Answer:
Todas son correctas
Explanation:
I) Los compuestos del carbono son solubles en disolventes no polares como el hexano, benceno, éter, etc. VERDADERO. La mayoría de los compuestos de carbono son apolares, y basados en la regla: Similar disuelve similar, podemos presumir que la mayoría de compuestos de carbono se disuelven en solventes no polares.
II) Los compuestos del carbono generalmente presentan puntos de fusión y de ebullición bajos. VERDADERO. Al ser sustancias apolares, sus fuerzas electrostáticas son bajas. De la misma manera, como su masa atómica es pequeña, las fuerzas de Van der Waals son despreciables haciendo que sus puntos de fusión y ebullición sean bajos respecto a sustancias de estrucutra similar.
III) La gran mayoría de los compuestos del carbono son combustibles, sean estos, gaseosos, líquidos o sólidos. VERDADERO. Los gases (Como el gas natural) son combustibles usados para cocina. Los líquidos (Como la gasolina) son combustibles y bastante inflamables. Los sólidos (Como la madera) se usan como combustibles para hacer asados o son el combustible en incendios forestales.
IV) El enlace covalente es característico de los compuestos del carbono. VERDADERO. La polaridad del carbono es neutral haciendo que la mayoría de los enlaces que forma sean covalentes.
Todas son correctas
Because electrons are orbiting the nucleus, the nucleus is stationary
true or false
Answer:
false, The nucleus of atoms still move around like crazy, it's just the electrons move more.
Cuál es el cruce para un niño donde su padre tiene el pelo rizo RR y su madre pelo lacio rr
Answer:
Rr
Explanation:
The nonmetals include which of the following groups? Use the periodic table to answer the question. Check all that apply.
halogens
alkali metals
lanthanides
noble gases
alkaline earth metals
Answer:
En el grupo de los no metales se incluyen los halógenos (flúor, cloro, bromo, yodo, astato y téneso), que tienen 7 electrones en su última capa de valencia y los gases nobles (helio, neón, argón, kriptón, xenón, radón), que tienen 8 electrones en su última capa (excepto el helio, que tiene 2).
Explanation:
halógenos
Answer:
1,4
Explanation:
A heat lamp produces____
light.
Answer:
infrared light
Explanation:
If calcium carbonate (Cacos) decomposes. What would the product of the reaction be?
Answer:
CaO
Explanation:
Group 2 Carbonates decompose to form oxides of the Group 2 element and Carbon dioxide
If a man reach a 25 km distance in 30 min in his car , find the average velocity
Answer:
Average velocity of car = 50 km/h
Explanation:
Given information;
Distance cover by man in his car = 25 kilometer
Time taken by man to cover distance = 30 min
Find:
Average velocity of car
Computation:
Time taken by man to cover distance = 30 min
Time taken by man to cover distance = 30 / 60
Time taken by man to cover distance = 0.5 hour
Average velocity = Distance / Time
Average velocity of car = Distance cover by man in his car / Time taken by man to cover distance
Average velocity of car = 25 / 0.5
Average velocity of car = 50 km/h
The first excited state of a particular atom in a gas is 6.1 eV above the ground state. A moving electron collides with one of these atoms, and excites the atom to its first excited state. Immediately after the collision the kinetic energy of the electron is 3.2 eV. What was the kinetic energy of the electron just before the collision
Answer:
The kinetic energy of the electron just before the collision is 9.3 eV.
Explanation:
We can find the kinetic energy of the electron before the collision can be found by energy conservation:
[tex] E_{i} = E_{f} [/tex]
[tex] K_{a_{i}} + K_{e_{i}} = K_{a_{f}} + K_{e_{f}} [/tex] (1)
Where:
[tex]K_{a_{i}}[/tex]: is the initial kinetic energy of the atom
[tex]K_{a_{f}}[/tex]: is the final kinetic energy of the atom = 6.1 eV + [tex]K_{a_{i}}[/tex]
[tex]K_{e_{i}}[/tex]: is the initial kinetic energy of the electron =?
[tex]K_{e_{f}}[/tex]: is the final kinetic energy of the electron = 3.2 eV
By solving equation (1) for [tex]K_{e_{i}}[/tex] we have:
[tex]K_{a_{i}} + K_{e_{i}} = (6.1 eV + K_{a_{i}}) + 3.2 eV[/tex]
[tex] K_{e_{i}} = 6.1 eV + 3.2 eV = 9.3 eV [/tex]
Therefore, the kinetic energy of the electron just before the collision is 9.3 eV.
I hope it helps you!
please let me know if this is correct?
Answer: Yes! you're all good. Alkali metals in group 1 are the most metallic :)
What is the molarity of the solution formed by dissolving 80. G of NAOH(s) into water to give a total volume of 4.00 l
Answer:
0.5 M
Explanation:
From the question given above, the following data were obtained:
Mass of NaOH = 80 g
Volume of solution = 4 L
Molarity =?
Next, we shall determine the number of mole in 80 g of NaOH. This can be obtained as follow:
Mass of NaOH = 80 g
Molar mass of NaOH = 23 + 16 + 1
= 40 g/mol
Mole of NaOH =?
Mole = mass / molar mass
Mole of NaOH = 80 / 40
Mole of NaOH = 2 moles
Finally, we shall determine the molarity of the solution. This can be obtained as follow:
Mole of NaOH = 2 moles
Volume of solution = 4 L
Molarity =?
Molarity = mole / Volume
Molarity = 2/4
Molarity = 0.5 M
Therefore, the molarity of the solution is 0.5 M.
1.25 X 10^24 molecules of chlorine gas react with sodium to form how many grams of sodium
chloride?
2Na + Cl2
--> 2NaCl
Answer:
241.28 g NaCl(s)
Explanation:
Given 1.25 x 10²⁴ molecules of Cl₂ = 1.25 x 10²⁴molecules Cl₂(g)/6.023 x 10²³ molecules/mole = 2.08 mole Cl₂(g)
2Na(s) + Cl₂(g) => 2NaCl(s)
excess 2.08mole ? mole
∴moles NaCl(s) formed from 2.08 moles Cl₂(g) = 2(2.08 mole NaCl(s))
= 4.16 mole NaCl(g) = 4.16 mole NaCl(s) x 58 g NaCl(s)/mole NaCl(s) = 241.28 g NaCl(s)
The mass of a neutron is
Stoichiometry - Chemistry
Answer:
C
Explanation:
in the option C when we rearrange it then it will he C3H6O2
Answer:
yes its C
Explanation:
correct me if iam wrong
What are the example of molecule ?
Explanation:
H2O water molecule
O3 Ozone
are some of common example of molecules
what is displacement?
Answer:
the moving of something form it's places or position
Which of the following statements about the nucleus is false?
A. Contains nearly all of the mass of the atom.
B. Able to be lost or gained in chemical reactions.
C. None of these
D. Made up of protons and neutrons
Answer:
B. Able to be lost or gained in chemical reactions.
Answer:
B
Explanation:
a chemical reaction would only move the nucleas
if you have a pop quiz and you get nervous is that unconditioned response? if yes why? if not what kind of response is it
Which is a constructive process? Rivers carrying sediment down stream, the rusting of a bridge, waves cutting back a beach front, volcanic eruption caused by plate tectonics
Answer:
volcanic eruption caused by plate tectonics.
Explanation:
Constructive process is one in which memories are influenced by some events. When a person tries to retrieve the memory he first click some event which is associated with that memory and then whole flash backs comes to his mind.
Polywool fibre is
a.natural
b.synthetic
c.monomer
d.blended
Polywool fibre is synthetic.
⇒b. Synthetic
Hope It Helps You ✌️
Answer:
[tex]\large{\underbrace{\underline{\fcolorbox{White}{pink}{\bf{b.synthetic }}}}}
[/tex]
Diego is trying to lift a piano to the second floor of his house. Diego uses a pulley system and gives a big lift to the piano.The piano moves upward, then stops, and then it starts to fall to the ground. (The direction of the force of gravity is negative.) Which list best describes the forces on the piano in the proper order
Answer:
positive force → balanced force → negative force
Explanation:
np
Answer:
positive force → balanced force → negative force
Explanation:
:)))
In the past mining companies were not made responsible for the clean-up of any of the mine sites. As a result, abandoned mines had a severe impact on the environment in Ontario. Which of these is not a result of these mining practices?
1) Chemical reactions producing sulphuric acid decrease soil and water PH in the area.
2) Acid leaching dissolves metals found in the soil thus allowing them to enter the water system.
3) Heavy metals which are left tailing ponds can dissolve and enter the water system.
4) Old and inefficient mining smokestacks contaminate the soils around abandoned mine sites.
Answer:
Old and inefficient mining smokestacks contaminate the soils around abandoned mine sites.
Explanation:
A smokestack, is a very tall channel commonly used in many instances to release gases produced by combustion processes directly into the air. These high towers are aimed at dispersing the gaseous pollutants over a wider area thereby minimizing their impact.
Old and inefficient smokestack do not contaminate the soil since they are very high towers that discharge gases directly into the atmosphere. Hence they are not part of the sources of soil contamination in abandoned mines.
calculate the final pressure of a gas that is expanded from 725cm³ at 30C and 1.19 atm to 1.12cm³ at 43C
Answer:
Final pressure, P2 = 1088.89 atm
Explanation:
Given the following data;
Initial volume, V1 = 725 cm³
Initial temperature, T1 = 30°C
Initial pressure, P1 = 1.19 atm
Final volume, V2 = 1.12 cm³
Final temperature, T2 = 43°C
To find the final pressure (P2), we would use the combined gas law.
Mathematically, the combined gas law is given by the formula;
[tex] \frac {PV}{T} = k [/tex]
[tex] \frac {P_{1}V_{1}}{T_{1}} = \frac {P_{2}V_{2}}{T_{2}} [/tex]
Substituting into the formula, we have;
[tex] \frac {1.19*715}{30} = \frac {P_{2}*1.12}{43} [/tex]
[tex] \frac {850.85}{30} = \frac {P_{2}*1.12}{43} [/tex]
[tex] 28.3617 = \frac {P_{2}*1.12}{43} [/tex]
Cross-multiplying, we have;
[tex] 28.3617 * 43 = 1.12P_{2} [/tex]
[tex] 1219.5531 = 1.12P_{2} [/tex]
[tex] P_{2} = \frac {1219.5531}{1.12} [/tex]
Final pressure, P2 = 1088.89 atm
Cuando se quema 1 mol de metano –o sea, 16 g–, se desprenden 802
kJ/mol.
○ Cuando se quema 1 mol de octano –o sea, 114 g–, se desprenden 5500
kJ/mol.
Pareciera que el octano puede brindar más energía al quemarse, pero vamos a
hacer un análisis más cuidadoso. Comparemos la combustión de igual masa de
cada combustible.
● Calculen la cantidad de calor que se desprende cuando se quema un gramo
de cada combustible.
1 gr de metano aporta……………………………
1 gr de octano aporta………………………………
Answer:
1 gramo de metano aporta 50.125 kilojoules.
1 gramo de metano aporta 48.246 kilojoules.
Explanation:
La cantidad de energía liberada por la combustión de una unidad de masa del hidrocarburo ([tex]Q[/tex]), en kilojoules por mol, es igual a la cantidad de energía liberada por mol de compuesto ([tex]\bar {Q}[/tex]), en kilojoules por mol, dividido por su masa molar ([tex]M[/tex]), en gramos por mol:
[tex]Q = \frac{\bar Q}{M}[/tex] (1)
A continuación, analizamos cada caso:
Metano
[tex]Q = \frac{802\,\frac{kJ}{mol} }{16\,\frac{g}{mol} }[/tex]
[tex]Q = 50.125\,\frac{kJ}{g}[/tex]
1 gramo de metano aporta 50.125 kilojoules.
Octano
[tex]Q = \frac{5500\,\frac{kJ}{mol} }{114\,\frac{g}{mol} }[/tex]
[tex]Q = 48.246\,\frac{kJ}{mol}[/tex]
1 gramo de metano aporta 48.246 kilojoules.
Determine the enthalpy for the reaction A+B --> C If we know the following:
A+E --> C+D; delta H = -200 kJ
D+B --> E; delta H = -100 kJ
Explanation:
here is the answer to the question
need help asap!!!
so i don’t necessarily need an answer just how to solve everything.
this is the first one:
calcium hydroxide + ammonium chloride
the instructions are attached to this question. i’m just not sure how to do everything. it doesn’t give me the products side only the reactants so how am i supposed to write and balance the equation?
Explanation:
とおふぉくぉをえおろとようおいおぽあおそ・
'」*とまっぉのもヴぉこぉぞぽ、こ、
Answer:
Ca(OH)2 + 2NH4Cl .................. CaCl2 + 2NH3 + 2H2O
Directions: Write True if the statement is correct, if it is not, make the false statement true by changing the underlined word or phrase 1. A constellation is a configuration of stars that form a pattern. 2. The Little Dipper is a part of the constellation Ursa Major 3. The North Star is found in the Little Dipper 4. The North Star is also called Merak. 5. The North Polar Constellations can be seen in the Northern Hemisphere. ales atterns in the night sky constellations
BRAINLIEST+FOLLOW+HEART+RATE
BAD ANSWER-REPORT
MAAYOS NA SAGOT KAILANGAN LANG PO
Answer:
1. A constellation is a configuration of stars that form a pattern. True
2. The Little Dipper is a part of the constellation Ursa Major. False
3. The North Star is found in the Little Dipper.True
4. The North Star is also called Merak. False
5. The North Polar Constellations can be seen in the Northern Hemisphere. ales atterns in the night sky constellations .True
A sample of substance "B" has a mass of 37.6g contained in a volume of
9.65mL. What is the density of substance "B"? (Report your answer with 3
s.f. E.G.: 6.00g/mL)
Answer:
3.90g/mL
Explanation:
To find the density of a substance, divide the mass by the volume.
So, 37.6 / 9.65 = 3.89637
then round to 3 significant figures
Good luck!
You react 25.0 grams of aluminum with iron (II) chloride. How many grams of iron will you
make? 2A1 + 3FeCl2 --> 2AlCl3 + 3Fe
(PLS HELP ASAP)
Explanation:
hope the picture above helps you to understand:)
If you produce 35.7 grams of sodium chloride how many molecules of Chlorine gas were
needed?
2Na + Cl2 --> 2NaCl
(PLS HELP ASAP)
Explanation:
I did it in steps to help u to understand :)
Energy transformation of a kettle?
Explanation:
Electrical energy into heat energy..hope it helps.stay safe healthy and happy...hat is the molarity of a solution prepared by dissolving 12.0 g of ethylene glycol, C2H6O4, in water to make 250.0 mL of solution
Answer:
0.512 M
Explanation:
We'll begin by calculating the number of mole in 12 g of C₂H₆O₄. This can be obtained as shown below:
Mass of C₂H₆O₄ = 12 g
Molar mass of C₂H₆O₄ = (2×12) + (6×1) + (4×16)
= 24 + 6 + 64
= 94 g/mol
Mole of C₂H₆O₄ =?
Mole = mass /molar mass
Mole of C₂H₆O₄ = 12 / 94
Mole of C₂H₆O₄ = 0.128 mole
Next, we shall convert 250 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
250 mL = 250 mL × 1 L / 1000 mL
250 mL = 0.25 L
Thus, 250 mL is equivalent to 0.25 L.
Finally, we shall determine the molarity of the solution. This can be obtained as follow:
Mole of C₂H₆O₄ = 0.128 mole
Volume = 0.25 L
Molarity =?
Molarity = mole /Volume
Molarity = 0.128 / 0.25
Molarity = 0.512 M
Thus, the molarity of the solution is 0.512 M