Choose the multiplication problem that correctly shows partial products.
A) A
B) B
C) C

Answer:

Width = 12in, Length = 17in

Step-by-step explanation:

We can create two expressions from the given statements:

1) L (length) = 5 + W (width)

and

2) 58 = 2L + 2W (the equation for rectangular perimeter)

Substituting L from the first equation into the second equation yields:

58 = 2(5+W) + 2W

Distributing the 2 and solving for W yields:

12in = W

Plug this back into the first expression,

L = 5 + 12

L = 17in

Answer:

width = 12 in

length = 17 in

Step-by-step explanation:

Let width of rectangle = x

⇒ length of rectangle = x + 5

Given:

Perimeter = 2 × width + 2 × length

⇒ 58  = 2x + 2(x + 5)

⇒ 58  = 2x + 2x + 10

⇒ 58  = 4x + 10

⇒ 48  = 4x

⇒ x = 12

Therefore,

width = x = 12 in

length = x + 5 = 12 + 5 = 17 in

Answer:

  see attached

Step-by-step explanation:

The values are plotted on the number line attached.

__

Each value is represented on the list both as a fraction and as a decimal. Equal values map to the same point on the number line.

  0.27 = 27/100

  0.49 = 49/100

  0.75 = 75/100

The location on the number line is found by effectively dividing the distance between 0 and 1 into 100 parts, then locating the point on the corresponding division. The attached number line shows the interval divided into 50 parts, so the given values will lie halfway between the grid marks on this number line.

Answer:

Step-by-step explanation:

Draw the third point at (0, 0). This would make the distance from (3,0) to (0,0) equal to 3, and the distance from (0,4) to (0,0) be 4.

Answer:

V(m) = [tex](4m+2)^3[/tex]

Step-by-step explanation:

The edge of the cube is increasing by 4 feet every minute

V(m) = [tex](4m + 2)^3[/tex]

Two is the starting sidelength of the cube, and 4m is how many feet the side of the cube has grown, depending on the number of minutes that have passed

Answer:

Asare is 17 and Felicia is 7.

Step-by-step explanation:

let x be felicia's current age and y be asare's age. The equation for their age is y=3x-4. If 3x-1 + x+3 = 30, that means that 4x+2=30, so 4x=28. If 4x=28, x=7. Felicia is 7 and 3*7-4=17.

7.5x11 = 4.85

82.5x = 4.85

*divide 82.5 on both sides*

x = 4.85 ÷ 82.5

x = 0.058788

Answer:

0.058787879

Step-by-step explanation:

(7.5)(x)(11)=4.85

82.5(x)=4.85

x=4.85÷82.5

x= 0.058787879

Answer:

132

Step-by-step explanation:

since they are 180 degrees subtract

Answer:

132

Step-by-step explanation:

since this is a 180 degree angle ABC will be

180-48

132

Step-by-step explanation:

the inner angle of 2 crossing segment lines is half of the sum of the 2 arc angles.

55 = (arc angle IG + arc angle JH)/2 = (76 + JH)/2

110 = 76 + JH

arc angle JH = 34°

The required arc angle JH measures 34 degrees.

In geometry, a chord is a line segment that connects two points on the circumference of a circle. The two endpoints of the chord lie on the circle, and the chord divides the circle into two segments - the major segment and the minor segment.

Given the problem, we are given that the inner angle measures 55 degrees. Thus, we can set up an equation using the formula and solve for the unknown value.

The equation is given as follows:

55 = (arc angle IG + arc angle JH)/2

We know that the arc angle IG measures 76 degrees, so we can substitute this value into the equation:

55 = (76 + arc angle JH)/2

Multiplying both sides of the equation by 2 yields:

110 = 76 + arc angle JH

Subtracting 76 from both sides of the equation gives:

arc angle JH = 34°

Therefore, the arc angle JH measures 34 degrees.

Learn more about chords here:

https://brainly.com/question/30009947

#SPJ2

Answer:

A. 65

Step-by-step explanation:

The sum of the measures of the interior angles of a triangle is always 180 degrees. This means that j+k+l = 180. j is equal to l, so I can rewrite this as k+2j = 180. k is 50, so 50+2j is 180, and 2j is 130. This means that j is 65.

Answer:

A. 65°

Step-by-step explanation:

We are given that <J ≅ <L  

We know that all angles in a triangle = 180°

K + J + L = 180

50 + 2J = 180

2J = 130

<J = 65°

I hope this helps!

Answer:

Width: 11.5 inches; Length: 16.5 inches

Step-by-step explanation:

Let l=length and w=width

l=w+5

2(w+5)+2w=56

4w=46

w=11.5, l=16.5

Answer:

⠀

Step-by-step explanation :

⠀

As it is given that, the length of a rectangle is 5 in longer than its width and the perimeter of the rectangle is 56 in and we are to find the length and width of the rectangle. So,

⠀

Let us assume the width of the rectangle as x inches and therefore, the length will be (x + 5) inches .

⠀

Now, According to the Question :

⠀

[tex]{\longrightarrow \qquad { \pmb{\frak {2 ( Length + Breadth )= Perimeter_{(Rectangle)} }}}}[/tex]

⠀

[tex]{\longrightarrow \qquad { {\sf{2 ( x + 5 + x )= 56 }}}}[/tex]

⠀

[tex]{\longrightarrow \qquad { {\sf{2 ( 2x + 5 )= 56 }}}}[/tex]

⠀

[tex]{\longrightarrow \qquad { {\sf{ 4x + 10= 56 }}}}[/tex]

⠀

[tex]{\longrightarrow \qquad { {\sf{ 4x = 56 - 10}}}}[/tex]

⠀

[tex]{\longrightarrow \qquad { {\sf{ 4x = 46}}}}[/tex]

⠀

[tex]{\longrightarrow \qquad { {\sf{ x = \dfrac{46}{4} }}}}[/tex]

⠀

[tex]{\longrightarrow \qquad{ \underline{ \boxed { \pmb{\mathfrak {x = 11.5}} }}} }\: \: \bigstar[/tex]

⠀

Therefore,

⠀

Now, We are to find the length of the rectangle:

[tex]{\longrightarrow \qquad{ { \frak{\pmb{Length = x + 5 }}}}}[/tex]

⠀

[tex]{\longrightarrow \qquad{ { \frak{\pmb{Length = 11.5 + 5 }}}}}[/tex]

⠀

[tex]{\longrightarrow \qquad{\underline{\boxed { \frak{\pmb{Length = 16.5}}}}}} \: \: \bigstar[/tex]

⠀

Therefore,

⠀

Answer:

C is the correct answer hope i helped

Step-by-step explanation:

Answer: 8/12

Step-by-step explanation:

1/4 times 3 will give you 3/12 and add 5/12

Answer:

I've done this question: Its batch 5

Step-by-step explanation:

It has to be all equal proportions

Step-by-step explanation:

D batch 5

c. batch 4

so d and c

Answer:

f’(2) = -21/128

f’(-1) = -42

Step-by-step explanation:

We are given a function:

[tex]\displaystyle \large{f(x)=\frac{6}{x^7}}[/tex]

We want to evaluate f’(2) and f’(-1). Keep in mind that f’(x) denotes or means the derivative of f(x). So what we are going to do first is to find the derivative of given function.

Derive the function, there are two ways to derive it, either using power rules or quotient rules. For this, I’ll demonstrate two methods.

Power Rules

If [tex]\displaystyle \large{f(x)=x^n}[/tex] then [tex]\displaystyle \large{f\prime (x)=nx^{n-1}}[/tex] where n is any real numbers.

Since the function is written in a fraction form, we’ll have to convert it to the x^n form using law of exponent.

[tex]\displaystyle \large{f(x)=\frac{6}{x^7} \to f(x)=6\cdot \frac{1}{x^7}}[/tex]

Law of Exponent I

[tex]\displaystyle \large{\frac{1}{a^n} = a^{-n}}[/tex]

Therefore:

[tex]\displaystyle \large{f(x)=6x^{-7}}[/tex]

Then derive the function using power rules:

Property of Differentiation I

[tex]\displaystyle \large{y=kf(x) \to y\prime = kf\prime (x)}[/tex] where k is a constant.

[tex]\displaystyle \large{f\prime (x)=6\cdot -7x^{-7-1}}\\\displaystyle \large{f\prime (x)=6\cdot -7x^{-8}}\\\displaystyle \large{f\prime (x)=-42x^{-8}}[/tex]

Quotient Rules

[tex]\displaystyle \large{y=\frac{f(x)}{g(x)} \to y\prime = \frac{f\prime (x)g(x)-f(x)g\prime (x)}{[g(x)]^2}}[/tex]

If f(x) = k or a constant then:

Property of Differentiation II

[tex]\displaystyle \large{y=k \to y\prime = 0}[/tex] for k is a constant.

[tex]\displaystyle \large{y=\frac{k}{g(x)} \to y\prime = \frac{0\cdot g(x)-kg\prime (x)}{[g(x)]^2}}\\\displaystyle \large{y\prime = \frac{-kg\prime (x)}{[g(x)]^2}}[/tex]

Therefore:

[tex]\displaystyle \large{f\prime (x)=\frac{-6\cdot 7x^{7-1}}{[x^7]^2}}\\\displaystyle \large{f\prime (x)=\frac{-42x^6}{x^{14}}}\\\displaystyle \large{f\prime (x)=-42x^{6-14}}\\\displaystyle \large{f\prime (x)=-42x^{-8}}[/tex]

Laws of Exponent used above:

[tex]\displaystyle \large{(a^n)^m = a^{nm}}\\\displaystyle \large{\frac{a^n}{a^m} = a^{n-m}}[/tex]

Therefore the derivative of function is:

[tex]\displaystyle \large{f\prime (x) = -42x^{-8}}[/tex] or [tex]\displaystyle \large{f\prime (x)=-\frac{42}{x^8}}[/tex]

Next is to substitute x = 2 and x = -1 in the derivative.

[tex]\displaystyle \large{f\prime (2)=-\frac{42}{2^8}}\\\displaystyle \large{f\prime (2) = -\frac{42}{256}}\\\displaystyle \large{f\prime (2)= -\frac{21}{128}}[/tex]

And:

[tex]\displaystyle \large{f\prime (-1)=-\frac{42}{(-1)^8}}\\\displaystyle \large{f\prime (-1) = -\frac{42}{1}}\\\displaystyle \large{f \prime (-1) = -42}[/tex]

Therefore, f’(2) = -21/128 and f’(-1) = -42.

Answer:

Center and above your top lip where it dips down....

Answer:

3t - t.t.t +3(-2t) + t

3t - t³ - 6t + t

3t - 6t + t - t³

-2t - t³

Option A is correct

1. d    2. a     3. c     4. b

[tex]1.d\ \{The\ intersection\ of\ three\ high\ lines\}[/tex]

[tex]2.\ a[/tex]

[tex]3.\ C[/tex]

[tex]4.\ b\ \{The\ intersection\ of\ three\ angular[/tex]

       [tex]bisectors\}[/tex]

I hope this helps you

:)

Answer:

Step-by-step explanation:

Various centers are defined for a triangle, depending on how they're constructed. Here, you're asked to match the construction with the name.

__

The orthocenter is the intersection of the altitudes of the triangle. Each altitude intersects a vertex and is orthogonal to the opposite side. The orthocenter will not be inside the triangle if the triangle is obtuse. The orthocenter of a right triangle is the right-angle vertex.

Figure D depicts the intersection of altitudes.

__

The incenter is the center of an inscribed circle of a triangle. The incenter must be the same distance from each side, so will be at the point of intersection of the angle bisectors. It always lies inside the triangle.

Figure B depicts the intersection of angle bisectors.

__

The centroid is the "center of gravity" of the triangle, the point at which the triangle could be balanced. Each median divides the triangle into two equal areas, so the intersection of medians marks a spot with equal area (weight) in every pair of opposite directions.

Figure C depicts the intersection of medians.

__

The circumcenter is the center of a circle that circumscribes the triangle. It is equidistant from the three vertices, so lies on the intersection of the perpendicular bisectors of the sides. It will lie outside the triangle for obtuse triangles. It is the midpoint of the hypotenuse of a right triangle.

Figure A depicts the intersection of perpendicular bisectors of the sides.

Answer:

For every 2 quarts of water, ¹/₂ cup of vinegar is used.

⇒ To find the amount of vinegar, divide the number of quarts by 4.

⇒ To find the number of quarts, multiply the amount of vinegar by 4.

4 qt water = 4 ÷ 4 = 1 cup vinegar

1¹/₂ cups vinegar = 1¹/₂ x 4 = 6 qt water

8 qt water = 8 ÷ 4 = 2 cup vinegar

Plot the points on the graph (see second attached image).

Draw a line through the points.

Find 3 along the x-axis and trace up to the line. Trace along to the y-axis.

Therefore, Gavin would need to use 12 quarts of water with 3 cups of vinegar.

Answer:

1/4 is the correct answer

Step-by-step explanation:

Even after replacing the marble the propability will not chance.

Answer:

91kg

Step-by-step explanation:

weight= mass × gravitational force

910kg = m× 10ms^-2

m= 910÷ 10

m= 91

Apply Pythagorean theorem

[tex]\\ \rm\rightarrowtail B^2=2.2^2-2^2[/tex]

[tex]\\ \rm\rightarrowtail B^2=5-4[/tex]

[tex]\\ \rm\rightarrowtail B^2=1[/tex]

[tex]\\ \rm\rightarrowtail B=1[/tex]

Area:-

Answer:6

Step-by-step explanation:

I did the test

Answer:

x=6

Step-by-step explanation:

please mark me as brainlest

Answer:

$710,000

Step-by-step explanation:

The computation of the owner’s equity at the end of the year is given below:

We know that

The accounting equation equals to

Total assets = Total liabilities + owners equity

where,

Total assets = $800,000 + $150,000 = $950,000

And, the total liabilities = $300,000 - $60,000 = $240,000

So, the owners equity at the end of the year would be

= $950,000 - $240,000

= $710,000

Answer:

D. 45

Step-by-step explanation:

To find out how many games will be played with 10 people, we need to first find the pattern of the given table. To start out, we can see that for the numbers of players added, it adds one each time it goes up one number. And, we can also see that starting at 1 games played, it adds 2 for the next and gets 3 games. Then it adds 3 to get 6 games. So, we can see that for every added person added, it starts at 1 and adds 2, then adds, 3, 4, 5, 6, etc... Knowing this, we can figure out how many games will be played with 10 people.

2 people gets 1 games

+1                    +2

3 people get 3 games

+1                    +3

4 people get 6 games

So, now we can simply skip to 6 and seven players becuase we know that the pattern holds true to itself.

6 people get 15 games

+1                   +6

7 people get 21 games

+1                   +7

8 people get 28 games

+1                    +8

9 people get 36 games

+1                   +9

10 people get 45 games

Answer:

4

Step-by-step explanation:

had to look it up but do 20 x 0.2 (1/5) and u get 4

Answer:

The answer to the problem is 4 1/2

Answer:

9/2

Step-by-step explanation:

the answer is 9/2 or 4.5,

the solution for that I have attached below

Answer(s):

[tex]\displaystyle y = 4sin\:(2x + \frac{\pi}{2}) \\ y = 4cos\:2x[/tex]

Step-by-step explanation:

[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{4}} \hookrightarrow \frac{-\frac{\pi}{2}}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 4[/tex]

OR

[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 4[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 4sin\:2x,[/tex]in which you need to replase "cosine" with "sine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{4}\:unit[/tex]to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{\pi}{4}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{\pi}{4}} = \frac{-\frac{\pi}{2}}{2}.[/tex]So, the sine graph of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 4sin\:(2x + \frac{\pi}{2}).[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph WILL hit [tex]\displaystyle [-1\frac{1}{4}\pi, 0],[/tex]from there to [tex]\displaystyle [-\frac{\pi}{4}, 0],[/tex]they are obviously [tex]\displaystyle \pi\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle \pi.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 0,[/tex]in which each crest is extended four units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.