An object accelerates downward at a constant rate of 2.00 m/s2 while completely submerged in water. Neglect the viscosity (fluid friction) of the water. The average density of the object is ______ kg/m3. Use g

Answer:

There is no work done.

Explanation:

Given the following data;

Mass = 10 kg

To find the work done?

In Physics, work done can be defined as the amount of energy transfered when an object or body is moved over a distance due to the action of an external force.

Mathematically, work done is given by the formula;

Work done = force * distance

[tex] W = F * d[/tex]

Where,

However, the weight suspended in the air by a strong cable does not move or experience any form of displacement. Therefore, there is no work done.

Answer:

The shortest time in which the driver can complete the operation is approximately 6.32456 seconds

Explanation:

The given parameters are;

The speed of the truck and the car = 35 mi/h ≈ 51.33 ft./s

Let "t" represent the time it takes the car to pass the truck by 40 ft., we have;

The distance covered by the truck = 35 mi/h × t

The distance covered by the car = 35 mi/h × t + 80 ft = 51.33

Let the distance over which the car accelerates = d

We have;

d = 51.33×t₁ + 1/2×5×t₁²

51.33·t + 80 - d = (51.33 + 5·t₁)·(t - t₁) - 1/2·20·(t - t₁)²

51.33 = 51.33 + 5·t₁ - 20·(t - t₁)

∴ 5·t₁ = 20·(t - t₁)

5·t₁ = 20·t - 20·t₁

25·t₁ = 20·t

t₁ = 4·t/5

(51.33 + 5·t₁)·(t - t₁) - 1/2·20·(t - t₁)² + 51.33×t₁ + 1/2×5×t₁² = 51.33·t + 80

We get;

(51.33 + 5·(4·t/5))·(t - (4·t/5)) - 1/2·20·(t - (4·t/5))² + 51.33×(4·t/5) + 1/2×5×(4·t/5)² = 51.33·t + 80

(51.33 + 4·t)·(t/5) - 2·t²/5 + 51.33 × (4·t/5) + 8·t²/5 = 51.33·t + 80

51.33×t/5 + 51.33×4·t/5 + 4·t²/5 - 2·t²/5 + 8·t²/5 = 51.33·t + 80

51.33·t + 10·t²/5 = 51.33·t + 80

2·t² = 51.33·t + 80 - 51.33·t = 80

t² = 80/2 = 40

t = √40 = 2·√10 ≈ 6.32456

The shortest time in which the driver can complete the operation is "t" ≈ 6.32456 seconds

Answer:

friction , magnetism etc

Answer:

The answer is below

Explanation:

a) What are the three longest wavelengths for standing waves on a 270-cm-long string that is fixed at both ends? b. If the frequency of the second-largest wavelength is 50.0 Hz, what is the frequency of the third-longest wave length?

Solution:

a) The wavelengths (λ) for standing waves is given by the formula:

[tex]\lambda_m=\frac{2*length\ of\ string}{m}\\\\Where\ m=1,2,3,.\ .\ .\\\\Given\ that\ length\ of\ string = 270\ cm=2.7\ m,\ m=1,2,3(three\ longest\ wavelengths)\\\\Hence:\\\\\lambda_1=\frac{2(2.7)}{1}=5.4\ m\\\\\lambda_2=\frac{2(2.7)}{2}=2.7\ m \\\\\lambda_3=\frac{2(2.7)}{3}=1.8\ m[/tex]

b) The frequency (f) and wavelength (λ) is given by:

fλ = constant

Hence:

[tex]f_2\lambda_2=f_3\lambda_3\\\\f_2=50\ Hz\\\\2.7*50=f_3(1.8)\\\\f_3=\frac{2.7*50}{1.8} \\\\f_3=75\ Hz[/tex]

The three longest wavelengths for the standing waves on a 270-cm long string that is fixed at both ends are:

1. 5.4 meters.

2. 2.7 meters.

3. 1.8 meters.

Given the following data:

To determine the three (3) longest wavelengths for these standing waves:

Mathematically, the wavelength for standing waves is given by the formula:

[tex]\lambda_n = \frac{2L}{n}[/tex]

Where:

Note: n = 1, 2, and 3.

When n = 1:

[tex]\lambda_1 = \frac{2\times 2.7}{1} \\\\\lambda_1 = 5.4 \;meters[/tex]

When n = 2:

[tex]\lambda_2 = \frac{2\times 2.7}{2} \\\\\lambda_2 = 2.7 \;meters[/tex]

When n = 3:

[tex]\lambda_3 = \frac{2\times 2.7}{3} \\\\\lambda_3 =\frac{5.4}{3} \\\\\lambda_3 = 1.8 \;meters[/tex]

Read more: https://brainly.com/question/14708169

Answer:

3015 N

Explanation:

From Newton's second law, we know that;

F.t = mv

F = force on the ball= ?

m= mass of the ball

v= velocity

F= mv/t

F= 0.045 × 67/0.0010

F= 3.015/0.0010

F= 3015 N

The force exerted by the racket on the ball is 3015 N.

The force exerted by the racket on the ball is given in the formula below.

⇒ Formula:

⇒ Where:

From the question,

⇒ Given:

⇒ Substitute these values into equation 1

Hence, The force exerted by the racket on the ball is 3015 N

Learn more about Force here: https://brainly.com/question/13370981

Answer:

the amplitude of the oscillation is 8 cm

Explanation:

The computation of the amplitude of the oscillation is shown below:

= Length of the spring - length of the equilibrium

= 32 cm - 24 cm

= 8 cm

By deducting the  length of the equilibrium from the length of the spring we can get the amplitude of the oscillation and the same is to be considered

hence, the amplitude of the oscillation is 8 cm

Answer:

[tex]F=1.334*10^-^6[/tex]

Explanation:

From the question we are told that

Mass of Dylan [tex]M_d=75kg[/tex]

Mass of Sarah [tex]M_s=54kg[/tex]

Centers separated by[tex]C=0.45m[/tex]

Generally the equation for solving gravitational force is given by

[tex]F=\frac{G*m_1m_2}{r^2}[/tex]

[tex]F=\frac{6.67*10^-^1^1*75*54}{(0.45)^2}[/tex]

[tex]F=1.334*10^-^6[/tex]

Therefore Gravitational force is given as

[tex]F=1.334*10^-^6[/tex]

The work done is 480 Joules.

Option 3 is correct.

The work done  is computed as multiplication of force and displacement.

Given that,  Force = 20 N

Displacement = 4 meter per second

For 6 second,

Displacement [tex]=4*6=24m[/tex]

                  [tex]Workdone=Force*displacement\\\\Workdone=20*24=480J[/tex]

Learn more:

https://brainly.com/question/21854305

Answer:

a = 9 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f}^{2}=v_{o}^{2} +2*a*x[/tex]

where:

Vf = final velocity = 30 [m/s]

Vo = initial velocity = 0

a = acceleration [m/s²]

x = displacement = 50 [m]

Now replacing:

[tex]30^{2}=0 +2*a*50\\100*a=900\\a=9[m/s^{2} ][/tex]

Answer:

x = 50 N

Explanation:

Given that we have a net force, a mass, and acceleration, we can use the fundamental formula for force found in newton's second law which is F = m × a.

Given a mass of 150 kg, and an acceleration 3.0m/s². We can substitute these two values in our formula to calculate the magnitude of these forces or it's net force to identify the unknown force acting on our known force for this situation to work.

_______

F (Net force) = F2 (Second force which we are given) - F1 (First force) = m × a

m (mass which we are given) = 150 kg

a (acceleration which we are given) = 3.0m/s

________

So F = m × a → F2 - F1 = m × a →

500 - F1 = 150 × 3.0 → 500 - F1 = 450 →

-F1 = -50 → F1 = 50

The three statements that are correct about the mechanical waves are options B, C, and D.

Mechanical waves are produced due to disturbances in any matter. Which clearly indicates that the mechanical waves cannot travel through empty space.

The mechanical waves require matter to transfer energy through oscillation in the matter. So it is true that the waves transfer energy by causing particles of matter to move.

Also, the mechanical waves need matter to transfer energy, the waves can transfer energy through solids, liquids, and gases.

An example of a mechanical wave is the sound produced by the guitar strings.

Learn more about mechanical waves:

https://brainly.com/question/3101711?referrer=searchResults

Answer: See explanation

Explanation:

The density would like be calculated by dividing the mass by volume. This will be:

Density = Mass / Volume

Density = 390 / 50

Density = 7.8g/cm

Answer:

C. 36J

Explanation:

KE = ½ m V²

= ½ × 8 × 3²

= 4 × 9

= 36 J

Hellow!

For this use the next formula:

Vf = Vo + gt

Initial velocity is zero, so the formula simplificate:

Vf = gt

Data:

Vf = Final velocity = ?

g = Gravity = 9.8 m/s²

t = Time = 12 s

Replacing according our data:

Vf = 9.8 m/s² * 12 s

Vf = 117.8 m/s

The final velocity will be 117.8 meters per second.

Answer:

quantity of charge that passes through Anita's window AC, Q = 316800 C

Explanation:

given  data

current I = 11 amps

runs t = 8.0 hours

solution

we get here quantity of charge that passes through Anita's window AC

the quantity of charge passing Q = I × t     .................1

Q =  11 A × ( 8 hr )×  ( 3600 s/hr)

so

quantity of charge that passes through Anita's window AC, Q = 316800 C

The quantity of charge that passes through Anita's window AC, will be

Q = 316800 C

The current is defined as the quantity of charge flowing from the wire per unit time. Also defined as the rate of flow of the charge through any circuit. The formula will be given as:

[tex]\rm I=\dfrac{Q}{t}[/tex]

Now it is given that:

current I = 11 amps

runs t = 8.0 hours

The quantity of charge that passes through Anita's window AC during these 8.0 hours. Will be calculated as:

[tex]Q=I\times t[/tex]

[tex]Q=11\times 8\times 3600[/tex]

[tex]Q=316800 \ C[/tex]

Thus the quantity of charge that passes through Anita's window AC, Q = 316800 C

To know more about Current follow

https://brainly.com/question/24858512

Answer:

1.625g

Explanation:

The half - life of a radioactive substance is the time taken for half of it to decay to half of its original composition.

 For the given specie, the original composition is 26g  and the half life is 15hrs:

                At time 0hrs                    Mass  = 26g

For the first half life at time 15hrs         Mass  = 13g

                                             30hrs        Mass  = 6.5g

                                              45hrs        Mass = 3.25g

                                              60hrs        Mass  = 1.625g

The question is incomplete, here is the complete question:

Which is greater, the energy of one photon of orange light or the energy of one quantum of radiation having a wavelength of [tex]3.36\times 10^{-9}m[/tex]

Answer: The energy of one quantum of radiation having wavelength [tex]3.36\times 10^{-9}m[/tex] is greater than the energy of 1 photon of orange light.

Explanation:

To calculate the energy of one photon, we use the Planck's equation:

[tex]E=\frac{N_Ahc}{\lambda}[/tex]

where,

E = energy of radiation

[tex]N_A[/tex] = Avogadro's number = [tex]6.022\times 10^{23}mol^{-1}[/tex]

h = Planck's constant = [tex]6.626\times 10^{-34}Js[/tex]

c = speed of light = [tex]3\times 10^8 m/s[/tex]

[tex]\lambda}[/tex] = wavelength of radiation

For 1 photon, the term [tex]N_A[/tex] does not appear

[tex]\lambda}[/tex] = 620 nm = [tex]620\times 10^{-9}m[/tex]             (Conversion factor: [tex]1nm=10^{-9}m[/tex] )

Putting values in above equation, we get:

[tex]E=\frac{6.626\times 10^{-34}Js\times 3\times 10^8m/s}{620\times 10^{-9}m}\\\\E=3.206\times 10^{-19}J[/tex]

[tex]\lambda}[/tex] = [tex]3.36\times 10^{-9}m[/tex]

Putting values in above equation, we get:

[tex]E=\frac{6.022\times 10^{23}mol^{-1}\times 6.626\times 10^{-34}Js\times 3\times 10^8m/s}{3.36\times 10^{-9}m}\\\\E=3.56\times 10^{7}J/mol[/tex]

Hence, the energy of one quantum of radiation having wavelength [tex]3.36\times 10^{-9}m[/tex] is greater than the energy of 1 photon of orange light.

Answer:

1.7791 ft^3

Explanation:

The computation of the extra water is as follows;

Here we use the following formula

Volume of the water = ÷ Weight of concrete canoe ÷ value of the weight of the specific water

= 147 lb ÷ 62.4 lb /ft^3

= 2.356 ft^3

Now the volume of water occupied in ultra lightweight

= 36 lb ÷ 62.4 lb /ft^3

= 0.5769 ft^3

Now the water volume displaced is

= 2.356 - 0.5769

= 1.7791 ft^3

Answer:

All objects, irrespective of their mass, experience the same acceleration g when falling freely under the influence of gravity at the same point on the Earth. If gravity is the only force acting on an object, the sum of kinetic energy and gravitational energy is constant. ...

Answer:

Gravity, also called gravitation, in mechanics, the universal force of attraction acting between all matter. ... On Earth all bodies have a weight, or downward force of gravity, proportional to their mass, which Earth's mass exerts on them. Gravity is measured by the acceleration that it gives to freely falling objects.The Earth's gravitational force accelerates objects when they fall. It constantly pulls, and the objects constantly speed up.Gravity is the force of attraction between two objects with mass and is dependent on the distance between these objects. Gravity is the force that repels two objects that have opposite charges. It is dependent upon the charges of the objects.

Explanation:

Answer:

The combination of Earth's elliptical orbit and the tilt of its axis results in the Sun taking different paths across the sky at slightly different speeds each day. This gives us different sunrise and sunset times each day.

Explanation:

Answer:

correct answer is d

The pinhole has a size comparable with the laser wavelength, so the pinhole diffracts the passing laser beam.

Explanation:

The researcher does not have a refraction problem since the medium on both sides of the pinhole is the same with the same refractive index, the problem he is having is with the diffraction of the laser beam through the pinhole, let's analyze the diffraction process that is described by the expression

          a sin θ = m λ

where a is the pinlole size,  λ the wavelength of the laser and m an integer.

The laser extends from the maximum of diffraction to the first zero (m = 1) of diffraction

         sin θ =  λ/a

when analyzing this expression we have some interesting cases

* when  λ « a. the sine approaches zero therefore we are in the case of optical geometry, in this case the laser passes through the hole without being diffracted

* when  λ ≈ a.  the sine function has values ​​between 0 and 1, for which a diffraction of the laser beam occurs, which increases the diameter of the same

* when  λ> a.  The laser does not pass through the gap since the sine cannot have values ​​greater than 1

After this analysis, we review the answers to the exercise to find that the correct answer is d

Answer:

0.1Ns

Explanation:

Impulse is the product of Force and time

Impulse = Force * Time

Given

Force = 10N

Time = 0.01s

Substitute into the formula

Impulse = 10 * 0.01

Impulse = 10 * 1/100

Impulse = 10/100

Impulse = 0.1Ns

hence the impulse of the hammer is 0.1Ns

Acne is a long-lasting condition that affects the sebaceous glands and hair follicles in the middle layer of the skin.Acne is characterized by clogged sebaceous glands, which produce pimples and cysts.

Which part of the integumentary system is responsible for acne?

        To learn more about acne in adolescents refer

        https://brainly.com/question/28430690

        #SPJ2

Answer:

The resistance of a wire is directly proportional to its length and inversely proportional to its cross-sectional area

Explanation:

Answer:

0.135m/s

Explanation:

Using the law of conservation of momentum

m1u1+m2u2 = m1v1 +m2v2

m1 and m2 are the masses

u1 and u2 are the initial velocities

v1 and v2 are thee final velocities

Substitute the given parameters and get v2

0.015(0.225)+0.03(0.18) = 0.015(0.315)+0.03v2

0.003375+0.0054 = 0.004725 + 0.03v2

0.008775 - 0.004725 = 0.03v2

0.00405 = 0.03v2

v2 = 0.00405/0.03

v2 = 0.135m/s

Hence the final velocity of the 0.03kg marble after collision is 0.135m/s

Answer:heat brings it up then down

Explanation:

Complete Question

The speed of a transverse wave on a string of length L and mass m under T is given by the formula

     [tex]v=\sqrt{\frac{T}{(m/l)}}[/tex]

If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string

Answer:

[tex](m/l)=\frac{10}{V^2}[/tex]

Explanation:

From the question we are told that

Speed of a transverse wave given by

[tex]v=\sqrt{\frac{T}{(m/l)}}[/tex]

Maximum Tension is [tex]T=10.0N[/tex]

Generally making [tex](m/l)[/tex] subject from the equation mathematically we have

[tex]v=\sqrt{\frac{T}{(m/l)}}[/tex]

[tex]v^2=\frac{T}{(m/l)}[/tex]

[tex](m/l)=\frac{T}{V^2}[/tex]

[tex](m/l)=\frac{10}{V^2}[/tex]

Therefore the Linear mass in terms of Velocity is given by

[tex](m/l)=\frac{10}{V^2}[/tex]

Answer:

i think its skin..think so this answre help you

Answer:

D-Enhancing memory

Explanation: