Answer:
-0.166 m/s²
Explanation:
F = Ma
a = F/M = (121 N +186 N)/(1850 kg) = 0.166 m/s²
The acceleration of 0.166 m/s² is in the direction opposite to the direction of travel, so might be considered to be negative.
Answer:
-0.166 m/s²
As a 1850 kg car is traveling down a road, it experiences a force of friction of 121 N and a force of air resistance if 186N. If the engine is not applying any force, what is the acceleration of the car
The table displays the scores of students on a recent exam. Find the mean of the
scores to the nearest 10th.
Score Number of Students
65
4.
70
2
75
2
80
1
85
7
90
5
Answer:
Solution
x f fx
65 4 260
70 2 140
75 2 150
80 1 80
85 7 595
90 5 450
total N=21 Summation fx=1675
We know
Mean= Summation fx/N
=1675/21
=79.8
Hence, the required mean is 79.8 ans.
The scores of students on a recent exam. The mean of the scores is 51.42857.
What is mean?The mean is the ratio of addition of all the observation values and the number of observations.
The mean of the score is equal to
Mean = {(65×4)+(70×2)+(75×2)+(80×1)+(85×7)+(90×5)} / (4+2+2+1+7+5)
Mean = 51.42857
Therefore, the mean of the scores is 51.42857.
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A pie is cooked in an oven at 200 °C. The aluminium film that ckvered the pie can be touched soon after it is removed while the pie is still dangerously hot. Explain this?
Answer and Explanation:
The aluminum is more productive in the absorption and heat transfer to other particles. It instantly converts heat absorbed from the environment into the atmosphere when removed from the oven, enabling us to operate with it faster than the pie that takes much longer to convert heat to the environment.
So this is the reason for pie to be the dangerously hot
A solid aluminum cube has sides each of length L . A second cube of the same material has sides four times the length of the first cube; i.e., 4 L . Compared to the first cube, the total surface area of the second cube is 1. twenty-seven times the first cube. 2. sixteen times the first cube. 3. sixty-four times the first cube. 4. eight times the first cube. 5. twenty-four times the first cube. 6. two times the first cube
Answer:
Option (2) : Sixteen times the first cube
Explanation:
[tex]Surface \: Area \: of \: Cube = 6 {a}^{2} [/tex]
[tex] \frac{T.S.A \: of \: larger \: cube}{T.S.A \: of \: smaller \: cube} = \frac{6 \times 16 {l}^{2} }{6 \times {l}^{2} } = 16[/tex]
When the linear dimensions of a solid are multiplied by ' R ', the surface area of all or any part of it increases by R² , and the volume of all or any part of it increases by R³ .
If the sides of the second cube are 4 times the sides of the first one, then the second cube has (4²) = sixteen times the surface area of the first one (2), and it has (4³) = 64 times the volume of the first one.
a body of mass 0.5kg is shot vertically into the air with an initial speed of 45m/s
, calculate the time taken to reach the maximum height
Answer:
The time to reach the maximum height is approximately 4.59 seconds
Explanation:
The maximum height in a problem where friction with the air is neglected, only needs the kinematic information of the initial velocity at which the object was launched vertically.
Recall that the formula for the velocity of an object under constant acceleration ([tex]a[/tex]) in terms of time (t) is given by:
[tex]v(t)=v_0+a\,\,t[/tex]
where [tex]v_0[/tex] is the initial velocity of the object (in our case the speed at which it was launched up in the air = 45 m/s)
Considering that the acceleration the object is subjected (which is the acceleration of gravity g = 9.8 m/s^2) is acting in opposite direction to the initial velocity of the object, we make sure to include a negative sign in the formula:
[tex]v(t)=v_0+a\,\,t=v_0-g\,\,t[/tex]
then, considering that at the time the object reaches its maximum height, is when it stops and starts it motion back towards earth, that is the point at which the object's velocity is zero. Then we can solve for the time as follos:
[tex]0=v_0-g\,\,t\\g\,\,t=v_0\\t=\frac{v_0}{g} \\t=\frac{45}{9.8} \\t\approx 4.59\,\,sec[/tex]
Study the interaction of the light rays with the mediums. Classify the medium in each image as being transparent or opaque.
Answer:
a) transparent
b) transparent
c) opaque
Explanation:
In the first one, the light rays go completely through, so it is transparent.
The second one I'm not too sure about. It is refraction so it's going through a different material, but the fact that it went through makes me say transparent.
Last one, the light rays are reflecting off the surface so it's opaque.
Please feel free to correct me if I'm wrong. This is just my understanding
Dust particles fall down when a carpet or a piece of cloth is beaten by a stick,why?
Dust particles fall down when we hit the carpet or a piece of cloth with a stick because it loses it inertia of rest and move forward, but dust particles fall down in absence of the carpet.
Since all stars begin their lives with the same basic composition what characteristics most determines how they will differ
Answer:
Mass they are formed with
Explanation:
All stars are born with the same composition such as one quarter of helium, three quarter of hydrogen, and heavier element does not found more than two except their mass. Mass that differ all stars from other stars they born with. How much the mass of a star is large , the star would be as messy.
For example our sun is a star and have large mass four times greater than other living stars. It is found that smallest mass is around 1/12th of sun mass. The masses of a star is determined by its orbit binary. Sun is called a brown dwarf.
A toy car, released from the table top, is at the
half-way mark along the ramp to the floor below.
☆
Тар
Kinetic Energy
Gravitational Potential Energy
Both of these
None of these
Answer:
Gravitational Potential Energy
Explanation:
A toy car, released from the table top, is at the half-way mark along the ramp to the floor below will be experiencing Gravitational Potential Energy. Thus, the correct option is B.
What is Gravitational Potential Energy?Gravitational energy is also known as the gravitational potential energy. It is the potential energy which a massive object has in relation to another massive object due to gravitational force. It is the potential energy which is associated with the gravitational field, and is released when the objects fall towards each other from a certain height.
When something has a high position, then its gravitational potential energy is high. For example, a book which is placed on a high bookshelf has a higher potential energy than a book which is placed on the bottom shelf because it has farther to fall.
Therefore, the correct option is B.
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A car is traveling 35 mph on a smooth surface. If a balanced force is applied to the car, what happens?
Answer:
Here is the answer.
Explanation:
Balanced forces- they are those forces that produce 0 resultant forces.
therefore, on applying a balanced force on the object, it wouldn't result in any change, as resultant force would be 0.
Which motor and body should Devon use to build the car with the greatest acceleration? motor 1, with body 1 motor 1, with body 2 motor 2, with body 1 motor 2, with body 2
Answer:
hello your question is incomplete below is the complete question
Devon has several toy car bodies and motors. The motors have the same mass, but they provide different amounts of force, as shown in the table.
Which motor and body should Devon use to build the car with the greatest acceleration?
motor 1, with body 1
motor 1, with body 2
motor 2, with body 1
motor 2, with body 2
answer: Motor 2 body 1
Explanation:
F = ma
hence a ( acceleration ) = F / m
force of motor 2 = 15 N since the mass of the motor is the same and that of the bodies aren't given
The motor and body that would produce the greatest acceleration would be : Motor 2 Body 1 if the mass of Body 1 is less than the mass of Body 2
Answer:
c
Explanation:
What problems would we have if Pascal had failed to give the Pascal's law? Write some points.
Answer:
Pascal's law states that a change in pressure at any point in an enclosed fluid is transmitted equally throughout the fluid.
Explanation:
Applications of Pascal's law include
>The hidden standard of the water powered jack and pressure driven press.
>Power intensification in the slowing mechanism of most engine vehicles.
>Utilized in artesian wells, water pinnacles, and dams.
>Scuba jumpers must comprehend this rule. At a profundity of 10 meters submerged, pressure is double the environmental weight adrift level, and increments by around 100 kPa for each expansion of 10 m depth.[5]
>Generally Pascal's standard is applied to bound space (static flow), however because of the consistent flow process, Pascal's rule can be applied to the lift oil instrument (which can be represented as a U tube with pistons on either end).
Without Pascal's law, none of the above could be possible.
FOR 30 points
Part 3
What single property was the most important in Jesseca's material?
Answer:
Jesseca wanted to create a material that reflected most of the light that fell on it.
Explanation:
Plato Answer
Answer:
this is the exact answer on Edmentum...
Explanation:
Jesseca wanted to create a material that reflected most of the light that fell on it.
Which of the following is a limit of science? (2 points) a The technology or tools available to test scientific claims b The number of times an experiment can be repeated c The total number of scientists in a field, like physics or chemistry d The use of critical thinking and evidence to study phenomena
Answer: A- The technology or tools available to test scientific claims. I just took this test and passed.
Attempt 3 of 2
SECTION 10F1
QUE
1 2 3 4 5 6 7
>
Which of the following will stay constant, no matter if the substance is in the solid, liquid, or gas state?
volume
shape
temperature
mass
Answer:
mass.
Explanation:
other physical factors are changeable but the mass of a particular substance is always constant.
A. In what frame of reference does special relativity apply? b. In what frames must general relativity be used? c. Describe what happens to time and length at speeds close to the speed of light.
Answer:special relativity apply to INERTIAL FRAME REFERENCE
Explanation:
inertial frame of reference is the one in which acceleration is zero this means object is moving with constant velocity
What does perseverance mean to you?
How long is the racetrack if it takes a racecar 3.4 s travelling at 75 m/s to finish?
Answer:
255 metres
Explanation:
The answer to thi question is actually quite simple. Since the car goes for 3.4 seconds, and it goes 75 metres every second, the answer is just 3.4 multiplied by 75 Metres.
Which force affect the movement of aeroplane and ship?
A cell membrane has a thickness of about 7 nm. How many cell membranes would it take to make a stack 3.4 in high?
Answer:
486 of cell membranes
Explanation:
one cell membrane has 7*10^-9m as the height
So, by dividing 3.4 with 7*10^-9 you will get the number of cell require to form the height.
3.4/(7*10^-9)=485.71
because we can't have decimal number of cell we would round it into three significant figures, 486.
What is the force per meter of length on a straight wire carrying a 6.40 A current when perpendicular to a 0.9 T uniform magnetic field
Answer:
5.76 N/m
Explanation:
From the question,
F = BILsinФ...................... Equation 1
and then,
F/L = BIsinФ.................. Equation 2
Where F/L = force per meter, I = current, B = magnetic field, Ф = angle.
Given: B = 0.9 T, I = 6.4 A, and Ф = 90° (Perpendicular)
Subtitute these values into equation 2
F/L = 0.9(6.4)(sin90°)
F/L = 5.76 N/m
The force per meter of length on a straight wire will be 5.76 N/m.
What is a magnetic field?It is the type of field where the magnetic force is obtained. With the help of a magnetic field. the magnetic force is obtained it is the field felt around a moving electric charge.
The given data in the problem si;
B is the megnetic field=0.9 T
I is the current = 6.4 A,
Ф is the angle = 90° (Perpendicular)
The megnetic field is found as;
[tex]\rm F= BILsin \phi \\\\ \frac{F}{L} =BIsin\phi \\\\ \frac{F}{L} =0.9 \times 6.4 \times sin 90^0\\\\ \frac{F}{L} =5.76 / N/m[/tex]
Hence the force per meter of length on a straight wire will be 5.76 N/m.
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Friends tell you that on a recent trip their average velocity was +20 m/s. Is it possible that at any time during the trip their velocity was -20 m/s? Explain
Answer:
Yes , it is possible .
Explanation:
Suppose they travelled from A to B , a distance of 800 m at a velocity of
40m /s and then come back on the same path covering a distance of 200 m at the rate of 20/ s .In other words their velocity in their return journey was -20m /s .
Net displacement = 600 m
Total time taken = (800 / 40) + (200 / 20)
= 20 + 10 = 30 s
Average velocity = net displacement / total time
= 600 / 30 = 20 m /s .
Hence average velocity of 20 m /s is possible .
A statistical analysis used to examine the influence of one variable on another is
Answer: the correlation coefficien
Explanation:
Regression and correlation analysis are statistical techniques used extensively in physical geography to examine causal relationships between variables. ... Utilization of correlation analysis on dependent and independent variables produces a statistic called the correlation coefficient
Answer:the right answer is regression
Explanation:
I just took my test and correlation was wrong the correct answer is b regression
An automobile travels a displacement of 75km 45 degrees north of east. How many kilometers north does it travel?
Answer:
It travelled 53.03 Km North.
The distance traveled by the automobile is 53.03 km north.
The given parameter:
the displacement of the automobile, = 75 km 45 degrees north of east.
To find:
the distance traveled by the automobileThe vertical component of the displacement is equal to the distance traveled by the automobile in north.
[tex]distance \ towards \ north = 75 \ km \ \times \ sin(45)\\\\distance \ towards \ north = 75 \ km \times 0.7071\\\\distance \ towards \ north = 53.03 \ km \ north[/tex]
Thus, the distance traveled by the automobile is 53.03 km north.
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A point on a wave completes one cycle every 5 seconds. The frequency of this wave is 1/5 seconds.
Question 2 options:
True
False
Answer:
True
Explanation:
1 cycle every 5 sec is the same when you set up the ratio as 1/5
Hope this helps!! Have a great day!! :)
Calculate the acceleration of a 23.9 kg mass when a net force of 158N north acts on it. Answer is 6.61ms^-2 north. Need to know how to get there.
Answer:
formula F = m * a
Explanation:
F = m * a
F = force = 158 N
m = mass = 23.9 kg
a = acceleration
158 = 23.9 * a
a = 158 / 23.9
a = 6.61m/s²
therefore, use the formula F = m * a
Raul started out fifteen meters to my left walking towards me. Three seconds
later, he was 6 meters to my left. How fast is Raul walking. Write an equation to
find his displacement, x, from the time, t. If he keeps going at the same rate,
where will he be 15 seconds from when he started?
Answer:
Raul will be 30 meters to the right of observer.
Explanation:
Raul is walking towards the observer, let be [tex]x[/tex] the position of Raul with respect to the observer and, besides, that [tex]x[/tex] is negative to the left and positive to the right.
Raul is moving at constant rate so that velocity ([tex]v[/tex]) is equal to:
[tex]v = \frac{x_{f}-x_{o}}{\Delta t}[/tex]
Where:
[tex]x_{o}[/tex], [tex]x_{f}[/tex] - Initial and final position of Raul regarding the observer, measured in meters.
[tex]\Delta t[/tex] - Change in time, measured in seconds.
Given that [tex]x_{o} = -15\,m[/tex], [tex]x_{f} = -6\,m[/tex] and [tex]\Delta t = 3\,s[/tex], the velocity of Raul is:
[tex]v = \frac{(-6\,m)-(-15\,m)}{3\,s}[/tex]
[tex]v = +3\,\frac{m}{s}[/tex]
The equation of his displacement is represented by clearing final position in the equation above:
[tex]x_{f} = x_{o}+v\cdot \Delta t[/tex]
If [tex]x_{o} = -15\,m[/tex] and [tex]v = +\frac{3}{5}\,\frac{m}{s}[/tex], the equation of motion is:
[tex]x_{f} = -15\,m + \left(+3\,\frac{m}{s} \right)\cdot \Delta t[/tex]
Then, if [tex]\Delta t = 15\,s[/tex], the final position of Raul regarding the observer is:
[tex]x_{f} = -15\,m + \left(+3\,\frac{m}{s} \right)\cdot (15\,s)[/tex]
[tex]x_{f} = +30\,m[/tex]
Raul will be 30 meters to the right of observer.
where would information on the chemical and physical properties of a specific chemical be located in a laboratory or in the workplace?
Answer:
on the body of the container of the chemical and it also on the shelf where the chemical is kept in the laboratory.
Explanation:
The information on the chemical and physical properties of a specific chemical should be located on the body of the container of the chemical. when storing chemicals in a laboratory the properties, both chemical and physical properties of the chemical should be written out and pasted on the body of the container that contains the chemicals.and also o the shelf where the chemical is kept in the laboratory or workplace .
An object accelerates 20.8 m/s2 when a force of 8.9 newtons is applied. What is the mass of the object?
Answer: 0.43kg
Explanation: a = 20.8m/s^2
F = 8.9N
m = ?
F = ma
8.9 = 20.8m
m = 8.9/20.8
= 0.43kg
Hope this helped..
Part A
The initial velocity of a car moving along a straight path was 0 meters/second. After 10 seconds, it reached a velocity of 25 meters/second.
Calculate the car's average acceleration during this time period.
Answer:
2.5 m/s²
Explanation:
Using the formula, v = u + at ( v = Final velocity; u = Initial velocity; t = Time; a = Acceleration)
25 = 0 + 10a
a = 25/10 = 2.5 m/s²
A certain part of a flat screen TV has a thickness of 150 nm how many meters is this
Answer:
[tex]1.5\,\,10^{-7}\,\,m= 0.00000015\,\,m[/tex]
Explanation:
The prefix nano means [tex]10^{-9}[/tex], therefore:
[tex]150 \,\,nm = 150\,\,10^{-9}\,m=1.5\,\,10^{-7}\,\,m= 0.00000015\,\,m[/tex]