Answer:
a violently exploding star that releases light energy whose intensity can illuminate a whole galaxy.
Explanation:
A Supernova is a violent star explosion that causes the release of light that expands so many times and that is capable of illuminating a galaxy. It marks the end of a star and also results in the release of gamma rays, radio waves, x-rays, and heavy elements. Unlike a nova, a supernova destroys the star where it occurs.
A supernova is classified into Type I and Type II. Type I supernova produces three times more brightness than Type II and it occurs as a white dwarf absorbs hot gas from an associate star. The Type II supernova marks the end of the star. It lacks the ability to produce nuclear energy at its core and results in the collapse of the star.
Why potential energy become equal to kinetic energy at height
Answer:
because potentil energy is redy to go but its bound up
And kinetic energy is in motion
Explanation:
Mars is about 1.5 times further from the Sun than Earth. Compared to Sun as seen from Earth, the Sun as seen on Mars is
Answer:
The Sun on Mars appears two third of the size of the Sun as seen Earth
Explanation:
The distance from the Sun to Mars = 1.5 × The distance from the Sun to Earth
Therefore, compared to the Sun as seen on Earth, we have;
The Sun as seen on Mars = 1.5 × smaller than the Sun as seen on Earth = 2/3 × The size of the Sun as seen on Earth
A system of releases 125kJ of heat while 104kJ of work is done in the system. Calcilate the change om imternal energy (in kJ)
Answer:
DU = 21 KJ
Explanation:
Given the following data;
Quantity of heat = 125 KJ
Work = 104 KJ
To find the change in internal energy;
Mathematically, the change in internal energy of a system is given by the formula;
DU = Q - W
Where;
DU is the change in internal energy.
Q is the quantity of energy.
W is the work done.
Substituting into the formula, we have;
DU = 125 - 104
DU = 21 KJ
_______ is an optical filter that passes light of a specific polarization and blocks waves of other polarizations.
a. Index of refraction
b. Laser
c. Polarizer
This filter picks out a specific polarization, so it makes a lot more sense to call it a polarizer than anything else. (C)
This question is a lot like asking "What color is an orange ?".
When cars travel around a banked (curved) road at the optimum angle,the normal reaction force (n) can provide the necessary centripetal force without the need for a friction force. (a)Describe whar would happen to Optimum banking angle when radius doubles? (b)Describe what would happen to optimum angle when speed doubles? (c)A car negotiate a turn of radius 80cm.What is the optimum banking angle for this curve if the speed is to be equal to 12m/s?
Answer:
(a) The optimum banking Decreases
(b) The optimum banking Increases
(c) The optimum banking is approximately 86.88°
Explanation:
(a) The equation of motion on a banked road is given as follows;
[tex]v = \sqrt{R \cdot g \times \left(\dfrac{tan (\theta) + \mu}{1 - \mu \cdot tan (\theta) }\right) }[/tex]
For no friction, we have;
v = √(R·g·tan(θ))
Where;
R₁ = The radius of the road
g = The acceleration due to gravity ≈ 9.81 m/s² = Constant
θ₁ = The bank angle
μ = The coefficient pf friction = Constant
v = The vehicle's speed
If the radius doubles, for no friction, we have;
v² = R·g·(tan(θ))
tan(θ) = v²/(R·g)
Therefore, when the radius doubles, tan(θ) becomes smaller and therefore, the optimum banking angle θ decreases (becomes smaller)
(b) When the speed doubles, we have;
v₁ = 2·v
∴ tan(θ₁) = (v₁)²/(R·g) = 4·(v)²/(R·g) = 4·tan(θ)
When the speed doubles, tan(θ) increases and therefore, the optimum banking angle θ increases increases
(c) The radius negotiated by the car, R = 80 cm = 0.8 m
The speed of the car, v = 12 m/s
From tan(θ) = v²/(R·g), we have;
tan(θ) = 12²/(0.8 × 9.81) ≈ 18.349
θ ≈ arctan(18.349°) ≈ 86.88°
Elements that typically give up electrons CHECK ALL THAT APPLY
A. are nonmetals
B. have a lower ionization energy
C. include the halogens
D. are metals
Answer:
B. have a lower ionization energy
D. are metals
Explanation:
An atom can be defined as the smallest unit comprising of matter that forms all chemical elements. Thus, atoms are basically the building blocks of matters and as such determines or defines the structure of a chemical element.
Generally, atoms are typically made up of three distinct particles and these are protons, neutrons and electrons.
In Chemistry, electrons can be defined as subatomic particles that are negatively charged and as such has a magnitude of -1.
Valence electrons can be defined as the number of electrons present in the outermost shell of an atom. Valence electrons are used to determine whether an atom or group of elements found in a periodic table can bond with others. Thus, this property is typically used to determine the chemical properties of elements.
Valency can be defined as a measure of the combining power of a chemical element with other atoms to form a molecule or chemical compound.
Typically, valency is measured by the amount of hydrogen atoms that a chemical element can combine with or displace to form a molecule or chemical compound.
Ionization energy can be defined as the minimum energy required to remove or detach an electron from a neutral atom in a gaseous state.
Generally, the ionization energy of chemical elements tend to increase from left to right across a period on the periodic table. This increase is due to the fact that the atomic radius of chemical elements generally decreases across the periodic table, typically from alkali metals (group one elements such as hydrogen, lithium and sodium) to noble gases (group eight elements such as argon, helium and neon) i.e from left to the right of the periodic table. Also, the atomic radius of a chemical element increases down each group of the periodic table, typically from top to bottom (column).
This ultimately implies that, atoms with relatively large atomic radii tend to have a low electron affinity and a low ionization energy.
In conclusion, chemical elements that typically give up electrons are metals because their outermost shell contains excess electrons and have a lower ionization energy.
A dart is thrown horizontally with an initial speed of 19 m/s toward point P, the bull's-eye on a dart board. It hits at point Q on the rim, vertically below P, 0.19 s later. (a) What is the distance PQ
Answer:
Explanation:
The dart will go forward horizontally with velocity of 19 m/s. It will also fall downwards with initial velocity of zero and gravitational acceleration of 9.8 m/s².
Distance PQ covered by the dart can be calculated using the following formula.
s = ut + 1/2 at²
u is initial velocity , a is acceleration and t is time.
Putting the values
s = 0 + 1/2 x 9.8 x .19²
= .1769 m
= 17.69 cm.
Ehy Newton's law of gravitation also called universal law?
Answer:
Gravity is a natural phenomenon that causes all massive objects to attract each other. The magnitude or force of this interaction depends on the masses and distance of the bodies. This causes objects to fall toward Earth, for example, and keep satellites and celestial bodies in their orbits, such as the Earth's orbit around the Sun. Gravity also causes the tidal phenomenon.
In physics, gravity can be approximated by Isaac Newton's laws of gravity. Although the accuracy of the law is sufficient, for example, when calculating the orbits of spacecraft, gravity is best described by Albert Einstein’s general theory of relativity, in which it is considered the curvature of space-time.
In an experiment the mass of a calorimeter is 36.35 g . Express in micrometer ,millimetre and kg.
Answer:
1. 36.35 g = 36.35E15 micrometer.
II. 36.35 g = 363.5 millimetre.
III. 36.35 g = 0.03635 kilogram.
Explanation:
Given the following data;
Mass of calorimeter = 36.35 gramsTo convert the mass in grams (g) to;
I. Micrometer
Conversion:
1 g = 1 exp 15 um
36.35 g = X um
Cross-multiplying, we have;
X = 36.35 * 1 exp 15 = 36.35 exp 15 um
36.35 g = 36.35E15 micrometer
II. Millimetre
Conversion:
1 g = 1 milliliter
36.35 g = X milliliter
Cross-multiplying, we have;
X = 36.35 * 1 = 36.35 milliliter
Next, we would convert milliliter to millimetre;
1 milliliter = 10 millimetre
36.35 milliliter = X millimetre
Cross-multiplying, we have;
X = 36.35 * 10 = 363.5 millimetre
36.35 g = 363.5 millimetre
III. Kilogram
Conversion:
1000 grams = 1 kilogram
36.35 g = X kilogram
Cross-multiplying, we have;
X * 1000 = 36.35 * 1
Dividing both sides by 1000, we have;
X = 36.35/1000 = 0.03635 kilogram
36.35 g = 0.03635 kilogram
Note:
g is the symbol for grams.Exp (E) means exponential = 10um is the symbol for micrometer.As compared with lower kVp exposures, when using high kVp will result in a scattered photon that is of ________ energy. Group of answer choices
Answer:
Increased
Explanation:
kVp is an acronym for kilovoltage peak, and it determines the strength x-ray beam strength, and the quality of the beam, it is a measure of the highest that the x-ray machine produces. A 60 kVp x-ray will produce photons with a maximum energy of 60 kilovolts while a 70 kVp will produce photons having 70 kilovolts as the maximum energy
Therefore, a high kVp exposure will result in scattered photon that is of increased energy compared with a lower kVp exposure.
4. A bullet of mass 30 g is fired from a rifle of mass 5kg at a speed of 259m/s.
a) What is the momentum of the rifle just after the bullet is fired?
b) What is the recoil velocity of the rifle?
Answer:
Rifle Momentum=7.77kg*m/s v'= 1.554 m/s
Explanation:
a) m1v1 + m2v2 = m1v1' + m2v2'
0+0 = 0.03*259 + P(rifle momentum)
solve for P
p= 7.77kg*m/s
b) 7.77= 5*v'
v'= 1.554 m/s
The momentum of the rifle just after the bullet is fired is 7.77 kg.m/s and the recoil velocity of the rifle at the time of firing is 1.554 m/s.
What is momentum?
Momentum of a particle is the product of the mass of the particle and its velocity. Momentum is a vector quantity. It has both the magnitude and direction of motion. According to the Newton's second law of motion, the rate of change of the momentum is equal to the force acting on the particle which is in motion.
Momentum can be calculated by the general formula
p = m.v
where, p = momentum of the particle,
m = mass of the particle,
v = velocity of the particle.
Rifle Momentum= mass × velocity
P = m × v'
a) m1v1 + m2v2 = m1v1' + m2v2'
0+0 = 0.03 × 259 + P(rifle momentum)
0 = 7.77 + P
P = 7.77kg.m/s
b) p = m × v
7.77= 5 × v'
v'= 1.554 m/s
Learn more about Momentum here:
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bakit itinuring angkop na angkop ang mga nilalamab ng ibong adarna sa kalinangan at kulturang pilipino
Answer:
Itinuring na angkop ang mga nilalaman ng Ibong Adarna sa kalinangan at kulturang Pilipino bagama't sinasabi ng marami na isang halaw o huwad na panitikan lamang ito sapagkat makikita dito ang pananampalataya sa Poong Maykapal, mataas na pagpapahalaga sa kapakanan ng pamilya, paggalang ng anak sa magulang, paggalang sa nakatatanda, pagtulong sa nangangailangan at pagpapakita ng lakas ng loob sa oras ng problemang kinakarap. Upang maunawaan ng lubusan buksan ang: brainly.ph/question/512605 brainly.ph/question/112864 brainly.ph/question/1789641Explanation:
#AnswerForTreesa.in which portion of the curve,
1. is the velocity uniform.
2.is the velocity increasing.
3.is velocity decreasing.
4.is acceleration zero.
B. at which point does the body start to move and stop.
________________________
I will mark as brainlist
Answer:
the answer is 4 acceleration is 0
Explanation:
this is because when parallel line is drawn through x axis the velocity will bw uniform
plz brainliest
A marble is rolling across a smooth 1.2 m tall table at a velocity of 3 m/s. How far from the edge of the table does it land? (SHOW ALL OF YOUR WORK)
Answer:
S = 1/2 g t^2 where t is the time to fall 1.2 m
t = (2 S / g)^1/2 = (2 * 1.2 / 9.8) = .495 s
Sy = Vy T = 3 m/sec * .495 sec = 1.48 m distance from edge of table
(Rotational speed has no effect since table is smooth)
if an object is placed at the center of carvature of a convance mirror the image formed is called
Answer:
When the object is placed between centre of curvature and principal focus of a concave mirror the image formed is beyond C as shown in the figure and it is real, inverted and magnified.
A box of tools rests in the back of a pickup truck. The truck accelerates to the north and the box remains at rest in the truck. The direction of the friction force on the box of tools is _____.
Answer:
The direction of friction force is toards north.
Explanation:
A tool box is at rest on the back of a track. The truck is accelerating towards north.
As the frame of reference is acceleratinf so it is a non inertial frame of reference.
Thus, teh toolkit experineces a pseudo force towards the south direction.
According to the question, the toolbox is at rest so the fiction force is balances by teh psheudoforce, and thus teh friction force is acting toards north.
A jet plane lands at a speed of 100 m/s and can accelerate at a maximum rate of -5.00 m/s^2 as it comes to a rest.
(a from the instant the plane touches the runaway, what is the minimum time needed before it can come to a rest?
(b Can this plane land on a runaway that is only 0.800 km long?
shown work pls will reward alot of points
Answer:
a) t = 20 s, b) x = 1000 m, As the runway is only 800 m long, the plane cannot land at this distance
Explanation:
This is a kinematics exercise
a) in minimum time to stop,
v = vo + at
v = 0
t = -v0 / a
we calculate
t = -100 / (5.00)
t = 20 s
b) Let's find the length you need to stop
v² = vo² + 2 a x
x = -v0 ^ 2 / 2a
x = - 100² / 2 (-5.00)
x = 1000 m
As the runway is only 800 m long, the plane cannot land at this distance.
What do you mean by kinematics?
Explanation:
study of motion of an object ...plzz if anyone knies the correct meaning of it ..do comment
13.Suppose a ball of mass m is thrown vertically upward with an initial speed v, its speed decreases continuously till it becomes zero. Thereafter, the ball begins to fall downward and attains the speed u again before striking the ground. It implies that the magnitude of initial and final momentums of the ball are same. Yet, it is not an example of conservation of momentum. Explain why?
Answer:
Law of conservation of momentum is applicable to isolated system (no external force is applied).
In this case, the change in velocity is due to the gravitational force of earth.When the ball is thrown up, negative force of gravity is applied and so the speed becomes zero.After that due to gravitational force the ball falls down with same initial velocity.