The first hill was 6.17 meters high.
What is the velocity?Velocity is defined as the displacement of the object in a given amount of time and is referred to as velocity.
The work done on Amy and her bicycle by gravitational force can be calculated as follows:
W = mgh
where m is the mass of Amy and her bicycle, g is the acceleration due to gravity (9.8 m/s²), and h is the change in height.
When Amy is coasting down the first hill, her potential energy is converted to kinetic energy, so the work done by gravity is equal to the initial increase in kinetic energy:
W = (1/2)mv²
where v is the velocity. Setting these two equations equal to each other, we get:
mgh = (1/2)mv²
Solving for h, we get:
h = (1/2)v²/g
Plugging in the known values, we get:
h = (1/2)(11 m/s)²/9.8 m/s² = 6.17 m
Thus, the first hill was 6.17 m high.
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Help please how do you do this
The impulse is given as -75 n.s
How to solve for impulseWe would first have to solve for the initial momentum and then the final momentum
The initial momentum is given as 6 x 5 = 30
The final momentum = -9 x 5 = -45
Then the impulse would be the change in momentum which is gotten as
I = Pf - Pi
I = -45 - 30
I = -75
The impulse is given as I = -75
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A student sees a mirror image of a tree in a pond on a very still day. The student is able to see a mirror image of the tree in the pond because light
striking the surface of the water -
bends downward.
bounces off.
becomes brighter.
is absorbed.
Answer:
B.
Explanation:
What causes a reflection in still water?
Reflection in water is caused when light hits the surface of still water and travels to our eye so we can see the complete image and light it's reflecting.
All materials reflect light in some way.
Hope it helped!
what can you say about the direction of the electric field from a negative charge? the electric field from a negative charge points ...
The electric field from a negative charge points is radially inward due to a negative charge.
What is electric field?An electric field is a physical fridge and it by the electric charges that exert a force on other charges extracting or appealing them. Electric electrocuted by electric chargers either stationary or moving the electric field is a vector field meaning that it is both thank you and direction the strength of the electric field is measured in moles per metre electric field and used in a variety of application from our generation to medical treatments.
When you move in an electric field, the electric potential changes since the electric field is a vector field. However, if you move perpendicular to the electric field, the electric potential remains unchanged. This is because the electric field strength is constant in all directions, except in the direction of the electric field. Therefore, if you move perpendicular to the electric field, the electric potential does not change.
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study of bluefish locomotion found that their tail motion produces an average thrust of 0.65 N . Suppose a 1.7 kg bluefish that is coasting horizontally at 0.45 m/s suddenly begins tail motion.
Answer:
he fish would travel a horizontal distance of 1.78 meters during the 2 seconds of tail motion
Explanation:
The initial horizontal velocity of the bluefish is 0.45 m/s. When it begins tail motion, it experiences an additional force due to the thrust produced by the tail. The thrust produced by the tail is 0.65 N. We can use Newton's second law to find the acceleration produced by this force:
F = ma
0.65 N = 1.7 kg * a
a = 0.38 m/s^2
This acceleration will cause the velocity of the bluefish to increase over time. The distance the fish travels during this time can be calculated using the kinematic equation:
d = vit + 1/2 at^2
where d is the distance traveled, vi is the initial velocity, a is the acceleration, and t is the time. Since the fish is initially coasting horizontally, its initial vertical velocity is 0 m/s. Therefore, vi = 0.45 m/s. The time interval for which the fish is tail-motoring is not given, so let's assume it is 2 seconds:
d = (0.45 m/s)(2 s) + 1/2 (0.38 m/s^2)(2 s)^2
d = 1.78 meters
Therefore, the fish would travel a horizontal distance of 1.78 meters during the 2 seconds of tail motion.
A cello string vibrates with a frequency of 64 Hz. If the wavelength of t waves in the string is 180 cm, calculate the wave speed.
Answer:
V=115.2m/s
Explanation:
V=fλ
where v=wave speed,f=frequency,λ=wavelength
convert 180cm to m
1.8m
V=64×1.8
V=115.2m/s
determine for what energy above ef (in terms of kt) the boltzmann approximation has an error less than 1%. (b) give the value of the probability function at this energy
The probability function at this energy where the Boltzmann approximation has an error less than 1%. (b) is given by
P(E) = (1/Z) * (1/100) * exp(-Ef/kT).What is Boltzmann approximation?The Boltzmann approximation states that the probability of a particle being in a state of energy E is proportional to the exponential of negative E divided by kT,
where
k is the Boltzmann constant and
T is the temperature in kelvins.
So, the probability function can be written as:
P(E) = (1/Z) * exp(-E/kT),
where
Z is the partition function, which normalizes the probabilities to add up to 1.
To find the energy above Ef (Ef is the Fermi energy) where the Boltzmann approximation has an error less than 1%, we can solve for the energy E such that P(E) is equal to 1% of the maximum probability P(Ef). We can set the following equality:
P(E) = 0.01 * P(Ef)
P(E) = 0.01 * (1/Z) * exp(-Ef/kT)
Rearranging and substituting the expression for P(E) from the Boltzmann approximation, we get:
E = Ef - kT * ln(100).
So, the energy above Ef where the Boltzmann approximation has an error less of than 1% is Ef minus kT times the natural logarithm of 100.
For the value of the probability function at this energy, we can use the expression for P(E) from the Boltzmann approximation:
P(E) = (1/Z) * exp(-E/kT)
P(E) = (1/Z) * exp(-(Ef - kT * ln(100))/kT)
P(E) = (1/Z) * (1/100) * exp(-Ef/kT).
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A rod of length 2a with total charge Q uniformly distributed along its length is placed along the zaxis with its center at the origin. Find the electric field everywhere?
The electric field due to a charged rod of length 2a with total charge q uniformly distributed along its length, placed along the z axis with its center at the origin.
Through the application of Coulomb's equation and the concept of superposition, we can determine the electric field everywhere caused by the charged rod. The electric field due to a tiny piece of the rod at a point P in space is given by:
dE = k dq / r²
where
k = Coulomb's constant,
dq i= the segment's charge,
r = the segment's distance from point P, and
dE = the segment's contribution to the electric field.
We integrate this formula along the entire length of the rod, from -a to +a, to determine the total electric field at P as follows:
E = ∫ dE = k ∫ dq / r²
where the rod's length is used as the integral. The charge per unit length of the rod, or dq, can be expressed in terms of the charge density as dq = ds, where ds is an element along the rod with an infinitesimal length. r = √(s² + z²) where z is the segment's distance from the z axis, we can also describe r in terms of the distance s from the origin to the segment.
E = k ∫ dq / r^2 = k ∫ λ ds / (s² + z²)
E = k λ z ∫_{-arctan(a/z)}^{arctan(a/z)} dθ / (1 + (a/z)² tan² θ)
E = k λ z / (2πε_0) ∫_{-a/z}^{a/z} du / (1 + u²)
E = k λ z / (2πε_0) [arctan(a/z) - arctan(-a/z)]
E = k λ a / (2πε_0 z√(a² + z²))
This is the equation for the electric field produced by a charged rod of length 2a, arranged along the z axis with its center at the origin, and with total charge q evenly distributed throughout its length. The electric field radiates outward from the rod, and as you move away from the rod, its strength diminishes as 1/r².
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Find the distance traveled by a climber if she climbs 10 meters up and then repels 10 meters back down. Include both magnitude and direction.
Answer:
Explanation:
Let up be the + direction.
Distance is the total length traveled.
Distance = 10 + 10 = 20 m
Displacement = 10 - 10 = 0
Internal hard disk is Select one: a. Removable but not fixed b. Not fixed c. Removable d. Fixed
Internal hard disk is Removable but not fixed. Thus, option A is the correct answer.
What is Hard disk?A hard disk drive (HDD) is a type of non-volatile storage device that stores digital data on rapidly rotating disks (platters) coated with magnetic material. Hard disk drives are commonly used in computers as the primary storage for the operating system and for user data, as well as in other devices such as external hard drives, network-attached storage (NAS) devices, and digital video recorders (DVRs). An HDD consists of one or more disks that spin at high speeds (usually 5,400 or 7,200 RPM) and are read from and written to by magnetic read/write heads that move across the disk surfaces. The data is stored on the disk in magnetic patterns, and the read/write heads can detect and change these patterns to read and write data.
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Vector A⃗ =2i^+3j^ and vector B⃗ =2i^−2j^+4k^ .
The summation of the two vector quantities is [tex]4 \hat{i} + \hat{j} + 4 \hat{k}[/tex].
What is vector quantity?In physics, a vector is a quantity with both a magnitude and a direction. It is often represented by an arrow whose length is proportional to the magnitude of the quantity and whose direction is the same as that of the quantity. A vector does not have position, while having magnitude and direction.
Ordinary quantities with a magnitude but no direction are referred to as scalars in contrast to vectors. For instance, while speed, time, and mass are scalars, displacement, velocity, and acceleration are vector quantities.
Given [tex]\vec{A} =2\hat{i} +3\hat{j}[/tex] and [tex]\vec{B} = 2 \hat{i} -2\hat{j} + 4 \hat{k}[/tex]
Hence,
[tex]\vec{A}+\vec{B} = 4 \hat{i} + \hat{j} + 4 \hat{k}[/tex]
Hence, sum of the two given vector quantity is [tex]4 \hat{i} + \hat{j} + 4 \hat{k}[/tex].
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An electronic package with a surface area of 1 m2 placed in an orbiting space station is exposed to space. The electronics in this package dissipate all 1950 W of its power to space through its exposed surface. The exposed surface has an emissivity of 1.0 and an absorptivity of 0.25. Given: 0 = 5.67x10-8 W/m2K4Determine the steady state exposed surface temperature of the electronic package if the surface is not exposed to the sun. If the surface is not exposed to the sun, the surface
The electronic package's steady state temperature can be calculated using the Stefan-Boltzmann Law, which states that the total energy radiated per unit surface area per unit time is proportional to the fourth power of the temperature.
The electronic package's energy balance equation is as follows:
Power absorbed minus power radiated equals power generated.
where P = absorptivity * incoming radiation P = emissivity * Stefan-Boltzmann constant * T4 Power generated = 1950 W (constant)
Because the surface is not in direct sunlight, we can assume that the incoming radiation is 0 and the power absorbed is 0.
Thus, the energy balance equation becomes:
0 - Power radiated = 1950 W
or
Power radiated = 1950 W
We can use the Stefan-Boltzmann Law to calculate the surface temperature:
Power radiated = emissivity * Stefan-Boltzmann constant * T^4
1950 W = 1 * 5.67 x 10^-8 W/m2K^4 * T^4
T^4 = (1950 / (5.67 x 10^-8))
T = ( (1950 / (5.67 x 10^-8))^(1/4))
The electronic package's steady state temperature is the temperature at which the amount of power generated by the electronics equals the amount of power radiated to space.
Full question.
An electronic package with a surface area of 1 m2 placed in an orbiting space station is exposed to space. The electronics in this package dissipate all 1 kW of its power to the space through its exposed surface. The exposed surface has an emissivity of 1.0 and an absorptivity of 0.25.Given: 0 = 5.67x10-8 W/m2K4 Determine the steady state exposed surface temperature of the electronic package (a) if the surface is exposed to a solar flux of 750 W/m2, and (b) if the surface is not exposed to the sun.
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Help meee!
Please for my physics Home work
. A steel bar 35mm by 35mm in section and 100mm in length is acted upon by a tensile load of 180KN along its longitudinal axis and 400kN and 300kN along the axes of lateral surfaces as shown in figure 2 below. Determine: (i) change in the dimensions of the bar (ii) change in volume Take E = 205 GPa Poisson's ratio (v) = 0.3
(i) The change in length is 8.78 x 10⁻⁸ m and the change in the width is -2.63 x 10⁻⁸ m
(ii) The change in volume of the bar is 7.53 x 10⁻¹¹ m³.
What is the change in the dimensions of the bar?
The bar undergoes elongation and reduction in cross-sectional area due to the applied loads.
Using the formula for longitudinal strain, we can calculate the change in length (ΔL) as follows:
ΔL = (180 × 10³ N) x (100 × 10⁻³ m) / (205 × 10⁹ N/m²)
ΔL = 8.78 x 10⁻⁸ m
The change in width (Δb) can be calculated using the formula for lateral strain:
Δb = -v x ΔL = -0.3 x ΔL
Δb = -0.3 x 8.78 x 10⁻⁸ m
Δb = -2.63 x 10⁻⁸ m
The change in volume can be calculated as follows:
ΔV = (35 × 10⁻³ m) x (35 × 10⁻³ m) x (ΔL + Δb)
ΔV = (35 × 10⁻³ m) x (35 × 10⁻³ m) x (ΔL - 0.3 x ΔL)
ΔV = (35 × 10⁻³ m) x (35 × 10⁻³ m) x (8.78 x 10⁻⁸m -2.63 x 10⁻⁸ m)
ΔV = 7.53 x 10⁻¹¹ m³
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The enthalpy of vaporization of Substance X is 21.0 kj/mol and its normal boiling point is 19. C Calculate the vapor pressure of X at -98. C Round your answer to 2 significant digits.
The vapor pressure of Substance X at -98. C is 1.01 atm, rounded to 2 significant digits.
What is vapor pressure?Vapor pressure is the pressure exerted by a vapor in equilibrium with its liquid or solid phase. It is an indication of a liquid's evaporation rate. It is directly related to the vapor's temperature, and increases with increasing temperature.
ln (P2/P1) = (ΔHvap/R) * ((1/T1) – (1/T2))
where:
P2 = vapor pressure of the substance at temperature T2
P1 = vapor pressure of the substance at temperature T1
ΔHvap = enthalpy of vaporization of the substance
R = ideal gas constant
T1 = normal boiling point of the substance
T2 = temperature at which the vapor pressure is being calculated
In this case, we are trying to calculate the vapor pressure of Substance X at -98. C.
We can plug in the known values into the equation to calculate the vapor pressure of Substance X at -98. C:
ln (P2/P1) = (21.0 kj/mol/8.314 J/mol-K) * ((1/19) – (1/273))
ln (P2/P1) = 0.0087
P2 = exp (0.0087) * P1
P2 = 1.009 * P1
P2 = 1.009 * 1.00 atm (atm is the vapor pressure of Substance X at 19. C, its normal boiling point)
P2 = 1.009 atm
Therefore, the vapor pressure of Substance X at -98. C is 1.01 atm, rounded to 2 significant digits.
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page 29 1.4. how is anthropology changing today? identify the ways anthropologists are adapting to the current era of intensified globalization.
Ways Anthropologists are adjusting by focusing on the ways that migration and communication patterns connect groups and by altering their study methodologies.
The anthropologist's job description:
Anthropologists as well as archaeologists both research the origin, progress, and behaviors of individuals. They examine global linguistic and cultural diversity, physical characteristics, and artifacts found in archaeology. creating research plans that include underrepresented topics. using research methods that make advantage of an extensive study design. promoting the use of collaborative techniques to co-create material
What do anthropologists study?
Anthropology compares human communities across borders and through time. For instance, we contrast the current and earlier legal and religious systems. While contrasting political systems, including family relationships, we look at multinational organizations.
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aball of mass 2kg has a diameter of 50cm falls in the pool. calculate its buoyant force and volume of water displaced?
The buoyant force and volume of water displaced are 19.6 N and 0.065 [tex]m^{3}[/tex] respectively.
Explanation:
According to Archimedes' principal, When a body is immersed fully or partially in a fluid, the the body experiences an upward force called buoyant force which is equal to the weight of fluid dispersed.
Buoyant force ([tex]F_{b}[/tex]) = mg
where, m is the mass of ball
g is acceleration due to gravity i.e. 9.8 [tex]ms^{-2}[/tex]
From the question putting the values we get,
[tex]F_{b} =[/tex] 2×9.8 = 19.6 N
Now,
Water displaced = Volume occupied by the ball
[tex]= \frac{4}{3} \pi r^{3}[/tex] ( as ball is sphere)
{diameter of the ball = 50cm or, 0.5m So radius =[tex]\frac{0.5}{2}[/tex]}
= [tex]\frac{4}{3}*\frac{22}{7}*(\frac{0.5}{2}) ^{3}[/tex]
[tex]=\frac{4}{3}[/tex] × [tex]\frac{22}{7}[/tex]×[tex]\frac{0.125}{8}[/tex]
[tex]= \frac{4}{3}[/tex] × [tex]\frac{22}{7}[/tex] × [tex]\frac{125}{8000}[/tex]
[tex]= 0.065 m^{3}[/tex]
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A small frictionless 4.40 kg cart is released from rest at the top of a hill (assume the hill is perfectly straight and flat, like a ramp). A student is interested in how the motion of the frictionless cart on the hill differs from the motion of a solid cylinder when they are released from rest. The length of the hill from starting point to ending point is 366 m and the point of release for the cart is 53 m above the ending point.
a.) Determine the acceleration of the cart.
b.) Determine the time it takes the cart to travel from the starting point to the ending point.
Now, the solid cylinder with the same mass as the cart and a radius of 0.024 m is released from rest at the top of the hill. Assume there is more than enough friction so that the cylinder rolls without slipping.
c.) Determine the acceleration of the cylinder.
d.) Determine the time it takes the cylinder to travel from the top of the ramp to the bottom.
The acceleration of the cart is 43.12 m/s².
Time it takes the cart to travel from the starting point to the ending point is 3.8 sec.
Acceleration of the cylinder is a = g - (v²)/R.
Time it takes the cylinder to travel from the top of the ramp to the bottom is d = v_0t + 1/2at².
How to calculate acceleration and time?a.) The acceleration of the cart can be calculated using the formula g = 9.8 m/s², where g is the acceleration due to gravity. a = F/m = m × g = 4.40 kg × 9.8 m/s² = 43.12 m/s²
b.) The time it takes the cart to travel from the starting point to the ending point can be calculated using the kinematic equation:
d = v_0t + 1/2at²,
where d is the distance traveled, v_0 is the initial velocity (which is 0 for this case), a is the acceleration (determined in part a), and t is the time.
366 m - 53 m = 313 m
313 = 0t + 1/2(43.12)t² = 1/2(43.12)t²
313 = 21.56t², t² = 313 / 21.56
t² = 14.52, t = √14.52 = 3.8 sec.
c.) The acceleration of the cylinder can be calculated using the formula a = g - (v²)/R, where v is the linear velocity of the cylinder's center of mass and R is the radius of the cylinder.
d.) The time it takes the cylinder to travel from the top of the ramp to the bottom can be calculated using the kinematic equation:
d = v_0t + 1/2at²,
where d is the distance traveled, v_0 is the initial velocity (which is 0 for this case), a is the acceleration (determined in part c), and t is the time.
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A positive point charge Q is located at x=a and a negative point charge −Q is at x=−a. A positive charge q can be placed anywhere on the y-axis.
1) Find an expression for (Fnet)x, the x-component of the net force on q. (Give your answer in terms of Q, q, a, y and constant K.)
The expression for (F net)x when the position of Q and -Q are given, is calculated to be Fx = 2k Qqa/[(a² + y²)]^3/2 x^.
Coulomb's law establishes that the electric force exerted by a point charge q₁ on q₂ is proportional to the values of the charges and inversely proportional to the square of the distance between them. Coulomb obtained this dependence experimentally and introduced a proportionality constant in its law, k = 9 × 10⁹ N m²/c² is coulomb's constant.
Mathematically, Coulomb's law is,
F = k q₁ q₂/r² r^
Let us denote the position of the charge q on the y-axis as 'y'.
The force between 'Q' and'q' is
F₁ = k Qq/(x² + y²)
F₁x = F₁ cosθ
where,
θ is the angle between F₁ and x-axis
F₁x = [k Qq/(x² + y²)] [x/√(x² + y²)]
when x = a, F₁x = k Qqa/[(a² + y²)]^3/2
F₂x = k × -Qq/(a² + y²) × [-a/√(a² + y²)]
Thus, the x-component of the net force,
Fx = 2k Qqa/[(a² + y²)]^3/2 x^
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Rocks in the asteroid belt are traveling around the Sun at a distance of 3.2 Astronomical Units (AU). According to Kepler's Third Law, what is the orbital period of these rocks?
Recall Kepler's Third Law can be written as
P 2 = a 3
if the period is measured in (Earth) years and the distance is measured in AU. Follow the steps in Example 3.1 (just with a different distance value).
Pick the answer that's closest to your result:
The orbital period of the rocks in the asteroid belt is approximately 5.73 years.
What is the average distance, a, between the sun and the asteroid, expressed in astronomical units?
The distance from the Sun to the asteroid belt is between 2-4 AU, or between 300 and 600 million kilometers (186-272 million mi).
Using Kepler's Third Law, we have:
P² = a³
where P is the orbital period of the rocks in years, and a is the semi-major axis of their orbit in astronomical units (AU).
Substituting a = 3.2 AU, we get:
P² = (3.2 AU)³
P² = 32.768 AU³
P = [tex]\sqrt{32.768}[/tex] years
P ≈ 5.73 years
Therefore, the orbital period of the rocks in the asteroid belt is approximately 5.73 years.
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True/Falseat any given point, the net electric field can point in multiple directions at any given point, the net electric field is the vector sum of all component electric fields
At any given point, the net electric field can point in multiple directions at any given point, the net electric field is the vector sum of all component electric fields - False
What is the electric field?The electric field is a measure of the electric force experienced by a charged particle in a specific location. It is a vector field, meaning it has both magnitude and direction.
The electric field at a particular point in space can be visualized as a field of force lines that emanate from positive charges and converge towards negative charges. The strength of the electric field is proportional to the number of force lines and the direction of the field is the direction that a positive test charge would experience a force if placed at that point.
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from a boat, the angle of elevation of the foot of a lighthouse on the edge of a cliff is 34 degrees. if the cliff is 150m high, how far from the base of the cliff is the boat
Answer:
Therefore, the boat is approximately 229.7 meters from the base of the cliff.
Explanation:
Let the horizontal distance between the boat and the foot of the lighthouse be x. Then, the angle of elevation of the top of the lighthouse from the boat is 90° - 34° = 56°.
We can use trigonometry to relate the angles and sides of the right triangle formed by the boat, the foot of the lighthouse, and the top of the lighthouse.
Taking the tangent of the angle of elevation of the foot of the lighthouse, we get:
tan(34°) = opposite/hypotenuse
tan(34°) = 150/x
Multiplying both sides by x, we get:
x * tan(34°) = 150
x = 150 / tan(34°)
x ≈ 229.7 meters
Therefore, the boat is approximately 229.7 meters from the base of the cliff.
the ampacity adjustment factors of 310.15(b)(3)(a) shall not apply to conductors installed in surface metal raceways where the __________.
conductors are not subjected to additional heat due to the raceway installation.that the raceway provides increased cooling and/or ventilation.
What is the ventilation ?Ventilation is the process of providing fresh air to an enclosed space and removing stale air from the same space. It is an important factor in maintaining the quality of air in an environment, both in terms of temperature, humidity, and gaseous pollution. Ventilation is accomplished by either mechanically or naturally moving air from an area of high pressure, where it is typically warmer, to an area of lower pressure, where it is typically cooler. Mechanical ventilation is typically used in closed buildings or spaces, such as homes, offices, and industrial buildings, while natural ventilation relies on the natural flow of air through open windows, doors, and other openings.
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Determination of unknown resistance In order to determine the nature of an electric component (D) we set up an electric circuit as follows → The electric component (D) is connected to a DC generator of adjustable voltage * An ammeter (A) is connected to measure the current I that traverse (D) A voltmeter (V) is connected to measure the voltage U across (D) 1- Draw a diagram that represent this electric circuit.
Here is a straight forward schematic showing the electrical circuit:
DC Generator ----> Component (D) ----> Ammeter (A) ----> Voltmeter (V)
What purpose does a DC generator serve?
The uses of DC generators
These generators are employed to power illumination, excite alternators, and charge cells. In Vdc railroads, they are utilized to supply dc current voltage for diesel generator. They are found in Stepper motor whenever rotary encoder is necessary.
How do DC generators operate?
A copper coil rotated in a magnetosphere induces a voltage, which is how a current (DC) generator operates. The voltage that is produced in the coil depends on how quickly the coil spins in the magnetosphere.
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If a particle is projected with speed 30m/s at an angle tan ¹2, find the greatest height and the corresponding horizontal distance. Find also the time of flight.
Answer:
The greatest height will be as follows:
h = (v²sin2θ)/2g
h = [(30m/s)² (2)] / (2 × 9.8 m/s²)
h = 225m
The corresponding horizontal distance will be as follows:
d = (v² sinθcosθ)/g
d = [(30m/s)² (2 × 1)] / 9.8 m/s²
d = 306m
The time of flight will be as follows:
t = (2v sinθ) / g
t = (2 × 30m/s × 2) / 9.8 m/s²
t = 12.24s
The given problem is a projectile motion problem in Physics. It can be solved using the formulas of kinematics considering the initial velocity of the particle and the angle of projection. Substituting the given values in their respective formulas will determine the time of flight, maximum height, and horizontal distance.
Explanation:The subject matter of this question is based on the physics principle of projectile motion. To solve this problem, we can use some basic formulas of kinematics regarding time of flight, maximum height, and horizontal distance. The angle of projection here is given as \\tan^{-1}2\\ which equals approximately 63.4 degrees.
Firstly, the time of flight (T) can be found using the formula: T = 2u*sin(theta)/g, where 'u' is the initial velocity, 'theta' is the angle of projection, and 'g' is the acceleration due to gravity (approx. 9.81 m/s\^2 ).
Secondly, the greatest height (H) can be found using the formula: H = u^2*sin^2(theta)/2g.
Last but not least, the horizontal distance or the range (R) can be found using the formula: R = u^2*sin(2*theta)/g.
By substituting the given values in these formulas, we will be able to find the time of flight, the greatest height, and the horizontal distance.
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1 point
A man jumps from an airplane and his speed of descent is given by V=50(1-e0.21) meters per second, where t is the
time in seconds. Find the time taken for his speed to reach 40 m/s.
Type your answer.....
The time taken for the man's speed to reach 40 m/s is 8.15 seconds.
What do you mean by speed?
Speed is the rate at which something moves or operates. It is usually measured in units such as miles per hour (mph) or kilometers per hour (kph). Speed is often used to describe the rate of change in a physical quantity, such as the speed of light. It can also be used to describe the rate of change in a process or activity, such as the speed at which a computer can process data.
So,
V = 50(1-e^-0.21t)
40 = 50(1-e^-0.21t)
e^-0.21t = (50-40)/50
-0.21t = ln((50-40)/50)
t = ln((50-40)/50)/-0.21
t ≈ 8.15 seconds
Therefore, the time taken is 8.15 seconds.
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Help meee!
Please for my physics Home work
A 193.4 g sample of water at 13.5°C is heated to steam at 131.1°C. How much heat was absorbed?
A 193.4 g sample of water at 13.5°C is heated to steam at 131.1°C. The amount of heat absorbed will be 96000 KJ.
What is Heat energy?Thermal energy refers to the energy which is contained within a system that is responsible for the temperature. Heat is the flow of thermal energy in the system.
Given that,
Mass, m = 193.4 g
We know that,
Q₁ = mcΔt
Q₁ = 193.4 × 4200 × (131.1 - 13.5)
Q₁ = 193.4 × 4200 × 117.6
Q₁ = 95,524,128 Joules
Now, the latent heat
Q₂ = mL
Q₂ = 193.4 × 2260
Q₂ = 437,084 Joules
Now, the total heat energy required,
Q = Q₁ + Q₂
Q = 95,524,128 + 437,084
Q = 95,961,212 Joules
Therefore, the heat energy is approximately 96000 KJ.
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Your question is incomplete, most probably the complete question is:
Calculate the heat energy required to convert completely a 193.4 g sample of water at 13.5°C is heated to steam at 131.1°C, given that the specific heat capacity of water is 4200 J/(kg°C) and the specific latent heat of vaporization of water is 2260 kJ/kg.
1a) Assuming a flat slope for Weber's Law for weight detection what else might be true? (Note: in the real world humans do not have a flat slope for weight detection so the correct answer might be ridiculous in the real world)A. The JND is always 5 poundsB. The JND is always 10% of the starting weightC. The JND is always equal to the starting weightD. Weber's Law would be proven false1b) What might, in the real world, display a flat slope for weight detection?A. A cameraB. An electric scaleC. A humanD. An airplane
In the real world, humans do not have a flat slope for weight detection. However, some devices such as cameras, electric scales, and airplanes may display a flat slope for weight detection.
For instance, when detecting a change in weight with a hand-held device, humans would be less accurate than with a more sophisticated device such as an electric scale. Furthermore, when detecting a change of weight in an environment with multiple stimuli, such as a room filled with noise, humans may not be able to accurately detect the change at all.
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A light bulb that has a resistance of 3 Ω is connected to a 9 V battery.
What current will the bulb draw? A. 1/3 A B. 3 A C. 6 A D. 12 A E. 27 A
What is the bulb’s power? A. 1/3 W B. 3 W C. 6 W D. 12 W E. 27 W
Answer:
see below
Explanation:
We have ,
R = 3Ω V = 9VSo , from V = iR ,
i = V/R
i = 9/3 A
i = 3A [ option B ]
again, we know that, Power = v²/R , so ;
P = 9²/3 W
P = 27W [ option E ]
and we are done!
how much work did the movers do horizontally pushing a 46 kg crate 10.3 across a rough floor without acceleration, if the effective coefficient of friction was 0.5
The work done is 2321 J.
What is the work that is done?We have to note that the acceleration has to do with the change in the velocity of the object with time. We are told that there is a movement of the crate as we can see. Let us note that the work that is done by the object subtracted from the work done by the friction. Thus we have that;
Work = (46 * 9.8 * 10.3) - (0.5 * 46 *9.8 * 10.3)
Work = 4643 - 2321
= 2321 J
The work that has been done is 2321 J. This is done in moving the object
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