Choose two statements that are true for this expression.
4x^3 – 7x^2 – 30/y + 15
A. There are four terms.
B. There are three terms. 30
C. The term is a ratio.
D. The entire expression is a difference.​

Answer:

41.4%

Step-by-step explanation:

120/290 = x/100

290x = 120 * 100

x = 41.3793...

Answer:

X+Y=8W^2-7W+7

Step-by-step explanation:

HEY,... HERES YOUR ANSWER ! I HOPE I HELPED! BRAINLIEST WOULD BE APPRECIATED :)

THE QUESTION-->

X=7W^2+4W-6

Y=W^2-11W+13

X+Y=?

THE EXPLANATION-->

SO LETS JUST ADD BOTH EQUATIONS!

SO...

X+Y=7W^2+4W-6+W^2-11W+13

SIMPLIFY LIKE TERMS..

7W^2+W^2+4W-11W-6+13

SIMPLIFY EVEN FURTHER..

X+Y=8W^2-7W+7

THE ANSWER-->

X+Y=8W^2-7W+7

HOPE I HELPED

PLS MARK BRAINLIEST  

DESPERATELY TRYING TO LEVEL UP

✌ -ZYLYNN JADE ARDENNE

JUST A RANDOM GIRL WANTING TO HELP PEOPLE!

                   PEACE!

Answer:

The expected value of:

X = 3 green marbles

Step-by-step explanation:

Number of marbles in a bag = 11

Make-up of the bag = 6 red and 5 green marbles

Sussan selects 7 marbles from the bag

The probability of collecting from 5 of the green marbles = 0.45

The probability of collecting from 6 of the red marbles = 0.55

The expected value of X = the probability of selecting a green marble multiplied by the number of marbles selected

= 0.45 x 7

= 3 green marbles

Answer:

Step-by-step explanation:

Ara of a triangle = 1/2 * base * height.

Before we find the area, we must look for all the sides of the triangle by taking the difference between any two points.

Given D = √(x₂-x₁)²+(y₂-y₁)²

Given the coordinates P(7,-3), Q(4,-3), R(4,9)

For the coordinates P(7,-3), Q(4,-3)

Given PQ = √(4-7)²+(-3+3)²

PQ = √(-3)²+0

PQ =  √9

PQ = 3

For coordinates P(7,-3), R(4,9)

Given PR = √(4-7)²+(9+3)²

PR = √(-3)²+12²

PR =  √9+144

PR = √153

For coordinates Q(4,-3), R(4,9)

Given QR = √(4-4)²+(9+3)²

QR = √(0)²+12²

QR =  √0+144

QR = 12

Since it is a rright angled triangle, the base of the triamgle will be QR and the height will be PQ since the longest side is PR

Area of the triangle = 1/2 * PQ*QR

Area of the triangle = 1/2 * 12*6

Area of the triangle = 6*6

Area of the triangle = 36 square units

Answer:

the capacity of the airplane be 200 passengers

Step-by-step explanation:

According to the question, the data provided is as follows

Number of passengers in an airplane = 180

Capacity = [tex]\frac{9}{10}[/tex]

Based on the above information

Let us assume the capacity of the airplane be x

So the equation would be

[tex]\frac{9}{10} \times x = 180\\\\\\x = \frac{1,800}{9}[/tex]

So x = 200

Therefore the capacity of the airplane be 200 passengers

We simply applied the above equation so that the capacity of the airplane could come

Answer/Step-by-step Explanation:

When calculating the length of a segment on a number line, the absolute value of the difference between one point on the numberline, and another point is what we're looking for.

1. Length of RS = |-5 - (-2)| = |-5 + 2| = |-3|

RS = 3

2. Length of RT = |-5 - 2| = |-7|

RS = 7

3. Length of ST = |-2 - 2| = |-4|

ST = 4

4. Length of RU = |-5 - 8| = |-13|

RU = 13

5. Given that the following coordinates:

P = 3

Q = 8

R = 14

5. PQ = |3 - 8| = |-5| = 5

6. QR = |8 - 14| = |-6| = 6

7. PR = |3 - 14| = |-11| = 11

Given that points A, B, C, and D are collinear, and AB = x, BC = 3x, CD = 4x - 13

8. If AC = 24,

BC can be calculated as follows:

AB + BC = AC

[tex] x + 3x = 24 [/tex]

Solve for x

[tex] 4x = 24 [/tex]

Divide both sides by 4

[tex] x = 6 [/tex]

Thus,, BC = 3x = 3(6) = 18

BC = 18

9. If BC = 15, BD can be calculated as follows:

Find the value of x first

BC = 3x

15 = 3x

Divide both sides by 3

5 = x

x = 5.

BD = [tex] 3x + (4x - 13) [/tex]

Plug in the value of x

BD = [tex] 3(5) + (4(5) - 13) = 15 + (20 - 13) [/tex]

BD = [tex] 15 + 7 = 22 [/tex]

BD = 22

10. m<PTR = 80° (taking the reading at the top from 0°)

11. m<PTQ = 45°

12. m<QTS = 128 - 45 = 83°

13. Luis read m<QTR wrongly, what he measured was the whole of <PTR.

According to the angle addition theorem, m<QTR = 80 - 45 = 35°.

Answer:

B. 7 + y = y + 7

Step-by-step explanation:

Commutative property of addition describe an equation in which the order of addition has no effect on the outcome of the sum. The result of addition of the expressions on the left hand side is the same as that on the right hand side. It requires only an addition to property.

In the given question, the equation that shows the correct application of commutative law of addition is; 7 + y = y + 7

Answer:

Parallel

Step-by-step explanation:

-x+6 slope:-1

X+y=20 slope -1

Hence the answer is parallel

Answer:

No

Step-by-step explanation:

because the answer is 7

2x + 7 = 3x

2x + 7 - 7 = 3x - 7

2x = 3x - 7

2x - 3x = 3x - 7 - 3x

-x = -7

x = 7

(A)

[tex]\dfrac{\partial f}{\partial x}=-16x+2y[/tex]

[tex]\implies f(x,y)=-8x^2+2xy+g(y)[/tex]

[tex]\implies\dfrac{\partial f}{\partial y}=2x+\dfrac{\mathrm dg}{\mathrm dy}=2x+10y[/tex]

[tex]\implies\dfrac{\mathrm dg}{\mathrm dy}=10y[/tex]

[tex]\implies g(y)=5y^2+C[/tex]

[tex]\implies f(x,y)=\boxed{-8x^2+2xy+5y^2+C}[/tex]

(B)

[tex]\dfrac{\partial f}{\partial x}=-8y[/tex]

[tex]\implies f(x,y)=-8xy+g(y)[/tex]

[tex]\implies\dfrac{\partial f}{\partial y}=-8x+\dfrac{\mathrm dg}{\mathrm dy}=-7x[/tex]

[tex]\implies \dfrac{\mathrm dg}{\mathrm dy}=x[/tex]

But we assume [tex]g(y)[/tex] is a function of [tex]y[/tex] alone, so there is not potential function here.

(C)

[tex]\dfrac{\partial f}{\partial x}=-8\sin y[/tex]

[tex]\implies f(x,y)=-8x\sin y+g(x,y)[/tex]

[tex]\implies\dfrac{\partial f}{\partial y}=-8x\cos y+\dfrac{\mathrm dg}{\mathrm dy}=4y-8x\cos y[/tex]

[tex]\implies\dfrac{\mathrm dg}{\mathrm dy}=4y[/tex]

[tex]\implies g(y)=2y^2+C[/tex]

[tex]\implies f(x,y)=\boxed{-8x\sin y+2y^2+C}[/tex]

For (A) and (C), we have [tex]f(0,0)=0[/tex], which makes [tex]C=0[/tex] for both.

Answer:

[tex]\huge\boxed{\text{next term}=4}\\\boxed{f(n)=4^{n-4}}[/tex]

Step-by-step explanation:

[tex]\dfrac{1}{64},\ \dfrac{1}{16},\ \dfrac{1}{4},\ 1,\ ...[/tex]

It's the geometric sequence where

[tex]a_1=\dfrac{1}{64},\ q=4[/tex]

[tex]\dfrac{1}{16}=\dfrac{1}{64}\cdot4\\\\\dfrac{1}{4}=\dfrac{1}{16}\cdot4\\\\1=\dfrac{1}{4}\cdot4\\\\1\cdot4=4\to\text{next term}[/tex]

[tex]f(n)=\dfrac{1}{64}\cdot4^{n-1}=\dfrac{1}{4^3}\cdot4^{n-1}=\dfrac{4^{n-1}}{4^3}\\\\\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\f(n)=4^{n-1-3}=4^{n-4}[/tex]

Answer:

The solution is (3, -3)

Step-by-step explanation:

5x + 2y = 9

2x - 3y = 15

Use elimination by addition/subtraction.  Multiply the first equation by 3 and the second by 2, obtaining:

15x + 6y = 27

4x   - 6y  =  30

----------------------

19x        = 57

This yields x = 3.

Substituting 3 for x into 5x + 2y = 9, we get  5(3) + 2y = 9, or

15 + 2y = 9, or

2y = -6

This yields y = -3.

The solution is (3, -3)

Answer:

1

Step-by-step explanation:

.25 is already a rational number as it equals 25/100 and 1/4 simplified

Answer:

d

Step-by-step explanation:

im pretty sure the right answer would be 12 and 21 just doesn't look right

Answer:

120 babies

Step-by-step explanation:

Divide 12 by 0.1:

12/0.1

= 120

So, 120 babies were born each day.

Answer:

Kindly check explanation

Step-by-step explanation:

Waiting times collected over a one month period:

2 5 10 12 4 4 5 17 11 8 9 8 12 21 6 8 7 13 18 3

A)

Class(x) - - frequency(f)

0-4 - - - - - 4

5-9 - - - - - - 8

10-14 - - - - - 5

15-19 - - - - - 2

20-24 - - - - 1

B)

Class(x) - - frequency(f)- - relative frequency(rf)

0-4 - - - - - 4 - - - - - - - - - - 4/20 = 0.20

5-9 - - - - - - 8 - - - - - - - - - - 8/20 = 0.40

10-14 - - - - - 5 - - - - - - - - - - 5/20 = 0.25

15-19 - - - - - 2 - - - - - - - - - - 2/20 = 0.10

20-24 - - - - 1 - - - - - - - - - - - 1/20 = 0.05

C)

Class(x) - - frequency(f) - - cumulative frequency

0-4 - - - - - 4 - - - - - - - - - - - 4

5-9 - - - - - - 8 - - - - - - - - - - - 12

10-14 - - - - - 5 - - - - - - - - - - - 17

15-19 - - - - - 2 - - - - - - - - - - - 19

20-24 - - - - 1 - - - - - - - - - - - - 20

D)

Class(x) - - f - - cf - - - - rf - - - - - - crf

0-4 - - - - 4 - -- 4 - - - 0.20 - - - 0.20

5-9 - - - - - 8 - - 12 - - - 0.40 - - - 0.60

10-14 - - - 5 - - -17 - - - 0.25 - - - 0.85

15-19 - - - 2 - - - 19 - - - 0.10 - - - 0.95

20-24 - - 1 - - - 20 - - 0.05 - - - 1.00

crf - cumulative relative frequency

rf - relative frequency

cf - cumulative frequency

E) 0.6 (from the cumulative relative frequency column)

9 minutes or less :

Frequency = 12, total frequency = 20

12 / 20 = 0.6

The frequency distribution of the given data and frequency table for them would be presented as mentioned below.

Frequency Distribution

Given that,

Data

2 5 10 12 4 4 5 17 11 8 9 8 12 21 6 8 7 13 18 3

a). The use of classes to create a frequency distribution through classes would be as follows:

Class(X)                             frequency(f)

0-4                                          4

5-9                                          8

10-14                                        5

15-19                                        2

20-24                                       1

b). The relative frequency distribution would be as follows:

Class(X)                             frequency(f)              relative frequency(rf)

0-4                                          4                                  4/20 = 0.20

5-9                                          8                                 8/20 = 0.40

10-14                                        5                                 5/20 = 0.25

15-19                                        2                                 2/20 = 0.10

20-24                                       1                                 1/20 = 0.05

c). The cumulative frequency distribution would be as follows:

Class(X)                             frequency(f)              cumulative frequency(cf)

0-4                                          4                                  4

5-9                                          8                                 12

10-14                                        5                                 17

15-19                                        2                                 19

20-24                                       1                                 21

d). The cumulative frequency distribution employing classes in part a would be as follows:

Class(X)           (f)                           (cf)               rf                 crf

                    Frequency      Cumulative     Relative   Cumulative Relative

                                                  Frequency   Frequency   Frequency

0-4                    4                               4              0.20               0.20

5-9                    8                               12            0.40                0.60

10-14                 5                                17             0.25                0.85

15-19                 2                                19             0.10               0.95

20-24               1                                 21             0.05                  1

e). The proportion of customers requiring an oil change wait 9 minutes would be:

Frequency [tex]= 12[/tex]

Total Frequency [tex]= 20[/tex]

The Proportion of customers requiring an oil change wait 9 minutes or less

[tex]= 12/20\\= 0.6[/tex]

Learn more about "Frequency Distribution" here:

brainly.com/question/7523130

Answer:

[tex]\frac{a}{b} = \frac{3}{10}[/tex]

Step-by-step explanation:

Given

[tex]Number = 0.3[/tex]

Required

Represent as [tex]\frac{a}{b}[/tex]

Let [tex]\frac{a}{b} = 0.3[/tex]

This can be further written as

[tex]\frac{a}{b} = \frac{0.3}{1}[/tex]

Multiply the numerator and denominator by 10

[tex]\frac{a}{b} = \frac{0.3 * 10}{1 * 10}[/tex]

[tex]\frac{a}{b} = \frac{3}{10}[/tex]

Since 3 and 10 are both integers, then

[tex]\frac{a}{b} = \frac{3}{10}[/tex]

Complete  Question

The complete question is shown on the first uploaded image

Answer:

The standard deviation is  [tex]\sigma = 1.17[/tex]      

Step-by-step explanation:

From the question we are told that

   The data is  

 x          1  2  3        4

P(X = x)    0.2 0.2 0.2   0.4  

 Generally the standard deviation is mathematically represented as

           [tex]\sigma = \sqrt{ \sum x^2 P(x) - (\sum x P(x))^2 }[/tex]

Here    [tex]x^2 = 1^2 \ \ 2^2 \ \ 3 ^2 \ \ 4^2[/tex]

    =>     [tex]x^2 = 1 \ \ 4 \ \ 9\ 16 \[/tex]

      [tex]\sum x^2 * P(x) = (1 * 0.2) + (4 * 0.2 ) + (9 * 0.2 ) + (16 * 0.2 )[/tex]

     [tex]\sum x^2 * P(x) = 9.4[/tex]

      [tex]\sum x P(x) = (1 *0.2) + (2*0.2) + (3 * 0.2) + (4 * 0.2)[/tex]

     [tex]\sum x P(x) = 2.8[/tex]

So  

    [tex]\sigma = \sqrt{ 9.2 - (2.8)^2 }[/tex]            

    [tex]\sigma = 1.17[/tex]        

Complete Question

A newsletter publisher believes that above 41% of their readers own a personal computer. Is there sufficient evidence at the 0.10 level to substantiate the publisher's claim?

State the null and alternative hypotheses for the above scenario.

Answer:

The null hypothesis is  [tex]H_o : p \le 0.411[/tex]

The  alternative hypothesis  is  [tex]H_a : \mu > 0.41[/tex]

Step-by-step explanation:

From the question we are told that

   The  proportion is  [tex]p = 0.41[/tex]

Generally the null hypothesis is  [tex]H_o : p \le 0.411[/tex]

The  above condition represents the  null hypothesis because it contains and equality in its condition

  The  alternative hypothesis  is  [tex]H_a : \mu > 0.41[/tex]

Answer:

we accept the alternate hypothesis that

there is a difference between the rate of medical malpractice lawsuits that go to trial and the rate of such lawsuits that are dropped or dismissed.

Step-by-step explanation:

We first write out our null and alternate hypothesis.

H0: no difference

H1: there is difference

n = 1228

P = 856

X = n-p

= 372

Z = ((x+0.5)-1228/2) divided by √1228/2

= 372.5 - 614/17.52

= -13.784

|Z|= 13.784

The decision is to reject the null hypothesis and accept the alternate because there is evidence that dismissed lawsuit if bigger than 0.5. so there is difference between lawsuits that go to trial and lawsuits that are dismissed

Answer:

y = (3/4)x - 6

Step-by-step explanation:

if line is parallel to -3x + 4y = 4, that means that they both have the same slope

Slope of that second line is 3/4.

now time to find the y-intercept

0 = 3/4*8 + b

therefore, b = -(3/4)*8 = -3*2 = -6

Therefore, equation of line is y = (3/4)x - 6

Answer:

  [tex]\dfrac{-4x+7}{2(x-2)}[/tex]

Step-by-step explanation:

Write the terms of numerator and denominator using a common denominator.

  [tex]\dfrac{\dfrac{3}{x-1}-4}{2-\dfrac{2}{x-1}}=\dfrac{\left(\dfrac{3-4(x-1)}{x-1}\right)}{\left(\dfrac{2(x-1)-2}{x-1}\right)}}=\boxed{\dfrac{-4x+7}{2(x-2)}}[/tex]

Answer: It's B on Edge 1843

Step-by-step explanation:

Don't listen to the guys in the comments they have peanuts for brains

Answer:

K = 4 ; N = 106

Step-by-step explanation:

Given the following :

Source of VARIATION - SS - df - - MS - - - - - F

Between groups - 1,959.79 - 3 - - 653.26 - 21.16*

Error - - - - - - - - 3,148.61 - - - - 102 - - 30.86

Total - - - - - - - - - - - 5,108.41 - 105

The degree of freedom between group (treatment) (DFT) is obtained using the formula ;

K - 1, where k = number of groups observed

DFT = K - 1 ; From the ANOVA table, DFT = 3

3 = K - 1

3 + 1 = K

K = 4

To obtain sample size (N) :

Degree of freedom of Error (DFE) is the difference between the sample size and the number of groups observed.

DFE = N - K ; From. The table DFE = 102 ; K = 4

102 = N - 4

102 + 4 = N

N = 106

Your question has been heard loud and clear.

2^0= 1

5^1= 5

4^3=64

2^0+5^1+4^3/7= 1+5+64/7 =  6+64/7= 15.14

So , 2^0+5^1+4^3/7 =  15.14

Thank you

Answer:

504  

Step-by-step explanation:

I think the correct question is like:The common ratio in a geometric series is 0.50 ( point 5) and the first term is 256.  

Find the sum of the first 6 terms in the series.

If it's right, then

Sₙ = (a₁ × (1 - rⁿ)) / (1 - r)

S₆ = (256 × ( 1 - 0.5⁶)) / (1 - 0.5)

= (256 × 0.984375) / 0.5

= 504

hope it will help :)

Answer:  3x-180

Step-by-step explanation:

Given: Expression for Revenue = [tex]5x^2 + 2x - 80[/tex]

Expression for Cost = [tex]5x^2- x + 100[/tex]

If profit is the difference between the revenue and the cost then the expression for profit will be:

Profit = Revenue - cost

[tex]=5x^2 + 2x - 80-(5x^2- x + 100)\\\\=5x^2 + 2x - 80-5x^2+x-100\ \ [\text{Multiply ' - ' sign inside the bracket}]\\\\=2x+x-80-100\\\\=3x-180[/tex]

Hence, the expression represents the profit is 3x-180 .

Answer:

its 3x-180 and for the seond one its $2,820

Step-by-step explanation:

got it right on edge

Answer:

It will take Clara more than  

16

weeks and up to and including  

32

weeks to grow out her hair.

Answer:

It will take Clara more than 16 weeks and up to and including 32 weeks to grow out her hair.

Step-by-step explanation: