Calculate the distance between the points J=(4, -2) and E = (7. – 7) in the coordinate plane.
Give an exact answer (not a decimal approximation).

Answer:

Step-by-step explanation:

√[(7-4)^2+{-7-(-2))^2] = √36 = 6

The distance between the points J=(4, -2) and E = (7. – 7) in the coordinate plane is 6.

"A coordinate plane is a two-dimensional plane formed by the intersection of two number lines. One of these number lines is a horizontal number line called the x-axis and the other number line is a vertical number line called the y-axis. These two number lines intersect each other perpendicularly and form the coordinate plane.

The plane is called two-dimensional because anywhere on this plane where you can put your finger, the location of that point will need two things– its distance on the x-axis and its distance on the y-axis."

Using the distance formula between the points

Given, J = (4,-2) and E = (7,-7)

Distance formula = [tex]\sqrt((x1 - x2)^2 -(y1 - y2)^2)[/tex]

[tex]= \sqrt((4-7)^2 + (-2 - (-7))^2)\\\\= \sqrt(9 + 25) = 6[/tex]

Hence, distance between the points J and E = 6

To know more about coordinate plane here:

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