Determine whether the series is convergent or divergent.
[infinity] 9
en+
3
n(n + 1)
n = 1
convergentdivergent

Answers

Answer 1

The given series is divergent.

We can determine the convergence or divergence of the given series using the nth term test. According to this test, if the nth term of a series does not approach zero as n approaches infinity, then the series is divergent.

Here, the nth term of the series is given by 9e^(n+3)/(n(n+1)). We can simplify this expression by using the fact that e^(n+3) = e^3 * e^n. Therefore, we have:

9e^(n+3)/(n(n+1)) = 9e^3 * (e^n / n(n+1))

As n approaches infinity, the term e^n grows faster than n(n+1). Therefore, the expression e^n / n(n+1) does not approach zero, and the nth term of the series does not approach zero either. Thus, by the nth term test, the series is divergent.

Therefore, the given series is divergent.

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Step-by-step explanation:

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