B) Three single-phase transformers, each rated at 10 kVA, 115/415 V, 50 Hz, are
connected to form a three-phase, 200/415 V transformer bank. The equivalent
impedance of each transformer referred to the high voltage side is (0.5 + j 1.0) Ω.
The three-phase transformer is connected to a three-phase source through threephase
feeders. The impedance of the feeder is (0.01 + j 0.03) Ω per phase. The
transformer delivers full load at rated voltage, and 0.8 lagging power factor, through a
three-phase load feeders of impedance (0.2 + j 0.3) Ω per phase.
i) Sketch the schematic diagram of the three-phase transformer connection.
ii) Solve the transformer winding currents.
iii) Solve the sending–end line voltage and the voltage regulation.
C ) A single-phase, 10 kVA, 400/200 V, 50 Hz transformer has Zeq = (0.02 + j 0.08) pu,
Rc = 30 pu and Xm = 10 pu.
i) Compute the equivalent circuit in ohmic values referred to low voltage side.
ii) If the high voltage side is connected to 400 V supply, and a capacitive load,
Zc = – j10 ohm, is connected to the low voltage side, compute the load current
and the load voltage

Temporary wiring methods shall be acceptable only if they are installed and used in a manner that does not create a hazard to the occupants of the building or to the general public, based on the conditions of use and any special requirements of the temporary installation.

These methods should be suitable for the intended purpose and the conditions of use, taking into consideration factors such as the environment, load capacity, and insulation type.

Furthermore, any special requirements for the temporary installation, such as voltage limitations, protection devices, or grounding, must also be fulfilled.

It is crucial to ensure that temporary wiring is properly installed, inspected, and maintained to prevent potential hazards and comply with all regulations.

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Exception among the statements you provided is: "All fields must have a default value."

In Erlang, type records have several properties that make them useful for organizing data. However, not all the statements you mentioned are true about records in Erlang. The following points are accurate:
Fields can be accessed by name: In Erlang records, you can access the fields by using their names, which makes it easy to work with structured data.Record must be named: Records in Erlang need to have a name so that they can be referred to and used within the code. Needs to be defined before used: Erlang records must be defined before being used in your code, ensuring that the structure of the data is consistent throughout the program.However, the statement "All fields must have a default value" is not necessarily true for records in Erlang. Although it is a good practice to provide default values for fields to avoid unexpected behavior, it is not mandatory. Fields can be left undefined, and it's up to the programmer to handle such cases properly within their code.
So, the exception among the statements you provided is: "All fields must have a default value."

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Hi! In your question about type record in Erlang, the statement "All fields must have a default value" is not true. While it's possible to provide default values for fields in a record, it is not a requirement. The other statements mentioned are true about Erlang records.

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To decrypt an encrypted database in Microsoft Access, you would need a long answer that includes both an administrator account and a password. Having access to an administrator account is essential as it grants you the necessary permissions to access and modify the database.

Additionally, you would need the password associated with the database to decrypt it successfully. Without the correct password, the encrypted database cannot be accessed, even with 128-bit decryption software or backup software. Therefore, it is essential to keep the password secure and not share it with unauthorized users.

In Microsoft Access, to decrypt an encrypted database, you need (c) a password. This password is set during the encryption process and is required to unlock the encrypted content.

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To list the name of the employee who worked on a project sponsored by their division, we can use a correlated subquery. Here is an example SQL query that can achieve this:

SELECT emp_name

FROM employee e

WHERE EXISTS (

 SELECT *

 FROM project p

 WHERE p.sponsor_division = e.division

 AND p.project_id = e.project_id

);

The above query uses a subquery to check if there exists a project in the database that is sponsored by the same division as the employee, and that the employee has worked on. This subquery is correlated with the outer query through the use of the e alias, which represents the employee table.

The EXISTS keyword is used to check for the existence of a matching record. If a match is found, the employee's name is selected in the outer query.

By using a correlated subquery, we can effectively filter out any employees who have worked on projects that are not sponsored by their division.

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The equation of motion for a hanging spring-mass system can be found using Newton's laws and the natural frequency can be computed.

To find the equation of motion for a hanging spring-mass system, we need to apply Newton's laws and use static equilibrium. Gravity affects the equation of motion and the system's natural frequency because it creates an additional force that opposes the motion of the mass.

This force is proportional to the mass and the acceleration due to gravity, and it reduces the system's natural frequency.

The natural frequency is the frequency at which the system oscillates without any external forces acting on it. As gravity is an external force, it changes the frequency at which the system oscillates.

The greater the mass of the object, the slower the oscillation and the lower the natural frequency.

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Answer: True

Explanation: I just know from other sources.

Repair of a leaky fitting in a galvanized piping system often requires that the pipe be cut and a new fitting installed so the leaking joint can be repaired.

Galvanized piping systems are commonly used for water distribution and plumbing applications. Over time, fittings in these systems may develop leaks due to corrosion, deterioration, or improper installation. To repair a leaky fitting, the affected section of the galvanized pipe needs to be cut to remove the damaged portion. This can be done using a pipe cutter or a saw specifically designed for cutting metal pipes.

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The potential difference across the element when the current is 2 amperes is 50 V

The given heating element supplies 300 kJ in 50 minutes. First, we need to convert minutes into seconds.1 minute = 60 seconds

Therefore, 50 minutes = 50 x 60 = 3000 seconds

We know that the power, P = energy / timeP = 300,000 / 3000P = 100 W

We are also given the current, I = 2 A

To find the potential difference, we can use Ohm's law. According to Ohm's law, the potential difference (V) across the element is given by

V = IR

Where R is the resistance of the heating element. We know that P = VIAlso, P = I²R

Therefore, R = P / I²R = 100 / 4R = 25 ohms

Now we can use Ohm's law to find V. V = IR

V = 2 x 25V = 50 V

Therefore, the potential difference across the element when the current is 2 amperes is 50 V.Answer:Therefore, the potential difference across the element when the current is 2 amperes is 50 V.

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To implement wireless networking, the following basic software is required: device drivers, wireless netork management software, security software and network protocol software.

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Maximum shear stress in the shaft = 8,658 psi.

To calculate the maximum shear stress produced in the shaft, we need to use the formula:

τ_max = (16T)/([tex]π*d^3[/tex])

where τ_max is the maximum shear stress, T is the torque transmitted through the shaft, d is the outer diameter of the shaft, and π is a mathematical constant approximately equal to 3.14159.

First, we need to calculate the torque T that is transmitted through the shaft. We can use the formula:

T = (HP ˣ 63025) / N

where T is the torque in lb-ft, HP is the power in horsepower, and N is the rotational speed in rpm.

Substituting the given values, we get:

T = (225 ˣ 63025) / 4000 = 3541.4 lb-ft

Next, we can substitute the given values for d and t in the formula for τ_max:

τ_max = (16T)/(πˣd³) = (16 ˣ 3541.4)/(πˣ(3.000)³ˣ(1-0.125/3.000)³) = 8,658 psi

Therefore, the maximum shear stress produced in the shaft is 8,658 psi.

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The to_char function can be used to format date, time, and number data.

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All proposals should demonstrate a thorough understanding of the data Integration issues mentioned above and clearly illustrate how the proposed solution addresses each of these challenges.

Data Quality: The proposed solution should ensure high data quality by identifying and resolving inconsistencies, inaccuracies, and redundancies across multiple data sources.
Data Mapping: It should facilitate efficient data mapping, including the establishment of relationships and transformation rules between data elements from different sources.
Data Transformation: The solution should enable seamless data transformation, conversion, and normalization, ensuring compatibility between source and target systems.
Data Governance: The proposed system should adhere to strict data governance standards, ensuring data security, privacy, and regulatory compliance.
Scalability: The solution should be capable of accommodating future growth, handling increased data volume, and integrating additional data sources as needed.
. Compatibility: The proposed system should be compatible with our existing technology infrastructure and integrate seamlessly with various applications and data sources.
Please submit your proposals, including a detailed description of the proposed solution, an implementation timeline, and cost estimates, by [submission deadline]. All proposals should demonstrate a thorough understanding of the data integration issues mentioned above and clearly illustrate how the proposed solution addresses each of these challenges.

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When drafting a Request for Proposal (RFP) for data integration, it is important to consider various types of issues that can arise during the process.

When preparing an RFP for data integration, it is crucial to address potential issues that can impact the success of the integration project.

Some common challenges include s:

By clearly outlining these challenges in the RFP and seeking solutions from potential vendors or service providers, organizations can ensure that their data integration project is carried out effectively and efficiently.

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To estimate the surface temperature, we will use the following equation:
Q = k * A * (T_surface - T_back) / d
Where:
- Q is the surface heat flux (4.63x10^3 W/m²)
- k is the thermal conductivity (50 W/m·K)
- A is the area of the heater element (we will assume it is a 1 m² area for simplicity)
- T_surface is the surface temperature we want to estimate
- T_back is the temperature at the back surface (266.4 °C)
- d is the thickness of the heater element (0.015 m)
First, let's solve the equation for T_surface:
T_surface = Q * d / (k * A) + T_back
Now, plug in the values:
T_surface = (4.63x10^3 W/m²) * (0.015 m) / (50 W/m·K * 1 m²) + 266.4 °C
T_surface ≈ 2.778 + 266.4 °C
T_surface ≈ 269.178 °C
Thus, the estimated surface temperature is approximately 269.178 °C.

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The horizontal coordinate on the generalized compressibility chart is the reduced pressure, which is defined as the pressure divided by the critical pressure of the gas.

On the generalized compressibility chart, the horizontal coordinate represents the reduced pressure.

The reduced pressure is defined as the actual pressure divided by the pressure of the gas at its critical point, also known as the critical pressure.

The critical pressure is a thermodynamic property specific to each gas and represents the pressure at which the gas can no longer be liquefied, regardless of temperature.

By dividing the actual pressure by the critical pressure, we obtain the reduced pressure, which is a dimensionless quantity.

The reduced pressure is used as the horizontal coordinate on the generalized compressibility chart to compare the behavior of different gases at various pressures and temperatures.

It allows for a standardized representation of gas properties and facilitates the analysis and prediction of gas behavior in different conditions.

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To compute the data rate required to live stream uncompressed HD video with a resolution of 1920 x 1080 pixels, a frame rate of 24 fps, and color depth equal to 10 bits, we can use the following formula:

Data Rate = Resolution x Frame Rate x Color Depth

Plugging in the values, we get:

Data Rate = 1920 x 1080 x 24 x 10
         = 4,718,592,000 bits per second
         = 4.72 Gbps

Therefore, the data rate required to live stream uncompressed HD video with these parameters is 4.72 Gbps. This is a very high data rate and is typically not practical for live streaming over the internet. Most streaming services compress the video to reduce the data rate and make it more feasible for streaming over the internet.

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The data rate required to live stream uncompressed HD video with these parameters is approximately 498.07 Mbps.

To calculate the data rate required to live stream uncompressed HD video, we need to determine the amount of data transmitted per second. This can be done by multiplying the number of pixels in each frame by the number of bits per pixel and then multiplying that result by the frame rate.

The number of pixels in each frame is given by the resolution, which in this case is 1920 x 1080 = 2,073,600 pixels.

The number of bits per pixel is 10, as given in the problem.

The frame rate is 24 frames per second.

Therefore, the data rate required to live stream uncompressed HD video with these parameters is:

Data rate = Number of pixels per frame x Number of bits per pixel x Frame rate

            = 2,073,600 x 10 x 24

            = 498,073,600 bits per second

Converting this to megabits per second (Mbps) by dividing by 1,000,000:

Data rate = 498,073,600 / 1,000,000

            = 498.07 Mbps

The data rate required to live stream uncompressed HD video with these parameters is approximately 498.07 Mbps.

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The transistor has a drain current of 52.8 mA when operating at the edge of saturation.

To find the drain current (Ip) at the edge of saturation, we need to first calculate the drain-source voltage (VDS) at this point. The edge of saturation is when VGS - Vth = VDS.

In this case, VGS = 2.0 V and Vth = 0.9 V, so VDS = VGS - Vth = 2.0 V - 0.9 V = 1.1 V.

The drain current in saturation is given by the equation:

Ip = (k' / 2) * (W/L) * (VGS - Vth)² * (1 + λVDS)

where λ is the channel-length modulation parameter, and VDS is the drain-source voltage.

Here, λ is not given, but assuming it to be 0, we get:

Ip = (k' / 2) * (W/L) * (VGS - Vth)² = (800 μA/V² / 2) * (12) * (1.1 V)² = 52.8 mA

The transistor has a drain current of 52.8 mA when operating at the edge of saturation.

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In torsion, two shafts will have equal strength if their torque transmitting capacity is the same. This means that the amount of torque each shaft can handle before failure is equivalent.

Material alone does not determine the strength of a shaft in torsion, as different materials have different mechanical properties. For example, a steel shaft will typically have a higher strength than an aluminum shaft of the same dimensions. The diameter of the shafts is also an important factor in determining strength, as a larger diameter will allow for a greater torque transmitting capacity. Finally, the angle of twist of the shaft is a critical consideration as it indicates the degree of deformation or stress the shaft can sustain before it fails. Two shafts with the same angle of twist will have similar deformation characteristics and strength. In summary, the strength of two shafts in torsion is dependent on a combination of factors, including torque transmitting capacity, material, diameter, and angle of twist.

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List of referrals with Patient Name, Physician, StartDate, and EndDate where StartDate is in 2013. Sorted by StartDate ascending, Patient First Name ascending, and Physician Last Name ascending.

This query retrieves a list of referrals that meet the criteria of having a start date in 2013. It includes the patient's first and last name combined into one field, the referring physician's last name, and the start and end dates of the referral. The results are sorted in ascending order by start date, patient first name, and physician last name. This query can be useful for analyzing referral patterns over time and identifying trends in physician referrals. By filtering by start date and sorting the results, it makes it easier to identify patterns and trends.

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There are many options available for publishing a website, and Phil will need to carefully consider his priorities and budget when choosing a web host and domain name registrar.

Phil is preparing to publish a Web site he just created and researches his options. He learns that some Web hosts offer domain name registration services, which means that he can register a domain name for his website through his chosen web host. Additionally, he finds out that web hosts typically charge $5 or less per month for hosting services, which is a reasonable cost for most individuals and small businesses. Phil also discovers that while storage space is available from web hosts, it is typically not available from Internet Service Providers (ISPs). Finally, he learns that free web sites may be available, but these usually require users to view advertising in order to offset the cost of hosting the website.

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The DBMS would need to read all pages from disk (10,000,000 pages) and write them out to temporary files.

Therefore, ceil(log_{11}10,000,000) = 3 passes would be needed to sort the file.

The I/O cost for the first pass would be 10,000,000 reads and 1,666,667 writes. In the second pass, the DBMS would merge pairs of temporary files, resulting in ceil(N/B²) = ceil(10,000,000/36) = 278,000 files. The I/O cost for the second pass would be 10,000,000 reads and 278,000 writes.

In the third pass, the DBMS would merge pairs of the resulting files from the second pass, resulting in ceil(N/B^3) = ceil(10,000,000/216) = 46,300 files. The I/O cost for the third pass would be 10,000,000 reads and 46,300 writes. The total I/O cost for sorting the file with 6 buffers would be 10,000,000*3 reads and (1,666,667 + 278,000 + 46,300)*2 writes = 31,658,934 writes.

Assuming that the memory can hold 1000 pages, we can calculate the maximum size of the database file that can be sorted with 5 passes and 10 buffers as follows: N <= 10⁹ = 1,000,000,000 pages.

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The statement "Currently, over 25% of the energy used globally is produced by wind and solar power" is false because the actual percentage of energy produced by wind and solar power globally is significantly less than 25%. Option B is correct.

The International Energy Agency's Renewables 2021 report states that the share of wind and solar energy in global electricity generation was around 10% in 2020. This indicates that while the use of renewable energy has grown significantly in recent years, it still accounts for a relatively small portion of the total energy production globally.

It is important to accurately understand the current state of renewable energy production as it helps in setting realistic targets and goals for future energy policies and investments.

Therefore, option B is correct.

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The given Boolean function "copyright oxford university press. all rights reserved. unauthorized reprinting or distribution is prohibited" can be realized using a CMOS implementation. CMOS stands for Complementary Metal-Oxide-Semiconductor and is a widely used technology for digital logic circuits.

To realize the given boolean function using CMOS, we need to first convert the sentence into its logical equivalent. We can represent "copyright" as A, "unauthorized reprinting or distribution is prohibited" as B, and "all rights reserved" as C. Then, the given sentence can be represented as A.C.B.

To implement this in CMOS, we can use three CMOS inverters connected in series to realize the AND operation between A and C. Then, we can use a PMOS transistor and an NMOS transistor connected in series to realize the NOT operation between B and the output of the previous AND gate. Finally, we can use a CMOS inverter to invert the output of the previous NOT gate to obtain the final output of the circuit.

In summary, the CMOS realization for the boolean function "copyright oxford university press. all rights reserved. unauthorized reprinting or distribution is prohibited" is a circuit consisting of three CMOS inverters, a PMOS transistor, an NMOS transistor, and a CMOS inverter. This circuit implements the logical expression A.C.B and can be used to detect unauthorized reprinting or distribution of copyrighted material.

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According to the video Making Stuff: Smaller, silicon transistors can be made smaller because they are materials that can be crafted into tiny mechanical switches.

Silicon is a semiconductor material that has unique properties that make it ideal for building transistors. It can be purified and grown into large single-crystal boules, which are then sliced into thin wafers that are used to make individual transistors. The smaller the transistor, the more of them can be packed onto a single computer chip, which increases the speed and power of the device.

This is because smaller transistors require less power to operate and generate less heat, which means that they can be packed more densely onto a chip without overheating. Silicon transistors are also metallic, which means that they conduct electricity and are used to build electrical circuits. The tiny mechanical switches that makeup transistors are able to turn on and off rapidly, which allows them to process information and control the flow of electrical current through a device.

Overall, the ability to make smaller silicon transistors is a crucial factor in the development of faster, more powerful, and more efficient electronic devices. As technology continues to advance, researchers and engineers will continue to find ways to make transistors even smaller and more efficient, leading to new innovations in the world of electronics.

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(a) The equilibrium band diagram for the Schottky barrier can be drawn as follows:

In the diagram, the Fermi level of the metal is aligned with the conduction band of p-type Si. The built-in potential at the interface creates a depletion region in the Si, where there are fewer holes than in the bulk. The barrier height is given by qV0, where q is the electron charge and V0 is the difference in the work function and electron affinity, which is 0.3 eV in this case.

(b) The band diagram with 0.3 eV forward bias and 2 V reverse bias can be drawn as follows:

In the forward bias diagram, the applied voltage reduces the barrier height and increases the current flow. In the reverse bias diagram, the applied voltage increases the barrier height and reduces the current flow. The width of the depletion region also changes with the applied voltage.

When a metal and semiconductor are in contact, a Schottky barrier is formed due to the difference in work function and electron affinity. In this case, the metal has a higher work function than the electron affinity of p-type Si, which creates a potential barrier at the interface. The acceptor doping in the Si introduces holes, which are the majority carriers in p-type semiconductors.

At equilibrium, the Fermi level of the metal is aligned with the conduction band of the Si, and the built-in potential creates a depletion region where there are fewer holes than in the bulk. The barrier height is given by qV0, where q is the electron charge and V0 is the difference in the work function and electron affinity.

In the forward bias diagram, the applied voltage reduces the barrier height and increases the current flow. In the reverse bias diagram, the applied voltage increases the barrier height and reduces the current flow. The width of the depletion region also changes with the applied voltage.

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The Boussinesq and Westergaard equations can be used to estimate the vertical pressure at different points below a column load.

The Boussinesq and Westergaard equations are analytical methods used to estimate the vertical pressure exerted by a column load on the soil at various points. These equations take into account factors such as the load magnitude, depth, and distance from the column.

To estimate the vertical pressure directly below the column load at depths of 5, 10, and 15 ft, the Boussinesq equation is typically employed. This equation considers the column load as a point load and calculates the resulting pressure distribution in the soil.

For estimating the vertical pressure at radial distances of 5, 10, and 20 ft, and at a depth of 10 ft, the Westergaard equation is utilized. This equation considers the column load as a circular load and provides a more accurate estimation of pressure at different distances from the column.

These equations are valuable tools in geotechnical engineering for understanding the soil-structure interaction and designing foundations. They enable engineers to assess the bearing capacity of soils, evaluate potential settlements, and ensure the stability and safety of structures.

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A construction project involves planning, designing, and building physical structures such as buildings, roads, bridges, and other infrastructure. It typically includes activities such as site preparation, excavation, foundation work, framing, electrical and plumbing installation, finishing, and inspection. Project management, scheduling, and budgeting are also critical components of construction projects.

In a construction project, various activities occur in different phases. Here's a brief explanation of where each activity would typically take place:

1. Design Development: This phase focuses on refining the design and creating detailed construction documents. Activities in this phase include architectural drawings, structural calculations, and coordination with other consultants such as mechanical, electrical, and plumbing engineers.

2. Bidding and Award: In this phase, the project is advertised for bidding and contractors submit their proposals. Activities include preparing bid documents, evaluating proposals, and selecting the winning bidder. Once the contract is awarded, the construction phase begins.

3. Construction: This phase involves the actual building of the project. Activities include site preparation, material procurement, and the physical construction of the structure according to the design specifications.

4. Project Closeout: In this final phase, the project team ensures all requirements are met, and the completed project is handed over to the owner. Activities include punch list completion, final inspections, and obtaining necessary certificates and permits for occupancy.

5. Construction Project Closeout: This is a sub-phase within the project closeout, specifically focusing on closing out the construction aspect of the project. Activities involve addressing any remaining construction issues, final payments to contractors, and releasing any retainage.

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The quantity of lines of force per unit of area is known as flux density. It is a measure of the strength of the magnetic field and is given by the total number of magnetic field lines passing through a given area. Flux density is denoted by the symbol B and is measured in teslas (T) or gauss (G).

Flux density is dependent on the strength of the magnetic field and the area of the surface on which the magnetic field acts. The larger the surface area, the more spread out the magnetic field lines will be, and hence the lower the flux density. Similarly, the stronger the magnetic field, the higher the flux density.Flux density is an important parameter in magnetic materials and devices such as transformers, motors, and generators. The magnetic properties of these materials are characterized by their permeability, which is a measure of how easily they can be magnetized. Flux density is directly proportional to the magnetizing force (ampere-turns) applied to a magnetic material and inversely proportional to its permeability.In summary, flux density is a measure of the strength of the magnetic field and is determined by the number of magnetic field lines passing through a given area. It is an important parameter in magnetic materials and devices and is dependent on the magnetizing force and the permeability of the material.

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An attenuator functions most effectively at the transcriptional level, specifically within the leader sequence of an operon.

The attenuator is a regulatory region located within the leader sequence of the mRNA molecule. It contains specific nucleotide sequences that can form secondary structures, such as hairpins, during transcription. The formation of these structures affects the continuation of transcription and can lead to premature termination of mRNA synthesis, thus attenuating or reducing the expression of downstream genes in the operon. Therefore, the attenuator's position within the leader sequence allows it to regulate gene expression by modulating the transcriptional process.

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The answer is B) pre-test.

A while loop checks the condition before executing the loop body. It will continue executing the loop body repeatedly until the condition becomes false.

The other options are incorrect:

A) Post-test: A post-test loop checks the condition after executing the loop body. This is not a while loop.

C) Infinite: A while loop is not necessarily infinite. It will continue until the condition becomes false.

D) Limited: A while loop is limited by the condition, but "limited" is not an appropriate description.

E) None of these: Some option must be correct for this type of question.

So the key feature of a while loop is that it checks the condition before executing the loop body. Hence, the answer is B) pre-test.

The while loop is a type of pre-test loop, meaning that the condition is checked at the beginning of each iteration before executing the code block.

This is in contrast to post-test loops, where the condition is checked at the end of each iteration, and infinite loops, where the loop never terminates. While loops can also be limited, meaning that they have a set number of iterations based on the condition provided. Therefore, the answer to your question is B) pre-test. However, this is a long answer, so let me know if you need any further clarification.

The while loop is a B) pre-test loop. This means that the loop's condition is checked before executing the loop body, and if the condition is true, the loop will continue to execute. If the condition is false, the loop will not execute at all.

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The system will have an overshoot for a step input. The amount of overshoot can be calculated using the damping ratio and natural frequency of the closed-loop system.

In order to determine if the system under closed-loop pi control will have an overshoot for a step input, we need to calculate the values of the closed-loop transfer function poles and zeros. The transfer function for a closed-loop pi control is given by:

G(s) = (kp + ki/s) / (1 + ki/s)

For case a (kp=2, ki=1), the closed-loop transfer function becomes:

G(s) = (2 + 1/s) / (1 + 1/s)

The poles of this transfer function are the roots of the denominator:

1 + 1/s = 0

s = -1

Therefore, the system will not have any overshoot for a step input.

For case b (kp=1, ki=3), the closed-loop transfer function becomes:

G(s) = (1 + 3/s) / (1 + 3/s)

The poles of this transfer function are the roots of the denominator:

1 + 3/s = 0

s = -3

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