Classify the data as qualitative or quantitative. If qualitative then classify it as ordinal or categorical, and if quantitative then classify it as discrete or continuous. Variable Height (in inches) Grade (ABCDF) Weight (exact) Color Data Type a Quantitative Continuous b Quantitative Discrete c Qualitative Categorical d Qualitative Ordinal

Answers

Answer 1

Answer:

Explained below.

Step-by-step explanation:

Qualitative variables are categorized or labelled to belong to a certain category or group.

There are two types of qualitative variables, Categorical and ordinal.

Categorical variable are those variables that are labelled in non-numeric or numeric form, where the numbers have no value. The order also does not matters. For example, the number on the jerseys of football players. It is not necessary that the player number 1 is actually the best player.

Ordinal variables are those variables where the label or category has to be in order. For example, the rank of students in the statistics class.

Quantitative variables are in numerical form and can be measured.

There are two types of quantitative variables, discrete and continuous.

Discrete variables are those variables that assume finite and specific value. For example, the number of girls in each section of a school.

Continuous variables are those variables that can assume any number of values between a specific interval. For example, the time it takes to reach point B from A.

Variable              Category               Sub-Category

Height              Quantitative              Continuous

 Grade               Qualitative                   Ordinal

Weight              Quantitative              Continuous

  Color                Qualitative               Categorical


Related Questions

pt 3 2-7 pleasee helpp

Answers

Answer:

-3x - 6 - 1

- 3x + 7

4x

Step-by-step explanation:

A motorcyclist starts from rest and reaches a speed of 6m/s after travelling with uniform acceleration for 3s .
the question is what is his acceleration?
by calculation​

Answers

Acceleration = final speed - initial speed / time

Acceleration = 6 m/s  - 0 / 3s

Acceleration = 6m/s / 3s

Acceleration = 2 m/s^2

Answer:

[tex]\Huge \boxed{\mathrm{2 \ m/s^2 }}[/tex]

Step-by-step explanation:

[tex]\displaystyle acceleration = \frac{final \ velocity - initial \ velocity}{elapsed \ time}[/tex]

[tex]\displaystyle A = \frac{V_f - V_i}{t}[/tex]

The initial velocity is 0 m/s.

The final velocity is 6 m/s.

The elapsed time is 3 s.

[tex]\displaystyle A = \frac{6 - 0}{3}[/tex]

[tex]\displaystyle A = \frac{6}{3}=2[/tex]

The acceleration is 2 m/s².

On a distant planet, a ball is thrown upwards from ground level , reaching a maximum height of 12m and hitting the ground again in eight seconds. Determine a quadratic equation in the form a * x ^ 2 + bx + + c =0 that could be used to calculate when the ball is a height of 3m. Do not solve the equation

Answers

Answer:

(-3 ÷ 4)x^2 + 6x

Step-by-step explanation:

Data provided in the question

Maximum height = 12m

Number of seconds = 8

Height = 3m

Based on the above information, the quadratic equation is as follows

Since it took 8 seconds for reaching the maximum height and then it returned to the ground level so here the highest point is done after 4 seconds also this graph represents the motion in parabola so the a should be negative

Now it is mentioned that

a × x ^ 2 + bx + c =0

We can assume that

x = 0

x = 8

As these {0.8} are intercepts of x

When x = 0, then it would be

a × 0 ^ 2 + b(0)  + c = 0 .................... (i)

Therefore 0 = 0

Now x = 8, it would be

a × 8 ^ 2 + b(8)  + c = 0

Therefore a(8)^2 + b(8) + c =  0 ..................(ii)

As we can see  that in the first equation c should be zero

While the second equation would be

64a + 8b = 0

i.e.

8a = -b or a = -b ÷ 8

Now as per the quadratic function, it appears

(-b ÷8)x^2 + bx + 0

Now the parabola vertex is (4, 12)

Now put this in the place of a

(-b ÷ 8)(4)^2 + b(4) = 12

Now for solving this b, all terms should be multiplied by 8

That comes

-b(16) + 32b = 96

16b = 96

So, b = 6.  

As a = -b ÷8

a = -6 ÷ 8

a = -3 ÷4

Now the equation is

= (-3 ÷ 4)x^2 + 6x

Hence, this is the equation

3/7 is it< or> then 3/5​

Answers

Two ways of solving:

1. Convert the fractions to decimals:

3/7 = 0.42857

3/5 = 0.6

0.42857 < 0.6

So 3/7 < 3/5

Second way is to rewrite the fractions with a common denominator:

3/7 = 15/35

3/5 = 21/35

Now compare the numerators:

15 < 21 so 3/7 < 3/5

sameer usually drinks 3 cups of coffee in the morning. How many liters of coffee does he drink? Round your answer to the nearest tenth

Answers

Answer: 0.7 liters

Step-by-step explanation:

First convert 3 cups to Liters

3 cups = 0.709765

Now round 0.709765 to the nearest 10 which give you 0.7

Answer:

0.7 liters Hope this helps!

Step-by-step explanation:

Use the given confidence interval limits to find the point estimate p^ and the margin of error E. 0.325

Answers

Answer:

0.350

Step-by-step explanation:

Confidence interval = point estimate ± margin of error

Point estimate = Confidence interval - margin of error

To get the margin of error, we will take the average of the difference of the interval given. Given the confidence interval 0.325<p<0.375

Margin of error = 0.375-0.325/2

Margin of error = 0.050/2

Margin of error = 0.025

Using the interval of 0.375

Point estimate = 0.375 - 0.025

Point estimate = 0.350

4-2(3+2) ²
2.
Help me plz i need the help

Answers

Answer:

-46 is your answer.

Step-by-step explanation:

=4-2(3+2)^2

=4-2(5)^2

=4-2(5✖️5)

=4-2(25)

Opening brackets to simplify

=4-50

=-46 is your answer.

Hope it will help you :)

Answer:

-46

Step-by-step explanation:

[tex]4 - 2(3 + 2)^{2} \\ [/tex]

PEDMAS

[tex]4 - 2(5)^{2} \\ 4 - 2(25) \\ 4 - 50 \\ = - 46[/tex]

In ΔKLM, the measure of ∠M=90°, the measure of ∠L=18°, and KL = 8.3 feet. Find the length of MK to the nearest tenth of a foot.

Answers

Answer:

2.6 ft

Step-by-step explanation:

8.3/sin 90 = MK/sin 18

MK = 8.3 sin 18 / sin 90

MK = 2.6 ft

Answer:

2.6

Step-by-step explanation:

If z=(x+y)ey and x=u2+v2 and y=u2−v2, find the following partial derivatives using the chain rule. Enter your answers as functions of u and v.
∂z/∂u= ______
∂z/∂v= ______

Answers

Answer:

Step-by-step explanation:

Given the functions  z=(x+y)[tex]e^y\\[/tex] and x=u²+v² and y=u²−v²

Using the composite derivative formula;

∂z/∂u= ∂z/∂x*∂x/∂u+∂z/∂y*∂y/∂u

∂z/∂u = y[tex]e^y[/tex]*2u + [(x+y)[tex]e^y[/tex]+x[tex]e^y[/tex]]*2u

∂z/∂u =y[tex]e^y[/tex]*2u + 2u[x[tex]e^y[/tex]+y[tex]e^y[/tex]+x[tex]e^y[/tex]]

∂z/∂u = y[tex]e^y[/tex]*2u + 2u[2x[tex]e^y[/tex]+y[tex]e^y[/tex]]

∂z/∂u = 2u[u²−v²][tex]e^{u^2-v^2}[/tex]+ 2u[2(u²+v²)[tex]e^{u^2-v^2}[/tex]+y[tex]e^{u^2-v^2}[/tex]]]

∂z/∂v= ∂z/∂x*∂x/∂v+∂z/∂y*∂y/∂v

∂z/∂v = y[tex]e^y[/tex]*2v + [(x+y)[tex]e^y[/tex]+x[tex]e^y[/tex]]*-2v

∂z/∂v =y[tex]e^y[/tex]*2v -2v[x[tex]e^y[/tex]+y[tex]e^y[/tex]+x[tex]e^y[/tex]]

∂z/∂v = y[tex]e^y[/tex]*2v -2v[2x[tex]e^y[/tex]+y[tex]e^y[/tex]]

∂z/∂v = 2v[u²−v²][tex]e^{u^2-v^2}[/tex]-2v[2(u²+v²)[tex]e^{u^2-v^2}[/tex]+y[tex]e^{u^2-v^2}[/tex]]

Anyone help?? A screenshot is attached below

Answers

Answer:

113°

Step-by-step explanation:

By remote interior angle theorem:

a + 35° = a - 30° + a - 48°

a + 35° = 2a - 78°

35° + 78° = 2a - a

113° = a

a = 113°

Will mark brainliest

Answers

Answer:

Interquartile range => 7

Third quartile => 22

Range => 13

First quartile => 15

Step-by-step explanation:

Order your data set, from the least amount to the highest amount:

$12, $14, $15, $15, $15, $15, $16, $22, $24, $25

Interquartile range (IQR) = third quartile (Q3) - first quartile (Q1)

Q1 = the middle value of the lower part of the data set, from the median to your left.

Q3 = the middle value of the upper part of the data set, from the median to your right.

The median lies between the 5th and 6th value that is enclosed in the parenthesis below:

$12, $14, ($15), $15, $15,[Median], $15, $16, ($22), $24, $25

The median divides the data set into upper and lower part.

Median = [tex] \frac{15 + 15}{2} = 15 [/tex]

First quartile: Q1 = $15

Third quartile: Q3 = $22

IQR = $22 - $15 = $7

Range = highest amount - least amount = 25 - 12 = $13

Please help! Find the domain of y = 4 square root 4x + 2

Answers

Answer:

x ≥ -1/2

Step-by-step explanation:

We know that we cannot graph imaginary numbers. Therefore, our x value has to be greater than or equal to 0:

To find our domain, we need to set the square root equal to zero:

√(4x + 2) = 0

4x + 2 = 0

4x = -2

x = -1/2

We now know that no value below -1/2 can be used or we will get an imaginary number. Therefore, our answer is x ≥ -1/2

Alternatively, we can graph the function and analyze domain:

You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places.

Answers

You intend to estimate a population mean μ from the following sample. 26.2 27.7 8.6 3.8 11.6 You believe the population is normally distributed. Find the 80% confidence interval.  Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places.

Answer:

The  Confidence interval = (8.98 , 22.18)

Step-by-step explanation:

From the given information:

mean = [tex]\dfrac{ 26.2+ 27.7+ 8.6+ 3.8 +11.6 }{5}[/tex]

mean = 15.58

the standard deviation [tex]\sigma[/tex] = [tex]\sqrt{\dfrac{\sum(x_i - \mu)^2 }{n}}[/tex]

the standard deviation = [tex]\sqrt{\dfrac{(26.2 - 15.58)^2 +(27.7 - 15.58)^2 +(8.6 - 15.58)^2 + (3.8 - 15.58)^2 + (11.6 - 15.58)^2 }{5 } }[/tex]

standard deviation = 9.62297

Degrees of freedom df = n-1

Degrees of freedom df = 5 - 1

Degrees of freedom df = 4

For df  at 4 and 80% confidence level, the critical value t from t table  = 1.533

The Margin of Error M.O.E = [tex]t \times \dfrac{\sigma}{\sqrt{n}}[/tex]

The Margin of Error M.O.E = [tex]1.533 \times \dfrac{9.62297}{\sqrt{5}}[/tex]

The Margin of Error M.O.E = [tex]1.533 \times 4.3035[/tex]

The Margin of Error M.O.E = 6.60

The  Confidence interval = ( [tex]\mu \pm M.O.E[/tex] )

The  Confidence interval = ( [tex]\mu + M.O.E[/tex] , [tex]\mu - M.O.E[/tex] )

The  Confidence interval = ( 15.58 - 6.60 , 15.58 + 6.60)

The  Confidence interval = (8.98 , 22.18)

Find the sum of (root2+root3)+(root3-root7)+(root7-root2​

Answers

Answer:

Step-by-step explanation:

√2 + √3 + √3 - √7 + √7 - √ 2

by changing the position

√2 - √2 + √3 + √3 - √7 + √7

√2 and -√2 gets canceled

-√7 and √7 gets cancelled

we are left out with √3 + √3

√3 + √3 gives 2√3

so the answer is 2√3

hope this helps

plz mark as brainliest!!!!!!!!

Find the absolute extrema for f(x,y)=4-x^2-y^4+1/2y^2 over the closed disk D:x^2+y^2 is less than or equal to 1

Answers

Find the critical points of [tex]f(x,y)[/tex]:

[tex]\dfrac{\partial f}{\partial x}=-2x=0\implies x=0[/tex]

[tex]\dfrac{\partial f}{\partial y}=y-4y^3=y(1-4y^2)=0\implies y=0\text{ or }y=\pm\dfrac12[/tex]

All three points lie within [tex]D[/tex], and [tex]f[/tex] takes on values of

[tex]\begin{cases}f(0,0)=4\\f\left(0,-\frac12\right)=\frac{65}{16}\\f\left(0,\frac12\right)=\frac{65}{16}\end{cases}[/tex]

Now check for extrema on the boundary of [tex]D[/tex]. Convert to polar coordinates:

[tex]f(x,y)=f(\cos t,\sin t)=g(t)=4-\cos^2-\sin^4t+\dfrac12\sin^2t=3+\dfrac32\sin^2t-\sin^4t[/tex]

Find the critical points of [tex]g(t)[/tex]:

[tex]\dfrac{\mathrm dg}{\mathrm dt}=3\sin t\cos t-4\sin^3t\cos t=\sin t\cos t(3-4\sin^2t)=0[/tex]

[tex]\implies\sin t=0\text{ or }\cos t=0\text{ or }\sin t=\pm\dfrac{\sqrt3}2[/tex]

[tex]\implies t=n\pi\text{ or }t=\dfrac{(2n+1)\pi}2\text{ or }\pm\dfrac\pi3+2n\pi[/tex]

where [tex]n[/tex] is any integer. There are some redundant critical points, so we'll just consider [tex]0\le t< 2\pi[/tex], which gives

[tex]t=0\text{ or }t=\dfrac\pi3\text{ or }t=\dfrac\pi2\text{ or }t=\pi\text{ or }t=\dfrac{3\pi}2\text{ or }t=\dfrac{5\pi}3[/tex]

which gives values of

[tex]\begin{cases}g(0)=3\\g\left(\frac\pi3\right)=\frac{57}{16}\\g\left(\frac\pi2\right)=\frac72\\g(\pi)=3\\g\left(\frac{3\pi}2\right)=\frac72\\g\left(\frac{5\pi}3\right)=\frac{57}{16}\end{cases}[/tex]

So altogether, [tex]f(x,y)[/tex] has an absolute maximum of 65/16 at the points (0, -1/2) and (0, 1/2), and an absolute minimum of 3 at (-1, 0).

(10c^6d^-5)(2c^-5d^4)

Answers

10c^6d^-5×2c^-5d^4

20cd^-1

20c×1/d

20c/d

The vector parametric equation for the line through the points (−1,−4,2) and (−1,0,−3) is:_______

Answers

Answer: [tex]x(t)=-1[/tex]

[tex]y(t)=-4+4(t)[/tex]

[tex]z(t)=2-5(t)[/tex]

Step-by-step explanation:

To find: The vector parametric equations for the line through the points (−1,−4,2) and (−1,0,−3).

Let A (−1,−4,2) and B(−1,0,−3)

First we find direction vectors : [tex]\overrightarrow{AB}=<-1-(-1),0-(-4),-3-2>[/tex]

[tex]<0,4,-5>[/tex]

Now, the parametric equations of the line:

[tex]x(t)=-1+0(t)[/tex]

[tex]y(t)=-4+4(t)[/tex]

[tex]z(t)=2-5(t)[/tex]

Hence, the vector parametric equations for the line through the points (−1,−4,2) and (−1,0,−3):

[tex]x(t)=-1[/tex]

[tex]y(t)=-4+4(t)[/tex]

[tex]z(t)=2-5(t)[/tex]

The quotient of a number and 7 is equal to 13

Answers

Answer:

91

Step-by-step explanation: 7*13 = 91

91/7 = 13

Daniel is starting his own sewing business. Daniel has calculated that he needs to earn $360 per week to support his family. If he knows he will only be able to work 30 hours per week, what is the minimum amount of dollars per hour will he need to charge his customers?

Answers

Answer:

$12 the hour

Step-by-step explanation:$360 divided by 30 is 12, meaning he will need to make a minimum of 12 an hour to support his family.

Answer: 12 dollars

Step-by-step explanation:

360 divided by 30 is 12

If you use a 0.10 level of significance in a two-tail hypothesis test, what is your decision rule for rejecting a null hypothesis that the population mean equals 500 if you use the Z test

Answers

Answer:

Our decision rule will be to reject The null hypothesis H0 if the test statistic is less than -1.645, or if it is greater than +1.645.

Step-by-step explanation:

The hypotheses would be;

Null hypothesis;H0: μ = 500

Alternative hypothesis;Ha: μ ≠ 500

Since it's two - tailed at 0.1 level of significance, then each tail will contain 5% or 0.05. From the z-table attached, the corresponding critical value of 0.05 is approximately 1.645 standard deviations from the mean.

Thus, our decision rule will be to reject The null hypothesis H0 if the test statistic is less than -1.645, or if it is greater than +1.645.

What is 25+543\43 squared

Answers

Answer:

i think the answer is 0.3071

Step-by-step explanation:

But I might be wrong

v−6(−3v+3) how do i do this and can you show me with work

Answers

Answer:

19v - 18

Step-by-step explanation:

Hello!

v - 6(-3v + 3)

Distribute the -6

-6 * -3v = 18v

-6 * 3 = -18

v + 18v -18

Combine like terms

19v - 18

The answer is 19v - 18

Hope this helps!

Answer:

V=6;v=1

Step-by-step explanation:

(V-6)(-3v+3)

-3v^2+3v+18v-18

-3v^2+21v-18

Multiple it by minus one we will get

3v^3-21v+18

Now breaking by midterm

3v^2-18v-3v+18

3v(v-6)-3(v-6)

(V-6)(3v-3)

V=6;v=1

Will mark brainliest who answers fastest and right

Answers

Answer: 330 people

Step-by-step explanation:

added them all up

In which set(s) of numbers would you find the number
67
Orational number
irrational number
O whole number
integer
O natural number
O real number

Answers

Answer:

Rational

Explanation: because it can be expressed in the quotient of two integers:67÷1

Calculate the surface area of the prism. Measurements are in centimetres
Please help me asap!!!! The correct answer is 2804

Answers

Answer:

2804 cm²

Step-by-step explanation:

Total area comprises of 6 faces: 2 trapezoids and 4 rectangles

Trapezoid = 1/2*(14+32)*24 = 552 cm² eachBottom = 17*32 = 544 cm²Top = 14*17 = 238 cm²Right side = 17*24 = 408 cm²Left side = 17*√((24² + (32-14)²) = 17* √900 = 17*30 = 510 cm²

Total area:

552*2 + 544 + 238 + 408 + 510 =  2804 cm²

at a maximum speed an airplane travels 2100 miles against the wind in 6 hours. Flying with the wind, the plane travel the same distance in 4 hours. what is the speed of the plane with no wind?

Answers

Step-by-step explanation:

Let w be the speed of wind and v be speed of airplane without wind.

[tex]average \: speed = \frac{total \: distance }{total \: time} [/tex]

(A)

[tex]speed \: against \: wind( v - w) = \frac{2100}{6} = 350mph[/tex]

(B)

[tex]speed \: with \: wind(v + w) = \frac{2100}{4} = 525mph[/tex]

(C)

Adding equations A and B, we get :

(v - w) + (v + w) = 350 + 525

2v = 875

V = 437.5 mph

If A is the set of all natural numbers, choose the set B that will make the following statement true
(See photo)

Answers

Answer:

b= {1,2,3,4} is the answer

If the principal is $350 and the interest rate is 3 percent, what is the simple interest earned in one year?
simple interest = Pxrxt

Answers

Answer:

The simple interest earned in one year is $10.5

Step-by-step explanation:

Simple interest = p × r × t

Where,

p = principal

r = interest rate

t = time

Principal= $350

Interest rate = 3%

=3/100

=0.03

Time= 1 year

Simple interest = p × r × t

= $350 × 0.03 × 1

= $10.5

The simple interest earned in one year is $10.5

Is -4 a irrational number?

Answers

Answer:

No.

Step-by-step explanation:

Irrational numbers are numbers that you can't solve like 3 squared. See you can't find the end of 3 squared, the numbers will go on forever just like pi.

Answer:

No

Step-by-step explanation:

A rational number can be written as the ratio of integers

-4/-1 = -4

This is a rational number

What is 0.658 rounded to 1 significant figure?

Answers

Answer: 0.07 calculatorsoup for significant rounding

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