Polygon B is a scaled copy of Polygon A.



What is the scale factor from Polygon A to Polygon B?

Answer:

3/8, 5/8, 3/4, 7/8, 4/3

Step-by-step explanation:

Answer:

Hello! Answer below.

Step-by-step explanation:

The answer to your question is:

18 9/10 or 18.9

Steps below...

You have to do this first.

1. Convert the mixed number to fraction.

2. [tex]7/2[/tex]

Multiplied by

[tex]27/5[/tex]

This will equal, 189/10

If you divide this the answer will be 18 9/10

So the answer is 18 9/10 or 18.9

Hope this helps!

By, BrainlyMagic

Answer:

Hey there!

This circle would have a center at (-4, -3) and a radius of 1.

Let me know if this helps :)

Answer:

Step-by-step explanation:

-7y = -10x - 8

y = 10/7x + 8/7

Answer/Step-by-step explanation:

Given:

Data set for sandwich calories=> 242, 290, 290, 280, 390, 350

Mean: the mean is given as sum of all values in the data set ÷ total no. of data set given

[tex] \frac{242 + 290 + 290 + 280 + 390 + 350}{6} = \frac{1,842}{6} = 307 [/tex]

Mean Absolute Value:

Step 1: find the absolute value of the difference between each value and the mean

|242 - 307| = 65

|290 - 307| = 17

|290 - 307| = 17

|280 - 307| = 27

|390 - 307| = 83

|350 - 307| = 43

Step 2: find the sum of all values gotten in step 1

65 + 17 + 17 + 27 + 83 + 43 = 252

Step 3: divide the result you get in step 2 by 6 to get the M.A.D

[tex] M.A.D = \frac{252}{6} = 42 [/tex]

The Mean Absolute Value represents or gives us an idea how spread the data set for the number of sandwich calories are.

Thus, averagely, the number of calories of sandwich at the restaurant are far from the mean caloric value by 42 calories.

Greetings,

I hope you and your family are staying safe and healthy!

Answer: $4.12 per hour

Step-by-step explanation:

So, 9am to 4pm is 7 hours

Why? Because you go from 10am, 11am, 12pm, 1pm, 2pm, 3pm, and 4pm.

So now all we have to do is to divide the amount he paid by the number of hours.

Like this:

[tex]\frac{28.84}{7} = 4.12[/tex]

Therefore,

The rental cost per hour is $4.12

-----------------------------------

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Answer:

AB = 10.77 units

Step-by-step explanation:

If the extreme ends of a line segment are [tex](x_1,y_1)[/tex] and [tex](x_2, y_2)[/tex].

Then the length of the segment joining these extreme ends will be,

d = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

If the extreme ends of the line segment AB are A(-3, 1) and (7, 5).

Measure of AB = [tex]\sqrt{(7+3)^2+(5-1)^2}[/tex]

AB = [tex]\sqrt{100+16}[/tex]

AB = [tex]\sqrt{116}[/tex]

AB = 10.77 units

Therefore, length of the segment AB will be 10.77 units.

Answer:

24 ft.

Step-by-step explanation:

10x2=20. 20+4=24

Answer:

24 FT.

Step-by-step explanation:

10x2=20. 20+4=24

Answer:

f(-3)= -3

Step-by-step explanation:

We are given the function:

f(x) = 2x+3

and asked to find f(-3). Essentially, we want to find f(x) when x is equal to -3.

Therefore, we can substitute -3 for each x in the function.

f(x)= 2x+3 at x= -3

f(-3)= 2(-3) +3

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition and Subtraction

Multiply 2 and -3.

f(-3) = (2*-3) +3

f(-3)= (-6)+3

Add -6 and 3.

f(-3)= (-6+3)

f(-3)= -3

If f(x)= 2x+3, then f(-3)= -3

Answer:

last option ie all of the above are true

Lines s and t are intersect at P. Therefor, option D is the correct answer.

In a plane, intersecting lines are any two or more lines that cross one another. The point of intersection, which can be found on all intersecting lines, is where the intersecting lines share a common point.

Straight lines s and t are intersect at P.

P is called point of intersection.

Therefor, option D is the correct answer.

Learn more about intersection of lines here:

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Answer:

0.04

Step-by-step explanation:

[tex] \dfrac{6300~L}{8.5~month} \times \dfrac{1000~cm^3}{1~Liter} \times \dfrac{1~ft^3}{(30.48~cm)^3} \times \dfrac{12~months}{1~year} \times \dfrac{1~year}{365.25~days} \times \dfrac{1~day}{24~hours} \times \dfrac{1~day}{24~hours} = [/tex]

[tex]= 0.04 \dfrac{ft^3}{hour}[/tex]

The value of the flow rate in cubic feet per hour is 0.04.

The rate of the flow of the fluid is defined as the volume of the fluid flowing through the cross-section per unit of time. The unit of the flow rate is cubic feet per hour or cubic meter per hour etc.

Given that water flows through a pipe at a rate of 6300 liters every 8.5 months. Then the flow rate in cubic feet per hour will be calculated as below:-

1 litre = 0.0353 cubic feet

6300 litres = 6300 x 0.0353

6300 litres = 222.4 cubic feet

1 month = 730 hours

8.5 months = 6205 hours

The rate of flow in cubic per hour will be:-

Rate of flow = 222.4 / 6205 = 0.04 cubic feet per hour

Therefore, the value of the flow rate in cubic feet per hour is 0.04.

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Answer:

Step-by-step explanation:

[tex]4 - 2(3 + 2) ^{2} \\ 4 - 2( {5}^{2} ) \\ 4 - 2(25) \\ 4 - 50 = - 46[/tex]

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Hi my lil bunny!

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[tex]y= [-7-6][/tex]

[tex]y = -13[/tex]

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Have a great day/night!

❀*May*❀

Answer:

45

Step-by-step explanation:

Answer: 45

Step-by-step explanation: Parentheses first.

10-1=9. Next is multiplication. 5(9)=45.

Answer:

Step-by-step explanation:

Circumference of a circle = πd

where

d is the diameter of the circle

From the question

Circumference = 56.52 inches

π = 3.14

To find the diameter substitute the value of the circumstance into the above formula and solve for the diameter

That's

56.52 = πd

[tex]d = \frac{56.52}{\pi} \\ d = \frac{56.52}{3.14} [/tex]

We have the final answer as

Hope this helps you

The diameter of Dion's bicycle tire is 18 inches.

The length of the perimeter of the circle is known as the Circumference. Mathematically, [tex]C=2\pi r[/tex]

The circumference of the bicycle tire is 56.52 inches.

So,

[tex]2\pi r=56.52\\r=\dfrac{56.52}{2\times 3.14}\\r=9 inches[/tex]

So, the diameter of the bicycle tire is [tex]9\times 2= 18[/tex] inches.

Thus, the diameter of the bicycle tire is 18 inches.

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Answer:

[tex] y = 178.3 ft [/tex]

Step-by-step explanation:

y is opposite to the reference angle, 27°.

350 ft is adjacent to the reference angle, therefore:

[tex] tan(27) = \frac{y}{350} [/tex]

Multiply both sides by 350

[tex] tan(27)*350 = \frac{y}{350}*350 [/tex]

[tex] tan(27)*350 = y [/tex]

[tex] 178.3 = y [/tex] (to nearest tenth)

[tex] y = 178.3 ft [/tex]

Answer:

It would be 81

Step-by-step explanation:

[tex]9^{2}[/tex] is the same as 9 times 9. And 9 times 9 is 81.

Answer:

2⁹ = 512

Step-by-step explanation:

2⁹ = 2*2*2*2*2*2*2*2*2 = 512

Answer:

[tex]\frac{3}{4}[/tex], [tex]\frac{30}{40}[/tex], [tex]\frac{45}{60}[/tex], [tex]\frac{60}{80}[/tex]....e.t.c are all equivalent fractions

Step-by-step explanation:

For the answer you need to know bout equivalent fractions

TO find equivalent fractions you have to multiply the numerator and denominator by the same amount

E.x.[tex]\frac{15}{20}=\frac{(15)(2)}{(20)(2)} =\frac{30}{40}[/tex]

Therefore [tex]\frac{30}{40}[/tex] is an equivalent fraction

Answer:

19.375 m.

Step-by-step explanation:

Before the first bounce it has travelled 10 meters.

Then after just hitting the ground the second time it has travelled 10 +1/2(10) = 15 m.

The common ratio is 0.5 and we want the sum of  5 terms

= a1  (1 - r^n) / (1 - r)

= 10 * (1 - 0.5^5) / (1 - 0.5)

= 19.375 m.

Answer:

  see attached

Step-by-step explanation:

This is asking you to recognize the symbols used to designate a point, line segment, ray, angle, line, and plane.

The point is designated by its letter.

A line segment is designated by the letters of its endpoints, with an overline.

A ray is designated by the endpoint and a point on the ray. The endpoint is listed first. The letters have an arrow over them pointing in the direction from the endpoint.

An angle is designated using the symbol ∠. If three letters are used to identify the angle, the middle one is the vertex.

A line is designated using its name, or by the letters of two points on the line. If the letters are used, there may be a double-ended arrow over them.

A plane is designated by 3 non-collinear points, for example, "plane ABC". It may also be designated by the name of the plane.

Answer:

No.

Step-by-step explanation:

High school GPA is not a significant predictor of University GPA.

The Grade Point Average obtained at the end of high school education has almost nothing (in my opinion, it has nothing to do with) to do with grades that the scholar will obtain in college. Many scholars find it difficult adjusting to the social and academic life demands of tertiary institution.

A good predictor for university Grade Point Average would be:

The CGPA (Cumulative Grade Point Average) obtained by the student(s) in each year/session/level/part in the university.

This will be a significant predictor for university GPA.

Answer:

5 + 2 x 9

Step 1 = 7 x 9

Step 2 = 63

Step-by-step explanation:

= 5 + 2 x 9

= 5 + ( 2 x 9 )

= 5 + 18

= 23

Step 2 = 7 x 9

= 63

Step 3 = 63

C. jin did not make a mistake

Sorry i'm wrong :)

Answer:

2/15

Step-by-step explanation:

given that the triple integral = ∫∫∫ 8x^2 dv

and T is the solid tetrahedron with vertices :  (0, 0, 0), (1, 0, 0), (0, 1, 0), and (0, 0, 1)

hence the equation of the plane: x + y + z = 1

T [ (X,Y,Z) : 0≤x≤1, 0≤y≤1-x, 0≤z≤1-x-y ]

attached below is the detailed solution ( we multiply our answer after evaluation with the coefficient of  8 as attached to the initial expresssion)

By evaluating the triple integral where T is the solid tetrahedron with verticies (0, 0, 0), (1, 0, 0), (0, 1, 0), and (0, 0, 1) the value calculated is 2/15.

Given :

The triple integral ∭ 8x^2 dV, where T is the solid tetrahedron with verticies (0, 0, 0), (1, 0, 0), (0, 1, 0), and (0, 0, 1).

The following calculation can be used to evaluate the triple integral:

[tex]\rm I = \int\int\int 8x^2dV[/tex]

T[(x,y,z) : [tex]0 \leq x \leq 1[/tex] ; [tex]0 \leq y \leq 1-x[/tex] ; [tex]0 \leq z \leq 1-x-y[/tex] ]

Now put the limits in the above integral.

[tex]\rm I = \int\limits^1_0\int\limits^{1-x}_0\int\limits^{1-x-y}_0 {8x^2} \, dz \, dy \, dx[/tex]

[tex]\rm I = \int\limits^1_0\int\limits^{1-x}_0 {8x^2} (1-x-y) \, dy \, dx[/tex]

[tex]\rm I = 8 \int\limits^1_0\int\limits^{1-x}_0 {x^2-x^3-x^2y} \, dy \, dx[/tex]

[tex]\rm I = 8 \int\limits^1_0 {x^2(1-x)-x^3(1-x)-x^2\dfrac{(1-x)^2}{2}} \, dx[/tex]

[tex]\rm I = 8 \int\limits^1_0 {x^2-x^3-x^3+x^4-x^2\dfrac{(1+x^2-2x)}{2}} \, dx[/tex]

[tex]\rm I = 4\left( \int\limits^1_0 {2x^2-4x^3+2x^4-x^2-x^4+2x^3} \, dx\right)[/tex]

[tex]\rm I = 4\left( \int\limits^1_0 {x^2+x^4-2x^3} \, dx\right)[/tex]

[tex]\rm I = 4\left( {\dfrac{x^3}{3}+\dfrac{x^5}{5}-\dfrac{x^4}{2}} \right)^1_0[/tex]

[tex]\rm I = 4\left( {\dfrac{1}{3}+\dfrac{1}{5}-\dfrac{1}{2}} \right)[/tex]

[tex]\rm I = \dfrac{2}{15}[/tex]

By evaluating the triple integral where T is the solid tetrahedron with verticies (0, 0, 0), (1, 0, 0), (0, 1, 0), and (0, 0, 1) the value calculated is 2/15.

For more information, refer to the link given below:

https://brainly.com/question/24308099

Answer: It will be 4 or -5.

Step-by-step explanation:

Answer:

x = 4, -5

Step-by-step explanation:

Step 1: Write out expression

0 = (x - 4)(x + 5)

Step 2: Find roots

x - 4 = 0

x = 4

x + 5 = 0

x = -5

Answer:

(a) the probability that an individual distance is greater than 214.80 cm is 0.1401.

(b) The probability that the mean for 15 randomly selected distances is greater than 204.00 cm is 0.2482.

(c) The normal distribution can be used because the original population has a normal distribution.

Step-by-step explanation:

We are given that the overhead reach distances of adult females are normally distributed with a mean of 205.5 cm and a standard deviation of 8.6 cm.

(a) Let X = the overhead reach distances of adult females.

The z-score probability distribution for the normal distribution is given by;

                         Z  =  [tex]\frac{X-\mu}{\sigma}[/tex]  ~ N(0,1)  

where, [tex]\mu[/tex] = population mean reach distance = 205.5 cm  

           [tex]\sigma[/tex] = standard deviation = 8.6 cm

So, X ~ Normal([tex]\mu=205.5,\sigma^{2} =8.6^{2}[/tex])

Now, the probability that an individual distance is greater than 214.80 cm is given by = P(X > 214.80 cm)

    P(X > 214.80 cm) = P( [tex]\frac{X-\mu}{\sigma}[/tex] > [tex]\frac{214.80-205.5}{8.6}[/tex] ) = P(Z > 1.08) = 1 - P(Z [tex]\leq[/tex] 1.08)

                                                                    = 1 - 0.8599 = 0.1401

The above probability is calculated by looking at the value of x = 1.08 in the z table which has an area of 0.8599.

(b) Let [tex]\bar X[/tex] = the sample mean selected distances.

The z-score probability distribution for the sample mean is given by;

                                   Z  =  [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex]  ~ N(0,1)  

where, [tex]\mu[/tex] = population mean reach distance = 205.5 cm  

           [tex]\sigma[/tex] = standard deviation = 8.6 cm

           n = sample size = 15

Now, the probability that the mean for 15 randomly selected distances is greater than 204.00 cm is given by = P([tex]\bar X[/tex] > 204.00 cm)

    P([tex]\bar X[/tex] > 204 cm) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] > [tex]\frac{204-205.5}{\frac{8.6}{\sqrt{15} } }[/tex] ) = P(Z > -0.68) = 1 - P(Z [tex]\leq[/tex] 0.68)

                                                                    = 1 - 0.7518 = 0.2482

The above probability is calculated by looking at the value of x = 0.68 in the z table which has an area of 0.7518.

(c) The normal distribution can be used in part​ (b), even though the sample size does not exceed​ 30 because the original population has a normal distribution and the sample of 15 randomly selected distances has been taken from the population itself.

Answer:

1/8, 2/8, 3/8, 4/8, 5/8, 6/8

Step-by-step explanation:

If i have interpreted correct. You want to know a fraction with a denonminator of 8 that is less than 5/6

5/6=0.8333

Multiple Answers

1/8, 2/8, 3/8, 4/8, 5/8, 6/8

Answer:

[tex]x_n=7(-3)^{n-1}[/tex]

Step-by-step explanation:

First, write some equations so we can figure out the common ratio and the initial term. The standard explicit formula for a geometric sequence is:

[tex]x_n=ar^{n-1}[/tex]

Where xₙ is the nth term, a is the initial value, and r is the common ratio.

We know that the second and fifth terms are -21 and 567, respectively. Thus:

[tex]a_2=-21\\a_5=567[/tex]

Substitute them into the equations:

[tex]x_2=ar^{(2)-1}\\-21=ar[/tex]

And:

[tex]a^5=ar^{(5)-1}\\567=ar^4[/tex]

To find a and r, divide both sides by a in the first equation:

[tex]r=-\frac{21}{a}[/tex]

And substitute this into the second equation:

[tex]567=a(\frac{-21}{a} )^4[/tex]

Simplify:

[tex]567=a(\frac{(-21)^4}{a^4})[/tex]

The as cancel out. (-21)^4 is 194481:

[tex]\frac{567}{1}=\frac{194481}{a^3}[/tex]

Cross multiply:

[tex]194481=567a^3\\a^3=194481/567=343[/tex]

Take the cube root of both sides:

[tex]a=\sqrt[3]{343} =7[/tex]

Therefore, the initial value is 7.

And the common ratio is (going back to the equation previously):

[tex]r=-21/a\\r=-21/(7)\\r=-3[/tex]

Thus, the common ratio is -3.

Therefore, the equation is:

[tex]x_n=7(-3)^{n-1}[/tex]

Answer:

There is no short answer.

Step-by-step explanation:

To find to intervals which f(x) increases or decreases, we first need to find it's derivative.

[tex]f(x) = sinx - cosx\\f'(x) = cosx - (-sinx) = cosx + sinx[/tex]

The function is increasing when it's value is  > 0 and decreasing when it's value is < 0.

If we take a look at this graph, cosx+sinx is positive when they are both positive or when cosx is greater then sinx on the negative part.

I hope this answer helps.

Answer:

[tex] \boxed{ \sf{ \bold{ \huge{ \boxed{71}}}}}[/tex]

Step-by-step explanation:

Using PEMDAS rule :

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

Let's solve:

[tex] \sf{8 + 7 \times 9}[/tex]

Multiply the numbers

⇒[tex] \sf{8 + 63}[/tex]

Add the numbers

⇒[tex] \sf{71}[/tex]

Hope I helped!

Best regards!