Answer:
a = 2
b = 5
Step-by-step explanation:
Given :
(ar^b)^4 = 16r^20 ; a and b are positive integers :
Opening the bracket :
a^4r^4b = 16r^20
a^4 = 16 - - - - - (1)
r^4b = r^20 - - - (2)
a^4 = 16
Take the 4th root of both sides :
(a^4)^(1/4) = 16^1/4
a = 2
From (2)
r^4b = r^20
4b = 20
Divide both sides by 4
4b/4 = 20/4
b = 5
Hence ;
a = 2
b = 5
if the mean of a random variable X is 45 what will be the mean of the sampling distribution of the sample mean?
Answer:
The mean of the sampling distribution is always equal to the mean of the population.
The mean of the sampling distribution of the sample mean is 45.
Given that,
The mean of the random variable X is 45.We need to find out the mean of the sampling distribution.Based on the above information, the calculation is as follows:
= mean of the random variable X
= 45
As the sampling distribution mean should always be equivalent to the population mean.
Therefore we can conclude that the mean of the sampling distribution of the sample mean is 45.
Learn more: brainly.com/question/521501
Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2 + 6xy + 12y2 = 28, (2, 1) (ellipse)
Answer:
The equation of the tangent line is [tex]y = -\frac{5}{18}\cdot x +\frac{14}{9}[/tex].
Step-by-step explanation:
Firstly, we obtain the equation for the slope of the tangent line by implicit differentiation:
[tex]2\cdot x + 6\cdot y + 6\cdot x \cdot y' + 24\cdot y \cdot y' = 0[/tex]
[tex]2\cdot (x + 3\cdot y) + 6\cdot (x + 4\cdot y) \cdot y' = 0[/tex]
[tex]6\cdot (x + 4\cdot y) \cdot y' = -2\cdot (x+3\cdot y)[/tex]
[tex]y' = -\frac{1}{3}\cdot \left(\frac{x + 3\cdot y}{x + 4\cdot y} \right)[/tex] (1)
If we know that [tex](x,y) = (2, 1)[/tex], then the slope of the tangent line is:
[tex]y' = -\frac{1}{3}\cdot \left(\frac{2+3\cdot 1}{2 + 4\cdot 1} \right)[/tex]
[tex]y' =-\frac{5}{18}[/tex]
By definition of tangent line, we determine the intercept of the line ([tex]b[/tex]):
[tex]y = m\cdot x + b[/tex]
[tex]b = y - m\cdot x[/tex] (2)
If we know that [tex](x,y) = (2,1)[/tex] and [tex]m = -\frac{5}{18}[/tex], then the intercept of the tangent line is:
[tex]b = 1 - \left(-\frac{5}{18} \right)\cdot (2)[/tex]
[tex]b = \frac{14}{9}[/tex]
The equation of the tangent line is [tex]y = -\frac{5}{18}\cdot x +\frac{14}{9}[/tex].
Which statement is true regarding the functions on the
graph?
f(6) = g(3)
f(3) = g(3)
f(3) = g(6)
f(6) = g(6)
Answer:
f(3) = g(3)
Step-by-step explanation:
on the graph the only point, where both lines cross (both functions create the same functional value) is at x=3.
since both lines have the same y-value there, we express this in math by the "=" sign. and both functions have the same input value (x=3) there.
Which descriptions from the list below accurately describe the relationship
between AABC and ADEF? Check all that apply.
E
37
B
10
8
5 37
4
534 D
A 3 C
53°
D
6
F
A. Same area
O B. Same size
C. Congruent
D. None of the above
Hi
Answer:
D. None of the above
Step-by-step explanation:
Both triangles have the same shape but different size. Their area cannot be the same. Also, the ratio of their corresponding side lengths are the same.
Thus:
8/4 = 10/5 = 6/3 = 2
This implies that both triangles are similar.
Therefore, both triangles cannot have the same area, they are not of the same size and cannot be congruent to each other.
In golf, scores are often written in relationship to par, the average score for a round at a certain course. Write an integer to represent a score that is 7 under par.
Answer:
-7
Step-by-step explanation:
If it is 7 below (a key word, which you can connect to 'negative'), then you just write it as -7.
If f(x) = 4^x-8 and g(x) = 5x+6, find (f + g)(x)
A. (F+g)(x) = -4^x - 5x + 2
B.(F+g)(x) = 4^x + 5x - 2
C.(F+g)(x) = 4^x - 3x + 6
D.(F+g)(x) = 9x - 2
Hey there!
We are given two functions - one is Exponential while the another one is Linear.
[tex] \large{ \begin{cases} f(x) = {4}^{x} - 8 \\ g(x) = 5x + 6 \end{cases}}[/tex]
1. Operation of Function
(f+g)(x) is a factored form of f(x)+g(x). We can common factor out x. Therefore:[tex] \large{(f + g)(x) = f(x) + g(x)}[/tex]
2. Substitution
Next, we substitute f(x) = 4^x+8 and g(x) = 5x+6.[tex] \large{(f + g)(x) = ( {4}^{x} - 8) + (5x + 6)}[/tex]
3. Evaluate/Simplify
Cancel out the brackets and combine like terms.[tex] \large{(f + g)(x) = {4}^{x} - 8 + 5x + 6} \\ \large{(f + g)(x) = {4}^{x} + 5x - 8 + 6} \\ \large{(f + g)(x) = {4}^{x} + 5x - 2}[/tex]
4. Final Answer
(f+g)(x) = 4^x+5x-2what was the original price of the car? MUST SHOW ALL STEPS OF THE PROCESS.
Answer:
19219.48
Step-by-step explanation:
16540x0.162+16540
The original price would be 100%
It was marked down 16.2%
100 % - 16.2% = 83.8%
The price you paid was 83.8% of the original price.
To find the original price divide the amount you paid by the percentage of the original price:
16,540 / 0.838 = 19.737.47
Original price: $19,737.47
a linear model is appropriate for the data in which scatterplot.?
Answer: (b) or 2
Step-by-step explanation: its the only one linear to the best possibility.
Which operation will solve the following word problem? Andrea's class has 20 students and half of the students are studying math, half of these are studying word problems. How many are studying word problems?
Addition
Subtraction
Division
Multiplication
divide .2÷20 =10 10 students are Studing word problems
15. Dravid is a famous cricket player. He has
so far scored 6980 runs in the test matches.
He wishes to complete 10,000 runs: How
many more runs does he need? *
4020 runs
3220 runs
2820 runs
O 3020 runs
Answer:
3020 runs
Step-by-step explanation:
Because he wants 10000 but only has 6980 so you have to minus 6980 from 10000. 10000-6980=3020
so 3020 is the answer
Answer:
3020 runs
Step-by-step explanation:
10,000-6980=3020
Multiply m and 6. Then, add 8.
Answer:
6m + 8 is the answer.
Step-by-step explanation:
( m x 6 ) + 8
= 6m + 8
Find the length of side ab, give your answer to 1 decimal place 62 and 12
Answer:
Huh? is it triangle? and right triangle? if it is its 62^2 = 12^2 + x^2
Step-by-step explanation:
Suppose the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 11 million dollars. If incomes for the industry are distributed normally, what is the probability that a randomly selected firm will earn less than 114 million dollars
Answer:
95.73%
Step-by-step explanation:
Given data:
mean μ= 95
standard deviation, σ = 11
to calculate, the probability that a randomly selected firm will earn less than 114 million dollars;
Use normal distribution formula
[tex]P(X<114)=P(Z<\frac{X-\mu}{\sigma} )[/tex]
Substitute the required values in the above equation;
[tex]P(X<114)=P(Z<\frac{114-95}{11} )\\P(X<114)=P(Z<1.7272)\\P(X<114)=0.9573[/tex]
Therefore, the probability that a randomly selected firm will earn less than 114 million dollars = 95.73%
Suppose a large telephone manufacturer has a problem with excessive customer complaints and consequent returns of the phones for repair or replacement. The manufacturer wants to estimate the magnitude of the problem in order to design a quality control program. How many telephones should be sampled and checked in order to estimate the proportion defective to within 9 percentage points with 89% confidence
Answer:
80 telephones should be sampled
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
The margin of error is of:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
89% confidence level
So [tex]\alpha = 0.11[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.11}{2} = 0.945[/tex], so [tex]Z = 1.6[/tex].
How many telephones should be sampled and checked in order to estimate the proportion defective to within 9 percentage points with 89% confidence?
n telephones should be sampled, an n is found when M = 0.09. We have no estimate for the proportion, thus we use [tex]\pi = 0.5[/tex]
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
[tex]0.09 = 1.6\sqrt{\frac{0.5*0.5}{n}}[/tex]
[tex]0.09\sqrt{n} = 1.6*0.5[/tex]
[tex]\sqrt{n} = \frac{1.6*0.5}{0.09}[/tex]
[tex](\sqrt{n})^2 = (\frac{1.6*0.5}{0.09})^2[/tex]
[tex]n = 79.01[/tex]
Rounding up(as 79 gives a margin of error slightly above the desired value).
80 telephones should be sampled
Your EZ Pass account begins with $80. It costs you $4/day. Write an equation
for the amount in your account (A) in terms of the number of days (D).
Answer:
The equation is [tex]A(d) = 80 - 4d[/tex]
Step-by-step explanation:
Linear function:
A linear function for the amount of money in an account after t days is given by:
[tex]A(d) = A(0) - md[/tex]
In which A(0) is the initial value and m is the daily cost.
Your EZ Pass account begins with $80. It costs you $4/day.
This means that [tex]A(0) = 80, m = 4[/tex]
So
[tex]A(d) = A(0) - md[/tex]
[tex]A(d) = 80 - 4d[/tex]
The accompanying data represent the homework scores for material for a random sample of students in a college algebra course.
36
47
54
58
60
66
66
68
69
70
72
75
77
77
78
78
78
79
79
79
79
79
80
82
84
85
86
86
86
87
89
89
91
92
92
93
93
94
96
99
(a) Construct a relative frequency distribution with a lower class limit of the first class equal to 30 and a class width of 10.
(b) What is the probability a randomly selected student fails the homework (scores less than 70)? (The standard deviation is 13.64)
Simplify your answer to two decimal places.
Answer:
[tex]\begin{array}{ccc}{Class} & {Frequency} & {Relative\ Frequency} &{30-39} & {1} & {0.025} & {40-49} & {1} & {0.025} & {50 - 59} & {2} & {0.050} & {60 - 69} & {5} & {0.125} & {70 - 79} & {13} & {0.325} & {80 - 89} & {10} & {0.250} & {90 - 99} & {8} & {0.200} &{Total} & {40} & {1}\ \end{array}[/tex]
[tex]P(x < 70) = 0.225[/tex]
Step-by-step explanation:
Given
[tex]Lower = 30[/tex]
[tex]Width = 10[/tex]
Solving (a): The relative frequency table
First, we construct the frequency table using the given parameters.
[tex]\begin{array}{cc}{Class} & {Frequency} &{30-39} & {1} & {40-49} & {1} & {50 - 59} & {2} & {60 - 69} & {5} & {70 - 79} & {13} & {80 - 89} & {10} & {90 - 99} & {8} & {Total} & {40}\ \end{array}[/tex]
The relative frequency (RF) is calculated as:
[tex]RF = \frac{Frequency}{Total}[/tex]
Using the above formula to calculate the relative frequency, the relative frequency table is:
[tex]\begin{array}{ccc}{Class} & {Frequency} & {Relative\ Frequency} &{30-39} & {1} & {0.025} & {40-49} & {1} & {0.025} & {50 - 59} & {2} & {0.050} & {60 - 69} & {5} & {0.125} & {70 - 79} & {13} & {0.325} & {80 - 89} & {10} & {0.250} & {90 - 99} & {8} & {0.200} &{Total} & {40} & {1}\ \end{array}[/tex]
Solving (b): [tex]P(x < 70)[/tex]
To do this, we add up the relative frequencies of classes less than 70.
i.e.
[tex]P(x < 70) = [30 - 39] + [40 - 49] + [50 - 59] + [60 - 69][/tex]
So, we have:
[tex]P(x < 70) = 0.025 + 0.025 + 0.050 + 0.125[/tex]
[tex]P(x < 70) = 0.225[/tex]
the volume of a rectangular pyramid with a length of 7 feet, a width of 6 feet, and a height of 4.5 feet.
Answer:
Volume = 63 feet
Step-by-step explanation:
To find the volume of a cube or a rectangular prism, the formula is
(L x W x H)/3. In other words, it is the length of the prism, times the width of the prism, times the height of the prism, whole divided by three, since it has a "triangular shape."
Let's substitute in values for these letters, L, W, and H. You said the length was 7, the width was 6, and the height was 4.5. Therefore, it will result in
(7 x 6 x 4.5)/3. That results in 189/3, which is 63.
Hope this helped!!!
Which of the following must be equal to 30% of x?
3x
(A)
1,000
3x
(B)
100
3x
(C)
10
(D) 3x
Answer:
You can go ahead with option D
Step-by-step explanation:
30% of x will be 3xChloe is working two summer jobs, landscaping and clearing tables. She must work no less than 12 hours altogether between both jobs in a given week. Write an inequality that would represent the possible values for the number of hours landscaping, ll, and the number of hours clearing tables, cc, that Chloe can work in a given week.
Answer:
[tex] L + C \ge 12 [/tex]
Step-by-step explanation:
L = hours landscaping
C = hours clearing tables
The sum of the hours must be no less than 12, so it must be 12 or more.
[tex] L + C \ge 12 [/tex]
The triangles are similar by:
the ASA similarity theorem.
the SSS similarity theorem.
the AAS similarity theorem.
the AA similarity postulate.
the SAS similarity theorem.
Answer:
E. by the SAS similarity theorem.
Step-by-step explanation:
Included angle x° in ∆ ABC ≅ included angle x° in ∆EDC (vertical angles are equal)
DC/BC = 240/150 = 1.6
EC/AC = 320/200 = 1.6
This implies that the ratio of two corresponding sides of both triangles are the same.
Two triangles are considered similar to each other by the SAS similarity theorem of they have a corresponding included angle that is equal and two corresponding sides that are congruent to each other. Therefore, both triangles are similar by the SAS similarity theorem.
Last year, Manuel deposited $7000 into an account that paid 11% interest per year and $1000 into an account that paid 5% interest per year. No withdrawals were made from the accounts. Answer the questions below. Do not do any rounding. (a) What was the total interest earned at the end of year? (b) What was the percent interest for the total deposited?
Answer:
The total interest earned at the end of the year was $ 820, and the interest generated by the total deposited was 10.25%.
Step-by-step explanation:
Given that last year, Manuel deposited $ 7000 into an account that paid 11% interest per year and $ 1000 into an account that paid 5% interest per year, and no withdrawals were made from the accounts, to determine what was the total interest earned at the end of year and what was the percent interest for the total deposited, the following calculations must be performed:
7000 x 0.11 + 1000 x 0.05 = X
770 + 50 = X
820 = X
8000 = 100
820 = X
820 x 100/8000 = X
82,000 / 8,000 = X
10.25 = X
Therefore, the total interest earned at the end of the year was $ 820, and the interest generated by the total deposited was 10.25%.
Starting from point A, a boat sales due south for 4 miles, then due east for 5 miles, then due south again for 6 miles. How far is the boat from point A?
Answer:
17 miles
By adding the miles they have traveled, you get you total distance.
rotation 90 degrees counterclockwise about the origin
Answer:
Point W = (-3, 3)Point X = (-3, 2)Point V = (-2, 3)The rotation rule states that rotation 90° counterclockwise means (x, y) = (-y, x)
The new points would be equal to:
Point W' = (-3, -3)Point X' = (-2, -3)Point V' = (-3, -2)Try graphing it to see if the new points make sense(because I'm not too sure :\)
A robot that makes _/6 of a boat per day will make 5 boats in 6 days
Use the probability distribution for the random variable x to answer the question. x 0 1 2 3 4 p(x) 0.12 0.2 0.2 0.36 0.12 Calculate the population mean, variance, and standard deviation. (Round your standard deviation to three decimal places.)
Answer:
[tex]\mu =2.16[/tex] --- Mean
[tex]\sigma^2 = 1.4944[/tex] -- Variance
[tex]\sigma = 1.222[/tex] --- Standard deviation
Step-by-step explanation:
Given
[tex]\begin{array}{cccccc}x & {0} & {1} & {2} & {3} & {4} \ \\ P(x) & {0.12} & {0.2} & {0.2} & {0.36} & {0.12} \ \end{array}[/tex]
Solving (a): The population mean
This is calculated as:
[tex]\mu = \sum x * P(x)[/tex]
So, we have:
[tex]\mu =0*0.12 + 1 * 0.2 + 2 * 0.2 + 3 * 0.36 + 4 * 0.12[/tex]
[tex]\mu =2.16[/tex]
Solving (b): The population variance
First, calculate:
[tex]E(x^2)[/tex] using:
[tex]E(x^2) = \sum x^2 * P(x)[/tex]
So, we have:
[tex]E(x^2) = 0^2*0.12 + 1^2 * 0.2 + 2^2 * 0.2 + 3^2 * 0.36 + 4^2 * 0.12[/tex]
[tex]E(x^2) =6.160[/tex]
So, the population variance is:
[tex]\sigma^2 = E(x^2) - \mu^2[/tex]
[tex]\sigma^2 = 6.16 - 2.160^2[/tex]
[tex]\sigma^2 = 6.160 - 4.6656[/tex]
[tex]\sigma^2 = 1.4944[/tex]
Solving (c): The population standard deviation
This is calculated as:
[tex]\sigma = \sqrt{\sigma^2}[/tex]
[tex]\sigma = \sqrt{1.4944}[/tex]
[tex]\sigma = 1.222[/tex]
If f(1) =160 and f(n+1)=-2f(n),
What is f(4)?
Answer:
f(n+1=-2f(n)
f(x)=-2f(n)
f(4)
f(4)=-2f(4)
Answer:
f(4) = - 1280
Step-by-step explanation:
Using the recursive rule and f(1) = 60 , then
f(2) = - 2f(1) = - 2 × 160 = - 320
f(3) = - 2f(2) = - 2 × - 320 = 640
f(4) = - 2f(3) = - 2 × 640 = - 1280
Find the value of z such that 0.05 of the area lies to the right of z. Round your answer to two decimal places.
Answer:
[tex]z = 1.6[/tex]
Step-by-step explanation:
Given
[tex]Pr = 0.05[/tex]
Required
The z value to the right
The z value to the right is represented as:
[tex]P(Z > z)[/tex]
So, the probability is represented as:
[tex]P(Z > z) = 0.05[/tex]
From z table, the z value that satisfies the above probability is:
[tex]z = 1.645[/tex]
[tex]z = 1.6[/tex] --- approximated
Which of the following rational functions is graphed below?
Answer:
the answer is d
Step-by-step explanation:
because when we put-1 from x the equation hasn't any value
can someone tell me where i can get a graph that shows this:
Weight Not Over (lbs.) Price
0 $0
1 $2.69
2 $3.17
3 $3.65
4 $4.13
5 $4.61
6 $5.09
7 $5.57
8 $6.03
9 $6.49
10 $6.95
Answer:
Note: See the attached photo for the graph showing Weight Not Over (lbs.) vs Price($). The attached excel file also shows the same graph with the data used to draw it in the excel.
Step-by-step explanation:
In the attached graph, Weight Not Over (lbs.) is on the horizontal axis while Price ($) is on the vertical axis.
From the attached, it can be observed that the graph shows an upward trend. That implies that there is a positive relation between Weight Not Over (lbs.) and Price. That is, as Weight Not Over (lbs.) rises, the Price also rises.
Nikola thinks that the model that reflects the growth of smartphones shipped from manufacturers to stores around the world may be logistic rather than exponential. Do you agree with Nikola
Answer:
When most people have a smartphone, that is, the variable starts getting closer to its capacity, the demand will start to have a slight decrease, until it stabilizes, so yes, Nikola is correct.
Step-by-step explanation:
Exponential model:
The variable keeps growing consistently, at a fixed rate.
Logistic model:
The variable starts growing, but as it approaches a limit, for example, the carry capacity of an environment, the growth rate starts to decrease, until the variable stabilizes at a fixed value.
Growth of smartphones shipped from manufacturers to stores around the world.
When most people have a smartphone, that is, the variable starts getting closer to its capacity, the demand will start to have a slight decrease, until it stabilizes, so yes, Nikola is correct.