bug s is slow and bug f is fast. both bugs start at 0 on a number line and move in the positive direction. the bugs leave 0 at the same time and move at constant speeds. four seconds later, f is at 12 and s is at 8. how many units apart are bugs f and s thirty seconds after leaving point 0.

Answers

Answer 1

After 30 seconds the bugs will be apart by (x -y) = 30 units

What is speed?

The speed of an object, aIso known as "v" in everyday speech and kinematics, is a scaIar quantity that measures how much its position changes over time or how much it changes per unit of time.

The distance traveIIed by an object during a time intervaI is equaI to the duration of the intervaI divided by the object's speed, with the instantaneous speed being the upper Iimit of the average speed as the intervaI's duration gets cIoser to zero. VeIocity differs from speed. Distance divided by time is the formuIa for measuring speed. A metre per second (m/s) is the metric unit of speed.

a) The speed of F is 12 units in 4 seconds, or 3 units per second.

x = 3t

The speed of S is 8 units in 4 seconds, or 2 units per second.

y = 2t

b) x-y = 3t -2t = t

After 30 seconds the bugs will be apart by (x -y) = 30 units

c) x - y = 100 = t

The bugs will be 100 units apart after 100 seconds.

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Answer 2

The distance between bug f and bug s after 30 seconds is: distance = 90 - 60 = 30 units.

what is algebra?

Algebra is a branch of mathematics that deals with mathematical operations and symbols used to represent numbers and quantities in equations and formulas. It involves the study of variables, expressions, equations, and functions.

When bug s and bug f leave point 0, they are initially at the same location, which is at position 0 on the number line. After four seconds, bug s has traveled a distance of 4v_s units from point 0, and bug f has traveled a distance of 4v_f units from point 0. We know that bug f has traveled 12 units in this time, so:

4v_f = 12

Solving for v_f, we get:

v_f = 3 units per second

Similarly, we know that bug s has traveled a distance of 8 units in four seconds, so:

4v_s = 8

Solving for v_s, we get:

v_s = 2 units per second

Now we can find out how far apart the bugs are after 30 seconds. Bug f has traveled a distance of 30v_f units from point 0, which is:

30v_f = 30 x 3 = 90 units

Similarly, bug s has traveled a distance of 30v_s units from point 0, which is:

30v_s = 30 x 2 = 60 units

Therefore, the distance between bug f and bug s after 30 seconds is:

distance = 90 - 60 = 30 units.

So the bugs are 30 units apart after 30 seconds.

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Related Questions

Solve each proportion

Answers

Answer:

D

Step-by-step explanation:

the correct answer is D

What is the difference in the interest that would have accrued if all of the money from question
#9 had only been in the savings account for the same 60 days?

Answers

We'll presume that the cash in question were initially split between two accounts since we don't know the answer to question #9: the amount that has been sitting in a savings account for 60 days is $78.00.

Where ought I to put my cash?

Because the FDIC for savings accounts and the NCUA for community bank accounts guarantee all deposit made by consumers, savings are a secure location to put your money.

Is keeping money in a savings account wise?

Savings accounts might assist you avoid overspending by keeping the money away from your spending account. You should save emergency cash in your bank account for easy access. Savings accounts keep money secure because the Deposit Insurance Corporation of the United States insures them for up to $250,000.

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A spinner is divided into seven equal sections numbered 1 through 7 If the spinner is spun twice, what is the THEORETICAL probability that it lands on 2 and then an odd number?
A) 1/49
B) 4/49
C) 1/7
D) 4/7

Answers

Answer: A) 1/49

Step-by-step explanation:

Since the spinner has seven equal sections numbered 1 through 7, the theoretical probability of landing on any particular number on a single spin is 1/7.

To find the theoretical probability that the spinner lands on 2 and then an odd number, we can multiply the probability of landing on 2 on the first spin by the probability of landing on an odd number on the second spin.

The probability of landing on 2 on the first spin is 1/7, and the probability of landing on an odd number on the second spin is 3/7 (there are three odd numbers among the remaining six sections).

Therefore, the theoretical probability of the spinner landing on 2 and then an odd number is:

(1/7) x (3/7) = 3/49

So the answer is A) 1/49.

The lunch special at Maria's Restaurant is a sandwich and a drink. There are 2 sandwiches and 5 drinks to choose from. How many lunch specials are possible?

Answers

Answer:

the question is incomplete, so I looked for similar questions:

There are 3 sandwiches, 4 drinks, and 2 desserts to choose from.

the answer = 3 x 4 x 2 = 24 possible combinations

Explanation:

for every sandwich that we choose, we have 4 options of drinks and 2 options of desserts = 1 x 4 x 2 = 8 different options per type of sandwich

since there are 3 types of sandwiches, the total options for lunch specials = 8 x 3 = 24

If the numbers are different, all we need to do is multiply them. E.g. if instead of 3 sandwiches there were 5 and 3 desserts instead of 2, the total combinations = 5 x 4 x 3 = 60.

For this question's answer, there are 2 x 5 = 10 lunch specials are possible.

The number of lunch specials possible are 10.

How many ways k things out of m different things (m ≥ k) can be chosen if order of the chosen things doesn't matter?

We can use combinations for this case,

Total number of distinguishable things is m.

Out of those m things, k things are to be chosen such that their order doesn't matter.

This can be done in total of

[tex]^mC_k = \dfrac{m!}{k! \times (m-k)!} ways.[/tex]

If the order matters, then each of those choice of k distinct items would be permuted k! times.

So, total number of choices in that case would be:

[tex]^mP_k = k! \times ^mC_k = k! \times \dfrac{m!}{k! \times (m-k)!} = \dfrac{m!}{ (m-k)!}\\\\^mP_k = \dfrac{m!}{ (m-k)!}[/tex]

This is called permutation of k items chosen out of m items (all distinct).

We are given that;

Number of sandwiches=2

Number of drinks=5

Now,

To find the total number of lunch specials, we need to multiply the number of choices for sandwiches by the number of choices for drinks.

Number of sandwich choices = 2

Number of drink choices = 5

Total number of lunch specials = 2 x 5 = 10

Therefore, by combinations and permutations there are 10 possible lunch specials.

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find the value of the derivative (if it exists) at
each indicated extremum.

Answers

Answer:

The value of the derivative at (0, 0) is zero.

Step-by-step explanation:

Given function:

[tex]f(x)=\dfrac{x^2}{x^2+4}[/tex]

To differentiate the given function, use the quotient rule and the power rule of differentiation.

[tex]\boxed{\begin{minipage}{5.4 cm}\underline{Quotient Rule of Differentiation}\\\\If $y=\dfrac{u}{v}$ then:\\\\$\dfrac{\text{d}y}{\text{d}x}=\dfrac{v \dfrac{\text{d}u}{\text{d}x}-u\dfrac{\text{d}v}{\text{d}x}}{v^2}$\\\end{minipage}}[/tex]

[tex]\boxed{\begin{minipage}{5.4 cm}\underline{Power Rule of Differentiation}\\\\If $y=x^n$, then $\dfrac{\text{d}y}{\text{d}x}=nx^{n-1}$\\\end{minipage}}[/tex]

[tex]\boxed{\begin{minipage}{5.4cm}\underline{Differentiating a constant}\\\\If $y=a$, then $\dfrac{\text{d}y}{\text{d}x}=0$\\\end{minipage}}[/tex]

[tex]\begin{aligned}\textsf{Let}\;u &= x^2& \implies \dfrac{\text{d}u}{\text{d}{x}} &=2 \cdot x^{(2-1)}=2x\\\\\textsf{Let}\;v &=x^2+4& \implies \dfrac{\text{d}v}{\text{d}{x}} &=2 \cdot x^{(2-1)}+0=2x\end{aligned}[/tex]

Apply the quotient rule:

[tex]\implies f'(x)=\dfrac{v \dfrac{\text{d}u}{\text{d}x}-u\dfrac{\text{d}v}{\text{d}x}}{v^2}[/tex]

[tex]\implies f'(x)=\dfrac{(x^2+4) \cdot 2x-x^2 \cdot 2x}{(x^2+4)^2}[/tex]

[tex]\implies f'(x)=\dfrac{2x(x^2+4)-2x^3}{(x^2+4)^2}[/tex]

[tex]\implies f'(x)=\dfrac{2x^3+8x-2x^3}{(x^2+4)^2}[/tex]

[tex]\implies f'(x)=\dfrac{8x}{(x^2+4)^2}[/tex]

An extremum is a point where a function has a maximum or minimum value. From inspection of the given graph, the minimum point of the function is (0, 0).

To determine the value of the derivative at the minimum point, substitute x = 0 into the differentiated function.

[tex]\begin{aligned}\implies f'(0)&=\dfrac{8(0)}{((0)^2+4)^2}\\\\&=\dfrac{0}{(0+4)^2}\\\\&=\dfrac{0}{(4)^2}\\\\&=\dfrac{0}{16}\\\\&=0 \end{aligned}[/tex]

Therefore, the value of the derivative at (0, 0) is zero.

(b) Write 5 as a percentage.​

Answers

Answer:

5 as a percentage of 100 is 5/100 which is 5%

any point on the parabola can be labeled (x,y), as shown. a parabola goes through (negative 3, 3)

Answers

The correct standard form of the equation of the parabola is:

[tex]y = -x^2 - 1[/tex].

To find the standard form of the equation of the parabola that passes through the given points (-3, 3) and (1, -1), we can use the general form of the equation of a parabola:

[tex]y = ax^2 + bx + c[/tex] ___________(1)

Substituting the coordinates of the two given points into this equation, we get a system of two equations in three unknowns (a, b, and c):

[tex]3 = 9a - 3b + c[/tex]

[tex]-1 = a + b + c[/tex]

To solve for a, b, and c, we can eliminate one of the variables using subtraction or addition. Subtracting the second equation from the first, we get:

[tex]4 = 8a - 4b[/tex]

Simplifying this equation, we get:

[tex]2 = 4a - 2b[/tex]

Dividing both sides by 2, we get:

[tex]1 = 2a - b[/tex]___________(2)

Now we can substitute this expression for b into one of the earlier equations to eliminate b. Using the first equation, we get:

[tex]3 = 9a - 3(2a - 1) + c[/tex]

Simplifying this equation, we get:

[tex]3 = 6a + c + 3[/tex]

Subtracting 3 from both sides, we get:

[tex]0 = 6a + c[/tex]

Solving for c, we get:

c = -6a __________(3)

Substituting this expression for c into the second equation, we get:

[tex]-1 = a + (2a - 1) - 6a[/tex]

Simplifying this equation, we get:

[tex]-1 = -3a - 1[/tex]

Adding 1 to both sides, we get:

[tex]-3a =0[/tex]

Solving for a, we get:

[tex]a = 0[/tex]

Substituting this value of a into the equation(3) for c, we get:

c = 0

Substituting a = 0 into the equation(2) for b that we found earlier, we get:

[tex]1 = 0 - b[/tex]

Solving for b, we get:

[tex]b = -1[/tex]

Putting the values of a, b and c in (1), we get

[tex]y = -x^2 - 1[/tex]

Therefore, the equation of the parabola that passes through the given points (-3, 3) and (1, -1) is:

[tex]y = -x^2 - 1[/tex]

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Complete question:

A parabola goes through (-3, 3) & (1, -1). A point is below the parabola at (-3, 2). A line above the parabola goes through (-3, 4) & (0, 4). A point on the parabola is labeled (x, y).

What is the correct standard form of the equation of the parabola?

The figure is in the image attached below

The Khan Shatyr Entertainment Center in Kazakhstan is the largest tent in the world. The spire on top is 60 m in length. The distance from the center of the tent to the outer edge is 97.5 m. The angle between the ground and the side of the tent is 42.7°.

Find the total height of the tent (h), including the spire.
Find the length of the side of the tent (x)

Answers

i. The total height of the tent including the spire is 150 m.

ii. The length of the side of the tent  x is 132.7 m.

What is a trigonometric function?

Trigonometric functions are required functions in determining either the unknown angle of length of the sides of a triangle.

Considering the given question, we have;

a. To determine the total height of the tent, let its height from the ground to the top of the tent be represented by x. Then:

Tan θ = opposite/ adjacent

Tan 42.7 = h/ 97.5

h = 0.9228*97.5

  = 89.97

h = 90 m

The total height of the tent including the spire = 90 + 60

                                           = 150 m

b. To determine the length of the side of the tent x, we have:

Cos θ = adjacent/ hypotenuse

Cos 42.7 = 97.5/ x

x = 97.5/ 0.7349

  = 132.67

The length of the side of the tent x is 132.7 m.

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Find the standard normal area for each of the following(round your answers to 4 decimal places)

Answers

Answer:

  (a) 0.0955

  (b) 0.0214

  (c) 0.9545

  (d) 0.3085

Step-by-step explanation:

You want the area under the standard normal PDF curve for intervals (1.22, 2.15), (2.00, 3.00), (-2.00, 2.00), and (0.50, ∞).

Calculator

The probability functions of a suitable calculator or spreadsheet can find these values for you. The attachment shows one such calculator. Its "normalcdf" function takes as arguments the lower bound and upper bound.

We used 1E99 as a stand-in for "infinity" as recommended by the calculator's user manual. For the purpose here, any value greater than 10 will suffice.

what is the number of real solutions

-X^2-9=6x

Answer options
1. Cannot be determined
2. No real solutions
3. One solution
4. two solutions​

Answers

Answer:

3. One solution

Step-by-step explanation:

-x²-9 = 6x

or, x²+6x+9 = 0

or, x²+2.x.3+3² = 0 [using (a+b)² = a²+2ab+b²]

or, (x+3)² = 0

or, x+3 = 0

x = -3

What is the equation of the line graphed?

Answers

The equation of given line which is graphed is  [tex]x+2=0.[/tex] By locating the slope (m) and y-intercept (b) in the graph of a line, we can define a linear function in the form y=mx+b.

What is the formula for a line on a line graph?

A straight line's graph equation can be expressed as [tex]y = m x + c[/tex]  , which consists of a term, a term, and a number. a new. to the a and the likes in the likes thes of the likes of thes of thes of thes of thes of thes of people.

A line graph is a type of graph that uses straight lines to connect the data points. A line graph can show how something changes over time or compares different situations1.

A horizontal line has the equation \(y = c\), where \(c\) is a constant. This means that the \(y\)-value of every point on the line is the same

Therefore, The set of all points (x,y) in the plane that satisfy the equation   [tex]y=f(x) y = f (x)[/tex]    is the function's graph.

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Find the sum-of-products expansions of the Boolean function F (x, y, z) that equals 1 if and only if a) x = 0. b) xy = 0. c) x + y = 0. d) xyz = 0.

Answers

a) F(x,y,z) = y'z'. b) F(x,y,z) = x'y'z' + x'y'z + xy'z'. c) F(x,y,z) = x'y'z'. d) F(x,y,z) = x'y'z + x'yz' + xy'z' + x'y'z'. These are the sum-of-products expansions of the Boolean function F(x, y, z) for the given conditions.

a) When x = 0, F(x,y,z) equals 1 if and only if yz = 0. This can be expressed as the sum of products: F(x,y,z) = y'z' (read as "not y and not z").

b) When xy = 0, F(x,y,z) equals 1 if and only if either x = 0 or y = 0. This can be expressed as the sum of products: F(x,y,z) = x'y'z' + x'y'z + xy'z' (read as "not x and not y and not z" OR "not x and not y and z" OR "x and not y and not z").

c) When x + y = 0, F(x,y,z) equals 1 if and only if x = y = 0. This can be expressed as the sum of products: F(x,y,z) = x'y'z' (read as "not x and not y and not z").

d) When xyz = 0, F(x,y,z) equals 1 if and only if x = 0 or y = 0 or z = 0. This can be expressed as the sum of products: F(x,y,z) = x'y'z + x'yz' + xy'z' + x'y'z' (read as "not x and not y and z" OR "not x and y and not z" OR "x and not y and not z" OR "not x and not y and not z").

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Label each of the following as Discrete Random Variable, Continuous Random Variable, Categorical Random Variable, or Not a Variable. 1. The Name of the people in the car that crosses the bridge Not a Variable 2. The time between each car crossing the bridge Continuous Random Variable 3. The type of cars that cross the bridge Categorical Random Variable 4. The number of cars that use the bridge in one hour Continuous Random Variable Question 2 3 pts Which of these are Continuous and which are Discrete Random Variables? 1. Type of coin Continuous Random Variable 2. Distance from a point in space to the moon Discrete Random Variable 3. Number of coins in a stack Continuous Random Variable

Answers

Distance from a point in space to the moon is a continuous random variable and Number of coins in a stack is a discrete random variable.

A discrete random variable is one that has a finite number of possible values or one that can be countably infinitely numerous. A discrete random variable is, for instance, the result of rolling a die because there are only six possible outcomes.

A continuous random variable, on the other hand, is one that is not discrete and "may take on uncountably infinitely many values," like a spectrum of real numbers.

1. The Name of the people in the car that crosses the bridge - Not a Variable

2. Continuous random variable measuring the interval between each car crossing the bridge.

3. The Categorical Random Variable for the type of vehicles crossing the bridge

4. The number of cars that use the bridge in one hour - Continuous Random Variable

For Question 2:

1. Type of coin - Categorical Random Variable

2. The distance from a given location in space to the moon - Continuous Random Variable

3. Number of coins in a stack - Discrete Random Variable

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Complete question is:

Label each of the following as Discrete Random Variable, Continuous Random Variable, Categorical Random Variable, or Not a Variable.

1. The Name of the people in the car that crosses the bridge Not a Variable

2. The time between each car crossing the bridge Continuous Random Variable

3. The type of cars that cross the bridge Categorical Random Variable

4. The number of cars that use the bridge in one hour Continuous Random Variable

Question 2: Which of these are Continuous and which are Discrete Random Variables?

1. Type of coin

2. Distance from a point in space to the moon

3. Number of coins in a stack

Question 11 (1 point)

(06.03 LC)


What is the product of the expression, 5x(x2)?


a

25x2


b

10x


c

5x3


d

5x2

Answers

The expressiοn 5x(x²) is equal tο 5 * x¹ * x² (5 * x³ = 5x³). Thus, οptiοn (c) 5x3 is the cοrrect respοnse.

Hοw are prοducts οf expressiοn determined?

The cοefficients (the numbers in frοnt οf the variables) οf the expressiοn 5x(x²) can be multiplied, and the expοnents οf the variables can be added, tο determine the prοduct.

The first cοefficient we have is 5 times 1, giving us 5. Sο, using the secοnd x², we have x tο the pοwer οf 2 multiplied by x tο the pοwer οf 1 (frοm the first x). Expοnents are added when variables with the same base are multiplied. Sο, x¹ multiplied by x² results in x³.

Cοmbining all οf the parts, the phrase becοmes:

5x(x²) is equal tο 5 * x¹ * x² (5 * x³ = 5x³).

Thus, οptiοn (c) 5x³ is the cοrrect respοnse.

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Work out the size of angle x. 79°) 35​

Answers

Answer: 66

Step-by-step explanation:

all 3 of them should equal to 180

so 79+35 is 114

180-114 will give us the answer which is 66

0.0125 inches thick
Question 4
1 pts
The combined weight of a spool and the wire it carries is 13.6 lb. If the weight of the spool is 1.75 lb.,
what is the weight of the wire?
Question 5
1 pts

Answers

In linear equation, 11.85 pounds is the weight of the wire.

What is  linear equation?

A linear equation is a first-order (linear) term plus a constant in the algebraic form y=mx+b, where m is the slope and b is the y-intercept. The variables in the previous sentence, y and x, are referred to as a "linear equation with two variables" at times.

Total weight of pool having 16 wires     =13.6 pounds

Weight of the pool                                 =1.75

Therefore the weight of the wire alone = 13.6 - 1.75

                                                             =  11.85 pounds

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Dividing sin^2Ø+cos^2Ø=1 by ____ yields 1+cot^2Ø=csc^2Ø


a.cot^2Ø

b.tan^2Ø

c.cos^2Ø

d.csc^2Ø

e.sec^2Ø

f.sin^2Ø

Answers

To obtain the required equation we divide the equation by sin²Ø.

What are trigonometric functions?

The first six functions are trigonometric, with the domain value being the angle of a right triangle and the range being a number. The angle, expressed in degrees or radians, serves as the domain and the range of the trigonometric function (sometimes known as the "trig function") of f(x) = sin. Like with all other functions, we have the domain and range. In calculus, geometry, and algebra, trigonometric functions are often utilised.

The given equation is:

sin²Ø+cos²Ø=1

To obtain the required equation we divide the equation with sin²Ø:

sin²Ø/sin²Ø +cos²Ø/ sin²Ø = 1/sin²Ø

1 + cot²Ø = csc²Ø

Hence, to obtain the required equation we divide the equation by sin²Ø.

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One reason for using a distribution instead of the standard Normal curve to find critical values when calculating a level C confidence interval for a population mean is that
(a) z can be used only for large samples.
(b) z requires that you know the population standard deviation θ
.
(c) z requires that you can regard your data as an SRS from the population.
(d) the standard Normal table doesn't include confidence levels at the bottom.
(e) a z critical value will lead to a wider interval than a t critical value.
(b) z requires that you know the population standard deviation θ
.

Answers

Therefore , the solution of the given problem of standard deviation comes out to be the group standard deviation in order to use (b) z.

What does standard deviation actually mean?

Statistics uses variance as a way to quantify difference. The image of the result is used to compute the average deviation between the collected data and the mean. Contrary to many other valid measures of variability, it includes those pieces of data on their own by comparing each number to the mean. Variations may be caused by willful mistakes, irrational expectations, or shifting economic or business conditions.

Here,

We use the z-distribution if the total standard deviation is known; otherwise, we use the t-distribution.

Additionally, for small sample sizes, the t-distribution is used, whereas for big sample sizes, the z-distribution is used.

The fact that z requires that you know the population standard deviation, and that this is frequently not known in practice, is one reason to use a distribution rather than the traditional .

Normal curve to find critical values when computing a level C confidence interval for a population mean.

You must be aware of the group standard deviation in order to use (b) z.

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The Butler family and the Phillips family each used their sprinklers last summer. The water output rate for the Butler family's sprinkler was 25 L per hour. The water output rate for the Phillips family's sprinkler was 40 L per hour. The families used their sprinklers for a combined total of 55 hours, resulting in a total water output of 1750 L. How long was each sprinkler used?

Answers

The Butler family used their sprinkler for 30 hours and the Phillips family used their sprinkler for 25 hours.

Let's solve the problem with algebra.

Let x represent the number of hours the Butlers used their sprinkler, and y represent the number of hours the Phillips family used their sprinkler. We are aware of the following:

The Butler family's sprinkler had a water output rate of 25 L per hour, so the total amount of water they used is 25x.

The Phillips family's sprinkler had a water output rate of 40 L per hour, so the total amount of water they used was 40y.

The sprinklers were used by the families for a total of 55 hours, so x + y = 55.

The total amount of water produced was 1750 L, so 25x + 40y = 1750.

Using these equations, we can now solve for x and y.

First, we can solve for one of the variables in terms of the other using the equation x + y = 55. For instance, we can solve for x as follows:

x = 55 - y

When we plug this into the second equation, we get:

25(55 - y) + 40y = 1750

We get the following results when we expand and simplify:

1375 - 25y + 40y = 1750

15y = 375

y = 25

As a result, the Phillips family ran their sprinkler for 25 hours. We get the following when we plug this into the equation x + y = 55:

x + 25 = 55

x = 30

As a result, the Butlers used their sprinkler for 30 hours.

As a result, the Butler family sprinkled for 30 hours and the Phillips family sprinkled for 25 hours.

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Let sinθ= 2√2/5 and π/2 < θ < π Part A: Determine the exact value of cos 2θ. Part B: Determine the exact value of sin (θ/2)

Answers

Answer:

Part A: To determine the exact value of cos 2θ, we can use the double-angle identity for cosine:

cos 2θ = 2 cos^2 θ - 1

We already know sin θ, so we can use the Pythagorean identity to find cos θ:

cos^2 θ = 1 - sin^2 θ

cos^2 θ = 1 - (2√2/5)^2

cos^2 θ = 1 - 8/25

cos^2 θ = 17/25

cos θ = ± √(17/25)

cos θ = ± (1/5) √17

Since θ is in the third quadrant (π/2 < θ < π), cos θ is negative, so we take the negative root:

cos θ = -(1/5) √17

Substituting into the double-angle identity:

cos 2θ = 2 cos^2 θ - 1

cos 2θ = 2 [-(1/5) √17]^2 - 1

cos 2θ = 2 (1/25) (17) - 1

cos 2θ = 34/25 - 1

cos 2θ = 9/25

Therefore, the exact value of cos 2θ is 9/25.

Part B: To determine the exact value of sin (θ/2), we can use the half-angle identity for sine:

sin (θ/2) = ± √[(1 - cos θ)/2]

We already know cos θ, so we can substitute it in:

cos θ = -(1/5) √17

sin (θ/2) = ± √[(1 - cos θ)/2]

sin (θ/2) = ± √[(1 - (-1/5) √17)/2]

sin (θ/2) = ± √[(5 + √17)/10]

sin (θ/2) = ± (1/2) √(5 + √17)

Since θ is in the third quadrant (π/2 < θ < π), sin θ is negative, so we take the negative root:

sin (θ/2) = -(1/2) √(5 + √17)

Therefore, the exact value of sin (θ/2) is -(1/2) √(5 + √17).

The exact values of the sine and cosine given are -(1/2) √(5 + √17) and 9/25.

What is the sine and the cosine of an angle?

The sine of an angle in a right triangle is the ratio of the hypotenuse to the side opposite the angle.

The cosine of an angle in a right triangle is the ratio of the hypotenuse to the side adjacent the angle.

Part A: To determine the exact value of cos 2θ, we can use the double-angle identity for cosine:

cos 2θ = 2 cos² θ - 1

Using the Pythagorean identity to find cos θ:

cos² θ = 1 - sin² θ

cos² θ = 1 - (2√2/5)²

cos² θ = 1 - 8/25

cos² θ = 17/25

cos θ = ± √(17/25)

cos θ = ± (1/5) √17

Since θ is in the third quadrant (π/2 < θ < π), cos θ is negative, so we take the negative root:

cos θ = -(1/5) √17

Substituting into the double-angle identity:

cos 2θ = 2 cos² θ - 1

cos 2θ = 2 [-(1/5) √17]² - 1

cos 2θ = 2 (1/25) (17) - 1

cos 2θ = 34/25 - 1

cos 2θ = 9/25

Therefore, the exact value of cos 2θ is 9/25.

Part B: To determine the exact value of sin (θ/2), we can use the half-angle identity for sine:

sin (θ/2) = ± √[(1 - cos θ)/2]

We already know cos θ, so we can substitute it in:

cos θ = -(1/5) √17

sin (θ/2) = ± √[(1 - cos θ)/2]

sin (θ/2) = ± √[(1 - (-1/5) √17)/2]

sin (θ/2) = ± √[(5 + √17)/10]

sin (θ/2) = ± (1/2) √(5 + √17)

Since θ is in the third quadrant (π/2 < θ < π), sin θ is negative, so we take the negative root:

sin (θ/2) = -(1/2) √(5 + √17)

Therefore, the exact value of sin (θ/2) is -(1/2) √(5 + √17).

Hence, the exact values of the sine and cosine given are -(1/2) √(5 + √17) and 9/25.

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Last week, the price of bananas at a grocery store was $1.40 per pound. This week, bananas at the
same grocery store are on a sale at a 10% discount. What is the total price of 6 pounds of bananas this
week at the grocery store?
A. $8.19
B. $9.18
C. $9.10
D. $8.40

Answers

According to one meaning of the phrase, it merely refers to the selling price of something. For instance, a piece of art would be sold for that amount if bids reached a record high of $10 million. Thus, option A is correct

What is the sale price by the number of pounds?

The sale price of bananas this week is 10% off the original price of $1.40 per pound, which means the sale price is:

$1.40 - 10% of $1.40 = $1.26 per pound

To find the total cost of 6 pounds of bananas this week, we can multiply the sale price by the number of pounds:

$1.26 per pound * 6 pounds = $ [tex]7.56[/tex]

Therefore, the total price of 6 pounds of bananas this week at the grocery store is $ [tex]7.56[/tex] .

However, we need to be careful with the answer choices provided. They all differ from $7.56, so we need to double-check our calculations.

If we add a 10% discount to $1.40 per pound, we get:

$1.40 - (10/100)*$1.40 = $1.26 per pound

And the total cost of 6 pounds at $1.26 per pound is:

$ [tex]1.26 \times 6[/tex] = $ [tex]7.56[/tex]

Therefore,  $ [tex]8.19[/tex] is not a possible answer, and the other options are either miscalculated or rounded incorrectly.

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Traffic signs are regulated by the Manual on Uniform Traffic Control Devices (MUTCD). The perimeter of a rectangular traffic sign is 126 inches. Also, its length is 9 inches longer than its widthFind the dimensions of this sign.

Answers

Answer:

Traffic signs are regulated by the Manual on Uniform Traffic Control Devices (MUTCD). The perimeter of a rectangular traffic sign is 126 inches. Also, its length is 9 inches longer than its widthFind the dimensions of this sign.

Step-by-step explanation:

Let's say the width of the sign is x inches. Then, according to the problem, the length of the sign is 9 inches longer than the width, which means the length is x + 9 inches.

The perimeter of a rectangle can be found by adding up the length of all its sides. For this sign, the perimeter is given as 126 inches. So we can set up an equation:

2(length + width) = 126

Substituting the expressions for length and width in terms of x, we get:

2(x + x + 9) = 126

Simplifying and solving for x:

2(2x + 9) = 126

4x + 18 = 126

4x = 108

x = 27

So the width of the sign is 27 inches, and the length is 9 inches longer, or 36 inches. Therefore, the dimensions of the sign are 27 inches by 36 inches.

Question 9 (2 points)
A survey asked 1,000 people if they invested in Stocks or Bonds for retirement. 700
said they invested in stocks, 400 said bonds, and 300 said both.
How many invested in neither stocks nor bonds?
Note: consider making a Venn Diagram to help solve this problem.
0
200
400
100

Answers

200 people invested in neither stocks nor bonds for retirement.

What is inclusion-exclusion principle?

The inclusion-exclusion principle is a counting method used to determine the size of a set created by joining two or more sets. It is predicated on the notion that if we just sum the set sizes, we can wind up counting certain components more than once (the elements that are in the intersection of the sets). We deduct the sizes of the sets' intersections from the sum of their sizes to prevent double counting.

The total number of people who invested in stocks are:

Total = Stocks + Bonds - Both

Total = 700 + 400 - 300

Total = 800

Using the inclusion- exclusion principle:

neither = Total surveyed - Total

neither = 1000 - 800 = 200

Hence, 200 people invested in neither stocks nor bonds for retirement.

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please help me with math i’ll give you brainlist

Answers

Answer: False

Step-by-step explanation:

25% of the data is between Q1 and the median.

3) Al hacerle un inventario el Sr. Manuel a su negocio que inició con un capital de 800.000,00 Bs, y su precio de venta al público el 60% sobre el costo de los productos, éste arrojó un monto de 385.000,00 Bs. Tomándose en cuenta que en gastos fueron 74.680,00 Bs, en pagos varios 247.000,00 Bs y en cuentas por pagar 185.460,00 Bs. ¿Diga, si el saldo del negocio es positivo (Ganancia) o es negativo (Pérdida)?

Answers

The end balance is negative, so Mr. Manuel lost money.

Is there a profit or a loss?

We know that Mr. Manuel spended $800,000 in a product, and it can be sold with an extra 60% over the cost. Then the revenue here is:

$800,000*(1.6) = $1,280,000

We also know that there are costs of $75,680, $247.000 and $185.460.

Now we know that profit is defined as the difference between the revenue and the costs, so to get the profit we need to solve the equation below:

P = $1,280,000 - $800,000 - $75,680 - $247.000 - $185.460

P = -$28,140

So we can see that Mr. Manuel had a loss at the end.

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A standard glass of wine is 5 oz. How many full glasses of wine can you get from a typical 750 ml bottle

Answers

Answer: 5 standard glasses

A standard glass of wine is 5 ounces. This is typical for any dry white, red, orange, or rosé wine. A standard bottle is 750mL, or about 25 ounces of wine. So, a normal 750mL bottle has 5 standard glasses of wine.

find the following answer

Answers

Cardinality of given set is 10.

Describe Cardinality.

The cardinality of a mathematical set refers to the number of entries in the set. It may be limited or limitless. For instance, if set A has six items, its cardinality is equivalent to 6: 1, 2, 3, 4, 5, and 6. A set's size is often referred to as the set's cardinality. The modulus sign is used to indicate it on either side of the set name, |A|.

a Set's Cardinality

A set that can be counted and has a finite number of items is said to be finite. On the other hand, an infinite set is one that has an unlimited number of components and can either be countable or uncountable.

Possible set of A=14+4+1+9=28

Possible set of C=1 +6+9+9=25

n(A∩ C)=10

Hence, Cardinality of given set is 10.

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Can someone help quick i have 6 questions left

Answers

Answer:

Step-by-step explanation:

long leg = 78  (means that 26√3*√3 = 26√9 = 26*3 = 78

for x: Short leg= 26√3

Hypotenuse= 2*26√3 = 52√3 for y

How many different strings of length 12 containing exactly five a's can be chosen over the following alphabets? (a) The alphabet {a,b) (b) The alphabet {a,b,c}

Answers

There are 792 strings across a,b, and 27,720 in a,b,c.

(a) We must select five slots for a's in an alphabet of "a,b" before filling the remaining spaces with "b's." Hence, the binomial coefficient is what determines how many strings of length 12 that include precisely five as:

C(12,5) = 792

As a result, there are 792 distinct strings of length 12 that include exactly five a's across the letters a, b.

(b) We may use the same method as before for an alphabet consisting of the letters "a,b,c." The first five slots must be filled with a's, followed by three b's, and the final four positions must be filled with c's. The number of strings of length 12 that contain exactly five a's across the letters "a," "b," and "c" is thus given by:

C(12,5) * C(7,3) = 792 * 35 = 27720

Thus, there are 27,720 distinct strings.

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30 POINTS! PLEASEHELP

Answers

Answer:

Required length is 13 feet

Step-by-step explanation:

[tex]{ \rm{length = \sqrt{ {12}^{2} + {5}^{2} } }} \\ \\ { \rm{length = \sqrt{144 + 25} }} \\ \\ { \rm{length = \sqrt{169} }} \\ \\ { \rm{length = 13 \: feet}}[/tex]

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