Answer:
13%
Step-by-step explanation:
780 interest/18 months=43.33 interest/month
43.33x12=520 interest/year
principal x interest rate = interest per year
4000 x interest rate =520
interest rate =520/4000
interest rate =.13 or 13%
What is the range of the given function?
{(–2, 0), (–4, –3), (2, –9), (0, 5), (–5, 7)}
A {x | x = –5, –4, –2, 0, 2}
B {y | y = –9, –3, 0, 5, 7}
C {x | x = –9, –5, –4, –3, –2, 0, 2, 5, 7}
D {y | y = –9, –5, –4, –3, –2, 0, 2, 5, 7}
[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]
[tex]\huge\underline{\sf{\red{Problem:}}}[/tex]
What is the range of the given function?(–2, 0), (–4, –3), (2, –9), (0, 5), (–5, 7)[tex]\huge\underline{\sf{\red{Choices:}}}[/tex]
A {x | x = –5, –4, –2, 0, 2}B {y | y = –9, –3, 0, 5, 7}C {x | x = –9,–5,–4,–3,–2,0,2,5,7}D {y | y = –9,–5,–4,–3,–2,0,2,5,7}[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]
[tex] \quad \quad \underline{ \boxed{\sf{ \red{ B.)\: {y | y = –9, –3, 0, 5, 7} }} }}[/tex]
What is range of a function?The range of a function is the complete set of all possible resulting values of the dependent variable (y, usually), after we have substituted the domain.The definition means:The range is the resulting y-values we get after substituting all the possible x-values.How to find the range?The range of a function is the spread of possible y-values (minimum y-value to maximum y-value)Substitute different x-values into the expression for y to see what is happening. (Ask yourself: Is y always positive? Always negative? Or maybe not equal to certain values?)Make sure you look for minimum and maximum values of y.[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]
#CarryOnLearning
[tex]\sf{\red{✍︎ C.Rose❀}}[/tex]
A number x cubed is six
Answer:
x = 1.817
Step-by-step explanation:
[tex]x^3 = 6\\\sqrt[3]{x} = \sqrt[3]{6} \\x = 1.817[/tex]
Please solve with explanation.
Answer:
Area = 160 cm²
Perimeter = 55.31 cm
Step-by-step explanation:
Applying,
Area of the figure = area of the rectangle- area of the triangle
A = lw+bh/2............... Equation 1
From the question,
Given: l = 16 cm, w = 12 cm, h = 8cm, b = 8 cm
Substitute these values into equation 1
A = (16×12)-(8×8/2)
A = 192-32
A = 160 cm²
Perimeter P = /BC/+/CD/+/DE/+/EF/+/FG/+/GA/
Applying pythagoras theorem to get /FG/
FG² = GE²+EF²
FG² = 8²+8²
FG² = 64+64
FG² = 128
FG = √128
FG = 11.31 cm
Therefore,
P = 16+12+4+8+11.31+4
P = 55.31 cm
TRUE or FALSE?
1.) If x = -3, then the value of 4x + 5 is 17.
Answer:
true
Step-by-step explanation:
[tex]dahil \: alam \: ko \: \: masagutan \: ko \: mayn[/tex]
Please help me out this is hard .
Answer:
24.6
Step-by-step explanation:
take 72 degree as reference angle
using tan rule
tan 72 = opposite / adjacent
3.07 = x/8
3.07 * 8 = x
24.56 = x
24.6 = x
Hey I need help with this new concept. Could someone help me out? I would prefer an explanation for one of the shapes if possible. Thanks!
Answer:
Step-by-step explanation:
set the equation for the area equal to the equation of the perimeter.
Then solve for x
-----------------------------
Figure a
area = perimeter
3x = 2(x + 3)
Distribute
3x = 2x + 6
subtract 2x from both sides
x = 6
perimeter
p = 2(x + 6)
p = 2(3 + 63)
p = 18
Area
a = 3x
a = 3*6
a = 18
----------------------------
Use the same method on the remaining figures
Can someone please answer these 2 questions
Answer:
part 1: $532.95. Part 2: 16
Step-by-step explanation:
Part 1: 15 * 15.35 = 230.25
30 * 10.09 = 302.70
230.25 + 302.70 = $532.95
Part 2: R = letters in the word desk
there are 4 letters in the word Desk
[tex]2^{R}[/tex] = [tex]2^{4}[/tex] = 2 * 2 * 2 * 2 = 4 * 4 = 16 subsets
Question 24 of 25 The graph of F(x) shown below resembles the graph of G(X) = x2, but it has been changed somewhat. Which of the following could be the equation of F(x)? G(X) = x2 Fx) = ?
Answer:
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!;;;;!!!!!!!!!!!
The required equation of graph f(x) is y = -x²-3.
What is parabola?A parabola is a U-shaped plane curve where any point is at an equal distance from a fixed point (known as the focus) and from a fixed straight line which is known as the directrix.
here, we have,
Given that,
The graph of f(x), resembles the graph of G(x) =x^2 .
We have to find,
Which of the following could be the equation of f(x).
According to the question,
Function, G(X) = x^2 ,
The graph in the given question figure. It is a parabola with vertex at (0,0).
By the graph predict that Sign of x^2 is positive, that is why the parabola opens up.
General equation of parabola is given by,
y = a(x-h)^2 + k
Where, a = 1, and vertex (h, k) is (0,0).
The graph of F(x) unknown function opens down ,
Sign of x^2 as negative. and the vertex is at (0,-3)
To find the equation of function f(x),
Putting the values of a and vertex coordinates,
y = a(x-h)^2 + k
The equation of parabola become:
y = -x²-3.
(solving we get)
Hence, The required equation of f(x) is y = -x²-3.
For more information about Parabola click the link given below.
brainly.com/question/4074088
#SPJ7
Can someone explain to me how this is wrong at all? I did the math like 10 times and somehow its wrong...? please lmk what the actual answer is because apparently im just incompetent
Also giving Brainliest
Answer:
total= 98
Step-by-step explanation:
so the way to do this is to find the total surface area of the white bench and then subtract the interfacing portion for the support, and then total surface area of support and also subract the area of the interface with the white as well as the ground
bench top area
area of long side *number of sides + area of end *number of ends
(9*2)*4+(2*2)*2= 72+8=80
interface area is area of long side of red portion
5*2=10
support area is same as bench top for rationale
(5*2)*4+(2*2)=40+8=44
total surface area = area of white + area of red - 2* interface area - bottom of red that interfaces with the ground
total = 80+48-2*10-(5*2)
total = 128-20-10
total= 98
Answer the questions for BRAINLIEST (EASY)
A.
B.
C.
Answer:
A=x-3
B=X-14
C=X-10
In triangle ABC, AB = 11 cm, BC = 9 cm and CA = 10 cm.
Find the area of triangle ABC.
Answer:
Area = 42.43 square cm
Step-by-step explanation:
Using Heron's Formula :
[tex]Area = \sqrt{s\times (s-a) \times (s-b) \times(s -c)} \ , \ where \ s \ =\ \frac{a+ b+ c}{2}[/tex]
Find Area :
[tex]s = \frac{11 + 9 + 10 }{2} = \frac{30}{2} = 15[/tex]
[tex]Area = \sqrt{15 \times ( 15 - 11 ) \times { (15 - 9 ) \times ( 15 -10)}\\\\[/tex]
[tex]= \sqrt{15 \times 4 \times 6 \times 5}\\\\=\sqrt{1800}[/tex]
[tex]= 42 . 43 \ cm^2[/tex]
Can someone answer this plz
Answer:
[tex]A^{I}[/tex]= (7, -1)
Step-by-step explanation:
Rotation is a method of rigid transformation in which a point is moved about a reference point through a stated angle. The rotation could be clockwise or counterclockwise so as to produce the image of the initial object.
In the polar coordinate given, the coordinate of A is given as;
A = (3, 3)
On rotating point A about point C counterclockwise for [tex]270^{o}[/tex], an image [tex]A^{I}[/tex] would be produced.
But [tex]A^{I}[/tex] would have a coordinate;
[tex]A^{I}[/tex]= (7, -1)
The image of A produced is [tex]A^{I}[/tex] (7, -1).
Question 2 Multiple Choice Worth 5 points)
(02.04 LC)
Determine the equation of the line shown in the graph
Answer choices
X= 5
y = 0
x = 0
y = 5
Answer:
A
Step-by-step explanation:
The line is parallel to y axis, so the equation is x = 5
How many miles did it cruise?
Answer:
A. 120
Step-by-step explanation:
600÷60=10
10×12=120
Hope this helps! :)
Instructions: Using the image, find the distance between the points given on the graph.
The length of the rectangle, in feet, is represented by (5x + 4). Find the perimeter of the rectangle.
Please help I’ll give brainllist
Answer:
TRUE
Step-by-step explanation:
TRUEAnswer:
true i think
Step-by-step explanation:
If triangle LMN ~ triangle PON, what is MN?
Answer:
pretty sure its 40cm
Step-by-step explanation:
hope this helps :)
Answer:
36cm
Step-by-step explanation:
Tan(14/12)=angle of ONP
Tan(42/X)=angle of LNM
singe those angels are the same;
Tan(14/12)=Tan(42/X)
14/12=42/X
14*X=42*12
X=(42*12)/14
X=36
This is the last question from my hw
Answer:
m = 9, n = 2
Step-by-step explanation:
Find [tex]f^{-1}[/tex] (x) by letting y = f(x) and rearranging making x the subject, that is
y = mx + n ( subtract n from both sides )
y - n = mx ( divide both sides by m )
[tex]\frac{y-n}{m}[/tex] = x
Change y back into terms of x with x = [tex]f^{-1}[/tex] (x) , then
[tex]f^{-1}[/tex] (x) = [tex]\frac{x-n}{m}[/tex]
Given [tex]f^{-1}[/tex] (x) = g(x) , then
[tex]\frac{x-n}{m}[/tex] = [tex]\frac{x-2}{9}[/tex]
By comparison of the 2 sides
m = 9 and n = 2
In the diagram AB is parallel to CD. Calculate the value of A ?
The image of the diagram is missing, so i have attached it.
Answer:
a = 30°
Step-by-step explanation:
From the diagram attached, we can see that the 2 angles a and 5a are interior supplementary angles.
The sum of interior supplementary angles is 180°
Thus;
5a + a = 180
6a = 180
a = 180/6
a = 30°
a trader sold an article at 10% profit if he had sold it at 10% loss,it would yield RS 140 less than the previous selling price.find the cost price of the article.
Answer:
CP = ₹ 700
Step-by-step explanation:
Let the cost price be 'x'
SP = [tex](\frac{100+Profit}{100})*CP[/tex]
[tex]= \frac{100+10}{100}*x\\\\=\frac{110}{100}*x\\\\= \frac{11}{10}x[/tex]
If it had been sold are 10% loss, then
SP = [tex](\frac{100-loss}{100})*CP[/tex]
[tex]=\frac{100-10}{100}*x\\\\=\frac{90}{100}*x\\\\=\frac{9}{10}x[/tex]
Difference in both the selling price = 140
[tex]\frac{11}{10}x-\frac{9}{10}x=140\\\\\\\frac{2}{10}x=140\\\\\frac{1}{5}x=140\\\\ x = 140*5\\x = 700[/tex]
what is the domain of the function represented by the graph
Answer:
Domain: all real numbers
Step-by-step explanation:
The domain is the values that x can take
X can be any real number
Domain: all real numbers
Write and solve a real-world problem that involves finding the volume of a rectangular or triangular prism
Answer:
l
Step-by-step explanation:
Davis's Snacks will make 8,412 ounces of corn chips next year. The company plans to put the chips into 4-ounce bags. How many bags will the company be able to fill next year?
Answer:
2103 bags
Step-by-step explanation:
8412/4=2103
Write the equation of the line that passes through points A(6,1) and B(9,4)? simple answers
Given:
Two points are A(6,1) and B(9,4).
To find:
The equation of the line that passes through the given points.
Solution:
If a line passes through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex], then the equation of the line is:
[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
It is given that the line passes through the two points A(6,1) and B(9,4). So, the equation of the line is:
[tex]y-1=\dfrac{4-1}{9-6}(x-6)[/tex]
[tex]y-1=\dfrac{3}{3}(x-6)[/tex]
[tex]y-1=1(x-6)[/tex]
[tex]y-1=x-6[/tex]
Adding 1 on both sides, we get
[tex]y-1+1=x-6+1[/tex]
[tex]y=x-5[/tex]
Therefore, the equation of the line is [tex]y=x-5[/tex].
okay so, hey my name is natalie. i don't have my phone and id love to communicate with any of yall, feel free to take some points and introduce your self. :)
Solve the following inequality for qq. Write your answer in simplest form. -6q+7≤8q-3
Answer:
q ≥ 5/7
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightEquality Properties
Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of EqualityAlgebra I
Terms/CoefficientsStep-by-step explanation:
Step 1: Define
Identify
-6q + 7 ≤ 8q - 3
Step 2: Solve for q
[Subtraction Property of Equality] Subtract 8q on both sides: -14q + 7 ≤ -3[Subtraction Property of Equality] Subtract 7 on both sides: -14q ≤ -10[Division Property of Equality] Divide -14 on both sides: q ≥ 5/7Here we see that any number q greater than or equal to 5/7 would work as a solution to the inequality.
Answer:
q ≥ [tex]\frac{5}{7}[/tex]
Step-by-step explanation:
Given
- 6q + 7 ≤ 8q - 3 ( add 6q to both sides )
7 ≤ 14q - 3 ( add 3 to both sides )
10 ≤ 14q ( divide both sides by 2 )
5 ≤ 7q ( divide both sides by 7 )
[tex]\frac{5}{7}[/tex] ≤ q , then
q ≥ [tex]\frac{5}{7}[/tex]
In the diagram below, ΔABC≅ΔSTR. Complete the statement ∠A≅
A. ∠C
B. ∠S
C. ∠T
D. ∠R
Answer:
b
Step-by-step explanation:
Answer: B <S
Step-by-step explanation:
Please help i dont remember how to do this
Complete the proof that
Answer:
The two column proof is presented as follows;
Statement [tex]{}[/tex] Reason
ΔSCW ≅ ΔTUW [tex]{}[/tex] Given
[tex]\overline {SV}[/tex] ≅ [tex]\overline {TU}[/tex] [tex]{}[/tex] CPCTC
[tex]\overline {SW}[/tex] ≅ [tex]\overline {TW}[/tex] [tex]{}[/tex] CPCTC
[tex]\overline {WV}[/tex] ≅ [tex]\overline {UW}[/tex] [tex]{}[/tex] CPCTC
∠SVW ≅ ∠TUW [tex]{}[/tex] CPCTC
SU = SW + UV [tex]{}[/tex] Additive property of Length
TU = TW + VW [tex]{}[/tex] Additive property of Length
SU = TW + VW [tex]{}[/tex] Substitution
SU = TV [tex]{}[/tex] [tex]{}[/tex] Transitive property
ΔSTV ≅ ΔTSU [tex]{}[/tex] SAS
∠TSV ≅ ∠STU [tex]{}[/tex] CPCTC
Step-by-step explanation:
The two column proof is presented as follows;
Statement [tex]{}[/tex] Reason
ΔSCW ≅ ΔTUW [tex]{}[/tex] Given
[tex]\overline {SV}[/tex] ≅ [tex]\overline {TU}[/tex] [tex]{}[/tex] Congruent Parts of Congruent Triangles are Congruent
[tex]\overline {SW}[/tex] ≅ [tex]\overline {TW}[/tex] [tex]{}[/tex] Congruent Parts of Congruent Triangles are Congruent
[tex]\overline {UV}[/tex] ≅ [tex]\overline {VW}[/tex] [tex]{}[/tex] Congruent Parts of Congruent Triangles are Congruent
∠SVW ≅ ∠TUW [tex]{}[/tex]Congruent Parts of Congruent Triangles are Congruent
SU = SW + UV [tex]{}[/tex] Additive property of Length
TU = TW + VW [tex]{}[/tex] Additive property of Length
SU = TW + VW [tex]{}[/tex] Substitution
SU = TV [tex]{}[/tex] Transitive property
ΔSTV ≅ ΔTSU [tex]{}[/tex] Side-Angle-Side rule of congruency
∠TSV ≅ ∠STU [tex]{}[/tex] Congruent Parts of Congruent Triangles are Congruent