Answer:
The weight of the wrench on the Moon is approximately 0.8555 N
Explanation:
On Earth, the acceleration of gravity at sea level is 9.8 m/s^2
then if the wrench weights 5.24 N that means that its mass according to Newton's second law is:
[tex]F = m \, a\\m=\frac{F}{a} \\m=\frac{5.24}{9.8} \, kg\\m=0.5347[/tex]
Now we can use the wrench's mass to find its weight on the Moon, knowing that the acceleration due to gravity there is 1.6 m/s^2:
[tex]W=m\,g\\W=(0.5347) \,(1.6) \,N\\W=0.8555\,\,N[/tex]
Answer:
Explanation:
0.8555
Perform the calculation and report your answer using sig figs. 126.3851 + 7.2 + 73.607 + 15.98
Answer:
223.2
Explanation:
126.3851 + 7.2 + 73.607 + 15.98 = 223.1721
When adding/subtracting, round to the fewest decimal places. 7.2 has 1 number after the decimal point, so we'll round our answer to 223.2.
Where are the most asteroids founds
Answer: Mars and Jupiter
Explanation:
How does a arrow represent displacement
Answer:
An arrow represents displacement. Because it's a vector quantity.
Vector quantity= Direction+Magnitude
When an arrow is put above a unit like
accelerationdisplacementit means that it's a vector quantity.
Hope this helps ;) ❤❤❤
Which acid is naturally found in foods and can be safe to eat? sulfuric acid citric acid hydrochloric acid nitric acid
Answer:
[tex]\Huge \boxed{\mathrm{citric \ acid}}[/tex]
Explanation:
Citric acid is naturally found in foods and can be safe to eat.
Citric acid is present in oranges, lemons, and other types of citrus fruits that we can eat.
The acid that is naturally found in foods and can be safe to eat would be citric acid, therefore the correct answer is option B .
What is a Chemical compound?
A chemical compound is a combination of two or more either similar or dissimilar chemical elements.
For example, H₂O is a chemical compound made up of two oxygen atoms and a single hydrogen atom.
As given in the problem statement we have to find out the acid from the given list of options that are naturally found in foods and can be safe to eat.
The sulphuric acid found in batteries, therefore, is not safe to eat, while the citric acid found in different fruits can be safe to eat.
The correct response is option B since citric acid is a naturally occurring acid that may be consumed without harm.
Learn more about a chemical compound here, refer to the link given below ;
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From a hot air balloon that is at rest at a certain height, a projectile is launched horizontally at 30m / s, how fast will it have after 4s?
A. 50m / s
B. 60m / s
C. 70m / s
D. 80m / s
Answer:
A. 50 m/s
Explanation:
Given in the y direction:
v₀ = 0 m/s
a = 10 m/s²
t = 4 s
Find: v
v = at + v₀
v = (10 m/s²) (4 s) + 0 m/s
v = 40 m/s
In the x direction, the velocity is constant at 30 m/s.
The overall speed is:
v² = (30 m/s)² + (40 m/s)²
v = 50 m/s
The answer:
A) 50 m/s
solve P= a+b+c for B
Answer:
b = - a - c + p
Explanation:
P= a+b+c : move the b over to the other side.
-b + p = a + c : move p over the other side.
-b = a + c - p : now just convert the a + c - p into,
b = -a - c + p
The required solution is b = -a - c + p for arithmetic equation p = a+b+c.
What are Arithmetic operations?Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions. The operator that performs the arithmetic operation is called the arithmetic operator.
What is the equation?The equation is defined as mathematical statements that have a minimum of two terms containing variables or numbers that are equal.
We have been given that equation as
⇒ p = a+b+c
Rearrange the term b to the other side and solve for b
⇒ -b + p = a + c
Rearrange the term p to the other side
⇒ -b = a + c - p
Multiply by (-1) the equation, and we get
⇒ b = -a - c + p
Therefore, the required solution is b = -a - c + p.
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No one can answer this, guaranteed
Answer:
T = 40.08 °C
Explanation:
Given:
m₁ = 0.33 kg, mass of iron horseshoe
T₁ = 693°C, initial temperature of horseshoe
c₁ = 448 J/(g-°C), specific heat
m₂ = 24 kg, mass of water
T₂ = 39°C, initial temperature of water
c₂ = 4186 J/(g-°C), specific heat of water
let T be the equilibrium temperature.
For energy balance,
m₁c₁(T₁ - T) = m₂c₂(T - T₂)
(0.330) * (448) * (693 - T) = (24) * (4186) * (T - 39)
147.84 * (693 - T) = 100,464 * (T - 39)
102,453.12 - 147.84T = 100,464T - 3,918,096
102,453.12 + 3,918,096 = 100,464T - 147.84T
4020549.12 = 100316.16T
T = 40.08 °C
A ball rolling on the floor is an example of motion. a random b) translatory c) multiple d) rotatory
Answer:
Actually it is linear motion but here option is not given so the best option is translators motion.
Explanation:
Hope it will help you :)
Answer:
d rotatory motion
Explanation:
A fisherman notices that his boat is moving up and down periodically, owing to waves on the surface of the water. It takes 3.5 s for the boat to travel from its highest point to its lowest, a total distance of 0.57 m. The fisherman sees that the wave crests are spaced 5.8 m apart.
(a) How fast are the waves traveling?
(b) What is the amplitude of each wave?
(c) If the total vertical distance traveled by the boat were 0.30 m but the other data remained the same, how would the answers to parts (a) and (b) be affected?
Answer:
1.2 m/s
0.31 m
0.15 m
Amplitude is 0.31 m
The waves are traveling at 1.2 m/s
The amplitude would be 0.15 m. The speed would remain the same.
(i think) (but try it)
Please help with theses 2 questions.
1. What is the name of 2F?
2.Using the diagram what is the name of the distance between O and 2F?
[tex] \huge{ \underline{ \underline{ \purple{ \bf{Answer:}}}}}[/tex]
1) Well, we know that lens is made by using 2 concave or convex mirror or sometimes we also use one plane mirror. The spherical mirrors are part of the glass sphere, and hence they have a centre and corresponding radius.
2F is double of focal length when light passes from one surface to another of the lens, so it can be said as the centre of curvature of the one of those spherical lens.
2) Distance between the optical centre and the centre of curvature is a lens can be termed as the radius of curvature of the lens. Well, we don't generally use these in case of lens. But still, the distance between O and 2F is double of the focal length or radius of curvature.
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A bus travels 6 km east and the 8 km south. The magnitude of the bus's resultant displacement is km
Answer:
Displacement, d = 10 km
Explanation:
It is given that,
Distance covered by the bus in east direction is 6 km and the distance covered by the bus in south direction is 8 km.
We need to find the resultant displacement. Displacement is the shortest path covered by an object. It can be given by :
[tex]d=\sqrt{6^2+8^2} \\\\d=\sqrt{36+64}\\ \\d=10\ km[/tex]
So, the displacement of the bus is 10 km.
a child hits a ball with a force of 350 N. (a) If the ball and bat are in contact for 0.12 is, what impulse does the ball receive? (b) what is its change in momentum?
Explanation:
(a) Impulse is force times time.
J = FΔt
J = (350 N) (0.12 s)
J = 42 Ns
(b) Change in momentum is equal to impulse.
J = Δp
Δp = 42 Ns
Answer:
A.4200Ns
Explanation:
Impulse=Force*Time
I=F*t
350N*0.12s
=42Ns
A cross country skier moves 28 meters westward then 62 meters eastward and finally 54 meters westward
Answer:
The answer is below
Explanation:
A cross-country skier moves 28 meters westward, then 62 meters eastward, and finally 54 meters westward.
For this motion, what is the distance moved?
What is the magnitude and direction of the displacement?
Answer:
a) The distance moved is the summation of all the distance, therefore:
Distance = Distance first moved westward + Distance moved eastward + Final distance moved westward = 28 m + 62 m + 54 m = 144 m
Distance = 144 m
b) Displacement is a vector quantity (has magnitude and direction). The displacement is the shortest distance from the starting to final point.
Total distance westward = 28 m + 54 m = 82 m
Total distance eastward = 62 m
Displacement = Total distance westward - Total distance eastward = 82 m - 62 m = 20 m
Displacement = 20 m westward
The displacement has a magnitude of 20 m and the direction is westward
Nail tips exert tremendous pressures when they are hit by hammers because they exert a large force over a small area. What force (in N) must be exerted on a nail with a circular tip of 1.45 mm diameter to create a pressure of 2.33 ✕ 109 N/m2? (This high pressure is possible because the hammer striking the nail is brought to rest in such a short distance.)
Answer:
The force is [tex]F = 3587.2 \ N[/tex]
Explanation:
From the question we are told that
The diameter is [tex]d = 1.4 \ mm = 0.0014 \ m[/tex]
The pressure is [tex]P = 2.33*10^{9} \ N/m^2[/tex]
Generally the radius is mathematically represented as
[tex]r = \frac{0.0014}{2}[/tex]
[tex]r = 0.0007 \ m[/tex]
The cross-sectional area of the nail is mathematically represented as
[tex]A = \pi r^2[/tex]
=> [tex]A = 3.142 * 0.0007 ^2[/tex]
=> [tex]A = 1.54 *10^{-6}[/tex]
Generally the pressure is mathematically represented as
[tex]P = \frac{F}{A}[/tex]
=> [tex]F = P * A[/tex]
=> [tex]F = 1.54*10^{-6} * 2.33*10^{9}[/tex]
=> [tex]F = 3587.2 \ N[/tex]
a solution contains 5.6ml of alcohol mixed with 75ml of water calculate the concentration of this solution.
Answer:
[tex]\huge \boxed{6.948 \%}}[/tex]
Explanation:
Volume of solute (Alcohol) ⇒ 5.6 ml
Volume or solvent (Water) ⇒ 75 ml
Total volume of solution ⇒ 5.6 ml + 75 ml ⇒ 80.6 ml
[tex]\displaystyle \sf Concentration \ of \ solution \ (\%)= \frac{Volume \ of \ solute}{Volume \ of \ solution} \times 100[/tex]
[tex]\displaystyle \sf Concentration \ of \ solution \ (\%)= \frac{5.6}{80.6} \times 100=\frac{5600}{806} = 6.947891[/tex]
The work function for cesium is 1.96 eV. (a) Find the cutoff wavelength for the metal, (b) what is the maximum kinetic energy for the emitted electrons when 425 nm light is incident on the metal
Answer:
Explanation:
λ = hc/¢
Where
h = the Plank constant 6.63 x 10-34 Is
C = 3.0×10^8
¢= 1.96eV
= (6.63×10^-34Js)×(3×10^8)÷( 1.96eV) × 1eV/1.6×10^-19J
= (1.989×10^-25)÷( 1.96eV)×1eV/1.6×10^-19J
= 6.342×10^-7m
B) maximum kinetic energy
= K=hf−ϕ ........1
ϕ = hc
Where
h = constant 6.63 x 10^-34Js
ϕ= 1.96eV
Recall
λ =425×10^-9m
f = frequency in Hz
f = c / λ
C = 3.0×10^8
f = 3.0×10^8 / 425×10^-9m
f = 0.000705Hz
From equation 1
K = (6.63 x 10^-34Js×0.000705Hz )- 6.63 x 10^-34Js×3.0×10^8
= 4.68×10^-37 - 1.989×10^-25
= - 1.98×10^-25J
Mega drives a car from Town A to the Town B with velocity of 30 km/h. At the same time, Anton go from Town B to the Town A with velocity of 60 km/h. If the space between Town A and Town B is 140 km, count the space when they meet each other! Please explain
Answer:
The space when they meet each other is from town A = 46.67km
s= ut
Let's consider x as the distance from town A to the meeting point:
Time duration,
Mega taken = Anton taken
x/ 30 = (140 - x)/ 60
2x = 140- x
3x = 140
x = 46.67km
what is the difference between science and trickery?
Answer:
science is the intellectual pratical activity encompassing the scientific study of structure of the physical and natural world through observations while trickery is the practice if decep5
Question 2 (1 point)
(01.01 MC)
Blake is a member of the cross-country track team and runs six days a week. He also helps around the house by washing his family's cars,
mowing the grass, and taking out the garbage and recycling. Which of the following describes a possible benefit of Blake's physical activity
point)
O
a
Blake may be less likely to commit to a healthy future.
Ob
Blake may have a decreased chance of disease.
Oc
Blake may require more assistance performing daily tasks.
O
Blake may struggle to achieve healthy body fat levels.
Answer: Blake may have a decreased chance of disease.
Explanation:
Research has shown that on average, a person who engages in more physical activity will live longer than a person who does not with one reason for this being that engaging in physical activity helps reduce the risk of diseases such as; heart disease, diabetes, and many forms of cancer.
Obesity (risk factor) and high blood pressure are also reduced by engaging in physical activity.
A submarine completed a 450 km training with an average speed of 50 km/h. For the first 180 km, it travelled at an average speed of 60 km/h. What was the average speed for the remaining distance? Km/h
Answer:
45km/hr
Explanation:
Total distance=450km
Total speed=50km/hr
Total time= distance/speed
=450/50
=9hrs
distance a=180km
speed a=60km/hr
Time a=180/60
=3hrs
Distance b=450-180=270km
Speed b=?
Time b=270/speed b
Total time=time a + time b
9=3+(270/speed b)
270/speed b =9-3
270/speed b =6
6*speed b =270
Speed b=270/6
Speed b=45km/hr
Answer:
45km/hr
Explanation:
Total distance=450km
Total speed=50km/hr
Total time= distance/speed
=450/50
=9hrs
distance a=180km
speed a=60km/hr
Time a=180/60
=3hrs
Distance b=450-180=270km
Speed b=?
Time b=270/speed b
Total time=time a + time b
9=3+(270/speed b)
270/speed b =9-3
270/speed b =6
6*speed b =270
Speed b=270/6
Speed b=45km/hr
You and a friend each drive 50.0 km. You travel at 90.0 km/h; your friend travels at 95.0 km/h. How long will your friend have to wait for you at the end of the trip?
Answer:
1.08 hours
Explanation:
Distance = speed × time
Time = distance / speed
The time you spend driving is:
t = 50.0 km / (90.0 km/hr)
t = 0.555 hr
The time your friend spends driving is:
t = 50.0 km / (95.0 km/hr)
t = 0.526 hr
The total time is 0.555 hr + 0.526 hr = 1.08 hr.
the radius of the earth is 6380 km and the height of the mount everest is 8848m . if the value of the acceleration due to gravity on the top of the mount everst is 9.77m/s²,calculate the value of acceleration due to gravity on the surface of the earth .what is the weight of a body of mass 50 kg on the top of mt.everest?
Explanation:
g = GM / R²
9.77 m/s² = GM / (6.38×10⁶ m + 8848 m)²
GM = 3.99×10¹⁴ m³/s²
At the surface of the earth:
g = GM / R²
g = (3.99×10¹⁴ m³/s²) / (6.38×10⁶ m)²
g = 9.80 m/s²
At the top of Mount Everest, the weight of a 50 kg object is:
F = mg
F = (50 kg) (9.77 m/s²)
F = 489 N
Gravity causes items to accelerate as they descend to the ground. Acceleration is a modification of velocity, and velocity is a measurement of the direction and speed of motion. Anything falls through gravity, and the longer it falls, the quicker it falls.
What acceleration due to gravity on surface of the earth?A particular term is given to the acceleration of a free-falling item because it is such a significant value. The acceleration of any object moving only as a result of gravity is referred to as the “acceleration of gravity.”
g = GM / R²
9.77 m/s² = GM / (6.38×10⁶ m + 8848 m)²
GM = 3.99×10¹⁴ m³/s²
At the surface of the earth:
g = GM / R²
g = (3.99×10¹⁴ m³/s²) / (6.38×10⁶ m)²
g = 9.80 m/s²
At the top of Mount Everest, the weight of a 50 kg object is:
F = mg
F = (50 kg) (9.77 m/s²)
F = 489 N
Therefore, 489 N is the weight of a body of mass 50 kg on the top of mt.everest.
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Express the following units into their basic units
a)neuton
b)joule
600 pages of a book have a total mass of 0.6kg; calculate the mass of each sheet of paper in the book in (i) Kilograms (ii) Milligram
Answer:
[tex]1g = 1000mg \\ \: \: \: \: \: \: \: \: = 0.001kg[/tex]
Explanation is attached to the picture
hope this helps
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Question 2 (1 point)
In a competition, an athlete threw a flying disk 178.7 meters through the air. While
in flight, the disk traveled at an average speed of 13.6 m/s. How long did the disk
remain in the air?
Your Answer:
Answer
units
A running back with a mass of 70 kg travels down the field with a velocity of 5.0 ms . Calculate the kinetic energy of the football player
Explanation:
KE = ½ mv²
KE = ½ (70 kg) (5.0 m/s)²
KE = 875 J
A pair of narrow, parallel slits separated by 0.275 mm is illuminated by the green component from a mercury vapor lamp (λ = 546.1 nm). The interference pattern is observed on a screen 1.25 m from the plane of the parallel slit. Calculate the distance from the central maximum to the first bright region on either side of the central maximum.
Answer:
2.481 mm
Explanation:
Given that
Distance between the slits, d = 0.275 mm = 2.75*10^-4 m
Wavelength of the lamp, λ = 546.1 nm
Distance between slit and the screen, L = 1.25 m
To solve this question, we would be applying the formula for Young's double slit fringes, from the path difference equal to a whole number of wavelengths.
mλ = dy/L
The question states that we should find the distance from the centre to the 1st order bright fringe, thus, m = 1
Now, we apply all these values into the question
1 * 546.1*10^-9 = (2.75*10^-4 * y) / 1.25
1.25 * 1 * 546.1*10^-9 = 2.75*10^-4 * y
6.825*10^-7 = 2.75*10^-4 * y
y = 6.825*10^-7 / 2.75*10^-4
y = 0.002481 m or 2.481 mm
(PLEASE HELP THANK YOU) A car is going 8 meters per second on an access road into a highway and then accelerates at 1.8 meters per second squared for 7.2 m seconds. How fast is it then going?
Answer:
20.96 m/s
Explanation:
Apply the kinematic equation:
Vf=Vi+at
Vi=8m/s
a=1.8m/s^2
t=7.2s
Putting this all in should give you your answer of 12.96m/s
Ariver is flowing at 3.6 m/s. A boy in a tube is floating the river downstream. If the boy can use
his arms to paddle at 1.7 m/s with the current, how fast will it appear he is moving to anyone on
the riverbank?
Answer:
The total speed is 5.3 m/s
Explanation:
The speed of river = 3.6 m/s
The speed of the tube that a boy use for downstream = 1.7 m/s
Now we have to find the total speed of the boy in the case of downstream. However, in this case, the total speed can be determined by adding both the given speeds.
The total speed = Speed of rive + speed of the tube
Total speed = 3.6 + 1.7
Total speed = 5.3 m/s
To explore the bottom of a 25-m-deep lake, your friend Tom proposes to get a long garden hose, put one end on land and the other in his mouth for breathing underwater, and descend into the depths. Susan, who overhears the conversation, reacts with horror and warns Tom that he will not be able to inhale when he is at the lake bottom.
Why is Susan so worried?
The pressure at a depth 01 25 m is 3 x 10^5 Pa. This is almost three times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
The pressure at a depth 01 25 m is 3.5 x 10^5 Pa. This is almost 3.5 times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
The pressure at a depth 01 25 m is 2 x 10^5 Pa. This is almost two times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
The pressure at a depth 01 25 m is 2.5 x 10^5 Pa. This is almost 2.5 times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
Answer:
The pressure at a depth 01 25 m is 2.5 x 10^5 Pa. This is almost 2.5 times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
Explanation:
The depth is h = 25 m
The density of water p = 1000 kg/m^3
Acceleration due to gravity g = 9.81 m/s^3.
Pressure due to a depth is gotten from
P = pgh
P = 1000 x 9.81 x 25 =245250 Pa
==> 2.45 x 10^5 Pa
Approximately 2.5 x 10^5 Pa
Atmospheric pressure = 1.01325 x 10^5 Pa
Dividing the pressure at the bottom of the pond by the atmospheric pressure gives a value of about 2.5,which means that the pressure is 2.5 times the atmospheric pressure.