b) Include this table on your slide:
Mass of Object 1 Mass of Object 2 (kg)
(kg)
Gravitational Force
(N)
1 x 1020
1 x 1020
1 x 1040 G
3 x 1020
1 x 1020
3 x 100 G
2 x 1020
2 x 1020
4 x 10"G
20
3 x 1020
4 x 10
12 x 10 G
c) Use the table to explain how the masses of Objects 1 and 2 relate to the gravitational force
between them. Be sure to:
Describe the scenario.
Explain the table headings to introduce the data in the table.
Use the data to show a trend.
Summarize the information from the table in a sentence, showing the relationship between
the masses of objects and the gravitational force between the objects.
d) Place text in the notes section below the slide explaining the information presented on it. This text
will act as the script for your presentation.
e) Remember to save your work.

The total internal energy of the gas is 5104 Joule.

Internal energy of helium gas=

3/2 × 1.3 × 8.31 × 315

= 5104 joule

Thus, we can conclude that the internal energy of the helium gas is 5104 Joule.

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Steering is defined as intentionally directing someone to or away from specific areas based on the ethnicity of the person or the area.

There are generally three terms used in real estate and that are Steering, Redlining and Blockbusting.

Buyers are guided by steering according to their class.

Redlining mainly refers to the loan industry's discrimination against purchasers.

Blockbusting is the practice of persuading residents of a neighborhood to sell their home because the socioeconomics of the area are deteriorating.

Steering is the act of influencing a buyer's selection of a community based on one of the racial, ethnic, religious, gender, familial, or national origin protected categories listed in the Fair Housing Act.

Hence, Steering is defined as intentionally directing someone to or away from specific areas based on the ethnicity of the person or the area.

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Answer:

As light from a star races through our atmosphere, it bounces and bumps through the different layers, bending the light before you see it. Since the hot and cold layers of air keep moving, the bending of the light changes too, which causes the star's appearance to wobble or twinkle.

The velocity of the boy when he hits the water at the bottom of the slide is 14 m/s.

The velocity of the boy when he hits the water at the bottom of the slide is calculated from the principle of conservation of energy.

K.E = P.E

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

v = √(2 x 9.8 x 10)

v = 14 m/s.

Thus, the velocity of the boy when he hits the water at the bottom of the slide is 14 m/s.

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During primary second stage underwater recovery, it is acceptable to switch to your alternate air source while you search for your primary which makes it a true statement.

This involves the intermediate pressure air from the regulator hose being taken and reduced to ambient pressure.

Switching to your alternate air source  will ensure that the diver breathe safely which is why True was chosen.

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Warming the bed with water is far more efficient than warming the bed with an iron, the difference is the specific heat capacity of water and iron.

The specific heat capacity of a substance can be defined as the amount of the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree).

q = m x C x AT

As the specific heat of water is 4.18 J/g°C and the specific heat of iron is 0.450 J/g°C. Since, the specific heat of water is greater than the specific heat of iron.

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The Moon s escape speed will be smaller than Earth's.

The minimum speed that is required for an object to free itself from the gravitational force exerted by a massive object.

The formula of escape speed is

where

v is escape velocity

G is universal gravitational constant

M is mass of the body to be escaped from

r is distance from the center of the mass

we can say that,

Escape speed depends on the gravity of the object trying to hold the spacecraft from escaping.

we know that,

The Moon's surface gravity is about 1/6th as powerful or about 1.6 meters per second per second.

since, v ∝ g

The Moon s escape speed will be smaller than Earth's.

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Option (c) and (d) are correct

a and b are the recessive alleles represented in genotype AaBb.

An allele is a different nucleotide sequence that codes for the production of a gene product at the same location on a lengthy DNA molecule.

Recessive Allele : A particular allele that, when present alone, has no effect on the person. The expression of the trait requires the presence of two copies of the allele.

Dominant Allele : A dominant allele is a gene variant that will result in a specific phenotype even when there are other alleles present.

Genotype - The genetic configuration that determines the features that an organism inherits from its parents is known as a genotype.

Phenotype - The term "phenotype" refers to an organism's observable physical characteristics, such as its appearance, growth, and behavior.

Hence (a) & (b) are the recessive alleles represented in the genotype AaBb.

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Meta-analysis indicates that violent video games increase aggressive thoughts, aggressive affect, and aggressive behavior.

Children who play violent video games have increased aggressive cognitions, aggressive behavior, psychological arousal as well as antisocial behavior.

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The velocity of light in glycerol is 2.04 × 10⁸ m/s.

To find the answer, we need to know about the expression of velocity of light in any medium.

Speed of light in glycerol= 3×10⁸/1.47 = 2.04 × 10⁸ m/s

Thus, we can conclude that the velocity of light in glycerol is 2.04 × 10⁸ m/s.

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The centripetal force on the car as it goes around the second curve is twice that compared to the first.

What is Centripetal force?

It is the force that is necessary to keep an object moving in a curved path and that is directed inward toward the center of rotation.

The formula of Centripetal force is:

F(c) = (m* v^2) / r

Here,

At the first curve,

The curve of radius = r

The constant speed = v

At the second curve,

The car speed (v')= 2 v

The radius of the curve (r')=2 r

According to the formula of centripetal Force:

As the car goes around the second curve,

F'(c) = m*v'^2 / r'

F'(c) = m* (2*v)^2 / 2r

F'(c) = 2* F

Thus,

The centripetal force on the car as it goes around the second curve is twice that compared to the first.

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the current in the coil of the motor is 8.70A

The motor coil's resistance is R = 27.

The motor's working voltage is V o = 235 V.

When the motor is running at its top speed, the rear emf is V b =141V.

The initial coil current when the motor is turned on must be calculated.

using the information provided,

I=VoR=(235v/27Ω)=8.70A

The number of turns is the first element that affects the current coil's strength. The current in amperes increases with the number of revolutions. The number of turns in a coil also multiplies the magnetic field. The strength of the current of the coil passing through the conductor is the second crucial element.

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The distance between the first and second-order dark fringe is 0.441 m.

Diffraction of a single slit:

When the light wave passes through a single slit of width which is comparable to the wavelength of the light, then the light wave bends at the edges of the slit. This is called diffraction.

Note: It is assumed that the slit is 3*10^(-3) mm wide. 1 nm = 10^(-9) m and 1mm = 10^(-3) m.

The dark fringes are obtained at the position which satisfies the equation,

d*sinθ = mλ

where d is the slit width, λ is the wavelength of the wave, θ is the angle of diffraction and m denotes the order of the dark fringe.

For first order fringe (m=1), the angle of diffraction θ₁ is,

d*sinθ₁ = λ

sinθ₁ =λ/d

Substitute λ=590 nm, d=3*10^(-3) mm, and solve it.

sinθ₁ =(590 nm)/(3*10^(-3) mm)

sinθ₁ =(590*10^(-9))/ (3*10^(-3)*10^(-3) m)

sinθ₁ =0.196

θ₁ =11.03 degree

Similarly, for second-order fringe (m=2), the angle of diffraction θ₂ is,

d*sinθ₂= 2λ

sinθ₂ =2λ/d

Substitute λ=590 nm, d=3*10^(-3) mm, and solve it.

sinθ₂ =(2*590 nm)/(3*10^(-3) mm)

sinθ₂ =(2*590*10^(-9))/ (3*10^(-3)*10^(-3) m)

sinθ₂ =0.393

θ₂ =23.14 degree

From geometry, the positions x₁ and x₂ of the first and second-order dark fringe from the center of the screen are x₁=Dtanθ₁ and x₂= Dtanθ₂ where D is the distance of the screen from the slit. The distance s between the first-order and second-order dark fringe is then given by,

s=D(tanθ₂-tanθ₁)

Substitute D=1.90 m, θ₁=11.03 degree, and θ₂=23.14 degree in this equation and solve it.

s=1.90*(tan(23.14)-tan(11.03))

s=1.90*(0.427-0.195)

s=0.441 m

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Electric forces can be explained using fields that extend through space. We can think of these fields as surrounding any charged object. The force acting on a charged particle at a spot may be calculated by knowing the electric field there. This is further explained below.

The electric force is the term used to describe the repulsion or attraction between two charged things. Newton's rules of motion define how a force interacts with a particular body.

In conclusion, Space-spanning fields may be used to explain electric forces. These fields may be thought of as enclosing any charged object. Knowing the electric field at a certain location will allow one to compute the force acting on a charged particle there.

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Answer:

(Choice B, Checked, Correct)   A field helps predict how electric forces will affect any charge at any location in the field.

Explanation:

CORRECT (SELECTED)

A field helps predict how electric forces will affect any charge at any location in the field.

Modeling the electric force as a field can help us understand electric forces. For instance, we know that any charge in an electric field will experience an electric force. We don’t need to measure the force on each charge to know its direction.

The position of the image, if the object moved to new position 20.0 cm from the mirror is 5.7372 cm.

As per the lens equation,

[tex]\frac{1}{p1} +\frac{1}{q1} =\frac{1}{f}[/tex]

Since, p1 is the position of object initially, q1 is the position of the image initially and f is the focal length of the lens.

[tex]\frac{1}{10.4} +\frac{1}{7.8} =\frac{1}{f}[/tex]

[tex]0.0961+0.1282=\frac{1}{f}[/tex]

[tex]f=4.458[/tex] is the focal length of the given lens.

Then the object moved to second position of p2=20.0 cm from the mirror.

So, [tex]\frac{1}{p2} +\frac{1}{q2} =\frac{1}{f}[/tex]

[tex]\frac{1}{20} +\frac{1}{q2} =\frac{1}{4.458}[/tex]

[tex]\frac{1}{q2}=0.2243-\frac{1}{20}[/tex]

[tex]\frac{1}{q2}=0.1743[/tex]

Hence, q2=5.7372 cm is the new position of the image.

Initially, the object placed 10.40 cm from the mirror, then the image formed at 7.80 cm, then the object moved to 20.0 cm from the mirror, then the new image formed at 5.74 cm.

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Effective polymerization of the composite resin is essential to obtain long term clinical success and has a great importance obtaining improved mechanical properties.

The purpose of this study was to measure the effect of the light intensity of LED and QTH curing devices in relation to the light distances, on the hardness (KHN) of two light cure nano-resin composite.

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The direction in which the magnetic force is acting on the charge is upwards.

This is the attraction and repulsion which usually occurs during the motion of electrically charged particles.

In the magnetic field, the charge is moving to the left. Therefore the direction the magnetic force is acting on the charge is upwards which is gotten via right hand rule.

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200 MeV of energy is the energy released per kilogram of fuel used. 
E1/E2=7.61=8 (E1 , E2 are energies)

U is equal to 1 kilogram or 1000 g.
There are 6.02310 23 atoms in one mole, or 235 g, of uranium. Therefore, 6.02310 23 atoms are present in 1000 g of 92/235 U.
It is understood that one atom releases 200 MeV of energy during its fission.

As a result, the energy released from the fission of one kilogram of 92/235 is given by E 2 = 6.02310 23 1000200/235 =5.10610 26 MeV E1/E2=7.61=8

In light of this, the energy released during the fusion of one kilogram of hydrogen is roughly eight times greater than the energy generated during the fission of one kilogram of uranium.

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Answer:

200 MeV of energy is the energy released per kilogram of fuel used.

E1/E2=7.61=8 (E1 , E2 are energies)

U is equal to 1 kilogram or 1000 g.

There are 6.02310 23 atoms in one mole, or 235 g, of uranium. Therefore, 6.02310 23 atoms are present in 1000 g of 92/235 U.

It is understood that one atom releases 200 MeV of energy during its fission.

As a result, the energy released from the fission of one kilogram of 92/235 is given by E 2 = 6.02310 23 1000200/235 =5.10610 26 MeV E1/E2=7.61=8

In light of this, the energy released during the fusion of one kilogram of hydrogen is roughly eight times greater than the energy generated during the fission of one kilogram of uranium.

Combination to prepare tertiary alcohol:

A Grignard reagent interacts first with an ester to produce a ketone, which then undergoes further reactions to produce tertiary alcohol.

Process to form tertiary alcohol:

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The x -component of the object's acceleration is 2 m/s².

Thus, we can conclude that the acceleration along x axis is 2 m/s².

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: The forces in (Figure 1) are acting on a 1.0 kg object. What is ax, the x-component of the object's acceleration?

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Answer:

none

Explanation:

stranger mid mid mid mid

Answer:

My favorite stranger things character is Eleven also known as Millie Bobby Brown

Explanation:

I hope this helps and have a good day!

The diagram shows a simple electric generator. The needle that measures electric current will move back and forth between a largely positive and a large negative value.

because of that she will experience a varying electrical field, and thus a varying electric current will be zero.

The maximum positive value will occur when the wire is perpendicular to the magnetic field lines after one-fourth of rotation, and then zero.

Hence option C is correct.

The diagram shows a simple electric generator. The needle that measures electric current will move back and forth between a largely positive and a large negative value.

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Answer: Two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg. If they are separated by a distance of 1.43 km, then, the magnitude of the force of attraction (in newtons) between the objects will be 52.9kN

Explanation: To find the answer we need to know more about the Newton's law of gravitation.

                        [tex]F=\frac{GMm}{r^2} \\where, G=6.67*10^-11Nm^2kg^-2[/tex]

                      [tex]M=8.22*10^9kg\\m=1.38*10^8 kg\\r=1.43*10^3m[/tex]

               [tex]F=6.67*10^-11*\frac{8.22*10^9*1.38*10^8}{1.43*10^3} =52.9kN[/tex]

Thus, if two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg and, If they are separated by a distance of 1.43 km, then, the magnitude of the force of attraction (in newtons) between the objects will be 52.9kN.

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Given,

V= 73800[tex]m^{3}[/tex]

H= 96.3 m

D= 1000 kg/[tex]m^{3}[/tex]

So, mass m=V*D=73800*1000=738*[tex]10^{5}[/tex] kg

Power= Energy/time= mgH/t = 0.58*(738*[tex]10^{5}[/tex]  *9.81*96.3)/60

=6.74*[tex]10^{8}[/tex] W

So the power output is 6.74*[tex]10^{8}[/tex] Watt.

Power in physics is the quantity of energy transported or converted per unit time. The watt, which is equal to one joule per second in the International System of Units, serves as the unit of power. Power is occasionally referred to as activity in earlier writings. Power has relationships with other factors. For instance, the power required to move a ground vehicle is equal to the product of the traction force on the wheels and the velocity of the vehicle. A motor's output power is calculated by multiplying its torque output by the angle of rotation of its output shaft. Similar to this, the power lost by an electrical component in a circuit is a function of both its voltage and current.

Each minute, 73,800 m3 of water passes over a waterfall 96.3 m high. Assuming that 58.0% of the kinetic energy gained by the water in falling is converted to electrical energy by a hydroelectric generator, calculate the power output of the generator. (The density of water is 1000 kg/m3 .)

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Then the separation between the two pennies will be O.354m.

To find the correct answer, we need to know about the electrostatic force of attraction.

                 [tex]m=3*10^{-3}kg\\n=4*10^{12}\\[/tex]

                 [tex]Q_1=4*10^{12}*1.6*10^{-19}=6.4*10^{-7}C.\\Q_2=-Q_1[/tex]

                    [tex]F_e=\frac{kQ_1Q_2}{r^2} =mg\\[/tex] , here given that the electrostatic force equal to the weight of the system.

                  [tex]r=\sqrt{\frac{kQ_1Q_2}{mg} } =\sqrt{\frac{(6.4*10^{-7})^2}{4*3.14*8.85*10^{-12}*3*10^{-3}*9.8} }\\\\r=0.354m[/tex]

Thus, we can conclude that the separation between the pennies is 0.354m.

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0.354m will be the separation between the two pennies.

We must understand the electrostatic force of attraction in order to arrive at the correct solution.

                  [tex]Q_1=ne=4*10^{12}*1.67*10^{-19}=6.4*10^{-7}C\\Q_2=-Q_1[/tex]

                      [tex]F=\frac{kQ_1Q_2}{R^2}=mg[/tex]

Given that the electrostatic force in this instance is equal to the system's weight.

                    [tex]R=\sqrt{\frac{kQ_1Q_2}{mg} } =0.354m[/tex]

As a result, we may say that the distance between the pennies is 0.354m.

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Normal is the  other half of an action-reaction pair

If a person is sitting on a chair , there must be a gravitation force acting in downward direction which is equal to the weight of that person . That means the person is exerting a force on the chair equal to its weight . But the person is not falling down the chair , because of newtons third law of motion .

There must be a counter force which is equal and opposite to the force exerted by the person on the chair , in order to make net force equal to zero and to make that man in stationary state ( no movement )  .That force is called Normal force which is been acted by the chair on the person .This implies Normal is the  other half of an action-reaction pair

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The particle moves parallel to the field

The particle is at rest.

If the magnetic field is uniform and the magnet dipoles are identical (apart from one being north pole and the other south pole) this two forces cancels out.

A uniform magnetic field is a magnetic field that has the same magnitude and direction throughout the region under consideration, thus the field lines need to be both parallel and spaced out evenly.

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Answer:

Approximately [tex]6.5 \times 10^{3}\; {\rm kJ}[/tex] (or equivalently [tex]6.5 \times 10^{6}\; {\rm J}[/tex]) assuming a melting point of [tex]0\; {\rm ^{\circ} C}[/tex] and a boiling point of [tex]100\; {\rm ^{\circ} C}[/tex].

Explanation:

The total amount of energy required is the sum of five parts:

The specific heat of ice is [tex]c(\text{ice}) = 2.09 \; {\rm kJ \cdot K^{-1} \cdot kg^{-1}}[/tex]. Energy required to raised the temperature of [tex]m = 2.0\; {\rm kg}[/tex] of ice by [tex]\Delta T = (0 - (- 18)) \; {\rm K} = 18\; {\rm K}[/tex]:

[tex]\begin{aligned}Q &= c(\text{ice}) \, m\, \Delta T \approx 75.24\; {\rm kJ} \end{aligned}[/tex].

The enthalpy of fusion (melting) of water is approximately [tex]\Delta H = 334\; {\rm kJ \cdot kg^{-1}}[/tex]. The energy required to melt [tex]m = 2.0\; {\rm kg}[/tex] of ice would be:

[tex]Q = m\, \Delta H \approx 668\; {\rm kJ}[/tex].

The specific heat of water is [tex]c(\text{water}) =4.18 \; {\rm kJ \cdot K^{-1} \cdot kg^{-1}}[/tex]. Energy required to raised the temperature of [tex]m = 2.0\; {\rm kg}[/tex] of water by [tex]\Delta T = (100 - 0) \; {\rm K} = 100\; {\rm K}[/tex]:

[tex]\begin{aligned}Q &= c(\text{water}) \, m\, \Delta T \approx836\; {\rm kJ} \end{aligned}[/tex].

The enthalpy of vaporization of water is approximately [tex]\Delta H = 2257\; {\rm kJ \cdot kg^{-1}}[/tex]. The energy required to vaporize [tex]m = 2.0\; {\rm kg}[/tex] of water would be:

[tex]Q = m\, \Delta H \approx 4.51 \times 10^{3}\; {\rm kJ}[/tex].

The specific heat of steam is [tex]c(\text{water}) =2.09\; {\rm kJ \cdot K^{-1} \cdot kg^{-1}}[/tex]. Energy required to raised the temperature of [tex]m = 2.0\; {\rm kg}[/tex] of steam by [tex]\Delta T = (220 - 100) \; {\rm K} = 120\; {\rm K}[/tex]:

[tex]\begin{aligned}Q &= c(\text{steam}) \, m\, \Delta T \approx 920\; {\rm kJ} \end{aligned}[/tex].

Hence, the total amount of energy required is approximately [tex]6.5 \times 10^{3}\; {\rm kJ}[/tex].

To produce a maximum emf of 1.0 V, the angular speed should rotate at 35.368 rad/s.

A uniform magnetic field is depicted by parallel straight lines that are distributed uniformly. The flux path is the same as the path of a tiny magnet's north-seeking pole. The flux channels are continuous, producing closed loops.

For a single loop of wire with a radius of 7.5 cm that rotates about a diameter in a uniform magnetic field of 1.6T. We need to determine the angular speed of rotation for it to produce a maximum electromotive force (emf) of 1.0 V.

Given that:

The radius = 7.5 cm, to convert it to meters, we will divide it by 100.

= (7.5/100) m

= 0.075 m

The area A of the wire is computed by using the formula:

A = πr²

A = π(0.075)²

A = 0.01767 m²

Imagine a coil with N turns with area A rotating at a constant angular velocity (q) inside a flux density of a (B) of a magnetic field, with its axis parallel to the field.

The maximum e.m.f can be computed by using the formula:

[tex]\mathbf{E_o = BAN \omega}[/tex]

Where;

Making the angular speed (ω) the subject of the formula, we have:

[tex]\mathbf{\omega =\dfrac{E}{BNA}}[/tex]

ω = 35.368 rad/s

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Spring scale or a spring balance is a type of measuring device that is used to measure the weight of the object.

Spring scale can be defined as:

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