ADEF is a dilation of AABC by a scale factor of. Which of the following
proportions verifies that AABC and ADEF are similar?
15
12
5
O A.
DE BC
AB DF
OB.
AB
DE
EF
AC
OC. PRO
DE
ВС
OD.
DE
=
AC
DF

ADEF Is A Dilation Of AABC By A Scale Factor Of. Which Of The Followingproportions Verifies That AABC

Answers

Answer 1

Answer:

c

Step-by-step explanation:

A scale drawing is a reduced form in terms of dimensions of an original image / building / object

the scale drawing is usually reduced at a constant dimension

scale of the drawing = original dimensions / dimensions of the scale drawing

DEF should be three times as big as ABC

AB = 5 ; DE = 5 x 3 = 15

AC = 3 ; DF = 3x 3 = 9

BC = 4 ; EF = 4 X 3 = 12

the options that correspond to this is option c


Related Questions

harleys house has a value of £160000 correct to 2 significant figures
write down the least possible value of the house
write down the greatest possible value of the house

Answers

Answer:

155,000

159,999

Step-by-step explanation:

In order to correct to 2 significant figures, look at the third figure, if the number is greater or equal to 5, add 1 to the ten thousand figure. If this is not the case, add zero. Replace all the figures before the thousand figure with zero. i.e. the hundred ten, unit

e.g. Rounding off 10,999 to the nearest thousand is 11,000

In this example, the least figure, the thousand figure should have to be rounded off to 2 significant figures is 5 and the greatest figure it can have is 9



How many millimeters are there in 6.23 meters?

623 millimeters
623,000 millimeters
6,230 millimeters
62,300 millimeters

Answers

Answer:

6,230 millimeters is your answer

Solve for x.
3x +13

6x + 5
x = [?]

Answers

Answer:

nessa resposta da 10 beijos

Answer:

x = 18

Step-by-step explanation:

The given angles are same- side exterior angles and sum to 180°, that is

6x + 5 + 3x + 13 = 180

9x + 18 = 180 ( subtract 18 from both sides )

9x = 162 ( divide both sides by 9 )

x = 18

Geometric stuff and please explain

Answers

Perimeter = Sum of the sides measures

Perimeter = | AB | + | AT | + | BT |

Perimeter = ( x + 3 ) + ( 4x ) + ( 2x + 2 )

40 = x + 4x + 2x + 3 + 2

Colect like terms

40 = ( 1 + 4 + 2 )x + ( 3 + 2 )

40 = 7x + 5

Subtract both sides - 5

40 - 5 = 7x + 5 - 5

35 = 7x

Switch sides

7x = 35

Divide both sides by 7

7x ÷ 7 = 35 ÷ 7

x = 5

_____________________________

AB = x + 3 = 5 + 3 ======》 AB = 8

AT = 4x = 4 × 5 =========》 AT = 20

BT = 2x + 2 = 2(5) + 2 ===》 BT = 12

According to the law of inequality in a triangle, the sum of any two random sides must be greater than the size of the other side which means :

AB + AT > BT

&

AB + BT > AT

&

AT + BT > AB

If the sides is true in the above inequalities, then those sides are able to form a triangle ;

But if even one of the above inequalities is violated, those sides will not be able to form a triangle.

8 + 20 > 12 ( Check )

8 + 12 > 20 ( Nope this inequlity violated )

Thus the measures of the sides can not represent the measures of the sides of a triangle .

And we're done ...

How do you graph x ≤ 5 on a number line? pls help!

Answers

Answer:

From 5, the arrow would be facing left and the dot on 5 would be closed

Step-by-step explanation:

Hope this helps

Find a third-degree polynomial equation with rational coefficients that has roots –5 and 6 + i.

Answers

The coefficients of the polynomial are rational, which means that any non-real roots occur alongside their complex conjugates. In this case, 6+i is a root, so 6-i is also a root.

So the simplest polynomial you can build with these roots is

(x - (-5)) (x - (6 + i )) (x - (6 - i )) = x ^3 - 7x ^2 - 23x + 185

(first choice)

32% of the days in a year the wind blows south.About how many days does the wind blows south?

Answers

Answer:

116 days because 32 percent of 365 is 116

I think the answer is 116 days. 117 if it asks you to round. Hope this helps!

The equation y=1470(1.05)tmodels the value of a painting in dollars (y) in terms of the number of years (t) after it was created. What is the initial value of the painting?

Answers

Answer:

0

Step-by-step explanation:

Because the initial value it the price the painting started at.

Hope this helped

Initial value of the painting as per equation y = 1470(1.05)t is equals to 0.

What is equation?

" Equation is defined as the representation of relation between two quantities using symbol of equality."

According to the question,

Given,

Equation of the given models 'y' = 1470(1.05)t

'y' represents the value of painting

't'  represents the number of years

Initial year 't' = 0 years

Substitute the value of  initial time 't' =0 in the given equation we get,

Initial value of the painting 'y' = 1470 (1.05) (0)

                                                 = 0 dollars

Hence,  initial value of the painting as per equation y = 1470(1.05)t is equals to 0.

Learn more about equation here

https://brainly.com/question/10413253

#SPJ2

Cameron drives a semi-truck for Haulin' Harry's Trucking Company. He earns $0.45 for every mile he drives. If Cameron drove 827.4 miles on his last route, how much money did he earn?

Answers

Answer:

$372.33

Step-by-step explanation:

For 1 mile= $0.45

For 827.4 miles = $0.45 x 827.4

= $372.33

Equation of a line is y = 2x + 5

a) what is the gradient?

b)what is y- intercepted?

c) if the gradient is -3 and y-intercept is 1,then what is the equation of the line?

Answers

Answer:

Step-by-step explanation:

Generally, we have the equation of a straight line as;

y = mx + b

where m is the slope and g is y intercept

a) The gradient is the slope and we have the value as 2

b) The y-intercept here is 5

c) for slope -3 and intercept 1, the equation becomes

y = -3x + 1

b(1)=−7
b(n)=b(n−1)+12 ​

Find the 4th term in the sequence.

Answers

Answer:

4th term = 29

to generate the terms, substitute n = 2, 3, 4 into the rule

noting that b(1) = - 7

b(2) = b(2 - 1) + 12 = b(1) + 12 = -7 + 12 = 5

b(3) = b(3 - 1) + 12 = b(2) + 12 = 5 + 12 = 17

b(4) = b(4 - 1) + 12 = b(3) + 12 = 17 + 12 = 29

help please asap just the answers

a = 2 ; b = −1 and c = −3​

Answers

Solution for above question :

The values are :

[tex]a = 2[/tex]

[tex]b = - 1[/tex]

[tex]c = - 3[/tex]

let's plug the values :

[tex] {c}^{2} + 5ab[/tex]

[tex]( - 3) {}^{2} + (5 \times 2 \times - 1)[/tex]

[tex]9 - 10[/tex]

[tex]-1[/tex]

Therfore, correct answer is :

[tex] \large - 1[/tex]

[tex]\mathfrak{good \: \: luck \: \: for \: \: your \: \: assignment}[/tex]

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]

[tex] \huge\underline{\sf{\red{Problem:}}}[/tex]

9.) Detemine the value of [tex] \sf{ {c}^{2} + 5ab.}[/tex]

[tex] \huge\underline{\sf{\red{Given:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{a = 2}[/tex]

[tex]\quad\quad\quad\quad\sf{b = - 1}[/tex]

[tex]\quad\quad\quad\quad\sf{c = - 3}[/tex]

[tex] \huge\underline{\sf{\red{Solution:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{⟶{c}^{2} + 5ab}[/tex]

[tex]\quad \quad \quad \quad \sf{⟶{( - 3)}^{2} + 5( 2)( - 1)}[/tex]

[tex]\quad \quad \quad \quad \sf{⟶9+ 5( 2)( - 1)}[/tex]

[tex]\quad \quad \quad \quad \sf{⟶9+ 10( - 1)}[/tex]

[tex]\quad \quad \quad \quad \sf{⟶9 - 10 }[/tex]

[tex]\quad \quad \quad \quad ⟶ \boxed{ \sf{ -1}}[/tex]

[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]

[tex]\huge\quad \quad \underline{ \boxed{ \sf{ \red{-1}}}}[/tex]

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]

#CarryOnLearning

[tex]\sf{\red{✍︎ C.Rose❀}}[/tex]

You kick a 3.2 kg ball with a Force of 61 N. Find the acceleration of the
ball in m/s2. Round your answer to 1 decimal place.

Answers

Answer:

[tex]19.4 ms^{-2}[/tex]

Step-by-step explanation:

Newton second law: [tex]\vec F= m\vec a[/tex] We know the force, we know the mass, we can substitute and find the acceleration, which is [tex]61/3.2 = 19.4 ms^{-2}[/tex]

Solve:
2(2x + 3) = -6(x + 9)

Answers

Answer:

The answer is x = -6

Step-by-step explanation:

Answer:

 =  − 6

Step-by-step explanation:

22344=14^3 in logarithmic form

Answers

Answer:

log 14 22,344 = 3

where 14 is the base logarithm

Step-by-step explanation:

Here, we have the base of the log as 14 and the exponent or power as 3

So we have the general form as;

Given y = a^x

Log form is log a y = x

Applying this here, we have

log 14 22,344 = 3

how to solve 3^8 times 3^2

Answers

8x8x8x6= 3,072 ? if i remember doing that right ig lol

Answer:

3072 that what I known as a 10th grader

What is the value of [tex]\frac{81^4}{3^5}[/tex]? (Express your answer in exponential form.)

Answers

Answer:[tex]3^1^1\\[/tex]

Step-by-step explanation:

[tex]\frac{81^4}{3^5}[/tex]

[tex]\frac{3^1^6}{3^5}[/tex]

The base is same power can be add or subtract

[tex]3^1^6^-^5[/tex]

[tex]3^1^1[/tex]

Graph a line with y- intercept of 5 and gradient of -10/3

Answers

Step-by-step explanation:

the equation is:

y= -10/3 x +5

the graph as attached

y is proportional
to x
y = 72 when x = 12
Write a direct
proportion
equation.
A. y = 12x
B. y = 6x
C. 72x = 12
D. 7 x 12 = y

Answers

Answer:

B :) (im sure btw)

Step-by-step explanation:

Find the distance between the points (-6, -8) and (6, -3).
Write your answer as a whole number or a fully simplified radical expression. Do not round.
units

Answers

Answer:

[tex]\displaystyle d = 13[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: [tex]\displaystyle d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}[/tex]

Step-by-step explanation:

Step 1: Define

Identify

Point (-6, -8)

Point (6, -3)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [Distance Formula]:                                                         [tex]\displaystyle d = \sqrt{(6- -6)^2+(-3- -8)^2}[/tex][√Radical] (Parenthesis) Subtract:                                                                   [tex]\displaystyle d = \sqrt{12^2+5^2}[/tex][√Radical] Evaluate exponents:                                                                       [tex]\displaystyle d = \sqrt{144+25}[/tex][√Radical] Add:                                                                                                 [tex]\displaystyle d = \sqrt{169}[/tex][√Radical] Evaluate:                                                                                         [tex]\displaystyle d = 13[/tex]

ASAP 30 POINTS BRAINLIEST IF RIGHT

Answers

Answer:

answer in the link below if you have any questions let me know

Answer:

≈ 0.14

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

[tex]\frac{f(b)-f(a)}{b-a}[/tex]

Here [a, b ] = [ - 1, 3 ] , then

f(b) = f(3) = [tex]\sqrt[3]{3+3}[/tex] = [tex]\sqrt[3]{6}[/tex] ≈ 1.817

f(a) = f(- 1) = [tex]\sqrt[3]{-1+3}[/tex] = [tex]\sqrt[3]{2}[/tex] ≈ 1.260 , then

average rate of change = [tex]\frac{1.817-1.260}{3-(-1)}[/tex] = [tex]\frac{0.557}{4}[/tex] ≈ 0.14 ( to the nearest hundredth )

10 points!!!!! Do 14 and 15 only hurry please.

Answers

Answer:

8. x = 16

9. x = 10

14.

m ∠RSU = 130°

m ∠UST = 50°

15.

m ∠RSU = 124°

m ∠UST = 56°

Step-by-step explanation:

8.

GivenDEF is bisected by EG. That is , ∠DEG = ∠GEF

That is , (x + 15)° = 31°

                x = 31 - 15 =  16

9.

GivenDEF is bisected by EG. That is , ∠DEG = ∠GEF

That is ,

           (6x - 4)° = 56°

            6x = 56 + 4

               6x = 60

                 x = 10

14.

13x + 5x = 180°                       [straight line angles ]

18x = 180

x = 10

m ∠RSU = 130°

m ∠UST = 50°

15.

4x + 12 + 2x = 180°                       [ straight line angles]

6x = 180 - 12

6x = 168

x = 28

m ∠RSU = 4(28) + 12 = 112 + 12 = 124°

m ∠UST = 2(28) = 56°

Answer:

14. 13x+5x

=18x

180(angles on a st. line)= 18x

180/18

=10

RSU=13*10=130

UST=5*10=50

Which of the following systems of linear inequalities is represented by the solution graphed below?

Answers

The answer to this question is option A.

Express 60g as a percentage of 3kg?

Answers

Answer:

2%

60/3000g= ?/100

60×100/3000=2

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in second, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of a second

Answers

10.17 seconds

hope this helps

Where is point B? (im also not good at these at all)

Answers

Answer:

[tex]{ \tt{on \: x - axis : 3}} \\ { \tt{on \: y - axis : 0}} \\ = > \: { \tt{x, \: y}} \\ { \boxed{ \bf{substitute \: for \: x \: and \: y}}} \\ \therefore \: { \boxed{ \bf{answer : } \:{ \tt {(3, \: 0)}}}} \\ \\ { \underline{ \blue{ \tt{⚜becker \: jnr}}}}[/tex]

What is the answer for this

Answers

Answer:

A

Step-by-step explanation:

The green is the starting place, when you move from a point on the green triangle to the blue one, you go 5 to the left and 3 down.

Identify the coefficients in this expression 4+3×+5×​

Answers

Answer:

8

Step-by-step explanation:

4 + 3x + 5x

= 4 + 8x

Hence, coefficient of x is 8 (Ans)

HELP I HAVE 10 MINS

If AB and CD have endpoints at A(- 1,3), B(6,8), C(4, 10) and D(9,3), are AB and CD parallel,
perpendicular, or neither? Explain.

Answers

Answer:

perpendicular

Flying against the wind, an airplane travels 3800 kilometers in 4 hours. Flying with the wind, the same plane travels 3750 kilometers in 3 hours. What is the rate of the plane in still air and what is the rate of the wind?

Answers

Answer:

[tex]V_w =1100[/tex] ---- velocity of wind

[tex]V_a = 150[/tex] --- velocity of airplane

Step-by-step explanation:

Given

[tex]V_a \to[/tex] velocity of airplane

[tex]V_w \to[/tex] velocity of wind

Flying with the wind, the distance (d) is:

[tex]d = (V_w + V_a) * t[/tex]

Where d and t are distance travel and time spent with the wind

So:

[tex]3750 = (V_w + V_a) * 3[/tex]

Divide by 3

[tex]1250 = (V_w + V_a)[/tex]

Flying against the wind, the distance (d) is:

[tex]d = (V_w - V_a) * t[/tex]

Where d and t are distance travel and time against with the wind

So:

[tex]3800 = (V_w - V_a) * 4[/tex]

Divide by 4

[tex]950 = (V_w - V_a)[/tex]

Make [tex]V_w[/tex] the subject

[tex]V_w= 950 + V_a[/tex]

Substitute: [tex]V_w= 950 + V_a[/tex] in [tex]1250 = (V_w + V_a)[/tex]

[tex]1250 = 950 + V_a + V_a[/tex]

[tex]1250 = 950 + 2V_a[/tex]

Collect like terms

[tex]2V_a = 1250 -950[/tex]

[tex]2V_a = 300[/tex]

Divide by 2

[tex]V_a = 150[/tex]

Substitute [tex]V_a = 150[/tex] in [tex]V_w= 950 + V_a[/tex]

[tex]V_w =950 +150[/tex]

[tex]V_w =1100[/tex]

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