Answer:
[tex]\displaystyle y' = -5(3x-1)^4(4 - x^4)^4(15x^4 - 4x^3 - 12)[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightDistributive Property
Algebra I
Terms/CoefficientsFactoringCalculus
Derivatives
Derivative Notation
Derivative of a constant is 0
Basic Power Rule:
f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹Derivative Rule [Product Rule]: [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]
Derivative Rule [Chain Rule]: [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]
Step-by-step explanation:
Step 1: Define
Identify
y = (3x - 1)⁵(4 - x⁴)⁵
Step 2: Differentiate
Product Rule: [tex]\displaystyle y' = \frac{d}{dx}[(3x - 1)^5](4 - x^4)^5 + (3x - 1)^5\frac{d}{dx}[(4 - x^4)^5][/tex]Chain Rule [Basic Power Rule]: [tex]\displaystyle y' =[5(3x - 1)^{5-1} \cdot \frac{d}{dx}[3x - 1]](4 - x^4)^5 + (3x - 1)^5[5(4 - x^4)^{5-1} \cdot \frac{d}{dx}[(4 - x^4)]][/tex]Simplify: [tex]\displaystyle y' =[5(3x - 1)^4 \cdot \frac{d}{dx}[3x - 1]](4 - x^4)^5 + (3x - 1)^5[5(4 - x^4)^4 \cdot \frac{d}{dx}[(4 - x^4)]][/tex]Basic Power Rule: [tex]\displaystyle y' =[5(3x - 1)^4 \cdot 3x^{1 - 1}](4 - x^4)^5 + (3x - 1)^5[5(4 - x^4)^4 \cdot -4x^{4-1}][/tex]Simplify: [tex]\displaystyle y' =[5(3x - 1)^4 \cdot 3](4 - x^4)^5 + (3x - 1)^5[5(4 - x^4)^4 \cdot -4x^3][/tex]Multiply: [tex]\displaystyle y' = 15(3x - 1)^4(4 - x^4)^5 - 20x^3(3x - 1)^5(4 - x^4)^4[/tex]Factor: [tex]\displaystyle y' = 5(3x-1)^4(4 - x^4)^4\bigg[ 3(4 - x^4) - 4x^3(3x - 1) \bigg][/tex][Distributive Property] Distribute 3: [tex]\displaystyle y' = 5(3x-1)^4(4 - x^4)^4\bigg[ 12 - 3x^4 - 4x^3(3x - 1) \bigg][/tex][Distributive Property] Distribute -4x³: [tex]\displaystyle y' = 5(3x-1)^4(4 - x^4)^4\bigg[ 12 - 3x^4 - 12x^4 + 4x^3 \bigg][/tex][Brackets] Combine like terms: [tex]\displaystyle y' = 5(3x-1)^4(4 - x^4)^4(-15x^4 + 4x^3 + 12)[/tex]Factor: [tex]\displaystyle y' = -5(3x-1)^4(4 - x^4)^4(15x^4 - 4x^3 - 12)[/tex]Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Derivatives
Book: College Calculus 10e
\lim _{x\to 0}\left(\frac{\sqrt{1+3x+x^2}-1}{\arcsin \left(2x\right)}\right)
Step-by-step explanation:
[tex]\displaystyle \lim_{x \to 0} \left(\dfrac{\sqrt{x^2 + 3x + 1} - 1}{\arcsin 2x} \right)[/tex]
Note that as [tex]x \rightarrow 0[/tex], the ratio becomes undefined. Using L'Hopital's Rule, where
[tex]\displaystyle \lim_{x \to c} \dfrac{f(x)}{g(x)} = \lim_{x \to c} \dfrac{f'(x)}{g'(x)} [/tex]
where f'(x) and g'(x) are the derivatives of the functions f(x) and g(x), respectively. Note that
[tex]f(x) = \sqrt{x^2 + 3x + 1} \:\:\text{and}\:\: g(x) = \arcsin 2x[/tex]
[tex]f'(x) = \dfrac{2x + 3}{2(\sqrt{x^2 + 3x + 1})}[/tex]
[tex]g'(x) = \dfrac{2}{\sqrt{1 - 4x^2}}[/tex]
Therefore,
[tex]\displaystyle \lim_{x \to 0} \dfrac{f'(x)}{g'(x)} = \lim_{x \to 0} \dfrac{2x + 3}{2(\sqrt{x^2 + 3x + 1})} \times \left(\dfrac{\sqrt{1 - 4x^2}}{2} \right)[/tex]
or
[tex]\displaystyle \lim_{x \to 0} \left(\dfrac{\sqrt{x^2 + 3x + 1} - 1}{\arcsin 2x} \right) = \dfrac{3}{4}[/tex]
HELP ME PLSSSSSS
if f(x) = 2x-3/5 , which of the following is the inverse of f(x)?
Alejandro used a mathematical property to create two equivalent expressions.
6(x + 2) = 6x + 30
Which of the following is the missing term?
O 24
Х
O 5x
6
5
A pen costs $2 and a ruler costs 50 cents. Write down an expression in dollar for the cost of p pen and r ruler.
Answer:
.50r + 2p
Step-by-step explanation:
cost of ruler * number of rules + cost of pens * number of pens
.50 *r + 2 *p
.50r + 2p
Which rules of exponents will be used to evallate this expression? Select three options.
Chester has less than $25 to spend at the county fair. The entrance fee is $5, and each ride costs $3. The number of rides, r, that Chester can go on is represented by the inequality 3r + 5 < 25. Select the most amount of rides Chester can go on without overspending
Answer:
6 rides
Step-by-step explanation:
3r+5<25
3r<20
r<6.67
rides=6
check answer
3r+5<25
3(6)+5<25
18+5<25
23<25
Find the Value of x
Answer:
42
Step-by-step explanation:
(adjacent straight angles sum up to 180)
3x+54=180
x=42
find the quotient of 8 divided by one-third, multiply 8 by
A:1/8
B:1/3
C:3
D:8
are the possible answers
Answer:
find the quotient of 8 divided by one-third, multiply 8 by
A:1/8
B:1/3( true
C:3
D:8
are the possible answers
WILL MARK YOU IF YOU HELP ME !!!!
Answer:
Perpendicular bisector
Answer:
perpendicular bisector
Hallar la ecuación de la recta (2,3) y (1,-2)
Answer:
[tex]y=5x-7[/tex]
Step-by-step explanation:
evaluate the given expression if w= 17, x= 29, and a =8 w+(1/x)+(1/z) a. 17.18 b.8.11 c. 94.13 d. 46.15
Answer:
a. 17.18
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightStep-by-step explanation:
Step 1: Define
Identify
w = 17
x = 29
z = 8
w + (1/x) + (1/z)
Step 2: Evaluate
Substitute in variables: 17 + (1/29) + (1/8)Add: 3981/232Divide: 17.1595PLEASE HELP!
Determine which of the following lists is in order from smallest to largest.
1. -3,131,0, (-3)^2
2. (-3)^2,-3,0, |3|
3. -3,0,|3|, (-3)^2
4. 0,-3,|3|, (-3)^2
Answer:
3. -3,0,|3|, (-3)^2
Step-by-step explanation:
Answer:
answer would be option 3
Step-by-step explanation:
help this helps
A small town experienced an explosive population increase Originally the town had population 170 within 3 years the town's population increased by 400% what is the town current population
Answer:
Step-by-step explanation:
We need to first find out how much 400% of 170 is and then add that increase to the original 170 people.
4(170) = 680 and
680 + 170 = 850 people after 3 years.
Consider the following sets of sample data: A: $30,500, $27,500, $31,200, $24,000, $27,100, $28,600, $39,100, $36,900, $35,000, $21,400, $37,900, $27,900, $18,700, $33,100 B: 4.29, 4.88, 4.34, 4.17, 4.52, 4.80, 3.28, 3.79, 4.84, 4.77, 3.11 Step 1 of 2 : For each of the above sets of sample data, calculate the coefficient of variation, CV. Round to one decimal place.
Answer:
[tex]CV=0.2[/tex] ---- dataset 1
[tex]CV = 7.2[/tex] --- dataset 2
Step-by-step explanation:
Given
[tex]A: 30500, 27500, 31200, 24000, 27100,28600, 39100, 36900, 35000, 21400, 37900, 27900, 18700,[/tex][tex]33100[/tex]
[tex]B: 4.29, 4.88, 4.34, 4.17, 4.52, 4.80, 3.28, 3.79, 4.84, 4.77, 3.11[/tex]
Required
The coefficient of variation of each
Dataset A
Calculate the mean
[tex]\mu = \frac{\sum x}{n}[/tex]
[tex]\mu = \frac{30500+ 27500+31200+24000+ 27100+28600+ 39100+ 36900+ 35000+ 21400+ 37900+ 27900+ 18700+33100}{14}[/tex][tex]\mu = \frac{418900}{14}[/tex]
[tex]\mu = 29921.43[/tex]
Next, calculate the standard deviation using:
[tex]\sigma = \sqrt{\frac{\sum(x - \mu)^2}{n}}[/tex]
So, we have:
[tex]\sigma= \sqrt{\frac{(30500 - 29921.43)^2 +.................+ (18700- 29921.43)^2 + (33100- 29921.43)^2}{13}}[/tex]
[tex]\sigma= \sqrt{\frac{487723571.42857}{14}}[/tex]
[tex]\sigma= \sqrt{34837397.959184}[/tex]
[tex]\sigma= 5902.32[/tex]
So, the coefficient of variation is:
[tex]CV=\frac{\sigma}{\mu}[/tex]
[tex]CV=\frac{5902.32}{29921.43}[/tex]
[tex]CV=0.2[/tex] --- approximated
Dataset B
Calculate the mean
[tex]\mu = \frac{\sum x}{n}[/tex]
[tex]\mu = \frac{4.29+ 4.88+ 4.34+ 4.17+ 4.52+ 4.80+ 3.28+ 3.79+ 4.84+ 4.77+ 3.11}{11}[/tex]
[tex]\mu = \frac{46.79}{11}[/tex]
[tex]\mu = 4.25[/tex]
Next, calculate the standard deviation using:
[tex]\sigma = \sqrt{\frac{\sum(x - \mu)^2}{n}}[/tex]
[tex]\sigma = \sqrt{\frac{(4.29 - 4.25)^2 + (4.88- 4.25)^2 +.........+ (3.11- 4.25)^2}{11}}[/tex]
[tex]\sigma = \sqrt{\frac{3.859}{11}}[/tex]
[tex]\sigma = \sqrt{0.35081818181}[/tex]
[tex]\sigma = 0.593[/tex]
So, the coefficient of variation is:
[tex]CV=\frac{\sigma}{\mu}[/tex]
[tex]CV = \frac{4.25}{0.5903}[/tex]
[tex]CV = 7.2[/tex] -- approximated
Two parallel lines, e and f, are crossed by two transversals.
What is the measure of <15
m<15 = 77°
m< 15 = 83°
m<15 = 93°
m<15= 97°
9514 1404 393
Answer:
∠15 = 97°
Step-by-step explanation:
At any given transversal of parallel lines, all obtuse angles are congruent, and all acute angles are congruent. Obtuse angle 15 is congruent to the one market 97°.
∠15 = 97°
For the equation, complete the solution. 7x + y = −18
Answer:
x= - 18/7 - 1/7y, y
or if you are solving for y= -18-7x, x
( SEE OTHER IMAGE)
Step-by-step explanation:
See image below:)
Answer:
[tex]x= \frac{- 18 - y }{7}[/tex]
y = - 18 - 7x
Step-by-step explanation:
7x + y = - 18
7x + y - y = - 18 - y
7x = - 18 - y
[tex]\frac{7x}{7}= \frac{- 18 - y }{7}[/tex]
[tex]x= \frac{- 18 - y }{7}[/tex]
7x + y = - 18
7x - 7x + y = - 18 - 7x
y = - 18 - 7x
199 rounded up to the nearest hundred
Answer:
199
Step-by-step explanation:
Answer:
It would be 200 because 199 is closer to 200 rather than 100.
A right triangle has side lengths 7, 24, and 25 as shown below. Use these lengths to find cos B, tanB, and sin B.
Answer:
cosB = 7/25 = 0,28
tanB = 24/7 = 3,428571429
sinB = 24/25 = 0,96
Find the area of the sector in
terms of pi.
120°
24
Area = [?] π
Enter
Bonjour, connaissez vous une app ou on peut manipuler des elastiques j'en ai besoin. Merci!
Answer:
Wow sup Comment allez-vous, je suis là pour vous aider à essayer cette application, je ne suis pas vraiment sûr de ce que vous entendez par " Rubber Band App " Mais je pense que cela pourrait aider à l'essayer Exercices de bande de résistance
What is the median of the following set of numbers?
1 5
12 1 121
1
121
13
O A. 27
ОВ.
COIN
OC. .
12
OD.
1 5
12 1 121
1
121
13
O A. 27
ОВ.
COIN
OC. .
12
OD. ????????????????
Median of the given data is 8.5.
What is median?In statistics, the median is the middle value of the given list of data in order. Data or observations can be sorted in ascending or descending order.
Given data,
1 , 5, 12, 1, 121, 1, 121, 13
Arranging in ascending order
1, 1, 1, 5, 12, 13, 121, 121
Number of elements N = 8
When number of elements is odd
Median = (N/2 th term + (N/2)+1 th term)/2
Median = (8/2 th term + (8/2)+1 th term)/2
Median = (4th term + 5th term)/2
Median = (5+12)/2
Median = 17/2
Median = 8.5
Hence, 8.5 is the median of the given data.
Learn more about median here:
https://brainly.com/question/28060453
#SPJ7
HW HELP ASAP PLZZZZZ
Answer:
ur ans is here...
Express in roster form. Set of B is the set of all elements x such that x is an element of natural numbers and x is a multiple of 8
=========================================================
Explanation:
The set of natural numbers is {1,2,3,...} basically anything positive and a whole number.
Any multiple of 8 is of the form 8x. Since x is a natural number, the smallest it can be is x = 1 which corresponds to 8x = 8*1 = 8. So 8 is the first multiple of the set. Then 16 is next because 8x = 8*2 = 16, and so on.
That's how we end up with {8, 16, 24, 32, ...}
The three dots, or ellipses, tell the reader that the pattern goes on forever. This set is infinitely large. We wouldn't stop at 800 because we could plug in say x = 200 to get 8x = 8*200 = 1600 and that's a multiple of 8.
A searchlight is shaped like a parabola. If the light source is located 3 feet from the base along the axis of symmetry and the depth of the searchlight is 4 feet, what should the width of the opening of the searchlight be?
9514 1404 393
Answer:
8√3 ≈ 13.86 ft
Step-by-step explanation:
The light source is usually placed at the focus, so the focus-vertex distance is p=3 ft. The equation for the parabola with its vertex at the origin is ...
y = 1/(4p)x^2
y = 1/12x^2
The opening for some y-value extends ±x from the axis of symmetry, so is a total of 2x in width.
For y=4, the corresponding value of x is ...
4 = 1/12x^2
48 = x^2
√48 = x = 4√3
Then the width of the searchlight opening is ...
2(4√3 ft) = 8√3 ft ≈ 13.86 ft
an isosceles triangle has one angel that measure 30 degree what is the measure of the other two angles that are equal?
Software Solution (SOS) helps subscribers solve software problems. All transactions are made over the telephone. For the year 2018, 10 engineers, most of whom are recent graduates, handled 119,000 calls. The average yearly salary for software engineers was $58,000. Starting in 2019, the firm retained and hired only software engineers with at least 2 years of experience. SOS raised the engineers’ salary to $73,000 per year. In 2019, eight engineers handled 127,000 calls.
Required:
1. Calculate the partial operational productivity ratio for both years.
2. Calculate the partial financial productivity ratio for both years. (Round your answers to 4 decimal places.)
Answer:
a. 11900, 15875
b. 0.2052, 0.2175
Step-by-step explanation:
number of engineers in 2018 = 10
calls handled in 2018 = 119000
average salary in 2018 = 58000
number of engineers in 2019 = 8
calls handled = 127000
salary = 73000
a.) operational productivity = output/input
in year 2018 = 119000/10= 11900
in year 2019 = 127000/8 = 15875
b.) ratio for both years = output/amount spent
in year 2018 = 119000/10*58000 = 0.2052
in year 2019 = 127000/8*73000 = 0.2175
Derek sold her house for $541,600, which was 140% of the amount she paid for it.
Calculate the amount she paid for the property.
9514 1404 393
Answer:
$386,857.14
Step-by-step explanation:
You have ...
sold = 140% × paid
Dividing by 140% gives ...
paid = sold/1.40 = $541,500/1.40 = $386,857.14
Derek paid $386,857.14 for the property.
For what value of x is the rational expression below equal to zero?
20+2x
5-x
O A. -10
O B. -5
C. 10
O D. 5
Answer:
A.-10 should be the answer to the question..
The rational expression is zero at x = -10.
What is rational expression?The ratio of two polynomials is known as a rational expression.
The given rational expression can equate to zero
[tex]\frac{20+2X}{5-X} =0[/tex]
Then, 20+2x=0
Therefore, x = (-20/2) = -10.
At x = -10, the given rational expression is zero.
To learn more about rational expression, use the link given below:
https://brainly.com/question/19585906
#SPJ2
WILL MARL BRAINLIEST IF YOU HELP
Answer:
C.
Step-by-step explanation:
In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side.
A.
9 + 9 = 18
18 < 22
No triangle
B.
7 + 3 = 10
10 = 10
No triangle
C.
5 + 6 = 11 and 11 > 9 good
5 + 9 = 14 and 14 > 6 good
9 + 6 = 15 and 15 > 5 good
There is a triangle.
Answer: C.
A study was done on the batting averages for two baseball players: Hitmore and Bunter. Data were collected over a period of time for baseball parks that are natural and artificial turf. It was found that Hitmore does better overall (.e., has a better batting average). However, for both natural and artificial turf separately, Bunter does better. Which of the following is correct?
This is an example of a negative association between variables.
This is an example of Simpson's Paradox.
"Turf" is a lurking variable in this example
Both (B) and (C) are correct
This situation is mathematically impossible
Answer:
Both (B) and (C) are correct
Step-by-step explanation:
Explaining in simple terms, The Simpson's paradox simply describes a phenomenon which occurs when observable trends in a relationship, which are obvious during singular evaluation of the variables disappears when each of this relationships are combined. This is what played out when hitmire appears to d well on both of natyraknamd artificial turf when separately compared, but isn't the same when the turf data was combined. Also, performance may actually not be related to the turf as turf may Just be. a lurking variable causing a spurious association in performance.