First, we need to set up our two equations. For the picture of this scenario, there is one length (L) and two widths (W) because the beach removes one of the lengths. We will have a perimeter equation and an area equation.
P = L + 2W
A = L * W
Now that we have our equations, we need to plug in what we know, which is the 40m of rope.
40 = L + 2W
A = L * W
Then, we need to solve for one of the variables in the perimeter equation. I will solve for L.
L = 40 - 2W
Now, we can substitute the value for L into L in the area equation and get a quadratic equation.
A = W(40 - 2W)
A = -2W^2 - 40W
The maximum area will occur where the derivative equals 0, or at the absolute value of the x-value of the vertex of the parabola.
V = -b/2a
V = 40/2(2) = 40/4 = 10
Derivative:
-4w - 40 = 0
-4w = 40
w = |-10| = 10
To find the other dimension, use the perimeter equation.
40 = L + 2(10)
40 = L + 20
L = 20m
Therefore, the dimensions of the area are 10m by 20m.
Hope this helps!
Answer:
Width: 10 m
Length: 20 m
Step-by-step explanation:
Hi there!
Let w be equal to the width of the enclosure.
Let l be equal to the length of the enclosure.
1) Construct equations
[tex]A=lw[/tex] ⇒ A represents the area of the enclosure.
[tex]40=2w+l[/tex] ⇒ This represents the perimeter of the enclosure. Normally, P=2w+2l, but because one side isn't going to use any rope (sandy beach), we remove one side from this equation.
2) Isolate one of the variables in the second equation
[tex]40=2w+l[/tex]
Let's isolate l. Subtract 2w from both sides.
[tex]40-2w=2w+l-2w\\40-2w=l[/tex]
3) Plug the second equation into the first
[tex]A=lw\\A=(40-2w)w\\A=40w-2w^2\\A=-2w^2+40w[/tex]
Great! Now that we have a quadratic equation, we can do the following:
Solve for its zeros/w-intercepts.Take the average of the zeros to find the w-variable of the vertex. (The area (A) in relation to the width of the swimming area (w) is what we've established in this equation, and the area (A) is greatest at the vertex. Finding the value of w of the vertex will tell us what the width needs to be for the area to be at a maximum.)Plug this w value into one of the equations to solve for l4) Solve for w
[tex]A=-2w^2+40w[/tex]
Factor out -2w
[tex]A=-2w(w-20)[/tex]
For A to equal 0, w=0 or w=20.
The average of 0 and 20 is 10, so the width that will max the area is 10 m.
5) Solve for l
[tex]40=2w+l[/tex]
Plug in 10 as w
[tex]40=2(10)+l\\40=20+l\\l=20[/tex]
Therefore, the length of 20 m will max the area.
I hope this helps!
HELP PLS ITS ALGEBRA 1
Answer:
[tex] - \frac{2}{6} [/tex]
Step-by-step explanation:
Use distributive property to simplify both sides.
[tex] \frac{1}{6} (1 - 6x) = - \frac{1}{3} ( 6x + \frac{1}{2} )[/tex]
Use the Golden Rule of Algebra: (What we do to one side, we must do to the other).
[tex] \frac{1}{6 } - x = - 2x - \frac{1}{6} [/tex]
[tex] \frac{1}{6} = - x - \frac{1}{6} [/tex]
[tex] \frac{2}{6 } = - x[/tex]
[tex]x = - \frac{2}{6} [/tex]
Answer:
Step-by-step explanation:
[tex]\frac{1}{6}[/tex](1-6x) = - [tex]\frac{1}{3}[/tex](6x+[tex]\frac{1}{2}[/tex])
distribute in the fractions
[tex]\frac{1}{6}[/tex] - 1x = -2x - [tex]\frac{1}{6}[/tex]
subtract [tex]\frac{1}{6}[/tex] from both sides
-[tex]\frac{1}{6}[/tex]+[tex]\frac{1}{6}[/tex]-1x = -2x -[tex]\frac{1}{6}[/tex]-[tex]\frac{1}{6}[/tex]
-1x = -2x -[tex]\frac{2}{6}[/tex]
-x = -2x - [tex]\frac{1}{3}[/tex]
[tex]\frac{1}{3}[/tex] = -2x + x
[tex]\frac{1}{3}[/tex] = -x
- [tex]\frac{1}{3}[/tex] = x
x = - [tex]\frac{1}{3}[/tex]
see? :/
Let N be the smallest positive integer whose sum of its digits is 2021. What is the sum of the digits of N + 2021?
Answer:
[tex]10[/tex].
Step-by-step explanation:
See below for a proof of why all but the first digit of this [tex]N[/tex] must be "[tex]9[/tex]".
Taking that lemma as a fact, assume that there are [tex]x[/tex] digits in [tex]N[/tex] after the first digit, [tex]\text{A}[/tex]:
[tex]N = \overline{\text{A} \, \underbrace{9 \cdots 9}_{\text{$x$ digits}}}[/tex], where [tex]x[/tex] is a positive integer.
Sum of these digits:
[tex]\text{A} + 9\, x= 2021[/tex].
Since [tex]\text{A}[/tex] is a digit, it must be an integer between [tex]0[/tex] and [tex]9[/tex]. The only possible value that would ensure [tex]\text{A} + 9\, x= 2021[/tex] is [tex]\text{A} = 5[/tex] and [tex]x = 224[/tex].
Therefore:
[tex]N = \overline{5 \, \underbrace{9 \cdots 9}_{\text{$224$ digits}}}[/tex].
[tex]N + 1 = \overline{6 \, \underbrace{000 \cdots 000000}_{\text{$224$ digits}}}[/tex].
[tex]N + 2021 = 2020 + (N + 1) = \overline{6 \, \underbrace{000 \cdots 002020}_{\text{$224$ digits}}}[/tex].
Hence, the sum of the digits of [tex](N + 2021)[/tex] would be [tex]6 + 2 + 2 = 10[/tex].
Lemma: all digits of this [tex]N[/tex] other than the first digit must be "[tex]9[/tex]".
Proof:
The question assumes that [tex]N\![/tex] is the smallest positive integer whose sum of digits is [tex]2021[/tex]. Assume by contradiction that the claim is not true, such that at least one of the non-leading digits of [tex]N[/tex] is not "[tex]9[/tex]".
For example: [tex]N = \overline{(\text{A})\cdots (\text{P})(\text{B}) \cdots (\text{C})}[/tex], where [tex]\text{A}[/tex], [tex]\text{P}[/tex], [tex]\text{B}[/tex], and [tex]\text{C}[/tex] are digits. (It is easy to show that [tex]N[/tex] contains at least [tex]5[/tex] digits.) Assume that [tex]\text{B} \![/tex] is one of the non-leading non-"[tex]9[/tex]" digits.
Either of the following must be true:
[tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex] is a "[tex]0[/tex]", or[tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex] is not a "[tex]0[/tex]".If [tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex], is a "[tex]0[/tex]", then let [tex]N^{\prime}[/tex] be [tex]N[/tex] with that "[tex]0\![/tex]" digit deleted: [tex]N^{\prime} :=\overline{(\text{A})\cdots (\text{B}) \cdots (\text{C})}[/tex].
The digits of [tex]N^{\prime}[/tex] would still add up to [tex]2021[/tex]:
[tex]\begin{aligned}& \text{A} + \cdots + \text{B} + \cdots + \text{C} \\ &= \text{A} + \cdots + 0 + \text{B} + \cdots + \text{C} \\ &= \text{A} + \cdots + \text{P} + \text{B} + \cdots + \text{C} \\ &= 2021\end{aligned}[/tex].
However, with one fewer digit, [tex]N^{\prime} < N[/tex]. This observation would contradict the assumption that [tex]N\![/tex] is the smallest positive integer whose digits add up to [tex]2021\![/tex].
On the other hand, if [tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex], is not "[tex]0[/tex]", then [tex](\text{P} - 1)[/tex] would still be a digit.
Since [tex]\text{B}[/tex] is not the digit [tex]9[/tex], [tex](\text{B} + 1)[/tex] would also be a digit.
let [tex]N^{\prime}[/tex] be [tex]N[/tex] with digit [tex]\text{P}[/tex] replaced with [tex](\text{P} - 1)[/tex], and [tex]\text{B}[/tex] replaced with [tex](\text{B} + 1)[/tex]: [tex]N^{\prime} :=\overline{(\text{A})\cdots (\text{P}-1) \, (\text{B} + 1) \cdots (\text{C})}[/tex].
The digits of [tex]N^{\prime}[/tex] would still add up to [tex]2021[/tex]:
[tex]\begin{aligned}& \text{A} + \cdots + (\text{P} - 1) + (\text{B} + 1) + \cdots + \text{C} \\ &= \text{A} + \cdots + \text{P} + \text{B} + \cdots + \text{C} \\ &= 2021\end{aligned}[/tex].
However, with a smaller digit in place of [tex]\text{P}[/tex], [tex]N^{\prime} < N[/tex]. This observation would also contradict the assumption that [tex]N\![/tex] is the smallest positive integer whose digits add up to [tex]2021\![/tex].
Either way, there would be a contradiction. Hence, the claim is verified: all digits of this [tex]N[/tex] other than the first digit must be "[tex]9[/tex]".
Therefore, [tex]N[/tex] would be in the form: [tex]N = \overline{\text{A} \, \underbrace{9 \cdots 9}_{\text{many digits}}}[/tex], where [tex]\text{A}[/tex], the leading digit, could also be [tex]9[/tex].
The price of an item decreased by 20% to $200. Then later the price decreased again from $200 to $150. What is the percent of decrease from the original price to the final price $150?
Answer:
40%
Step-by-step explanation:
ok so first find the og price:
100% - 20% = 80%
so 80% = 200
let the 100% be x:
x * 0.8 = 200
x= 250
100% = 250
(difference/ og price) * 100% = the percentage decrease/ increase
(250-150/250)* 100% = 40%
OR
((the final price/ og price) * 100%) - 100%
((150/250)*100%) - 100% = 40%
There was a 40% decrease from the og price to the final price of 150.
Can someone help me solve this problem please
Thankyouuuu
Answer:
in picture
Step-by-step explanation:
Brainliest please
Answer:
this is the best way for the question
Replace ∗ with a monomial so that the trinomial may be represented by a square of a binomial: b2 + 20b +*
Given:
The expression is:
[tex]b^2+20b[/tex]
To find:
The a monomial so that the trinomial may be represented by a square of a binomial.
Solution:
If an expression is [tex]x^2+bx[/tex], then be need to add square of half of coefficient of x, i.e., [tex]\left(\dfrac{b}{2}\right)^2[/tex] in the given expression to make in perfect square.
We have,
[tex]b^2+20b[/tex]
Here, coefficient of b is 20,so wee need to add square of half of coefficient of b, i.e., [tex]\left(\dfrac{20}{2}\right)^2[/tex].
[tex]\left(\dfrac{20}{2}\right)^2=10^2[/tex]
[tex]\left(\dfrac{20}{2}\right)^2=100[/tex]
Therefore, we need to add 100 to make [tex]b^2+20b[/tex] a perfect square binomial.
∠1 and ∠2 are supplementary angles. m∠1 = x − 39, and m∠2 = x + 61. Find the measure of each angle.
∠1 = 79, ∠2 = 101
∠1 = 40, ∠2 = 150
∠1 = 40, ∠2 = 140
∠1 = 79, ∠2 = 111
If A and B are independent events, then it must be true that P(ATB) = P(A).
well, let's take a look at two independent events
A) the potato is hot
B) it's raining
now, the potato could be hot whether is raining or not, A is totally independent of B, so what's the probability of "the potato being hot, GIVEN that it's raining" P(A | B) is the same as if it wasn't raining, or P(A), the fact that B occurred, doesn't affect A at all, the potato is hot regardless, rain or not. So P(A | B) = P(A).
What is the probality of rolling a 6-sided die on a getting a 1 or a prime number?
Answer:
1/12
Step-by-step explanation:
Chances of getting a 1 are 1/6 and chances of getting a prime number excluding 1 is 3/6. 3/6 x 1/6= 3/36 or 1/12 chance.
Drag each condition to the correct location on the table.
Match each condition to the number of triangles that can be constructed to fit the condition.
condition A: one side
measuring 4 inches,
another side measuring
8 inches, and a third
side measuring 10 inches
condition B: one angle
measuring 60°, another
angle measuring 40°, and
a third angle measuring 90°
condition C: one side
measuring 4 inches,
another side measuring
8 inches, and the angle
between them measuring 70°
condition D: one side
measuring 5 inches,
another side measuring
7 inches, and a third
side measuring 12 inches
condition E: one angle
measuring 30°, another
angle measuring 80°,
and the length of the
included side measuring
8 inches
condition F: one angle
measuring 40°, another
angle measuring 80°, and
a third angle measuring 60° I don't know how to do a pic, but it is no triangle one triangle and many triangle
Answer:
Condition A= 320 inches
Condition B= 190 Degrees F
Condition C= 2240 inches
Condition D= 350 inches
Condition E= 110 Degrees F 8 inches
Condition F= 180 Degrees F
Step-by-step explanation:
4 inches
8 inches
70 inches
60 D
40 D
90 D
4 inches
8 inches
70 D
5 inches
7 inches
12 inches
30 D
80 D
8 inches
40 D
80 D
60 D
Answer:
Condition A= 320 inches
Condition B= 190 Degrees F
Condition C= 2240 inches
Condition D= 350 inches
Condition E= 110 Degrees F 8 inches
Condition F= 180 Degrees F
Step-by-step explanation:
how do I set it up for this?
Answer:
CF = 8.5
Step-by-step explanation:
Given 2 intersecting chords, then
The product of the parts of one chord is equal to the product of the parts of the other chord, that is
CF × DF = BF × EF , substitute values
CF × 14 = 7 × 17
14CF = 119 ( divide both sides by 14 )
CF = 8.5
please help i don’t have much time left !!!
Answer:
8.5
Step-by-step explanation:
QR is 10
PQRS AREA is 45
10 times 4.5 is 45
meaning BC and PQ is 4.5
4.5 plus 4.5 is 9
26 minus 9 is 17
17 divided by two is 8.5
AB is 8.5
Solve for x. Round to the nearest tenth of a degree, if necessary.
Answer:
x ≈ 28.8°
Step-by-step explanation:
Using the sine ratio in the right triangle
sin x = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{AB}{AC}[/tex] = [tex]\frac{3.9}{8.1}[/tex] , then
x = [tex]sin^{-1}[/tex] ([tex]\frac{3.9}{8.1}[/tex] ) ≈ 28.8° ( to the nearest tenth )
I would appreciate the help on all of these :)
Answer:
Pythagoras theorem states that c²=a²+b²
14²=12²+x²
14²-12²=x²
196-144=x²
52=x²
√52=√x²
7.2111025509279785=x
rounded up to the nearest hundredth=7.21
the median of 2,8,6,10,4,12
Answer: 6
Step-by-step explanation: 6 is a median
Hey there!
To find your mean you have to put the numbers from descending (least/decreasing) to ascending (greater/increasing) order
Median is also understood as the “middle number”
2, 8, 6, 10, 4, 12
= 2, 4, 6, 8, 10, 12
Based on that information, you have in your new data set you have 2 pairs in the middle (6 & 8), so you’ll have to total/average of the number. We have to DIVIDE them by 2 because it’s 2 numbers
6 ends the descending set and 8 starts the ascending set
Median = 6 + 8 / 2
6 + 8 = 14
= 14/2
= 7
Answer: therefore your MEDIAN is most likely 7
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
c) What should be subtracted from 5m - 3n to get 2m + 5n?
What she hechosomoce 2-59
Answer:
3m-8n
Step-by-step explanation:
Set up an equation:
(5m-3n)-(2m+5n) = ?
Solve:
5m-3n
- 2m+5n
3m-8n
Hope this helps!
A wind turbine has three equally spaced blades that are each 131 feet long
What is the distance y from the tip of one blade to the tip of another blade? Round your answer to the nearest tenth. Show work
Answer:
Step-by-step explanation:
Picture this circumstance occurring within a circle. The center of the circle is where all the blades meet. That means that in terms of a circle's parts, these blades are the radii of the circle. And if they are all evenly spaced out, and there are 3 of them, the central angle in between each pair is 120 degrees (360/3). Once we know that, we can use the arc length formula for a circle which is
[tex]AL=\frac{\theta}{360}*2\pi r[/tex] and filling in:
[tex]AL=\frac{120}{360}*2(3.1415)(131)[/tex] so
AL = 274.4 feet
Please help ASAP and please explain how you got the answer.
Answer:
The third one
Step-by-step explanation:
All show complementary angles ( angles that add up to 90 degrees ) except for the third one
First one: shows a square within the two angles which indicates that the angles form a right angle ( 90 degree angle ) meaning that they are complementary angles
Second: the angles add up to equal 90 ( 50 + 40 = 90 ) hence they are complementary angles
Third one: the angles form a straight line. Angles that form a straight line add up to equal 180 and are known as supplementary angles
Fourth: the angles shown add up to 90 ( 65 + 25 = 90) hence they are complementary angles
All are complementary but the third one
Explain what the construction does and list the steps to creating the construction. Be as detailed as possible :D
Step-by-step explanation:
This construction bisects the pqr angle.
This is done by placing a compass on the pqr angle and marking construction lines at the points c and a.
Then at where the construction lines at points c and a meet the lines qr and qp draw 2 more from that placement.
Then draw a line running through angle pqr and where the construction lines meet at point b.
Hope this helps and good luck!
After simplification, the value of 1-2/1(1+2)-3/(1+2)(1+2+3)-4/(1+2+3)(1+2+3+4)-...-100/(1+2+...+99)(1+2+...+100)
is a proper fraction in its lowest form. Find the difference of its numerator and denominator.
Answer: no
Step-by-step explanationn. .......................................................w:eorkeok,feoferkeorkoe
PLZ HELPPP!!! whoever answers first with a good answer ill mark as brainliest
This is because the nth term is found by adding the previous two terms
F(n) = nth term
F(n-1) = term just before the nth term
F(n-2) = term before the F(n-1) term
F(n) = F(n-1) + F(n-2)
We can re-index values of n to say this equivalent statement
F(n+2) = F(n+1) + F(n)
Based on either equation mentioned, adding F(51) and F(52) will get us F(53). In other words, the 51st and 52nd terms add to the 53rd term.
What is the equation of the line that passes through the given point and is perpendicular to the given line?
Point: (1,1)
Line: y=15x+45
Answer:
y= -1/15x + 16/15
Step-by-step explanation:
When two lines are perpendicular to each other that means their slopes are the negative reciprocals of each other.
So that means if a line has has a slope of 6, a line perpendicular to that line will have a slope of -1/6.
(a reciprocal is when the fraction is flipped over)
In this case, the negative reciprocal of 15 would be -1/15. So the slope of the line that is perpendicular would be -1/15.
The equation we would have so far for that line would be: y=-1/15x+b
Now we have to find the 'b' or the y intercept, which we can get by plugging in the point that was given (1,1), which is on that line.
Which gives us 1=-1/15(1)+b.
1=-1/15+b
1+1/15=b
Then you solve for b and get b= 16/15.
The equation of the line that is perpendicular to the given line is y= -1/15x + 16/15.
The equation of the line that passes through the point (1, 1) and is perpendicular to y = 15x + 45 is
y = 15x - 14.
What is an equation of a line?The equation of a line is given by:
y = mx + c
where m is the slope of the line and c is the y-intercept.
Example:
The slope of the line y = 2x + 3 is 2.
The slope of a line that passes through (1, 2) and (2, 3) is 1.
We have,
Let the equation of a line is y = mx + c.
The line is perpendicular to y = 15x + 45.
y = 15x + 45 is in the form of y = mx + c
This means,
Slope = 15
m = 15
The line passes through the point (1, 1) = (x, y).
This means,
y = mx + c
1 = 15 x 1 + c
1 = 15 + c
c = 1 - 15
c = -14
The equation of the line is y = 15x - 14.
Thus,
The equation of the line that passes through the point (1, 1) and is perpendicular to y = 15x + 45 is
y = 15x - 14.
Learn more about equation of a line here:
https://brainly.com/question/23087740
#SPJ2
On a Venn diagram, shade the region:
1. AnB
2. (BnC)nA
Answer:
hope it will be helpful to you
Step-by-step explanation:
anb shade and anbnc shade
The 20th term of an arithmetic progression 1,5,9,13......
Answer:
a₂₀ = 77
Step-by-step explanation:
There is a common difference between consecutive terms , that is
5 - 1 = 9 - 5 = 13 - 9 = 4
This indicates the sequence is arithmetic with nth term
[tex]a_{n}[/tex] = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 1 and d = 4 , then
a₂₀ = 1 + (19 × 4) = 1 + 76 = 77
PLEAS ANSWER ASAP If you like peanut butter and chocolate, then you will love Reese's.
What is the contrapositive of the statement?
Having some difficulty with this test, can you please help?
Answer:
y = 3/2x +1
Step-by-step explanation:
The y int = is 1 by observation
To calculate the slope it is rise over run
3/2 as for every 3 up the line moves 2 across
What is the answer to this question
pls answer w explanation!
What is the product of the complex numbers 2 + 6i and 2 - 6i? (Note: i= √-1)
Answer:
10
Step-by-step explanation:
Apply difference of squares.
[tex](x + y)(x - y) = {x}^{2} - {y}^{2} [/tex]
[tex](2 + 6i)(2 - 6i) = {2}^{2} - {6i}^{2} [/tex]
[tex] = 4 + 6[/tex]
[tex] = 10[/tex]
Use the equation of the water level of the river represented by the equation y = −4x + 170, where x represents the number of years and y represents the total feet. What points are located on the line? Check all that apply. (170, 0) (0, 170) (12, 126) (50, 30) (5, 150) (60, –70)
Answer:
(0, 170) (5, 150) (60, -170)
Step-by-step explanation:
Plug each x value into the equation. The point is located on the line if the y values match.
Ex. -4 (170) + 170 = -510 this point is not on the line
-4 (0) + 170 = 170 this point is on the line because it is a "true" statement
Answer:
(0, 170) (5, 150) (60, -170)
Step-by-step explanation:
A paintball park charges an entrance fee, and fee per game played. On saturday, Jesse plays 19 games and pays a total of 62.50 dollars. Paula plays 10 games and pays a total of 40 dollars. Find the entrance fee and then fee per games played
Answer:
Entrance fee=15, fee per games played=2.50
Step-by-step explanation:
x=fee per games played, y=entrance fee
19x+y=62.50 equation 1
10x+y=40 equation 2
y=40-10x isolate y in equation 2
19x+40-10x=62.50 substitute y value from equation 2 into equation 1
9x=22.50
x=2.50
solve for y by substituting x value in either equation
10x+y=40
10(2.50)+y=40
25+y=40
y=15
Check answer:
19x+y=62.50
19(2.50)+15=62.50
47.50+15=62.50
62.50=62.50
PLEASE HELP ILL GIVE BRAINLIEST
If t< sand s< r what is the relationship between the values tand /?
Answer:
If you are talking about inequalities, t < r.
Step-by-step explanation:
Since s is bigger than t and r is bigger than s,
r should be bigger than t obviously.