Answer:
1840:1
Explanation:
If m is the mass of the electron, and 1840m is the mass of the proton, then:
p₁ = p₂
m₁v₁ = m₂v₂
m v₁ = 1840m v₂
v₁ = 1840 v₂
The kinetic energy of the electron is:
KE₁ = ½ m₁ v₁²
KE₁ = ½ m (1840 v)²
KE₁ = 1692800 mv²
The kinetic energy of the proton is:
KE₂ = ½ m₂ v₂²
KE₂ = ½ (1840m) v₂²
KE₂ = 920 mv²
The ratio of the kinetic energies is:
KE₁ / KE₂
(1692800 mv²) / (920 mv²)
1840:1
A yellow train of mass 100 kg is moving at 8 m/s toward an orange train of mass 200 kg traveling in the opposite direction on the same track at a speed of 1 m/s. What is the initial momentum of the orange train?.......... A. 200 kgm/s B. -200 kgm/s C. 100 kgm/s D. 80 kgm/s
Answer:The answer is option A.
Momentum=mass×velocity.
Orange train=mass is 200 and velocity is 1.
which is 200×1=200kgm/s.
The initial momentum of the orange train is 200 kgm/s.
What is momentum?Momentum is the product of mass and velocity of any object.Momentum is denoted by P.Momentum P = mv , where m = mass and v = velocity.Momentum is a vector quantity.How to calculate momentum of the orange train?
The orange train is having mass of 200 kg and it is travelling with speed of 1 m/s.
So, the orange trains momentum will be ,
P = mv
∴ P = 200 x 1
∴ P = 200 kgm/s
Therefore, the initial momentum of the orange train is 200kgm/s.
Learn more about momentum here -
https://brainly.com/question/22257327
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A point charge Q moves on the x-axis in the positive direction with a speed of A point P is on the y-axis at The magnetic field produced at the point P, as the charge moves through the origin, is equal to What is the charge Q?
The question is missing. Here is the complete question.
A point charge Q moves on the x-axis in the positive direction with a speed of 160 m/s. A point P is on the y-axis at y = + 20mm. The magnetic field produced at point P, as the charge moves through the origin is equal to -0.6μT k. What is the charge Q? [tex]\mu_{0}=4.\pi.10^{-7}[/tex]T.m/A)
Answer: Q = [tex]-0.015.10^{-3}[/tex]C
Explanation: Magnetic Field (B) is a vector field, i.e., has magnitude and direction, and describes the distribution of magnetic force in the space around. It happens when an electrical charge is in movement.
Its magnitude is determined by the formula:
[tex]B = \frac{\mu_{0}}{4.\pi}\frac{Qvsin(\theta)}{r^{2}}[/tex]
where
[tex]\mu_{0}[/tex] is the vacuum permeability constant;
r is the distance between charge and a point you want to know the magnetic field;
θ is the angle between velocity and distance r;
For this question, magnetic field has that magnitude when charge is passing through the origin. So, angle between velocity and distance is 90°.
Calculating to determine charge:
[tex]-0.6.10^{-6} = \frac{4.\pi.10^{-7}}{4.\pi}\frac{Q.160.sin(90)}{(2.10^{-2})^{2}}[/tex]
[tex]-0.6.10^{-6} = 10^{-7}\frac{Q.160.1}{(2.10^{-2})^{2}}[/tex]
[tex]-2.4.10^{-10} = Q.160.10^{-7}[/tex]
[tex]Q = \frac{-2.4.10^{-10}}{160.10^{-7}}[/tex]
[tex]Q = -0.015.10^{-3}[/tex]
Charge Q is [tex]-0.015.10^{-3}[/tex]C or [tex]-0.015[/tex]mC.
Describe two homeostasis mechanisms
Answer:
The interpretation including its given subject is listed in the subsection below on explanatory.
Explanation:
Homeostasis should be any mechanism of self-regulation from which an individual seeks to preserve equilibrium when adapting to requirements better suited towards its existence.
Two mechanisms are given below:
Blood Pressure: Pressure is regulated by either a homeostatic system through which the blood becomes circulated throughout the individual's body.Body Temperature: The body requires multiple forms of heat regulatory oversight such as:Endothermic is something a living creature can hold one's own internal body temperature. Ectothermic is really where the external atmosphere absorbs temperature.a vehicle moving with a uniform a acceleration of 2m/s and has a velocity of 4m/s at a certain time .
what is will its velocity be
a: 1s later
b: 5s later.
Answer:
1 second later the vehicle's velocity will be:
[tex]v(1)= 6\,\,\frac{m}{s} \\[/tex]
5 seconds later the vehicle's velocity will be:
[tex]v(5)=14\,\,\frac{m}{s}[/tex]
Explanation:
Recall the formula for the velocity of an object under constant accelerated motion (with acceleration "[tex]a[/tex]"):
[tex]v(t)=v_0+a\,t[/tex]
Therefore, in this case [tex]v_0=4\,\,\frac{m}{s}[/tex] and [tex]a=2\,\,\frac{m}{s^2}[/tex]
so we can estimate the velocity of the vehicle at different times just by replacing the requested "t" in the expression:
[tex]v(t)=v_0+a\,t\\v(t)=4+2\,\,t\\v(1)=4+2\,(1) = 6\,\,\frac{m}{s} \\v(5)=4+2\,(5)=14\,\,\frac{m}{s}[/tex]
Fill in the nuclide symbol for the missing particle in the following nuclear equation.
_______ → + 0 e1 + 13C6
Answer:
Nitrogen 13
Explanation:
We need fill in the blank the nuclide symbol for the missing particle in the following nuclear equation.
[tex]X\rightarrow ^0e_1+^{13}C_6[/tex]
In this reaction, the emission of positron takes place. The atomic number in the LHS and the RHS should be same. So,
[tex]^{13}_7 N \rightarrow ^0e_1+^{13}C_6[/tex]
So, the LHS have nitrogen 13, a radioactive isotope.
Estimate the distance (in cm) between the central bright region and the third dark fringe on a screen 5.00 m from two double slits 0.500 mm apart illuminated by 500-nm light.
Answer:
1.25cm
Explanation:
Using
Minimum, as dsinစ = (m+1/2) lambda
Third dark fringe m= 2
dsinစ = (2+1/2)lambda
d(y/L)= (5/2) lambda
Y= 5/2* lambda *L/d
So substituting
=[ (500E-9m)(5m)/0.5E-3] 5/2
=0.0125m
= 1.25cm
Explanation:
In a Young experiment two slits are speared by 6(um), the third dark fringe is formed at an angle 5.6°. The distance between slits and viewing screen is 2 (m).
A- What is the frequency of light used for this experiment?
B- What is the distance between second bright fringe and central fringe?
Answer:
A) f = 1.28x10¹⁵ Hz
B) y = 0.20 m
Explanation:
A) The frequency of light can be found as follows:
[tex] f = \frac{c}{\lambda} [/tex]
Where:
c: is the speed of light = 3.0x10⁸ m/s
λ: is the wavelength
The wavelength can be calculated using the following equation:
[tex] sin(\theta) = \frac{\lambda(m - 1/2)}{d} [/tex]
Where:
m = 3, d = 6 μm, θ = 5.6°
[tex] \lambda = \frac{d*sin(\theta)}{m - 1/2} = \frac{6 \cdot 10^{-6} m*sin(5.6)}{3 - 1/2} = 2.34 \cdot 10^{-7} m [/tex]
Now, the frequency is:
[tex] f = \frac{c}{\lambda} = \frac{3.0 \cdot 10^{8} m/s}{2.34 \cdot 10^{-7} m} = 1.28 \cdot 10^{15} Hz [/tex]
Hence, the frequency of light used for this experiment is 1.28x10¹⁵ Hz.
B) The distance between the second bright fringe and central fringe (y) is:
[tex] tan(\theta) = \frac{y}{D} [/tex]
[tex] y = D*tan(\theta) = 2 m*tan(5.6) = 0.20 m [/tex]
Therefore, the distance between the second bright fringe and central fringe is 0.20 m.
I hope it helps you!
A hydraulic press has one piston of diameter 4.0 cm and the other piston of diameter 8.0 cm. What force must be applied to the smaller piston to obtain a force of 1600 N at the larger piston
Answer:
The force is [tex]F_1 = 400.8 \ N[/tex]
Explanation:
From the question we are told that
The first diameter is [tex]d_1 = 4.0 \ cm = 0.04 \ m[/tex]
The second diameter is [tex]d_2 = 8.0 \ cm = 0.08 \ m[/tex]
Generally the first area is
[tex]A_1 = \pi * \frac{d^2_1 }{4}[/tex]
=> [tex]A_1 = 3.142 * \frac{0.04^2}{4}[/tex]
=> [tex]A_1 = 0.00126 \ m^2[/tex]
The second area is
[tex]A_2 = \pi * \frac{d^2_2 }{4}[/tex]
[tex]A_2 = 3.142 * \frac{0.08^2}{4}[/tex]
[tex]A_2 = 0.00503 \ m^2[/tex]
For a hydraulic press the pressure at both end must be equal .
Generally pressure is mathematically represented as
[tex]P = \frac{F}{A}[/tex]
=>
[tex]\frac{F_1}{A_1 } = \frac{F_2}{A_2 }[/tex]
=> [tex]F_1 = \frac{1600}{0.00503} * 0.00126[/tex]
=> [tex]F_1 = 400.8 \ N[/tex]
Convert 37 mg to Dg (Dekagram)
0.37 dg
Explanation:1 dg ....... 100 mg
x dg .........37 mg
x = 1×37/100 = 37/100 = 0.37 dg
What is the root mean square speed of an As4 particle as it is sublimed? (Assume at high temperatures arsenic acts like an ideal gas; the Boltzmann constant, kB, can be approximated as 1.4 x 10-23 J∙K-1) and the kinetic energy of the gas is equal to 3/2kB T
Answer: [tex]v_{rms} =[/tex] 273m/s
Explanation: Root Mean Square Speed of an atom or molecule is the speed of a particle in a gas. It is the average speed a particle in a gas can have.
It can be calculated:
[tex]\frac{1}{2}mv^{2} = \frac{3}{2} k_{B}T[/tex]
[tex]v^{2} = \frac{3k_{B}T}{m}[/tex]
[tex]v = \sqrt{\frac{3k_{B}T}{m}}[/tex]
m is mass of one atom or molecule in kg.
An atom of Arsenic sublimes at 614°C. Converting to Kelvin:
T = 614 + 273 = 887K
Molecular mass of As4 is approximately 0.3kg.
[tex]m = \frac{0.3}{6.10^{23}}[/tex]
[tex]m=5.10^{-25}[/tex]kg
Calculating Root mean square speed :
[tex]v = \sqrt{\frac{3*1.4.10^{-23}*887}{5.10^{-25}}[/tex]
[tex]v = \sqrt{745.08.10^{2}[/tex]
v = 273m/s
The root mean square speed of As4 is approximately 273m/s.
Calculate the force that must be applied to an object weighing 25 pounds for it to be in equilibrium, if it is on a plane inclined at 45 °
Answer:
17.7 lb
Explanation:
Assuming the force is parallel to the incline, draw a free body diagram of the object. There are 3 forces:
Normal force N pushing perpendicular to the incline,
Weight force mg pulling down,
and applied force F pushing parallel to the incline.
Sum the forces in the parallel direction:
∑F = ma
F − mg sin 45° = 0
F = mg sin 45°
F = (25 lb) sin 45°
F = 17.7 lb
Q10. Explain the Retention time, in GC. What will happen to retention time, if you increase the detector temperature
Answer:
The detector temperature doesn't affect retention time
Explanation:
Retention time is one of the chromatographic parameters. Is defined as the time of a compound spends from injection to detection.
A solute in GC is added to the injector where is volatilized. When volatilized, it pass through a column until the detector.
The detector temperature doesn't affect retention time. To change retention time you must change injector temperature or column temperature. An increase in column or injector temperature results in a decrease in retention time.
During which stage of the water cycle does water from the ocean form clouds?
Answer:
Condensation
Explanation:
Condensation is the process by which water vapor in the air is changed into liquid water. Condensation is crucial to the water cycle because it is responsible for the formation of clouds.
Answer:
This process is called condensation.
Explanation:
When a cloud becomes full of liquid water, it falls from the sky as rain or snow.
ANSWER ASAP PLEASEEE Kendra wonders what would happen if the oceans did not exist on Earth. Based on her understanding of the oceans and the water cycle she predicts that Earth would become warmer, with less rain, more clouds, and that living things would not survive. Which part of her prediction is incorrect answers; 1.That living things would not survive 2.That Earth would get warmer 3.That there would be less rain 4.That there would be more clouds
Answer:
that there would be more clouds.
Explanation:
one of the cycles is precipitation. without water there would be no rain and clouds are what causes the rain to come down
Answer:
it's D or 4 that there would be more clouds
Explanation:
hoped it helped!!
A 8700-kgkg boxcar traveling at 14 m/sm/s strikes a second boxcar at rest. The two stick together and move off with a speed of 5.0 m/sm/s.What is the mass of thesecond car?
Answer:
m₂ = 15660 kg
Explanation:
Given that,
Before collision,
Mass of box car 1, m₁ = 8700 kg
Speed of box car 1, u₁ = 14 m/s
Speed of box car 2, u₂ = 0 (at rest)
After collision,
The two stick together and move off with a speed of 5 m/s
Let m₂ is the mass of the second car. As cars stick together, it is a case of inelastic collision. Using the conservation of momentum as follows :
[tex]m_1u_1+m_2u_2=(m_1+m_2)V\\\\8700\times 14+0=(8700+m_2)5\\\\121800=43500+5m_2\\\\121800-43500=5m_2\\\\m_2=\dfrac{78300}{5}\\\\m_2=15660\ kg[/tex]
So, the mass of the second car is 15660 kg.
Answer:
15000 kg
Explanation:
m1v1+m2v2=(m1m2)Vf
8700(15)=(8700+m)5.5
130500=8700+m(5.5)
130500/5.5=8700+m
130500-8700=m
m=15027.3 kg
Julie drives 100 mi to Grandmother's house. On the way to Grandmother's, Julie drives half the distance at 38.0 mph and half the distance at 62.0 mph. On her return trip, she drives half the time at 38.0 mph and half the time at 62.0 mph.A) What is Julie's average speed on the way to grandmother's house?B) What is her average speed in the return trip?
Answer:
A.46.7mph
B.50mph
Explanation:
We know that from the data given
Julie drove 50 miles at a speed of 38 mph, and another 50 miles for 62mph. Thus , for the first 50 miles, she drove for the following time
T1= distance/speed
====> 50/38= 1.3hrs
the next 50 miles, she drove for
T2= 50/62
= 0.8hrs
So average speed is
Totaldistance/ total time
100/2.1
= 46.7mph
B. Because the time she used driving at 35 mph is the same amount of time she used driving at 65 mph, the average speed is just the average of the two speeds given which is
(50+50)/2 = 50mph
Explanation:
Answer:
46.95 mph
50 mph
Explanation:
first, we start by finding the average speed. The average speed if given by the relation
Average Speed = Total distance / Total Time
from the question, we know that
total distance is 100 mi
total time is time of the first distance + time of the second distance
t = (50mi / 38) + (50mi / 62)
t = 1.32 + 0.81
t = 2.13 hrs
Then, the average speed going to grandmothers house will be
Speed = 100mi / 2.13 hrs
Speed = 46.95 mph
on her return trip
speed on the first distance * half the time + speed on the second distance * half the time
x = V1 * t/2 + V2 * t/2
100 = 38 * t/2 + 62 * t/2
100 = 100 * t/2
t/2 = 100/100
t/2 = 1
t = 2 hrs
The average speed then will be, = 100 mi / 2 hrs = 50mph
Give five difference between manometer and barometer
Answer:
Manometer is a measures to the atmospheric measure.
Barometer is a measure to the atmospheric pressure.
Explanation:
Manometer is there are two types (1) closed tube (2) open tube, is filled with liquid water and mercury and the tube.Manometer do not need equal size of the tubes to the open ended manometers.Manometers is simple to attach on this filled to the high pressure gas in the bulb,this gas pressure put on the tube.Manometer is the attach the gas and vacuum gas to the open of the air, its high pressure gas is to the one of end.Manometer are filled the mercury to the heavy liquid manometer filled the liquid water and oil with the mercury.Barometer is to the close ended tube and the glass tube is the open and that a vacuum is the other end.Barometer can the u shaped and the closed ended tubes to the barometers.Barometer is the mercury closed end and vacuum is the tallest point in the liquid.Barometer is also used to be a table or left standing and also be digital and portable traditional glass, may find the digital clock .Barometer are filled the mercury to the high level liquid must be extreme tall in change in atmospheric pressure.A sound source of frequency f moves with constant velocity (less than the speed of sound) through a medium that is at rest. A stationary observer hears a sound whose frequency is appreciably different from f because:________
a. interference effects set up a standing-wave pattern that alters the frequency
b. the wavelength established in the medium is not the same as it would be if the source were at rest.
c. the equation that relates velocity of propagation, frequency, and wavelength of a sound traveling through a medium does not apply in this situation
d. the sound wave travels through the medium with a velocity different from that which it would have if the source were at rest
Answer:
The correct answer is d
Explanation:
In this exercise they ask us which statement is correct, for this we plan the solution of the problem, this is a Doppler effect problem, it is the frequency change due to the relative speed between the emitter and the receiver of sound.
The expression for the Doppler effect of a moving source is
f ’= (v / (v- + v_s) f
From this expression we see that if the speed the sound source is different from zero feels a change in the frequency.
The correct answer is d
Open the Faraday Law simulation and discover what you can about induction. Make a list of ways to cause induction.
Answer:
Current can be induced in a lot of ways. I'll try and list as much of these methods as I can here.
1. Moving a bar magnet relative to a wire coil
2. Moving a wire coil relative to a magnet.
3. Move a wire coil that has electricity flowing though it relative to a wire coil without electricity flowing through it.
4. Moving a current carrying circuit relative to a non-current carrying circuit
5. Rapidly opening and closing the switch of a current carrying circuit beside a non current carrying circuit.
6. Moving a bar magnet through the middle of a wire coil.
7. Moving a wire coil through a magnet
8. Moving a circuit relative to a magnetic field.
The main idea is to cause a change in the magnetic field, or to change the available area of the wire loop, or to change the angle between the field and the loop.
Calculate (in MeV) the total binding energy for 40Ar. Express your answer in mega-electron volts to four significant figures.
Answer:
299.4 MeV
Explanation:
For 40 Ar
Number of neutrons = 22
Number of protons= 18
Mass of each proton = 1.007277 amu
Mass of each neutron= 1.008665 amu
Total mass of protons= 18 × 1.007277 amu = 18.130986 amu
Total mass of neutrons = 22 × 1.008665 amu = 22.19063 amu
Total mass of protons and neutrons= 18.130986 + 22.19063 = 40.321616 amu
Mass defect = 40.321616 amu - 40 amu
Mass defect = 0.321616 amu
Since 931 is the conversion factor from amu to MeV
Binding energy = 0.321616 amu × 931 = 299.4 MeV
Binding energy = 299.4 MeV
An ion has 109 neutrons, 87 protons and 84 electrons. What is the net charge in Coulombs on the ion?
Answer:
4.8E-19C
Explanation:
Charge is calculated by getting the net sum of protons and electrons
So
87protons - 84electrons= +3
So the charge of the ion is +3
But 1proton= 1.6*10^-19C
So charge will be 3 x 1.6E-19C
4.8x10^-19C
A block that weighs 200 N is initially at rest on a horizontal surface where the coefficient of static friction is 0.500 and the coefficient of kinetic friction is not yet known.
A) What is the gravitational force on this block?
B) What is the mass of the block?
C) What is the normal force on this block?
D) What is the smallest force needed to start moving the block?
E) If you were pushing the block with the force you found in C, what force would the block exert on you?
F) If you were pushing the block with the force you found in C, and the block began to accelerate at 1.96 meters per second squared, what is the net force on the block?
G) If the block accelerates at 1.96 meters per second squared, what is the coefficient of kinetic friction?
Answer:
A) W= 200N, B) m = 20.4 kg , C) N = 200 N , D) F = 100 N ,
E) F_reaction = 200 N , F) F _net = 40 N
Explanation:
This exercise can be solved using Newton's second law
A) The gravitational force is the weight of the block
Fg = W = m g
W = 200 N
B) m = W / g
m = 200 / 9.8
m = 20.4 kg
C) Normal is the reaction of the floor to the weight of the block
N-W = 0
N = W
N = 200 N
D) we write Newton's second law on the x-axis
F - fr = 0
F = fr
the friction force equation is
fr = μ_s N
fr = μ_s W
subtitute
F = 0.50 200
F = 100 N
E) As the forces in the natural are in pairs, by Newton's third law or law of action and reaction, the block responds with a force of equal magnitude, but opposite direction
F_reaction = 200 N
F and G) We write Newton's second law
F - fr = m a
fr = N = μ_k mg
F - μ_k m g = m a
μ_k = (F - ma) / mg
μ_k = (200 - 20.4 1.96) / 200
μ_k = 0.8
In general, the coefficient of kinetic friction is lower than the static one
the net force is
F_net = F -fr = F - μ_k W
F_net = 200 - 0.8 200
F _net = 40 N
A car travelling at a constant speed of 70km/h passes a stationary police car. The police car immediately goes on the chase accelerating uniformly to reach a speed of 85km/h in 10s and continues at that speed until it overtakes the other car. Calculate the time taken for the police car to overtake the car?
Answer:
18.24 seconds
Explanation:
First you convert the km/h to m/s, 70km/h=(175/9)m/s,85km/h=(425/18)m/s.
You know it took 10 seconds for the police to reach 85 km/h. Calculate the distance that the car is ahead of the police (175/9)*10=1750/9m. Then by divide 1750/9 with 425/18, you will get the value 8.24. Add the 10 seconds with the 8.24 you will get 18.24 sec which is the total time.
Is the statement "An object always moves in the direction of the net force acting on it" true or false
Answer:
False
Explanation:
This is because according to newtons second law which says the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object. So take for example a net a net force in opposite direction will cause an object to slow down.
velocity vector here is not the same as acceleration vector
Using the Bohr model, find the ionization energy of the ground He ion.
Answer:
54.4ev
Explanation:
Using
E = - me⁴Z²/8Eo²h²n²
Where n= 1
Z= 1
h=6.6E-31Js
me= 9.1x 10-31kg
Eo=8.85E-12m-3 kg-1 s4 A2
So by substituting
E= -(9.1x 10-31kg)⁴x 1²/8(8.85E-12m-3 kg-1 s4 A2)² x (6.6E-31Js)² x 1²
So E= 54.4ev
A teapot with a surface area of 700 cm2 is to be plated with silver. It is attached to the negative electrode of an electrolytic cell containing silver nitrate (Ag+ NO3-). If the cell is powered by a 12.0-V battery and has a resistance of 1.30 , how long does it take for a 0.133-mm layer of silver to build up on the teapot? (The density of silver is 10.5 multiplied by 103 kg/m3.)
2.18) The calorie is a unit of energy defined as the amount of energy needed to raise 1 g of water by 1oC. a) How many calories are required to bring a pot of water at 1oC to a boil
Answer:
Q = 80000 cal
Explanation:
La expresin para el calor es
Q = m [tex]c_{e}[/tex]ce ΔT
el calor especifico del agua es ce= 1 cal/gr ºC
la temperatura de ebullición del agua es Ef = 100ºC y partimos de la temperatura ambiente To= 20 OC
Q = m 1 ( 100 – 20)
q= 80 m
en el ejercicio no se da la masa de agua, pro podemos suponer, pote lleva 1 litros = 100 G
Q = 80 1000
Q = 80000 cal
A sprinter is running a 100m sprint race. The race begins, and stopwatch is started. The sprinter passes the 12m [N] mark at 1.92 s and passes the 59m [N] mark at 7.98s, What was the sprinter's average velocity between the two time marks? Show all your work.
Answer:
velocity = 7.7558 m/s
Explanation:
s = u × t
s - distance u - velocity t - time
59 - 12 = (7.98 - 1.92) *u
47 = ( 6.06) u
u = 7.7558 m/s
When a sprinter is running a 100m sprint race. The race begins, and the stopwatch is started. The sprinter passes the 12m [N] mark at 1.92 s and passes the 59m [N] mark at 7.98s, then the sprinter's average velocity between the two-time marks would be
What is Velocity?The total displacement covered by any object per unit of time is known as velocity. The velocity of an object depends on the magnitude as well as the direction of the object.
the mathematical expression for velocity is given by
velocity = total displacement /time
As given in the problem a sprinter is running a 100m sprint race. The race begins, and the stopwatch is started. The sprinter passes the 12m [N] mark at 1.92 s and passes the 59m [N] mark at 7.98s
The total displacement covered by the sprinter
S = 59-12
S= 47 m
The total time is taken by the sprinter
T= 7.98 -1.92
= 6.06 seconds
Velocity = S/T
=47/6.06
=7.75 m/s
Thus. the average velocity of the sprinter would be 7.75 m/s
Learn more about Velocity from here
brainly.com/question/18084516
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Show that (a)KE=1/2mv2
Answer:
[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{see \: below}}}}}[/tex]
Explanation:
[tex] \underline{ \bold{ \sf{To \: prove \: that \: kinetic \: energy = \frac{1}{2} m {v}^{2} }}}[/tex]
Let us consider, a body of mass ' m ' is lying at rest ( initial velocity = 0 ) on a smooth surface. Let a constant force F displaces this body in its own direction by a displacement ' d '. Let 'v' be it's final velocity. The work done ' W ' by the force is given by :
[tex] \sf{W = FD}[/tex]
⇒[tex] \sf{W = m \: \times a \: \times s} \: \: \: \: \: \: \: \: \: ( \: ∴ \: f \: = \: ma \: ; \: s \: = d)[/tex]
⇒[tex] \sf{W = m \: \times \frac{v - u}{t} \times \frac{u + v}{2} \times t \: \: \: \: \: \: \: \: \: (∴ \: a = \frac{v - u}{t} and \: s = \frac{u + v}{2} \times t}[/tex]
⇒[tex] \sf{W = m \times \frac{ {v}^{2} - {u}^{2} }{2} }[/tex]
⇒[tex] \sf{W = \frac{1}{2} m {v}^{2} \: \: \: \: \: \: \: \: \: \: \: \: (since, \: initial \: velocity(u) = 0)}[/tex]
The work done becomes the kinetic energy of the body. Thus, the kinetic energy of a body of mass ' m : moving with the velocity equal to 'v ' is 1 / 2 mv²
∴ [tex] \sf{KE= \frac{1}{2} m {v}^{2} }[/tex]
[tex] \sf{ \underline{ \bold{ {proved}}}}[/tex]
Hope I helped!
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Two sources emit beams of light of wavelength 550 nm. The light from source A has an intensity of 10 μW/m2, and the light from source B has an intensity of 20 μW/m2. This is all we know about the two beams. Which of the following statements about these beams are correct? A) Beam B carries twice as many photons per second as beam A. B) A photon in beam B has twice the energy of a photon in beam A. C) The frequency of the light in beam B is twice as great as the frequency of the light in beam A. D) A photon in beam B has the same energy as a photon in beam A. E) None of the above statements are true.
Answer:
A) Beam B carries twice as many photons per second as beam A.
Explanation:
If we have two waves with the same wavelength, then their intensity is proportional to their power, or the energy per unit time.
We also know that the amount of photon present in an electromagnetic beam is proportional to the energy of the beam, hence the amount of beam per second is proportional to the power.
With these two facts, we can say that the intensity is a measure of the amount of photon per second in an electromagnetic beam. So we can say that beam B carries twice as more power than beam A, or Beam B carries twice as many photons per second as beam A.