4. The Emerson First National Bank is lending you money to buy a new car. The loan agreement will probably state
that you must carry
insurance.
A no-fault
B. collision
C. medical
D. liability​

Answers

Answer 1

Answer:

D. liability​

Step-by-step explanation:

The Emerson First National Bank is lending you money to buy a new car.

Before an agreement will be reached for any Organization to lend someone money there have to be something like a collateral.

The agreement will in it's document state that there must be a form of a reliability to hold on, such that if something's happen to the car, or you don't meet the paying up time, or something happens to you,they will see something to hold on.

Answer 2

Answer:

COLLISION insurance.

Step-by-step explanation:


Related Questions

Forty percent of all Americans who travel by car look for gas stations and food outlets that are close to or visible from the highway. Suppose a random sample of n=25 Americans who travel by car are asked how they determine where to stop for food and gas. Let x be the number in the sample who respond that they look for gas stations and food outlets that are close to or visible from the highway.
a. What are the mean and variance of x?
b. Calculate the interval μ±2σμ±2σ. What values of the binomial random variable x fall into this interval?
c. Find P(6≤≤x$\leq$14). How does this compare with the fraction in the interval μ±2σμ±2σ for any distribution? For mound-shaped distributions?

Answers

Answer:

Explained below.

Step-by-step explanation:

Let the random variable X be defined as the number of Americans who travel by car look for gas stations and food outlets that are close to or visible from the highway.

The probability of the random variable X is: p = 0.40.

A random sample of n =25 Americans who travel by car are selected.

The events are independent of each other, since not everybody look for gas stations and food outlets that are close to or visible from the highway.

The random variable X follows a Binomial distribution with parameters n = 25 and p = 0.40.

(a)

The mean and variance of X are:

[tex]\mu=np=25\times 0.40=10\\\\\sigma^{2}=np(1-p)-25\times0.40\times(1-0.40)=6[/tex]

Thus, the mean and variance of X are 10 and 6 respectively.

(b)

Compute the values of the interval μ ± 2σ as follows:

[tex]\mu\pm 2\sigma=(\mu-2\sigma, \mu+ 2\sigma)[/tex]

           [tex]=(10-2\cdot\sqrt{6},\ 10+2\cdot\sqrt{6})\\\\=(5.101, 14.899)\\\\\approx (5, 15)[/tex]

Compute the probability of P (5 ≤ X ≤ 15) as follows:

[tex]P(5\leq X\leq 15)=\sum\limits^{15}_{x=5}{{25\choose x}(0.40)^{x}(1-0.40)^{25-x}}[/tex]

                        [tex]=0.0199+0.0442+0.0799+0.1199+0.1511+0.1612\\+0.1465+0.1140+0.0759+0.0434+0.0212\\\\=0.9772[/tex]

Thus, 97.72% values of the binomial random variable x fall into this interval.

(c)

Compute the value of P (6 ≤ X ≤ 14) as follows:

[tex]P(6\leq X\leq 14)=\sum\limits^{14}_{x=6}{{25\choose x}(0.40)^{x}(1-0.40)^{25-x}}[/tex]

                        [tex]=0.0442+0.0799+0.1199+0.1511+0.1612\\+0.1465+0.1140+0.0759+0.0434\\\\=0.9361\\\\\approx P(5\leq X\leq 15)[/tex]

The value of P (6 ≤ X ≤ 14) is 0.9361.

According to the Tchebysheff's theorem, for any distribution 75% of the data falls within μ ± 2σ values.

The proportion 0.9361 is very large compared to the other distributions.

Whereas for a mound-shaped distributions, 95% of the data falls within μ ± 2σ values. The proportion 0.9361 is slightly less when compared to the mound-shaped distribution.

Probabilities are used to determine the chance of an event.

[tex]\mathbf{Mean = 10}[/tex] and [tex]\mathbf{Variance = 6}[/tex].97.72% values of the binomial random variable x fall into the interval [tex]\mathbf{\mu \pm 2\sigma}[/tex].93.61% values of the binomial random variable x fall into the interval 6 to 14

The given parameters are:

[tex]\mathbf{n = 25}[/tex]

[tex]\mathbf{p = 40\%}[/tex]

(a) Mean and variance

The mean is calculated as follows:

[tex]\mathbf{Mean = np}[/tex]

[tex]\mathbf{Mean = 25 \times 40\%}[/tex]

[tex]\mathbf{Mean = 10}[/tex]

The variance is calculated as follows:

[tex]\mathbf{Variance = np(1 - p)}[/tex]

So, we have:

[tex]\mathbf{Variance = 25 \times 40\%(1 - 40\%)}[/tex]

[tex]\mathbf{Variance = 6}[/tex]

(b) The interval  [tex]\mathbf{\mu \pm 2\sigma}[/tex]

First, we calculate the standard deviation

[tex]\mathbf{\sigma = \sqrt{Variance}}[/tex]

[tex]\mathbf{\sigma = \sqrt{6}}[/tex]

[tex]\mathbf{\sigma = 2.45}[/tex]

So, we have:

[tex]\mathbf{\mu \pm 2\sigma = 10 \pm 2 \times 2.45}[/tex]

[tex]\mathbf{\mu \pm 2\sigma = 10 \pm 4.90}[/tex]

Split

[tex]\mathbf{\mu \pm 2\sigma = 10 + 4.90\ or\ 10 - 4.90}[/tex]

[tex]\mathbf{\mu \pm 2\sigma = 14.90\ or\ 5.10}[/tex]

Approximate

[tex]\mathbf{\mu \pm 2\sigma = 15\ or\ 5}[/tex]

So, we have:

[tex]\mathbf{\mu \pm 2\sigma = (5,15)}[/tex]

The binomial probability is then calculated as:

[tex]\mathbf{P = ^nC_x p^x \times (1 - p)^{n - x}}[/tex]

This gives

[tex]\mathbf{P = ^{25}C_5 \times (0.4)^5 \times (1 - 0.6)^{25 - 5} + ...... +^{25}C_{15} \times (0.4)^{15} \times (1 - 0.6)^{25 - 15}}[/tex]

[tex]\mathbf{P = 0.0199 + ..... + 0.0434 + 0.0212}[/tex]

[tex]\mathbf{P = 0.9772}[/tex]

Express as percentage

[tex]\mathbf{P = 97.72\%}[/tex]

This means that; 97.72% values of the binomial random variable x fall into the interval [tex]\mathbf{\mu \pm 2\sigma}[/tex]

[tex]\mathbf{(c)\ P(6 \le x \le 14)}[/tex]

The binomial probability is then calculated as:

[tex]\mathbf{P = ^nC_x p^x \times (1 - p)^{n - x}}[/tex]

So, we have:

[tex]\mathbf{P = ^{25}C_6 \times (0.4)^6 \times (1 - 0.4)^{25 - 6} + ...... +^{25}C_{14} \times (0.4)^{14} \times (1 - 0.4)^{25 - 14}}[/tex]

[tex]\mathbf{P = 0.0422 +.............+0.0759 + 0.0434}[/tex]

[tex]\mathbf{P = 0.9361}[/tex]

This means that:

93.61% values of the binomial random variable x fall into the interval 6 to 14

By comparison, 93.61% is very large compared to the other distributions., and the proportion 93.61 is slightly less when compared to the mound-shaped distribution.

Read more about binomial probability at:

https://brainly.com/question/19578146

What is the value of (-3/4)-4

Answers

Answer: -19/4

Step-by-step explanation:

Answer:

-4.75

Step-by-step explanation:

-3+16/4

= -19/4

= -4.75

Part A) What is the cost of 14.6 gallons of gasoline at $2.70 per gallon? Part B) Explain the steps you would take to solve this problem.

Answers

Answer:

$39.42

Step-by-step explanation:

SImply multiply 14.6 with 2.70 which will give us 39.42.

Price per gallon=2.70Total gallons=14.6

Price:-

[tex]\\ \tt\hookrightarrow 14.6(2.7)[/tex]

[tex]\\ \tt\hookrightarrow 39.42\$[/tex]

36,815 to the nearest hundred

Answers

Answer:

36,800

Step-by-step explanation:

If x < 5, we round down.

If x ≥ 5, we round up.

We are specifically looking at 8 and 1 in 36,815.

1 < 5, so we round down:

36,800

5. 2x + 5 - 7x = 15
6.
X=

Help me

Answers

Answer:

-2

Step-by-step explanation:

2x+5-7x=15

Combine like terms

-5x+5=15

Subtract 5 from both sides

-5x=10

Divide -5 from both sides

x=-2

Answer:

2x+5-7x=15

-5x+5=15

5-15 =5x

-10 =5x

10/5=x

x= -2

1. A research team wants to investigate the usefulness of relaxation training for reducing levels of anxiety in individuals experiencing stress. They identify 30 people at random from a group of 100 who have "high stress" jobs. The 30 people are divided into two groups. One group acts as the control group - they receive no training. The second group of 15 receive the relaxation training. The subjects in each group are then given an anxiety inventory. The summarized results appear below where higher scores indicate greater anxiety. Evaluate using the criteria of p < .05. Assume it is a two tailed test.

Answers

Answer:

a. H0:u1=u2

Ha:u1>u2

b. T-critical value =1.7011

c. We can conclude that relaxation training has reduced stress levels based on evidence gathered from statistical calculations

Step-by-step explanation:

Please find attachment

Suppose that the functions g and h are defined for all real numbers x as follows.
g(x) = 3x-6
h(x) = 5x
Write the expressions for (g-h)(x) and (g+h)(x) and evaluate (g-h)(-1) ​

Answers

Answer:

See Below.  

Step-by-step explanation:

We are given the two functions:

[tex]\displaystyle g(x) = 3x - 6 \text{ and } h(x) = 5x[/tex]

Part A)

Recall that:

[tex](g\cdot h)(x)=g(x)\cdot h(x)[/tex]

Substitute and simplify:

[tex]\displaystyle \begin{aligned} (g\cdot h)(x) & = (3x-6)\cdot(5x) \\ \\ &=5x(3x)-5x(6) \\ \\&=15x^2-30x \end{aligned}[/tex]

Part B)

Recall that:

[tex](g+h)(x)=g(x)+h(x)[/tex]

Substitute and simplify:

[tex]\displaystyle \begin{aligned} g(x) + h(x) & = (3x-6) + (5x) \\ \\ & = 8x- 6 \end{aligned}[/tex]

Part C)

Recall that:

[tex]\displaystyle (g-h)(x) = g(x) - h(x)[/tex]

Hence:

[tex]\displaystyle \begin{aligned} (g-h)(-1) & = g(-1) - h(-1) \\ \\ & = (3(-1)-6) - (5(-1)) \\ \\ & = (-9) + (5) \\ \\ & = -4\end{aligned}[/tex]

in training for a swim meet Logan swim 750 meters in 1/3 of an hour his swimming partner Milo swam 2/3 of Logan's distance in 1/4 of an hour.Compare mila's and logan's swimming speeds.​

Answers

Answer:

speed of Logan is 37.5 m/minutes

speed of Milo is 33.33 meters per minutes

Speed of Logan is greater than speed of Milo

difference in speed = 37.5 - 33.33 = 4.17 meters per minutes

Step-by-step explanation:

we will calculate speed in meters per minutes

we know 1 hour = 60 minutes and

1 minutes = 60 seconds

speed = distance/time

____________________________________

For Logan

distance = 750 meters

time = 1/3 of hour = 1/3 *60 minutes = 20 minutes

speed = 750/20 = 37.5 meters per minute

__________________________________________________

For milo

distance = 2/3 of Logan's distance = 2/3 * 750 meters = 500 meters

time = 1/4 of hour = 1/4 *60 minutes =15 minutes

speed = 500/15 = 33.33  meters per minute

Thus, speed of Logan is 37.5 m/minutes

speed of Milo is 33.33 meters per minutes

Speed of Logan is greater than speed of Milo

difference in speed = 37.5 - 33.33 = 4.17 meters per minutes

Find the area of a triangle whose vertices are P(1,3,2) Q(2,-1, 1) R(-1,2,3)​

Answers

Answer:

5199

Step-by-step explanation:

Because

What is the slope of the line?


A. −1/2



B. 2



C. −2



D. 1/2


















Answers

Answer:

[tex]\frac{2}{1}[/tex]

Step-by-step explanation:

Hello!

To find the slope of a line we divide how many times it goes over by the number of times it goes up

The line goes over 4 and up 2 which is shown like

[tex]\frac{4}{2}[/tex]

We can simplify this

[tex]\frac{2}{1}[/tex]

The answer is [tex]\frac{2}{1}[/tex]

Hope this helps!

It’s D. (1/2)

Explanation :-
m=(y2-y1)/(x2-x1)
m=(1- -1)/(2- -2)
m=1/2

The face of a cat is symmetrical, with the bridge of the nose falling on the line of symmetry directly between the eyes. If a cat’s right eye is 3 inches from the bridge of its nose, how far is the cat’s left eye from its right eye?

Answers

Answer:

6

Step-by-step explanation:

The cat's bridge of its nose lines up directly on the line of symmetry, so let's say it's (0,0). If the cat's right eye is 3 inches away from its nose, then that point is (3, 0). The cat's left eye is also 3 inches away from the bridge of its nose, so that point is (-3, 0). How do you go from -3 to 3? You must add 6!

Square root of 136161
by
long
division​

Answers

Answer:

369

Step-by-step explanation:

Hello. If we write this number as square root of (41)^2 x 9^2, 41 and 9 will exit in the root. So, 41 x 9 = 369.

who was the first president of unitate state America​

Answers

Answer:

George Washington

Step-by-step explanation:

[tex] &#128075 [/tex] Hello! ☺️

R- George Washington

[tex]<marquee direction="left" scrollamount="2" height="100" width="150">Mynea04</marquee>[/tex]

On a tree farm, a forester wants to estimate the total number of trees with diameters exceeding 12 inches. A map of the farm is available. Discuss the problem of choosing appropriate sampling units and an appropriate frame.

Answers

Answer:

The problems associated with choosing appropriate sampling units and frame are given below;

Step-by-step explanation:

1. The only aid available to the forester or researcher is a map of the farm.

2. Appropriate sampling units will be hard to choose because farm trees are only characterized by attributes such as

- type of crop/plant (as all trees of a certain crop are much likely to have similar width or diameter)

- height of tree (as height is closely related to width)

- location of tree on the farm (e.g. North on the map, East on the map, South on the map, West on the map)

- age of tree (as older trees are more likely to have diameters exceeding 12 inches, than the younger trees)

- etcetera.

3. Appropriate frame (size) of sample will be hard to choose because a number of trees cannot just be selected from the total number of trees, if the categorization for sampling units is uncertain.

The distribution of the weights of a sample of 140 cargo containers is symmetric and bell-shaped, with a mean of 500 pounds and a standard deviation of 20 pounds. What percentage of the cargo containers will weigh between 460 pounds and 540 pounds?
a. 95%
b. Can't tell-there is not enough information
c. 67%
d. 99%

Answers

Answer:

a. 95%

Step-by-step explanation:

We solve this question, using z score formula.

Z score formula = (x - μ)/σ/√n

where x is the raw score

μ is the population mean

σ is the population standard deviation.

n is number of samples

For z1, where x1 = 460, μ = 500, σ = 20, n = 140

z score formula = (460 - 500)/ 20

= -40/20

= -2

We find the probability of the z score using the z score table.

P(x = 460) = P(z = -2)

= 0.02275

For z2, where x2 = 540, μ = 500, σ = 20

z score formula = (540 - 500)/20

= 40/20

= 2

We find the probability of the z score using the z score table.

P(x = 540) = P(z = 2)

= 0.97725

The probability that the cargo containers will weigh between 460 pounds and 540 pounds is calculated as:

= 460 < x < 540

= P(z = 2) - P(z = -2)

= 0.97725 - 0.02275

= 0.9545

Converting to percentage

0.9545 × 100

= 95.45%

Therefore,the percentage of the cargo containers will weigh between 460 pounds and 540 pounds is 95%

Which set of ordered pairs could represent the same function as y = x2 ?
A (1, 1), (2, 4), (3,6)
B (1,1),(3,9), (7,49)
© (1,2), (4,16), (8, 64)
D (4,8), (5, 25), (6,36)

Answers

Answer:

B (1, 1),(3, 9), (7, 49)

Step-by-step explanation:

Given function:

y = x²

Let's verify which set of pairs are same with the given function:

A....................

(1, 1) - yes(2, 4) - yes(3, 6)  - no, 6≠ 3²

B....................

(1, 1) - yes(3, 9) - yes(7, 49)  - yes

C....................

(1, 2)- no, 2≠ 1²(4, 16) - yes(8, 64)  - yes

D....................

(4, 8) - no, 8 ≠ 4²(5, 25) - yes(6, 36) - yes

Which of the following is a monomial ? 9/x 11x2 20x9-7x 20x -14

Answers

Answer: 11x^2

Step-by-step explanation:

I suppose that the options are:

a) 9/x

b) 11x^2

c) 20x^9-7x

d) 20x -14

First, a polynomial is something like:

aₙx^n + .... + a₂*x^2 + a₁*x^1 + a₀*x^0

Where n is the degree of the polynomial,  the therms a are the coefficients, and aₙ is the leading coefficient.

Depending on the number of terms of the polynomial, it takes different names.

If we have only one term, it is called a monomial, if it has two terms, it is called a binomial, and so on.

So if we want to find a monomial, then we need to look at the options with only one term.

The options with only one term are options a and b.

But option a is a quotient (we have a negative power of x: 9/x = 9*x^-1)

So this is not a polynomial, then the correct option is option b.

Find the volume of the cylinder either enter an exact answer in terms of pi or use 3.14 for pi

Answers

1/2πr^2h.

1/2×3.142×3^2×2=

1/2×56.556=28.278~ 28.

Answer:

18pi

Step-by-step explanation:

I just got it right on Khan Academy

how many lines are symmetry has an isosceles triangle ​

Answers

an isosceles triangle has 3 lines of symmetry

Identify the LCD of the rational expressions in the equation.
[tex]\frac{x}{x+3} + \frac{1}{x} = \frac{3}{x}[/tex]

Answers

Answer: okay so i did the equation for you to find the least common denominator. hope that helps!

What expression converts 100 inches per minute to feet per minute?

Answers

1 foot= 12 inches.

To convert you must have "2 fractions" to multiply.

Your first fraction must be 100in/1min. (100 inches per 1 minute).

The second should serve to convert inches to feet. It should be 1 foot/ 12 inches. (1 foot per 12 inches).

Your product should be 100ft/12 which equals 8.3 repeating or 25/3 (8 1/3) feet.

Flaws in a carpet tend to occur randomly and independently at a rate of one every 270 square feet. What is the probability that a carpet that is 8 feet by 14 feet contains no flaws

Answers

Answer:

The probability that it contains no flaws=0.585

Step-by-step explanation:

Flaws in a carpet tend to occur randomly and independently at a rate of one every 270 square feet.

One = 270 ft²

8*14= 112 ft²

Probability of containing flaws

So if 270 ft² = 1

112 ft² = 112/270

112ft² = 0.415

The probability that it contains no flaws= 1- probability that it contains

The probability that it contains no flaws= 1-0.415

The probability that it contains no flaws=0.585

For i≥1 , let Xi∼G1/2 be distributed Geometrically with parameter 1/2 . Define Yn=1n−−√∑i=1n(Xi−2) Approximate P(−1≤Yn≤2) with large enough n .

Answers

Answer:

The answer is "0.68".

Step-by-step explanation:

Given value:

[tex]X_i \sim \frac{G_1}{2}[/tex]

[tex]E(X_i)=2 \\[/tex]

[tex]Var (X_i)= \frac{1- \frac{1}{2}}{(\frac{1}{2})^2}\\[/tex]

             [tex]= \frac{ \frac{2-1}{2}}{\frac{1}{4}}\\\\= \frac{ \frac{1}{2}}{\frac{1}{4}}\\\\= \frac{1}{2} \times \frac{4}{1}\\\\= \frac{4}{2}\\\\=2[/tex]

Now we calculate the [tex]\bar X \sim N(2, \sqrt{\frac{2}{n}})\\[/tex]

[tex]\to \frac{\bar X - 2}{\sqrt{\frac{2}{n}}} \sim N(0, 1)\\[/tex]

[tex]\to \sum^n_{i=1} \frac{X_i - 2}{n} \times\sqrt{\frac{n}{2}}} \sim N(0, 1)\\\\\to \sum^n_{i=1} \frac{X_i - 2}{\sqrt{2n}} \sim N(0, 1)\\[/tex]

[tex]\to Z_n = \frac{1}{\sqrt{n}} \sum^n_{i=1} (X_i -2) \sim N(0, 2)\\[/tex]

[tex]\to P(-1 \leq X_n \leq 2) = P(Z_n \leq Z) -P(Z_n \leq -1) \\\\[/tex]

                               [tex]= 0.92 -0.24\\\\= 0.68[/tex]

1. When bisecting a line segment, why must you find the intersection points of the arcs both above and below the line segment? A. To make sure that you get a straight line to bisect the line segment. B. The intersection point above the line segment overestimates the midpoint, while the intersection point below the line segment underestimates the midpoint. C. Finding both intersection points helps if the line segment is not completely vertical or horizontal. D. Only one intersection point is needed to find the midpoint, but finding both points allows you to check your work. 2. A line segment has a length of approximately 10 cm. If a compass is set to a width of 9 cm, will it still be possible to bisect the line segment? Explain. A. No, it is not possible. The compass should be just a little bit wider than half of the length of the line segment, which in this case is 5 cm. B. Yes, it is still possible. The width of the compass in respect to the length of the line segment does not matter. C. No, it is not possible. The width of the compass should be exactly half of the length of the line segment, which in this case is 5 cm. D. Yes, it is still possible. So long as the compass is wider than half the length of the line segment and still intersects the line segment, it is possible to bisect the line segment.

Answers

Answer:

A)Option A - To make sure that you get a straight line to bisect the line segment

B) Option D - Yes, it is still possible. So long as the compass is wider than half the length of the line segment and still intersects the line segment, it is possible to bisect the line segment.

Step-by-step explanation:

1) In bisection of a line segment, we seek to divide the line into 2 equal parts. Now, when using the bisection points of an arc, it's important to have two intersection points above and below the line segment so that we can draw a straight line that will pass through the horizontal line segment we are bisecting to make the bisected parts equal in length.

So option A is correct.

2) When bisecting a horizontal line segment using compass, usually we place one leg of the compass at one endpoint of the line and open the other leg of the compass to a length that's more than half of the horizontal line segment. Thereafter, we draw our arc from top to bottom. Without changing the distance of the opened compass, we put one of the legs at the 2nd endpoint and now draw another arc to intersect the previously drawn one.

Now, from the question we are told that the line segment has a length of approximately 10 cm and the compass is set to a width of 9 cm. Now, since 9cm is more than half of the line segment and provided this width of 9cm is maintained when moving the leg to the second endpoint, then it is possible.

Option D is correct.

What is the probability that a randomly chosen student admitted in the hospital is between 11 and 14 years

Answers

Answer:

convert 13.025 to base 10

A truck traveled 205 miles in 3 1/2 hours. The distance is the product of the rate and the time. To the nearest tenth, what is the average speed of the delivery truck? Enter your answer in the box. ____ miles per hour

Answers

Answer:

58.6 miles / hour

Step-by-step explanation:

The formula is

d= rt  where d is the distance, r is the rate ( speed) and t is the time

205 miles = r * 3.5 hours

Divide each side by 3.5

205 miles/ 3.5 hours = r

58.57142857 miles / hour = r

To the nearest tenth

58.6 miles / hour

Answer:

58.6

Step-by-step explanation:

So the truck traveled 205 miles in 3.5 hours.

As given, the distance is the product of the rate and the time. In other words:

[tex]d\text{ mi}=r\cdot t\text{ hours}[/tex]

Substitute 205 for d and 3.5 for t. Thus:

[tex]205\text{ mi} =r\cdot (3.5)\text{hours}[/tex]

Divide both sides by 3.5 hours. Thus:

[tex]r=\frac{205\text{ mi}}{3.5\text{ hours}}[/tex]

Divide 205 and 3.5:

[tex]r\approx58.6\text{ mi/hr}[/tex]

Let (8,−3) be a point on the terminal side of θ. Find the exact values of cosθ, cscθ, and tanθ.

Answers

Answer:

[tex]\text{Cos}\theta=\frac{\text{Adjacent side}}{\text{Hypotenuse}}=\frac{x}{R}=\frac{8}{\sqrt{73}}[/tex]

[tex]\text{Csc}\theta=-\frac{\sqrt{73}}{3}[/tex]

[tex]\text{tan}\theta =\frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{y}{x}=\frac{-3}{8}[/tex]

Step-by-step explanation:

From the picture attached,

(8, -3) is a point on the terminal side of angle θ.

Therefore, distance 'R' from the origin will be,

R = [tex]\sqrt{x^{2}+y^{2}}[/tex]

R = [tex]\sqrt{8^{2}+(-3)^2}[/tex]

  = [tex]\sqrt{64+9}[/tex]

  = [tex]\sqrt{73}[/tex]

Therefore, Cosθ = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}=\frac{x}{R}=\frac{8}{\sqrt{73}}[/tex]

Sinθ = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}=\frac{y}{R}=\frac{-3}{\sqrt{73} }[/tex]

tanθ = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{y}{x}=\frac{-3}{8}[/tex]

Cscθ = [tex]\frac{1}{\text{Sin}\theta}=\frac{R}{y}=-\frac{\sqrt{73}}{3}[/tex]

Find the cost of 4 tubes of oil paint and 2 canvases

Answers

Answer:

You have to put in the whole word problem

Step-by-step explanation:

The amount of a chemical solution is measured to be 2 liters. What is the percent error of the measurement? 2.55% 25% 50%

Answers

Answer:

2.55 percent

Step-by-step explanation:

A company finds that the rate at which the quantity of a product that consumers demand changes with respect to price is given by the​ marginal-demand function Upper D prime (x )equals negative StartFraction 4000 Over x squared EndFraction where x is the price per​ unit, in dollars. Find the demand function if it is known that 1002 units of the product are demanded by consumers when the price is ​$4 per unit.

Answers

Answer:

D(x) = 4000 / x + 2

Step-by-step explanation:

Given:

marginal-demand function = d /dx[D(x )] = D'(x)= -4000/x²

Quantity of product demanded = 1002 units

Price of product per unit = $4

To find:

demand function D(x)

Solution:

D'(x)= -4000/x²

      =  -4000/x² dx

      = -4000 x⁻² dx

D(x) = -4000 x⁻¹ + C

D(x) = -4000/x + C

Since we know that the quantity of product is 1002 and price per unit is $4 so,

D(4) = 1002 = 4000/4 + C

          1002 = 4000/4 + C  

          1002 = 1000 + C  

           1002 - 1000 = C

            C = 2

Hence the demand function is:

D(x) = 4000 / x + 2

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