If the measure of 24 is 100°, what is the measure of 28?​

The equation of the required line in slope-intercept form is y = -1/4x + 8.

Here are the steps to find the equation of the line:

Step 1: Find the slope of the given line in slope-intercept form

y = mx + c

-4x + y = 43 ⇒ y = 4x + 43... (1)

Here, the slope (m1) of the given line is 4.

Step 2: Find the slope of the required line as the two lines are perpendicular to each other.

m1 × m2 = -1

[As the given line and the required line are perpendicular to each other]

4 × m2 = -1 ⇒ m2 = -1/4

So, the slope (m2) of the required line is -1/4.

Step 3: Write the equation of the required line in point-slope form.

y - y1 = m(x - x1)

[Using the point-slope formula]

Let (x1, y1) = (-8, 10)m = -1/4

Putting the values in the above formula, we get

y - 10 = -1/4(x - (-8)) ⇒ y - 10 = -1/4(x + 8)... (2)

Step 4: Simplify the above equation to get the required equation of the line in slope-intercept form.

y - 10 = -1/4x - 2 ⇒ y = -1/4x + 8... (3)

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Using the Poisson Approximation the probability are:

a)  0.6321

b)  0.3679

c) 0.2642

The Poisson distribution is utilized to compute the likelihood of a particular amount of occurrences happening over a set period. The Poisson approximation will be used to answer the given question, and it is a form of a probability distribution that can be used to approximate the probability of particular events that occur infrequently, and it is suitable for both continuous and discrete variables.

a) The probability of having at least one student with the same birthday as Brad using the Poisson Approximation.

Let the number of other students with the same birthday as Brad be represented by x. Here, x is a discrete variable with a Poisson distribution that follows a Poisson distribution with an average of λ, which is equal to 1:

λ = average number of students having the same birthday as Brad = 1.

Using the Poisson distribution formula, the probability of having at least one student with the same birthday as Brad is given by:

P(X >= 1) = 1 - P(X = 0)

= 1 - e ^ (-λ)P(X = 0)

= (e^(-λ))(λ^0) / 0!

= e^(-λ)

= e^(-1)

= 0.3679

Therefore, the probability of having at least one student with the same birthday as Brad is:

P(X >= 1) = 1 - P(X = 0)

= 1 - 0.3679

= 0.6321

b) The probability of having exactly one student with the same birthday as Brad using Poisson Approximation

P(X = 1) = (e^(-λ))(λ^1) / 1!

= e^(-1)(1) / 1!

= e^(-1)

= 0.3679

Therefore, the probability of having exactly one student with the same birthday as Brad is:

P(X = 1)

= e^(-1)

= 0.3679

c) The probability of having at least two students with the same birthday as Brad using Poisson Approximation

P(X >= 2) = 1 - P(X < 2)

= 1 - [P(X = 0) + P(X = 1)]

= 1 - [e^(-λ)(λ^0) / 0! + e^(-λ)(λ^1) / 1!]

= 1 - [e^(-1) + e^(-1)(1) / 1!]

= 1 - [e^(-1) + e^(-1)]

= 1 - 2e^(-1)

= 0.2642

Exact probability: 1 - (364/365)^180 = 0.4406

Poisson Approximation Probability: 0.6321

The exact probability is 0.4406, which is less than the Poisson approximation probability, which is 0.6321.

This result indicates that the Poisson approximation formula overestimates the likelihood of having at least one student with the same birthday as Brad.

Exact probability: (364/365)^179(1/365) = 0.3775

Poisson Approximation Probability: 0.3679

The exact probability is 0.3775, which is quite similar to the Poisson approximation probability, which is 0.3679.

This result indicates that the Poisson approximation formula provides a reasonably precise estimate of the likelihood of having exactly one student with the same birthday as Brad.

Exact probability: 1 - [1 + 364/365 + ... + (364!/347!)/365^34] = 0.1827

Poisson Approximation Probability: 0.2642

The exact probability is 0.1827, which is less than the Poisson approximation probability, which is 0.2642.

This result indicates that the Poisson approximation formula overestimates the likelihood of having at least two students with the same birthday as Brad.

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a.

There are 15,504 ways to choose 20 batteries from the given types.

b.

there are 18,564 ways to choose 20 batteries such that at least four of them are 9-volt batteries.

To choose 20 batteries from the given 5 types (aaa, aa, c, d, and 9-volt), we can use the combination formula and is given by:

nCr = n! / (r! * (n-r)!)

5C20 = 5! / (20! * (5-20)!) = 15,504

there are 15,504 ways to choose 20 batteries from the given types.

b. To choose 20 batteries such that at least four of them are 9-volt batteries, we employ the method:

First, we choose four 9-volt batteries out of the total number of 9-volt batteries, which is 1.

we then need to choose the remaining 16 batteries from the remaining 4 types (aaa, aa, c, and d), while making sure that we don't choose any 9-volt batteries.

Applying the combination formula, with n = 4 and r = 16:

4C16 = 4! / (16! * (4-16)!) = 18,564

Therefore, the total number of ways to choose 20 batteries such that at least four of them are 9-volt batteries is:

1 * 18,564 = 18,564

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We are given that the SAT and ACT measure the same aptitude but use different scales. To find the equivalent ACT score for a given SAT score, we can use the conversion chart.
SAT 1100 = ACT 23
Therefore, the equivalent ACT score for a student with an SAT score of 1104 is 23.
3. If a student gets an SAT score of 1536, find the equivalent ACT score.
Solution:
To find the equivalent ACT score for a given SAT score, we can use the conversion chart.
SAT 1536 = ACT 35
Therefore, the equivalent ACT score for a student with an SAT score of 1536 is 35.
Therefore, the SAT score = 1536 and the ACT score = 35.

1. If a student gets an SAT score that is the 70th percentile, find the actual SAT score.
Solution:
We are given that SAT scores are normally distributed with a mean of 990 and a standard deviation of 201. We are asked to find the SAT score for the 70th percentile.
P( SAT score < X) = 0.70
We can use the standard normal table to find the corresponding z-score for the 70th percentile.
z = 0.52
We can use the z-score formula to find the SAT score:
z = (X - μ) / σ
0.52 = (X - 990) / 201
X = 1103.72
Therefore, the actual SAT score for the 70th percentile is 1104.
2. What would be the equivalent ACT score for this student?

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The slopes are,

1) 7/6

2)7/2

3) -1

4) -2

5) 10/9

What is slope?

Calculated using the slope of a line formula, the ratio of "vertical change" to "horizontal change" between two different locations on a line is determined. The difference between the line's y and x coordinate changes is known as the slope of the line.Any two distinct places along the line can be used to determine the slope of any line.

1) The given points , [tex](x_1,y_1) =(0,1)[/tex] and [tex](x_2,y_2) = (6,8)[/tex] then,

=> slope  = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex] = [tex]\frac{8-1}{6-0} = \frac{7}{6}[/tex]

2) The given points [tex](x_1,y_1) =(-1,10)[/tex] and [tex](x_2,y_2) = (-5,-4)[/tex] then,

=> Slope = [tex]\frac{-4-10}{-5+1} = \frac{-14}{-4}=\frac{7}{2}[/tex]

3)  The given points [tex](x_1,y_1) =(-10,2)[/tex] and [tex](x_2,y_2) = (-3,-5)[/tex] then,

=> slope = [tex]\frac{-5-2}{-3+10} = \frac{-7}{7}=-1[/tex]

4)  The given points [tex](x_1,y_1) =(-3,-4)[/tex] and [tex](x_2,y_2) = (-1,-8)[/tex] then,

=> slope = [tex]\frac{-8+4}{-1+3} = \frac{-4}{2}=-2[/tex]

5)The given points [tex](x_1,y_1) =(0,1)[/tex] and [tex](x_2,y_2) = (-9,-9)[/tex] then,

=> slope = [tex]\frac{-9-1}{-9+0} = \frac{-10}{-9}=\frac{10}{9}[/tex]

Hence the slopes are,

1) 7/6

2)7/2

3) -1

4) -2

5) 10/9

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In response to the stated question, we may state that As a result, the function student will have to pay off the debt in 24 weeks.

In mathematics, a function is a connection between two sets of numbers in which each member of the first set (known as the domain) corresponds to a single element in the second set (called the range). In other words, a function takes inputs from one set and produces outputs from another. Inputs are commonly represented by the variable x, whereas outputs are represented by the variable y. A function can be described using an equation or a graph. The equation y = 2x + 1 represents a linear function in which each value of x yields a distinct value of y.v

a. Let L(w) be the monetary amount owing after w weeks.

Because the starting amount owing is $360 and the weekly payment is $15, the equation for the amount owed as a function of time is: L(w) = 360 - 15w

b. The inverse function of L(w) reflects the number of weeks required to repay a certain loan amount. In terms of L, we can solve for w:

L = 360 - 15w

L - 360 = -15w

w = (360 - L)/15

As a result, the inverse function is: L(-1)(w) = (360 - w)/15.

c. 0 = 360 - 15w

15w = 360 = 24

As a result, the student will have to pay off the debt in 24 weeks.

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Increasing lexicographic order: (0, 0), (0, 1/2), (1/4, 0), (1/4, 1/2)).Thus, the increasing lexicographic order of the critical points of the function f(x,y) = xy(1 - 4x - 2y) are (0, 0), (0, 1/2), (1/4, 0), and (1/4, 1/2).

lexicographic order: (0, 0), (0, 1/2), (1/4, 0), (1/4, 1/2)).Thus, the increasing lexicographic order of the critical points of the function f(x,y) = xy(1 - 4x - 2y) are (0, 0), (0, 1/2), (1/4, 0), and (1/4, 1/2).

Suppose that f(x,y) = xy(1 - 4x - 2y). f(x,y) has 4 critical points.

Let's discuss what are critical points and how we can determine them,A critical point is a point on the graph where the derivative changes its sign.

In other words, the derivative either changes from negative to positive or from positive to negative. A critical point is also known as a stationary point or a turning point

To determine the critical points, we need to find the derivative of the given function and set it equal to zero.The given function is[tex]f(x,y) = xy(1 - 4x - 2y).[/tex]

Let's find the partial derivative of f with respect to [tex]x:f_x(x,y) = y(1 - 4x - 2y) - 4xy = (1-2y)(1-4x)y.[/tex] (1)

Now, find the partial derivative of f with respect to y:f_y(x,y) = x(1 - 4x - 2y) - 2xy = (1-2x)(1-2y)x. (2)

To find the critical points, we need to set both partial derivatives (1) and (2) equal to zero.

(1-2y)(1-4x) = 0 and (1-2x)(1-2y) = 0.

Solving both equations separately, we have the following critical points:(1/4, 1/2), (1/4, 0), (0, 1/2), and (0, 0).

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The greater number is [tex]$n^3+8$[/tex]

Let x be the greater number and y be the smaller number. We know that x-y=8.

We are also given that the smaller number is n³.

So we can set up the equation:

x = y + 8

x = n³ + 8

Therefore, the greater number is [tex]$n^3+8$[/tex].

The greater number is given as n³ + 8. If the smaller number we get is represented by the n³,  then by adding 8 to that value gives the greater number. The difference between the two numbers is always going to be 8, regardless of the value of n.

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As a result, the triangles and are similar triangles according to the meaning of similarity. Thus, the Angle-Angle Similarity Principle has been demonstrated.

Three straight edges and three angles make up a closed, two-dimensional triangle. By joining three non-collinear lines, it is created. One of the most fundamental geometric shapes, triangles are used in many disciplines, including physics, engineering, and construction. According to their edges and angles, triangles can be classified as equilateral, isosceles, scalene, acute, obtuse, or right triangles.

given

Take into account two triangles Z and T such that ZT ZX and ZUZY. We must demonstrate the similarity of these two shapes.

We are aware that if two triangles are similar, their respective sides and angles will be proportional.

Now, let's prove that the respective sides of these two triangles are proportional. Since ZT ZX, the respective sides of similar triangles result in TZ/ZX = TU/ZY. If we simplify this number, we obtain:

TU/ZX Equals TZ/ZY.

This demonstrates that the ratio between the respective sides of these two triangles.

As a result, the triangles and are similar triangles according to the meaning of similarity. Thus, the Angle-Angle Similarity Principle has been demonstrated.

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The complete question is :- Write a proof of the Angle-Angle Similarity Theorem.

If two angles of one triangle are congruent to two angles of another triangle, then the triangles are similar.

Given: ZT ZX, ZUZY

Prove: Δτυν - ΔΧΥΖ

Dilate XYZ by the scale factor

Dimension of photograph is 35cm and 22cm.

And external dimension of photo frame is 45cm and 30cm

So, the area of the border surrounding the photograph=Area of photo frame−Area of photo.

So, The area of the border surrounding the photograph [tex]=45\times30-35\times22[/tex]

[tex]=1350-770=580cm^2[/tex]

The product of the two expressions can be simplified to -1/2(y-1).

Let's first focus on the expression 27y/(y²-1). This expression has a denominator that is a difference of squares, which we can factor as (y+1)x(y-1). We can then use partial fraction decomposition to rewrite the expression as follows:

27y/(y²-1) = (A/(y+1)) + (B/(y-1))

Multiplying both sides by (y+1)x(y-1), we get:

27y = Ax(y-1) + Bx(y+1)

We can then solve for A and B by setting y = 1 and y = -1, respectively. This gives us:

A = -9 B = 9

Substituting these values back into our partial fraction decomposition, we get:

27y/(y²-1) = (-9/(y+1)) + (9/(y-1))

Now let's focus on the expression (y²+y)/(36y²). We can factor out a y from the numerator and denominator to get:

y(y+1)/(36yxy)

We can then simplify this expression by cancelling out the y's:

(y+1)/36

Now that we have simplified each expression separately, we can multiply them together.

(27y/(y²-1)) x ((y²+y)/(36y²)) = ((-9/(y+1)) + (9/(y-1))) x ((y+1)/36)

We can distribute the second expression and simplify:

=> ((-9y)/(y+1) + (9y)/(y-1)) x ((y+1)/36) = ((-9y)(y-1) + (9y)(y+1)) / (36x(y²-1))

=> (-9y² + 9y - 9y² - 9y) / (36x(y²-1)) = (-18y² - 18y) / (36x(y²-1))

=> (-1/2)x(y+1)/(y-1)(y+1) = -1/2(y-1)

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It sounds like you want to find how many diagonals a nonagon has.

A nonagon has n = 9 sides.

The number of diagonals would be...

[tex]d = \text{number of diagonals}\\\\d = \frac{n(n-3)}{2}\\\\d = \frac{9(9-3)}{2}\\\\d = \frac{9(6)}{2}\\\\d = \frac{54}{2}\\\\d = 27\\\\[/tex]

A nonagon has 27 different diagonals.

Answer: 2 solutions

Step-by-step explanation:

To find the angle of a regular polygon, use the formula 180(n-2)/n (where n is the amount of sides.)

Setting them equal, we get (180n-360)/n = 1680.

Multiplying by n on both sides, we get 180n-360 = 1680n.

Solving, we get 1500n = 360.

n = 0.24, which means it is not a shape, as you cannot have a shape with 0.24 sides.

The other way to look at it is to take full revolutions of 360 away from each angle, giving us 240 (the smallest remainder without it going negative). However, all the angles would be concave. If all the angles are concave, then it might connect backwards.

Subtracting 240 from 360 (to get the "exterior" angles, we get 120. Plugging it in to our equation 180(n-2)/n and solving, we get 180n-360 = 120n, and solving gives us 60n = 360, or n=6.

Since the amount of sides came together cleanly, we can classify this polygon as a normal hexagon, which has 6 sides.

Answer: 5 ≥ y-2 is equivalent to y ≤ 7.

Step-by-step explanation: To check if 5 is greater than or equal to y-2, we need to isolate the variable y on one side of the inequality sign.

5 ≥ y - 2

First, we can add 2 to both sides to get rid of the subtraction of 2 on the right side:

5 + 2 ≥ y - 2 + 2

7 ≥ y

Therefore, we can see that y is less than or equal to 7 for this inequality to hold true.

To work out the mean cost of a present in pounds (£), we need to divide the total cost of the presents (£80.52) by the number of presents (4).

The calculation will look like this:

£80.52 ÷ 4 = £20.13

Therefore, the mean cost of a present in pounds (£) is £20.13.

Answer:

9. 6.32

10. 4.12

Step-by-step explanation:

9. c^2 = 2^2 + 6^2 = 4 + 36 = 40

c = √40 = 6.32

10. c^2 = 1^2 + 4^2 = 17

c = √17 = 4.12

The loan's interest rate, which is [tex]0.475[/tex] percent or [tex]4.75[/tex]%, is imposed by Andrea.

An interest rate provides information on how costly lending is or how profitable saving is. Hence, if you are a borrower, an interest rate refers to the total you pay for borrowing money and is expressed as a proportion of the total loan amount.

Borrowing money is more expensive when rates of interest are elevated and less expensive when rates of interest are low. Be sure you fully understand how the rate of interest will impact the entire amount you have to pay before accepting a loan.

maturity value [tex]=[/tex] principal [tex]+[/tex] (principal [tex]*[/tex] interest rate [tex]*[/tex] time)

maturity value [tex]= 34,275[/tex]

principal [tex]= 30,000[/tex]

time [tex]= 3[/tex] years

So we have:

[tex]34,275 = 30,000 + (30,000 * interest rate * 3)[/tex]

Simplifying this equation, we get:

[tex]34,275 - 30,000 = 9,000 *[/tex] interest rate

[tex]4,275 = 9,000[/tex] [tex]*[/tex] interest rate

interest rate [tex]= 4,275 / 9,000[/tex]

interest rate [tex]= 0.475[/tex]

Therefore, the interest rate charged on the loan is [tex]0.475[/tex] or [tex]4.75[/tex]%.

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Answer: Yes Sofia will have enough money

=======================================================

Explanation:

Refer to the drawing below. I've split the hexagon into two pieces. The bottom is a rectangle and the top is a trapezoid.

The area of the rectangle is 16*7 = 112 square meters.

The trapezoid has 16 as one of the parallel sides. The other side is x meters. We'll use the perimeter 54 to determine what x must be

sum of the exterior sides = perimeter

6+7+16+7+6+x = 54

42+x = 54

x = 54-42

x = 12

The top most side is 12 meters. This is the missing side of the trapezoid. The hexagon has a height of 12.66 meters, so the trapezoid's height must be 12.66-7 = 5.66 meters. Refer to the blue segment I marked in the drawing below.

area of the trapezoid = 0.5*height*(base1+base2)

area = 0.5*5.66*(16+12)

area = 79.24 square meters

----------------

Recap so far

The total area of the entire hexagon is therefore 112+79.24 = 191.24 square meters.

Let's convert that to square decimeters.

Recall that 1 decimeter = 10 centimeters

Multiply both sides by 10

1 decimeter = 10 centimeters

10*(1 decimeter) = 10*(10 centimeters)

10 decimeters = 100 centimeters

10 decimeters = 1 meter

Then,

[tex]191.24 \text{ sq m}= 191.24 \text{ sq m} * \frac{10 \text{ dm}}{1 \text{ m}} * \frac{10 \text{ dm}}{1 \text{ m}}\\\\= \frac{191.24*10*10}{1*1} \text{ sq dm}\\\\= 19124 \text{ sq dm}\\\\[/tex]

The entire lawn is 19124 square decimeters.

----------------

We have one final block of calculations to determine the total price.

x = number of rolls

1 roll covers 90 square decimeters

x rolls cover 90x square decimeters

90x = 19124

x = 19124/90

x = 212.489 approximately

Round up to the nearest integer to get x = 213. It doesn't matter that 212.489 is closer to 212. We round up to clear the hurdle. It means we'll have leftover grass that isn't used (perhaps it could be handy to have some back up grass just in case mistakes are made, and some patches need to be redone).

In short, Sofia needs 213 rolls.

1 roll costs $4.50

213 rolls will cost 213*4.50 = 958.50 dollars.

This is under the $1000 threshold (with 1000-958.50 = 41.50 dollars to spare).

Sofia will have enough money to pay for all of the grass.

Answer:

Exponents are a mathematical notation used to represent repeated multiplication. An exponent, also known as a power, consists of a base number and a small superscript number, which indicates how many times the base number should be multiplied by itself.

For example, in the expression 2^3, the base number is 2 and the exponent (or power) is 3. This means that 2 should be multiplied by itself three times: 2 x 2 x 2 = 8. So, 2^3 is equal to 8.

Exponents can also be negative or fractions. In these cases, the negative exponent indicates division and the fraction exponent indicates taking a root.

For instance, in the expression 2^-3, the negative exponent means that 2 is in the denominator of a fraction: 1/2 x 1/2 x 1/2 = 1/8. So, 2^-3 is equal to 1/8.

In the expression 4^(1/2), the fraction exponent means that we take the square root of 4: 2 x 2 = 4. So, 4^(1/2) is equal to 2.

Exponents have many practical applications in science, engineering, and other fields. They can be used to represent large or small quantities, as well as to simplify complex mathematical expressions.

Step-by-step explanation:

The `det(E2) of the given matrix is equal to 366`.

Given a 5 by 5 matrix E= `[11 2 -1 -3 4;10 -1 -2 -1 -2;-1 2 3 2 1;1 1 1 -1 -1;2 -1 -2 1 1]`.

To find `det(E)`, we can use the following steps.

Step 1: Create a 5 by 5 matrix E1 by adding a multiple of the ith row to the jth row, given i = 3 and j = 5.

We need to add -1/3 times the 3rd row to the 5th row. It can be done by the following operation.`E1 = E` (start with the original matrix) `=> E1(5,:) = E(5,:) - E(3,:) / 3` (subtract the 3rd row of E divided by 3 from the 5th row of E)

This results in the matrix `E1 = [11 2 -1 -3 4;10 -1 -2 -1 -2;-1 2 3 2 1;1 1 1 -1 -1;1/3 -7/3 -7/3 7/3 4/3]

`Step 2: Create a 5 by 5 matrix E2 by adding a multiple of the ith row to the jth row, given i = 2 and j = 5.We need to add -20 times the 2nd row to the 5th row.

It can be done by the following operation.`E2 = E1` (start with the matrix from Step 1) `=> E2(5,:) = E1(5,:) - 20 * E1(2,:)` (subtract 20 times the 2nd row of E1 from the 5th row of E1)

This results in the matrix `E2 = [11 2 -1 -3 4;10 -1 -2 -1 -2;-1 2 3 2 1;1 1 1 -1 -1;0 -13 33 -13 44]

`Step 3: Find det(E2) by using the cofactor expansion along the 5th column.`det(E2) = 0 - (-13) * A1 + 33 * A2 - (-13) * A3 + 44 * A4 - 0 * A5`where A1, A2, A3, A4, and A5 are the 2 by 2 determinants of the submatrices obtained by deleting the 5th row and the ith column, for i = 1, 2, 3, 4, and 5. We can use the following notation.

A1 = det([11 -1 -3 4;10 -2 -1 -2;-1 3 2 1;]) = 324A2 = det([11 2 -3 4;10 -1 -1 -2;-1 2 2 1;]) = -54A3 = det([11 2 -1 4;10 -1 -2 -2;-1 2 3 1;]) = -142A4 = det([11 2 -1 -3;10 -1 -2 -1;-1 2 3 2;]) = 50A5 = det([11 2 -1 -3;10 -1 -2 -1;-1 2 3 2;]) = 366.

Therefore `det(E2) = 0 - (-13) * 324 + 33 * (-54) - (-13) * (-142) + 44 * 50 - 0 * 50 = 366`.

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For (a), the value for x is 11, as P(X>x) = 0.5 when the mean is 7 and the standard deviation is 4. This can be found using the standard normal table.

For (b), the value for x is 19, as P(X>x) = 0.95 when the mean is 7 and the standard deviation is 4. This can also be found using the standard normal table.

For (c), the value for x is 9, as P(x< X<9) = 0.2 when the mean is 7 and the standard deviation is 4. This is found by subtracting the z-scores of x and 9 from each other, and then finding the area of the z-score between those two numbers using the standard normal table.

For (d), the value for x is 4, as P(3< X) = 0.2 when the mean is 7 and the standard deviation is 4. This is found by subtracting the z-score of 3 from the mean and then finding the area of the z-score to the left of that number using the standard normal table.

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The expected value of cases in which juries got the right decision is 150, and the variance is 375.

1. Since 25% of defendants in the state are innocent, that means that 75% of the defendants are guilty.
2. This means that in the given year, 150 out of the 200 people put on trial will be guilty.
3. Thus, the expected value of cases in which juries got the right decision is 150.
4. The variance of the number of cases in which juries got the right decision is calculated by taking the expected value and subtracting it from the total number of people put on trial, which is 200.
5. The result of the calculation is 375, which is the variance of cases in which juries got the right decision.

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Answer:

The answer is 657 and 365.

Step-by-step explanation:

Let the two numbers be x and y respectively

In first case,

x+y=1022

x=1022-y----------- eqn i

In second case

x-y=292

1022-y-y=292 [From eqn i]

1022-2y=292

1022-292=2y

730=2y

730/2=y

y=365

Substituting the value of y in eqn i

x=1022-y

x=1022-365

x=657

Hence two numbers are 657 and 365.

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the volume of the rectangular prism with a width of 10 cm, height of 3 cm, and a depth of 7 cm is 210 cubic cm.

The volume of a rectangular prism is calculated by multiplying its length, width, and height. In this case, the width is 10 cm, the height is 3 cm, and the depth is 7 cm. Therefore, the volume of the rectangular prism can be calculated as follows:

Volume = Length x Width x Height

Since the length of the rectangular prism is not given, we cannot calculate the exact volume. However, we can provide a formula that can be used to calculate the volume of any rectangular prism with the given dimensions.

Formula for the volume of a rectangular prism:

Volume = Width x Height x Depth

Substituting the given values, we get:

Volume = 10 cm x 3 cm x 7 cm

Volume = 210 cubic cm

Therefore, the volume of the rectangular prism with a width of 10 cm, height of 3 cm, and a depth of 7 cm is 210 cubic cm.

It is important to note that the unit of measurement used for the dimensions should be the same for all three dimensions in order to obtain the correct volume. In this case, the unit of measurement used is centimeters (cm), and the volume is expressed in cubic centimeters (cm³).

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Answer:

4[tex]\sqrt{2\\}[/tex]

Step-by-step explanation:

This is a 45 45 90 Triangle meaning that x would be 4 squareroot 2

so the formula goes lets say 4= a and the other side is b

a=b and x=a[tex]\sqrt{2[/tex]

Therefore, the area of the whole figure is 60170 square centimeters.

Area is a measurement of the amount of space inside a 2-dimensional shape, such as a rectangle, triangle, circle, or any other polygon. It is usually measured in square units, such as square inches, square feet, square meters, etc. The formula for finding the area of a shape depends on the type of shape. For example, the area of a rectangle is calculated by multiplying its length by its width, while the area of a circle is calculated by multiplying the square of its radius by pi (3.14).

Here,

To find the area of the whole figure, we need to find the area of the triangle and the area of the rectangle, and then add them together.

The area of the triangle can be found using the formula:

Area of triangle = (1/2) x base x height

where base is the length of one side of the triangle (2 cm) and height is the altitude (1.7 m). We need to convert the altitude to centimeters to match the units of the base:

1.7 m = 170 cm

So, the area of the triangle is:

Area of triangle = (1/2) x 2 cm x 170 cm = 170 cm²

The area of the rectangle is simply:

Area of rectangle = length x width = 2 m x 3 m = 6 m²

Now, we can add the two areas together to get the total area of the figure:

Total area = Area of triangle + Area of rectangle

= 170 cm² + 6 m²

Since the units are different, we need to convert one of them to match the other. Let's convert the area of the rectangle from meters to centimeters:

6 m² = 60000 cm²

Now, we can add the two areas together:

Total area = 170 cm² + 60000 cm²

= 60170 cm²

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One Imaginary solution is not possible for a quadratic equation of the form ax² + bx + c = 0.

By replacing the factorization method, the quadratic formula aids in evaluating the quadratic equations' solutions.

A quadratic equation has the general form ax² + bx + c = 0, where a, b, and c are real numbers, sometimes known as "numeric coefficient".

We can forecast the nature of the roots by determining the discriminant's value.

Three potential outcomes, each with a different impact

If b² - 4ac > 0, two separate roots that are real.

If b² - 4ac = 0, two real roots have magnitudes that are equal.

If b² - 4ac 0, there are no real roots and just imaginary ones.

Thus, the quadratic equation ax² + b x + c = 0 cannot have a single imaginary solution.

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The fireworks display occurred due north of the person at point A. This can be determined by calculating the direction and speed of sound. Assuming the speed of sound is approximately 343 meters per second, the fireworks display must have occurred approximately 0.58 seconds away from point A, which is approximately 343 meters due north of point A. This means that the fireworks display occurred somewhere between the two points.


To double-check the calculations, we can look at the two points and the direction in which the sound traveled. Point A is due north of the fireworks display, and point B is due west. This means that the sound traveled both north and west, which is consistent with the calculations.


Therefore, we can conclude that the fireworks display occurred due north of point A.

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