At equilibrium the reactant and product concentrations are constant because a change in one direction is balanced by a change in the other as the forward and reverse rates become equal: (MTS 5/5/2018) When a chemical system is at equilibrium, Group of answer choices the concentrations of the reactants and products have reached constant values. the concentrations of the reactants are equal to the concentrations of the products. the forward and reverse reactions have stopped. the reaction quotient, Q, has reached a maximum. None of the choices.

Answers

Answer 1

Answer:

concentrations of the reactants and products have reached constant values

Explanation:

When a reaction is carried out in a closed system, it attains dynamic equilibrium after sometime. We define dynamic equilibrium as a situation in which the forward and reverse reactions proceed at the same rate.

When this occurs, the concentration of the reactants and products remain fairly constant. Hence the answer.


Related Questions

If silicon has a charge of +4 and oxygen has a charge of -2, what is the total charge on this structure?

Answers

Answer:

Zero with the subscripts, +2 without them.

Explanation:

Hello!

In this case, since we consider that two silicon are bonded with four oxygen atoms to form silicon oxide according to the following chemical equation:

[tex]Si^{4+}+O^{2-}\rightarrow Si_2O_4[/tex]

It is also possible to realize it can be simplified to obtain:

[tex]SiO_2[/tex]

Which means that the total charge with the subscripts is zero, and without the subscripts +2 (+4-2).

Best regards!

A fuel tank holds 22.3 gallons of gasoline. If the density is 0.8206 g/mL, what is the mass in kilograms of gasoline in a full tank

Answers

Answer:

[tex]m=69.3kg[/tex]

Explanation:

Hello!

In this case, since the density is computed by dividing the mass of the substance by its occupied volume (d=m/V), we first need to realize that 0.8206 g/mL is the same to 0.8206 kg/L, which means we first need to compute the volume in L:

[tex]V=22.3gal*\frac{3.78541L}{1gal}=84.415L[/tex]

Then, solving for the mass in d=m/V, we get m=d*V and therefore the mass of gasoline in that full tank turns out:

[tex]m=0.8206g/L*84.415L\\\\m=69.3kg[/tex]

Best regards!

Consider 55 mL of water (H2O) in a beaker and 55 mL of acetone [(CH3)2CO] in an identical beaker under identical conditions. Complete the sentences to explain the relationship between the vapor pressure of water and acetone.

Answers

Answer:

More slowly than

Larger than

Weaker

Explanation:

The vapor pressure of a solution describes how quickly a solution will turn into vapour. If we say that a solution has a high vapour pressure, we are actually saying that the solution turns into vapour more quickly.

Acetone has a higher vapour pressure than water so acetone turns to vapour quicker than water.

Vapour pressure has a lot to do with the magnitude of intermolecular forces in solution. The stronger the magnitude of intermolecular forces, the lower the vapor pressure and the more slowly the solution evapourates.

So, the hydrogen bonds in water provides stronger intermolecular forces than dispersion and dipole interaction in acetone. Hence, water vaporizes more slowly than acetone.

You are given 100 mL of of a KOH solution with pH of 12.0. You are required to change the pH to 11.0 by adding water. How much water will you add

Answers

Answer:

We need to add 900 mL of water.

Explanation:

To know the amount of water to add first we need to calculate the concentration of KOH when the pH is 12 and when is 11:

[tex] 14 = pH + pOH [/tex]

[tex] pOH = -log[OH] [/tex]

[tex] OH = 10^{-pOH} [/tex]

When pH = 12 (initial):

[tex]pOH_{i} = 14 - 12 = 2[/tex]

[tex]OH_{i} = 10^{-2}=0.01 M[/tex]

When pH = 11 (final):

[tex]pOH_{f} = 14 - 11 = 3[/tex]

[tex]OH_{f} = 10^{-3} = 0.001 M[/tex]

Now, by using the following equation we can find the volume of the solution to achieve a pH = 11:

[tex]C_{i}V_{i} = C_{f}V_{f}[/tex]

[tex]V_{f} = \frac{C_{i}V_{i}}{C_{f}} = \frac{0.01 M*100 mL}{0.001 M} = 1000 mL[/tex]

Finally, to bring 100 mL of the initial solution to 1000 mL we need to add the following amount of water:

[tex]1000 mL = V_{KOH} + V_{H_{2}O}[/tex]

[tex] V_{H_{2}O} = 1000 mL - V_{KOH} [/tex]

[tex] V_{H_{2}O} = 1000 mL - 100 mL = 900 mL [/tex]

Therefore, we need to add 900 mL of water.

I hope it helps you!            

The amount of water that needs to be added will be 900 mL

What will be the amount of water needed?

For finding the amount of water added we have to calculate the concentration of KOH at pH=12 and pH=11

[tex]14=pH+_pOH[/tex]

[tex]_pOH=-Log[OH][/tex]

[tex]OH=10^{-_pOH}[/tex]

[tex]_pOH_f=14-11=3[/tex]

When pH = 12 (initial):

[tex]_pOH_i=14-12=2[/tex]

[tex]_pOH_i=10^{-2}=0.01[/tex]

When pH = 11 (final):

[tex]_pOH_i=10^{-2}=0.01[/tex]

[tex]_pOH_f=14-11=3[/tex]

Now, by using the following equation we can find the volume of the solution to achieve a pH = 11:

[tex]C_iV_i=C_fV_f[/tex]

[tex]V_f=\dfrac{C_iV_I}{C_f} =\dfrac{0.01\times100}{0.001} =1000\ mL[/tex]

Finally, to bring 100 mL of the initial solution to 1000 mL we need to add the following amount of water:

[tex]1000=V_{KOH}+V_{H_2O}[/tex]

[tex]V_{H_2O}=1000mL-V_{KOH}[/tex]

[tex]V_{H_2O}=1000-100=900mL[/tex]

Thus the amount of water that needs to be added will be 900 mL

To know more about PH-Scale follow

https://brainly.com/question/940314

Uranium-238 undergoes radioactive decay according to the incomplete below. 238
92
U= 4
2 He + X.
What is the decay product represented by X?


Answers

The decay product represented by X : Thorium (Th) : ²³⁴₉₀Th

Further explanation

Given

Decay reaction

²³⁸₉₂U ⇒ ⁴₂He + X

Required

The decay product

Solution

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

alpha α particles ₂He⁴ beta β ₋₁e⁰ particles gamma particles ₀γ⁰ positron particles ₁e⁰ neutron ₀n¹

In a decay reaction, the sum of the mass number and atomic number of the elements in the reactants and products must be the same

So the mass number of the element X = 238 - 4 = 234

Atomic number of the element X = 92 - 2 = 90

If we look at the periodic system, then the element with atomic number 90 is Thorium (Th)

Cells are the basic unit of life true or false

Answers

true ! search it up on safari and it tells you that it’s true

Under certain conditions, the substance ammonium chloride can be broken down to form ammonia and hydrogen chloride. If 29.4 grams of ammonium chloride react to form 9.4 grams of ammonia, how many grams of hydrogen chloride must simultaneously be formed

Answers

Answer: 20.0 g of hydrogen chloride must simultaneously be formed

Explanation:

The balanced chemical reaction is :

[tex]NH_4Cl\rightarrow NH_3+HCl[/tex]

According to the law of conservation of mass, mass can neither be created nor be destroyed. The mass on reactant side must be equal to the mass on product side.

Thus mass of reactants = mass of products

Given : mass of ammonium chloride = mass of reactants = 29.4 g

mass of ammonia = 9.4 g

mass of products = mass of ammonia + mass of hydrogen chloride

9.4 g +mass of hydrogen chloride = 29.4 g

mass of hydrogen chloride = 20.0 g

How many molecules are in 50.0 grams of NaOH?

Answers

Answer:

7.53 × 10²³ molecules NaOH

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

Reading a Periodic TableUsing Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Explanation:

Step 1: Define

50.0 g NaOH

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of Na - 22.99 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of NaOH - 22.99 + 16.00 + 1.01 = 40 g/mol

Step 3: Convert

Set up:                              [tex]\displaystyle 50.0 \ g \ NaOH(\frac{1 \ mol NaOH}{40 \ g \ NaOH})(\frac{6.022 \cdot 10^{23} \ molecules \ NaOH}{1 \ mol \ NaOH})[/tex]Multiply:                                                                                                           [tex]\displaystyle 7.5275 \cdot 10^{23} \ molecules \ NaOH[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

7.5275 × 10²³ molecules NaOH ≈ 7.53 × 10²³ molecules NaOH

1: draw the structural formula for N2 + 3H2 → 2NH3

2: draw the structural formula for 2CO2 + 3H2O → C2H5OH+ 3O2
]down below is a picture with more accurate depiction of the questions plz answer both

Answers

Answer:

Hey..! I know only 1st one answer

20g of water at 30°C was mixed with 40g of water at 75°C. What is
the final temperature of the mixture? (specific heat capacity of water
is 4.184 J/g°C).​

Answers

Answer:

The temperature of the mixture is 60°C

Explanation:

We can write the energy of water as follows:

E = m×C×T

Where E is energy in Joules, m is mass of water, C is specific heat of water = 4.184J/g°C and T is temperature

Replacing fot both samples:

E = 20g×4.184J/g°C×30°C

E = 2510.4J

E = 40g×4.184J/g°C×75°C

E = 12552J

The total energy of the mixture is 12552J + 2510.4J = 15062.4J

Mass = 60g:

15062.4J = 60g×4.184J/g°C×T

60°C = T

The temperature of the mixture is 60°C

PLZZZ help asaap plz its 50 points plzzzz Calculate for the formula mass (for ionic compounds) and molecular mass (for covalent compounds):
Mg3 (AlO3)2



(NH4)2 C2O4




Al 4 ( Fe (CN)6)3

Answers

hope it helps

mark me brainliest

Many children are uncomfortable around white lab coats. Specifically explain why this occurs in what a doctor or dentist could do to counteract this reaction and still wear a white lab coat

Answers

Answer:

Sanitize

Explanation:

What is the relationship between particle collisions and reaction rates?

Answers

Answer:

Collision theory states that the rate of a chemical reaction is proportional to the number of collisions between reactant molecules. The more often reactant molecules collide, the more often they react with one another, and the faster the reaction rate.

Consider a 75.0-g sample of H2O(g) at 1258C. What phase or phases are present when 215 kJ of energy is removed from this sample

Answers

Answer:

Explanation:

The first process is to draw out the heating curve to have a look at the transition possible which we've shown in the file below.

Now;

To find the energy removed to convert 75g steam → ice then comparing it with 215 kJ.

So conversion of steam at 125 °C → 100 °C

[tex]\Delta H = (75 \ g) (2.0 \ J/g^0C ) (125 - 100)^0 \ C[/tex]

[tex]\Delta H = 3750 \ J[/tex]

[tex]\Delta H = 3.75 \ kJ[/tex]

Since this is lesser than the energy given  (215 kJ), we then have to find the energy removed in the next phase.

For condensation of steam

Find the energy removed to change the steam from 100° C to liquid  at 100° C

[tex]\Delta H_2 = ( \dfrac{75 \ g}{18.02 \ g/mol}) (40.7 \ kJ/mol)[/tex]

[tex]\Delta H_2 =1.690* 10^ 2 \ J[/tex]

[tex]\Delta H_2 =169 \ kJ[/tex]

The total energy that is now removed from the system is:

[tex]\Delta H_1+ \Delta H_2 = (169 + 3.75) \ kJ[/tex]

[tex]\Delta H_1+ \Delta H_2 \simeq 173 \ kJ[/tex] which is still lesser than 215 kJ

To the third step; which is the conversion of water at 100° C → water at 0° C

[tex]\Delta H_3 = ( 75 \ g) (4.2 \ J/g^0 C)(100-0)^0C[/tex]

[tex]\Delta H_3 = 31500 \ J[/tex]

[tex]\Delta H_3 = 31.5 \ kJ[/tex]

Thus;

[tex]\Delta H_1+\Delta H_2+\Delta H_3 = (169 + 3.75 +31.5) \ kJ[/tex]

[tex]\Delta H_1+\Delta H_2+\Delta H_3 =204 \ kJ[/tex]

To the fourth step;

For freezing of water; we need to find the energy removed to change the water at 0° C → ice at 0° C

[tex]\Delta H_4 = (\dfrac{75 \ g}{18.02 \ g/mol})(6.02 \ kJ/mol)[/tex]

[tex]\Delta H_4 = 25.1 \ kJ[/tex]

To change to the solid phase at 0° C; the total energy that is being removed from the steam is  

[tex]\Delta H_1+\Delta H_2+\Delta H_3 +\Delta H_4 =(169 + 3.75 + 31.5 +25.1) \ kJ[/tex]

[tex]\Delta H_1+\Delta H_2+\Delta H_3 +\Delta H_4 =229 \ kJ[/tex]

Here, the calculated total energy is more than the given energy 215 kJ.

This implies that the water is not fully converted to ice when 215 kJ of energy removal occurs, Hence the two phases that exist are liquid and solid.

What would be the mass of 9.03 x 1021 molecules of hydrobromic acid?

Answers

Answer:

[tex]1.214\ g[/tex]

Explanation:

[tex]We\ know\ that,\\No.\ of\ molecules\ of\ Hydrobromic\ acid=9.03*10^{21} HBr\ molecules\\Now,\\We\ know\ that\ Hydrobromic\ acid\ is\ constituted\ by\ 1\ Hydrogen\ molecule\\ and\ 1\ Bromine\ molecule.\\Gram\ Atomic\ Mass\ of\ Bromine \approx 80\ g\\Gram\ Atomic\ Mass\ of\ Hydrogen =1\ g\\Hence,\\The\ Gram\ Molecular\ Mass\ Of\ Hydrobromic\ Acid=1*1+1*80=81\ g\\Avagadro's\ Constant=6.022*10^{23}\ particles[/tex]

[tex]Now,\\We\ know\ that,\\Mass=\frac{No.\ of\ particles}{Avagadro's\ Constant}*GMM\\Here,\\Mass\ of\ 9.03*10^{21} molecules\ of\ HBr= \frac{9.03*10^{21}}{6.022*10^{23}}*81 \approx 1.214\ g[/tex]

How do we determine the central atom in a chemical bond? How information is need to determine the shape that results in the bonded atoms of the molecule? ​

Answers

Answer:

- the central atom is usually the atom with the lowest subscript in the molecular formula and the atom that can form the most bonds. If all of the atoms usually form the same number of bonds, the least electronegative atom is usually the central atom.

- molecular shape (the shape that a single molecule has) is important in determining how the molecule interacts and reacts with other molecules. Molecular shape also influences the boiling point and melting point of molecules. If all molecules were linear then life as we know it would not exist.

Calculate the final pH of a solution made by the addition of 10 mL of a 0.5 M NaOH solution to 500 mL of a 0.4 M HA originally at pH

Answers

This question is not complete, the complete question is;

Calculate the final pH of a solution made by the addition of 10 mL of a 0.5 M NaOH solution to 500 mL of a 0.4 M HA originally at pH  = 5.0 ( pKa = 5.0)

Neglect the volume change.

Options:

a) 6.10

b) 5.09

c) 7.00

d) 5.02

Answer:

the final pH of a solution is 5.02

Option d) 5.02 is the Correct Answer

Explanation:

Given the data in the question,

Initially pKa = pH; so ratio is 1:1

thus, 0.4 M acid and base

Now, moles of NaOH = molarity × volume = 0.5 × 10 = 5 mmol = 5 × 10⁻³ mol.

Going into 500 mL ( 0.5 L ) of solution

new molarity will be;

⇒ moles / volume = 5 × 10⁻³ / 0.5 = 0.01 M

ACID reacting with BASE

original concentration of acid = 0.4 - 0.01 = 0.39 M

original concentration of base = 0.4 + 0.01 = 0.41 M

so

pH = 5 + log( base/acid)

= 5 + log ( 0.41/0.39)

= 5 + log ( 1.0512)

= 5 + 0.021

pH = 5.02

Therefore the final pH of a solution is 5.02

Option d) 5.02 is the Correct Answer

Please help if you know please and thanks ;)

Answers

Answer:

it takes two hydrogen atoms for every oxygen atom to produce this reaction, so the mole ratio between hydrogen and oxygen is 2:1

Which branch of chemistry would be used to make steel?

Answers

Answer:

the five major branches of chemistry are organic, inorganic, analytical, physical, and biochemistry.

Air will expand about the same amount as propane with the same change in temperature over ordinary temperature ranges.

Answers

Answer:

Yes this is true

Explanation:

Answer:

i have the same question for chemistry, do you have the answer?

Explanation:

What is the molar mass for Ca(C2H3O2)2?

A. 71g B. 99g C. 158g D. 148g

Answers

The molar mass of Ca(C2H3O2)2 would be 158g

40.078+(12.0107*2 + 1.00794*2 + 15.9994*2)*2

please help !!!

What law states that matter can never be created or destroyed?
A. The law of gravity
B. The law of constant phases
C. The law of conservation of matter
D. The atomic theory

Answers

Answer:

C) The law of conservation of matter

Explanation:

Conservation means keeping/ retaining something, in this case it is matter. Hope this helps!


C. The law of conservation of mass/matter

What is the mass of two moles of the diatomic gas, Nz?

Answers

Answer:

56.04 g

Explanation:

Step 1: Given data

Moles of nitrogen (n): 2 mol

Step 2: Calculate the molar mass of nitrogen (M)

The molar mass of the molecule is the sum of the masses of the molecules that form it.

mN₂ = 2 × mN = 2 × 14.01 g/mol = 28.02 g/mol

Step 3: Calculate the mass corresponding to 2 moles of nitrogen

We will use the following expression.

m = n × M

m = 2 mol × 28.02 g/mol = 56.04 g

Investigate: Note the empty jars on the shelf that can be filled by using the slider. Set the amount to 2.000 moles of carbon (mol C), then press Start. Each jar holds exactly one mole of carbon. Your goal is to determine the mass in grams of two moles of carbon. Before you can find the mass, what do you need to know

Answers

Answer:

The molar mass of carbon

Explanation:

Before the mass (in grams) of two moles of carbon can be determined, the molar mass of the element would be needed.

This is because the number of mole of an element is the ratio of its mass and the molar mass. That is,

number of mole = mass/molar mass

Hence, the mass of elements can be obtained by making it the subject of the formular;

mass = number of mole x molar mass

Therefore, the molar mass of carbon would be needed before the mass of 2 moles of the element can be determined.

Name of this compound:
S3P2

Answers

Answer:

sodium phosphide

Explanation:

50 POINTS PLEASE NO FAKE ANSWERS I REALLY NEED THESE ANSWERED

1. The following reaction shows calcium chloride reacting with silver nitrate.

CaCl2 + 2AgNO3 → 2AgCl + Ca(NO3)2

How many grams of AgCl are produced from 30.0 grams of CaCl2?

(Molar mass of Ca = 40.078 g/mol, Cl = 35.453 g/mol, O = 15.999 g/mol, Ag = 107.868 g/mol, N = 14.007 g/mol)

19.4 grams
38.8 grams
58.2 grams
77.5 grams

2. The table shows the recipe and the available ingredients for making the maximum possible number of sandwiches.


Making Sandwiches
Recipe for One Sandwich Ingredients Available
2 cheese slices, 1 ham slice, 2 bread slices 12 cheese slices, 10 ham slices, 12 bread slices


If the ingredients represent reactants of a chemical reaction, which of the following represents the leftover reactant?
Two ham slices
Four ham slices
Two cheese slices
Four cheese slices

3. Read the given chemical reaction.

C2H6 + O2 → CO2 + H2O

How many moles of H2O are produced during the complete combustion of 1.4 moles of C2H6?

2.8 moles
4.2 moles
5.6 moles
7.0 moles

4. The image represents the reaction between a certain number of molecules of N2 and H2.

[IMAGE INCLUDED]

If the maximum possible amount of NH3 is formed during the reaction, what is the leftover reactant?

One molecule of N2
One molecule of H2
Two molecules of N2
Two molecules of H2

Answers

1.B 2.A 3.B 4.D is your answers

Calculate the molarity of a solution prepared by dissolving 15.0 moles of solute in enough solvent to 50.0 liters of solution.

Answers

Answer:

Molarity of a solution = 0.3 mol/liter

Explanation:

Given:

Moles of solute = 15 moles

Amount of solution = 50 liters

Find:

Molarity of a solution

Computation:

Molarity of a solution = Moles of solute / Amount of solution

Molarity of a solution = 15 / 50

Molarity of a solution = 0.3 mol/liter

The type of elements found in groups 13-18 include

Answers

Answer:

Please put question in!

Explanation:

alkenes a. none of the above b. are relatively polar compounds c. are reasonably soluble in water d. have lower boiling points than alcohols of similar molecular weight

Answers

Answer:

have lower boiling points than alcohols of similar molecular weights.

Explanation:

Alkenes are hydrocarbons of the general molecular formula CnH2n. Alkenes are nonpolar hydrocarbons that are insoluble in water.

We must recall that alcohols are able to associate in water due to hydrogen bonding. This causes alcohols to have a relatively higher boiling point than alkenes of comparable molecular weight. Hencethe answer above.

Humans have developed ways to increase the carrying capacity of their environment. True or false

Answers

Answer:

false.nowadays humans are destroying forest,extracted more minerals,making pollution. in my view.

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