A youth club has 150 members. 60 of the members are girls. What percentage of the club members are girls?
Answer:
40 %
Step-by-step explanation:
no of members in youth club = 150
no of girls = 60
girls percentage = ?
girls percentage = no of girls / total members * 100%
= 60 / 150 *100%
=6000 / 150
=40 %
25 points!! Which table shows 4 points on the line that passes through the point (–1,5) and has the same slope as the line 2x+3y=6?
For a certain population, the population proportion is .6. If samples of size 60 are taken, determine the standard deviation of the distribution of sample proportions rounded to the nearest hundredth.
The standard deviation of the distribution of sample proportions is rounded to the nearest hundredth.60 Are taken but the single is 1.
How is the standard deviation of the sampling distribution of a proportion calculated?The population proportion is .6. If samples of size 60 are taken, determine the standard deviation of the distribution of sample proportions rounded to the nearest hundredth.
The Sampling Distribution of the Sample Proportion
and standard deviation σˆP=√pq/n.
How do you find the proportion of a population with mean and standard deviation?This is given by the formula Z=(X-m)/s where Z is the z-score, X is the value you are using, m is the population means and s is the standard deviation of the population. Consult a unit normal table to find the proportion of the area under the normal curve falling to the side of your value.13
Learn more about standard deviation at
https://brainly.com/question/475676
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What is the product?
(-20d^2+s)(5d^2-6s)
Answer:
-100d⁴ + 125d²s - 6s²
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Terms/CoefficientsExpand by FOILStep-by-step explanation:
Step 1: Define
Identify
(-20d² + s)(5d² - 6s)
Step 2: Expand
FOIL: -100d⁴ + 120d²s + 5d²s - 6s²[Addition] Combine like terms: -100d⁴ + 125d²s - 6s²how to solve 3^8 times 3^2
Answer:
3072 that what I known as a 10th grader
help please asap just the answers
a = 2 ; b = −1 and c = −3
The values are :
[tex]a = 2[/tex][tex]b = - 1[/tex][tex]c = - 3[/tex]let's plug the values :
[tex] {c}^{2} + 5ab[/tex][tex]( - 3) {}^{2} + (5 \times 2 \times - 1)[/tex][tex]9 - 10[/tex][tex]-1[/tex]Therfore, correct answer is :
[tex] \large - 1[/tex][tex]\mathfrak{good \: \: luck \: \: for \: \: your \: \: assignment}[/tex]
[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]
[tex] \huge\underline{\sf{\red{Problem:}}}[/tex]
9.) Detemine the value of [tex] \sf{ {c}^{2} + 5ab.}[/tex][tex] \huge\underline{\sf{\red{Given:}}}[/tex]
[tex]\quad\quad\quad\quad\sf{a = 2}[/tex]
[tex]\quad\quad\quad\quad\sf{b = - 1}[/tex]
[tex]\quad\quad\quad\quad\sf{c = - 3}[/tex]
[tex] \huge\underline{\sf{\red{Solution:}}}[/tex]
[tex]\quad\quad\quad\quad\sf{⟶{c}^{2} + 5ab}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶{( - 3)}^{2} + 5( 2)( - 1)}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶9+ 5( 2)( - 1)}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶9+ 10( - 1)}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶9 - 10 }[/tex]
[tex]\quad \quad \quad \quad ⟶ \boxed{ \sf{ -1}}[/tex]
[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]
[tex]\huge\quad \quad \underline{ \boxed{ \sf{ \red{-1}}}}[/tex]
[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]
#CarryOnLearning
[tex]\sf{\red{✍︎ C.Rose❀}}[/tex]
HELP I HAVE 10 MINS
If AB and CD have endpoints at A(- 1,3), B(6,8), C(4, 10) and D(9,3), are AB and CD parallel,
perpendicular, or neither? Explain.
Answer:
perpendicular
If k = 23 and m
-14, what is ✓k + m?
Submit
Answer:
3
Step-by-step explanation:
Evaluate:
Sqrt of k = 32 + m = -14
Sqrt of 32-14 = 9
Sqrt of 9 = 3
Therefore, our answer is 3!
Btw sqrt means: square root
Hope this helps! Have a good day!
What is the value of [tex]\frac{81^4}{3^5}[/tex]? (Express your answer in exponential form.)
Answer:[tex]3^1^1\\[/tex]
Step-by-step explanation:
[tex]\frac{81^4}{3^5}[/tex]
[tex]\frac{3^1^6}{3^5}[/tex]
The base is same power can be add or subtract
[tex]3^1^6^-^5[/tex]
[tex]3^1^1[/tex]
10 points!!!!! Do 14 and 15 only hurry please.
Answer:
8. x = 16
9. x = 10
14.
m ∠RSU = 130°
m ∠UST = 50°
15.
m ∠RSU = 124°
m ∠UST = 56°
Step-by-step explanation:
8.
Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF
That is , (x + 15)° = 31°
x = 31 - 15 = 16
9.
Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF
That is ,
(6x - 4)° = 56°
6x = 56 + 4
6x = 60
x = 10
14.
13x + 5x = 180° [straight line angles ]
18x = 180
x = 10
m ∠RSU = 130°
m ∠UST = 50°
15.
4x + 12 + 2x = 180° [ straight line angles]
6x = 180 - 12
6x = 168
x = 28
m ∠RSU = 4(28) + 12 = 112 + 12 = 124°
m ∠UST = 2(28) = 56°
Answer:
14. 13x+5x
=18x
180(angles on a st. line)= 18x
180/18
=10
RSU=13*10=130
UST=5*10=50
What is the value of 2 + (-2/3) ^2 ÷1/3 ?
16
3
-2
0
.
Answer:
Doing the test rn got 3 1/3 i dont know if u should trust me but just try
Step-by-step explanation:
Jeanette purchased a concert ticket on a web site. The original price of the ticket was $75. She used a coupon code to receive a 20% discount. The web site applied a 10% service fee to the discounted price. What was the final cost of the ticket?
Answer:
$66
Step-by-step explanation:
$75
75*.8 =60
60*1.1= $66
What is the value of U
I don't have a value... jk jk :)
Answer: 40°
Explanation... since U is on a straight line and since GS is 140
180 - 140 = 40
Hope it helps...
Please help I’ll give brainliest
Answer:
The answer for this question is 3
Answer:
i believe its 2 but i could be wrong
Step-by-step explanation:
im sorry if i am
Solve for x.
3x +13
6x + 5
x = [?]
Answer:
nessa resposta da 10 beijos
Answer:
x = 18
Step-by-step explanation:
The given angles are same- side exterior angles and sum to 180°, that is
6x + 5 + 3x + 13 = 180
9x + 18 = 180 ( subtract 18 from both sides )
9x = 162 ( divide both sides by 9 )
x = 18
Express 60g as a percentage of 3kg?
Answer:
2%
60/3000g= ?/100
60×100/3000=2
A delivery truck is transporting boxes of two sizes: large and small. The combined weight of a large box and a small box is 80 pounds. The truck is transporting 60 large boxes and 65 small boxes. If the truck is carrying a total of 4975 pounds in boxes, how much does each type of box weigh? X Large box: pounds Small box: ( pounds 5 ?
Answer:
small = 35 pounds
large = 45 pounds
Step-by-step explanation:
Let x = large boxes
y = small boxes
two equations can be derived from the question
x + y = 80 equation 1
60x + 65y = 4975 equation 2
multiply equation 1 by 60
60x +60y = 4800 equation 3
subtract equation 2 from 3
5y = 175
y = 35
substitute for y in equation 1
x + 35 = 80
x = 80 - 35
x = 45
Pls don’t have much time
Answer:
the answer is b
Step-by-step explanation:
35 occurs the most on the graph meaning that it's the mode
32% of the days in a year the wind blows south.About how many days does the wind blows south?
Answer:
116 days because 32 percent of 365 is 116
Bari Jay, a gown manufacturer, received an order for prom dresses from China. Her cost is $32 a gown. If her markup based on selling price is 76%, what is the selling price of each gown? (Round your answer to the nearest cent.)
Answer:
$56.32
Step-by-step explanation:
Find the selling price by multiplying the original cost by 1.76:
32(1.76)
= 56.32
So, the selling price is $56.32
Find a third-degree polynomial equation with rational coefficients that has roots –5 and 6 + i.
The coefficients of the polynomial are rational, which means that any non-real roots occur alongside their complex conjugates. In this case, 6+i is a root, so 6-i is also a root.
So the simplest polynomial you can build with these roots is
(x - (-5)) (x - (6 + i )) (x - (6 - i )) = x ^3 - 7x ^2 - 23x + 185
(first choice)
Identify each expression with a sum of x2 + 3x +1.
Answer:
There are no like terms.
Step-by-step explanation:
Helppppp
Solve for x.
X= [?]
5х – 5/2x + 10
Answer:
if you want to find how many degree for x
Step-by-step explanation:
you must collect all degree and completing 180 degree for this, (5x-5)+(2x+10)=180 7x=175 x=10,12
Now,
5x - 5 + 2x + 10 = 180° ( linear pair )
7x + 5 = 180°
7x = 180° - 5°
x = 175°/7
x = 25°
I hope it's help u...
Mark me as brainliest....
ASAP 30 POINTS BRAINLIEST IF RIGHT
Answer:
answer in the link below if you have any questions let me know
Answer:
≈ 0.14
Step-by-step explanation:
The average rate of change of f(x) in the closed interval [ a, b ] is
[tex]\frac{f(b)-f(a)}{b-a}[/tex]
Here [a, b ] = [ - 1, 3 ] , then
f(b) = f(3) = [tex]\sqrt[3]{3+3}[/tex] = [tex]\sqrt[3]{6}[/tex] ≈ 1.817
f(a) = f(- 1) = [tex]\sqrt[3]{-1+3}[/tex] = [tex]\sqrt[3]{2}[/tex] ≈ 1.260 , then
average rate of change = [tex]\frac{1.817-1.260}{3-(-1)}[/tex] = [tex]\frac{0.557}{4}[/tex] ≈ 0.14 ( to the nearest hundredth )
Flying against the wind, an airplane travels 3800 kilometers in 4 hours. Flying with the wind, the same plane travels 3750 kilometers in 3 hours. What is the rate of the plane in still air and what is the rate of the wind?
Answer:
[tex]V_w =1100[/tex] ---- velocity of wind
[tex]V_a = 150[/tex] --- velocity of airplane
Step-by-step explanation:
Given
[tex]V_a \to[/tex] velocity of airplane
[tex]V_w \to[/tex] velocity of wind
Flying with the wind, the distance (d) is:
[tex]d = (V_w + V_a) * t[/tex]
Where d and t are distance travel and time spent with the wind
So:
[tex]3750 = (V_w + V_a) * 3[/tex]
Divide by 3
[tex]1250 = (V_w + V_a)[/tex]
Flying against the wind, the distance (d) is:
[tex]d = (V_w - V_a) * t[/tex]
Where d and t are distance travel and time against with the wind
So:
[tex]3800 = (V_w - V_a) * 4[/tex]
Divide by 4
[tex]950 = (V_w - V_a)[/tex]
Make [tex]V_w[/tex] the subject
[tex]V_w= 950 + V_a[/tex]
Substitute: [tex]V_w= 950 + V_a[/tex] in [tex]1250 = (V_w + V_a)[/tex]
[tex]1250 = 950 + V_a + V_a[/tex]
[tex]1250 = 950 + 2V_a[/tex]
Collect like terms
[tex]2V_a = 1250 -950[/tex]
[tex]2V_a = 300[/tex]
Divide by 2
[tex]V_a = 150[/tex]
Substitute [tex]V_a = 150[/tex] in [tex]V_w= 950 + V_a[/tex]
[tex]V_w =950 +150[/tex]
[tex]V_w =1100[/tex]
Cameron drives a semi-truck for Haulin' Harry's Trucking Company. He earns $0.45 for every mile he drives. If Cameron drove 827.4 miles on his last route, how much money did he earn?
Answer:
$372.33
Step-by-step explanation:
For 1 mile= $0.45
For 827.4 miles = $0.45 x 827.4
= $372.33
The radius of a cylinder of volume 2970cm³ is 30mm. Find the volume of a similar cylinder of radius 40mm.
34.3 cm3
if you use formula
30mm 2970cm3
x-x un^3
Josie is purchasing a $75 appliance for her kitchen. She has three coupons to the store that she can choose from. Which is a true statement about Josie’s options?
Answer:
where are the answer choices?
Step-by-step explanation:
Graph the following: Max did not get less than 87 on his test.
Answer:
y > 87
Step-by-step explanation:
What Max got will be represented by y.
y is not less than 87.
y is greater than 87
y > 87
Geometric stuff and please explain
Perimeter = Sum of the sides measures
Perimeter = | AB | + | AT | + | BT |
Perimeter = ( x + 3 ) + ( 4x ) + ( 2x + 2 )
40 = x + 4x + 2x + 3 + 2
Colect like terms
40 = ( 1 + 4 + 2 )x + ( 3 + 2 )
40 = 7x + 5
Subtract both sides - 5
40 - 5 = 7x + 5 - 5
35 = 7x
Switch sides
7x = 35
Divide both sides by 7
7x ÷ 7 = 35 ÷ 7
x = 5
_____________________________
AB = x + 3 = 5 + 3 ======》 AB = 8
AT = 4x = 4 × 5 =========》 AT = 20
BT = 2x + 2 = 2(5) + 2 ===》 BT = 12
According to the law of inequality in a triangle, the sum of any two random sides must be greater than the size of the other side which means :
AB + AT > BT
&
AB + BT > AT
&
AT + BT > AB
If the sides is true in the above inequalities, then those sides are able to form a triangle ;
But if even one of the above inequalities is violated, those sides will not be able to form a triangle.
8 + 20 > 12 ( Check )
8 + 12 > 20 ( Nope this inequlity violated )
Thus the measures of the sides can not represent the measures of the sides of a triangle .
And we're done ...