The radius of a circle is 4.5 cm.find the circumference to the nearest tenth

The union of the set elements is [2, ∞)

From the question, we have the following parameters that can be used in our computation:

[2,3] ∪ (3,∞)

The above is a union set

The definition of the union set is that we write out all the elements in the set

Using the above as a guide, we have the following:

[2,3] ∪ (3,∞) = [2, ∞)

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The stem-and-leaf plot is finished as follows:

4| 1 3 7.

The stem-and-leaf plot lists all the measures in a data-set, with the first number as the key, for example:

4|5 = 45.

To complete the stem-and-leaf plot, we must obtain the measures above 40 from the table, which are given as follows:

41, 43 and 47.

Considering the format of the plot, the plot is completed as follows:

4| 1 3 7.

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The given quantity as a single logarithm are as follows:

1. 20.8In(4x)

2. 3cos(3Inx)Inx

3. 4cos'zln'z

Function ve process of state of instruction that text input papa mississippi start x and output function ladki company it's a programming language allow me the code to create the complex command with simple instruction for example function in the used to it to numbers together a generator and i'm number from san also be combined to create more public sequence are instruction.

Express the given quantity as a single logarithm: In(a + b) + In(a - b) - 4Inx = In[(a+b)(a-b)] - 4Inx

Differentiate the function f(x) = 5.2In(4x) - 52: f'(x) = 20.8In(4x)

Differentiate the function f(t) = sin(3Inx): f'(t) = 3cos(3Inx)Inx

Differentiate the function f(x) = ln(4sin'z): f'(x) = 4cos'zln'z

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The requried generalization that can be made is at least half of the trout in both lakes measure between 12 and 18 inches. Option B is correct.

The statistic is the study of mathematics that deals with relations between comprehensive data.

Here,
Interquartile range (IQR), The IQR is the range of the middle 50% of values in a data set. To calculate the IQR, we first need to find the quartiles of the data set.

In the given question we have 3 IQR data sets that jointly vary from 10 to 17 by this we can conclude that, at least half of the trout in both lakes measure between 12 and 18 inches.

Thus, the requried generalization that can be made is at least half of the trout in both lakes measure between 12 and 18 inches. Option B is correct.

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The population of the town is 2564 people after 4 years.

An exponential function's curve is created by a pattern of data called exponential growth, which exhibits higher increases over time.

y = a(1+r)ˣ,

where a is the initial population and r is the rate in decimals and x is the time period.

Given:

The initial population of the town is 1652 people.

And the town's population is tripling every 10 years.

Let y₀ be the initial population, r be the growth rate and t be the time.

So,

y = y₀(e[tex])^{rt}[/tex]

Substituting the values to the function,

y = 1652(e[tex])^{rt}[/tex]

In 10 years,

3y₀= y₀(e[tex])^{rt}[/tex]

r = log(3)/10

Now, the population of town after 4 years is,

y = 1652(e[tex])^{{ln(3)/10} \cdot {t}}[/tex]

y = 2563.64

y ≈ 2564 people.

Therefore, the population is y ≈ 2564, people.

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The equation of the line with Slope: 6/7 that passes through (-5,4) will be 7y = 6x + 58.

A connection between a number of variables results in a linear model when a graph is displayed. The variable will have a degree of one.

The linear equation is given as,

y = mx + c

Where m is the slope of the line and c is the y-intercept of the line.

The slope of the line is 6/7. Then the equation is given as,

y = (6/7)x + c

The equation passes through (-5, 4). Then we have

4 = (6/7) (-5) + c

4 = -30/7 + c

c = 58 / 7

Then the equation is given as,

y = (6/7)x + 58/7

7y = 6x + 58

The equation of the line with Slope: 6/7 that passes through (-5,4) will be 7y = 6x + 58.

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The Bernoulli equation for this particular differential equation is [tex]dy/dx = 6x(y-1)[/tex]  the final solution is [tex]y = x^3 + 1[/tex].

The Bernoulli equation for this particular differential equation is [tex]dy/dx = 6x(y-1)[/tex]. To solve the equation, we first use the substitution u = y – 1. This substitution simplifies the equation to [tex]dy/dx = 6xu[/tex], which is a first-order linear equation with constant coefficients. Now we can use the method for solving Bernoulli equations to find the solution.

We first find the integrating factor, which is [tex]I(x) = exp(∫6xdx)= exp(3x^2)[/tex]. Then we multiply both sides of the equation by I(x) to get [tex]I(x)dy/dx = 6xI(x)u[/tex]. We can now integrate both sides with respect to x and get the general solution of [tex]y = u + 1 = (1/I(x))∫6xI(x)dx + 1[/tex]. After calculating the integral, the final solution is [tex]y = x^3 + 1[/tex].

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Answer:

$2,450

Step-by-step explanation:
2/10, n/30 = discounts of 2%

Credit sale = $2,700
Sale return = $200

Net Receivable =$ 2,700 - $ 200 = $2,500

Discount = 2,500 x %2 = 50
Payment Receipt = $2,500 - $50 = $2,450
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The value of b form the logarithmic equation [tex]log_b}3=0.7925[/tex] is 3.9998688.

In mathematics, the logarithm is the inverse function to exponentiation. That means the logarithm of a number x to the base b is the exponent to which b must be raised, to produce x.

Given that, [tex]log_b}25=2.3219[/tex] and [tex]log_b}3=0.7925[/tex].

Solve the equation by rewriting in exponential form using the definition of a logarithm and simplifying.

We know that, logₐN=x is written exponential form as aˣ=N

Here, [tex]b^{2.3219}=25[/tex]

b=4.00006709

[tex]b^{0.7925}=3[/tex]

b=3.9998688

Therefore, the value of b is 3.9998688.

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People with pica, a type of eating disorder, compulsively consume one or more non-food objects like ice, clay, paper, ash, or soil.

Recurrent episodes of binge eating are the hallmark of a specific type of eating disorder called binge eating disorder. Food addiction and compulsive overeating are both symptoms of this eating disorder. Uncontrollable and quick eating without feeling hungry, as well as negative emotions, depressive symptoms, and guilt over the eating, are prominent symptoms of this illness.

given

People with pica, a type of eating disorder, compulsively consume one or more non-food objects like ice, clay, paper, ash, or soil.

Pica is a kind of pagophagia. It entails consuming ice, snow, or ice water excessively.

Individuals who have pica are not forced to consume ice due to a physical condition like anaemia.

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Answer:

7-12=x

5(x+2)

7-12=-5

5(-5+2)

5(-3)

Step-by-step explanation:

By using the midpoint rule, the value of n to approximate the integral is 9.24.

The integral of a function is a measure of the total area under the curve of the function over a given interval. The Midpoint Rule is a method used to approximate the value of an integral by dividing the interval into smaller subintervals, finding the midpoint of each subinterval, and using the height of the function at the midpoint to estimate the area of the subinterval.

In this specific problem, we are asked to approximate the integral of the function f(x) = sin root x from x = 0 to x = 48, using the Midpoint Rule with n = 4 subintervals. To do this, we divide the interval [0,48] into 4 equal subintervals of width

=> (48-0)/4 = 12.

The midpoint of each subinterval is calculated as follows:

1st subinterval: (0 + 12)/2 = 6

2nd subinterval: (12 + 24)/2 = 18

3rd subinterval: (24 + 36)/2 = 30

4th subinterval: (36 + 48)/2 = 42

Next, we find the height of the function f(x) = sin root x at each of these midpoints.

1st subinterval: sin root 6 = 0.77

2nd subinterval: sin root 18 = 0.97

3rd subinterval: sin root 30 = 0.87

4th subinterval: sin root 42 = 0.71

Finally, we multiply each height by the width of the subinterval to find the estimated area of each subinterval, and add up these areas to obtain the final estimate of the integral:

(0.77 * 12) + (0.97 * 12) + (0.87 * 12) + (0.71 * 12) = 9.24

So, our final estimate of the integral of f(x) = sin root x from x = 0 to x = 48 using the Midpoint Rule with n = 4 is 9.24. Rounding to 4 decimal places, our answer is 9.2400.

Complete Question:

Use the Midpoint Rule with the given value of n to approximate the integral. Round the answer to four decimal places.

∫0 to 48 sin √x dx, n=4

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Suppose that So, S1, S2,... is a sequence of subsets of N the following sets is guaranteed to be different from all sets in the sequence is S = {n² | n² & Sn}.

Subsets are a part of the mathematical concept of sets. A set is anything that is wrapped in curly braces, such as "a,b,c,d." If set A is a collection of even integers and set B is composed of the numbers 2, 4, and 6, then set A is the superset of set B and set B is said to be a subset of set A. Review Sets Subset and Superset for further details.

Set A is referred to as a subset of Set B if each element of Set A is also present in Set B. In other words, Set B includes Set A.

As an illustration, if set A has the elements X, Y, and set B contains the elements X, Y, and Z, then set A is the subset of set B.

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Answer:

[tex]x+\sqrt{2}[/tex]

Step-by-step explanation:

The conjugate of [tex]x-\sqrt{2}[/tex] would simply be [tex]x+\sqrt{2}[/tex]. All you have to do is simply change the sign to its opposite.

The fith letter Diego will type is the letter a

From the question, we have the following parameters that can be used in our computation:

Letters: a, s, d and f

When the letters are repeated, we have

a s d f a s d f a s d f a s d f a s d f......

using the above as a guide, we have the following:

Fifth letter = a

Hence. the fifth letter is a

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A counterexample that shows that all the integers are not divisible by 3 is given as follows:

2.

The statement for this problem is given as follows:

"All the positive integers are divisible by 3".

The statement is false, as only numbers whose sum of the digits is a multiple of 3 are divisible by 3, hence for example, the number 2 is not divisible by 3.

The counterexample is the statement that proves that a conjecture(another statement) is false, hence the number 2 is the counterexample showing that not all positive statements are divisible by 3.

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The solution is, prime factorization of 756 = 3*2*3*2*3*7

In mathematics, multiplication is a method of finding the product of two or more numbers. It is one of the basic arithmetic operations, that we use in everyday life.

here, we have,

756

we know,

756 = 6*6*21

       =3*2*3*2*3*7

as, we know, 2,3,7 all are prime.

so, prime factorization of 756 = 3*2*3*2*3*7

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Answer:

5025π m³

Step-by-step explanation:

the figure consists of two figures;

a cone and phere

volume of a cone=1/3πr²h

volume of hemisphere=2/3πr³

1/3×π×15×15×37=2775π

2/3×π×15×15×15=2250π

sum up the volumes

2775π+2250π

=5025π m³

The median of 20 is the most accurate to use since the data is skewed.

Option C is the correct answer.

A histogram is a representation of the distribution of data with intervals.

We have,

The data given shows a histogram that is skewed to the right.

Now,

Since the data is skewed.

The median is a better measure of the center of data than the mean.

Now,

Arrange the data in order:

10, 10, 10, 10, 15,15,15,19, 20, 20, 20, 25, 25, 25, 30, 30, 55, 55

Median = middle value.

Median = 20

Thus,

The median of 20 is the most accurate to use since the data is skewed.

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Answer:

your question is a bit confusing...

Step-by-step explanation:

Answer: Option D, "C-E-G-A-Bb-A-G-E" is not an example of a boogie-woogie bass line. Boogie-woogie is a genre of blues music that is characterized by a repetitive bass pattern that usually consists of 8th notes. The bass line is usually made up of the root note, fifth note, and octave of a chord, and it is played in a swung or shuffle rhythm. The most common boogie-woogie bass line consists of the notes of a I-IV-V chord progression in a 12-bar blues structure. Option D deviates from this typical pattern and therefore would not be considered a boogie-woogie bass line.

Step-by-step explanation:

Answer:

[tex]b[/tex] ≈ [tex]7.7[/tex]

Step-by-step explanation:

We need to use the Pythagorean Theorem: [tex]a^2+b^2=c^2[/tex]

In this case we have a and c. So let's plug those into the equation:

[tex](5.7)^2+b^2=(9.6)^2[/tex]

Solve:

[tex]32.49+b^2=92.16[/tex]

Round to the nearest tenth:

[tex]32.5+b^2=92.2[/tex]

Subtract 32.5

[tex]b^2=59.7[/tex]

Find 'b'

[tex]b=\sqrt{59.7}[/tex]

[tex]b[/tex] ≈ [tex]7.7[/tex]

I hope this helped you!

Be safe and have great day! (:

Answer:

Step-by-step explanation:

3+d<3-d

3+d<3-dcancel equal terms

3+d<3-dcancel equal termsd<-d

3+d<3-dcancel equal termsd<-dMove the variable to the left

3+d<3-dcancel equal termsd<-dMove the variable to the leftd+d<0

3+d<3-dcancel equal termsd<-dMove the variable to the leftd+d<0collect like terms

3+d<3-dcancel equal termsd<-dMove the variable to the leftd+d<0collect like terms2d<0

3+d<3-dcancel equal termsd<-dMove the variable to the leftd+d<0collect like terms2d<0divide both sides

3+d<3-dcancel equal termsd<-dMove the variable to the leftd+d<0collect like terms2d<0divide both sidesd<0

The correct answer is option b.The approximate value of pool in that area is $20.000c.

A value that is similar to another value but not exactly equal to it is referred to as an approximation number. When the outcomes of the numerical calculations are unknown, the approximation is applied. They are typically used when greater place value decimal numbers emerge as a result.

Approximate value of a pool in the area = Value of home with a swimming pool in the area - Value of home without a swimming pool in the same area.

Value of home with a swimming pool in the area = $250,000

Value of home without a swimming pool in the same area = $230,000.

The approximate value of pool in the area = 250000 - 230000 = 20000.

Hence, the correct answer is option b. The approximate value of pool in that area is $20.000c.

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The solution of the  the linear equation is y = 3/(x - 9xlnx)

What is the solution to an equation?

In order to make the equation's equality true, the unknown variables must be given values as a solution. In other words, the definition of a solution is a value or set of values (one for each unknown) that, when used as a replacement for the unknowns, transforms the equation into equality.

xy' + y = 3xy², y(1) = -3

This is Bernoulli  equation: y' + (1/x)y = 3y²;

Let u = y^(1 - 2) = 1/y is new function.

Then u' = - y'/y

or

y' = -u'/u²;

y = 1/u.

Substitute all this in our ODE:  - u'/u² +(1/x)/u = 3/u², or u' - (1/x)u = -3.

we get linear, 1st order not homogenies ODE:

integrated factor:

μ = e∫(-1/x)dx = e-lnx = 1/x²

u'·1/x - 1/x2 = -3/x;

(u/x)' = - 3/x; u/x

       = ∫(-3/x)dx;

 u/x = -3lnx + C;

u = - 3xlnx + Cx;

y =1/u = 1/(- 3xlnx + Cx)

To get C ,use initial conditions:

y(1) = 3;

3 = 1/(-3·1·ln1 + C);

C = 1/3;

y = 3/(x - 9xlnx)

The solution of the  the linear equation is y = 3/(x - 9xlnx)

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The solution of the  the linear equation is y = 3/(x - 9xlnx)

What is the solution to an equation?

In order to make the equation's equality true, the unknown variables must be given values as a solution. In other words, the definition of a solution is a value or set of values (one for each unknown) that, when used as a replacement for the unknowns, transforms the equation into equality.

xy' + y = 3xy², y(1) = -3

This is Bernoulli  equation: y' + (1/x)y = 3y²;

Let u = y¹⁻² = 1/y is new function.

Then u' = - y'/y

or

y' = -u'/u²;

y = 1/u.

Substitute all this in our ODE:  - u'/u² +(1/x)/u = 3/u², or u' - (1/x)u = -3.

we get linear, 1st order not homogenies ODE:

integrated factor:

μ = e∫(-1/x)dx = e-lnx = 1/x²

u'·1/x - 1/x2 = -3/x;

(u/x)' = - 3/x; u/x

      = ∫(-3/x)dx;

u/x = -3lnx + C;

u = - 3xlnx + Cx;

y =1/u = 1/(- 3xlnx + Cx)

To get C ,use initial conditions:

y(1) = 3;

3 = 1/(-3·1·ln1 + C);

C = 1/3;

y = 3/(x - 9xlnx)

The solution of the  the linear equation is y = 3/(x - 9xlnx)

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Using the cross product property, the value of d is 5.76.

Proportions are defined as the concept where two or more ratios are set to be equal to each other.

Suppose we have two ratio p : q and r : s.

If both these ratios are proportional, then we can write it as  p : q = r : s or p/q = r/s

Given proportional relation is,

9 / 10=d / 6.4

Doing the cross multiplication,

9 × 6.4 = 10 × d

57.6 = 10d

d = 57.6 / 10

d = 5.76

Hence the solution of the proportion is d = 5.76.

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Answer:

uajajjahajajaaajjsjaja

The time shown is 15:40, which indicates that it is 20 minutes to 4 o'clock in the afternoon.

The time displayed is 15:40, which is consistent with a 24-hour clock. It indicates that there are now 20 minutes left until 6:00.

The time 15:40 is in the afternoon because the afternoon begins at 12:00 and lasts until 18:00.

The 24-hour clock format avoids any doubt regarding AM (morning) or PM (afternoon/evening), it is vital to highlight.

As a result, 15:40 specifies that it is in the afternoon and that there are still 20 minutes until 4 o'clock.

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Answer: C

Step-by-step explanation:

The column on an accounting worksheet that may not balance at the end of an accounting period is the Adjustments column.

The Adjustments column on an accounting worksheet includes all the adjusting entries that are needed to update the accounts before the financial statements are prepared. These adjustments can include accruals, deferrals, depreciation, and other adjustments that need to be made to the accounts to accurately reflect the financial position of the company.

Since the Adjustments column is used to record these adjusting entries, it is possible that this column may not balance at the end of the accounting period, as the adjustments may not perfectly offset each other. However, this is not a problem, as the purpose of the worksheet is to help prepare the financial statements, not to balance each individual column.

Therefore, the correct answer is option D, the Adjustments column.

Answer:

C. The Income Statement

Step-by-step explanation:

The Income Statement column on an accounting worksheet may not balance at the end of an accounting period.

An accounting worksheet is a tool used by accountants to help organize and summarize financial information and to prepare financial statements. The worksheet is typically a multi-column form that includes columns for the unadjusted trial balance, adjustments, adjusted trial balance, income statement, and balance sheet.

The Adjustments column is used to record adjusting entries and to update the account balances to reflect accruals, deferrals, and other accounting adjustments. The Adjusted Trial Balance column is the result of the adjustments made in the Adjustments column and should include all the account balances that will be used to prepare the financial statements.

Answer:

x = 24, y = 12

Step-by-step explanation:

We can use the law of sines to solve for x

The law of sines says the ratio of the length of a side of a triangle to the sine of the angle opposite that side is the same for all sides (and angles)

In this triangle

the side with length 12√3 is opposite 60°

the side with length x is opposite 90°

Using the law of sines,

[tex]\dfrac{12\sqrt{3}}{\sin60}=\dfrac{x}{\sin 90}\\[/tex]

sin 60 = [tex]\dfrac{\sqrt{3}}{2}[/tex]

sin 90 = 1

[tex]\rightarrow \dfrac{12\sqrt{3}}{\dfrac{\sqrt{3}}{2}}=\dfrac{x}{1}\\\\\\x = 12\sqrt{3} \div \dfrac{\sqrt{3}}{2}}\\\\\textrm{When dividing fractions, flip the divisor and multiply}\\\\\rightarrow 12\sqrt{3} \times \dfrac{2}{\sqrt{3}}\\\\\textrm{$\sqrt{3}$ cancels out from numerator and denominator}:\\\\\\\rightarrow x = 12 \times 2 = \boxed{24}\\\\\\[/tex]

To solve for y we can again use the law of sines
[tex]\dfrac{y}{\sin 30} = \dfrac{x}{\sin 90}\\\\\textrm{again, as before $\sin 90$ is 1}\\\\\rightarrow \dfrac{y}{\sin 30} = x\\\\\rightarrow x = \dfrac{y}{\sin 30}\\\\\rightarrow y = x \sin 30\\\\\sin30 = \dfrac{1}{2}[/tex]

So y = x/2 = 24/ 2 = 12

ans:
x = 24, y = 12

Note
Another way to solve this question is to first recognize the triangle as a 30-60-90 right triangle

In a triangle of this kind, if the longest side side is a, the shortest side is a/2, and the third side is √3/2a

We could have solved this in this manner also

Here longest side = x, shortest side is y

The other side is 12√3 = x √3/2

So x = 12√3 ÷ √3/2 = 24 (as in the first method)

y = x/2 = 12

This approach is ok too, I find it less intuitive and we have to remember the ratios