Answer:
0.9984
Step-by-step explanation:
we have shape parameter for the first component as 2.1
characteristics life = 100000
for this component
we have
exp(-2000/100000)².¹
= e^-0.0002705
= 0.9997
for the second component
shape parameter = 1.8
characteristic life = 80000
= exp(-2000/80000)¹.⁸
= e^-0.001307
= 0.9987
the reliability oif the system after 2000 events
= 0.9987 * 0.9997
= 0.9984
the area of triangle
(b) Two fair dice are tossed, and the up face on each die is recorded. Find the probability of
observing each of the following events:
A: (A 4 does not appear on either die)
B: The difference of the numbers is 2 or less)
(The sum of the numbers is odd)
P(A) =
(07 Marks)
(
P(B)
(07 Marks)
G)
(07 Marks)
ses
P(C)
Answer:
50% chance
Step-by-step explanation:
lol math go brrr
11 George will cover part of a floor with tiles.
The part of the floor is in the shape of a triangle as shown.
305 cm
371.5 cm
George buys tiles in packs.
Each pack covers 1 m2 and costs £39.95
The tiles can be cut and joined.
George gets off the cost of the packs of tiles.
Work out the lowest cost of the tiles for George.
Answer:
484ed+36_67'ten 355+(36)8wwhThe lowest cost of the tiles for George, for coring the considered triangular floor with the tiles of rate £39.95 per meter sq. is £226.3 approximately.
How can we interpret measurement of something?Remember that volume, area, length etc all are measured relatively.
If you are 1.7 meters tall, then you're height is measured relative to meters. This is called unit of the measurement. It means that if we collect 1 meter and 0.7 meters too,they together will be equally tall as you.
Similarly, if we say that a triangle has area of 40 square inches, then it means that its area is equal to 40 squares of 1 inch sides.
In the same way, volume is measured usually relative to unit cubes. Like how many unit cubes (cubes with 1 unit length of their sides) can be fitted (without any overlap or gap, but can be sliced to make them fit inside) inside the considered shape.
For this case, the tiles we will use will have the same area as the area of the triangular floor.
The triangular floor is of height and base of size 305 cm and 371.5 cm
Since the price rate of tiles is in meter sq, so it would be better if we convert the legths specified in meters.
100 cm = 1 m
1 cm = 1/100 m
305 cm = 305/100 = 3.05 m
371.5 cm = 3.715 m
The area of a triangle is half of the product of its base and height.
Thus, we get:
Area of tiles that will be used = area of the considered triangular floor =
[tex]\dfrac{3.05 \times 3.715}{2} \approx 5.665 \: \rm m^2[/tex]
Since 1 sq. m cost £39.95, therefore, 5.665 sq. meters will cost [tex]5.665 \times 39.95 \approx 226.3 \: \rm euros[/tex]
Thus, the lowest cost of the tiles for George, for coring the considered triangular floor with the tiles of rate £39.95 per meter sq. is £226.3 approximately.
Learn more about interpretation of measurement here: https://brainly.com/question/3424879
What is the scare root of 85 roused to nearest tenth?
Answer:
9.2
Step-by-step explanation:
You can do this calculation with a calculator by taking the square root of 85.
Hi there!
»»————- ★ ————-««
I believe your answer is:
9.2
»»————- ★ ————-««
Here’s why:
Assuming that you mean "the square root of 85 rounded to the nearest tenth..."
⸻⸻⸻⸻
[tex]\boxed{\text{Calculating the Answer...}}\\\\\rightarrow \sqrt{85} = 9.21954445729....[/tex]
⸻⸻⸻⸻
Since the digit to the right of the tenth (the 1) is less than or equal to four, we round down.
⸻⸻⸻⸻
[tex]9.21954445729...\approx\boxed{9.2}[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
Find the value of x.
Answer:
the value of x is 29°
hope it helps
have a nice day
HELP PLEASE. Will give maximum points (100). I’m desperate. Will give brainiest for the correct answer, if wrong answer is given on purpose, I will report. Plz help.
Answer:
C, D, D.
Step-by-step explanation:
Problem 6)
We want to determine the equation of the graphed inequality.
First, let's determine the equation of the line for the inequality. We can see that it passes through the points (-2, 0) and (0, 2). Find the slope:
[tex]\displaystyle m=\frac{\Delta y}{\Delta x}=\frac{2-0}{0-(-2)}=\frac{2}{2}=1[/tex]
So, the slope of the line is one.
And since it passes through the point (0, 2), our y-intercept is two. Therefore, the equation of the line is:
[tex]y=x+2[/tex]
Next, notice that the shaded region is below the line. Also, the line itself is also shaded.
Since the shaded region is below the line, y is less than the graph of the line and since the line itself is shaded, our sign is less than or equal to.
Hence:
[tex]y \leq x + 2[/tex]
Our answer is C.
Problem 7)
We have the inequality:
[tex]-2x+8+5x>2x+1[/tex]
First, solve the inequality. Combine like terms:
[tex]3x+8>2x+1[/tex]
Subtract x from both sides:
[tex]x+8>1[/tex]
And subtract 8 from both sides:
[tex]x>-7[/tex]
Therefore, any value greater than -7 will satisfy the inequality.
Out of the choices, the only choice greater than -7 is -5.
So, our answer is D.
Problem 8)
We have the inequality:
[tex]5x+7\leq 8x-3+2x[/tex]
Again, solve the inequality. Combine like terms:
[tex]5x+7\leq 10x-3[/tex]
Subtract 5x from both sides:
[tex]7\leq 5x-3[/tex]
And add three to both sides:
[tex]10\leq 5x[/tex]
Divide both sides by five:
[tex]2\leq x[/tex]
Flip:
[tex]x\geq 2[/tex]
Therfore, any value greater than or equal to 2 will satisfy the inequality.
Out of the choices, the only choice greater than or equal to 2 is 2.
So, our answer is D.
rationalize the denominator of √3+√2\ 5+√2
Answer:
[tex]\frac{ 5 \sqrt3 \ + \ 5 \sqrt2 \ - \ \sqrt6 \ - \ 2}{23}[/tex]
Step-by-step explanation:
[tex]\frac{\sqrt3 \ + \ \sqrt2 }{5 \ + \ \sqrt2 } \\\\=\frac{\sqrt3 \ + \ \sqrt2 }{5 \ + \ \sqrt2 } \times \frac{5 \ - \ \sqrt2 }{5 \ - \ \sqrt2 } \\\\=\frac{( \sqrt3 \ + \ \sqrt2)(5 \ - \ \sqrt2)}{(5 \ + \ \sqrt2)( 5 \ - \ \sqrt 2 )}\\\\=\frac{( \sqrt3 \ + \ \sqrt2)(5 \ - \ \sqrt2)}{(5 \ + \ \sqrt2)( 5 \ - \ \sqrt 2 )}\\\\=\frac{5 \sqrt3 \ + \ 5\sqrt 2 \ - \ \sqrt{ 3\times 2 } \ - \ \sqrt{2 \times 2}}{(5)^2 \ - \ (\sqrt2)^2}\\\\= \frac{ 5 \sqrt3 \ + \ 5 \sqrt2 \ - \ \sqrt6 \ - \ 2}{25 - 2}\\\\[/tex]
[tex]= \frac{ 5 \sqrt3 \ + \ 5 \sqrt2 \ - \ \sqrt6 \ - \ 2}{23}[/tex]
Which point is part of the solution of the inequality y ≤ |x + 4| − 3?
Answer:
Step-by-step explanation:
Check out the attachment and help me out please!!!
Answer:
20
Step-by-step explanation:
4 + 2 + 5 + 4 + 0 + 1 + 1 + 3 = 20
Which statement must be true if APQR = ASTU?
Answer:
(a) [tex]PQ \sim ST[/tex]
Step-by-step explanation:
Given
See attachment
Required
Which must be true
[tex]\triangle PQR \simeq \triangle STU[/tex] implies that:
The following sides are corresponding
[tex]PQ \sim ST[/tex]
[tex]PR \sim SU[/tex]
[tex]QR \sim TU[/tex]
The following angles are corresponding
[tex]\angle P \sim \angle S[/tex]
[tex]\angle Q \sim \angle T[/tex]
[tex]\angle R \sim \angle U[/tex]
From the given options, only option (a) is true because:
[tex]PQ \sim ST[/tex]
Test the claim that the mean GPA of night students is larger than the mean GPA of day students at the 0.10 significance level. The null and alternative hypothesis would be: H 0 : p N ≥ p D H 1 : p N < p D H 0 : p N ≤ p D H 1 : p N > p D H 0 : p N = p D H 1 : p N ≠ p D H 0 : μ N ≤ μ D H 1 : μ N > μ D H 0 : μ N ≥ μ D H 1 : μ N < μ D H 0 : μ N = μ D H 1 : μ N ≠ μ D The test is: two-tailed right-tailed left-tailed The sample consisted of 30 night students, with a sample mean GPA of 3.34 and a standard deviation of 0.02, and 30 day students, with a sample mean GPA of 3.32 and a standard deviation of 0.08. The test statistic is: (to 2 decimals) Use the conservative degree of freedoms. The p-value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Answer:
H0 : μN ≤ μD
H1 : μN > μD
Right tailed
Test statistic = 1.33
Pvalue = 0.097
Fail to reject the Null
Step-by-step explanation:
H0 : μN ≤ μD
H1 : μN > μD
The test is right tailed ; culled from the direction of the greater than sign ">"
Night students :
n1 =30 x1= 3.34 s1 = 0.02
Day students:
n2 = 30 x2 = 3.32 s2 = 0.08
The test statistic :
(x1 - x2) / √(s1²/n1) + (s2²/n2)
T= (3.34 - 3.32) / √(0.02²/30) + (0.08²/30)
T = 0.02 / 0.0150554
Test statistic = 1.328
Using the conservative approach ;
df = Smaller of n1 - 1 or n2 - 1
df = 30 - 1 = 29
Pvalue(1.328, 29) = 0.097
At α = 0.10
Pvalue < α ; Hence, we reject H0 ; and conclude that there is significant evidence that GPA of night student is greater than GPA of day student
How is solving for speed similar to solving for time?
O They both require that two numbers be added.
O They both require that two numbers be subtracted
O They both involve writing a rate.
O They both use the same units of measure.
Answer:
third one
Step-by-step explanation:
Please help :)
Solve 3(m-4)=33
Thanks so much :)
Answer:
3(m-4)=33
3m-12=33
3m=45
m=15
Check:
3(15-4)=33
3(11)=33
33=33
Hope This Helps!!!
Answer:
m = 15
Step-by-step explanation:
3 ( m - 4 ) = 33
Solve for m
3 ( m - 4 ) = 33
Divide both side by 3
[tex]\small \sf \frac{3(m-4)}{3} = \frac{33}{3} \\ [/tex]
m - 4 = 11
Add 4 to both side
m - 4 + 4 = 11 + 4
m = 15
What is the lcd for 3/6 and 2/9
9514 1404 393
Answer:
LCD = 18
Step-by-step explanation:
6 and 9 have a common factor of 3, so the LCD is ...
(6×9)/3 = 18
Then the fractions can be written as ...
3/6 = 9/18
2/9 = 4/18
Using the proper terminology, how would you explain and visually demonstrate that this is not always the case?
ONLY ANSWER IF YOU KNOW THE ANSWER
Answer:
Answer is 6.
Step-by-step explanation:
The product is
[tex]15\times \frac{2}{5}[/tex]
Now, it does not means that the product of two quantities is always more than the individual quantities.
here, 2/5 is a part of whole.
So,
The product is
[tex]15\times \frac{2}{5}\\\\=3\times 2\\\\= 6[/tex]
The answer is 6 which is less than 15.
Here, it is the 2/5 part of whole 15.
The ocean surface is at 0 ft elevation. A diver is underwater at a depth of 138 ft. In this area, the ocean floor has a depth of 247 ft. A rock formation rises to a peak 171 ft above the ocean floor. How many feet below the top of the rock formation is the diver?
Answer:
The ocean surface is at 0 ft elevation. A diver is underwater at a depth of 138 ft. In this area, the ocean floor has a depth of 247 ft.
Step-by-step explanation:
3s + 4t = 22
8s + 8t = 48
What is s and what is t
(Similtaneous Equations)
9514 1404 393
Answer:
(s, t) = (2, 4)
Step-by-step explanation:
We can eliminate the t variable by subtracting the first equation from half the second.
(1/2)(8s +8t) -(3s +4t) = (1/2)(48) -(22)
s = 2
3(2) +4t = 22
4t = 16
t = 4
The solution is (s, t) = (2, 4).
We are testing a new drug with potentially dangerous side effects to see if it is significantly better than the drug currently in use. If it is found to be more effective, it will be prescribed to millions of people.
1.
a. What does it mean in context to make a type I error in this situation?
b. What does it mean in context to make a type Il error in this situation?
c. Which error do you think is worse? Now we are testing to see whether taking a vitamin supplement each day has significant health benefits. There are no (known) harmful side effects of the supplement.
2.
a. What does it mean in context to make a type I error in this situation?
b. What does it mean in context to make a type Il error in this situation?
c. Which error do you think is worse? For a given situation, what should you do if you think that committing a type l error is much worse than committing a type Il error?
A. Increase the significance level.
B. Decrease the significance level.
C. Nothing, just be careful to take a good sample.
Answer:
1) a) accepting the new drug is better based on its effectiveness when in reality the drug ain't better than the drug in current use because of its side effects
b) Accepting and using the current drug in use when it is not as effective as the new drug
c) Type 1 error
2) a) rejecting the vitamin supplement based on not knowing the harmful side effects
b) Accepting the Vitamin supplement based on just health benefits it portrays without comparison with other supplement.
c) Type II error
3) Increase the significance level ( A )
Step-by-step explanation:
1)
a) To make a type 1 error in this situation is accepting the new drug is better and prescribing it to the millions of people based only on its effectiveness when in reality the drug ain't better than the drug in current use because of its side effects
b) A type II error in context is :Accepting and using the current drug in use when it is not as effective as the new drug
c) Type I error
2)
a) Type 1 error is rejecting the vitamin supplement based on not knowing the harmful side effects
b) Accepting the Vitamin supplement based on just health benefits it portrays without comparison with other supplement.
c) Type II error
3) If committing a type 1 error is much worse
Increase the significance level
Amy types at an average speed of 38 words per rinute. She has already typed 1,450 words of her final paper, which will be more than 4,000
words. Which inequality can be used to solve for x, the number of minutes it will take Amy to finish typing her paper?
ОА.
38x-1,450 > 76
OB.
38[X+1,450) > 4,000
Ос. .
38x> 4,000
OD.
38x + 1,450 > 4,000
Reset
Next
ntum. All rights reserved.
o
74°F Mostly cloudy
I
о
m
De here to search
Answer: D. 38x + 1,450 > 4,000
Step-by-step explanation:
It has to be greater than 4,000 so A makes no sense
The parentheses are in the wrong place completely changing the meaning for B
C disregards the info we have about how she's already typed 1,450 words
The answer has to be D
HELP PLEASE!!!!!!!!!!
Answer:
12
Step-by-step explanation:
Find the critical point for f and then use the second derivative test to decide whether the critical point is a relative maximum or a relative minimum.f(x)=-x^2-2x-9
Answer:the answer is 9
Step-by-step explanation:
1) What is the opposite of adding 5?
2) What is the opposite of subtracting 20?
3) What is the opposite of multiplying by 1/2?
4) What is the opposite of dividing by 10?
I need help pleasereee
Answer:
1. subtracting 5
2. adding 20
3. dividing by 1/2
4. multiplying by 10
Given right angle ABC, what the value of tan(A)?
5/13
12/13
12/5
13/12
need answer asap
Hi there!
[tex]\large\boxed{12/5}}[/tex]
tan (angle) = Opposite side / Adjacent side, so:
Tan (A) = opposite side / adjacent side
= 24 / 10
Simplify:
= 12 / 5
Please show process!!!!
THANK YOU!
Will mark brainylist
Answer: 103 degrees
Step-by-step explanation:
51 + 26 = 77
A triangle adds up to 180 degrees
180 - 77 = 103
= 103 degrees
Please help me as soon as possible
Answer:
I think the choose (B)
5x/x + 3/x
Answer:
I thinkchoose no.3
5x+3
5x+3x
The light from a lamp creates a shadow on a wall with a hyperbolic border. Find the equation of the border if the distance between the vertices is inches and the foci are inches from the vertices. Assume the center of the hyperbola is at the origin.
The equation of the hyperbola is,
(x/12)² - 4y²/(527) = 1
The standard equation of the hyperbola is
(x/a)² - (y/b)² = 1
Here (a, 0) and (-a, 0) are vertices and asymptotes y = ± √(b/a)x
Foci are (c, 0) & (-c, 0)
Then a² + b² = c²
Here we have to give that.,
2a = 24
a = 12
And 2c = 7
c = 7/2
Therefore a = 12 and c = 3.5
Substituting a and c in Pythagorean identity;
b² = 527/4
Then, the equation of the hyperbola is
(x/12)² - 4y²/(527) = 1
For further information regarding hyperbolas, kindly refer
brainly.com/question/28989785
#SPJ4
We have b = 0, which implies that the foci coincide with the vertices, making the hyperbola a degenerate case. In this scenario, the equation of the border would be a vertical line passing through the vertices/foci, given by the equation x = ±a.
To find the equation of the hyperbolic border created by the shadow on the wall, we can start by understanding the properties of a hyperbola. A hyperbola is defined as the set of all points such that the difference of the distances from any point on the hyperbola to two fixed points, called the foci, is constant.
Let's label the vertices of the hyperbola as A and B, and the foci as F1 and F2. The distance between the vertices is given as 2a inches, and the foci are located at a distance c inches from the vertices.
Using the given information, we can find the value of a and c. Since the center of the hyperbola is at the origin, the coordinates of the vertices are (±a, 0), and the coordinates of the foci are (±c, 0).
The distance between the foci is given by the equation:
c = √(a^2 + b^2)
We know that the distance between the foci is given as 2c inches, so:
2c = 2√(a^2 + b^2)
Since c is given as a distance from the vertices, we can substitute c = a - b to simplify the equation:
2(a - b) = 2√(a^2 + b^2)
Squaring both sides to eliminate the square root:
4(a - b)^2 = 4(a^2 + b^2)
Expanding the equation:
4(a^2 - 2ab + b^2) = 4a^2 + 4b^2
Simplifying the equation:
4a^2 - 8ab + 4b^2 = 4a^2 + 4b^2
Canceling out the common terms:
-8ab = 0
Dividing by -8:
ab = 0
This implies that either a = 0 or b = 0. However, since a represents the distance between the vertices and b represents the distance between the foci and vertices, we can rule out a = 0 as it would result in a degenerate hyperbola.
for such more question on hyperbola
https://brainly.com/question/16454195
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The University of Montana ski team has thirteen entrants in a men's downhill ski event. The coach would like the first, second, and third places to go to the team members. In how many ways can the thirteen team entrants achieve first, second, and third places
Answer:
1716 ways
Step-by-step explanation:
Given that :
Number of entrants = 13
The number of ways of attaining first, second and third position :
The number of ways of attaining first ; only 1 person can be first ;
Using permutation :
nPr = n! ÷(n-r)!
13P1 = 13! ÷ 12! = 13
Second position :
We have 12 entrants left :
nPr = n! ÷(n-r)!
12P1 = 12! ÷ 11! = 12
Third position :
We have 11 entrants left :
nPr = n! ÷(n-r)!
11P1 = 11! ÷ 10! = 11
Hence, Number of ways = (13 * 12 * 11) = 1716 ways
Express the function as the sum of a power series by first using partial fractions. f(x)=x+62x2−9x−5
Answer:
[tex]\frac{x+6}{2x^2-9x+5}=-\sum_{n=0}^{\infty} [(-2)^{n}x^{n} + \frac{x^{n}}{5^{n+1}}][/tex]
when:
[tex]|x|<\frac{1}{2}[/tex]
Step-by-step explanation:
In order to solve this problem, we must begin by splitting the function into its partial fractions, so we must first factor the denominator.
[tex]\frac{x+6}{2x^2-9x+5}=\frac{x+6}{(2x+1)(x-5)}[/tex]
Next, we can build our partial fractions, like this:
[tex]\frac{x+6}{(2x+1)(x-5)}=\frac{A}{2x+1}+\frac{B}{x-5}[/tex]
we can then add the two fraction on the right to get:
[tex]\frac{x+6}{(2x+1)(x-5)}=\frac{A(x-5)+B(2x+1)}{(2x+1)(x-5)}[/tex]
Since we need this equation to be equivalent, we can get rid of the denominators and set the numerators equal to each other, so we get:
[tex]x+6=A(x-5)+B(2x+1)[/tex]
and expand:
[tex]x+6=Ax-5A+2Bx+B[/tex]
we can now group the terms so we get:
[tex]x+6=Ax+2Bx-5A+B[/tex]
[tex]x+6=(Ax+2Bx)+(-5A+B)[/tex]
and factor:
[tex]x+6=(A+2B)x+(-5A+B)[/tex]
so we can now build a system of equations:
A+2B=1
-5A+B=6
and solve simultaneously, this one can be solved by substitution, so we get>
A=1-2B
-5(1-2B)+B=6
-5+10B+B=6
11B=11
B=1
A=1-2(1)
A=-1
So we can use these values to build our partial fractions:
[tex]\frac{x+6}{(2x+1)(x-5)}=\frac{A}{2x+1}+\frac{B}{x-5}[/tex]
[tex]\frac{x+6}{(2x+1)(x-5)}=-\frac{1}{2x+1}+\frac{1}{x-5}[/tex]
and we can now use the partial fractions to build our series. Let's start with the first fraction:
[tex]-\frac{1}{2x+1}[/tex]
We can rewrite this fraction as:
[tex]-\frac{1}{1-(-2x)}[/tex]
We can now use the following rule to build our power fraction:
[tex]\sum_{n=0}^{\infty} ar^{n} = \frac{a}{1-r}[/tex]
when |r|<1
in this case a=1 and r=-2x so:
[tex]-\frac{1}{1-(-2x)}=-\sum_{n=0}^{\infty} (-2x)^n[/tex]
or
[tex]-\frac{1}{1-(-2x)}=-\sum_{n=0}^{\infty} (-2)^{n} x^{n}[/tex]
for: |-2x|<1
or: [tex] |x|<\frac{1}{2} [/tex]
Next, we can work with the second fraction:
[tex]\frac{1}{x-5}[/tex]
On which we can factor a -5 out so we get:
[tex]-\frac{1}{5(1-\frac{x}{5})}[/tex]
In this case: a=-1/5 and r=x/5
so our series will look like this:
[tex]-\frac{1}{5(1-\frac{x}{5})}=-\frac{1}{5}\sum_{n=0}^{\infty} (\frac{x}{5})^n[/tex]
Which can be simplified to:
[tex]-\frac{1}{5(1-\frac{x}{5})}=-\sum_{n=0}^{\infty} \frac{x^n}{5^(n+1)}[/tex]
when:
[tex]|\frac{x}{5}|<1[/tex]
or
|x|<5
So we can now put all the series together to get:
[tex]\frac{x+6}{2x^2-9x+5}=-\sum_{n=0}^{\infty} [(-2)^{n}x^{n} + \frac{x^{n}}{5^{n+1}}}[/tex]
when:
[tex]|x|<\frac{1}{2}[/tex]
We use the smallest interval of convergence for x since that's the one the whole series will be defined for.
A company decides to drain the water heater to flush out sediments. The water heater has a capacity of 500 gallons. It drains 100 gallons in 20 minutes. After 20 minutes, they open another drain valve and it drains 200 gallons in the next 20 minutes. The drain valves are closed for 10 minutes, while the workers take a break and then the water heater is drained until the water heater is completely empty.
What are the domain and the range of this relation?
Answer:
≤ y ≤ 70 and 0 ≤ x ≤ 500
Step-by-step explanation:
In this relation we have two things to analyze, the number of gallons of water in the heater, that is 500 gallons, and the time that it took to empty the heater.
Let's count the time.
First, there are 20 minutes in wich 100 gallons are drained.
then, another drain valve is opened, so in 20 minutes they drain 200 gallons of water.
now, the wait for 10 minutes.
Now there are 200 gallons remaining, so the workers must wait for the other 20 minutes to drain the 200 gallons remaining.
The total amount of time is 70 minutes.
So if we have a relationship of water in the heater vs time, where X is the water remaining and Y is the time, the correct domains are:
Y from 0 minutes to 70 minutes
X from 0 gallons to 500 gallons
So the correct options are C and E.
0 ≤ y ≤ 70 and 0 ≤ x ≤ 500
Will give brainliest answer
Answer:
1. log3 81 = 4
2. 4 3/2=8
Step-by-step explanation:
1. Convert the exponential equation to a logarithmic equation using the logarithm base (3)(3) of the right side (81)(81) equals the exponent (4)(4).
log3(81)=4
or
you can remember this
loga Y= X
so, a^x =y
2. Use the definition of a logarithm,
log
b
(
x
)
=
y
⟹
b
y
=
x
, to convert from the logarithmic form to the exponential form.