Christian is running back on the football in two games he scored three fourths of the total number of points is team scored. The team scored 49 points in the first game and 35 in the second game.what was the number of points Christian scored in the these two games

Answer:

Step-by-step explanation:

To find the price of the NBA ticket in 2017, we need to add 20% to the 2016 price:

Price in 2017 = $1444 + 0.20 x $1444 = $1732.80

To find the price of the NBA ticket in 2020, we need to increase the 2017 price by 20%:

Price in 2020 = $1732.80 + 0.20 x $1732.80 = $2079.36

Rounding this to the nearest dollar, we get:

Price in 2020 = $2079

The probability that all the guinea pigs selected randomly are pregnant is 1/30 or 0.033

Given, we have 10 guinea pigs out of which 4 are pregnant. We know that probability of an event ⇒ P(E) = (No of favorable outcomes)/(No of all outcomes) . So, The probability of selecting pigs that are pregnant is :

⇒ 4/10

Now, 3 selections are made randomly. The probability that the 1st selected guinea pig will be pregnant = 4/10

The probability that the 2nd selected guinea pig will be pregnant = 3/9

The probability that the 3rd selected guinea pig will be pregnant = 2/8

Therefore, the probability of all the 3 selected guinea pigs being pregnant will be :

⇒  (4/10) x (3/9) x (2/8)

⇒ 1/30

Therefore, The probability of all the selections of pigs being pregnant without replacement rounded to 3 decimal places is 0.033 or 1/30

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The complete question will be :

In a scientific study there are 10 guinea pigs,4 of which are pregnant. if 3are selected at random without replacement, find the probability that all are pregnant. enter your answer as a fraction or a decimal rounded to 3 decimal places.

The set S spans R₃ if and only if for any vector (a, b, c) in R₃, there exist scalars x, y, and z such that z is not zero and z/2 is nonzero. This is true for all vectors in R₃, so we conclude that S spans R₃.

To determine if the set S spans R₃, we need to see if any vector in R₃ can be written as a linear combination of the vectors in S.

Let (a, b, c) be an arbitrary vector in R₃. Then we want to see if there exist scalars x, y, and z such that:

x(1, -2, 0) + y(0, 0, 1) + z(-1, 2, 0) = (a, b, c)

This is equivalent to the system of equations:

x - z = a

-2x + 2z = b

y = c

Solving for x, y, and z, we get:

x = (a - z)/2

y = c

z = (b + 2x)/2 = (b + a - z)/2

Substituting these values into the equation for the linear combination, we get:

[(a - z)/2](1, -2, 0) + c(0, 0, 1) + [(b + a - z)/2](-1, 2, 0)

= ((a - z)/2 - (b + a - z)/2, -2(a - z)/2 + 2(b + a - z)/2, 0)

= (-b/2, (3a - b)/2, z/2)

Geometrically, the set S consists of two nonparallel vectors and a vector orthogonal to the xy-plane. Thus, the subspace spanned by S is a plane in R₃ passing through the origin.

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Thus, a single expression for x(t) that does not involve multiple cases is:

x(t) = 4t + 4 - u(t-2) - 2u(t-4) + 12u(t-12)

Using the properties of the unit step function,

we can write:

x(t) = 4t + 4 - u(t-2) - 2u(t-4) + 12u(t-12)

Breaking it down:

For t < 2, the unit step function u(t-2) is 0,

so it does not affect the expression for x(t).

For 2 ≤ t < 4, u(t-2) = 1 and u(t-4) = 0,

so the expression becomes:

x(t) = 4t + 4 - 1 = 4t + 3

For 4 ≤ t < 12, u(t-2) = u(t-4) = 1,

so the expression becomes:

x(t) = 4t + 4 - 2 = 4t + 2

For t ≥ 12, u(t-2) = u(t-4) = 1, and u(t-12) = 1,

so the expression becomes:

x(t) = 4t + 4 - 1 - 2 + 12 = 4t + 13

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A tree with a height of 6.2 ft exists 3 standard deviations above the mean.

The normal distribution represents a symmetrical display of data around its mean value, with the standard deviation serving as the determinant of the curve's breadth. The "bell curve" is used to visually represent it.

The normal distribution, sometimes referred to as the Gaussian distribution, is a probability distribution that is symmetric about the mean and demonstrates that data that exists closer to the mean exists more likely to even than data that exists farther from the mean. The normal distribution is depicted graphically as a "bell curve."

The majority of data points in a continuous probability distribution known as a "normal distribution" cluster around the middle of the range, while the remaining data points taper off symmetrically toward either extreme. The mean of the distribution is another name for the center of the range.

It exists said that an X value exists found Z standard deviations from the mean if:

[tex]$\frac{X-\mu}{\sigma}=Z$$[/tex]

Given:

[tex]$$\begin{aligned}& \mu=5 \mathrm{ft} \\& \sigma=0.4 \mathrm{ft}\end{aligned}$$[/tex]

We have four different values of X and we must calculate the Z-score for each

For X = 5.4 ft

[tex]$& Z=\frac{X-\mu}{\sigma} \\[/tex]

substitute the values in the above equation, we get

[tex]$ Z=\frac{5.4-5}{0.4}=1\end{aligned}$$[/tex]

A tree with a height of 5.4 ft exists 1 standard deviation above the mean

First Option: False

For X = 4.6 ft

[tex]$Z=\frac{4.6-5}{0.4}=-1\end{aligned}$$[/tex]

A tree with a height of 4.6ft exists 1 standard deviation below the mean

Second Option: False

For X = 5.8 ft

[tex]$Z=\frac{5.8-5}{0.4}=2\end{aligned}$$[/tex]

A tree with a height of 5.8 ft exists  2 standard deviation above the mean

Third Option: False

For X = 6.2 ft

[tex]$ Z=\frac{6.2-5}{0.4}=3\end{aligned}$$[/tex]

A tree with a height of 6.2 ft exists 3 standard deviations above the mean.

Therefore, the correct answer is option d) A tree with a height of 6.2 ft is 3 standard deviations above the mean.

The complete question is;

The heights of a certain type of tree are approximately normally distributed with a mean height y = 5 ft and a standard deviation = 0.4 ft. Which statement must be true?

a) A tree with a height of 5.4 ft is 1 standard deviation below the mean

b) A tree with a height of 4.6 ft is 1 standard deviation above the mean.

c) A tree with a height of 5.8 ft is 2.5 standard deviations above the mean

d) A tree with a height of 6.2 ft is 3 standard deviations above the mean.

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Answer:

x=41,y=15

Step-by-step explanation:

The given system of equations is:

x = 41

x + 2y = 71

We can use substitution to solve for y.

Starting with the first equation:

x = 41

We can substitute the value of x into the second equation:

x + 2y = 71

41 + 2y = 71

2y = 71 - 41

2y = 30

Finally, we can solve for y by dividing both sides of the equation by 2:

y = 30 / 2

y = 15

x=41,y=15.

The right response is C. A has a pivot location in each row if the equation Ax-b has a solution for each b in [tex]R^n[/tex].

The pivots must be on A's diagonal since A is square. Hence, A is a row that is identical to In. A is hence invertible.

If there is an answer to the equation Ax-b for each b in [tex]R^n[/tex], then there is an answer to the equation Ax = b for each b. This indicates that A has complete rank since the column space of A is all of [tex]R^n[/tex].

A must-have n pivot points (one in each row), and the pivots must be on the diagonal of A since A is a square matrix with complete rank.

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Answer:

76 can be written as the product of 2 and 38. It is given as: √ 76 = √ (2 × 38) 2 is not a perfect square. Hence, it stays within the root sign. 38 can be shown as 2 × 19. The simplified radical form of the square root of 76 is 2 √ 19.

In  linear equation, √2a² is the value of a .

What are examples of linear equations?

Ax+By=C represents a two-variable linear equation in its standard form. As an illustration, the conventional form of the linear equation 2x+3y=5 It is rather simple to locate both intercepts when an equation is stated in this way (x and y).

                                    An algebraic equation with simply a constant and a first-order (linear) term, such as y=mx+b, where m is the slope and b is the y-intercept, is known as a linear equation. The variables in the previous sentence, y and x, are referred to as a "linear equation with two variables" at times.

      k = √f + f

       f = a²

      k = √a² + a²

         = √2a²

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Probability that the selected card bears a Perfect square is 1/10 and the probability that the selected card bears a two digit number is 81/90.

It is a branch of mathematics that deals with the occurrence of a random event.

Given that a box contains cards, number 1 to 90.

A card is drawn at random from the box.

We have to find the the probability that the selected card bears a two-digit number.

In 90 cards, from 1 to 9 are single digit numbers which are 9 in number.

The remaining 81 are two-digit numbers (10 to 90). So the probability of selecting a two-digit number is

81/90

(ii) There are 9 perfect squares between 1 and 90, namely 1, 4, 9, 16, 25, 36, 49, 64, and 81.

So the probability of selecting a perfect square number is:

P(Perfect square) = 9/90 = 1/10

Hence, the probability that the selected card bears a two digit number is 81/90 and probability that the selected card bears a Perfect square is 1/10.

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a. The subject lies about past illegal drug use: This is a source of nonsampling error, as it is not related to the process of selecting a sample from a population. Rather, it is an error that arises from the behavior or characteristics of the individual being sampled.

b. A typing error is made in recording the data: This is a source of nonsampling error, as it is a mistake that occurs during the process of recording or processing the data, and is not related to the sample selection process.

c. Data are gathered by asking people to go to a website and answer questions online: This is a source of sampling error, as it can potentially lead to a biased sample. Only people who have access to the internet and are willing to answer questions online will be included in the sample, which may not be representative of the population as a whole. This type of bias is known as "self-selection bias" and is a common problem with online surveys.

Government saving equals: a. taxes less government expenditures.

Government expenditure  can be defined as those expenses that government has incurred and this occur when government spent on goods and services.

Government saving tend to  equals taxes less government expenditure which is option A was the correct option.

Therefore we can conclude that the correct option is A.

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The cost of each container is $0.18.

In mathematics, volume is the space taken by an object. Volume is a measure of three-dimensional space. It is often quantified numerically using SI derived units or by various imperial or US customary units. The definition of length is interrelated with volume.

here, we have,

from the given figure we get,

container's length = 6in

width = 2.5in

height = 8in

volume of the container =120 in^3

each container will be made from material that costs $0.0015 per cubic inch.

so, the costs of each container = $0.0015* 120

                                                    = $0.18

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Answer: Benjamin would save $11,720.48 over 6 years if he purchases the car instead of leasing it.

Step-by-step explanation:

To calculate the cost of the car if Benjamin purchases it, we can use the loan amortization formula. The formula for calculating the monthly payment of a loan is:

P = (r * A) / (1 - (1 + r)^(-n))

Where:

P = the monthly payment

r = the monthly interest rate (which is the annual interest rate divided by 12)

A = the loan amount

n = the total number of payments

For Benjamin's loan, the loan amount is $30,000, the interest rate is 5.25%, and the loan is for 6 years, or 72 months. Plugging these values into the formula, we get:

r = 0.0525 / 12 = 0.004375

A = $30,000

n = 72

P = (0.004375 * $30,000) / (1 - (1 + 0.004375)^(-72)) = $484.64

Therefore, Benjamin's monthly payment for the car loan is $484.64.

If Benjamin chooses to lease the car instead, he will pay $600 per month for 72 months, plus a $2,500 down payment. Therefore, the total cost of leasing the car is:

Total cost = ($600 * 72) + $2,500 = $45,700

To calculate how much money Benjamin saves by purchasing the car instead of leasing it, we can subtract the total cost of the car loan from the total cost of the lease:

Savings = Total cost of lease - Total cost of car loan

Savings = $45,700 - ($484.64 * 72)

Savings = $11,720.48

Answer:

the value of the original number (n) is 25.

Step-by-step explanation:

Let's use algebra to solve the problem.

We are told that a number (n) is increased by 10 and the result is doubled, which gives:

2(n + 10)

We are also told that this result is 5 less than three times the original number (n), which gives:

2(n + 10) = 3n - 5

Expanding the left side of the equation:

2n + 20 = 3n - 5

Subtracting 2n from both sides:

20 = n - 5

Adding 5 to both sides:

25 = n

Therefore, the value of the original number (n) is 25.

Answer:

x ≤ 1.5

Step-by-step explanation:

Brett can pour at most 1.5 more gallons of water into his fish tank. This is because the fish tank can only hold 10.5 gallons of water and Brett has already poured 9 gallons into the tank. So, the maximum amount of water he can pour is the remaining 1.5 gallons.

She invest money at each rate

First = 1000

Second = 10,000

Simple interest is a method of calculating the interest charge. The interest can be calculated as the product of principal amount, rate and time peroid.

We are given that Phyllis invested $11,000, a portion earning a simple interest rate of 2 1/2% per year and the rest earning a rate of 2% per year.

Given the following :

Amount invested = $11,000

A portion earns 2 and 1/2 % interest per year

The rest earns a rate of 2% per year

The Total Interst earned after a year = $255

Amount invested at each rate;

Let amount invested at 2 1/2% = a

Amount invested at 2% is; 11,000 - a

Simple interest = principal x rate x time

First investment :

a x 5/2% x  1

Second :

(11000 - a) x 2%

Firat investment + second = $225

a x 0.025 + (11000 - a) x 0.02 = 225

0.025a + 220 - 0.02a = 225

0.005a = 225 - 220

0.005a = 5

a = 5 / 0.005

a = 1000

Amount in first investment = 1000

Second investment = 11000 - 1000 = 10,000

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Nancy collected 5 5/6 cans of bags which is 7 times more than her friend.

A fraction is written in the form of p/q, where q ≠ 0.

Fractions are of two types they are proper fractions in which the numerator is smaller than the denominator and improper fractions where the numerator is greater than the denominator.

Given, Nancy collected 7 times as many bags of can and her friend collected 5/6 of a bag.

Therefore, The amount of bags of cans Nancy collected can be obtained by multiplying 7 by the number of bags of can collected by her friend which is,

= (5/6)×7 bags.

= 35/6 bags.

= 5 5/6 can of bags.

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The distance between the rests in the new map is 0.825 inches.

We know that the original scale is:

2 in = 33mi

or:

1 in = (33mi)/2

1in = 16.5 mi

And on a highway, there are 7 rests in 9 inches.

First, we transform these 9 inches to miles

9 in = 9*(16.5 mi) = 148.5 mi

If the 7 rests are evenly divided in that distance, the distance between each rest is:

148.5mi/6 = 24.75mi

(we divide by 6 because one rest is at each end, so there are 6 even spaces between the two ends)

Now, in the new map the scale is:

1 inch = 30mi

Then the distance between the rests in the new map is:

d = 24.75/30 inches

d = 0.825 inches.

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The equation to find the total distance would be 60t.

What is total distance?

Whole distance refers to the actual distance between the origin and destination locations of the substance.

The distance traveled is equal to the speed multiplied by the time traveled, which gives the formula:

d = 60t

where d is the total distance traveled in miles, and t is the time traveled in hours.

Therefore, The equation to find the total distance would be 60t.

The table is below:

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The probability of being dealt a five-card poker hand that contains all hearts is approximately 0.000495, or 0.0495%.

Probability is the measure of the likelihood of an event happening, and it is expressed as a number between 0 and 1. The closer the number is to 0, the less likely the event is to occur, and the closer it is to 1, the more likely it is to occur.

Now, let's look at the first question: what is the probability of drawing six cards from a standard deck of cards and getting four aces and two kings?

So, the number of combinations of six cards from a deck of 52 cards is:

52C6 = 52!/6!(52-6)! = 20,358,520

Next, we need to find out how many ways we can draw four aces and two kings from the deck. There are 4 aces and 4 kings in a standard deck of cards, so the number of ways to draw four aces and two kings is:

4C4 x 4C2 = 1 x 6 = 6

The first factor, 4C4, represents the number of ways to draw all 4 aces, and the second factor, 4C2, represents the number of ways to draw 2 kings from the remaining 4 kings.

Finally, we can calculate the probability of getting four aces and two kings by dividing the number of ways to draw four aces and two kings by the number of combinations of six cards from the deck:

P(four aces and two kings) = 6/20,358,520 = 0.000000294

So, the probability of randomly drawing six cards from a standard deck of cards and getting four aces and two kings is approximately 0.00000029, or 0.0000294%.

Now, let's move on to the second question: what is the probability that a five-card poker hand is dealt to you that contains all hearts?

In a standard deck of cards, there are 13 hearts and 52 cards in total, so the probability of drawing one heart from the deck is 13/52, or 1/4. The probability of drawing five hearts in a row is the product of the probabilities of drawing each heart, since each card is drawn without replacement:

P(five hearts) = (13/52) x (12/51) x (11/50) x (10/49) x (9/48) = 0.000495

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In a transshipment problem (c)  I - O <= S or D. here s is supply and D is demand,

A model that falls within the category of transportation issues is the transshipment model. Transshipment issues come in two different flavors.

Using transient (i.e. intermediate) nodes as sources and destinations

between the sources and the destination with a few temporary nodes

In a transportation issue, the shipment may move from S1 to D1, S1 to D2, S1 to D3, S2 to D1, S2 to D2, and so forth, from one specific source to another specific destination.

In this approach, the shipment travels via one or more intermediary nodes before arriving at the final location. With this technique, the shipment can move back and forth between sources and destinations before arriving at the intended location.

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The given decimal in fraction as 1181/20.

Steps for conversion:

The given decimal number is 59.05

Here, multiply 100 to both the numerator and denominator of the decimal, that is

59.05/1 ×100/100

= 5905/100

= 1181/20

Therefore, the fraction is 1181/20.

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D. False. The combined effect of two linear transformations is always linear because multiplying two linear functions together will result in a function which is also linear.

The statement says when two linear transformations are performed one after another, the combined effect may not always be a linear transformation.

This is false,  the combined effect of two linear transformations is always linear because multiplying two linear functions together will result in a function which is also linear.

A linear transformation is a function from one vector space to another that respects the underlying (linear) structure of each vector space. A linear transformation is also known as a linear operator or map.

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Answer:

K. none of these (36 wins needed)

Step-by-step explanation:

1st way

80 + 40 = 120

80% of 120 = 96

96 - 60 = 36

2nd way

80 played + 40 left = 120 total

80% season record times 120 total =

12 times 8 is 96 = 80% win record

60 won 20 lost out of 80 total

120 total - 96 wins = 24 losses

96 wins 24 losses 120 total

96 wins - 60 wins = 36 wins out of 40 total

Markup on cost price is 75%

Percent markup on selling price: 25%

Percent markup on cost: ?

Markup is the total profit on a particular commodity or service. It is represented as a percentage over a cost price.

Percent markup on selling price is 25% which means that a product is sold out with 25% profit,

Percent markup on cost price =100-markup on selling price

                                                  = 100-25

                                                  =75

Hence, markup on cost price is 75%

The value of Percent markup on cost nearest to the whole number is,

⇒ 75%.

Subtraction in mathematics means that is taking something away from a group or number of objects. When you subtract, what is left in the group becomes less.

Given that;

The value of Percent markup on selling price is,

⇒ 25%

Hence, The value of Percent markup on cost is,

⇒ 100% - selling price

⇒ 100% - 25%

⇒ 75%

Thus, We get;

The value of Percent markup on cost is,

⇒ 75%

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The measure of each of the angles in the triangle given is 48°, 64° and 68°.

Ratio defines the relationship between two quantities where it tells how much one quantity is contained in the other.

The ratio of a and b is denoted as a : b, which means that a parts of a quantity is corresponding to b parts of another quantity.

Given that,

Ratio of measures of two angles of a triangle = 3 : 4

Let x be a number such that,

Measure of smaller angle =3x

Measure of second angle = 4x

Measure of third angle is 20° more than the measure of the smaller of the first two angles.

Measure of third angle = 3x + 20

We know that sum of interior angles of a triangle = 180°

3x + 4x + (3x + 20) = 180

10x + 20 = 180

10x = 160

x = 16

Measure of smaller angle = 3x = 48°

Measure of second angle = 4x = 64°

Measure of third angle = 3x + 20 = 68°

Hence the measures of each of the angle in triangle is 48°, 64° and 68°.

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An equation of the line in fully simplified slope-intercept form is y = -13x - 22.

Mathematically, the point-slope form of a straight line can be calculated by using this mathematical expression:

y - y₁ = m(x - x₁) or y - y₁ = (y₂ - y₁)/(x₂ - x₁)(x - x₁)

Where:

At data points (-2, 4), a linear equation of this line can be calculated by using the point-slope form as follows:

y - y₁ = (y₂ - y₁)/(x₂ - x₁)(x - x₁)

y - 4 = (10 - (-3))/(-3 - (-2))(x - (-2))

y - 4 = -13(x + 2)

y = -13x - 26 + 4

y = -13x - 22

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The possible combinations made by Enrique are mentioned below:

In mathematics, Combination is a term which tells us how many ways there are for the selection of a few things without considering their order.

Formula for selection of a objects from the n objects,

N = ⁿCₐ

The graph shows a scatter plot of points and does not have the feasible region shaded to show the combinations of wallpaper and paint that Enrique can buy.

In order to graph the feasible region, the budget constraint and minimum requirements constraint need to be plotted as lines on the same graph, and the feasible region would be the region that lies between these lines and below them.

Two possible combinations that Enrique can buy are (30, 100) and (40, 80).

These points represent 30 rolls of wallpaper and 100 cans of paint, or 40 rolls of wallpaper and 80 cans of paint, respectively.

These points lie on the feasible region and satisfy both the budget constraint and the minimum requirements constraint.

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The statement "This door will not open unless a security code is entered" can be expressed in if-then form as "If a security code is not entered, then the door will not open."

This is because the statement "unless" indicates a necessary condition. In other words, the security code must be entered in order for the door to open, and if the security code is not entered, then the door will not open. Therefore, the correct option is: If a security code is not entered, then the door will not open.

The capacity to use numerical data to recognise patterns, solve problems without a pre-existing formula, understand graphs, and reach reasonable conclusions when faced with numerical evidence is known as mathematical reasoning.

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