{m_1m_2}{ {r}^{2} } } [/tex]

[tex]:\implies\tt{F_g = 6.67 \times {10}^{ - 11} \times \frac{(2500 )(3000)}{ {8}^{2} } }[/tex]

[tex]:\implies\tt{F_g = 6.67 \times {10}^{ - 11} \times \frac{7500000}{64} }[/tex]

[tex]:\implies\tt{F_g = 7.814 \times {10}^{ - 6} }[/tex]

Gravitational force of attraction is 7.814 × 10^-6 N.

Yoo what it do I don’t know the answer tho

Answers

Answer:

You should try your best to answer the question.

Which statement best explains the environmental drawback of using geothermal energy over energy generated by fossil fuels?

More cost-effective over time
Less pollution than fossil fuel plants
More energy plant locations available
Changes to regional landscapes

Answers

Answer:

Die Antwort lautet: Weniger Umweltverschmutzung als Kraftwerke mit fossilen Brennstoffen

Explanation:

hoffe das hat geholfen!! :))

Answer:

Changes to regional landscapes

Explanation:

It would be D because this is a cost or drawback and geothermal energy production would cause changes to the landscape, unlike how fossil fuels would.  I also got this right on the quiz.

Hope this helps!

The app claimed it has "Forbidden text"​

Answers

What??? I’m confused

PLZ HELP ME FAST A relationship between two variables is called:
A.
observable
.B.
correlation
.C.
causation
D.
finite.

Answers

Answer:

B- Correlation

Explanation:

Answer:

correlation

Explanation:

The length of daylight changes as the seasons change during the year. what causes these changes in the number of daylight hours?

Answers

Answer:

The earth travels around the sun in a (parabolic) path known as the ecliptic.

The axis of the earth's rotation is tilted about 23 deg to the ecliptic.

At the winter solstice (around Dec. 21), the sun will appear to be at its farthest south in its orbit. (This marks the beginning of winter for observers in the northern hemisphere and the beginning of summer for an observer in the southern hemisphere)

The tilt of the axis of the earth's rotation causes the change in the daylight hours.

how did you identify the layer that belonged next to the cambrian layer?

Answers

Answer:

Morphology and phylogenetics revealed by fossils. Perhaps the strongest evidence to support the Cambrian evolutionary explosion of animal forms is the first clear appearance, in the Early Cambrian, of skeletal fossils representing members of many marine bilaterian animal phyla

what is the cost of monthly (30 days) electric bill of ana if her city's cost of electricity is 0.05$ per kwh and she uses three refrigerators running in 600-watt power rating and open 24 hours

Answers

Answer:

1kW = 1000W

600W = 0.6kW

Cost of electric bill = 0.6kWh × 24 × 30 × $0.05

                               = $21.60

the smallest division value of electronic balance​

Answers

Answer:

0.1g to 0.0000001g hope it helps uu

A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation h(t) = â€""16t2 48t 190. Approximately when will the projectile hit the ground? 1. 5 seconds 3. 2 seconds 5. 3 seconds 6. 2 seconds.

Answers

The time for the projectile to hit the ground from the given position is 1.5 s.

The given parameters:

Initial velocity of the projectile, u = 48 ft/sHeight, h = 190 ftModel of the projectile path, h(t)  = –16t² + 48t + 190.

The time for the projectile to hit the ground is calculated as follows:

when the projectile hits the ground, the final velocity = 0

[tex]v_f = 0\\\\\frac{dh(t)}{dt} = v_f\\\\\frac{dh(t)}{dt} = -32t + 48\\\\-32t+48 = 0\\\\32t = 48\\\\t = \frac{48}{32} \\\\t = 1.5 \ s[/tex]

Thus, the time for the projectile to hit the ground from the given position is 1.5 s.

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A box slides across a rough surface, eventually coming to rest.
Part A
a. Use the work-energy principle (Khan Academy:Work and the work-Energy Principle and the definition of work to explain why the box comes to rest.

b. Explain how the motion of the box is consistent with the Law of Conservation of Energy.

Answers

Answer:

he was a random act like you to be the first time I see is a great day and night to get a very happy to see you soon I hope that the world is not the same thing to say about this

a) When a box slides across a rough surface, eventually coming to rest, its kinetic energy is used during work done against frictional resistance force.

b) This work done is stored in the box as a potential energy. Thus the motion of the box is consistent with the Law of Conservation of Energy.

What is  work-Energy Principle?

According to the work-energy theorem, the work done by the net force acting on a body equals the change in kinetic energy.

It can simply be written as:

Work done = initial kinetic energy - final kinetic energy

The work energy theorem equation is the one presented above.

Now when a box slides across a rough surface, eventually coming to rest, frictional force comes into play. This force is opposite to the direction of motion of the box. Hence, the kinetic energy of the box is used during work done against frictional resistance force and stored in the box as a potential energy and thus  Law of Conservation of Energy followed.

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A 2.0 kg block rests on a level surface. The coefficient of static friction is, and the coefficient of kinetic friction is A horizontal force, X, is applied to the block. As X is increased, the block begins moving. Describe how the force of friction varies as X increases from the moment the block is at rest to when it begins moving. Indicate how you could determine the force of friction at each value of X―before the block starts moving, at the point it starts moving, and after it is moving. Show your work.

ps. I had to change F to X because of brainly.

Answers

By Newton's second law, the net force acting on the block in the vertical direction is

∑ F [ver] = n - mg = 0

where n = magnitude of normal force and mg = weight of the block. It follows that n = mg.

When the block is at rest, the applied force X will not be enough to move the box until it can overcome the maximum mag. of static friction. If µ[s] is the coefficient of static friction, then the maximum mag. of the frictional force is

f = µ[s] n = µ[s] mg

The net horizontal force would be

∑ F [hor] = X - µ[s] mg = 0

so a minimum force of X = µ[s] mg is required to get the block moving. Any mag. smaller than this and the block stays at rest/in equilibrium.

Once the mag. of X exceeds µ[s] mg, the block will begin to move. At that point, if the coefficient of kinetic friction is µ[k], then the net force on the block is

∑ F [hor] = X - µ[k] mg = 0

so a minimum force of X = µ[k] mg would be needed to keep the block moving at constant speed, or otherwise X = µ[k] mg + ma if the block is accelerating with mag. a.

The principles here are captured in the attached plot.

If you were traveling 60 mph and not wearing a seatbelt and collided with a fixed object, how fast would you be traveling when you hit the windshield

Answers

Your speed when your car hits a fixed object is 60 mph.

The given parameters:

Your initial speed, v = 60 mph

What is relative velocity?

Relative velocity tells us how fast we are traveling from a fixed point or reference point.

When travel at 60 mph in a car, you are moving at the same rate with the car.If you are not wearing a seat belt, when you hit a fixed object, you will move forward at the same rate as the car's speed.

Thus, we can conclude that your speed when your car hits a fixed object is 60 mph.

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what does the slope of the curve on a velocity vs. time graph represent?

Answers

Answer:

the slope of velocity-time graph represent an object acceleration

What ions are produced from acids and bases?

Answers

Answer:

Give person above me brainliest

Explanation:

A wave has a frequency of 2700 Hz and λ of 6m. Calculate the speed of the wave.pls help

Answers

Answer:

16,200 m/s

Explanation:

The speed of the wave given only it's frequency and wavelength can be found by using the formula

[tex]c = f \times \lambda[/tex]

where

c is the velocity of the wave in m/s

[tex] \lambda[/tex] is the wavelength in m

f is the frequency in Hz

From the question

c = 2700 × 6 = 16,200

We have the final answer as

16,200 m/s

Hope this helps you

A car accelerates at a constant rate of 3 m/s2 for 5 seconds. If it reaches a velocity of 27 m/s, what was its initial velocity?

A
15 m/s

B
42 m/s

C
12 m/s

D
2.1 m/s

Answers

The initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.

CALCULATE INITIAL VELOCITY:

The initial velocity of the car can be calculated by using one of the equation of motion as follows:

V = u + at

Where;

V = final velocity (m/s)u = initial velocity (m/s)a = acceleration due to gravity (m/s²)t = time (s)

According to this question, a car accelerates at a constant rate of 3 m/s² for 5 seconds. If it reaches a velocity of 27 m/s, its initial velocity is calculated as follows:

u = v - at

u = 27 - 3(5)

u = 27 - 15

u = 12m/s.

Therefore, the initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.

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Before a rifle is fired, the linear momentum of the bullet-rifle system is zero.

After the rifle is fired:

I. kinetic energy of the system is zero

II. linear momentum of the system is zero

Answers

Hi there!

II. Linear momentum of the system is zero.

This is an example of a RECOIL collision. With the Law of Conservation of Momentum, momentum remains constant before and after the collision.

Thus, the total momentum would also be equivalent to zero after the collision.

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Ellen held a substance that is comprised of elements that have been chemically joined. The substance now has different properties than the elements that were joined to make it. Ellen is most likely holding a a. compound b. water molecule c. single atom d. mixture Explain in detail what it means to synchronize computers and mobile devices and include at least two strategies for keeping your files in sync in your answers Which tools would you use to make chart 1 look like chart 2 in excel. Amy is adding two numbers. She got the answerwhich is 2003 However she copied the question wrong.The one's column of the first number should be 7. shewrote it to I. The hundred's columnofthe second numbershould be 2. she wrote it to 3. What is the correct ansuelif she copied it correctly? A "sentiment" is a feeling or belief. Based on the meaning of this word, what is wilsons message in this sentence?. If the sum of squares for a sample containing 51 items equals 200, what is the standard deviation?A) 1.98 B) 2.00 C) 3.92 D) 4.00 help pls !! i am confused1. 2. 3. 4. What is the least angle measure by which this figure can berotated so that it maps onto itself?O 45O 90 O 180O 360 either elements or compounds which are present prior to a chemical reaction if f(x)=2x^2+1 and g(x)= x^2-7 find (f-g)(x) Giveaways really soon!!! here is the second question 1. A roller coaster with a mass of 800 kg sits stationary at the top of a section of track, 75 m abovethe ground as shown. When the brake is released, it starts to roll down the track2. For each height represented in the diagram, calculate the gravitational potential energy usingEp = mgh. Show ONE SAMPLE calculation in the calculations section below and fill in Table 1 foreach of the heights of the roller coaster. (6 marks)3. Assuming there is no friction, determine the mechanical kinetic energy using Ek = Etotal - Ep.Show ONE SAMPLE calculation in the calculations section below and fill in Table 1 for each ofthe heights of the roller coaster. (6 marks)4. For each height represented in the diagram, calculate the velocity using = 2 . Show ONESAMPLE calculation in the calculations section below and fill in Table 1 for each of the heights ofthe roller coaster. (6 marks)5. Use your answers to graph how gravitational potential energy, mechanical kinetic energy, andvelocity change as the roller coaster changes height. Use different colours for the three lines onthe graph. Graph paper is provided below. (3 marks)6. Repeat steps 1 5 above for a roller coaster cart that has a mass of 300 kg and enter yourresults in Table 2.Calculations:800 kg roller coaster cart:Sample calculation for gravitational potential energy:Sample calculation for Mechanical kinetic energy:Sample calculation for velocity:300 kg roller coaster cart:Sample calculation for gravitational potential energy:Sample calculation for mechanical kinetic energy:Sample calculation for velocity:Results:Table 1: Potential energy, kinetic energy, total energy, and velocity of the 800 kg roller coaster cartTable 2: Potential energy, kinetic energy, total energy, velocity of the 300 kg roller coaster cart.Graphs:Its graphing time. These graphs are a bit different than the ones you did in thedata analysis assignment at the beginning of the course. In this case you havethree things to graph on each graph. (One graph for the 800 kg roller coaster cartand one graph for the 300 kg roller coaster cart.) You need to graph thegravitational potential energy with respect to height, the mechanical kineticenergy vs height, and the velocity vs height.Lets look at the energy graphs first. In this case both kinetic energy andmechanical energy cover the same range of values. This means they can use thesame scale on the y-axis. So, you will use the left y-axis and the x-axis to graphthe kinetic energy vs height and the potential energy vs height. You will need alegend to explain which line is which. Colour coding is a nice way to highlight this.The velocity values are much different than the energy values. This means youneed a totally different scale. So, your left y-axis wont work. You need to make asecond scale on the right y-axis for your velocity values. You will plot the pointsthe same way as normal, but you will use the numbers on the right-hand scaleinstead. Again, be sure to add your velocity line to the legend with a separatecolour code.Discussion Questions:1. Describe the relationship between the gravitational potential energy and the mechanical kineticenergy of the roller coaster on your graph. (2 marks)2. Describe the shapes of each of the three lines in the graph. Explain why the velocity is different.(4 marks)3. Describe how mass affects the speed at the bottom of the roller coaster. (2 marks)4. Describe how mass affects the gravitational potential energy and the mechanical kinetic energyof the roller coaster. (2 marks)5. At what point does the roller coaster have a maximum value for the following? Justify youranswer by explaining why. (2 marks each)a. Gravitational potential energyb. Mechanical energyc. Velocity6. In your calculations, you assumed that the roller coaster was frictionless. All real roller coastersencounter friction. Describe how the actual values of the variables would differ, or not differ,from your calculated values for a real roller coaster. 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