Answer:
what are you confused on?
1L = 1000 mL
Molarity (M) = moles of solute / L of solution
Calculate the moles of NaCl required to prepare 250 mL of 1.5 M aqueous solution.
Answer:· 44 g NaCl Explanation: The problem provides you with the molarity and volume of the target
Explanation:
need help asap, In this reaction how many units of B are required to form 40 units of C? A+2B--->C
Answer:
80 units B
Explanation:
Equation for the reaction is given below:
A + 2B —> C
From the equation above,
2 units of B reacted to produce 1 unit to C.
Finally, we shall determine the unit of B needed to produce 40 units of C. This can be obtained as follow:
From the equation above,
2 units of B reacted to produce 1 unit to C.
Therefore, x unit of B will react to produce 40 units of C i.e
x unit of B = 2 × 40
x unit of B = 80 units
Thus, 80 units B is needed for the reaction.
What is a similarity between a fish embryo and a human embryo in the late stages of development?
They both have tails
They both have gills.
They both have spines.
They both have arms.
Answer:In the LATER stages of development they would have a spine
Explanation:
i What
What is ment by
ment by covalency?
how do you melt water FREE 100 POINTS
Answer:
by adding heat
Explanation:
Adding heat can cause ice (a solid) to melt to form water (a liquid). Removing heat causes water (a liquid) to freeze to form ice (a solid).
by adding heat
when water was changes to soild or a gas , we say change to a different state of the matter. Even though the waters physical from change its molecular stay the same
A solution of silver chlorate reacts with a solution of lithium iodide.
provide the net ionic equation if the reaction takes place.
Answer: [tex]Ag^+(aq)+I^-(aq)\rightarrow AgI(s)[/tex]
Explanation:
A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.
Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.
The given chemical equation is:
[tex]AgClO_3(aq)+LiI(aq)\rightarrow AgI(s)+LiClO_3(aq)[/tex]
The complete ionic equation is:
[tex]Ag^+(aq)+ClO_3^-(aq)+Li^+(aq)+I^-(aq)\rightarrow AgI(s)+Li^+(aq)+ClO_3^-(aq)[/tex]
The ions which are present on both the sides of the equation are lithium and chlorate ions. and hence are not involved in net ionic equation.
Thus the net ionic equation is:
[tex]Ag^+(aq)+I^-(aq)\rightarrow AgI(s)[/tex]
Where do most of the rivers in North Carolina flow to?
What is the atomic number for an element with 41 neurons and a mass number of 80
Answer:
92.9 I think not sure but hope this helps
A sugar solution is 15% pure. How
many grams of sugar are there in 550
grams of the solution?
Answer:
Amount of sugar in solution = 82.5 gram
Explanation:
Given:
Sugar in solution percentage = 15%
Total solution = 550 grams
Find:
Amount of sugar in solution
Computation:
Amount of sugar in solution = Sugar in solution percentage x Total solution
Amount of sugar in solution = 15% X 550
Amount of sugar in solution = 82.5 gram
Jason has a bag that contains
8
88 identically shaped boxes.
6
6start color #6495ed, start text, 6, end text, end color #6495ed of the boxes are
blue
bluestart color #6495ed, start text, b, l, u, e, end text, end color #6495ed, and
2
2start color #28ae7b, start text, 2, end text, end color #28ae7b are
green
greenstart color #28ae7b, start text, g, r, e, e, n, end text, end color #28ae7b.
3
of the blue boxes have a prize
3 of the blue boxes have a prizestart color #6495ed, start text, 3, space, o, f, space, t, h, e, space, b, l, u, e, space, b, o, x, e, s, space, h, a, v, e, space, a, space, p, r, i, z, e, end text, end color #6495ed, and
1
of the green boxes has a prize
1 of the green boxes has a prizestart color #28ae7b, start text, 1, space, o, f, space, t, h, e, space, g, r, e, e, n, space, b, o, x, e, s, space, h, a, s, space, a, space, p, r, i, z, e, end text, end color #28ae7b.
Jason randomly selects a box from the bag. Let
A
AA be the event that he selects a box with a prize and
B
BB be the event that the box is green.
Which of the following statements are true?
Choose all answers that apply:
Choose all answers that apply:
(Choice A)
A
P
(
A
|
B
)
=
P
(
A
)
P(A | B)=P(A)P, left parenthesis, A, start text, space, vertical bar, space, end text, B, right parenthesis, equals, P, left parenthesis, A, right parenthesis, the conditional probability that Jason selects a box with a prize given that he has chosen a green box is equal to the probability that Jason selects a box with a prize.
(Choice B)
B
P
(
B
|
A
)
=
P
(
B
)
P(B | A)=P(B)P, left parenthesis, B, start text, space, vertical bar, space, end text, A, right parenthesis, equals, P, left parenthesis, B, right parenthesis, the conditional probability that Jason selects a green box given that he has chosen a box with a prize is equal to the probability that Jason selects a green box.
(Choice C)
C
Events
A
AA and
B
BB are independent events.
(Choice D)
D
The outcomes of events
A
AA and
B
BB are dependent on each other.
(Choice E)
E
P
(
A
and
B
)
=
P
(
A
)
⋅
P
(
B
)
P(A and B)=P(A)⋅P(B)P, left parenthesis, A, start text, space, a, n, d, space, end text, B, right parenthesis, equals, P, left parenthesis, A, right parenthesis, dot, P, left parenthesis, B, right parenthesis, the probability that Jason selects a box that contains a prize and is green is equal to the probability that Jason selects a box with a prize multiplied by the probability that he selects a green box.
Answer:
A. P(A | B)=P(A)P, left parenthesis, A, start text, space, vertical bar, space, end text, B, right parenthesis, equals, P, left parenthesis, A, right parenthesis, the conditional probability that Jason selects a box with a prize given that he has chosen a green box is equal to the probability that Jason selects a box with a prize.
B. P(B | A)=P(B)P, left parenthesis, B, start text, space, vertical bar, space, end text, A, right parenthesis, equals, P, left parenthesis, B, right parenthesis, the conditional probability that Jason selects a green box given that he has chosen a box with a prize is equal to the probability that Jason selects a green box.
C. Events AAA and BBB are independent events.
E. P(A and B)=P(A)⋅P(B)P, left parenthesis, A, start text, space, a, n, d, space, end text, B, right parenthesis, equals, P, left parenthesis, A, right parenthesis, dot, P, left parenthesis, B, right parenthesis, the probability that Jason selects a box that contains a prize and is green is equal to the probability that Jason selects a box with a prize multiplied by the probability that he selects a green box.
Explanation:I got it right on Kahn
What is the specific heat of iron, if it requires 1120 J of heat energy to raise the
temperature of 430.0 g of iron from 10.0ºC to 20.4ºC
Answer:
Specific heat is defined as the amount of heat needed to raise the temperature by one degree celsius. Therefore, in 1 kg there are 100 grams so, 10 grams equal 0.01 Kg. Thus, calculate the specific heat value as follows. Thus, we can conclude that specific heat of the given metal is 0.5 .
Explanation:
1°C if the pressure is 149.3 kPa? How many moles of hydrogen sulfide H2S are contained in a 327.3 mL bulb at 48.
Answer:
Number of moles of H₂S gas = 0.0183 moles
Note: The question is incomplete. The complete question is given below:
How many moles of hydrogen sulfide H2S are contained in a 327.3 mL bulb at 48.1°C if the pressure is 149.3 kPa?
Explanation:
The following values are given in the question :
Volume of H₂S gas = 327.3 M = 0.3273 L
Temperature of gas = 48.1°C = (273.15 + 48.1) K = 321.25 K
Pressure of gas = 149.3 kPa
1 kPa = 0.00987 atm; 149.3 kPa = 149.3 × 0.00987 atm = 1.474 atm
Molar gas constant, R = 0.0821 liter·atm/mol·K.
number of moles, n = ?
Using PV = nRT
n = PV/RT
n = (0.3273 × 1.474)/(0.0821 × 321.25)
n = 0.0183 moles
Therefore, number of moles of H₂S gas = 0.0183 moles
Equal masses of aluminum and copper are heated to 100 degree C and placed in water. Which would cause the water to reach the higher temperature? Explain your answer.
Answer:
copper will reach to higher temperature first.
Explanation:
Match the function to the part of the cell.
1.lysosome
A.serves as a temporary storage area for nutrients and waste materials
2.vacuole
B.breaks down waste materials
3.chloroplast
C.converts energy from the sun to food energy
Answer: Chloroplast: Converts energy from the sun to food energy
Answer: Vacuole: Servers as a temporary storage area for nutrients and waster materials.
Answer: Lysosome: Breaks down waste materials
Explanation: Dude above me is wrong
What is the function of white blood cells?
A) immunity
b) carry nutrients, waste
C) blood clotting
Answer:
A
Explanation:
They help fight infection and other disease
Answer:
immunity is the answer for this question
valence number of a metallic element X is 3. What is the formula of its oxide?
Answer:
the formula of its oxide is X2O3.
There are two types of chemical compound one is covalent compound and other is ionic compound, covalent compound formed by sharing of electron and ionic compound formed by complete transfer of electron. Therefore, the formula of given metallic oxide is X[tex]_2[/tex]O[tex]_3[/tex].
What is chemical Compound?Chemical Compound is a combination of molecule, Molecule forms by combination of element and element forms by combination of atoms in fixed proportion.
An ionic compound is a metal and nonmetal combined compound. Ionic compound are very hard. They have high melting and boiling point because of strong ion bond.
Since valence number of a metallic element X is 3 and valence number of oxide is 2. So, the formula of its oxide is X[tex]_2[/tex]O[tex]_3[/tex].
Therefore, the formula of given metallic oxide is X[tex]_2[/tex]O[tex]_3[/tex].
To learn more about chemical compound, here:
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C3H8(g) + 5 O2(g) ---->3 CO2 (g)+ 4H2O (g)
If the experiment contains 75.0 grams of O2, how many grams of H2O should be produced?
Answer: 33.75g H2O
Explanation:
75g O2 (1 mol O2/32g O2) (4 mol H2O/5 mol O2) (18g H2O/1 mol H2O) = 33.75g H2O
This is a stoichiometric calculation in which 75 is multiplied by 1, 4, and 18 (the top numbers), and then divided by (32 x 5 x 1), which are the bottom numbers.
Stoichiometry is super fun once you get the hang of it!!
If we add 22.5 g of HCl to 45.8 g of water, what is the percent by mass of HCl in the solution?
Answer:
[tex]\%m/m=33.0\%[/tex]
Explanation:
Hello there!
In this case, since the percent by mass of a solute in a solution is computed via the following division:
[tex]\%m/m=\frac{m_{solute}}{m_{solute}+m_{solvent}} *100\%[/tex]
Next, given the mass of HCl and that of water, we plug them in to obtain:
[tex]\%m/m=\frac{22.5g}{22.5g+45.8g} *100\%\\\\\%m/m=33.0\%[/tex]
Best regards!
Estimate the crystal field stabilization energy for the octahedral ion hexacyanomanganate(III) , if the wavelength of maximum absorption for the ion is 600 nm. [Note: This is a high-field (low-spin) complex.]
Answer:
The crystal field stabilization energy for the octahedral ion hexacyanomanganate(III) , if the wavelength of maximum absorption for the ion is 600 nm is - 1987.59kJ/mole
Explanation:
Lets calculate -:
Crystal field stabilization energy -
[tex]E=\frac{hc}{\pi }[/tex]
where h = planks constant = [tex]6.626\times10^-^3^4 Js[/tex]
c= velocity of light = [tex]3\times10^8m/second[/tex]
[tex]\pi =wavelength=600nm=600\times10^-^9m[/tex]
[tex]E=\frac{6.626\times10^-^3^4\times3\times10^8}{600\times10^-^9}[/tex]
=[tex]0.033\times10^-^1^6 J/ion[/tex]
= [tex]0.033\times10^-^1^6\times6.023\times10^2^3[/tex]
= [tex]0.198759\times10^7 J/mole[/tex] = [tex]1987.59\times10^3J/mole[/tex]
= [tex]1987.59kJ/mole[/tex]
Thus , the crystal field stabilization energy for the octahedral ion hexacyanomanganate(III) is 1987.59kJ/mole
the article is on newsela called the water cycle
Answer:
Explanation:Canguru comeu algumas folhas de 3 galhos de eucalipto. Cada galho tinha inicialmente20 folhas. Canguru comeu algumas folhas do primeiro galho e depois comeu tantas folhas do segundo galho quantas tinham sido deixadas no primeiro galho. Depois ele comeu 2 folhas do terceiro galho. No total, quantas folhas foram dei-xadas nos 3 galhos?Canguru comeu algumas folhas de 3 galhos de eucalipto. Cada galho tinha inicialmente20 folhas. Canguru comeu algumas folhas do primeiro galho e depois comeu tantas folhas do segundo galho quantas tinham sido deixadas no primeiro galho. Depois ele comeu 2 folhas do terceiro galho. No total, quantas folhas foram dei-xadas nos 3 galhos?Canguru comeu algumas folhas de 3 galhos de eucalipto. Cada galho tinha inicialmente20 folhas. Canguru comeu algumas folhas do primeiro galho e depois comeu tantas folhas do segundo galho quantas tinham sido deixadas no primeiro galho. Depois ele comeu 2 folhas do terceiro galho. No total, quantas folhas foram dei-xadas nos 3 galhos?Canguru comeu algumas folhas de 3 galhos de eucalipto. Cada galho tinha inicialmente20 folhas. Canguru comeu algumas folhas do primeiro galho e depois comeu tantas folhas do segundo galho quantas tinham sido deixadas no primeiro galho. Depois ele comeu 2 folhas do terceiro galho. No total, quantas folhas foram dei-xadas nos 3 galhos?Canguru comeu algumas folhas de 3 galhos de eucalipto. Cada galho tinha inicialmente20 folhas. Canguru comeu algumas folhas do primeiro galho e depois comeu tantas folhas do segundo galho quantas tinham sido deixadas no primeiro galho. Depois ele comeu 2 folhas do terceiro galho. No total, quantas folhas foram dei-xadas nos 3 galhos?
can someone help me, please?
When air hockey is played, a small plastic puck slides across a table that has holes through which air is forced. What effect does the air have on the game?
Answer:
it reduces the atmospheric pressure
120 L of C3H8 is how many grams?
Answer:
44.09562 grams
Explanation:
An FCC iron-carbon alloy initially containing 0.20 wt% C is carburized at an elevated temperature and in an atmosphere wherein the surface carbon concentration is maintained at 1.0 wt%. If after 51 h the concentration of carbon is 0.35 wt% at a position 3.9 mm below the surface, determine the temperature at which the treatment was carried out. You will need to use data in the two tables below to solve this problem.
Answer:
Explanation:
[tex]\text{From the information given:}[/tex]
[tex]C_o = 0.20 \ wt\% \\ \\ C_s = 1 \ wt\% \\ \\ t = 51 \ h \\ \\ x = 3.9 \ mm \\ \\ C_x = 0.35 \ wt\%[/tex]
[tex]\text{Using Fick's 2{nd} \ law \ of \ diffusion;} \\ \\ \dfrac{C_x- C_o}{C_s-C_o}= 1 - erf ( \dfrac{x}{2\sqrt{Dt}})[/tex]
[tex]\dfrac{0.35-0.20}{1-0.20}= 1 - erf ( \dfrac{x}{2\sqrt{Dt}})[/tex]
[tex]0.1875 = 1 - erf ( \dfrac{x}{2\sqrt{DT}}) \\ \\ erf ( \dfrac{x}{2\sqrt{DT}}) = 1 - 0.1875 \\ \\ erf ( \dfrac{x}{2\sqrt{DT}}) = 0.8125[/tex]
[tex]\text{To find the value of Z by Obtaining Data from Tabulation of Error Function}[/tex] [tex]\text{Table Values:}[/tex]
Z erf(z)
0.90 → 0.7970
0.95 → 0.8209
? → 0.8225
∴
[tex]\dfrac{z-0.90}{0.95-0.90}= \dfrac{0.8125-0.7970}{0.8209-0.7970}[/tex]
[tex]\dfrac{z-0.90}{0.05}= \dfrac{0.0155}{0.0239}[/tex]
[tex]z = 0.9324[/tex]
[tex]\text{To determine the diffusion coefficient;}[/tex]
[tex]erf (0.9324) = 0.8125 = erf (\dfrac{x}{2\sqrt{Dt}}) \\ \\[/tex]
[tex]\dfrac{x}{2 \sqrt{Dt}}= 0.9324 \\ \\ \dfrac{3.9 \times 10^{-3}}{2 \times \sqrt{D\times 51 \times 3600}} = 0.92324 \\ \\ \sqrt{D} = 4.88 \times 10^{-6} \\ \\ D = \sqrt{4.88 \times 10^{-6}} \\ \\ D = 2.38 \times 10^{-11} \ m^2 /s[/tex]
How many joules are in 1.81 calories need to know ASAP
Who ever has the best answer to this question gets brainliest
Answer:
"Conduction from the sun heating the metal slide" is the answer
Explanation:
A chemist has a sample of 1.88 M HCl. What volume of the sample does he require to prepare 200 mL of 0.45 M HCl?
Answer: v = 200 ml · 0.45 M/ 1.88 M
Explanation: when solution is diluted, amount of substance
is same and n= c · V v1 = v2 · c2 / c1
The appropriate answer is "47.87 mL".
Given values are:
Concentration of undiluted HCl, [tex]C_1=1.88 \ M[/tex]Concentration of diluted HCl, [tex]C_2=0.45 \ M[/tex]Volume of diluted HCl, [tex]V_2=200 \ mL[/tex]By using the dilution equation, we get
→ [tex]C_1V_1=C_2V_2[/tex]
or,
→ [tex]V_1=\frac{C_2V_2}{C_1}[/tex]
By substituting the given values, we get
→ [tex]=\frac{0.45\times 200}{1.88}[/tex]
→ [tex]=\frac{90}{1.88}[/tex]
→ [tex]= 47.87 \ mL[/tex]
Thus the above answer is correct.
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help please i don’t know
Answer:
Okay, so basically your first question is asking what parts of everything mean so part A is the atomic number and the atomic number, in this case, the atomic number is 8 and atomic numbers are the number of protons so there are 8 protons, Part B. is the symbol which identifies what it is, O=Oxygen, Part C. is the name, oxygen, Part D. is the atomic mass, you usually round it so it would be 16, the number of protons+neutrons is this number so since we know the number of protons is 8, 16-8=8, therefore giving 8 neutrons, The number of electrons is equal to the number of protons.
After:
Now using this lovely knowledge, find Carbon and neon :)
A 23.8 mL sample of HCl of unknown concentration is neutralized by 5.45 mL of 0.331 M Ca(OH)2. What is the concentration of the HCl solution?
(The answer is 0.152, but I need an explanation/steps to get that answer)
Is this equation balanced: AgNO3 + 2 KCl -->AgCl + KNO3 Yes No
Answer:
No
Explanation:
AgNO₃ + KCl --> AgCl + KNO₃
This reaction is a precipitation reaction. AgCl is formed as a white solid due to its low solubility in water.