Explanation:
Using percentage by volume (v/v)
When the solute is a liquid, it is sometimes convenient to express the solution concentration as a volume percent.
Formula
The formula for volume percent (v/v) is: [Volume of solute (ml) / Volume of solution (ml)] x 100
Example
Make 1000ml of a 5% by volume solution of ethylene glycol in water.
Procedure
First, express the percent of solute as a decimal: 5% = 0.05
Multiply this decimal by the total volume: 0.05 x 1000ml = 50ml (ethylene glycol needed).
Subtract the volume of solute (ethylene glycol) from the total solution volume:
1000ml (total solution volume) - 50ml (ethylene glycol volume) = 950ml (water needed)
Dissolve 50ml ethylene glycol in a little less than 950ml of water. Now bring final volume of solution up to 1000ml with the addition of more water. (This eliminates any error because the final volume of the solution may not equal the calculated sum of the individual components).
So, 50ml ethylene glycol / 1000ml solution x100 = 5% (v/v) ethylene glycol solution.
Which of the following pieces of lab equipment is used to protect eyes
Question 2 (0 points)
A spinner is spun and a die is rolled. What is the probability
of spinning red with the spinner or rolling an odd number with the
die.
red
/yellow
blue
green
Answer:
The probability of spinning red with the spinner or rolling an odd number with the die is [tex]\dfrac{1}{8}[/tex]
Explanation:
Given that,
Total color in spinner = 4
Let the area of four parts is equal in the spinner.
We need to calculate the probability of spinning red
Using formula of probability
[tex]P(A) = \dfrac{Number\ of\ red\ color\ outcome}{Total\ number\ of\ colors\ in\ the\ spinner}[/tex]
Put the value into the formula
[tex]P(A)=\dfrac{1}{4}[/tex]
We need to calculate the probability of odd number of the die
Using formula of probability
[tex]P(B) = \dfrac{Number\ of\ odd\ digits\ outcome}{Total\ number\ of\ digits\ in\ the\ die}[/tex]
Put the value into the formula
[tex]P(B)=\dfrac{3}{6}[/tex]
[tex]P(B)=\dfrac{1}{2}[/tex]
We need to calculate the probability of spinning red with the spinner or rolling an odd number with the die
Using formula of probability of two events which is independent
[tex]P(A\ and\ B)=P(A)\times P(B)[/tex]
Put the value into the formula
[tex]P(A\ and\ B)=\dfrac{1}{4}\times\dfrac{1}{2}[/tex]
[tex]P(A\ and\ B)=\dfrac{1}{8}[/tex]
Hence, The probability of spinning red with the spinner or rolling an odd number with the die is [tex]\dfrac{1}{8}[/tex]
The principal, Mrs. Integer tells Mrs. Apex to write down exactly what she is doing step by step. In the scientific method this is called ... a the conclusion. b the data. c the hypothesis d the observation e the procedure
Answer:
E. the procedure
Explanation:
In scientific experiments, several steps are taken in order to achieve a significant result. However, the steps involved when performing the experiment should be taken note of and written down in a very comprehensible manner. The written step by step process involved in an experiment is called the PROCEDURE.
A procedure should be a guide to performing the experiment by a new experimenter. It should include everything done during the experiment. In this case, Mrs. Integer is telling Mrs. Apex to write down all she is doing during the experiment in a step by step manner. In essence, the principal is simply asking her to write a PROCEDURE.
What did Henry Moseley contribute to the modern periodic table?
O A. He discovered the lanthanides and actinides.
O B. He identified all of the elements that are currently in the periodic
table.
O C. He ordered the elements based on atomic number.
O D. He ordered the elements based on atomic mass.
Answer:the answer c
Explanation: because he believes that properties of elemets are periodic function of there atomic number
Question 7 (5 points)
(01.03 LC)
The atoms and molecules in a liquid are in constant motion. As temperature decreases, what is true of the particles in the liquid? (5 points)
a.) The distance between the particles increases.
b.) The attraction between the particles decreases.
c.) The rate of particle movement decreases.
d.) The potential energy of the particles decreases.
Answ Es la B .
Explanation
By raising the temperature of a liquid, it turns into a gas, therefore its particles will have more movement and its kinetic energy will increase. the more you raise the temperature, the more space they will have between the molecules.
What entropy change is associated with the reversible phase change from 1.0kg of ice to water at 0 ° C?
Answer:
1200 J/K
Explanation:
The formula for the entropy associated with a reversible phase change is
[tex]\Delta S= \dfrac{q_{\text{rev}}}{T}[/tex]
1. Calculate q
For a reversible phase change like melting,
[tex]q_{\text{rev}} = m\Delta_{\text{fus}}H = \text{1000 g} \times \dfrac{\text{334 J}}{\text{1 g}} = \text{334 000 J}[/tex]
2. Calculate ΔS
[tex]\Delta S = \dfrac{q_{\text{rev}}}{T} =\dfrac{\text{334 000 J}}{\text{273.15 K}} = \textbf{1200 J/K}[/tex]
A leaky faucet can waste 3,000 gallons of water per year. Which of the following is correct to convert the water wasted to liters/month? [1 gallon = 3.8 liters]
a
Divide 3,000 by 3.8
b
Multiply 3,000 by 12
c
Multiply 3,000 by 3.8 and divide the result obtained by 12
d
Divide 3,000 by 3.8 and multiply the result obtained by 12
Answer:
c
Multiply 3,000 by 3.8 and divide the result obtained by 12
A scientist wrote a report that communicates the steps he performed in an investigation, the data he gathered, and his conclusions. A second scientist used the report to carry out the same investigation. However, her results were very different. Are the results of the investigation described below valid? If not, what should the scientists do next? Explain your reasoning.
Answer:
yes, this is an acceptable practice in research.
Explanation:
Note that, having a different result in one's research does not imply it is automatically invalid. However, because there may have been some errors or limitations in the previous work by the male researcher, it is possible that the later results are more accurate, even though she used the same procedures. She may have been more careful when calculating her results.
Answer:
Since the results did not match, she should repeat the investigation again. If the data still cannot be replicated, then the results are not valid. In that case, the next step is to restart the process of inquiry from the beginning. An improved design might produce valid, repeatable results.
Explanation:
Alchemy is the process of trying to turn non-gold metals into gold. It was practiced hundreds of years ago by scientists who believed that with the right amounts of heat or chemical reactions, they could make gold. After years of experiments and observations, gold was never produced. Which best describes the practice of alchemy
Answer:
Alchemy is a practice of making gold from other metals.
Explanation:
Alchemy is a method which is practiced by the ancient scientists of Europe, Africa and Asia trying to produced gold from other metals. This method was failed to produced gold from metals and all scientist suggested that metals can not be converted into gold. Greeks were the people who presented the theory of alchemy in the first few centuries of CE.
Answer:
the answer is Alchemy was scientific because it included observations and experiments
Explanation:
i took the test
What is the mass, in grams, of 1.33 mol of water, H2O? Express the mass in grams to three significant figures.
Explanation:
First find the mass of 1 mole of water (Molecular mass)
[tex] H_{2} O = 2H + O [/tex]
[tex]
= 2(1) + 32 [/tex]
[tex]
= 34 \: grams
[/tex]
Hence 1 mole of water is 34 g
Compare
1 mole = 34 g
1.33 mole = x g
[tex] \frac{x}{34} = \frac{1.33}{1} [/tex]
[tex]
x = 1.33 \times 34 [/tex]
[tex]
\color{blue}{\boxed{x = 45.2}} \: \: \: \: to \: 3 \: s.f.
[/tex]
Therefore 1.33 moles of water is 45.2 grams
The mass of the substances can be given by the molar mass and the moles of the substances. The mass of 1.33 mole of water is expressed in grams as, 23.94 grams.
What is mass?The mass has been defined as the product of the moles of the substance and the molar mass in grams per mole. The mass is given in grams and has a formula,
Moles = mass ÷ molar mass
Mass = molar mass × moles
Given,
Moles = 1.33 moles
Molar mass of water (H₂O) is calculated as = 2 (1) + 16= 18 grams per mole
Using the formula of mole, mass is calculated as:
Mass = molar mass × moles
mass = 1.33 × 18
= 23.94 grams
The mass of the substance can be calculated if the value of the molar mass and the moles of the substance has been known. The molar mass of the substance can be calculated by adding the mass of the individual masses of the element in a molecule.
Therefore, 1.33 mol of water contains 23.94 grams.
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Can anyone solve this please. I need this fastly
Answer:
Average atomic mass = 63.3896
Explanation:
Step 1: Find how much Cu-65 we have
1 - Amount of Cu-63 = Amount of Cu-65
1 - 0.6915 = Amount of Cu-65
Amount of Cu-65 = 0.305
Step 2: Find the average atomic mass of Cu
(0.6915 x 63) + (0.305 x 65) = Average atomic mass
(43.5645) + (19.825) = Average atomic mass
63.3895 = Average atomic mass
Therefore the average atomic mass of Cu is 63.3895 atomic mass units
is 0.0410 M−1 s −1 . We start with 0.105 mol C2F4 in a 4.00-liter container, with no C4F8 initially present. What will be the concentration of C2F4 after 3.00 hours ? Answer in units of M.
Answer:
After three hours, concentration of C₂F₄ is 0.00208M
Explanation:
The rate constant of the reaction:
2 C2F4 → C4F8 is 0.0410M⁻¹s⁻¹
As the units are M⁻¹s⁻¹, this reaction is of second order. The integrated law of a second-order reaction is:
[tex]\frac{1}{[A]} =\frac{1}{[A]_0} +Kt[/tex]
Where [A] and [A]₀ represents initial and final concentrations of the reactant (C₂F₄), K is rate constant (0.0410M⁻¹s⁻¹) and t is time of the reaction (In seconds).
3.00 hours are in seconds:
3 hours ₓ (3600 seconds / 1 hour) = 10800 seconds
Initial concentration of C2F4 is:
0.105mol / 4.00L = 0.02625M
Replacing in the integrated law:
[tex]\frac{1}{[A]_0}= \frac{1}{0.02625} +0.0410M^{-1}s^{-1}*10800s\\\frac{1}{[A]_0}=480.9M^{-1}[/tex]
[A] = 0.00208M
After three hours, concentration of C₂F₄ is 0.00208MWhich of the following best describes this sentence?
There were 20 flamingos at the zoo.
Group of answer choices
Qualitative observation
Quantitative observation
Qualitative inference
Quantitative inference
Answer:
i think quantitative observation
What units should be used when describing the density of oil?
Answer:
Generally, density is measured using he SI unit for measurement of density which is kg/m³ or the cgs units used to describe the density of a substance which is g/cm³
However, due to its nature (being composed of varying amount proportions of different compounds mixed together resulting in a variation of the density of naturally produced crude oil) of having different densities whereby the lighter oils are more easily processed than the heavier variety of oils, oil density is related to the quality of the oil and it is usually measures in API gravity as follows;
°API = (141.5/S.G.) - 131.5
Where;
API = American Petroleum Institute
S. G. = Specific gravity
As such the API gravity of fresh water with a S. G. of 1.0 has is 10 degrees
Explanation:
Zinc carbonate dissolves in water to the extent of 1.12 x 10-4 g/L at 25 C. Calculate the solubility product Ksp for ZnCO3 at 25 C.
Answer:
Ksp= 7.98 × 10^-13
Explanation:
According to the question, we are to calculate the solubility constant (Ksp) of Zinc carbonate (ZnCO3) in a dissolved solution.
The equilibrium of the reaction is:
ZnCO3 (aq) ⇌ Zn2+ (aq) + CO32- (aq)
According to this; 1 mole of Zinc carbonate (ZnCO3) dissolves to give 1 mole of Zinc ion (Zn2+) and 1 mole of carbonate ion (CO32-).
This illustrates that:
(Zn2+) = 1.12 x 10-4 g/L
(CO32-) = 1.12 x 10-4 g/L
However, 1.12 x 10-4 g/L is the solubility in mass concentration of ZnCO3, we need to convert it to molar concentration in mol/L by dividing by the relative molar mass of ZnCO3.
To calculate the molar mass of ZnCO3, we say:
Zn (65.4) + C (12) + 03 (16×3)
= 65.4+12+48
= 125.4g/mol.
Hence, molar concentration= 1.12 x 10-4 g/L / 125.4 g/mol
= 8.93 × 10^-7 mol/L.
Therefore;
Zn2+) = 8.93 x 10-7 mol/L
(CO32-) = 8.93 x 10-7 mol/L
Ksp = [Zn2+] [CO32-]
Ksp = (8.93 x 10-7) × (8.93 x 10-7)
Ksp = 7.98 × 10^-13
Which phase change absorbs energy? A. H2O (g) --> H2O (s) B. H2O (g) --> H2O (l) C. H2O (l) --> H2O (g) D. H2O (l) --> H2O (s)
Answer:
C. H2O (l) --> H2O (g)
Explanation:
Hello,
In this case, we need to remember that processes absorbing energy are those that have positive heat, it means, process that obtain energy from a certain source. In such a way, processes that need energy, in terms of phase chance are fusion, sublimation and evaporation, which are the change from solid to liquid, solid to gas and liquid to gas respectively. Therefore, for the given options, we can see that C. H2O (l) --> H2O (g) accounts for an evaporation process which actually absorbs energy.
Best regards.
WILL AWARD BRAILIEST Which of the following best describes the particles inside a propane tank and inside a glowing neon sign? A: The particles in both are charged. B: The particles of both fill up the entire space available to them. C: The particles in the propane tank take limited space and those in the glowing neon sign are uncharged. D: The particles in the propane tank are charged and those in the glowing neon sign fill up the entire space available.
Answer:
it is A as both are always charged
Explanation:
Answer: A the particle is always charged
Explanation:
Which of these discoveries contradict components of Dalton’s atomic theory? Check all of the boxes that apply.
Explanation:
ATOMIC THEORY
Lesson 1 - Page 5
J.J. Thomson
In 1897, English physicist J. J. Thomson (1856–1940) disproved Dalton’s idea that atoms are indivisible. When elements were excited by an electrical current, atoms break down into two parts. One of those parts is a negative tiny particle, which Thomson called a corpuscle in 1881. The term electron was introduced in 1891 by G. Johnstone Stoney (1826-1911) as a way to describe a “natural unit of electricity.” Thomson envisioned these negative charges embedded into positive charges, like an English plum pudding. The plums were the electrons and the pudding was the positive matter.
Thomson's idea of an atom did not survive very long. English physicist Ernest Rutherford (1871–1937) studied the effects of bombarding thin gold foil with alpha particles. Alpha particles are helium atoms that have lost their electrons and are positive. Rutherford’s model had a nucleus, which occupied a very small area toward the middle, and was positive. He used the term proton for the positive particles. However, his electrons were moving on the outside of the nucleus in no definable manner in his model.
A is Dalton's Model; B is Thomson;
and C is Ruthford's model of an atom
What is the light transmission of chlorine?
Explanation:
The Absorption of Light by Chlorine, Bromine and their Gaseous Mixtures
An infrared wave has a wavelength of 0.00005 m. What is this wavelength in
scientific notation?
A. 5.0 x 10-6 m
B. 5.0 x 10-5 m
C. 5.0 x 10-4 m
D. 5.0 x 10-3 m
Can someone please help me fast!!
Answer:
B. [tex] 5 \times {10}^{ - 5}\: m [/tex]
Explanation:
[tex]0.00005 \: m= 5 \times {10}^{ - 5} \: m \\ [/tex]
If anyone is good at chemistry do you mind helping? (●'◡'●)
• Before the balloon was placed inside the hot water, the pressure was the same inside and outside the balloon. The hot water raised the kinetic energy of the air molecules inside the balloon, expanding the balloon, through thermal expansion.
• (1) the pressure of air inside the balloon increased, (2) the volume of the inside of the balloon increased as well, and (3) the temperature of the balloon increased. Note that pressure and volume are inversely proportional, and pressure and temperature are directly proportional. Therefore as the temperature increases, the pressure inside will increase, causing an increase in the volume. At a certain point though the volume will increase too much as to cause a significant decrease in pressure.
• The air molecules will gain kinetic energy, hence (1) increasing the molecules's speed, and (2) heating the air molecules.
Convert each of the following lengths to the units requested.
A. 17.3 m to kilometers.
B. 2.56 m to kilometers
C. 567 dm to meters
D. 5.13 m to millimeters
Answer:
A=0.173 Km
B=0.00256 km
C=56.7 m
D=5130 mm
Explanation:
first we need to know that
[tex]1km=1000m\\\\1dm=0.1m\\\\1000mm=1m[/tex]
so we can form the following
[tex]\frac{1km}{1000m}=1\\\\\frac{0.1m}{1dm} \\\\\frac{1000mm}{1m}[/tex]
so in A
[tex]17.3m\\\\=17.3m*1\\\\=17.3m(\frac{1km}{1000m} )\\\\=0.0173km[/tex]
in B
[tex]2.56m\\\\=2.56m*1\\\\=2.56m(\frac{1km}{1000m} )\\\\=0.00256km[/tex]
in C
[tex]567dm\\\\=567dm*1\\\\=567dm(\frac{0.1m}{1dm} )\\\\=56.7m[/tex]
in D
[tex]5.13m\\\\=5.13m*1\\\\=5.13m(\frac{1000mm}{1m} )\\\\=5130mm[/tex]
Do objects with large masses always have large
weights? Explain
Answer:
No
Explanation:
No, as sometimes objects with large masses are very light since they aren't dense.
. What is the kinetic energy of a jogger with a mass of 65.0 kg traveling at a speed of 2.5 m/s?
Answer:
Kinetic energy=1/2mv^2.
1/2×65×2.5^2.
1/2×6.5×6.25.
1/2×40.625.
=20.3125Joules.
The branch of science which deals with the chemicals bond is called chemistry.
The correct answer is 20.3125J
The energy formed by the motion of particles is called kinetic energy. The formula is half of the product of the mass and velocity.
[tex]Kinetic\ energy=\frac{1}{2}mv^2.[/tex]
After putting the value:-
[tex]\frac{1}{2}*65*2.5^2.[/tex]
After solving the equation, the kinetic energy is 20.3125Joules.
Hence, the correct answer is 20.3125Joules.
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Can someone pls explain this to be step by step:
The density of a substance is 1.03g/cm? What would be the density in mg/mm'?
Answer:
Explanation:
You can do this by doing dimensional analysis.
The first step is to change grams to mg
1000 mg = 1 gram
So the fraction will look like this
1.03 g * 1000 mg/ 1 gram = 1030 mg (the grams cancel out)
Now move onto the volume. The volume is actually 1 cm^3. This becomes 1 cm^3 / 1000 mm^3
So the answer becomes
1030 mg / cm^3 * ( 1 cm^3/1000 mm^3) The cm^3 cancel out
1030 mg / 1000 mm^3
1.030 mg/ mm^3
The rate constant for a second-order reaction is 0.54 M-1s-1. What is the half-life of this reaction if the initial concentration is 0.39 M
Answer:
4.748 seconds
Explanation:
second-order is one in which the rate is proportional to the square of the concentration of one reactant. This can be expressed below;
2A----->P
Where
A is the reactant.
P is the product.
The rate can be expressed as
Rate= k[A]^2
Half-life reffers to time required to reduce the concentration of reactant to half of its initial value.
The half life of reaction can be calculated using below formula
Half-life =. 1/(K*I)
Where,
K = Rate constant = 0.54 1/ms
I = Initial concentration = 0.39 m
If we substitute these values we have
Half-life t(1/2) =1/(0.54×0.39)
=4.748 seconds
Therefore, the half life is 4.748 seconds
La rapidez a la que cantan los grillos de árbol es de 2.0 ×102 veces por minuto a 27°C, pero es sólo de 39.6 veces por minuto a 5°C. A partir de estos datos, calcule la "energía de activación" para el proceso del canto.
Answer:
51096J/mol = Energía de activación para el proceso del canto
Explanation:
Podemos solucionar este problema usando una forma de la ecuación de Arrhenius:
[tex]Ln\frac{K_2}{K_1} = \frac{-Ea}{R} (\frac{1}{T_2} - \frac{1}{T_1} )[/tex]
Donde K representa la velocidad de reacción (En este caso, la velocidad a la que cantan los grillos), Ea es la energía de activación, R la constante de los gases (8.314J/molK) y T representa la temperatura absoluta de 1, el estado inicial y 2, el estado final.
Estado inicial: K1 = 2.0x10²; T1 = 27°C + 273.15 = 300.15K
Estado final: K2 = 39.6; t2 = 5°C + 273.15 = 278.15K
Reemplazando en la ecuación:
[tex]Ln\frac{39.6}{2.0x10^2} = \frac{-Ea}{8.314J/molK} (\frac{1}{278.15K} - \frac{1}{300.15K} )\\\\-1.6195 = \frac{-Ea}{8.314J/molK}*2.6351x10{-4}K{-1}[/tex]
51096J/mol = Energía de activación para el proceso del cantoCite as principais características das tentativas de organização da Tabela periódica-Tríades de Dobereiner, o Parafuso Telúrico de Chancourtois e a Lei das Oitavas de Newlands.
Answer:
Todos os três cientistas classificaram os elementos de acordo com o peso atômico.
Explicação:
As características da Tabela Periódica da Tríade Dobereiner são as seguintes:
1. é uma das classificações mais antigas de elementos.
2. nesta classificação, o peso atômico de um átomo é igual à média dos outros dois pesos atômicos.
3. é baseado no peso atômico.
Características do parafuso telúrico de Chancourtois
1. É a primeira classificação baseada no peso atômico.
2. foi a primeira representação gráfica dos elementos da tabela periódica.
Características da Lei das Oitavas de Newlands
1. também organizou os elementos de acordo com o peso atômico.
2. Em uma linha há apenas sete elementos e o oitavo vem abaixo do primeiro elemento devido às mesmas propriedades físicas e químicas.
Given 1 in=2.54 cm, how many centimeters are in an average hand (9.50 inches) __ cm (3 significant figures)
Answer:
9.5 inches = 24.1 cm
Explanation:
Given that,
1 inch = 2.54 cm
We need covert 9.5 inches to cm. For this we will use unitary method. To convert 9.5 inches to cm multiply 2.54 and 9.5. So,
9.5 inches = (2.54 × 9.5) cm
9.5 inches = 24.13 cm
or
9.5 inches = 24.1 cm
Hence, this is the required solution.
What kind of mixture is spaghetti and meatballs? A) Solute B) Suspension C) Heterogeneous D) Homogeneous
Answer: C
Explanation:
Spaghetti and meatballs are Heterogeneous mixture. A heterogeneous mixture is a mixture that is not uniform in composition throughout the mixture.
What are heterogeneous mixtures?A heterogeneous mixture is one in which the composition is not uniform throughout.Vegetable soup is a diverse concoction. A spoonful of soup contains varying amounts of various vegetables and other soup ingredients. Concrete, oil, lettuce, and trail mix (no cement).There are numerous mixtures all around us. Soils are made up of a wide range of substances, and their compositions vary depending on the sample taken.The following scoop may contain earthworms, but it may also contain dirt and grass. Another example of a heterogeneous mixture is smog.This cloudy pollutant buildup is a combination of water and pollutants from gasoline and plastics combustion, possibly mixed with nitrogen oxide derivatives and ozone.To learn more about heterogeneous mixtures, refer
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