Replacing the single co-sinusoidal term with two or more terms of different frequencies will lead to a more complex motion of the oscillator, with multiple oscillations superimposed on each other.
The resulting motion may exhibit resonance or chaotic behavior, depending on the frequencies of the driving forces and the natural frequency of the oscillator. This occurs when the frequency of the driving force matches the natural frequency of the oscillator, leading to a large amplitude oscillation. Frequencies of the driving forces are not in resonance with the natural frequency of the oscillator, the resulting motion may be chaotic, with the oscillator undergoing complex oscillations of varying frequencies and amplitudes.
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select the accurate statements concerning membrane fluidity.
-The degree of membrane fluidity varies depending on the composition of the membrane. -Phospholipids are relatively free to move around laterally within the membrane. -Unanchored proteins are relatively free to move around laterally within the membrane.
All of the above given statements are true.
What is membrane?A membrane controls the flow of chemicals between two environments as a selectively permeable barrier. The cell membrane is the most well-known biological membrane.
a. The amount of membrane fluidity varies based on the membrane's make-up. This is because the fluidity of the membrane can be impacted by the lipid composition, particularly the length of fatty acid chains and degree of unsaturation of phospholipids.
b. Phospholipids can travel around the membrane's lateral space quite freely. This is so that individual phospholipids can migrate laterally inside the membrane's lipid bilayer structure.
c. Unanchored proteins can essentially travel wherever they choose in the membrane's lateral space. This is due to the ability of proteins to diffuse laterally within the lipid bilayer, independent of the cytoskeleton or other proteins in the membrane.
These conclusions accurately characterize the degree of fluidity within the membrane and how the ratio of lipids to proteins affects it.
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you are called to the scene of an overturned tanker truck. arriving at the scene, you notice a fluid draining from the underside of the truck. you use your binoculars to look on the placard on the back of the vehicle so that you can identify the material from your:
Northern American Emergency Response Guide.The main goal of the ERG Handbook is to help first responders immediately identify any unique or general risks associated with the material(s) at issue.
What does ERG guide 111 entail?There is also Guide 111, which is for "hazardous" materials.When using generic information, make sure to replace it with more detailed instructions as soon as new information becomes available.
What is the number on my ERG Guide?The orange panel next to the diamond-shaped sign or on the extremities and sides of the a cargo tank, vehicle, or rail car may also display the 4-digit ID Number.
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what do you notice about the momentum before and after of the red cart vs the momentum before and after of the blue cart?
However, in general, the law of conservation of momentum states that the total momentum of an isolated system remains constant if there are no external forces acting on the system. This means that the sum of the momenta before an event is equal to the sum of the momenta after the event.
What is the momentum ?
Momentum is the quantity of motion of a moving body, also known as its mass multiplied by its velocity. Momentum is a vector quantity, which means it has both a direction and a magnitude. Momentum is conserved in an isolated system. This means that the total momentum of a system remains constant as long as no external forces act on it. Momentum is an important concept in classical mechanics, as well as in modern physics. In everyday life, momentum can be seen in sports, such as a baseball thrown with a certain speed, or a car moving with a certain speed.
If the red and blue carts are part of an isolated system, their total momentum before the event would be equal to their total momentum after the event. Therefore, any change in the momentum of one cart must be compensated for by an equal and opposite change in the momentum of the other cart.
So, if one cart experiences an increase in momentum after the event, the other cart must experience a decrease in momentum of the same magnitude. Conversely, if one cart experiences a decrease in momentum, the other cart must experience an increase in momentum of the same magnitude.
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a car with initial velocity 30.0 m/s decelerates with constant acceleration -5.0 m/s2 until the car comes to a stop. how far does the car travel before it comes to rest?
The car travels 90m before it comes to rest.
Distance is the total movement of an object without any regard to direction. We can define distance as how much ground an object has covered despite its starting or ending point.
Velocity (v) is a vector quantity that measures displacement (or change in position, over the change in time.
Acceleration is defined as the rate of change of velocity with respect to time.
The initial velocity is 30.0 m/s.
The acceleration is [tex]-5.0\ m/s^2[/tex].
The car comes to a stop. Hence the final velocity is 0 m/s.
Using the third equation of motion,
[tex]v^2 - u^2=2as[/tex]
Substituting the values,
[tex]0^2 - 30^2=2(-5)s[/tex]
The value of s is 90m.
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Problem 1 A skydiver of mass 80.0 kg (including parachute) jumps off a plane and begins her descent. Ра Throughout this problem use 9.80 m/s² for the magnitude of the acceleration due to gravityAt the beginning of her fall does the skydiver have an acceleration?A) No, the skydiverfalls at a constant speed B) Yes and her acceleration is directed upward C) Yes and her acceleration is directed downward
At the start of her fall, the skydiver experiences an acceleration of 9.80 m/s2 in a downward direction. The correct response is option (C), which states that she is accelerating downward.
At the beginning of her fall, the skydiver has an acceleration, and her acceleration is directed downward.
The acceleration is caused by the force of gravity, which is proportional to the mass of the skydiver, and since the skydiver has a mass of 80.0 kg, the force of gravity on her is,
F_gravity = m * g
= (80.0 kg) * (9.80 m/s^2)
= 784 N
According to Newton's second law of motion, the acceleration of an object is proportional to the net force acting on it, and inversely proportional to its mass,
a = F_net / m
The net force,
F_net = F_gravity = (80.0 kg) * (9.80 m/s^2) = 784 N
a = F_net / m = 784 N / 80.0 kg = 9.80 m/s^2
Therefore, the skydiver has an acceleration of 9.80 m/s^2 directed downward at the beginning of her fall. Answer: (C) Yes and her acceleration is directed downward.
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how long does it take for an object to hit the ground falling 1.2 meters ar 5.3 m/s
It takes approximately 0.111 seconds for an object to fall .
Solving for how long does it take for an object to hit the ground:
The time it takes for an object to fall 1.2 meters at a velocity of 5.3 m/s can be calculated using the equation:
t = [tex]\sqrt{\frac{2 * d}{g} }[/tex]
where,
d = the distance fallen
g = the acceleration due to gravity
t = the time taken to fall that distance.
d = 1.2 meters
g = 9.8 m/s²
t= ?
Substituting in the numbers, we get:
t =[tex]\sqrt{\frac{ 2 * 1.2}{9.8\\ } }[/tex]
t = 0.111 seconds
Hence, it takes approximately 0.111 seconds for an object to fall 1.2 meters at 5.3 m/s.
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The volume of a monatomic ideal gas triples in an isothermal expansion. By what factor does its pressure change?
In an isothermal expansion, the pressure of a monatomic ideal gas increases by a factor of 1/3 (or 2/3).
What is ideal gas?A collection of presumptions about a gas's behavior defines, it as an ideal gas in theory. These hypotheses, which are based on experimental observations of actual gases, are helpful for comprehending and forecasting the behavior of gases under diverse circumstances.
The temperature of the gas doesn't change during an isothermal expansion. In the equation of state for an ideal gas, PV = nRT, where n is the number of moles, R is the universal gas constant, and T is the temperature, pressure and volume are connected.
The pressure of a monatomic ideal gas will change by a factor of 1/3(2/3) if its volume triples. This can be obtained by maintaining a constant temperature and changing the equation of state to P = (nRT) / V.
Since the pressure and volume are inversely related, the pressure will fall by a factor of 1/3 (or 2/3) if the volume triples.
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when making a lane change in front of a car, where should that car be in your mirrors? in the middle of your side mirror on the outside edge of your side mirror on the very edge of your rearview mirror toward the middle of your rearview mirror
When making a lane change in front of a car, the car should be toward the middle of your rearview mirror. Correct option is D.
Place the seat and steering wheel so that you can access the gear shifter, brake pedal, and accelerator while still feeling comfortable. Move the rearview mirror gently so that you can look straight out of the back windshield's centre without turning your head.
A straight, even reflection of the back window should be visible in the rearview mirror. Every 5 to 8 seconds, check your rearview mirror. You can keep track of who is approaching you, who has already past you, and who is acting erratically or dangerously close behind you by often checking your rearview mirror.
An adjustable reflecting device called a rearview mirror allows drivers to see the road, other cars, and things behind their vehicle.
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b The students investigating the speed of sound in gold declared that their
value of speed of sound in gold (from the graph in the task) is accurate
within a range of ±25 m/s. A reliable source of information gives the value
of speed of sound in gold as 3240 m/s. Are the results of the group of
students in agreement with the accepted value? Explain your answer.
Clap-echo technique With this technique, you time how long it takes you to hear an echo after a loud clap. You clap loudly when far away from a wall, then wait for the echo.
How do you calculate distance and sound speed?speed equals distance/time. A sound wave will cover a greater distance in the same amount of time as it moves quicker. The speed of a sound wave would be 350 m/s if it were noticed to cover 700 meters in 2 seconds.
The distance traveled is twice as far as the gap between you and the wall (because the sound has to travel to the wall and back).
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the side wall of a dam with width 70 m is a quarter circle with radius of 7 m. when the dam is full, calculate the hydrostatic force on the dam in n and its line of action.
The required hydrostatic force on the dam when width and the radius of the dam are given is calculated to be 31284956.29 N.
It is given that width of the dam is 70 m.
Radius of the circle is 7 m.
The height of the dam will be equal to the half of its radius.
h = r/2 = 7/2 = 3.5 m
Area is given by the formula, A = r ω
where,
ω is width
r is radius
Volume is given as, V = ω πr²/4
Horizontal force is given by, Fx = ρ g h A = 1000× 9.8× 7/2× 7× 70 = 16807000 N
Vertical force Fy = ρ g V = 1000 × 9.8 × 70 × π 7²/4 = 98× 7000× 49π /4 = 26386990 N
The resultant of vertical and horizontal force is nothing but the hydrostatic force.
F = √(Fx² + Fy²) = √(16807000² + 26386990²) = √(282475249000000+696273241260100) = 31284956.29 N
Thus, the hydrostatic force on the dam in N is calculated to be 31284956.29 N.
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Calculate the time it takes a 200 W appliance to transfer 40,000 J of energy
Explanation:
P=energy used/time taken
200=40000/t
200t=40000
divide both sides by 200
t=200s
[tex] power = \frac{workdone}{time \: taken} [/tex]
[tex] p = \frac{w}{t} [/tex]
200 = 40,000 / t
200t = 40,000
200t / 200 = 40,000 / 200
t = 200s
If you pull a pendulum with a mass of 7.4 kg back at an angle of 13°, what is the magnitude of the restoring force on it?
F=-mg sin is the net force operating on a basic pendulum bob of mass m. It is a force that restores.
What force is the restoring force in a straightforward pendulum in straightforward harmonic motion?A simple pendulum's restoring force is directed towards the mean position when it moves in a simple harmonic motion (lowest point). Here, the force of gravity acts as the restoring force at the centre of mass of the bob.
What is the pendulum motion equation?Pendulums are employed to control clock movement because the period—the amount of time between each full oscillation—is constant. The formula for a pendulum's period T is T = 2L/g squared.
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a 2.0- kg blob of play dough moving at 2 m/s slams into a 2.0- kg blob of play dough at rest. find the speed of the two stuck-together blobs immediately after colliding.
After hitting, the two putty blobs that were locked together moved at a speed of 1.5 metres per second.
Both before and after the contact, the momentum is preserved. In other words, the starting and end momentum values are equal.
Initial momentum is 6 kg/s (kg/s = 2 * 3 + 2 * 0).
Thus, the ultimate momentum is 6 kg/m/s.
Final body weight is 2 plus 2 kg.
Final body speed is calculated as final speed/final mass, which is 6/4 = 1.5 m/s.
Thus, 1.5 m/s was the speed of the two putty blobs that had just collided and were stuck together.
Speed is defined as the ratio of distance to the amount of time it took to cover that distance. Due to its lack of magnitude and merely having a direction, speed is a scalar number.
When an item travels an identical distance in a same amount of time, this is referred to as having uniform speed.
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What is your hypothesis (or hypotheses) for this experiment? (kinetic energy)
Kinetic energy of any object is always positive. This should be hypothesis for any experiment.
What is hypothesis?
A hypothesis is a theory put up to explain a phenomenon. A hypothesis must be testable according to the scientific method for it to be considered a scientific hypothesis.
Scientific hypotheses are typically based on prior observations that cannot be adequately explained by the current body of knowledge. Despite the frequent confusion between the terms "hypothesis" and "theory," a scientific hypothesis differs from a scientific theory.
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a ball is thrown horizontally from the roof of a building 45 m building and lands 105 m from the base od the building, what is the velocity just before it hits the ground
The velocity of the ball just before it hits the ground is 35 m/s.
What is velocity?
Velocity is a vector quantity that describes the rate of change of an object's position in a specific direction. It is defined as the derivative of an object's position with respect to time. Mathematically, velocity is expressed as:
v = Δx / Δt
The velocity of the ball just before it hits the ground can be calculated using the concept of projectile motion. In this case, we have two components of motion: horizontal and vertical. The horizontal component is constant and equal to the initial velocity, while the vertical component is affected by gravity and follows a parabolic path.
We can use the following equation to find the time it takes for the ball to fall from the roof to the ground:
h = vi * t + 0.5 * g * t²
where h is the height of the building (45 m), vi is the initial velocity (which we are trying to find), g is the acceleration due to gravity (9.8 m/s²), and t is the time it takes for the ball to fall.
Since the ball lands 105 m from the base of the building, we can also use the horizontal component of the motion to find the time:
d = vi * t
where d is the horizontal distance traveled by the ball (105 m).
We can equate these two equations to eliminate time and find the velocity of the ball:
h = vi * (d/vi) + 0.5 * g * (d/vi)²
45 = 105 + 0.5 * 9.8 * (d/vi)²
(d/vi)² = 2 * h / g = 2 * 45 / 9.8 = 9.18
d/vi = 3
vi = d / 3 = 105 / 3 = 35 m/s
So, the velocity of the ball just before it hits the ground is 35 m/s.
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when two metal spheres of radius r are placed in contact, they attract each other with a small gravitational force. if two spheres of the same metal that have twice the radius were placed in contact, they would attract each other with a stronger gravitational force. how much stronger?
The gravitational force between two spheres with twice the radius would be 4 times stronger.
The strength of the gravitational force between two masses is proportional to the product of their masses and inversely proportional to the square of the distance between them.
In this scenario, the mass of the spheres increases with the cube of their radius, while the distance between their centers decreases with the increase in radius.
Hence, when the radius of the spheres is doubled, the mass of each sphere increases by a factor of 8 and the distance between their centers decreases by a factor of 2, resulting in a net increase in gravitational force by a factor of 4.
The formula for the gravitational force between two point masses is given by:
F = G × (m1 × m2) / r²
Where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the two spheres, and r is the distance between their centers.
If we have two spheres with radius r, their masses are given by:
m1 = m2 = (4/3) × π × r³ × ρ
Where ρ is the density of the metal. When the radius of the spheres is doubled, their masses become:
m1' = m2' = (4/3) × π × (2r)³ × ρ = 8 × (4/3) × π × r³ × ρ
And the distance between their centers is halved:
r' = r/2
Substituting these values into the equation for gravitational force, we get:
F' = G × (m1' × m2') / r'²
F' = G × (8 × (4/3) × π × r³ × ρ)² / (r/2)²
F' = 4 × G × (4/3) × π × r³ × ρ × (4/3) × π × r³ × ρ / r²
F' = 4 × F
So the gravitational force between the spheres with twice the radius is 4 times stronger than the force between the spheres with the original radius.
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a box is being pushed across the floor by a constant force the coeficient of kinetic friction is at time what is the new velocity and position
The velocity and position of a box being pushed across the floor by a constant force with a coefficient of kinetic friction are determined by Newton's second law of motion, which states that the force acting on an object is equal to its mass times its acceleration.
In this scenario, the applied force, friction force, and mass of the box all play a role in determining its velocity and position.
The applied force is the force being applied to the box to move it across the floor. The frictional force, which acts in the opposite direction to the applied force, is proportional to the normal force and the coefficient of kinetic friction. The normal force is the force exerted by the floor on the box, perpendicular to the floor.As the box is pushed, it will eventually reach a velocity at which the frictional force is equal in magnitude to the applied force, and the net force on the box will be zero. At this point, the box will move at a constant velocity, as it is no longer accelerating. The position of the box will be dependent on the initial velocity, the applied force, and the time elapsed.
Overall, the velocity and position of a box being pushed across the floor by a constant force with a coefficient of kinetic friction are interrelated and determined by the balance of forces acting on the object.
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What is the relationship between the velocity and position of a box being pushed across the floor by a constant force with a coefficient of kinetic friction?
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the difference in point of view that occurs when the lens (or other device) through which the eye views a scene is separate from the lens that exposes the film is called
The difference in point of view that occurs when the lens (or other device) through which the eye views a scene is separate from the lens that exposes the film is called the parallax effect.
What is parallax effect?Parallax effect is an interactive technique used by web developers to create a visually engaging experience for users. It works by having the background move at a slower speed than the foreground when the user scrolls down the page. This creates an illusion of depth, as if the user is looking into the scene from different angles. The effect is especially popular for creating immersive experiences such as 3D games, virtual tours, and interactive storytelling. Parallax effect can be used to bring websites to life, offering users an engaging and dynamic experience. It is also a great tool for storytelling, helping to convey emotion and create a unique visual experience.
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if i double the length, and halve the radius of a copper wire, what is the value of its new resistance? original resistance was r0
The new resistance of the copper after doubling the length and reducing the radius will be 8 times of the original resistance.
Resistance can be defined as the property of the conductor which opposes the flow of electric current. Resistance is also defined as the ratio of the voltage applied to the electric current flowing through the circuit.
R = ρl/ A
where, R is the electric circuit,
ρ is the resistivity or specific resistance,
l is the length of the wire,
A is the cross-sectional area of the wire.
If we double the length of copper wire and reduce the radius to half. Then, the new resistance will be:
R = ρl/ A
l' = 2l
r' = r/2
A = πr²
A' = π(r/2)²
A' = πr²/4
R' = new resistance,
R' = ρ ×2l/ πr²/4
R' = 4 × ρ ×2l/ πr²
R' = 8ρl/ A
Therefore, the new resistance will be 8 times of the original resistance.
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Four 2. 0-µC point are at the corners of a rectangle with sides of length 3. 0 cm and 4. 0 cm. What is the electric potential (relative to infinity) at the midpoint of the rectangle? (k = 1/4πε0 = 9. 0 × 109 N ∙ m2/C2)
The electric potential at the midpoint of the rectangle is 3440 V relative to infinity.
How close to infinity is electric potential?
Whenever a charge Q is infinitely far away from another charge, the electric potential is deemed to be 0. The resultant electric field is zero at P, the halfway between two identical charges.
To find the electric potential at the midpoint of the rectangle, we need to calculate the electric potential due to each of the four point charges, and then add them up. The electric potential at a point is given by the equation:
[tex]\mathrm{V = k \times q / r}[/tex]
where V is the electric potential, k is Coulomb's constant (1/4πε0), q is the charge, and r is the distance from the point charge to the point where we want to calculate the potential.
Let's assume that the rectangle lies in the x-y plane, with one corner at the origin. We can label the other corners as A, B, and C, where AB is parallel to the x-axis and BC is parallel to the y-axis.
The distance from the midpoint of AB to each of the four point charges is given by:
[tex]\mathrm{r_1 = r_3 = \sqrt{(1.5 cm)^2 + (2 cm)^2}= 2.5 cm}[/tex]
[tex]\mathrm{r_2 = r_4 = \sqrt{(1.5 cm)^2 + (1 cm)^2}= 1.8 cm}[/tex]
The electric potential due to each of the point charges at the midpoint of AB is given by:
[tex]\mathrm{V_1 = k \times q / r_1 = (9.0 \times 10^9 N \cdot m^2/C^2) \times (2.0 \times 10^{-6} C) / (2.5 \times 10^{-2} m) = 720 V}[/tex]
[tex]\mathrm{V_2 = k \times q / r_1 = (9.0 \times 10^9 N \cdot m^2/C^2) \times (2.0 \times 10^{-6} C) / (1.8 \times 10^{-2} m) = 100V}[/tex] = 1000 V
[tex]\mathrm{ V_3 =k \times q / r_3 = 720 V}[/tex]
[tex]\mathrm{ V_4 =k \times q / r_4 = 1000V}[/tex]
The total electric potential at the midpoint of AB is the sum of these four potentials:
[tex]\mathbf{V_{total} }[/tex] = V1 + V2 + V3 + V4
= 720 V + 1000 V + 720 V + 1000 V
= 3440 V
Therefore, the electric potential at the midpoint of the rectangle is 3440 V relative to infinity.
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Two parents, both heterozygous (Tt) and tall, are crossed to produce offspring. What are the possible genotypes and phenotypes of the offspring? What is the percentage chance of being homozygous?
Answer:
Look below
Explanation:
The possible genotypes of the offspring are: TT, Tt, and tt.
The possible phenotypes of the offspring are: tall and short.
The percentage chance of being homozygous can be calculated using a Punnett square. When the heterozygous parents are crossed, the possible genotypes of the offspring are:
| T | t
--|---|---
T | TT| Tt
t | Tt| tt
From the Punnett square, we can see that there is a 25% chance of the offspring being homozygous (TT or tt). This is because there are four possible outcomes and two of them result in a homozygous genotype (TT and tt).
A student pulls on a cart and applies a 20N force at an angle of 25 degrees above the horizontal to move a crate a distance of 10m across a rough floor that creates a frictional force of 2N. (A) Draw a FBD (B) How much work does the student do? (C) What is the total work done? (D) If the cart starts at rest how fast is it going after 10m?
how far (in cm) from a piece of paper must you hold your father's 1.80 d reading glasses to try to burn a hole in the paper with sunlight?
To burn a hole in a piece of paper with sunlight using your father's 1.80 D reading glasses, you must hold the glasses about 6 cm away from the paper.
This is because the glasses will act as a magnifying lens, and the focal length of the lens is determined by the diopter number (1.80 in this case). The focal length of a 1.80 D lens is approximately 6 cm.
The focal length of a lens is the distance between the lens and the image sensor when the subject is in focus, usually stated in millimeters (e.g., 28 mm, 50 mm). The focal length determines the angle of view of the lens, and thus how much of the scene will be captured when the image is taken.
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Can we see a source of light through a bent tube? Explain your your answer
Because a curved tube is not an homogeneous medium, we cannot perceive a light source through it. Hence the tube should have a straight, homogeneous medium so that the source of the light can be seen.
What does light mean in the Bible?Light has always represented righteousness, kindness, wisdom, understanding, grace, hope, and the revelation of God in the Bible. On the other side, darkness has been associated with sin, evil, and hopelessness.
What exactly is God's light?Aspects of the divine presence that are felt as light in theophany or visions, or that are depicted as such in allegorical or metaphor, are referred to as divine light in theology.
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A man standing on a lift throws a ball upwards with the maximum initial velocity he can and is found to be equal to 55 m/s. After what time the ball returns to his hand if (a) the lift is stationary, (b) the lift is moving up with a uniform velocity of 7 m/s, (c)the lift is moving down with a velocity of 7 m/s. Also given g = 9.8 m/s2
what is the relationship between the voltage across a resistor and capacitor when the resistor and capacitor are in series and are powered by a voltage source
The voltage across the resistor and capacitor will be the same. This is because the voltage source is supplying the same voltage to both components, and since the same amount of current is passing .
What is the voltage ?Voltage is a measure of electrical potential energy per unit charge. It is measured in volts (V). Voltage is an important factor in the functioning of electric circuits. It determines the amount of current that will flow in a circuit. A higher voltage will cause more current to flow through the circuit, while a lower voltage will cause less current to flow. Voltage is also related to power, as the electrical power is equal to the product of the voltage and current. the same amount of current is passing through both components, the voltage drop across each component must be equal.
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A ray of light is incident on a right angled prism of refractive index 1,5 , calculate the angle of refraction of the ray within the prism
The angle of refraction of the ray within the prism is 1.3
What is angle of refraction?The angle of refraction is described as the angle between a refracted ray and the normal drawn at the point of incidence to the interface at which refraction occurs.
Given, μ=refractive index of liquid.
The angle of incidence, i = 60 °
internal reflection , angle of refraction r = 90 °
Now,
sinr/ sini = μ / μ1
sin60° = μ/ 1.5
μ= √3 / 2 x 1.5
μ=1.3
in conclusion, the angle of refraction is the measurable quantity that indicates the amount of refraction taking place at any boundary.
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Complete question:
ACB is a right-angled glass prism with refractive index 1.5. Angle A, B, C are 60
∘
,30
∘
and 90
∘
respectively. A thin layer of liquid is on the AB. For a ray of light which is incident normally on AC to ;be totally reflected at AB, the refractive index of the liquid on AB should be
What is the gauge pressure of the water right at the point p, where the needle meets the wider chamber of the syringe? neglect the pressure difference caused by the radius change?
The gauge pressure at point P, which has a zero-reference against the atmospheric pressure, is 3200 Pa. The needle meets the wider chamber of the syringe at the end of the needle.
Using Poiseuille's law, we can resolve the exercise. In a closed pipe, it states that for a fluid in laminar flow.
The equation:
ΔP = 8μLQ / 4r⁴
Where,
μ = viscosity of the fluid
L = length of the pipe
r = radius
Q = Av
= πr²v
= (3.14 x 10⁻³) (10)
= (3.14 x 10⁻⁵)
Hence, the gauge pressure:
ΔP = 8 (0.001) (4 cm) (3.14 x 10⁻⁵)) / 4 (0.001 m)⁴
= 3200 Pa
So, the gauge pressure of the water at point P is 3200 Pa.
And, the needle meets the wider chamber of the syringe at the end of the needle.
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the thicknesses are h1 5 0.5 mm and h2 5 0.3 mm, respectively. find the force f to make the upper plate move at a speed of 1 m/s. what is the fluid velocity at the interface between the two fluids?
The upper plate must move with a force of 143 N in order to move at a speed of 1 m/s. The two fluids' contact has a fluid velocity of 0.714 m/s.
What is the pipe's fluid velocity?Pipe velocity is an area averaged attribute that is unaffected by the cross-sectional flow pattern or laminarity of the flow in the pipe. For instance, fluid may be moving twice as fast down the center axis as predicted by the pipe velocity.
Fluid Velocity
We are given fluid viscosities as;
₁ = 0.1 N.s/m²
₂ = 0.15 N.s/m²
Thicknesses of plates are;
h₁ = 0.5 mm and h₂ = 0.3 mm
Since the shear stress is constant throughout,
τ = ₁(du₁/dy₁) = ₂(du₂/dy₂)
⇒ ₁(Ui/h₁) = ₂(U - Ui)/h₂
where Ui is the interface speed and U is the upper body's movement speed, we have;
Ui = U/(1 + (₁/₂)*(h₂/h₁))
⇒ Ui = 1/(1 + (0.1/0.15)*(0.3/0.5))
⇒ Ui = 0.714 m/s
Force required is;
F = ₁ * (Ui/h₁) * (A)
We are given A = 1 m²
Thus;
F = 0.1 * (0.714/0.0005) * 1
F ≈ 143 N
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Question:
Luids of viscosities 1 =0.1 N.s/ms and 2 =0.15 N.s/m2 are contained between two plates (each plate 1
m2 area). The thicknesses are h1=.5 mm and h2=0.3 mm, respectively. Find the force F to make the upper
plate move at a speed of 1 m/s. What is the fluid velocity at the interface between the two fluids?
how much more time (in terms of t1) does it take the ladybug to get back to its starting point from the place where it reverses its acceleration?
[tex]T_{1}+\sqrt{2 }T_{1}[/tex] is the time (in terms of [tex]T_{1}[/tex]) does it take the ladybug to get back to its starting point from the place where it reverses its acceleration
The following is a roughly formula-free, Physics-focused solution. The velocity continues to move incorrectly even when the acceleration [tex]T_{1}[/tex]changes. By symmetry, the ladybug is at rest after an additional period and is twice as far from its starting point as it was before it applied the brakes.
As a result, it must now go twice as far. Under constant acceleration, the distance traveled is proportional to the square of the time. Consequently, the amount of time needed to return to the starting location from the farthest point reached is 2–[tex]\sqrt{T_{1} }[/tex]. Total time from the time the acceleration reversed is therefore [tex]T_{1}+\sqrt{2 }T_{1}[/tex].
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