A 56 kg woman climbs the stairs to a height of 5 m. Determine: a) what mechanical work
she performed; b) what work the woman will do when climbing the stairs and carrying a 5 kg load.

Answers

Answer 1

Answer:

a) W = 2746.8[J]

b) W = 2992.05 [J]

Explanation:

Work is defined as the product of force by distance. We must bear in mind that the force that performs the work is the one that acts in the same direction of displacement.

For this case, we must calculate the weight of the woman, the weight is defined as the product of mass by gravity.

[tex]w=m*g\\[/tex]

where:

w = weight [N] (units of Newtons]

m = mass = 56 [kg]

g = gravity acceleration = 9.81 [m/s²]

[tex]w=56*9.81\\w=549.36[N][/tex]

a)

[tex]W=F*d[/tex]

where:

F = weight = 549.36[N]

d = distance = 5 [m]

[tex]W = 549.36*5\\W = 2746.8[J][/tex]

b)

The new mass will be the combination of the mass of the woman plus that of the load.

[tex]m_{new} = 56+5\\m_{new}=61[kg][/tex]

[tex]w_{new}=61*9.81\\w_{new}=598.41[N][/tex]

The new work done.

[tex]W =598.41*5\\W=2992.05[J][/tex]


Related Questions

what are the characteristics of image when object is between f1 and 2f1 for concave lense?​

Answers

Answer:

The required diagram is shown in the figure. When an object is placed in front of the convex lens, i.e., between 2F

1

and F

1

, its image is formed beyond 2F

2

on the other side of the lens. The image is real, inverted and enlarged.

solution

A force of 400-N pushes on a 25-kg box horizontally. The box accelerates at 9 m/s? Find the coefficient of kinetic friction between the box and floor.

Answers

Answer:

0.69

Explanation:

Using the Newtons law of motion;

[tex]\sum Fx = ma_x\\Fm - Ff = ma_x[/tex]

Fm is the moving force = 400N

Ff is the frictional force = μR

μ is the coefficient of kinetic friction

R is the reaction = mg

m is the mass

a is the acceleration

The equation becomes;

[tex]Fm - \mu R = ma_x\\Fm - \mu mg = ma_x\\400- \mu (25)(9.8) = 25(9)\\400 - 254.8 \mu = 225\\- 254.8 \mu = 225 - 400\\- 254.8 \mu = -175\\ \mu = \frac{-175}{- 254.8} \\\mu = 0.69[/tex]

Hence the coefficient of kinetic friction between the box and floor is 0.69

The coefficient of kinetic friction between the box and the floor is 0.714.

Friction: This can be defined as the force that tends to oppose two surfaces in motion.

The question above can be solved using the formula

F-ma = mgμ................. Equation 1

Where F = Force applied to push the box, m = mass of the box, a = acceleration of the box, μ = coefficient of kinetic friction, g = acceleration due to gravity.

make μ the subject of the equation

μ = (F-ma)/mg................ Equation 2

From the question,

Given: F = 400 N, m = 25 kg, a = 9 m/s²,

Constant: g = 9.8 m/s²

Substitute these values into equation 2

μ = [400-(25×9)]/(25×9.8)

μ = (400-225)/245

μ = 175/245

μ = 0.714

Hence, the coefficient of kinetic friction between the box and the floor is 0.714.

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Have you ever written a bio-data or an application letter? Share your experience in the
space below. (e.g. How did you find the experience? What was hard? What was easy?)
Leave the space blank if you have never written any of these.​

Answers

Answer:

I found the experience tasking

Explanation:

I wouldn't say it was hard, neither was it easy. I'd rather go for something like it being tasking. It's worthy of note that it was my first time, and I think it's very normal especially when one hasn't been doing something of that nature previously. Of course I did my draft, which unsurprisingly happened to be not good enough, and I had to look for templates to guide me through the acceptable way.

I still did it in my own way, but in the right way. Ever since then though, I have never stuttered when writing application letters, as it had since then seem inborn

The experience of writing a bio-data or an application letter was quite a tasking goal, where proper structure is required.

The given problem is based on the fundamentals of bio-data. Biodata is a document that is used to display the biographical data about the work experience in any organization.

As per my experience it was neither hard nor easy. I'd rather go for something like it being tasking. It's worthy of note that it was my first time, and I think it's very normal especially when one hasn't been doing something of that nature previously.

I did my draft, which unsurprisingly happened to be not good enough, and I had to look for templates to guide me through the acceptable way.  I still did it in my own way, but in the right way. Ever since then though, I have never stuttered when writing application letters, as it had since then seem inborn.

Thus, it is concluded that writing a bio-data or an application letter was quite a tasking goal, where proper structure is required.

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80g of kerosene was burned to raise the temperature of 3 l of water to 90c ⁰C. What is the efficiency of the burner?​

Answers

Answer:

363

Explanation:

80g of kerosene was burned to raise the temperature

k = 90+273

= 363

In an RC parallel circuit, Et = 480 V, R = 50ko, and XC = 47 ko. What is the reactive power?

Answers

Correct question is;

In an RC parallel circuit, Et = 480 V, R = 50kΩ, and XC = 47 kΩ. What is the reactive power?

Answer:

P_r = 4.9 VARs

Explanation:

We are given;

Total voltage: Et = 480 V

Resistance; R = 50kΩ = 50000 Ω

Capacitive reactance; XC = 47 kΩ = 47000 Ω

Formula for current across the capacitor is;

Et = I_c • XC

I_c = Et/XC

l_c = 480/47000

I_c = 0.01021 A

Formula for reactive power is;

P_r = (I_c)² × XC

P_r = 0.01021² × 47000

P_r = 4.9 VARs

according to newton's first law of motion what is the reason for a ball throwing up in the airfall back to earth

Answers

the force of earth's gravitational field is always directed downwards (towards the center of the earth. When the ball is thrown up, it is going against the earth's gravitational field and so, the earth's gravitational force pulls it back down, accelerating it downwards.

What is the acceleration a of the refrigerator 4 s after the person begins pushing on it with a force of 400 N?

Answers

Answer:

What is the acceleration a of the refrigerator 4 s after the person begins pushing on it with a force of 400 N? a=2m/s^2 Applying Newton's 2nd law, a=Fnet/m=(400N)/(200kg)=2m/s^2. The acceleration is constant.

Explanation:

The person begins to push a refrigerator with a force of 400 N. So, the acceleration of the refrigerator will be 2 m/s².

What is Acceleration?

In mechanics, acceleration is the measure of how rapidly an object's velocity changes over time. It is a vector quantity. An object's acceleration depends on the direction of the net force exerted on it.

A vector quantity, acceleration is something that has both a magnitude and a direction. As a vector quantity, velocity is also. The ratio of the velocity vector change over a time interval to that interval is the definition of acceleration.

There are several types of acceleration :

Uniform AccelerationNon-Uniform AccelerationAverage Acceleration

According to the question, the given values are :

Force applied to the refrigerator is 400 N.

The mass of the refrigerator is 200 kg.

Use the 2nd law of newton,

[tex]Force= mass*acceleration[/tex]

Acceleration = 400/200

Acceleration = 2 m/s².

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A black widow spider hangs motionless from a web that extends vertically from the ceiling above. If the spider has a mass of 1.27 g, what is the tension in the web

Answers

Answer:

Tension = 0.012 N

Explanation:

If the black widow spider is hanging vertically motionless from the ceiling above. Then, the weight of the spider must be balancing the tension in the spider web. Therefore,

Tension = Weight

Tension = mg

where,

m = mass of spider = 1.27 g = 0.00127 kg

g = acceleration due to gravity = 9.8 m/s²

Therefore,

Tension = (0.00127 kg)(9.8 m/s²)

Tension = 0.012 N

Only 35 % of the intensity of a polarized light wave passes through a polarizing filter. What is the angle between the electric field and the axis of the filter

Answers

Answer:

The angle between the electric field and the axis of the filter is 54⁰

Explanation:

Apply the equation for intensity of light through a polarizer.

[tex]I = I_oCos^2 \theta[/tex]

where;

I is the intensity of the transmitted light

I₀ is the intensity of the incident light

θ is the incident angle

If only 35 % of the intensity of a polarized light wave passes through a polarizing filter, then the ratio of the intensity of the transmitted light to that of the intensity of the incident light is given by;

[tex]\frac{I}{I_o} = Cos^2 \theta\\\\\frac{35}{100} = Cos^2 \theta\\\\Cos^2 \theta = 0.35\\\\Cos\theta = \sqrt{0.35} \\\\Cos\theta = 0.5916\\\\\theta = Cos^{-1}(0.5916)\\\\\theta = 54 ^0[/tex]

Therefore, the angle between the electric field and the axis of the filter is 54⁰

The angle between the electric field and the axis of the filter for the polarized light wave which passes through a polarizing filter is 54°.

What is electric field?

The electric field is the field, which is surrounded by the electric charged. The electric field is the electric force per unit charge.

From the Malus's law, the intensity of the polarized beam can be calculated with the following formula.

[tex]I=I_o\cos^2\theta[/tex]

Here, (I₀) is the intensity of the polarized beam incident on the observer θ is the angle of incident.

It is given that only 35 % of the intensity of a polarized light wave passes through a polarizing filter.

The angle between the electric field and the axis of the filter can be found out using the above formula as,

[tex]35\%=(100\%)\cos^2\theta\\\theta=\cos^{-1}\sqrt{\left(\dfrac{35}{100}\right)}\\\theta=54^o[/tex]

Hence, the angle between the electric field and the axis of the filter for the polarized light wave which passes through a polarizing filter is 54°.

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A bird perched in a tree is balanced or unbalanced​

Answers

Answer: Balanced

Explanation: When a bird is perched on a tree it is sitting still will stay still if the forces acting on it are balanced.

A 10-turn ideal solenoid has an inductance of 3.5 mH. When the solenoid carries a current of 2.0 A the magnetic flux through each turn is:

Answers

Answer:

7 * 10^-4Wb

Explanation:

The magnetic flux is the product of the inductance and current

Magnetic flux = LI

L is the inductance = 3.5mH

I is the current = 2.0A

Number of turns N = 2A

Since for a 10-turn solenoid, L = 3.5mH

For a one-turn solenoid, L = 3.5/10 = 0.35mH

magnetic flux = 0.35mH * 2

magnetic flux = 0.35 * 10^-3 * 2

magnetic flux = 0.7* 10^-3

Magnetic flux = 7 * 10^-4Wb

Hence the magnetic flux through each turn is 7 * 10^-4Wb

The magnetic flux through each turn is 7 ×10⁻⁴ Wb. The magnetic flux is the product of the inductance and current.

What is megnetic flux?

The surface integral of the normal component of the magnetic field B across a surface is the magnetic flux through that surface. It is commonly indicated by the letters B.

The weber is the SI unit for magnetic flux, while the maxwell is the CGS unit.

The given data in the problem is;

[tex]\rm \phi[/tex] is the magnetic flux =?

L is the inductance = 3.5mH

I is the current = 2.0A

N number of turns of solenoid  = 2A

The inductance for the one turn is found by;

For a 10-turn solenoid, L = 3.5mH

For a one-turn solenoid, L = 3.5/10 = 0.35mH

The megnetic flux through each turn is found by;

[tex]\rm \phi = L \times I \\\\ \rm \phi = 0.35 \times 10^{-3}\times 2\\\\ \rm \phi =7 \times 10^{-4}[/tex]

Hence the magnetic flux through each turn is 7 ×10⁻⁴ Wb.

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A boy throws a tell ball straight up . disregarding any effects of air resistance, the forces acting 9n the ball untill it returns to the ground is are

Answers

well in my opinion I think that is called gravity but I’m no expert.

A light bulb uses 1.2 A when connected across a 120 V source. What is the resistance by the bulb?

Answers

V=iR
R=V/i
R=120/1.2
R ≈ 100Ω

Suppose that a brass rod 2.0 m long expands 0.2 cm when its temperature is increased a certain amount. By how much will a brass rod 80 m long expand with the same change in temperature?

Answers

Answer:

0.08 m

Explanation:

Linear expansivity brass = 2 * 10^-5 C

Linear expansivity = change in length / (initial length * θ)

Change in length = 0.2cm = 0.002m

Initial length = 2m

2 * 10^-5 = 0.002 / (2 * θ)

(2 * 10^-5 * 2θ) = 0.002

4 * 10^-5θ = 0.002

θ = 0.002 / 4 * 10^-5

θ = 2 * 10^-3 / 4 * 10^-5

θ = 0.5 * 10^2

θ = 50°C

For a rod of original length 80m at the same temperature of 50°C

Linear expansivity = change in length / (initial length * θ)

Change in length = dL

2 * 10^-5 = dL / (80 * 50)

2 * 10^-5 * 80 * 50 = dL

160 * 10^-5 * 50 = dL

8000 * 10^-5 = dL

0.08 m = dL

Hence, change in length = 0.08m

What are the two main regions of the body?
cranial and spinal
axial and appendicular
trunk and limbs
muscular and skeletal

Answers

Answer: Your correct answer would be the second option; axial and appendicular. The axial region makes up the axis of the human body, this includes your head, neck, etc. The appendicular region makes up the parts of the human body that connects to the axial region, for example limbs and appendages.

matter can be a solid, lquid or gas. but you cannot see the particles or adoms that make up matter because they are

Answers

Answer:

very small...

Explanation:

i guess... but i may be missing something. the question feels too straightforward

An object has density rho.

a. Suppose each of the object's three dimensions is increased by a factor of 2 without changing the material of which the object is made. Will the density change? If so, by what factor? Explain.
b. Suppose each of the object's three dimensions is increased by a factor of 2 without changing the object's mass. Will the density change? If so, by what factor? Explain.

Answers

Answer:

a. the density will not change

b. D' = 0.125 D

So, the density will change by a factor of 0.125

Explanation:

a.

Density is the material property and the value of density is constant for all solid materials. So, when the dimensions of the a solid are increased, while the material is same, then the material must be added to the object for increasing its dimensions. So, with the increase in the volume, the mass of the object also increases. And as a result the density of the object remains constant.

Since, here the material remains the same.

Therefore, the density will not change

b.

Density = mass/Volume

D = m/V   ------------ equation (1)

Now,

V = LWH   ----------- equation (2)

Now, if each dimension increases by a factor of 2, the volume becomes:

V' = (2L)(2W)(2H)

V' = 8 LWH

using equation (2)

V' = 8 V

So, for constant mass, density becomes:

D' = m/V'

D' = m/8V

using equation (1)

D' = D/8

D' = 0.125 D

So, the density will change by a factor of 0.125

(a) The density of the object will be reduced by one-eighth times on increasing the dimension by a factor of two and keeping the material constant.

(b)  With constant mass and increasing the dimensions by a factor of 2, the density will reduce by the factor of 1/8.

What is density of object?

The degree measure of the compactness of an object is known as the density of an object. Mathematically, it is expressed as the ratio of the mass of the object to its volume.

(a)

Let us consider an object of dimension 'a'. As per the above definition, the density of an object is,

[tex]\rho = \dfrac{m}{V}[/tex]

Here,

m is the mass of the object.

V is the volume of the object. And its value is, [tex]V = a^{3}[/tex].

So the density becomes,

[tex]\rho = \dfrac{m}{a^{3}}[/tex]  ..............................................................(1)

Now, if the dimensions of the object is increased by a factor of 2. Then, new density becomes,

[tex]\rho' =\dfrac{m}{(2a) \times (2a) \times (2a)}\\\\\\ \rho' =\dfrac{m}{8a^{3}}\\\\[/tex]

Substitute the value of equation (1) in the above expression as,

[tex]\rho' =\dfrac{1}{8} \times \dfrac{m}{a^{3}}\\\\\rho' =\dfrac{1}{8} \times \rho[/tex]

Thus, we can conclude that the density of the object will be reduced by one-eighth times on increasing the dimension by a factor of two and keeping the material constant.

(b)

The density of the material is equal to the ratio of the mass of the object (m) and the volume of the object (V). So, if the mass remains unchanged and the dimensions increased by the factor of 2, then the result will remain same as the above part.

Thus, we can conclude that with constant mass and increasing the dimensions by a factor of 2, the density will reduce by the factor of 1/8.

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A ferry crossed the Potomac River four times in one day. The ferry traveled the same distance for each trip, but it took different amounts of time. The time for each trip is shown in the table below. Time for Ferry to Cross on Different Trips Trip Number Time Trip 1 10 minutes Trip 2 11 minutes Trip 3 9 minutes Trip 4 12 minutes On which trip did the ferry travel the fastest? A. Trip 3 B. Trip 2 C. Trip 4 D. Trip 1

Answers

Explanation:

trip 3 ( 9 minutes)

If the ferry is moving at a faster speed, it will travel the same distance in a shorter time. The ferry crossed the river the fastest on Trip 3 because it took the shortest amount of time on that trip.

A football player kicks a football off a tee with a speed of 21 m/s at an angle of 51°.

a. What is the horizontal component of the velocity?
b. What is the vertical component of the velocity?
c. How long does it take the ball to reach its highest point?
d. What is the maximum height of the ball?
e. What is the total amount of time that the ball is in the air?
f. How far is the ball from the football player when it lands?

I would appreciate any help :)

Answers

Answer:

see explanation

Explanation:

Answer:

a. 13.22 m/s

b. 16.32

c. 1.664 s

d. 13.58

e. 3.328

f. 40.0m

Explanation:

This is basically what the guy said, i dunno if you saw the letters, but he added some at the end of every answer.

How does the air pressure inside a tennis ball change when you hit it?​

Answers

When the can is opened and the balls are put into play more air starts to push on the inside of the balls. As the balls get older small amounts of air start to seep out which minimises inside pressure. This reduces the amount of air that pushes on the inside of the ball when it hits the ground, thus reducing bounce.

A motobike's tire rotates with a constant angular speed of 62.8 rad/s. The radius of a tire is 30cm. Assuming that no slipping occurs, the number of
revolutions of the tire in one second is:

a.
12.6
b.
20
C.
18.8
d.
10

Answers

Answer:

10

Explanation:

Given that :

Angular speed (w) = 62.8 rad/s

Radius of tire (r) = 30 cm

Number of revolutions per second :

s = 2πr

s = 2π * 0.3 = 1.8849555

The number or revolutions per second :

θ = s / r

θ = 1.884955 / 0.3

θ = 6.283185 rad

Number of revolutions per second :

62.8 / 6.283185

= 9.9949309

= 10

What are the 6 uses of electromagnet?​

Answers

I would say x-rays, microwave radiation, radio waves, Ultraviolet radiation, and Gamma rays.

Did the energy you used to lift the notebook get stored in the book as potential energy? Explain your answer with reasons.

Answers

Answer:

Because when you move a object the energy stored in moving objects. As the object moves faster, more energy is stored. Motion energy is the sum of potential and kinetic energy in an object that is used to do work.

Explanation:

answer it please

What is the Central Idea of "Shelter Dog Protects Owner with Epilepsy“

What is the author’s viewpoint?

Do you agree or disagree with that viewpoint?

Why? Explain your answer.

parpgraph 1-2

Answer:

Yes, the energy used to lift the book was stored in the book as potential energy. The book moved when it was let go.

Explanation:

This is what edmentum sample answer says so I hope this helps out!

sound is faster than light that is why we hear thunder before we see lightning

Answers

Answer:

false

Explanation:

sound travels slower than light. that is why we see lightning before we hear the thunder

WHAT IS CHANGES IN SOLID MATERIALS ​

Answers

Answer: Solid to a Liquid Liquid to a Solid Liquid to a Gas Gas to a Liquid Solid to a Gas Gas to a Solid

Explanation:

A 1000 kg car and a 2000 kg car are lifted the same distance in a
mechanic's shop. Neglecting friction, raising the more massive car
requires

Answers

Answer:

Twice as much work

Explanation:

A carriage of 20 kg is pulled with a force of 35 N. How far the carriage will go
doing 95 J work?

Answers

Answer:

2.71 m

Explanation:

Force is the product of mass and acceleration

F=m*a

Work done is the product of force and distance

Work done=F*d

In this case;

F= 35 N

Work done = 95 J

95 =35 * d

95 /35 = d

2.71 m= d

What do the skull and vertebrae have in common

Answers

Answer: ok

Explanation: ok

A student drops a 2.4-kg ball. It’s speed right before hitting the ground is 5 m/s. If 15 J of energy was transferred to the environment as the ball fell, what was the total initial energy of the ball?

21 J
30 J
45 J
6 J

Answers

The answer is 45J

Don’t know how to explain sorry

If one person is applying an upward force equal to 60 N at one end, at what location on the board is the other person applying an upward force

Answers

Answer:

When one person applies force f1 = 60 N at one end, the other person applies f2 = 160 - 60 = 100 N. The torques about the center must balance. Thus the distances from the center d1 and d2 must be such that f1*d1 = f2*d2, or 60*1.5 = 100*d2, so d2=0.9. Thus f2 must be applied at a point 1.5 + 0.9 = 2.4 m from the end where f1 is applied.

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