Compound A has molecular formula C4H10. Compound A gives two monochlorides, B and C, on photochemical chlorination. Treatment of either of these monochlorides with potassium tert-butoxide gives the same alkene (C4H8) as the product, but B leads to just one isomer of the alkene, D, whereas C gives D and another isomer of the alkene, E. Treatment of monochlorides B and C with aqueous ethanol gives products F and G, respectively, both of which are of molecular formula C4H10O. What are the chemical names of compounds A-G

Answers

Answer 1

Answer:

Explanation:

Radical chlorination of butane in the presence of light gives rise to the formation of two isomeric monochlorides B (1-chlorobutane) and C  (2-chlorobutane). Both upon reaction with a bulky base (potassium tert-butoxide) give rise to D(but-1-ene) and E(but-2-ene) respectively, this is because the bulky base abstracts the less hindered proton. Compound B and C were later treated with aqueous C2H5OH which results in the hydrolysis of alkyl halides to produce Compound F(butan-1-ol) and compound G (butan-2-ol) respectively.

The diagrammatic expression of the whole reaction is shown in the attached image below.

Compound A Has Molecular Formula C4H10. Compound A Gives Two Monochlorides, B And C, On Photochemical

Related Questions

what is the atomic structure of an element that has atomic number of 11 and neutron number of 12.​

Answers

Answer:

See explanation

Explanation:

The atomic number refers to the number of protons in the nucleus, it also tells us the number of electrons in the neutral atom since the atom is electrically neutral because the number of protons and electrons are equal.

If an atom has the atomic number 11, then the electrons in the atom are arranged in the shells in the order; 2, 8, 1.

Two electrons are found in the innermost shell, eight electrons are found in the next shell and one electron is found on the outermost shell.

The nucleus of the atom is composed of a total of 23 nucleons; 11 protons and 12 neutrons.

if B is completely insoluble in water. Your description should include the volume of solvent required.6b) Assuming that 2 mg of the impurity B are present along with 100 mg of A, describe how you can purify A if B has the same solubility behavior as A. Will one crystallization produce pure A

Answers

Answer:

1st step : mix the mixture with water that way A will dissolve while B will remain insoluble.

2nd step :To get B from the solution, filter the mixture and get B

3rd step : To get A from the solution evaporate the new solution

Explanation:

Assuming 2mg of impurity B to be present

100 mg of A is present as well

Method of purifying A given that B is of same solubility

Dissolve the 100 mg of A with 30 mL

1st step : mix the mixture with water that way A will dissolve while B will remain insoluble.

2nd step :To get B from the solution, filter the mixture and get B

3rd step : To get A from the solution evaporate the new solution

. ¿Cuantos moles de Fosfato de Bario se producen cuando reaccionan 0.38 mol de Nitrato
de bario? Suponga que el ácido fosfórico está en exceso. Base sus cálculos en la siguiente
ecuación.
Ba(NO3)2(aq) + HAPO.(aq)
Ba,(PO.),(s) + HNO3(aq)
-

Answers

Respuesta:

0.13 mol

Explicación:

Paso 1: Escribir la ecuación química balanceada

3 Ba(NO₃)₂ + 2 H₃PO₄ ⇒ Ba₃(PO₄)₂ + 3 H₂O

Paso 2: Establecer la relación molar apropiada

La relación molar de Ba(NO₃)₂ a Ba₃(PO₄)₂ es 3:1.

Paso 3: Calcular cuantos moles de fosfato de bario se producen a partir de 0.38 moles de nitrato de bario

0.38 mol Ba(NO₃)₂ × 1 mol Ba₃(PO₄)₂/3 mol Ba(NO₃)₂ = 0.13 mol Ba₃(PO₄)₂

The energy of a photon that has a frequency of 1.821 x 1016 5-1 is blank j?

Answers

Answer:

1.207 ××10⁻¹⁷ J

Explanation:

Step 1: Given and data

Frequency of the photon (ν): 1.821 × 10¹⁶ s⁻¹Planck's constant (h): 6.626 × 10⁻³⁴ J.s

Step 2: Calculate the energy (E) of the photon

We will use the Planck-Einstein's relation.

E = h × ν

E = (6.626 × 10⁻³⁴ J.s) × ( 1.821 × 10¹⁶ s⁻¹) = 1.207 ××10⁻¹⁷ J

Select all the correct answers
When two generalizations can be made based on what you know about cycles of matter in a closed system?
New matter is added, and old matter is destroyed.
Matter changes its physical form, allowing it to return to its original state.
The amount of matter within the system remains the same
Matter and energy can cross the boundaries of the system.
The cycle has a well-defined starting and Stopping point

Answers

Answer:

A

Explanation:

The acid dissociation constant, Ka, of HNO3 is 4.0 x104. What does the ka
value indicate about this compound?
A. HNO3 is neither an acid nor a base,
B. HNO3 is a strong acid.
C. HNO3 is a weak acid
D. HNO3 is a strong base.

Answers

Answer:

i thing its b

Explanation:

The acid dissociation constant (Ka) is a measure of the strength of an acid in solution. In HNO₃ (nitric acid), the given Ka value is 4.0 x 10⁴. It represents the equilibrium constant for the dissociation reaction of an acid in water. Therefore, option B is correct.

The dissociation constant often denoted as Kd, is a measure of the strength of the interaction between a ligand and a receptor or between a substrate and an enzyme.

A high Ka value indicates a strong acid, while a low Ka value indicates a weak acid. In this case, the Ka value of 4.0 x 10⁴ for HNO₃ is relatively high.

To learn more about the dissociation constant, follow the link:

https://brainly.com/question/28197409

#SPJ6

La is element 57 on the periodic table a sample contains 2.82 * 10€25 power atoms of La calculate the amount of LA

Answers

Answer:

[tex]n=46.8molLa\\\\m=6.50x10^3gLa[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate both moles and grams of lanthanum by using the Avogadro's number as a relationship of atoms to moles and its atomic mass as a relationship to moles to grams to obtain the following:

[tex]n=2.82x10^{25}atomsLa*\frac{1molLa}{6.022x10^{23}atomsLa}=46.8molLa\\\\m=46.8molLa*\frac{138.9gLa}{1molLa} =6.50x10^3gLa[/tex]

Regards!

How is the atomic mass of an element calculated?

Answers

Answer:

Mass number (A) is the number of nucleons (proton and neutron) present in a atom.

Explanation:

electrons don't cout since they are thousandth's of the mass of protons or neutrons

“Conductor, circuit breaker, switch” use the words provided to write the function of fuses. 


Answer pls ​

Answers

Answer:

The fuse is a thin wire that is the conductor of electricity is designed to breaks the circuit if there is a fault in an appliance that causes excessive current to flow in a circuit.

The conductor used in the fuse is melt and separated in such cases of excessive current in a circuit and switch the current off.

A circuit breaker is made up of a thin wire that is specially designed to switch that automatically breaks circuit current in the overcurrent condition.


What would happen to the Earth's hydrosphere if there were no atmosphere?

Answers

Weather happens in the atmosphere. However, without the hydrosphere there would be no water to evaporate. Therefore, no clouds or rain would form. The temperature of the Earth would rapidly start to rise once our atmosphere had disappeared. Without our atmosphere we have little protection from the Sun's heat. It would penetrate to the Earth's surface and cause the water to start boiling off into steam that would float off into space. Since we need water for survival, the lack of water from the hydrosphere would prevent all life source such as plants, animals, and humans from surviving.

which effect of long-term environmental change is the driving force behind evolution?​

Answers

Answer:

climate change

Explanation:

climate change is driving force of evolution because when the climate is changed the animal and human need to adapt to it's natural change.

How many joules of heat energy are required to raise the temperature of 100.0 g of aluminum by 120.0°C? The specific heat of aluminum is 0.897 J/g.°C. 2 3

Answers

Answer:

10764 J

Explanation:

Remember the equation for specific heat::

q = mcΔT

q = 100 x 0.897 x 120

q = 10764

An article about half-lives describes a parent isotope. What is a parent isotope?

A. The isotope that forms from the radioactive decay of a less stable isotope.
B. The isotope that forms from the radioactive decay of a more stable isotope.
C. The isotope that undergoes radioactive decay to form a less stable isotope.
D. The isotope that undergoes radioactive decay to form a more stable isotope.

I think the answer is D.

Answers

Answer:

D. The isotope that undergoes radioactive decay to form a more stable isotope.

Explanation:

In radioactivity, isotopes of an unstable atom disintegrates/decays into more stable ones accompanied with the emissions of certain particles e.g alpha, gamma and beta particles.

In this process, the isotope of the atom that undergoes radioactive decay to form a more stable isotope is known as the PARENT ISOTOPE while the more stable isotope that arises from the decay is called the DAUGHTER ISOTOPE.

(238, 92) Uranium → (234,90) Thorium + (4,2) Helium

In the above reaction, Uranium is the parent isotope because it decays into a more stable isotope (Thorium).

Answer:

He's Right

Explanation:

i got it right

Calculate the amount of heat needed to melt 89.9 g of solid methanol (CH3OH) and bring it to a temperature of 49.1C.

Answers

Answer:

20075.35 J

Explanation:

We'll begin by calculating the number of mole in 89.9 g of CH₃OH. This can be obtained as follow:

Mass of CH₃OH = 89.9 g

Molar mass of CH₃OH = 12 + (3×1) + 16 + 1

= 12 + 3 + 16 + 1

= 32 g/mol

Mole of CH₃OH =?

Mole = mass / molar mass

Mole of CH₃OH = 89.9 / 32

Mole of CH₃OH = 2.81 moles

Next, we shall determine the heat required to melt the solid methanol (CH₃OH). This can be obtained as follow:

Mole of CH₃OH (n) = 2.81 moles

Heat of fusion (Hբ) = 3.17 KJ/mol

Heat required to melt CH₃OH (Q₁) = ?

Q₁ = n × Hբ

Q₁ = 2.81 × 3.17

Q₁ = 8.9077 KJ

Converting to J

Q₁ = 8.9077 × 1000

Q₁ = 8907.7 J

Next, we shall determine the heat required to change the temperature of methanol to 49.1 °C. This can be obtained as follow:

Mass of CH₃OH (M) = 89.9 g

Initial temperature (T₁) = 0 °C

Final temperature (T₂) = 49.1 °C.

Specific heat capacity of CH₃OH (C) = 2.53 J/gºC

Heat required to change the temperature (Q₂) =?

Q₂ = MC(T₂ – T₁)

Q₂ = 89.9 × 2.53 × (49.1 – 0)

Q₂ = 89.9 × 2.53 × 49.1

Q₂ = 11167.65 J

Finally, we shall determine the total heat. This can be obtained as follow:

Heat required to melt CH₃OH (Q₁) = 8907.7 J

Heat required to change the temperature (Q₂) = 11167.65 J

Total heat required (Q) =?

Q = Q₁ + Q₂

Q = 8907.7 + 11167.65

Q = 20075.35 J

Therefore, the total heat required to melt the methanol and bring it to a temperature of 49.1 °C is 20075.35 J

10-Concentration is the amount of a substance in a predefined volume of space. The basic measurement of concentration in chemistry is molarity or the number of moles of solute per liter of solvent. What is the molarity of a solution containing 9.478 grams of Rucl, in enough water to make 1.00 L of solution?

Answers

Answer:

0.0457 M

Explanation:

Concentration is the amount of a substance in a predefined volume of space. The basic measurement of concentration in chemistry is molarity or the number of moles of solute per liter of solution. What is the molarity of a solution containing 9.478 grams of RuCl₃, in enough water to make 1.00 L of solution?

Step 1: Given data

Mass of RuCl₃ (solute): 9.478 gVolume of solution: 1.00 L

Step 2: Calculate the moles corresponding to 9.478 g of RuCl₃

The molar mass of RuCl₃ is 207.4 g/mol.

9.478 g × 1 mol/207.4 g = 0.04570 mol

Step 3: Calculate the molarity of the solution

We will use the definition of molarity.

M = moles of solute / liters of solution

M = 0.04570 mol / 1.00 L = 0.0457 M

PLZZZ HELPPPPPPPPPPPPPPPPPPPPP

Answers

Answer:

1 +-0.05cm

Explanation:

because this is more suitable

the intrument that tells both the speed and direction of the wind is the?

Answers

Answer:

anemometer

Explanation:

The instrument that is being described is called an anemometer. This is a device that has 4 ladel like objects that allow the wind to hit it, causing it to spin. The force of the spin allows meteorologists to calculate the speed of the wind. On top of this device is usually an arrow which can rotate around the device with the wind and point in the direction that the wind is blowing. Using a N, NE, E, SE, S, SW, W, and NW direction.

A certain alkyl halide is reacted with OH- to form an alcohol. The alkyl halide is optically active but the product(s) is/are optically inactive. Which of the following could be the reactant?a) 3-bromo-3-methylhexane.b) 1-chlorobutane.c) 2-bromo-2-methylbutane.d) 3-bromo-2,3,4-trimethypentane.

Answers

Answer:

a. 3-brumo - 3-methylhexane

Explanation:

Alkyl Halides can undergo substitution reactions. Nucleophiles are electron rich species and has negative charge while Electrophiles are electron deficient species which carry positive charge. Alkyl halide which have polar carbon atom are electrophiles.

Soybeans is used in food production and cooking in 2007 United States produced 3.06 billions bushels of soybeans and 65% of the harvest was used to make soybeans oil

Answers

Answer:

1.071

Explanation:

Answer:

Find the percentage of soybeans used for other purposes:

100% − 65% = 35%.

Multiply the result (35%) by the total bushels of soybeans produced:

35

100

=

0.35

.

0.35 × 3.06 billion bushels = 1.071 billion bushels

The amount of soybeans used for other purposes was 1.071 billion bushels.

Explanation:

PLATO

For the iron thiocyanate system, what is the value of the equilibrium constant, Kc, if the following are the concentrations of all species present. Provide your answer to three digits after the decimal.

FeSCN2+ 0.501
Fe3+ 0.494
SCN- 0.639

Answers

Answer:

Kc = 0.630

Explanation:

The equilibrium of the thiocyanate system occurs as follows:

FeSCN²⁺(aq) ⇄ Fe³⁺(aq) + SCN⁻(aq)

And equilibrium constant, kc, is:

Kc = [SCN⁻] [Fe³⁺] / [FeSCN²⁺]

Replacing with the gven concentrations:

Kc = 0.639M*0.494M / 0.501M

Kc = 0.630

What size volumetric flask would you use to create a 1.00M solution using 166.00 g of KI?

Answers

Answer:

A 1 liter volumetric flask should be used.

Explanation:

First we convert 166.00 g of KI into moles, using its molar mass:

Molar mass of KI = Molar mass of K + Molar mass of I = 166 g/mol

166.00 g ÷ 166 g/mol = 1 mol KI

Then we calculate the required volume, using the definition of molarity:

Molarity = moles / liters

Liters = moles / molarity

1 mol / 1.00 M = 1 L


Which equation represents a combustion reaction?


2SO2 + O2 → 2SO3

Pb(NO3)2 + 2HCl → PbCl2 + 2HNO3

2C2H6 + 7O2 → 4CO2 + 6H2O

Ca + 2HCl → CaCl2 + H2

Answers

poop man poop man poop man poop man

Answer:

2SO2 + O2 => 2SO3

Explanation:

Combustion reaction involves heating of a compound/element/substance in presences of oxygen.

Which of the following is true for a nuclear reaction? (5 points)

Select one:
a.Electrons are lost.
b.Electrons are gained.
c.The identity of element changes.
d.The identity of element remains same.

Answers

the identity of element remains same

D. The identity of an element remains the same.

Use the electronic configuration to explain the occurrence of period and groups to the periodic table.

Answers

Answer:

H2O

Explanation:

hydrogen has 1 electron

and oxygen has 6 electron which form a water molecule Atom

En una práctica experimental, para la obtención de cloruro cobaltoso, se hacen reaccionar 120 g de sulfuro cobaltoso de 60% de pureza con 30 cm3 de ácido nítrico concentrado (densidad 1,142 g/cm3, 69,8% en peso de HNO3), en presencia de ácido clorhídrico concentrado (densidad 1,19 g/cm3, 37,33 % en peso de HCl). Calcular:
a) El volumen de ácido clorhídrico concentrado que se requiere para la reacción.
b) La cantidad máxima de cloruro de cobalto (II) que se puede preparar.
c) El número de moléculas de monóxido de nitrógeno que se deprenden.
d) El número de átomos de azufre que se forman.
e) El número de moles de agua que se obtiene.
CoS + HNO3 + HCl → CoCl2 + NO + S + H2O

Answers

Answer: D

Explanation:

Utilicé traductor de español para responder esta pregunta

How many moles are present in a sample if it consists of 5.61x1022 particles? Report your answer to 3 decimal places. Do not include units.​

Answers

Answer:

The mole is defined as a collection of 6.022 × 1023 particles.

The atomic mass given on a periodic table that is given in grams is the mass of

one mole (6.022 × 1023 particles) of that element

Explanation:

atomic number of element is 15 write a formula of an oxide​

Answers

Answer:

Atomic Number. 15=phosphorus

Valency=3

So, Oxide=P203

The main product of free radical bromination of methane is
A) ethane
B) chloromethane
C) bromonethane
D) bromine

Answers

Answer: C

Explanation:

5pts) Reaction Characterization (1pts) Select the type of reaction Choose... (1pts) Write the balanced equation for the formation of the Grignard reagent from bromobenzene. Include all reagents and products but not solvents.

Answers

Answer:

See explanation and image attached

Explanation:

Grignard reagent is any organic compound that is classified as an alkyl or aryl magnesium halide (RMgX).

Grignard reagents are produced when the alkyl halide reacts with magnesium metal in ether and tetrahydrofuran as solvents.

They are good nucleophiles and are involved in the synthetic routes to many important classes of organic compounds.

The formation of Grignard reagent from bromobenzene is shown in the image attached to this answer.

What is the initial pressure of a gas if it’s occupied a volume of 0.375 L but now occupies a volume of 1.25 L at a pressure of 95.5 K PA

Answers

Answer:

318 kPa

Explanation:

Step 1: Given data

Initial pressure (P₁): ?Initial volume (V₁): 0.375 LFinal pressure (P₂): 95.5 kPaFinal volume (V₂): 1.25 L

Step 2: Calculate the initial pressure of the gas

Assuming constant temperature and ideal behavior, we can calculate the initial pressure of the gas using Boyle's law.

P₁ × V₁ = P₂ × V₂

P₁ = P₂ × V₂ / V₁

P₁ = 95.5 kPa × 1.25 L / 0.375 L = 318 kPa

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