-Cesar the monkey observed the swinging behaviors of his parents. He is now able to swing from branch to branch after much practice. The observation of his parents swinging and practicing what he saw mainly involved _____ neurons; the neurons that are the basis of
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Complete Question

A parallel plate capacitor contains a positively charged plate on the left, and a negatively charged plate on the right. An electron in between the plates is moving to the right. Which statement is true?

Group of answer choices

a The potential energy of the electron is decreasing and it is moving to a region having a higher potential

b The potential energy of the electron is decreasing and it is moving to a region having a lower potential.

c The potential energy of the electron is increasing and it is moving to a region having a lower potential

d  The potential energy of the electron is increasing and it is moving to a region having a higher potential.  

Answer:

The correct option is  C

Explanation:

From the question we are told that

  An electron in between the plates is moving to the right

Generally the potential energy of the electron is mathematically represented as  

          [tex]PE  =  e *  V[/tex]

Here  e is the charge on the electron and  V  is the electric potential of the electron

Generally the left side with the positive charge has a higher potential than the right side with the negative  charge

Now when the potential energy of the electron increases it will move toward the plate with the lower potential  which is the left plate

Answer:

....................

Answer:

20

Explanation:

40/2.0=20.......

hope it helps

Answer:

BIOFLU TABLET

Explanation:

PAG MAY LAGNAT UBO IBIOFLU NAYAN

Answer:

Antibodies are the answer.

Explanation:

Many companies are adding antibodies to ring a bell in the cells to tell the white blood cells to be able to notice the Corona Virus in the blood stream.

Answer:

The pressure in the tunnel is 97.45 kPa

Explanation:

Given;

atmospheric pressure, P₁ = 101.3 kPa

air velocity in the tunnel, v₂ = 80 m/s

density of air at 20°C, ρ = 1.204 kg/m³

pressure in the tunnel, P₂ = ?

Apply Bernoulli's equation;

P₁ + ¹/₂ρv₁² + ρgz₁ = P₂ + ¹/₂ρv₂² + ρgz₂

v₁ = 0

z₁ = z₂ = 0

P₁ = P₂ + ¹/₂ρv₂²

P₂ = P₁ - ¹/₂ρv₂²

P₂ = 101.3 kPa - (0.5 x 1.204 x 80²)

P₂ = 101.3 kPa - 3.8528 kPa

P₂ = 97.45 kPa

Therefore, the pressure in the tunnel is 97.45 kPa

Answer:

Electromagnetic waves transfer energy through vibrations of electric and in magnetic fields. For sound waves the energy is transferred through the vibration of air particles or particles of a solid. Waves also carry energy, the amount of energy they carry depends on their frequency and their amplitude. The more energy and the higher frequency amplitude, the more energy waves are ^‿^

Answer:

The answer is D) diagonal line with varying slope, from 3 to 5 on USATestprep

Explanation:

Answer:

mass = 5 [kg]

Explanation:

The difference between weight and mass should be clarified, the weight is equal to the product of the mass by the gravity of the place. While the mass will always be conserved regardless of the place, it will never change.

weight = mass * gravity of the place

}Therefore the mass is the same in the earth as in the moon

Answer:

D) The objects have the same acceleration. With no air resistance and the same gravity, the acceleration due to gravity should be the same for both objects.

Answer:

b

Explanation:

Analysing the question:

We are given:

mass of object (m) = 0.03 kg

height of object (h) = 2.94 m

acceleration due to gravity (a) = 10 m/s²

initial velocity (u) = 0 m/s [the object fell, we are NOT given any initial velocity]

final velocity (v) = v m/s

Solving for Final velocity:

from the third equation of motion:

v² - u² = 2ah

replacing the variables

(v)² - (0)² = 2(10)(2.94)

v² = 58.8

v = 7.67 m/s

Answer:

True

Explanation:

Answer: very true

Explanation:

Answer:

3.89*10^3

Explanation:

The Scientific notation of the question 0.00389 is 3.89*10^3 ( which is 3 point Eighty Nine Multiply ( Multiply sign " * " ) Ten with raising power (this sign is used normally to write power ^ ) Three).

Answer: (B) Too many to count

Explanation: Have a wonderful day everyone! :D

The exercises that encompasses stretching in the human body is : B) too many to count

exercises can be defined as any activity that puts your muscle to work and helps burn calories in your body.

exercises are one of the keys to staying and living healthy.

exercises are of different types and forms and some encompasses stretching in the human body.

In conclusion, The exercises that encompasses stretching in the human body is too many to count

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Answer:

The work required is -515,872.5 J

Explanation:

Work is defined in physics as the force that is applied to a body to move it from one point to another.

The total work W done on an object to move from one position A to another B is equal to the change in the kinetic energy of the object. That is, work is also defined as the change in the kinetic energy of an object.

Kinetic energy (Ec) depends on the mass and speed of the body. This energy is calculated by the expression:

[tex]Ec=\frac{1}{2} *m*v^{2}[/tex]

where kinetic energy is measured in Joules (J), mass in kilograms (kg), and velocity in meters per second (m/s).

The work (W) of this force is equal to the difference between the final value and the initial value of the kinetic energy of the particle:

[tex]W=\frac{1}{2} *m*v2^{2}-\frac{1}{2} *m*v1^{2}[/tex]

[tex]W=\frac{1}{2} *m*(v2^{2}-v1^{2})[/tex]

In this case:

Replacing:

[tex]W=\frac{1}{2} *2145 kg*((12\frac{m}{s} )^{2}-(25\frac{m}{s} )^{2})[/tex]

W= -515,872.5 J

The work required is -515,872.5 J

The amount of work needed by the vehicle to decrease its speed from 25 m/s to 12 m/s is 515872.5 J.

The amount of work required by the truck to decrease its speed can be calculated using the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, The amount of work needed by the vehicle to decrease its speed from 25 m/s to 12 m/s is 515872.5 J.

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Answer:

The answer is C 283 kelvin

Answer: C.

283 K

Explanation: edmentum

Answer:

b  16 m/s².

Explanation:

Hello.

In this case, the force exerted to the mass of 400 kg at an acceleration of 4 m/s² is:

[tex]F=400kg*4m/s^2=1600N[/tex]

Now, since the mass is decreased to 100 kg (1/4 of 400 kg), and the force remain the same, the new acceleration should be:

[tex]a=\frac{F}{m}=\frac{1600kg*m/s^2}{100kg}\\ \\a=16m/s^2[/tex]

Thus, the answer is b  16 m/s².

Best regards.

Answer:

The distance is  [tex] s =  2.3 \  m [/tex]

Explanation:

From the question we are told that

   The  frequency of the current is  [tex]f =  10\ kHz  = 10 *10^{3} \  Hz[/tex]

   The magnitude of the  current  is  [tex]I_o  =  0.5\ Amps[/tex]

     The number of turns is  [tex]N =  150\  turns[/tex]

     The  diameter is  [tex]d =  30 mm  = 0.03 \ m[/tex]

      The detection level is  [tex]V_{rms}  =  200 \mu V  =  200 * 10^{-6} \  V[/tex]

Generally the radius is mathematically represented as

      [tex]r =  \frac{d}{2}[/tex]

=>    [tex]r =  \frac{0.03}{2}[/tex]

=>      [tex]r 0.015 \ m [/tex]

Generally the magnetic field  generated by the fence is mathematically represented as

      [tex]B  =  \frac{\mu_o *  N * I}{2 *  \pi * s}[/tex]

Here s is the point where the do will feel the magnetic field

      [tex]\mu_o[/tex] is the permeability of free space with value  [tex]\mu_o =   4\pi * 10^{-7} N/A^2 [/tex]    

   So

         [tex]B  =  \frac{ 4\pi * 10^{-7}  *  150 *  I}{2 * 3.142  * s}[/tex]

Generally the magnetic flux is mathematically represented as

     [tex]\Phi =  B *  \pi * r^2[/tex]

=>   [tex]\Phi =   \frac{ 4\pi * 10^{-7}  *  150 * I}{2 * 3.142  * s} *  \pi * r^2[/tex]

=>   [tex]\Phi  =  \frac{2.121 *10^{-8} *  I }{s}[/tex]

Generally the induced emf is mathematically represented as

      [tex]\epsilon  =- \frac{d \Phi}{dt}[/tex]

=>    [tex]\epsilon  =- \frac{ 2.121 *10^{-8} }{ s } *  \frac{d I}{dt}[/tex]

Generally the angular frequency is mathematically represented as

   [tex]w =  2 \pi f[/tex]

=>        [tex]w =  2 *  10*10^{3} \pi [/tex]

=>       [tex]w =  20000 \pi [/tex]

So the current is mathematically represented as

        [tex]I = I_o sin (wt)[/tex]

=>     [tex]I = I_o sin ( 20000 \pi * t)[/tex]

So

  [tex]\epsilon  =- \frac{ 2.121 *10^{-8} }{ s } *  \frac{d [ I_o sin ( 20000 \pi * t)]}{dt}[/tex]

  [tex]\epsilon  =- \frac{ 2.121 *10^{-8} }{ s } *  I_o * 20000 \pi   [  cos ( 20000 \pi * t) [/tex]  

   [tex]\epsilon  =- \frac{ 2.121 *10^{-8} }{ s } * 0.5 * 20000 \pi   [  cos ( 20000 \pi * t) [/tex]    

    [tex]\epsilon  =- \frac{ 6.6*10^{-4} }{ s } [  cos ( 20000 \pi * t) [/tex]  

Here the  

    [tex]\epsilon_{rms} = \frac{ \frac{ 6.6*10^{-4} }{ s }}{\sqrt{2} }[/tex]

=>     [tex]\epsilon_{rms} = \frac{ 6.6*10^{-4} }{ s\sqrt{2}  }[/tex]

But from the question we are told that  [tex]V_{rms}  =  200 \mu V  =  200 * 10^{-6} \  V[/tex]

So

    [tex]\frac{ 6.6*10^{-4} }{ s\sqrt{2}  } = 200 * 10^{-6}[/tex]

=>  [tex]6.6*10^{-4}= 2.8284 *10^{-4} * s[/tex]

=>  [tex] s =  2.3 \  m [/tex]

Answer:

2,400kg * m/s

Explanation:

You are missing some information in the question but the rest could be found some where else.

The question gives the masses and starting velocity of each car.

Car 1: m = 600kg and sv = 4m/s

Car 2: m 400kg and sv = 0m/s

Find the momentum of both cars.

Car 1: 600 * 4 = 2400

Car 2: 400 * 0 = 0

Add both.

2400 + 0 = 2400

Best of Luck!

Answer: answer C

Explanation:

Your welcome

Answer:

(a). 14.4 lbf/in^2.

(b). 27.8 in, AS THE TEMPERATURE INCREASES, THE LENGTH OF MERCURY DECREASES.

Explanation:

So, from the question above we are given the following parameters which are going to help us in solving this particular Question;

=> The "barometer accidentally contains 6.5 inches of water on top of the mercury column (so there is also water vapor instead of a vacuum at the top of the barometer)"

=> "On a day when the temperature is 70oF, the mercury column height is 28.35 inches (corrected for thermal expansion)."

With these knowledge, let us delve right into the solution;

(a). The barometric pressure = water vapor pressure + acceleration due to gravity (ft/s^2) × water density(slug/ft^3) × {ft/12 in}^3 × [ height of mercury column + specific gravity of mercury × height of water column].

The barometric pressure= 0.363 + {(62.146) ÷ (12^3) × 390.6425}. = 14.4 lbf/in^2.

(b). { (13.55 × length of mercury) + 6.5 } × (62.15÷ 12^3) = 14.4 - 0.603.

Length of mercury = 27.8 in.

AS THE TEMPERATURE INCREASES, THE LENGTH OF MERCURY DECREASES.

Answer:

if the force increases while the mass of the ball remains the same, the acceleration increases.

Explanation:

According to Newton's second law of motion, the acceleration of an object produced by a net force is directly proportional to the magnitude of the net force Fn and inversely proportional to the mass of the object m.

[tex]\displaystyle a=\frac{Fn}{m}[/tex]

Suppose the net force doubles to 2Fn. The new acceleration will be:

[tex]\displaystyle a'=\frac{2Fn}{m}=2\frac{Fn}{m}=2a[/tex]

The acceleration doubles too. Thus, if the force increases while the mass of the ball remains the same, the acceleration increases.

Answer: B. The resulting current is the difference of the two and has the direction of the larger current.

Explanation: Superposition Theorem states that the result in a particular branch of a linear circuit when a variety of sources are acting at the same time equals the sum of the response of each particular source acting at a time, i.e., if sources are acting on a line circuit, the resulting current in any branch is the sum of all the currents produced if each source is producing it by itself.

To solve by this method:

1) Find current in a particular branch considering one only independent source and deactivating the others;

2) Repeat the first step for all the sources in the circuit;

3) Add all the results: If the current obtained is in the same direction, add them; If it's in the opposite direction, subtract them and obtain the net current;

Therefore, when using superposition, if one current is in one direction and the other produced by other source is in the opposite direction, the net current is the difference between the two abd has the direction of the larger current.

Answer:

i think the answer is c

Explanation:

zrrxtcyvjvugugyctcyvjv

A free body diagram consists of a diagrammatic representation of a single body or a subsystem of bodies isolated from its surroundings showing all the forces acting on it.

"A body is said to be "free" when it is singled out from other bodies for the purposes of dynamic or static analysis." The object does not have to be "free" in the sense of being unforced, and it may or may not be in a state of equilibrium; rather, it is not fixed in place and is thus "free" to move in response to forces and torques it may experience.

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Answer:

dfmwekognjioq 4eijqgi24gno3p2qtijoq2 gjo23ijgto32tneqew gqewkgnoweqgmnlqwe gwjoegkqwji4toqn34goti34

Explanation:

Answer:

1) its initial velocity is zero, 2) the downward direction as positive

3) h = 25.66 m

Explanation:

This is a free fall exercise.

1) with falls, its initial velocity is zero and the acceleration is constant throughout the path and is equal to the acceleration due to gravity.

2) a widely used selection to estimate the downward direction as positive

3) We know that for the second part of the fall

         y₀ -y = h/2   at  t = 1 s

        y = y₀ + v₁ t + ½ g t²

where v₁ is the initial velocity of this interval at the point y = h / 2

        v₁ t = (y -y₀) - ½ g t²

        v₁ = h / 2 - ½ g t²

        v₁ = h/2 - g/2

now let's write the equation for the first interval

         v₁² = v₀² + 2 g (y₁ - y₀)

       in this interval v₀ = 0

         v₁² = 2 g (y₁ -y₀)

         v₁² = 2g h/2

we write our system of equations

           v₁² = (h/2 - g/2)²

           v₁² = (2g h / 2)

           (h /2 - g/2)² = (2g h / 2)

            h² / 4 - 2  g/2  h/2 + (g/2)² = g h

            h² / 4 - g h/2 - g h + g²/4 = 0

            h² - 3 g h + g² =0              

            h² - 29.4 h +96.04 = 0

we solve the quadratic equation

            h = [29.4 ±√ (29.4² - 4 96.04)] / 2

            h = [29.4 ± 21.91] / 2

            h₁ = 25.66 m

            h₂ = 3.75 m

As the system takes more than 1 S to fall, the correct answer for the height is h = 25.66 m

Answer 1)

This is a free fall exercise with falls, its initial velocity is zero and the acceleration is constant throughout the path and is equal to the acceleration due to gravity.

Answer B :

A widely used selection to estimate the downward direction as positive.

Answer 3:

We know that for the second part of the fall:

        y₀ -y = h/2   at  t = 1 s

       y = y₀ + v₁ t + ½ g t²

where v₁ is the initial velocity of this interval at the point

       y = h / 2

       v₁ t = (y -y₀) - ½ g t²

       v₁ = h / 2 - ½ g t²

       v₁ = h/2 - g/2

Answer 4:

Now let's write the equation for the first interval

        v₁² = v₀² + 2 g (y₁ - y₀)

      in this interval v₀ = 0

        v₁² = 2 g (y₁ -y₀)

        v₁² = 2g h/2

we write our system of equations

          v₁² = (h/2 - g/2)²

          v₁² = (2g h / 2)

          (h /2 - g/2)² = (2g h / 2)

           h² / 4 - 2  g/2  h/2 + (g/2)² = g h

           h² / 4 - g h/2 - g h + g²/4 = 0

           h² - 3 g h + g² =0              

           h² - 29.4 h +96.04 = 0

we solve the quadratic equation

           h = [29.4 ±√ (29.4² - 4 96.04)] / 2

           h = [29.4 ± 21.91] / 2

           h₁ = 25.66 m

           h₂ = 3.75 m

As the height is h = 25.66 m.

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Answer:

Explanation:

See attached file for answer.

Answer:

A, B and C

Explanation:

Option A is correct because, the force on particle 1 depends on the electric field due to particle 2. Since the electric field due to particle 2 is the force per unit charge acting at the point of particle 1, the force at the point of particle 1 is the product of that electric field due to particle 2 and the charge on particle 1. So, Particle 2's electric field contributes to the electric force on particle 1.

Option B is correct because the force on a charge can only be exerted due to an external electric field. So, Particle 1's electric field does not contribute to the electric force on particle 1

Option C is correct since an electric field is always present in the region surrounding a charge irrespective of whether there is a charge in the region of the electric field or not. So, If particle 2 were removed, there would still be a non-zero electric field at its location.

Answer:

I = 0.09[amp] or 90 [milliamps]

Explanation:

To solve this problem we must use ohm's law, which tells us that the voltage is equal to the product of the voltage by the current.

V = I*R

where:

V = voltage [V]

I = current [amp]

R = resistance [ohm]

Now, we replace the values of the first current into the equation

V = 180*10^-3 * R

V = 0.18*R (1)

Then we have that the resistance is doubled so we have this new equation:

V = I*(2R) (2)

The voltage remains constant therefore 1 and 2 are equals and we can obtain the current value.

V = V

0.18*R = I*2*R

I = 0.09[amp] or 90 [milliamps]